hhhep faaast plssssss​

Hhhep Faaast Plssssss

Answers

Answer 1

Answer:

false

Explanation:

I am in need of points sorry


Related Questions

A 2.0 kg breadbox on a fric-
tionless incline of angle u 40 is
connected, by a cord that runs over a
pulley, to a light spring of spring con-
stant k 120 N/m, as shown in
Fig. 8-43. The box is released from rest when the spring is unstretched. Assume that the pulley is massless and frictionless. (a) What is the speed of the box when it has moved 10 cm down the in- cline? (b) How far down the incline from its point of release does the box slide before momentarily stopping, and what are the (c) magnitude and (d) direction (up or down the incline) of the box’s acceleration at the instant the box momentarily stops?

Answers

Dhjwbxuzb wm I known kdn wi. Wlzkk n

The datasheet for a 5 V, three-terminal voltage regulator indicates that the output voltage changes by 3 mV when the input voltage is varied from 7 V to 25 V, and the output voltage varies by 5 mV when the load is varied from 0.01 A to the full load of 1 A. The line- and load regulation are respectively which of the following?

a. 6.7mΩ
b. 0.01Ω
c. 0.1Ω
d. 20mΩ

Answers

Answer:

0.01 Ω

Explanation:

Given that the output voltage varies by 5 mV when loaded from 0.01 A to 1 A

Therefore, the regulators output resistance is given by :

[tex]$I_L=\frac{V_L}{R_L}$[/tex]

[tex]$(1.00 - 0.01)A= \frac{5 \ mV}{R_L}$[/tex]

[tex]$0.99 \ A= \frac{5 \ mV}{R_L}$[/tex]

∴ The line and load regulation is 0.01 Ω

For the Earth, most of the information we've learned about its interior, including the mantle and core, comes from drilling down directly into it.


True
False

Answers

True 1:b 2:12354 3:b 4:c 5:d 6:b 7:a 8:b 9:c 10:C 11:d 12:c 13:d 14: a 15:c

The distance from the sun to Earth would be
Which phrase best completes the sentence?
any number of light years
more than one light year
exactly one light year
less than one light year
4

Answers

Answer:

less than one lightyear=d

Explanation:

I took the test.:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D:D::):):):):):):):):):):):):):):):):):):):):):)

Why is Rome warmer than New York in January

Answers

Answer:

The basic answer is sea flows. On the off chance that the air making a trip to New York moves via land, it will be cooler than the air and flows that reach, for instance, San Francisco. Along these lines, Rome is hotter than New York because of flows, topography and air development designs.

Explanation:

Brainliest?

Anatomy and Phys PLEASE HELP
you’ve learned about the structures that make up the reproductive system. Imagine that you are so interested in reproductive health that you are exploring careers related to this health field.

For this activity you are going to research careers related to the promotion or treatment of reproductive health and choose one career to focus on. You are going to identify the key factors of the educational path that you would need to take to work in this career, the annual salary that you would earn, the schedule that you may find yourself working, physical requirements for the job, and how long it will take you to achieve this goal.

You will produce a list of 10 or more strengths and weaknesses that will identify why you are qualified for this role.

You will then prepare a list of at least five questions that you would like to ask someone already working in the career. Your questions ought to be relevant to the career you have chosen and should be related to the research that you have conducted.

Answers

Answer:

Get to work.

Explanation:

This is not Brainly material. This is a project that you need to get started on and do your best on. It always looks worst before you get started on it. Just sink your teeth in and you'll be finishing it up before you know it.

Answer:

careers related to the promotion or treatment of reproductive health and choose one career to focus on. You are going to identify the key factors of the educational path that you would need to take to work in this career, the annual salary that you would earn, the schedule that you may find yourself working, physical requirements for the job, and how long it will take you to achieve this goal.

Explanation:

When the car is moving the unbalanced force acting on the car is 150 N.
A) State the equation which relates unbalanced force, mass and acceleration?​

Answers

Answer:

 F = m a,  a = 0.3 m / s²

this acceleration points in the direction of the unbalanced force

Explanation:

In this problem we must use Newton's second law. Let's fix a reference system with the x axis parallel to the surface and the y axis perpendicular

Y axis y

         N-W = 0

         N = W = mg

X axis

        ∑ F = m a

        F = m a

we substitute

        150 = m a

To find an acceleration value, the mass of the car must be known, if the mass is m = 500 kg

        a = 150/500

        a = 0.3 m / s²

this acceleration points in the direction of the unbalanced force

Find the wavelength of light which is capable of ionizing a hydrogen atom?

