Hydrogen peroxide and water both contain the same two elements. Write their chemical formulas. Compare and contrast their properties. Explain the importance of writing correct chemical formulas

Answers

Answer 1

Hydrogen peroxide and water both contain the same two elements. The chemical formulas of hydrogen peroxide and water are respectively H2O2 and H2O. The two compounds have distinct physical and chemical properties. Here is a long answer to the question posed.



Water is a colorless, odorless, and tasteless liquid that is vital for life. Its melting point is 0 degrees Celsius, while its boiling point is 100 degrees Celsius. Water is the most prevalent chemical substance on Earth, with about 71% of the planet's surface covered by it.

Hydrogen peroxide is a pale blue liquid that is slightly more viscous than water. It has a bitter taste, and its odor is similar to that of bleach. The boiling point of hydrogen peroxide is 150.2°C, while the melting point is -0.43°C. Hydrogen peroxide is a powerful oxidizer that is commonly used as a bleaching agent, disinfectant, and antiseptic.


Chemical formulas are utilized in a variety of scientific applications, including chemical reactions and product descriptions. An incorrect chemical formula can have significant ramifications, potentially resulting in the formation of a hazardous substance.

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Related Questions

Consider the equilibrium system described by the chemical reaction below, which has a value of Kc equal to 1.79 at a certain temperature. If a reaction mixture initially contains 0.050 M H2S and 0.050 M SO2, what will the equilibrium concentration of H20 be? 2 H2S(g) + SO2(g) ⇄ 3 S(s) + 2 H2O(g)

Answers

Equilibrium is a state of a reversible chemical reaction where the rates of forward and reverse reactions become equal, which results in the concentration of reactants and products being constant.

The chemical equation of the system described above is:2 H2S(g) + SO2(g) ⇄ 3 S(s) + 2 H2O(g)This system has an equilibrium constant (Kc) equal to 1.79 at a certain temperature. When the reaction mixture initially contains 0.050 M H2S and 0.050 M SO2, the equilibrium concentration of H2O can be found out as follows:As per the given equation, the mole ratio of H2S to H2O is 2:2 or 1:1. Therefore, the initial concentration of H2O is zero.The initial concentration of H2S is 0.050 M.Therefore, according to the equilibrium constant expression for this reaction, we can say that:[tex]\begin{align*}{K_c}&=\frac{\mathrm{[S]^3[ H_2O]^2}}{\mathrm{[ H_2S]^2[SO_2]}} \\ \\{1.79}&=\frac{\mathrm{(0.0.0.050)^2 [H_2O]^2}}{\mathrm{(0.050)^2 (0.050)}} \\ \\{1.79} \times \mathrm{(0.050)^3}&= \mathrm{[H_2O]^2} \\ \\{\mathrm{[H_2O]}}&= \sqrt{\mathrm{1.79} \times \mathrm{(0.050)^3}} \\ \\{\mathrm{[H_2O]}}&= \mathrm{0.027\ M} \end{align*}[/tex]Thus, the equilibrium concentration of H2O is 0.027 M.

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if 4.10 grams of chromium is heated with 9.30 grams of chlorine what mass of chromium(III) chloride is produced?​

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Answer:

4.1g of Cr will make (317/104) x 4.1 = 12.5g of CrCl3

During strenuous exercise, lactic acid builds up in muscle tissues. In a 1.00 M aqueous solution, 2.94% of lactic acid is ionized. What is the value of Ka for lactic acid?

Answers

The value of Ka for lactic acid is approximately 0.0303. To find the value of Ka for lactic acid, we can use the ionization percentage and the initial concentration of the acid.

