I need help asap. Math Writing Expressions.

Answer:

Step-by-step explanation:

Perpendicular bisector of the chord connecting the the points (-1,2) and (2,3) is also passing through the center of the circle.

We'll find the equation of the line and solve the system to find the center.

Midpoint of the chord:

Equation of the line through chord (-1,2) and (2,3):

Perpendicular bisector is:

And the given line is:

Solve the system:

Find y:

The center is (-1, 7)

Find the radius, the distance from center to one of points on circle

The equation of circle is:

Hope This Helps!!!

Hope This Helps!!!Have A GREAT DAY!!!

Answer:

80

Step-by-step explanation:

because 16 decided by 0.2 is 80

hope this helps!!!!

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\text{If x = -2, then substitute it into the given equation}[/tex].

[tex]\large\textsf{f(x) = 4(-2) - 2}[/tex]

[tex]\large\textsf{y = 4(-2) - 2}[/tex]

[tex]\large\textsf{4(-2) = \boxed{\bf -8}}[/tex]

[tex]\large\textsf{y = -8 - 2}[/tex]

[tex]\large\textsf{-8 - 2 = \boxed{\bf -10}}[/tex]

[tex]\boxed{{\large\text{y = \bf -10}}}[/tex]

[tex]\boxed{\boxed{\large\text{Answer: \textsf{\huge \bf y = -10}}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

[tex]\quad\quad\quad\quad \tt{f(x) = 4x - 2}[/tex]

[tex]\quad\quad\quad\quad \tt{f( - 2) = 4( - 2)- 2}[/tex]

[tex]\quad\quad\quad\quad \tt{f( - 2) = ( - 8)- 2}[/tex]

[tex]\quad\quad\quad\quad \tt{f( - 2) = - 10}[/tex]

[tex]\quad\quad\quad\quad\boxed {\tt{\color{green}f( - 2) = - 10}}[/tex]

__________

#LetsStudy

Answer:

6.4 × 10 ^-5

Step-by-step explanation:

(0.04)^5 × 625 = 6.4 × 10^-5 (6.4e-5)

Answer:

B is the answer

Step-by-step explanation:

Answer:

perimeter = 25.62 units

Step-by-step explanation:

Let the quadrilateral be ABCD

A = (1, 5), B = (6, 5), C= (1, 11) , D = (6, 11)

To find the perimeter we need to add the lengths of sides AB , BC, CD, and AD.

Lets find the length of all sides using distance formula;

[tex]distance = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]

[tex]AB = \sqrt{(1-6)^2+(5-5)^2} = \sqrt{25} = 5units\\\\BC= \sqrt{(6-1)^2+(5-11)^2} = \sqrt{25+36} =\sqrt{61} units\\\\CD=\sqrt{(1-6)^2 + (11-11)^2} = \sqrt{25} = 5units\\\\AD = \sqrt{(1-6)^2+(5-11)^2} = \sqrt{25+36} = \sqrt{61}units[/tex]

Perimeter = AB + BC + CD + AD

               [tex]=10 + 2\sqrt{61} units[/tex] = 25.62 units

Answer:

A. x > -4

Step-by-step explanation:

< less than

>greater than

the unknown number x is greater than -4

{9, 8, 7, ...} the number is counting down. So the next number is 6.

is 6 greater than -4

or less than -4

therefore

x(which is 6) is greater than -4

x > -4

Answer:

c

Step-by-step explanation:

Step-by-step explanation:

It will take 42.35 minutes to weed the garden together.

Why?

To solve the problem, we need to use the given information about the rate for both Laura and her husband. We know that she can weed the garden in 1 hour and 20 minutes (80 minutes) and her husband can weed it in 1 hour and 30 minutes (90 minutes), so we need to combine both's work and calculate how much time it will take to weed the garden together.

