Answer:
For the car to move with constant velocity the additional force required is [tex]F__{dg} }= -3674 \ N[/tex]
Explanation:
From the question we are told that
The net force of the car is [tex]F_{net} = 3674 \ N[/tex]
Generally the total force acting on the car is the net force plus the force due to gravity acting in direction of the car (Let denote it as [tex]F__{dg}[/tex])
So the total force acting on the car is mathematically represented as
[tex]F_{net} + F__{dg}} = F[/tex]
Here this F representing the total force can be mathematically represented as
[tex]F = ma[/tex]
Now for constant velocity to be attained, the acceleration of the car will be zero
So at constant velocity
[tex]F = m * 0[/tex]
=> [tex]F = 0 \ N[/tex]
So
[tex]F_{net} + F__{dg}} = 0[/tex]
=> [tex]F__{dg} }= -F_{net}[/tex]
=> [tex]F__{dg} }= -3674 \ N[/tex]
The force of gravity would be greatest between which of the following?
Answer:
between a ball and a car
Explanation:
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Find the kinetic energy of a 3.5 kg cat that has a momentum of 0.22 kg • m/s.
A) 3.98 x 10^-5 J
B) 4.32 x 10^-4 J
C) 6.91 x 10^-3 J
D) 7.22 x 10^-2 J
Answer:
6.19*10^-3 J
Explanation:
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What is the period of a rotating object if it spins 24 times in 13 seconds?
Answer:
The period is 0.54 seconds
Explanation:
Period (T)
Is the time required for a rotating object to make one complete revolution around a circular path.
If it takes a time t to complete n revolutions, the period is:
[tex]\displaystyle T=\frac{t}{n}[/tex]
The rotating object spins n=24 times in t=13 seconds, thus its period is:
[tex]\displaystyle T=\frac{13}{24}[/tex]
T = 0.54 sec
The period is 0.54 seconds
How much heat in kcal is required to change 0.5 kg of ice, originally at - 10 0 * C into steam at 110 C?Constants needed in the problemLatent heat of fusion=79.7 kcal/kg Specific heat of ice=0.5 kcal/kg/K ; Latent heat of vaporization ation = 539 kcal/kg ; Specific heat of water 1.0 kcal/kg/K Specific heat of ieam=0.480 kcal/kg
Answer:
Q = 364.25 kcal
Explanation:
In this question, we will have to calculate the heat absorptions for different steps of temperature rise and phase change. And then we will ad them to calculate total heat absorbed.
1. RISE IN TEMPERATURE OF ICE:
First, the temperature of ice will be increased from - 10°C to 0 °C. Heat absorbed during this process will be given as:
Q₁ = mC₁ΔT₁
where,
Q₁ = Heat absorbed while increasing temperature of ice = ?
m = mass of ice = 0.5 kg
C₁ = specific heat of ice = 0.5 kcal/kg k
ΔT₁ = change in temperature of ice = 0 - (-10) = 10 k
Therefore,
Q₁ = (0.5 kg)(0.5 kcal/kg.k)(10)
Q₁ = 2.5 kcal
2. MELTING OF ICE:
Now, the melting of ice will occur at 0°C and the heat absorbed during this process will be:
Q₂ = m(Latent Heat of Fusion of Ice)
where,
Q₂ = heat Absorbed during melting of ice = ?
Therefore,
Q₂ = (0.5 kg)(79.7 kcal/kg)
Q₂ = 39.85 kcal
3. RISE IN TEMPERATURE OF WATER:
Now, the temperature of water will be increased from 0°C to 100 °C. Heat absorbed during this process will be given as:
Q₃ = mC₃ΔT₃
where,
Q₃ = Heat absorbed while increasing temperature of water = ?
m = mass of water = 0.5 kg
C₃ = specific heat of water = 1 kcal/kg k
ΔT₃ = change in temperature of ice = 100 - 0 = 100 k
Therefore,
Q₃ = (0.5 kg)(1 kcal/kg.k)(100 k)
Q₃ = 50 kcal
4. VAPORIZATION OF WATER:
Now, the vaporization of water will occur at 100°C and the heat absorbed during this process will be:
Q₄ = m(Latent Heat of Vaporization of Water)
where,
Q₄ = heat Absorbed during vaporization of water = ?
