I need help on this angles on a straight line problem, it involves algebra. I don't need an explanation just the answer please.

Answer:

---

Step-by-step explanation:

Convert the fraction to a decimal(40% = 40/100 = 0.4). Multiply it by 120.

0.4x120=a

---

hope it helps

The equation 40 ÷ 100 × 120 = a shows

the relationship 40% of 120 is a

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign. It shows the relationship of equality between the expression written on the left side with the expression written on the right side. In every equation in math, we have, L.H.S = R.H.S (left hand side = right hand side).

'An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values.'

For example, 3x + 5 = 15.

Given,

Relation, 40% of 120 is a

⇒ 40% × 120 = a

Above relation can be written in equation as

40 ÷ 100 × 120 = a

Hence, 40 ÷ 100 × 120 = a is the equation

for relation such that  40% of 120 is a.

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The probability that this person liked the tea, given that the person is female is P = 0.806

The probability will be given by the quotient between the number of females that liked the tea and the total number of females in the experiment.

We know that there are 25 + 6 = 31 females in the experiment, and 25 of them liked the tea, then the probability that a random female likes the tea is:

P = 25/31 = 0.806

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Answer: there you go! I hope this helps!

Step-by-step explanation:

The statement second is correct because the end behavior is that as x = ±∞ , f(x) → 0

A limit is a value at which a function approaches the output for the given values in mathematics. Limits are used to determine integrals, derivatives, and continuity in calculus and mathematics.

We have a function:

[tex]\rm f(x) = \frac{7x^2+x+1}{x^4+1}[/tex]

Applying limit:

[tex]\lim_{x \to \pm \infty} \rm f(x)[/tex]

[tex]\rm \lim_{x \to \pm\infty} \frac{7x^2+x+1}{x^4+1}[/tex]

Divide by x^4 on the numerator and denominator, we get:

[tex]\rm \lim_{x \to \pm\infty} \frac{7/x^4+1/x^3+1/x^4}{1+1/x^4}[/tex]

So the value of the limit will be zero whereas x tends to ±∞

Thus, the statement second is correct because the end behavior is that as x = ±∞ , f(x) → 0

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Answer: n < 60

Step-by-step explanation:

n - 48 < 12

n - 48 + 48 < 12 + 48

n < 60

Answer:

D-Ability to access cash value

The statement which is not a characteristic of term life insurance is B) Coverage can be denied upon renewal.

Term life insurance is the simplest form of the life insurance which is a death benefit which pays the policyholder when lives or their heirs when they died.

Here,

Term life insurance has to be renewed periodically.

The coverage of the term life insurance can be extended by renewing it. So it cannot be denied upon renewal.

In term life insurance, it will paid out if you die.

There is a characteristic of ability to access cash value in term life insurance.

Hence the characteristic which is not that of the term life insurance is option B) Coverage can be denied upon renewal.

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Step-by-step explanation:

here u go ..ntgs different hope this will too helps ..stay safe

Answer:

Step-by-step explanation:

Today's calculators have statistical functions built in.

A.  Here we use:

normalcdf(10,310,205,35), WHICH returns 0.999.

B.  normalcdf(135,275, 205,35) = 0.954

C.  normalcdf(240, 10000, 205, 35) = 0.159

Answer:

57%

Step-by-step explanation:

Answer:

I think the first one 57%

Step-by-step explanation:

hope this helps sorry if it doesn't have a good rest of your afternoon/day :) ❤

Answer:

The answer is "0.425".

Step-by-step explanation:

The  T be a requirement today that such rains.

The Y be a situation yesterday that now it rained.

The O is a condition for tomorrow to rain.

[tex]P(O| (Y\ AND \ T)) = 0.8\\\\P(O|(Y \ AND \ NOT\ (T)) =0.3\\\\P( O|(NOT \ (Y)\ AND\ T)= 0.4\\\\P( O| NOT\ (Y) \ OR \ NOT \ (T)) =0.2[/tex]

There Arena and morrow overview To Aspects Which will rain:

[tex]Y\ AND \ T, Y \ AND \ NOT \ (T),\ NOT\ (Y) \ AND\ T, \ NOT(Y)\ OR \ NOT(T)[/tex]

Each has the option of [tex]\frac{1}{4}[/tex] INDEPENDENTLY happening.