So, calculating we have:

Laura's rate:

\frac{1garden}{80minutes}

80minutes

1garden

Husband's rate:

\frac{1garden}{90minutes}

90minutes

1garden

Now, writing the equation we have:

Laura'sRate+Husband'sRate=CombinedRateLaura

′

sRate+Husband

′

sRate=CombinedRate

\frac{1}{80}+\frac{1}{90}=\frac{1}{time}

80

1

+

90

1

=

time

1

\frac{1*90+1*80}{7200}=\frac{1}{time}

7200

1∗90+1∗80

=

time

1

\frac{170}{7200}=\frac{1}{time}

7200

170

=

time

1

\frac{17}{720}=\frac{11}{time}

720

17

=

time

11

\frac{17}{720}=\frac{1}{time}

720

17

=

time

1

\frac{17}{720}*time=1

720

17

∗time=1

time=1*\frac{720}{17}=42.35time=1∗

17

720

=42.35

Hence, we have that it will take 42.35 minutes to weed the garden working together.

Answer:

[tex]4.\ \sin E = \cos G[/tex]

Step-by-step explanation:

Given

[tex]\triangle EFG[/tex]

[tex]\angle F = 90^o[/tex] --- right angle

Required

Which of the options is true

In a triangle, we have:

[tex]\angle E + \angle F + \angle G = 180^o[/tex] --- angles in a triangle

Substitute [tex]\angle F = 90^o[/tex]

[tex]\angle E + 90^o + \angle G = 180^o[/tex]

Collect like terms

[tex]\angle E + \angle G = 180^o -90^o[/tex]

[tex]\angle E + \angle G =90^o[/tex]

This implies that E and G are complementary angles.

For complementary angles, E and G;

[tex]\sin E = \cos G[/tex] and [tex]\sin G = \cos E[/tex]

Hence, (4) is true

Answer:

I'm sorry hindi ko po alam eh

Let the third side be x :

( 3√5 )^2 = 6^2 + x^2

45 = 36 + x^2

x^2 = 45 - 36

x^2 = 9

x = 3

Answer: feugfberuyvfeygcreuyug

Step-by-step hththrhfhr

Answer: 80%

Step-by-step explanation:

Hence, if the numerator is decreased by 40% and the denominator is decreased by 25%, the original fraction is decreased by 80 percent.

Answer:

the answer is C

Step-by-step explanation:

Which type of triangle, if any, can be formed with sides measuring 8 inches, 8 inches, and 3

inches?

A. a scalene triangle

B. an equilateral triangle

C. an isosceles triangle

D. no triangle

Answer:

B.

Step-by-step explanation:

3/12 reduces to 1/4.

1/2 alone is greater than 1/4, so when 2/10 is added to 1/2, it is certainly greater than 3/12.

Answer: B.

Answer:

F

Step-by-step explanation:

Answer:

3/2

Step-by-step explanation:

(y-y)/(x-x)=-1+7/2+2=6/4=3/2

Answer:

Slope = 1.5

Step-by-step explanation:

m = (y₂ -y₁) / (x₂-x₁)

m = (-1+7) / (2+2)

m = 1.5

Answer:

( − 5 ) ( 3 + 1 )

Step-by-step explanation:

Use the sum-product pattern: 3 2 − 1 4 − 5

3 2 + − 1 5 − 5

Common factor from the two pairs: 3 2 + − 1 5 − 5

( 3 + 1 ) − 5 ( 3 + 1 )

Rewrite in factored form

Answer:

Step-by-step explanation:

Standard form:

3x2 − 14x − 5 = 0

Factorization:

(x − 5)(3x + 1) = 0

Solutions based on factorization:

x − 5 = 0   ⇒   x1 = 5

3x + 1 = 0   ⇒   x2 = −1

3

≈ −0.333333

Extrema:

Min = (2.333333, −21.333333)

Answer:

(3 x + 1 ) ( x − 5 )

Answer:

a) 120 possible experimental runs

b) 8 possible experimental runs

c) 0

Step-by-step explanation:

a. For the experiment, there are 6 different temperatures (T), 5 different pressures (P), and 4 different catalysts (C). We can find the total number of combinations using the product rule.

N = T × P × C

N = 6 × 5 × 4 = 120

b) If we use only the lowest temperature, we have T = 1, and if we use the two lowest pressures, we have P = 2. We can find the total number of combinations using the product rule.

