How is the atomic mass of an element related to a mole?
O A. The atomic mass, in grams, is the mass of 6.02 x 1023 moles.
O B. The atomic mass, in grams, is the mass of 6.02 x 1023 electrons.
O C. The atomic mass, in grams, is the mass of one mole of atoms.
O D. The atomic mass, in grams, is the mass of one mole of protons.

Answer:

Gravity will always be pulling everything towards Earth's center at an acceleration of 9.81 m/sec².

Molecules' general shape, as well as bond lengths, bond angles, torsional angles, and any other geometrical factors that affect each atom's position, are revealed by their molecular geometry. The molecular geometry of AsCl₃ is trigonal pyramidal.

Molecule geometry is the study of the three-dimensional configuration of the atoms that make up a molecule. Because the shared pairs of electrons remain localized in a specific location between the nuclei of the involved atoms, covalent molecules have directed bonds.

The arsenic atom is surrounded by 4 regions of electron density which means that it has a steric number equal to 4. According to VSPER Theory, the molecular geometry will be trigonal pyramidal, AX₃E₁.

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Answer:

C 7.5 Moles of MgSO4

Explanation:

Answer:

It's false

Explanation:

Answer:

true or false

a. very little oxygen and nitrogen are found in air. false

b. oxygen is the main cause of the formation of rust in iron.   false

c.  impure air is odourless true

.d.  plants take in oxygen gas during respiration. true

e. air contains water vapour. ​true

Explanation:

Answer:

A- Dry with low humidity

Explanation:

The hydrosphere includes the water which is on the surface of the earth, below the ground and in the air.  

On analyzing the climatic conditions in the tropics due to the interaction of the atmosphere and hydrosphere, the presence of water droplets in tropics is less resulting in less humidity and, thus the climatic condition is dry.

Therefore the climatic condition that is typically found in tropics due to interaction of the atmosphere and hydrosphere is dry with low humidity.

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Answer:

D

Explanation:

The valence electrons are the outer electrons and must be located in the outermost shell. In this case, D.

Answer:

i did not find the amswer sorry

The probability density function is nonnegative everywhere, and its integral over the entire space is equal to the terms "probability distribution function" and "probability function" .

In probability theory, a probability density function (PDF), or density of a continuous random variable, is a function whose value at any given sample (or point) in the sample space (the set of possible values taken by the random variable) can be interpreted as providing a relative likelihood that the value of the random variable would be equal to that sample.

Probability density is the probability per unit length, in other words, while the absolute likelihood for a continuous random variable to take on any particular value is 0 (since there is an infinite set of possible values to begin with), the value of the PDF at two different samples can be used to infer, in any particular draw of the random variable, how much more likely it is that the random variable would be close to one sample compared to the other sample.

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heterotrophs cannot create their own food and rely on others for food

Answer: it wound'nt let me type the equations out so i did it on g.o.o.gl.e docs :')

Explanation:

hope this helps <3

have a great day/night/noon

:)

Answer: D.

Explanation:

Asexual reproduction requires only one parent, making it more efficient and take a shorter amount of time than sexual reproduction.

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Explanation:

What do you mean by 'how many oxygen'?

oxygen atoms? or oxygen percentage?

if oxygen atoms is 12 atoms

Answer:

Place the object in the graduated cylinder, and record the resulting water volume as "b." Subtract the volume of the water alone from the volume of the water plus the object. For instance, if "b" was 50 milliliters and "a" was 25 milliliters, the volume of the irregularly shaped object would be 25 milliliters.

Answer:

0.16 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 0.012 moles of O₂

The molar ratio of O₂ to CO₂ is 5:3. The moles of CO₂ produced are 3/5 × 0.012 mol = 0.0072 mol.

Step 3: Calculate the volume occupied by 0.0072 moles of CO₂ at standard temperature and pressure

At STP, 1 mole of CO₂ occupies 22.4 L.

0.0072 mol × 22.4 L/1 mol = 0.16 L

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Explanation:

Are you asking if that is the formula for caprylic acid? The answer is yes. CH₃(CH₂)₆COOH is the correct formula.

Caprylic acid, also known as C8 or octanoic acid, is a medium chain triglyceride (MCT) primarily found in coconut oil. It's the shortest of all the MCTs, making it the easiest for the body to break down into fuel. Once it is consumed, C8 is instantly digested and converted into ketones.

Answer:

True

Explanation:

Answer:

Answer: 0.66 hours

Explanation:

[tex]{ \rm{time = \frac{distance}{speed} }} \\ \\ { \rm{time = \frac{(950.5 \times 1000) \: m}{400 \: m {s}^{ - 1} } }} \\ \\ { \rm{time = {2376.25 \: s}}}[/tex]

• Remember 1 second accounts for 1/3600 hours

[tex]{ \rm{time = \frac{2376.25}{3600} }} \\ \\ { \rm{time = 0.66 \: hours}}[/tex]

The time taken by object  traveling at a speed of 400 m/s to reach 950.5 km distance is 0.66 hr or 39.6 min.

What is average velocity ?

Average velocity is given by the total distance covered by the object in total given time. SI unit of velocity is m/s.

Here in this question it is given that the object is travelling with speed v of 400 m/s and it is to find the time t to reach 950.5 km distance d.

it is known that 1 km = 1000 m

that is 950.5 km = 950500 m

Now, using the relation of speed-distance to find time t to reach 950.5 km distance :

[tex]\begin{aligned}v&=\frac{d}{t}\\t&=\frac{d}{v}\\&=\frac{950500}{400}\\&=2376.25 \text{ s}\end{aligned}[/tex]

Now converting 2376.25 sec into hrs by dividing it by 3600 we get :

2376.25/3600 = 0.66 hr or 39.6 min.