Its possibility of tomorrow's rain is:

[tex]P(O) = P(O | Y\ AND\ T) P(Y\ AND\ T) + P(O|(Y \ AND \ NOT\ (T))[/tex]

       [tex]P((Y\ AND \ NOT\ (T)) + P(O|(\ NOT\ (Y) \ AND \ T))P(\ NOT\ (Y) \ AND\ T) \\\\+ P( O| \ NOT\ (Y)\ OR\ NOT\ (T)) P(\ NOT\ (Y)\ OR\ NOT\ (T))\\\\[/tex]

      [tex]=0.8\times \frac{1}{4} +0.3\times \frac{1}{4}+0.4\times \frac{1}{4}+0.2\times \frac{1}{4}\\\\ =\frac{1}{4}(0.8+0.3+0.4+0.2)\\\\= \frac{1.7}{4}\\\\= 0.425[/tex]

Answer: 21 miles

Step-by-step explanation:

7x3 = 21 miles

Answer:

the answer is A-  B/3 or B divided by 3

Step-by-step explanation:

Answer:

[tex](1)\ [12]x^2 [-][37]x - 30 = (3x + 2)(4x - 15)[/tex]

[tex](2)\ x^2\ [\ -]\ 169 = (x \[+ ]\ 13){x\ [- ]\ [13 ])[/tex]

[tex](3)\ x^2 [-]\ [9]x + 20 = (x\ [-] 5)(x- [4])[/tex]

[tex](4)\ x^2 + [11]x + 28 = (x + 7)(x + [4])[/tex]

[tex](5)\ x^2 + [5]x - 24 = (x\ [-]\ [3])(x\ [+]\ [8])[/tex]

Step-by-step explanation:

Given

See attachment for complete question

Required

Complete the boxes

Solving (1):

[tex][ \ ]x^2 [ \ ] [\ ]x - 30 = (3x + 2)(4x - 15)[/tex]

Swap the equation

[tex](3x + 2)(4x - 15) = [ \ ]x^2 [ \ ] [\ ]x - 30[/tex]

Open bracket

[tex]12x^2 -45x + 8x - 30 = [ \ ]x^2 [ \ ] [\ ]x - 30[/tex]

Simplify the like terms

[tex]12x^2 -37x - 30 = [ \ ]x^2 [ \ ] [\ ]x - 30[/tex]

So, we have:

[tex][12]x^2 [-][37]x - 30 = [ \ ]x^2 [ \ ] [\ ]x - 30[/tex]

i.e.

[tex][12]x^2 [-][37]x - 30 = (3x + 2)(4x - 15)[/tex]

Solving (2):

[tex]x^2\ [\ ]\ 169 = (x \ [\ ]\ 13)(x\ [\ ]\ [\ ])[/tex]

The above expression illustrates the difference of two squares.

So, complete the first equation with minus

[tex]x^2\ [\ -]\ 169 = (x \ [\ ]\ 13)(x\ [\ ]\ [\ ])[/tex]

Express 169 as 13^2

[tex]x^2\ [\ -]\ 13^2 = (x \ [\ ]\ 13)(x\ [\ ]\ [\ ])[/tex]

Apply difference of two squares

[tex](x + 13)(x - 13) = (x \[\ ]\ 13){x\ [\ ]\ [\ ])[/tex]

So, the complete expression is:

[tex]x^2\ [\ -]\ 169 = (x \[+ ]\ 13){x\ [- ]\ [13 ])[/tex]

Solving (3):

[tex]x^2 [\ ]\ [\ ]x + 20 = (x \ [\ ]5)(x - [\ ])[/tex]

20 can be expressed as: -5 * -4

So, the expression becomes

[tex]x^2 [\ ]\ [\ ]x + 20 = (x \ [- ]5)(x - [4 ])[/tex]

Expand

[tex]x^2 [\ ]\ [\ ]x + 20 = x^2 - 5x - 4x + 20[/tex]

[tex]x^2 [\ ]\ [\ ]x + 20 = x^2 -9x + 20[/tex]

So, the complete expression is:

[tex]x^2 [-]\ [9]x + 20 = (x\ [-] 5)(x- [4])[/tex]

Solving (4):

[tex]x^2 + []x + 28 = (x + 7)(x + [])[/tex]

28 can be expressed as 7 * 4

So, the expression becomes

[tex]x^2 + []x + 28 = (x + 7)(x + [4])[/tex]

Expand

[tex]x^2 + []x + 28 = x^2 + 7x + 4x + 28[/tex]

