I got three questions that need to be answered.

For questions 1-3, solve for x. Round your answer to the nearest tenth.

Answer:

24.5 unit²

Step-by-step explanation:

Area of ∆

= ½ | x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂) |

= ½ | (-1)(3 -(-4)) + 6(-4 -3) + (-1)(3 - 3) |

= ½ | -7 - 42 |

= ½ | - 49 |

= ½ (49)

= 24.5 unit²

Method 2:

Let the vertices are A, B and C. Using distance formula:

AB = √(-1-6)² + (3-3)² = 7

BC = √(-6-1)² + (-4-3)² = 7√2

AC = √(-1-(-1))² + (4-(-3))² = 7

Semi-perimeter = (7+7+7√2)/2

= (14+7√2)/2

Using herons formula:

Area = √s(s - a)(s - b)(s - c)

here,

s = semi-perimeter = (14 + 7√2)/2

s - a = S - AB = (14+7√2)/2 - 7 = (7 + √2)/2

s - b = (14+7√2)/2 - 7√2 = (14 - 7√2)/2

s - c = (14+7√2)/2 - 7 = (7 + √2)/2

Hence, on solving for area using herons formula, area = 49/2 = 24.5 unit²

Answer:

24.5

Step-by-step explanation:

To find the area with the coordinates provided:

(-1,3), (6,3), (-1,-4)

First we count the units that are inside the triangle which is area.

[tex]\frac{49}{2}[/tex]

So we know that there are [tex]\frac{49}{2}[/tex] units and then we divide 49 by 2 which gets you 24.5.

49 ÷ 2 = 24.5

The answer is 24.5 units.

Answer:

x = 2, y = 3

Step-by-step explanation:

Log x + log y = log 6         Log xy = Log 6            xy = 6

y = 6/x

Log(x-1)+2 Log y=2 Log 3

Log(x-1) = 2 Log 3 - 2 Log y = Log 3² - Log y² = Log 9 - Log y² = Log (9 / y²)

x - 1 = 9/y²

x - 1 = 9 / (6/x)² = 9 /(36/x²) = x²/4

4x - 4 = x²

x² -4x + 4 = 0

(x-2)² = 0

x = 2

y = 6/x = 3

Answer:

13/25

Step-by-step explanation:

if you put it in decimal the fraction is greater

Answer:

13/25 is larger then 50%

Step-by-step explanation:

13/25=52%

50%=12.5/25

Answer: 14 pages a day

Step-by-step explanation:

98 / 7 = 14

Answer: 14 pages read per day.

Step-by-step explanation:

98/7= 14

Hope this helps!

Answer:

No

Step-by-step explanation:

Solutions to systems of equations are points at which the lines of the equations intersect. Knowing this, only equations representing the same line would have infinitely many solutions because they would intersect at every one of each other's points - they're the exact same line. Therefore, if they are not the same line, they would not intersect at each and every point, and would not have infinitely many solutions.  

Answer:

(x-6)(x+2) D

Step-by-step explanation:

first you need to see which two numbers add up to -4 and multiply to -12 which is -6 and 2

Answer:

i believe the answer is A 90

Step-by-step explanation:

Answer:

x=29

Step-by-step explanation:

3x+15+2x+20=180

3x+2x+15+20=180

5x+35=180

5x=180-35

5x=145

x=145/5

x=29

Answer:

$12,500

Step-by-step explanation:

I got this answer by first taking the purchase price of the car and multiplying it by .10 to see what ten percent of the price was and I got $2,500. Then I took and multiplied 2,500 by 5 years and go 12,500. Then I subtracted 12,500 from the original purchase price to get $12,500. Meaning that the value of the care has decreased by half of the purchase price.

HOPE THIS HELPS!

Answer:

8.93h in³

Step-by-step explanation:

The circumference of the base of the cone is 8.5pi inches. What is the volume of the cone in terms of ne? Round to the nearest hundredth. Enter

Step 1

We find the radius of the cone

Base area = 8.5 π inches

Radius = √Area/π

Radius = √8.5 π /π

Radius = √8.5

Radius of the cone = 2.9154759474 inches

Approximately = 2.92 inches

Step 2

We find the volume of the cone

= πr²h/3

Height is not given, so we find in terms of h

= π × 2.92² × h/3

= 8.9288252005h in³

Approximately = 8.93h in³

The

Answer:

The second and third one

Step-by-step explanation:

According to the statement, numbers between 4 and 5 is 4.1 - 4.9

But it is doubled so it is 8.2 - 9.8

These numbers are greater than 8 and less than 9

These numbers are also greater than 9 and less than 10

Answer:

82

Step-by-step explanation:

Sides AB and BC are equal, which means angle BAC and BCA have the same measure, as stated in the base angles theorem. Angle BAC is 49 degrees, so angle BCA must also be 49 degrees. The sum of all angles in a triangle is 180 degrees, so angles BAC, BCA, and CBA will add up to 180. Write this in an equation:

BAC+BCA+CBA=180

BAC and BCA both measure 49 degrees:

49+49+CBA=180

Solve for CBA

CBA=180-49-49

CBA=82

lmk if i made any errors, hope this helps :)

Answer:

Then, the polynomial [tex]x^{2}+11\cdot x + 30[/tex] is equal to the product of the binomials [tex](x+5)[/tex] and [tex](x+6)[/tex].