Therefore,
Q₄ = (0.5 kg)(539 kcal/kg)
Q₄ = 269.5 kcal
5. RISE IN TEMPERATURE OF STEAM:
Now, the temperature of steam will be increased from 100°C to 110 °C. Heat absorbed during this process will be given as:
Q₅ = mC₅ΔT₅
where,
Q₅ = Heat absorbed while increasing temperature of steam = ?
m = mass of steam = 0.5 kg
C₅ = specific heat of steam = 0.48 kcal/kg k
ΔT₅ = change in temperature of ice = 110 - 100 = 10 k
Therefore,
Q₅ = (0.5 kg)(0.48 kcal/kg.k)(10 k)
Q₅ = 2.4 kcal
Hence, the total heat absorbed to change 0.5 kg of ice at - 10°C into steam at 110°C will be:
Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅
Q = 2.5 kcal + 39.85 kcal + 50 kcal + 269.5 kcal + 2.4 kcal
Q = 364.25 kcal
A car’s brakes decelerate it at a rate of -2.20 m/s2. If the car is originally travelling at 17 m/s and comes to a stop, then how far, in meters, will the car travel during that time?
Answer:
x = 65.68 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}^{2}=v_{o}^{2}-2*a*x[/tex]
where:
Vf = final velocity = 0 (comes to stop)
Vo = initial velocity = 17 [m/s]
a = desaceleration = -2.2 [m/s²]
x = displacement [m]
Now replacing, we have:
[tex](0)^{2}=(17)^{2}-2*(2.2)*x\\4.4*x = 289\\x = 65.68 [m][/tex]
An object starts at 16 m/s with an acceleration of 4.5 m/s? How far does it go in 9.0 seconds?
what is the KE of a 1.00 kg hammer swinging at 20.0 m/s? 200 Joules
I know the answer I just need help understanding it.
Answer:
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 1250 kg
Velocity (v) = 20.0 m/s.
Kinetic energy (K.E) =?
Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:
K.E = ½mv²
Where:
K.E is the kinetic energy
m is the mass of the object
v is the velocity of the object.
Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:
Mass (m) = 1250 kg
Velocity (v) = 20.0 m/s.
Kinetic energy (K.E) =?
K.E = ½mv²
K.E = ½ × 1250 × 20²
K.E = 625 × 400
K.E = 250000 J
Therefore, the kinetic energy of the automobile is 250000 J
How does pressure change as you go deeper into Earth’s interior
Answer:
The temperature and the pressure both increase as we go deeper within the Earth, toward its core.
Explanation:
Charges are of two kinds—negative charges and ________________ charges. __________ amounts of both kinds of charges are found in every piece of matter.
Answer: the first is positive and second is equal
Explanation:
Answer: 1. Positive
Explanation:
Because there is negative charges and positive charges
Convert 45km to miles show your work
Answer:
distance = 27.95 [mi]
Explanation:
in order to solve this problem, we must use the appropriate conversion factor, i.e. a conversion factor that relates the kilometers to Miles.
[tex]1 [km] = 0.6214 [mill]\\45[km]*0.6212[\frac{mill}{1km} ]=27.95 [mill][/tex]
What are the different isotopes of carbon and which isotopes are relevant for carbon dating?
The three isotopes of carbon are C-12, C-13, and C-14. The carbon isotope 14C, which is the most commonly used radioactive cosmogenic isotope, can be used to date occurrences that took place within the last 60,000 years or so.
There are three types of carbon isotopes. Carbon-12 (12C) is by far the most prevalent isotope of carbon and it has six neutrons in relation to its six protons. Carbon-13 (13C), the second-heaviest carbon isotope, has seven neutrons. Since neither 12C nor 13C undergoes radioactive decay over time, they are both referred to as stable isotopes. The nucleus of the rare carbon-14 (14C) isotope has eight neutrons. This isotope, in contrast to 12C and 13C, is unstable or radioactive. A 14C atom will eventually transform into a stable byproduct.
The process of radiocarbon dating, also known as carbon dating or carbon-14 dating, uses the characteristics of radiocarbon (14C), a radioactive isotope of carbon, to estimate the age of an object made of organic material.
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a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.
Answer:
Average speed = ( 2V + V1 + V2)/4
Explanation:
Given that a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.
Since the distance is covered at equal intervals of time, and
Speed = distance/time
For the first half distance,
V = distance/t
Cross multiply
Distance = Vt
For the second half distance
(V1 + V2)/2 = distance/t
Distance = t(V1 + V2)/2
The average speed = total distance/ total time.
Average speed = [Vt + t( V1 + V2)/2] ÷ 2t
Average speed = (2Vt + V1t + V2t)/4t
Average speed = t( 2V + V1 + V2)/4t
Time t will cancel out
Average speed = ( 2V + V1 + V2)/4
An object that is experiencing two vertical forces (upwards and a downwards) is moving downward with a constant speed. What can be concluded about the strength of the two forces?