[tex]x^2 + []x + 28 = x^2 + 11x + 28[/tex]

So, the complete expression is:

[tex]x^2 + [11]x + 28 = (x + 7)(x + [4])[/tex]

Solving (5):

[tex]x^2 + []x - 24 = (x\ []\ [])(x\ []\ [])[/tex]

-24 can be expressed as -3 * 8

So, the expression becomes

[tex]x^2 + []x - 24 = (x\ [-]\ [3])(x\ [+]\ [8])[/tex]

Expand

[tex]x^2 + []x - 24 = x^2 +8x - 3x - 24[/tex]

[tex]x^2 + []x - 24 = x^2 +5x - 24[/tex]

So, the complete expression is:

[tex]x^2 + [5]x - 24 = (x\ [-]\ [3])(x\ [+]\ [8])[/tex]

An equation is formed of two equal expressions. The complete equations are:

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

1. The first equation that is given to us is:

[tex](?x^2)\ ?\ (?x)-30 = (3x+2)(4x-15)[/tex]

Now, if we simply expand the right-hand side of the equation we will get the equation that is mentioned on the left side of the given equation, therefore,

[tex](3x+2)(4x-15)\\\\= 12x^2-45x+8x-30\\\\=12x^2-37x-30[/tex]

Thus, the complete equation will be

[tex]12x^2-37x-30 = (3x+2)(4x-15)[/tex].

2. The second equation that is given to us is,

[tex]x^2\ ?\ 169 = (x\ ?\ 13)(x\ ?\ ?)[/tex]

Now, if look closely at the equation, and substitute the '-' in the place of '?' the equation we will be in the form of an algebraic equation, therefore, the solution of the equation can be made using the algebraic expression,

[tex]a^2-b^2 = (a+b)(a-b)\\\\(x^2-13^2) = (x+13)(x-13)\\\\\(x^2-169) = (x+13)(x-13)[/tex]

Thus, the complete equation will be

[tex](x^2-169) = (x+13)(x-13)[/tex].

3. The third equation that is given to us is,

[tex]x^2\ ?\ (?x)+20 = (x\ ?\ 5)(x-?)[/tex]

As we can see in the equation, on the left side of the equation the last digit is +20, therefore, the digits on the right side of the equation should be such that their product should be +20, as 5 is already given therefore, the other term should be 4 also, the second term is positive but we need the product to be positive, therefore, the sign of the digit 5 will also be negative.

[tex]x^2\ ?\ (?x)+20 = (x\ ?\ 5)(x-?)\\\\x^2\ ?\ (?x)+20 = (x- 5)(x-4)[/tex]

Now, if we solve the right side of the equation we will get the left side of the equation,

[tex](x- 5)(x-4)\\\\= x^2 - 4x-5x +20\\\\=x^2-9x+20[/tex]

Thus, the complete equation is

[tex]x^2-9x+20=(x-5)(x-4)[/tex].

4. The fourth equation that is given to us is

[tex]x^2 + ?x + 28 = (x+7)(x+?)[/tex]

As we can see in the equation, on the left side of the equation the last digit is +28, therefore, the digits on the right side of the equation should be such that their product should be +28, as 7 is already given therefore, the other term should be 4. Also, 28 is a positive integer, and 7 is also a positive integer, therefore, the number in the last will be positive as well.

[tex]x^2 + ?x + 28 = (x+7)(x+4)[/tex]

Now, if we solve the right side of the equation we will get the left side of the equation,

[tex](x+7)(x+4)\\\\= x^2 + 4x+ 7x + 28\\\\= x^2 + 11x+28[/tex]

Thus, the complete equation is

[tex]x^2 + 11x + 28 = (x+7)(x+4)[/tex]

5. The fifth equation that is given to us is

[tex]x^2 + ?x -24=(x\ ?\ ?)(x\ ?\ ?)[/tex]

As we can see in the equation, on the left side of the equation the last digit is -24, therefore, the digits on the right side of the equation should be such that their product should be -24, Since the product is negative, therefore, either one of the digits on the right should be negative as well, but the middle term on the right is positive, therefore, the bigger number will be positive while the smaller ones will be negative.