N = T × P × C

N = 1 × 2 × 4 = 8

c) If we perform 5 experimental runs with 4 possible catalysts, it is not possible to use a different catalyst each time. At least, 1 catalyst must be repeated twice. Then, the event "a different catalyst is used on each run" has a probability of 0.

Answer:

Max (-7/2, 97/4)

Domain: all real numbers

Range: (negative infinity, 97/4)

Step-by-step explanation:

Im assuming this is a quadratic equation y = -x^2-7x+12

The max/min are the vertex (-b/2a)

Answer:

48 people.

Step-by-step explanation:

Each person gets 1/4 of a pizza meaning that one pizza can serve 4 people. If one pizza can serve 4 people, 12 pizzas can serve 48 people, because 4x12=48.

Answer:

A. 15.31

I did the standard deviation calculator and this is what I got

Answer:

[tex]Mean = 4[/tex]

Step-by-step explanation:

Given

[tex]f(x) =\left \{ {{\frac{c}{x^3} \ x\ge 2} \atop {0\ x<2}} \right.[/tex]

Required

The mean of x

Given that:

[tex]f(x) = \frac{c}{x^3}[/tex]     [tex]x \ge 2[/tex]

First, solve for c using;

[tex]\int\limits^a_b {f(x)} \, dx = 1[/tex]

Substitute [tex]f(x) = \frac{c}{x^3}[/tex] and [tex]x \ge 2[/tex]

[tex]\int\limits^{\infty}_2 {\frac{c}{x^3}} \, dx = 1[/tex]

Isolate c

[tex]c\int\limits^{\infty}_2 {\frac{1}{x^3}} \, dx = 1[/tex]

Rewrite as:

[tex]c\int\limits^{\infty}_2 {x^{-3}} \, dx = 1[/tex]

[tex]c[\frac{x^{-3+1}}{-3 +1}]|\limits^{\infty}_2 = 1[/tex]

[tex]c[\frac{x^{-2}}{-2}]|\limits^{\infty}_2 = 1[/tex]

[tex]-\frac{c}{2} [x^{-2}]|\limits^{\infty}_2 = 1[/tex]

Expand

[tex]-\frac{c}{2} [{\infty}^{-2} - {2}^{-2}]= 1[/tex]

[tex]-\frac{c}{2} [0 - \frac{1}{4}]= 1[/tex]

[tex]-\frac{c}{2} *- \frac{1}{4}= 1[/tex]

[tex]\frac{c}{8}= 1[/tex]

Solve for c

[tex]x = 8 * 1[/tex]

[tex]x = 8[/tex]

So, we have:

[tex]f(x) = \frac{c}{x^3}[/tex]     [tex]x \ge 2[/tex]

[tex]f(x) = \frac{8}{x^3}[/tex]     [tex]x \ge 2[/tex]

So, the mean is calculated as:

[tex]Mean = \int\limits^a_b {x * f(x)} \, dx[/tex]

This gives;

[tex]Mean = \int\limits^{\infty}_2 {x * \frac{8}{x^3}} \, dx[/tex]

[tex]Mean = \int\limits^{\infty}_2 {\frac{8}{x^2}} \, dx[/tex]

[tex]Mean = 8\int\limits^{\infty}_2 {\frac{1}{x^2}} \, dx[/tex]

Rewrite as:

[tex]Mean = 8\int\limits^{\infty}_2 {x^{-2} \, dx[/tex]

Integrate

[tex]Mean = 8 {\frac{x^{-2+1}}{-2+1}|\limits^{\infty}_2[/tex]

[tex]Mean = 8 {\frac{x^{-1}}{-1}}|\limits^{\infty}_2[/tex]

[tex]Mean = -8x^{-1}|\limits^{\infty}_2[/tex]

Expand

[tex]Mean = -8[(\infty)^{-1} - 2^{-1}][/tex]

[tex]Mean = -8[0 - \frac{1}{2}][/tex]

[tex]Mean = -8* - \frac{1}{2}[/tex]

[tex]Mean = 8* \frac{1}{2}[/tex]

[tex]Mean = 4[/tex]