Answer:
Both upward and downward forces are equal
Explanation:
When an object is acted upon by two vertical forces ; upward and downward, and the object moved at a constant speed, then the net force acting upon the object is zero(upward force + downward force = 0). This is because an object will only move at a constant velocity if the opposing forces cancels each other out. Since the falling object is already in motion, and maintaining a constant velocity, there is no for required to keep the body in motion and as such the Velocity at which the body is moving remains constant.
At the local destruction derby a 400 kg Toyota moving at 10 m/s collides with an 800 kg Chevy. Both are at rest after the collision. What was the velocity of the Chevy before the collision?
Answer:
[tex]u_2 = -5m/s[/tex]
Explanation:
Given
Before Collision
Toyota
[tex]mass = m_1 = 400kg[/tex]
[tex]iniital\ velocity = u_1 =10m/s[/tex]
Chevy
[tex]mass = m_2=800kg[/tex]
[tex]initial\ velocity = u_2 = ??[/tex]
After Collision
Both Toyota and Chevy
[tex]final\ velocity = v = 0m/s[/tex]
Required
Determine the initial velocity of Chevy
This question will be answered using the following law of conservation of momentum which states that:
[tex]m_1u_1 + m_2u_2 = (m_1 + m_2)v[/tex]
Substitute values for m1, m2, u1 and v
[tex]400 * 10 + 800 * u_2 = (400 + 800) * 0[/tex]
[tex]4000 + 800u_2 = (1200) * 0[/tex]
[tex]4000 + 800u_2 = 0[/tex]
Collect Like Terms
[tex]800u_2 = 0 - 4000[/tex]
[tex]800u_2 = -4000[/tex]
Divide through by 800
[tex]\frac{800u_2 = -4000}{800}[/tex]
[tex]u_2 = \frac{-4000}{800}[/tex]
[tex]u_2 = -5m/s[/tex]
The velocity of Chevy before collision was 5m/s in the opposite direction of Toyota
according to newtons third law of motion what happened to the back of a skateboard when the person pushes down on the front of the skateboard
Answer:I think it would start moving
Explanation:
A book that weighs 5 N sits on a table. What force does the table apply to the book?
Answer:
E =F.d =[1/2]mv^2
mad = [1/2]mv^2
d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0
So d = at^2/2
F = ma= 20a= 50 , a=5/2 and t=2
so d = [5/2][2^2]/2=5
Explanation:
Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
What is Newton's third law of motion?Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.
Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
The given data in the problem is ;
W is the weight of the book sits on table = 5N
N is the normal force on the book
From the equilibrium equation ;
Weight -Normal force on the book =0
Weight =Normal force on the book
The normal force on the book =5N
Hence the table exerts a force of 5 N on the book in order to be in stable condition.
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6th grade science I mark as brainliest.
Answer:
Solution:-Distance =400m
Time=20s
We need to find speedAs we know that
[tex]{\boxed{\sf speed \dfrac {Distance {}_{(d)}}{Time {}_{(t)}}}}[/tex]
Substitute the values[tex]\LARGE\leadsto\sf speed=\dfrac {400}{20}[/tex]
[tex]\LARGE\leadsto\sf 20m/s[/tex]
The normal force of a parked car is 15,000 Newtons. The coefficient of static friction between the rubber of the tires and the asphalt of the road is 0.75. What is the maximum static friction force?
Answer:
11250 N
Explanation:
From the question given above, the following data were obtained:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
Friction and normal force are related by the following equation:
F = μR
Where:
F is the frictional force.
μ is the coefficient of static friction.
R is the normal force.
With the above formula, we can calculate the frictional force acting on the car as follow:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
F = μR
F = 0.75 × 15000
F = 11250 N
Therefore, the frictional force acting on the car is 11250 N
What two things does force depend on
Select three effective methods for helping a friend who is showing self harming behavior
Answer:
Avoid judging or criticizing your friend.
Let your friend know that you care and want to help
Share the ways you cope with stress and other problems in your life
I had this question
tarzans mass is 75kg. calculate his weight
Answer:
75kg=165.346697lbs
Explanation: F A T
*NEED THIS ANSWERED ASAP*
run this moving man simulation to get a visual understanding of all that you learned in this lesson about position velocity and acceleration during this activity you will explain these Concepts first click the introduction tab, and answer the question. set a small constant V on the velocity slider and check the velocity Vector box. click play, watch, and describe the motion in terms of what you see happening with the man's displacement, velocity and acceleration.