Given that 2.94% of lactic acid is ionized in a 1.00 M solution, we can calculate the concentration of the ionized form ([tex]CH_{3}CH(OH)COO-[/tex]) by multiplying the ionization percentage by the initial concentration of the acid: [[tex]CH_{3}CH(OH)COO-[/tex]] = 2.94% × 1.00 M = 0.0294 M

Since lactic acid ([tex]CH_{3}CH(OH)COO-[/tex]) is a monoprotic acid, the concentration of the undissociated form is equal to the initial concentration minus the concentration of the ionized form: [[tex]CH_{3}CH(OH)COOH[/tex]] = 1.00 M - 0.0294 M = 0.9706 M

The equilibrium expression for the ionization of lactic acid can be written as: Ka = [[tex]CH_{3}CH(OH)COO-[/tex]] / [[tex]CH_{3}CH(OH)COOH[/tex]]

Substituting the values, we get: Ka = 0.0294 M / 0.9706 M = 0.0303

Therefore, the value of Ka for lactic acid is approximately 0.0303.

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For the following equilibrium, BaSO4(s) = Ba² + (aq) + S0 - (aq) if HCl is added, how will the quantities of each species change? Select the correct answer below: [Ba2+] increases, (so-1 decreases, mass of solid decreases O [Ba? +1 decreases, (so 1 decreases, mass of solid decreases [Ba? increases, so increases, mass of solid increases [Ba²+] decreases, (so increases, mass of solid increases

Answers

Adding HCl to the equilibrium BaSO4(s) ⇌ Ba²+(aq) + SO4²-(aq) will result in an increase in [Ba²+] and a decrease in [SO4²-]. The mass of the solid BaSO4 will also decrease.

When HCl is added, it dissociates into H+ and Cl- ions. The H+ ions react with the SO4²- ions from the dissociation of BaSO4, forming HSO4- ions and shifting the equilibrium to the right. As a result, more Ba²+ ions are released into the solution, leading to an increase in [Ba²+]. On the other hand, the decrease in [SO4²-] occurs because some of the SO4²- ions combine with H+ ions to form HSO4-. Since the equilibrium is being driven towards the products, the concentration of Ba²+ increases, [SO4²-] decreases, and the mass of the solid BaSO4 decreases.

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2 questions. will give brainliest if i can figure out how

What happens to the electrons of a reducing agent during a reaction?
a.Electrons are gained
b.Electrons are lost
c.Electrons are held
d.Electrons are doubled

When is a substance reduced during an oxidation reduction reaction?
a.After one substance is oxidized
b.Before one substance is oxidized
c.Same time as one substance is being oxidized
d.Only oxidation occurs

Answers

1= b. electrons are lost

2= a. after one substance is oxidized

Which of the following are conjugate acid/base pairs? Select all that apply.
a. NaCl and NaOH
b. HCl and Cl-
c. H2SO4 and SO42-
d. H3PO4and H2PO4-
e. H2CO3 and CO32

Answers

The following are conjugate acid/base pairs:

HCl and Cl-.H2SO4 and SO42-.H3PO4 and H2PO4-.H2CO3 and CO32-.

Explanation:

In the acid-base reaction, the acid donates the proton (H+) while the base receives the proton. The substance that loses its proton becomes a conjugate base while the substance that gains a proton becomes the conjugate acid.

The conjugate acid/base pairs differ by one proton (H+).

NaCl and NaOH are not conjugate acid/base pairs as they are not acids or bases. NaOH is a strong base while NaCl is a neutral salt.

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Which of these would be found in a wetland?
Mrs. Cornell and vultures
Cattails and salamanders
Maple trees and cats
Oak trees and squirrels

Answers

Answer:

jwjsjdjdhdvjeiejjrjrje

how might using water somethimes require changing its original state?

Answers

When water changes state in the water cycle, the total number of water particles remains the same. The changes of state include melting, sublimation, evaporation, freezing, condensation, and deposition. All changes of state involve the transfer of energy.

compute the equilibrium constant for the spontaneous reaction between sn2 (aq) and fe(s) . express your answer using two significant figures.

Answers

The equilibrium constant for the given reaction is 0.93 (to two significant figures). Hence, the answer is 0.93.