Answers

Answer:

The correct answer is -  91.4 nm

Explanation:

According to Bohr's model, the minimum wavelength to ionize Hydrogen atom from n= 1 state is expressed as:

(h×c)/λ=13.6eV

here,

h - Planck constant

c - the speed of light

λ - wavelength

Placing the value in the formula for the wavelength

(6.626×10^−34J.s × 3×10^8 m/s)/λ  =  13.6 ×1.6 × 10^−19 J

λ≈91.4nm

Thus, the correct answer would be = 91.4 nm

A solenoid that is 93.9 cm long has a cross-sectional area of 17.3 cm2. There are 1270 turns of wire carrying a current of 7.80 A. (a) Calculate the energy density of the magnetic field inside the solenoid. (b) Find the total energy in joules stored in the magnetic field there (neglect end effects).

Answers

Answer:

[tex]65.6\ \text{J/m}^3[/tex]

[tex]0.11\ \text{J}[/tex]

Explanation:

B = Magnetic field = [tex]\mu_0 \dfrac{N}{l}I[/tex]

[tex]\mu_0[/tex] = Vacuum permeability = [tex]4\pi10^{-7}\ \text{H/m}[/tex]

N = Number of turns = 1270

[tex]l[/tex] = Length of solenoid = 93.9 cm = 0.939 m

[tex]I[/tex] = Current = 7.8 A

A = Area of solenoid = [tex]17.3\ \text{cm}^2[/tex]

Energy density of a solenoid is given by

[tex]u_m=\dfrac{B^2}{2\mu_0}\\\Rightarrow u_m=\dfrac{(\mu_0 \dfrac{N}{l}I)^2}{2\mu_0}\\\Rightarrow u_m=\dfrac{\mu_0N^2I^2}{2l^2}\\\Rightarrow u_m=\dfrac{4\pi\times 10^{-7}\times 1230^2\times 7.8^2}{2\times 0.939^2}\\\Rightarrow u_m=65.6\ \text{J/m}^3[/tex]

The energy density of the magnetic field inside the solenoid is [tex]65.6\ \text{J/m}^3[/tex]

Energy is given by

[tex]U_m=u_mAl\\\Rightarrow U_m=65.6\times 17.3\times 10^{-4}\times 0.939\\\Rightarrow U_m=0.11\ \text{J}[/tex]

The total energy in joules stored in the magnetic field is [tex]0.11\ \text{J}[/tex].

A wire carries a current of 4.2 A at what distance from the wire does the magnetic field have a magnitude of 1.3×10^ -5 t

Answers

Answer:

the distance is 6.46 cm.

Explanation:

Given

current in the wire, I = 4.2 A

magnitude of the magnetic field, B = 1.3 x 10⁻⁵ T

The distance from the wire is determined by using Biot-Savart Law;

[tex]B = \frac{\mu_o I}{2\pi r} \\\\r = \frac{\mu_o I}{2\pi B}[/tex]

Where;

r is the distance from the wire where the magnetic field is experienced

[tex]r = \frac{\mu_o I}{2\pi B}\\\\r = \frac{4\pi \times 10^{-7} \times 4.2 }{2\pi \times 1.3 \times 10^{-5}}\\\\r = 0.0646 \ m\\\\r = 6.46 \ cm[/tex]

Therefore, the distance is 6.46 cm.

If 10 Coulombs flow through a circuit every 2 seconds, what is the current?
A. Not enough info
B. 5 A
C. 10 A
D. 1 A

Answers

Answer:

not enought info

Explanation:

tbh I just know it's not 5 10 or 1

Answer:

B. 5 A

Explanation:

10/2= 5

Educere

a disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. what is the angular acceleration?
b. how many radians did the disk turn while stopping?
c. how many revolutions?​

Answers

Answer:

too many

Explanation:

What type of feeder is a snake? *

Answers

Answer:

slender-bodied non-stinging insect having iridescent wings that are outspread at rest; adults and nymphs feed on mosquitoes etc.