Answer:
When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero
Explanation:
plato
When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.
What is Velocity?Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.What is Displacement?Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.What is Acceleration?Acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down.When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.
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What is the speed of an eagle that travels 200 meters in 4 seconds? A. 800 m/s2 B. 800 m/s C. 50 m/s2 D. 50 m/s
Answer:
The answer is D.
Explanation:
You have to apply distance formula :
[tex]distance = speed \times time[/tex]
[tex]let \: d = 200,t = 4[/tex]
[tex]200 = s \times 4[/tex]
[tex]4s = 200[/tex]
[tex]s = 200 \div 4[/tex]
[tex]s = 50 \: m {s}^{ - 1} [/tex]
An eagle travels 200 meters in 4 seconds
To find:-Speed of the eagle
Solution:-HereDistance=d=200m
Time=t=4s
As we know[tex]{\boxed{\sf Speed ={\dfrac{Distance{}_{(d)}}{Time{}_{(t)}}}}}[/tex]
Substitute the values[tex]\qquad\quad {:}\longmapsto\sf Speed=\dfrac {200}{4}[/tex]
[tex]\qquad\quad {:}\longmapsto\sf Speed=50m/s [/tex]
[tex]\therefore{\underline{\boxed{\bf Speed\:of\:eagle=50m/s}}}[/tex]
Hence Correct option is DWhat factors determine the distance at which two atoms form a bond ?
Answer:
The length of the bond is determined by the number of bonded electrons (the bond order). The higher the bond order, the stronger the pull between the two atoms and the shorter the bond length. Generally, the length of the bond between two atoms is approximately the sum of the covalent radii of the two atoms.
Explanation:
PLEASE HELP ME! IM TIMED
Answer:
Toothpaste
Because it is viscous
Which of the following are possible non-SI units to describe the rate of
acceleration? (Choose all that apply)
1) meters per second per minute
2) miles per kilometer per
second
3) miles per hour per second
4) kilometers per hour squared
5) meters per hour per kilometer
6) kilometers per minute
The possible non-SI units to describe the rate of acceleration is the kilometers per hour squared. That is option 4.
What is acceleration?Acceleration is the relationship that exists between velocity and time. It is defined as the change of velocity in both speed and direction with respect to time.
The formula for acceleration is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.
Velocity is defined as the rate of objects position with time.
The SI units of velocity = meter/seconds
Substitute for velocity in first equation:
a = meter/sec/sec
a = meter/sec²
But 1000meters = 1 Km
3600 secs = 1 hour
Therefore, the possible non-SI units to describe the rate of acceleration is the kilometers per hour squared.
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Many athletes use altitude training to improve their performance. They travel to areas of high altitude where there is less oxygen in the air. The body adapts to the stress of less oxygen by becoming more efficient at transporting and using oxygen. What are athletes who train in high altitudes most likely trying to enhance?
Answer:
Its A
Explanation:
Energy Production in the Mitochondria because of the lack of less oxygen you would want to build up more ways to get more energy production going
Energy Production in the Mitochondria because of the lack of less oxygen one want to build up more ways to get more energy production.
What is resultant force ?Resultant force is a summation of all force which act on a point or object. It will be either negative or positive i.e if we takes on direction is positive then other three direction will be taken in negative and then add all force so the outcome is called resultant force acting on a object. Mass is a physical quantity which is measured in kilograms . It will neither depend on any other quantity.
It is also doesn't depend on acceleration due to gravity like weight is depend on acceleration due to gravity but mass is not .Weight is varies from one place to another place but mass doesn't depend on place or position.
Therefore, Energy Production in the Mitochondria because of the lack of less oxygen one want to build up more ways to get more energy production.
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what is the mass and volume of 1000kg/m3 of water?
Answer: The mass would be 1000m3 and the volume would be 1000kg
Explanation:
Please help! Will mark brainliest!
Answer:
im pretty sure its d
Explanation:
a cannon launches a 3.0 kg pumpkin with 110J of kinetic energy. what is the pumpkin’s speed?
Answer:
v = 8.56 [m/s]
Explanation:
The kinetic energy can be calculated by means of the following equation.
[tex]E_{k}=\frac{1}{2}*m*v^{2}[/tex]
where:
m = mass = 3 [kg]
v = velocity [m/s]
Ek = kinetic energy [J]
[tex]110 = \frac{1}{2} *3*(v^{2} )\\v^{2} = 220/3\\v=\sqrt{73.333}\\v=8.56[m/s][/tex]