Given, spontaneous reaction between Sn2(aq) and Fe(s) is:Sn2(aq) + Fe(s) → Sn(s) + Fe2+(aq)The standard reduction potentials for Sn2+(aq) and Fe2+(aq) are given as:Sn2+(aq) + 2e- → Sn(s); E°red = -0.14 VFe2+(aq) + 2e- → Fe(s); E°red = -0.44 VThe cell potential (E°cell) for the spontaneous reaction can be calculated using the formula: E°cell = E°reduction at cathode - E°reduction at anodeE°cell = E°red of Fe2+ - E°red of Sn2+E°cell = (-0.44 V) - (-0.14 V)E°cell = -0.3 VThe standard equilibrium constant (K°) can be calculated using the relation: ΔG° = -RTlnK°Here, ΔG° is the change in Gibbs free energy for the reaction, R is the gas constant, and T is the temperature in Kelvin.Assuming T = 298 K, we can use R = 8.314 J/mol*K.ΔG° = -nFE°cellHere, n is the number of electrons transferred in the reaction and F is the Faraday constant (96485 C/mol).n = 2 for the given reaction.ΔG° = -2 * 96485 C/mol * (-0.3 V)ΔG° = 58.32 kJ/molSubstituting the values of R, T, and ΔG° in the equation ΔG° = -RTlnK°, we get:lnK° = -ΔG°/RTlnK° = -(58.32 kJ/mol) / (8.314 J/mol*K * 298 K)lnK° = -0.0737K° = e-lnK°K° = e0.0737K° = 0.93The equilibrium constant for the given reaction is 0.93 (to two significant figures). Hence, the answer is 0.93.

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How are organisms classified as Eukarya different from organisms classified as Archaea and Bacteria?

A)They are all multicellular.
B)They all produce their own food.
C) They all reproduce sexually.
D) They all have membrane-bound nuclei

Answers

Answer: D

Explanation: The Eukarya differ from the Archea and Bacteria in that their cells are eukaryotic, meaning they contain a membrane enclosed nucleus and other membrane enclosed organelles.

Eukarya is different from organisms classified as Archaea and Bacteria because Eukarya have membrane-bound nuclei. Therefore, option (D) is correct.

How does the classification of Eukarya differ from Archaea?

The type of cell of the organism can be classified into three domains. First is the bacteria which have no nucleus present in cells. Then Archaea have no nucleus in the cells but they have a different cell wall than bacteria. Then Eukarya have a nucleus in them.

The domains of Archaea and Bacteria are both composed entirely of small, single-celled organisms but they also have differences. All are composed of prokaryotic cells, which are nucleus-less cells.  T

All the cells in the Eukarya domain contain their genetic material or DNA within the nucleus. Four classes make up the Eukarya domain: Plantae, Fungi, Animalia, and Protista.

Therefore, the domain of the Eukarya is different from organisms classified as Archaea and Bacteria as Eukarya have membrane-bound nuclei.

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What does the first ionization energy represent?

Answers

I believe it is A. The first option

a 0.0280 m solution of an organic acid has an [h ] of 1.60×10-3 m .Using the values above, calculate the pH of the solution. What is the percent ionization of the acid? Calculate the Ka value of the acid.

Answers

The pH of the solution is 2.80, the percent ionization of the acid is 5.71%, and the Ka value of the acid is 9.14 × 10-5.

A.0280 M solution of an organic acid has an [H] of 1.60×10-3 M.Using the values above, the pH of the solution, the percent ionization of the acid, and the Ka value of the acid are given below:pH of the solution: The formula for calculating the pH of a solution is as follows:pH = -log[H] = -log[1.60 × 10-3] = 2.80Percent ionization of the acid:Percent ionization is given by the following formula:Percent ionization = ( [H+]/[HA] ) × 100 = (1.60 × 10-3/0.0280) × 100 = 5.71%Ka value of the acid:The formula for calculating the Ka value of an acid is as follows:Ka = [H+]2 / [HA]Ka = [1.60 × 10-3]2 / [0.0280]Ka = 9.14 × 10-5Hence, the pH of the solution is 2.80, the percent ionization of the acid is 5.71%, and the Ka value of the acid is 9.14 × 10-5.

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What is the proper disposal of all chemicals in this reaction? Briefly explain any hazards associated with barium nitrate and silver nitrate

Answers

Barium nitrate is toxic if ingested or inhaled, while silver nitrate is corrosive and can cause severe skin and eye irritation.