Therefore, the time taken by object to reach 950.5 km distance is 0.66 hr or 39.6 min.

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The method of propagation of the given organisms is shown below:

1. Mongo ---> seeds

2. Moss ---> spores

3. Ferns ---> stem

4. Pine Tree ---> cones

5. Guava ---> seeds

6. Mango ---> seeds

7. Coconut ---> seeds

8. Katakataka ---> leaves

9. Potato ---> stem

10. Okra ---> seeds

Repr0duction is the process by which living organisms produce young ones of their kind.

Repr0duction can either involve two parents through the joining of male and female gametes to produce a zygote i.e. seeds in plants and embryo in animals or can involve only one parent and occurs through vegetative parts such as roots, stem, or leaves.

The table below gives organisms and their propagation parts:

1. Mongo ---> seed

2. Moss ---> spores

3. Ferns ---> stem

4. Pine Tree ---> cones

5. Guava ---> seeds

6. Mango ---> seeds

7. Coconut ---> seeds

8. Katakataka ---> leaves

9. Potato ---> stem

10. Okra ---> seeds

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Answer:

A carbon dioxide and oxygen

If there is direct variation and y=75 when x=25,when y=48 X = 16. Therefore, option A is correct.

link between two variables that can be described mathematically by an equation where one variable equals a constant multiplied by the other. For instance, the constant of variation is k = = 3 if y varies straight as x and y = 6 when x = 2. Consequently, y = 3x is the equation that describes this direct variation.

When x is not equal to zero, an equation of the form y = kx describes the linear function known as direct variation. When x is not equal to zero and k is a nonzero real number constant, the equation of the form xy = k describes the nonlinear function known as inverse variation.

x = ky

where k is constant

25 = k × 75

25 / 75 = k

k = 1 / 3

now when y = 48 then substitute the values

x = ky

x = 1 ÷ 3 × 48

x = 16

Thus, option A is correct.

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Answer:

child stage.

Explanation:

they are more vubnlerabke at that stage

The maximum amount of a substance that can be dissolved in a solvent at a given temperature is referred to as its solubility.

Sucrose has a solubility of 320 g/100 g H2O at 70°C.

Sucrose has a solubility of 320 g/100 g H2O at 70°C.

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Answer:

Explanation:

Consider the general chemical reaction

                                                       [tex]\mathrm{A} \ \overset{k}{\longrightarrow} \ \mathrm{product}[/tex]  .

If [A] is the concentration of A (reactant) at any time t and n is the reaction order for the whole equation, the rate is then related to the concentration of reactant A with the following differential form of equation

                                               [tex]Rate \ = \ -\displaystyle\frac{d[\mathrm{A}]}{dt} \ = \ k[\mathrm{A}]^{n}[/tex]  .

where k is the rate constant.

*Note that the differential term [tex]\displaystyle\frac{d[\mathrm{A}]}{dt}[/tex] has a negative sign to denote that the concentration of A is decreasing over time t.

Since the chemical reaction between tert-butyl bromide and water is given to be a first-order reaction, hence n = 1, and the resulting differential equation becomes

                                        [tex]Rate \ = \ -\displaystyle\frac{d[\mathrm{A}]}{dt} \ = \ k[\mathrm{A}]^{1} \ = \ k[\mathrm{A}][/tex]

To solve this first-order linear homogenous differential equation, the method of separation of variables can be used.

[tex]\-\hspace{1cm} \displaystyle\frac{d[\mathrm{A}]}{dt} \ = -\ k[\mathrm{A}] \\ \\ \-\hspace{0.5cm} \displaystyle\frac{1}{[\mathrm{A}]} \, d[\mathrm{A}] \ = -\ k \, dt \\ \\ \int\ {\displaystyle\frac{1}{[\mathrm{A}]} \, d[\mathrm{A}] \ = \ -\int {k} \, {dt}[/tex]

         [tex]\ln{[\mathrm{A}]} \ = \ -kt \ + \ C \\ \\ \-\hspace{0.45cm} $[A]$ \ = \ e^{-kt \ + \ C} \\ \\ \-\hspace{0.45cm} $[A]$ \ = \ e^{-kt}e^{C} \ \ \ \ \ \ \ \ \ (e^{a \ + \ b} \ = \ e^{a}e^{b} \ \ \ \mathrm{by \ the \ law \ of \ indices})[/tex]

Since the term [tex]e^{C}[/tex] is a constant, let [tex]\alpha \ = \ e^{C}[/tex], hence [tex][\mathrm{A}] \ = \ \alpha e^{-kt}[/tex] or [tex]C \ = \ \alpha e^{-kt}[/tex] according to the question. Given that the initial concentration (t = 0) of tert-butyl bromide is 0.2 mol/L and k = 0.0537[tex]\mathrm{h^{-1}}[/tex], so

[tex]0.2 \ = \ \alpha e^{-0.0537 \ \times \ 0} \\ \\ 0.2 \ = \ \alpha \ \ \ \ \ (e^{0} \ = \ 1)[/tex]

Therefore, the rate equation is [tex]C \ = \ 0.2e^{-0.0537t}[/tex].

The concentration of tert-butyl alcohol after 1 hour is

[tex]C \ = \ 0.2e^{-0.0537 \ \times \ 1} \\ \\ C \ = \ 0.2e^{-0.0537} \\ \\ C \ = \ 0.190 \ \mathrm{mol/L} \ \ \ (3 \ \ \mathrm{s.f.})[/tex]

Answer:

Because of the two different parts of the molecule, a soap molecule is soluble in water and at the same time can dissolve fats. The fats are attracted to the non-polar tail part of the soap while the polar head makes the whole complex.

Explanation:

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Answer:

to identify the element by using flame tests