[tex]x^2 + ?x -24=(x+8)(x-3)[/tex]

Now, solving the right side of the equation to get the complete left side of the equation we will get,

[tex](x+8)(x-3)\\\\=x^2 -3x + 8x -24\\\\=x^2 + 5x - 24[/tex]

Thus, the complete equation is

[tex]x^2 + 5x - 24=(x+8)(x-3)[/tex]

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Answer:

5/16 pounds

Step-by-step explanation:

The problem mentions that Audrey needs to cut a 5-pound block into 16 pieces. This means that each of the 16 pieces of cheese must weigh the same, thus we have to divide 5 pounds by 16 to divide the weight equally. Thus, all you need to do is divide 5 by 16, giving you 5/16. Therefore, your answer is that each block of cheese weighs 5/16 pounds.

Answer:

0.3125 pounds

Step-by-step explanation:

Each wedge of cheese weights 0.1325 pounds

Answer:

4 3/4

Step-by-step explanation:

= (8 - 3) + (1/4 - 1/2)

= 5 + 1/4 - (1 x 2 over 2 x 2)

= 5 + 1/4 - 2/4

= 5 and (1/2 over 4)

= 5 + -1/4

= 4 3/4

Answer:

Solution given:

-2(3x+12y-5-17x-16y+4)

-6x-24y+10+34x+32y-8

34x-6x+32y-24y+10-8

28x+8y+2 is a required answer.

Answer:

Part A

c = p + 55h

Part B

$362

Step-by-step explanation:

Dawson's Garage charges $55 per hour to do car repairs plus the cost of the parts.

Part A

h = the number of hours

p = the cost of the parts

c = the total cost of the repairs.

The equation to model this situation is written as:

c = p + $55 × h

c = p + 55h

Part B

What will the cost of the repairs be if the parts cost $142 and it takes 4 hours to do the repairs?

From the above question:

p = $142

h = 4

Since our equation =

c = p + 55h

Hence,

c = 142 + 55 × 4

c = 142 + 220

c = 362

Therefore, the cost of repairs = $362

Answer: 1.6

Step-by-step explanation: So the diameter is the length of the hall sphere so you would times the radius by two to get the diameter wich is 1.6

Answer:

D

Step-by-step explanation:

The area of the expanded rectangular patio is: D. (0.5l)(0.2w)

Area = (length)(width)

Given the following:

New length = 50% of l = 0.5l

New width = 20% of w = 0.2w

Area of the expanded rectangular patio = (0.5l)(0.2w)

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Answer:

0,0

Step-by-step explanation:

In adjoining the figure to find the coordinates of point P the distance of P from y-axis is 0 units and the distance of P from x- axis is 0 units

Answer:

I think the answer is option 2

3 is the correct choice

Answer:

31

Step-by-step explanation:

y+y=y+31

2y-y=31

y=31°

Answer:

[tex] x =63^o[/tex]

Step-by-step explanation:

Given :-

We know that the tangents are perpendicular to the radius at the point of contact . And here OLMN is a quadrilateral. Also we know that , the angle sum property a triangle is 360° .

According to question :-

[tex]\implies x + 117^o + 90^o +90^o = 360^o \\\\\implies x + 297^o = 360^o \\\\\implies x = 360^o - 297^o \\\\\implies x = 63^o [/tex]

Hence the value of x is 63° .

Answer:

The one on the bottom left

Step-by-step explanation:

Have a wonderful Day

Answer:

3. 43     4. 84     5. 522

Step-by-step explanation:

Answer:

352 students

Step-by-step explanation:

Given

See attachment for table

[tex]n = 400[/tex]

Required

Attendance of students in this year's show

First, we calculate the mean of the table

[tex]Mean= \frac{\sum x}{n}[/tex]

So, we have:

[tex]Mean= \frac{85\% + 91\% + 92\% + 87\% +84\% + 89\%}{6}[/tex]

[tex]Mean= \frac{528\%}{6}[/tex]

[tex]Mean= 88\%}[/tex]

Multiply the mean by the total students

[tex]Expected = Mean * n[/tex]

[tex]Expected = 88\% * 400[/tex]

[tex]Expected = 352[/tex]

Answer:352

Step-by-step explanation:

You basically just find the mean

Answer:

10 + 30x

Step-by-step explanation:

Answer:

-10 - 30x

Step-by-step explanation:

-10 (1 + 3x)

(-10 · 1) + (-10 · 3x)

-10 + -30x

-10 - 30x

Answer:

False

Step-by-step explanation:

Because the red line on the right is shorter then the one on the left, hope this helps.