What are the potential hazards associated with barium nitrate and silver nitrate, and how should they be properly disposed of?


Barium nitrate is toxic if ingested or inhaled, posing risks to the respiratory, cardiovascular, and nervous systems. It can also harm aquatic life if released into water bodies. Silver nitrate is corrosive and can cause severe irritation and burns to the skin and eyes. To properly dispose of these chemicals, consult local waste management authorities for specific guidelines. Follow any recommended neutralization procedures, use suitable containers for storage, and label them clearly with the contents and hazards. Engage a licensed waste disposal company or hazardous waste facility to ensure proper collection and disposal. Adhering to local regulations and best practices is crucial to minimize the environmental and health risks associated with these chemicals.

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balance
A FeS2 + B O2 → C Fe2O3 + D SO2 *

Answers

Answer:

4FeS2 + 6O2 > 2Fe2O3 + 8SO2

Explanation:

HELP ME! is iodine solution polar, non-polar, or ionic?

Please don't attach links, i will report you

Answers

Answer:

Since the iodine-iodine bond is a pure covalent bond, iodine is a non-polar molecule. The electronegativity difference between the two Iodine atoms is zero.

does this help???

When we celebrate a new year we are really celebrating what?

Answers

We are celebrating a fresh start to another year

enzymes act as catalysts because they: group of answer choices decrease the enthalpy of the products. increase the entropy of the products.

Answers

Enzymes act as catalysts because they decrease the activation energy required to initiate a chemical reaction.

Why enzymes are considered as catalysts?

Enzymes are molecules that accelerate chemical reactions by lowering the energy barrier (activation energy) for the transition state of the reaction. Enzymes bind to substrates, which are the reactants of the reaction.

The binding of the substrate to the enzyme lowers the energy required to transition the reactants to the transition state. This results in the lowering of activation energy that is required for a reaction to proceed

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How is oxide different from a neutral oxygen atom

Answers

Answer: The main difference between oxide and oxygen is that oxide is a chemical compound with at least one oxygen atom while oxygen is an element whose atomic number is 8.

Explanation: let me know if it was right or wrong

a 900 w carbon-dioxide laser emits light with a wavelength of 10μm into a 3.0-mm-diameter laser beam.

Answers

The 900 W carbon-dioxide laser emits light with a wavelength of 10 μm into a 3.0 mm diameter laser beam. This means that the laser is producing a high-power output in the infrared region of the electromagnetic spectrum.

The wavelength of 10 μm corresponds to the mid-infrared range, which is commonly used in various applications such as industrial cutting and welding, medical procedures, and scientific research.

The 3.0 mm diameter laser beam represents the spatial profile of the laser output. It indicates that the laser beam has a relatively small cross-sectional area, allowing for focused and concentrated energy delivery.

The combination of a high-power output and a specific wavelength allows the carbon-dioxide laser to efficiently perform tasks that require precision and controlled energy deposition, making it suitable for a wide range of industrial and scientific applications.

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A 0.330 gram sample of an unknown, monoprotic acid (the molar ratio between acid and base is 1-to-1) was dissolved in 50.0 mL of water and titrated to equivalence point with 22.00 mL of 0.150 M NaOH. Determine the molar mass of the the unknown aci

Answers

The molar mass of the unknown monoprotic acid will be approximately 100 g/mol.

To determine the molar mass of unknown monoprotic acid, we will use the concept of stoichiometry.

First, let's calculate the number of moles of NaOH used in the titration:

Moles of NaOH = concentration of NaOH × volume of NaOH used

= 0.150 mol/L × 0.02200 L

= 0.00330 mol

Since the acid and base have a 1-to-1 molar ratio, the number of moles of the unknown acid is also 0.00330 mol.

Next, let's calculate the molar mass of the unknown acid:

Molar mass of the unknown acid = mass of the unknown acid / moles of the unknown acid

We are given the mass of the unknown acid as 0.330 grams and the moles of the unknown acid as 0.00330 mol.

Molar mass = 0.330 g / 0.00330 mol

= 100 g/mol

Therefore, the molar mass is 100 g/mol.