Explanation:

I hope this works. I have a snake and it helps to know this stuff

An airplane flying at a velocity of 610 m/s lands and comes to a complete stop over a 53 second period?
a. did this airplane speed up or slow down? Explain you reasoning.
b. did the airplane accelerate or decelerate? Explain?
c. Calculate the acceleration.​

Answers

A. The airplane slowed down. It states that the plane lands and come to a complete stop over a 53 second period
B. It decelerares ,the sped doesn’t increase, it slows down
C. 11.5 m/s

Light rays enter a transparent material. Which description best describes what happens to the light rays

Answers

When light encounters transparent materials, almost all of it passes directly through them. Glass, for example, is transparent to all visible light. ... Most of the light is either reflected by the object or absorbed and converted to thermal energy. Materials such as wood, stone, and metals are opaque to visible light.

In a double-slit experiment, the slits are illuminated by a monochromatic, coherent light source having a wavelength of 527 nm. An interference pattern is observed on the screen. The distance between the screen and the double-slit is 1.54 m and the distance between the two slits is 0.102 mm. A light wave propogates from each slit to the screen. What is the path length difference between the distance traveled by the waves for the fifth-order maximum (bright fringe) on the screen

Answers

Answer:

  Λ = 5.14 10⁻⁴ m

Explanation:

This is a double slit experiment, which for the case of constructive interference

          d sin θ = m λ

let's use trigonometry

         tan θ = y / L

   

as the angles are very small

         tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ

         sin θ = y / L

we substitute

         d y / L = m λ

        y = m λ L / d

we calculate for the interference of order m = 5

         y = 5  527 10⁻⁹  1.54/0.102 10⁻³

         y = 3.978 10⁻² m

Now we can find the difference in length between the two rays, that of the central maximum and this

let's use the Pythagorean theorem

           L’= [tex]\sqrt{L^2 +y^2}[/tex]

           L ’= [tex]\sqrt{1.54^2 +(3.978 \ 10^{-2})^2 }[/tex]

           L ’= 1.54051 m

optical path difference

          Λ = L’- L

          Λ = 1.54051 - 1.54

          Λ = 5.14 10⁻⁴ m

If you double the diameter of a telescope, you double its light-collecting area.


True
False

Answers

Answer:true

Explanation:because the double lights

A uniform magnetic field is in the positive z direction. A positively charged particle is moving in the positive x direction through the field. The net force on the particle can be made zero by applying an electric field in what direction

Answers

Answer:

We apply an electric field in the negative y direction

Explanation:

Since A uniform magnetic field is in the positive z direction and A positively charged particle is moving in the positive x direction through the field, the magnetic force acting on the positively charged particle is in the positive y direction according to Fleming's right-hand rule.

For the net force on the particle to be zero, we apply an electric field in the negative y direction to create an electric force on the positively charged particle, so as to cancel out the magnetic force.

A uniform sphere has a moment of inertia that is (2/5)MR2. A sphere of uniform density, with mass 29 kg and radius 0.5 m is located at the origin, and rotates around an axis parallel with the x axis. If you stand somewhere on the x axis and look toward the origin at the sphere, the sphere spins counterclockwise. One complete revolution takes 0.5 seconds. What is the rotational angular momentum of the sphere

Answers

Answer:

[tex]36.44\ \text{kg m/s}\hat{i}[/tex]

Explanation:

I = Moment of inertia of sphere = [tex]\dfrac{2}{5}MR^2[/tex]

M = Mass of sphere = 29 kg

R = Radius of sphere = 0.5 m

T = Time taken for one revolution = 0.5 s

[tex]\omega[/tex] = Angular velocity = [tex]\dfrac{2\pi}{T}[/tex]

[tex]L=I\omega\\\Rightarrow L=\dfrac{2}{5}MR^2\dfrac{2\pi}{T}\\\Rightarrow L=\dfrac{4MR^2\pi}{5T}\\\Rightarrow L=\dfrac{4\times 29\times 0.5^2\pi}{5\times 0.5}\\\Rightarrow L=36.44\ \text{kg m/s}[/tex]

The rotational angular momentum of the sphere is [tex]36.44\ \text{kg m/s}\hat{i}[/tex].