Step-by-step explanation:

The polynomial [tex]x^{2}+11\cdot x + 30[/tex] is a polynomial of the form [tex]x^{2} - (r_{1}+r_{2})\cdot x + r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})[/tex], where [tex]r_{1}[/tex] and [tex]r_{2}[/tex] are the roots of the polynomial. Then, we find the following system of equations:

[tex]-r_{1}-r_{2} = 11[/tex] (1)

[tex]r_{1}\cdot r_{2} = 30[/tex] (2)

After some algebraic handling, the solution of this system is [tex]r_{1} = -5[/tex] and [tex]r_{2} = -6[/tex].

Then, the polynomial [tex]x^{2}+11\cdot x + 30[/tex] is equal to the product of the binomials [tex](x+5)[/tex] and [tex](x+6)[/tex].

Answer:

it will take 4 months

Step-by-step explanation:

Answer:x=-7

Step-by-step explanation:

Step-by-step explanation:

I'm not sure it's probably x=-2

The figure that shows a reflection of pre-image ABC over the y-axis is the third figure.

From the complete information, the triangle ABC is reflected over the y axis.

The vertices of the triangle are A(1, 1), B(3, 4) and C(3, 1). The vertices of the images are A(1, 1) = A'(-1, 1). B(3, 4) = B(-3, 4) ans C(3, 1) = C'(-3, 1).

In conclusion, the figure that shows a reflection of pre-image ABC over the y-axis is the third figure.

Learn more about reflection on:

https://brainly.com/question/3643476

Answer:

i think its c

Step-by-step explanation:

its not a or b

Answer:

C. cubic

Step-by-step explanation:

Correct on Edge 2021!!!

Answer:

V=128

Step-by-step explanation:

Answer:

V =128ft^3

Step-by-step explanation:

V=lwh=4*4*8=128

Step-by-step explanation:

-3. 2

-2. 1

-7. 6

i did my best.

Answer:

- 3.4(21) = - 71.4

(- 2.3)(- 7.9) = 18.17

9.24 ÷ - 7 = -1.32

(- 8.5) ÷ (- 3.4) = 2.5

- 6.85 ÷ 0.5 = - 13.7

Answer:

point estimate: .73

margin of error: .02

Step-by-step explanation:

correct on edg

Answer:

[tex]2^x-4=32\quad :\quad x=\frac{2\ln \left(6\right)}{\ln \left(2\right)}\quad \left(\mathrm{Decimal}:\quad x=5.16992\dots \right)\\\\2^x-4=32 \\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\2^x-4+4=32+4\\\mathrm{Simplify}\\2^x=36\\\\apply exponential rule\\x\ln \left(2\right)=\ln \left(36\right)\\x\ln \left(2\right)=\ln \left(36\right)\\x=\frac{2\ln \left(6\right)}{\ln \left(2\right)}[/tex]

hope it helps:)

Answer: $67.15

Step-by-step explanation:

Answer:

Both A and B are possible.

Step-by-step explanation:

It's both!

This is a might tricky. First you have to find the altitude. You have to determine if this is a real triangle.

Sin(22) = opposite / hypotenuse. The hypotenuse = 111. The angle is 22

opposite = hypotenuse * sin(22)

opposite = 111 * sin(22)

opposite = 41.58  and this is the altitude.

What have you learned?

Since 42 is larger than 41.58 you have 2 solutions to the triangle. One of the angles is acute, and the other one is obtuse. They are supplementary angles.

Sin(C) / c = Sin(A) / a

Sin(C) = c * Sin(22) / 42

Sin(C) = 111*sin(22)/ 42

Sin(C) = .99003

Sin(C) = 81.9

So that's your first answer. The second answer comes from Finding the supplement to this angle

supplement + 81.9 = 180

supplement = 180 - 81.9

supplement = 98.1

Answer:

Step-by-step explanation:

Each part is equal to 65/(1+4)=$13

Since Stephanie only got 1 part, she got $13.

Answer:

Ecuación estándar de un círculo

(x−2)2+(y−2)2=25

Forma general de la ecuación de un círculo

x2−4x+y2−4y−17=0

Ecuaciones paramétricas de un círculo

x=5cosθ+2y=5sinθ+2

Step-by-step explanation:

Ecuación Estándar de un Círculo

La ecuación estándar de un círculo con el centro en (x_0, y_0) y radio r es

(x^2-x_0) + (y^2-y_0)=r^2

Ecuaciones Paramétricas de un Círculo

Las ecuaciones paramétricas de un círculo con el centro en (x_0, y_0) y radio r son

x=r cos \theta + x_0\\y=r sin \theta + y_0

Ecuación General de un Círculo

La ecuación general de un círculo con el centro en (x_0, y_0) y radio r es

x^2+ax+y^2+by+c=0,

donde

a=-2x_0\\b=-2y_0\\c=x^2_0+y^2_0-r^2