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Which of these objects is made of cells?
A. rocks B. snow C. trees D. water

Answers

Answer:

I think it's trees

Explanation:

I'm not 100% sure tho

In the following molecules, the primary intermolecular attractive force is

Answers

Answer:

Dipole-dipole

Explanation:

please help me with these questions, im not understanding :(

Answers

Answer:

this is all the answers i hope you have a good day

Explanation:

may i please have a branlliests

A combustion reaction is a common reaction used to produce energy. Write a combustion reaction for the combustion of ethanol, C₂H5OH. View Available Hint(s) C,HyOH + 3 Oz → 2 CO, + 3 H,O C₂H5OH(

Answers

Combustion reaction is a common reaction used to produce energy. The reaction that describes the combustion of ethanol, C₂H5OH is as follows:

C₂H5OH + 3O₂ → 2CO₂ + 3H₂O
The energy released by the combustion reaction is used to generate electricity or to power machines and vehicles.

This reaction is a chemical process in which a fuel reacts with oxygen to produce heat and light energy. Ethanol is a colorless liquid with a formula of C₂H₅OH. It is an important biofuel and is commonly used as a fuel additive to gasoline. In the combustion process, ethanol reacts with oxygen to produce carbon dioxide and water vapor.Combustion reactions are exothermic reactions that release energy in the form of heat and light. They are commonly used in engines and power plants to produce energy from fuels. The energy released by the combustion reaction is used to generate electricity or to power machines and vehicles.

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Identify which properties are common to each of the following chemical families

(a) alkali metals

(b) alkaline earth metals

(c) halogens

(d) noble gases

Answers

The noble gases have a full outer shell of valence electrons, making them stable and unreactive. They are colorless, odorless gases at room temperature and have very low boiling points. Their lack of reactivity makes them useful in a variety of applications, including lighting and welding.

The properties that are common to each of the following chemical families include:

(a) Alkali metals The alkali metals have a single valence electron in their outermost shell, which is easily lost to form an ion with a charge of +1. They are the most reactive metals, reacting with water and air to produce hydrogen gas and an oxide layer, respectively. They are silvery-white and have a soft texture.

(b) Alkaline earth metals The alkaline earth metals have two valence electrons in their outermost shell, which they readily lose to form ions with a charge of +2. They are less reactive than the alkali metals, but they still react with oxygen to form an oxide layer on their surface. They are also silvery-white in color and have a harder texture than the alkali metals.

(c) Halogens The halogens have seven valence electrons in their outermost shell, making them highly reactive nonmetals. They readily form ions with a charge of -1 by gaining an electron. They are diatomic molecules at room temperature and can be found in a variety of colors and states of matter.

(d) Noble gases The noble gases have a full outer shell of valence electrons, making them stable and unreactive. They are colorless, odorless gases at room temperature and have very low boiling points. Their lack of reactivity makes them useful in a variety of applications, including lighting and welding. These properties are common to each of the following chemical families.

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92.12 kJ of heat is required to convert 58.40 g of gold from liquid to gas phase. What is the heat of vaporization of gold in J/g?

Answers

Answer:

The heat of vaporization of the gold sample is 1577.397 joules per gram.

Explanation:

The latent heat of vaporization of gold ([tex]h_{v}[/tex]), in kilojoules per gram, is the heat required by a unit mass of gold to transform the material from liquid to gas:

[tex]h_{v} = \frac{E}{m}[/tex] (1)

Where:

[tex]E[/tex] - Energy required for vaporization, in joules.

[tex]m[/tex] - Mass, in grams.

If we know that [tex]E = 92120\,J[/tex] and [tex]m = 58.40\,g[/tex], then the heat of vaporization of the gold sample is:

[tex]h_{v} = \frac{E}{m}[/tex]

[tex]h_{v} = 1577.397\,\frac{J}{g}[/tex]

The heat of vaporization of the gold sample is 1577.397 joules per gram.

what were the advantages and disadvantages of each measuring device?

Answers

To assess the advantages and disadvantages of different measuring devices, specific devices need to be mentioned. Without specific devices, a comprehensive analysis of their advantages and disadvantages is not possible.

