How many moles are 3.21×10^28 molecules of N2?

Answer:

B. Indicator

Explanation:

An indicator is used to determine whether an acid or alkali has been added to a solution.

Indicators can be liquid or a paper called litmus paper. There also some digital forms of indicators that can tell whether an acid or alkali has been added to a solution.

Answer:

[tex]4.86\times10^{-7}\ \text{m}[/tex]

Explanation:

R = Rydberg constant = [tex]1.09677583\times 10^7\ \text{m}^{-1}[/tex]

[tex]n_1[/tex] = Principal quantum number of an energy level = 2

[tex]n_2[/tex] = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

[tex]\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}[/tex]

The wavelength of the light emitted is [tex]4.86\times10^{-7}\ \text{m}[/tex].

Answer:Ion-dipole

Explanation:

Answer:

Dissolves a chemical sample well at high temperatures.

Does not dissolve a chemical sample well at low temperatures.

Explanation:

Recrystallization is a purification technique that involves mixing of an impure solid compound with a hot solvent leading to a saturated solution. As this solution cools, the compound to be purified becomes less soluble in the solvent, and pure crystals appear from the solution as the solution cools.

A good recrystallization solvent should

Answer:

No matter how many times you cut it, its chemical properties won't change and it'll still be paper.

Explanation:

Answer:

249 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 5.00 moles of C₃H₈

The molar ratio of C₃H₈ to CO₂ is 1:3. The moles of CO₂ produced are 3/1 × 5.00 mol = 15.0 mol

Step 3: Convert "30.0°C" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 30.0°C + 273.15 = 303.2 K

Step 4: Calculate the volume of carbon dioxide

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 15.0 mol × 0.0821 atm.L/mol.K × 303.2 K/1.50 atm

V = 249 L

Answer:

Moon has to be in-between the Earth and the Sun.

2. Moon's umbra should sweep your place.

3. Latitude and longitude of your place should be within the befitting limits.

Answer:

2 atm

Explanation:

The symbol 'atm' is used for pressure. Hence, the symbol used to indicate the pressure at which a chemical reaction is carried out can be, 2 atm.

Answer:

Explanation:

Energy

Answer:

Explanation:

From the combustion of carbon, the reactions occurring in limited oxygen conditions are:

[tex]C(graphite) + \dfrac{1}{2}O_{2(g)} \to CO_{(g)}[/tex]  

[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex]  

If it occurs in excess, then any leftover CO changes to CO2. i.e.

[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex]   ---- (1)

[tex]CO_{(g)} + \dfrac{1}{2}O_{(g)} \to CO_{2(g)}[/tex]          ----- (2)

From (1), the enthalpy change is:

[tex]\Delta H_{rxn1} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{f C(graphite)}+ \Delta H^0_{fCO_2(g)}[/tex]

[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol -(0+0)[/tex]

[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol[/tex]

From (2), the enthalpy change is:

[tex]\Delta_{rxn2} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{fCO(g)} + \dfrac{1}{2} \Delta H^0_{fO_2(g)})[/tex]

[tex]\Delta_{rxn2} = -393.5 \ kJ/mol -(-110.5 + \dfrac{1}{2}(0))[/tex]

[tex]\Delta_{rxn2} = -283.0 \ kJ/mol[/tex]

Subtracting (2) from (1), we get:

[tex]C(graphite) + O_{2(g)} \to CO_{2(g)} \ \ \ \Delta H_{rxn} = -393.5 \ kJ/mol}[/tex]

[tex]CO_{(g)} + \dfrac{1}{2} O_2(g) \to CO_{2(g)}} \ \ \ \Delta H _{rxn2} = -283.0 \ kJ/mol[/tex]

[tex]C(graphite) + O_{2(g)} \to CO (g) + \dfrac{1}{2}O_{2(g)} \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]

[tex]C(graphite) + \dfrac{1}{2} O_{2(g)} \to CO (g) \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]

The enthalpy change ΔH of the reaction = -110.5 kJ/mol

Answer:

a) 4

b) 2

c) 5

d) 2

e) 4

f) 3

Explanation:

The complete question is shown in the image attached to this answer.

We know that the shorter the wavelength, the greater the energy. The greatest energy and shortest wavelength among the emission lines is 4.

Applying the same argument as above, the greatest energy catapults the electron from energy level n=1 to n=4. This will corresponds to the shortest wavelength since energy is inversely proportional to wavelength.  

Frequency is also inversely related to wavelength for two waves travelling at the same speed. Hence, the transition that corresponds to the highest energy and shortest wavelength in the emission spectrum will have the highest frequency.

The emission line with the lowest energy occurs when the electron moves from n=2 to n=1.

The ionization energy is the energy required to remove an electron from the hydrogen atom. It corresponds to the transition n=1 to n=∞

Answer:

water spreads the spicy taste around your mouth, while milk does not and it helps the hot taste go away.

Explanation:

Answer:

water makes ur mouth burn more but milk it helps bc of what's in it

Answer:

The volume of the gas increases as the temperature increases.