The advantages and disadvantages of measuring devices vary depending on the specific device and its application. Different devices have unique features and limitations that affect their accuracy, precision, ease of use, and suitability for different measurements. For example, consider two commonly used measuring devices: a ruler and a digital caliper. A ruler, while simple and inexpensive, may have limitations in terms of precision and accuracy due to human error in reading the markings. On the other hand, a digital caliper offers higher precision and accuracy, as it provides digital readouts and can measure small distances with greater precision. However, digital calipers may be more expensive and require batteries for operation.

Other factors to consider when evaluating measuring devices include durability, range of measurements, calibration requirements, ease of calibration, portability, and the specific needs of the measurement task at hand. To provide a more detailed analysis, it would be helpful to specify the measuring devices being compared.

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Considering the limiting reactant concept, how many moles of C are produced from the reaction of 1.00 mol A and 1.00 mol B?
A(g) + 2 B(g) → 3 C(g)
Please show all work, thank you.

Answers

1.50 mol of C are produced from the reaction of 1.00 mol A and 1.00 mol B.

The balanced chemical equation for the given reaction is A(g) + 2 B(g) → 3 C(g). This equation can be used to determine the number of moles of C produced from the reaction of 1.00 mol A and 1.00 mol B. The limiting reactant concept must be considered to solve this problem.Limiting reactant:The limiting reactant is the reactant that is completely consumed in a chemical reaction. In other words, the reactant that runs out first limits the amount of product that can be formed.To determine the limiting reactant, the stoichiometry of the chemical reaction must be used. This involves using the mole ratios from the balanced chemical equation to determine how much product can be formed from each reactant.Let's calculate the number of moles of C that can be produced from 1.00 mol A:A(g) + 2 B(g) → 3 C(g)Molar ratio of A to C = 1 : 3From the balanced equation, 1 mol of A produces 3 mol of C. Therefore, 1.00 mol A will produce 3.00 mol C.Let's calculate the number of moles of C that can be produced from 1.00 mol B:A(g) + 2 B(g) → 3 C(g)Molar ratio of B to C = 2 : 3From the balanced equation, 2 mol of B produces 3 mol of C. Therefore, 1.00 mol B will produce 1.50 mol C.The actual amount of product that can be formed is limited by the smaller of these two values. In this case, 1.50 mol C is the smaller value, so 1.50 mol C is produced from the reaction of 1.00 mol A and 1.00 mol B.Answer:1.50 mol of C are produced from the reaction of 1.00 mol A and 1.00 mol B.

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Hydrogen-3 has a half-life of 12.3 years. How many years will it take for 539.3 mg 3^H to decay to 2.1 mg 3^H? time to decay:________________________________________________ years Sodium-24 has a half-life of 14.8 hours. How much of a 563.3 mg sodium-24 sample will remain after 3.7 days? mass remaining:_____________________________________________ mg.

Answers

Approximately 4.41 mg of the sodium-24 sample will remain after 3.7 days.

Part A - Hydrogen-3 decay. The half-life of Hydrogen-3 is 12.3 years, and we have to find the time that would take for 539.3 mg 3^H to decay to 2.1 mg 3^H. Let's use the formula given below and find out how many years it will take. Amount = Initial amount * (1/2)^(Time/half life). Initial amount = 539.3 mg. The amount left = 2.1 mg. Time = ?Half-life = 12.3 years. Amount left/Initial amount = (1/2)^(Time/half-life)2.1/539.3 = (1/2)^(Time/12.3)log(2.1/539.3) = log(1/2)^(Time/12.3)(Time/12.3) = log(539.3/2.1) / log2. Time = 12.3 * log(539.3/2.1) / log2Time = 12.3 * 11.3949 / 0.30103. Time = 466.95 years. Therefore, it would take approximately 466.95 years for 539.3 mg 3^H to decay to 2.1 mg 3^H.

Part B - Sodium-24 decay. The half-life of Sodium-24 is 14.8 hours. Let's find out how much of a 563.3 mg sodium-24 sample will remain after 3.7 days. Initial amount = 563.3 mg. Half-life = 14.8 hours. We need to find the amount left after 3.7 days (88.8 hours). Amount = Initial amount * (1/2)^(Time/half-life). Amount = 563.3 * (1/2)^(88.8/14.8)Amount = 563.3 * (1/2)^6Amount = 4.41 mg. Therefore, approximately 4.41 mg of the sodium-24 sample will remain after 3.7 days.

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the formulas of three important acids and three important bases and describe their uses.

Answers

Answer:

18929eu9sisjwiejwjxjjejxme

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What is the difference in the number of years? (Round your answer to the nearest tenth, if necessary) You are given the line y=-2x-5, and it then shifted up 2 units. Write your equation of the new line. . What's another way to say "an author's perspective"? Okay this will give you brainliest just pls help 12. (a) Copy the T-accounts that follow: Salaries Expense Salaries Payable Dec. 31 29 000 Dec. 31 145 (b) At the end of the fiscal period, $1750 is owed to the employees. Prepare the adjusting entry to record the salaries owing. (c) Post the adjusting entry to the T-accounts. 13. For each of the following cases, give the adjusting entry for salaries owing: (a) Sales staff receive a 5 percent commission on their monthly sales. In May, they sold $26 000 worth of goods for which they are to be paid on June 30. The date of the adjustment is May 31. (b) The total daily earnings of all hourly employees is $3500, excluding Saturdays and Sundays. They are paid every Friday. What will the adjusting entry be if the financial statements are prepared as It the end of the work day on Wednesday? Why does the farmer arrive at themarket too late? Bearcat Construction begins operations in March and has the following transactions. March 1 Issue common stock for $16,500. March 5 Obtain $8,100 loan from the bank by signing a note. March 10 Purchase construction equipment for $20,500 cash. March 15 Purchase advertising for the current month for $1,100 cash. March 22 Provide construction services for $17,100 on account. March 27 Receive $12,100 cash on account from March 22 services. March 28 Pay salaries for the current month of $5,100.Required: Record each transaction. Magic Video Games, Inc., sells an expensive video gamespackage. Because the package is so expensive, the company wants to advertise an impressive guaranteefor the life expectancy of its computer control system.The guarantee policy will refund the full purchase price if the computer fails during the guarantee period.The research department has done tests that show that the mean life for the computer is 35 months, with standard deviation of 5 months. The computerlife is normally distributed. How long can the guarantee period be if management does not want to refund the purchase price on more than 6.596 of theMagic Video packages? U is the set of integers. G is the set of negative integers. What is the complement of set G in universive U?Pls help fast Subtract 11x - 4y from the sum of 15x + 15y and - 18x + 15y. Speculator is willing to create an arbitrage strategy on the derivative market. The spot price of zero-coupon bond with face of 120 GBP and remaining maturity of 1.5Y is 100 GBP. The spot risk-free market rate for 8M period is 12% pa. under continuous compounding. What should be speculator's arbitrage strategy if speculator could write / enter an 8M forward contract with: a. delivery price of 110 GBP, b. delivery price of 102 GBP. LOOK AT THE PHOTO AND ANSWER PLEASE If 10 is the area of a circle what is the radius? The area of a square can be found using the equation A = s, where A is the area and s is the measure of one side of the square.Match the equation for how to solve for the side length of a square to its description.Drag the equation into the box to match the description.--------------------------------------------------------------------------------------------------------[ A square has an area of 99 in ][ - ]--------------------------------------------------------------------------------------------------------A.) s=/99inB.) s=(99)^2inC.) s=99in the basics of color theory assume what central tenets What is the length of the diameter? 1.Explain why we need unit root test for stationary and the meaning of a spurious regression.2.What are autocorrelation and Durbin-Watson test? And how are they related?3. Explain the concept of VAR and VEC model and how they differ?4.Explain the characteristic of an ARDL and its application5.Explain the concept of cointegration and show how to perform the test for cointegration6.Briefly explain these following tasks of heteroskedasticity: (1) the meaning of heteroskedasticity; (2) how to detect heteroskedasticity; (3) heteroskedasticity consequences for the OLS Estimation