Explanation:

Gas volume does increase with increasing temperature providing that the pressure remains constant. Temperature and pressure both interact with the gas volume according to the gas Laws and both variables must be accounted for at the same time.

Answer:

convection

Explanation:

i believe

The popcorn in the pot pops up because of the conduction process when heated. The solid particles transfers heat energy by conduction mode.

There are three mode of heat transfer namely, conduction, convection and radiation. Conduction is taking place in solids whereas, convection is taking place in liquids and gases. Radiation is the way of heat transfer through vacuum.

In conduction, the heat energy transfers from one molecule to the other which are closely packed in the solids as in a chain. Thus, heat easily moves through the chain.

In gases and liquids, the hot molecules moves to the surface to make other molecules hot and this flow of molecules make the entire substance hot.

Popcorn is a solid substance thus, able to conduct heat energy. This heat energy leads them to thermal vibration and they pop up from the hot pot. Therefore, it is an example of conduction.

To find more on conduction, refer here:

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Answer:

Theory- 1 to 7

Explanation:

Exercise- 8 to 25

ect

The right alternative is Option D (0.78 V).

According to the question,

By putting the values, we get

Cu+2 + 2e → Cu E = 0.52 V

Ag+1 + 1e Ag E° = 0.78 V

= 1.23 - 0.45

= 0.78.

negative

The standard cell potential is quite negative, so the reaction will not occur spontaneously as written.

Missing parts of the question.

Using the two cell reduction potentials shown for their corresponding reaction, calculate the cell potential for a voltaic cell made from these two systems: 0.78.

Cu+2 + 2e → Cu E = 0.52 V

Ag+1 + 1e Ag E° = 0.80 V

options:

A)

0.28 V

B)

–1.32 V

C)

1.32 V

D)

–0.28 V

Learn more about cell potential at

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hope it helps you......

Answer:

0.2g

Explanation:

mass=mole/molar mass

molar mass of oxygen is 32

6.06/32=0.19 or 0.2 units=grams

Answer:

The periodic law states “When elements are arranged in order of increasing atomic number, there is a periodic repetition of their chemical and physical properties

Answer:

Ethanoic or acetic acid.

Explanation:

Hello!

In this case, since the chemical formula of the compound excludes the hydrogen from the CHO form, we can infer it is a leaving group, which is likely to be bonded with an oxygen due to the high polarity of the O-H bond. In such a way, the most feasible condensed structure is:

[tex]CH_3-COOH[/tex]

Whereas the COOH stands for the carboxyl group; therefore the compound is ethanoic acid or acetic acid.

Regards!

Answer:

D. Oxidation

Explanation:

In an electrolytic cell, oxidation (the loss of electrons) takes place at the anode. At the cathode reduction takes place.

A mnemonic technique that could be used is that the process that starts with a vowel (Oxidation) takes place at the place that also starts with a vowel (Anode).

Explanation:

hope it helps you

Answer:

5 g

Explanation:

Step 1: Write the balanced equation

3 AgNO₃(aq) + Na₃AsO₄(aq) ⇒ Ag₃AsO₄(s) + 3 NaNO₃(aq)

Step 2: Calculate the reacting moles of Na₃AsO₄

100.0 mL of 0.1 M Na₃AsO₄ react.

0.1000 L × 0.1 mol/L = 0.01 mol

Step 3: Calculate the moles of Ag₃AsO₄ formed from 0.01 moles of Na₃AsO₄

The molar ratio of Na₃AsO₄ to Ag₃AsO₄ is 1:1. The moles of Ag₃AsO₄ formed are 1/1 × 0.01 mol = 0.01 mol.

Step 4: Calculate the mass corresponding to 0.01 moles of Ag₃AsO₄

The molar mass of Ag₃AsO₄ is 461.61 g/mol.

0.01 mol × 461.61 g/mol = 5 g

Answer:

Yes

Explanation:

A molecule has a center of symmetry when, for any atom in the molecule, an identical atom exists diametrically opposite this center an equal distance from it(Wikipedia).

A center of symmetry is said to exist in a molecule when reflection of all parts of the molecule through the center of symmetry produces an indistinguishable configuration(Housecroeft and Sharpe,2012)

Obviously, the Cl2 molecule has a center of symmetry, hence it is symmetrical. Reflection of the molecules through its center of symmetry produces an indistinguishable configuration.

Answer:

0.96mL must be given

Explanation:

First, we need to obtain the mass of Solumedrol required for the child by using its mass. Then, with this mass we can solve the volume that must be administered:

Mass of solumedrol required:

20kg * (3mg / kg) = 60mg of solumedrol are required.

Volume given:

60mg Solumedrol * (2mL / 125mg) =

0.96mL must be given

The change in pressure over a given distance is defined as a pressure gradient. The strength of this pressure gradient determines how fast the wind moves from higher pressure toward lower pressure. A stronger pressure gradient will cause stronger winds, as shown in Figure 2. >> Balanced in the vertical by the force of gravity