Which of the following is NOT something
the atmosphere does?
A. traps in warmth
B. keeps Earth in a spherical shape
C. provides oxygen to breathe
D. protects Earth from meteoroids

Answers

Answer:

I think the answer is B, keeps Earth in a spherical shape

An organ pipe open at both ends has a length of 0.80 m. If the velocity of sound in air is 340 m/s, what is the frequency of the second harmonic of this pipe

Answers

Answer:

the frequency of the second harmonic of the pipe is 425 Hz

Explanation:

Given;

length of the open pipe, L = 0.8 m

velocity of sound, v = 340 m/s

The wavelength of the second harmonic is calculated as follows;

L = A ---> N   +  N--->N   +   N--->A

where;

L is the length of the pipe in the second harmonic

A represents antinode of the wave

N represents the node of the wave

[tex]L = \frac{\lambda}{4} + \frac{\lambda}{2} + \frac{\lambda}{4} \\\\L = \lambda[/tex]

The frequency is calculated as follows;

[tex]F_1 = \frac{V}{\lambda} = \frac{340}{0.8} = 425 \ Hz[/tex]

Therefore, the frequency of the second harmonic of the pipe is 425 Hz.

The frequency of the second harmonic of the pipe is 425 Hz.

What is the frequency?

Frequency is the number of oscillations per second in the sinusoidal wave.

Given is length of the open pipe, L = 0.8 m, and velocity of sound, v = 340 m/s

The wavelength of the second harmonic is represented as

L = A → N   +  N→N   +   N→A

where, L is the length of the pipe in the second harmonic, A represents antinode of the wave, N represents the node of the wave

Length = λ/4 +λ/2 +λ/4

Length = λ

The frequency is calculated

frequency = speed of light / wavelength

Put the values, we get

f = 340/0.80

f = 425 Hz

Therefore, the frequency of the second harmonic of the pipe is 425 Hz.

Learn more about frequency.

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Which is observed globally: "Earth Day" or "Arbor Day"?

Answers

Answer:

Earth Day is observed globally

Explanation:

Earth day is more globally observed. Arbor day is lowkey rare

Convert (a) 50 oF, (b) 80 oF, (c) 95 oF to Celsius

Answers

I really need these points thx a lot

How much gravitational force do two lead balls with a mass of 8 kilograms, the centers of mass of which are 17 cm apart, affect each other?

Answers

Answer:

1.48×10⁻⁷ Newtons

Explanation:

From the question,

According to newton's law of universal gravitation.

F = Gmm'/r²........................ Equation 1

F = gravitational force, G = gravitational constant, m = mass of the first ball, m' = mass of the second ball, r = distance between the balls.

Given: m = m' = 8 kg, r = 17 cm = 0.17 m,

Constant : G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

F =  (6.67×10⁻¹¹×8×8)/(0.17²)

F = 1.48×10⁻⁷ N

Hi please zoom in to see it clearly, uh you don’t have to answer them all but it would be nice !!! (no links please) :)

Answers

Explanation:

Newton's second law of motion states that the external force is directly proportional to the rate of change of momentum. Mathematically, Newton's second law of motion is given by :

F = ma

Where

m is the mass and a is the acceleration

If there is a smaller mass, it would need a weaker force to accelerate it as the force is directly proportional to the mass. Hence, the correct option is (d).

Your boss asks you to design a drone that begins its flight near the surface and rises to 9600 m. At the surface it will fly through air having a density of 1.23 kg per cubic meter and at its highest altitude the air density will become 0.62 kg per cubic meter. If the flight velocity near sea level is 45 mph, then how fast will in need to go at its highest altitude to maintain the same lift. Assume the coefficient of lift remains constant.

Answers

Answer:

[tex]63.38\ \text{mph}[/tex]

Explanation:

L = Lift force

[tex]\rho[/tex] = Density of air

A = Surface area

v = Velocity

[tex]v_1[/tex] = 45 mph

[tex]\rho_1=1.23\ \text{kg/m}^3[/tex]

[tex]\rho_2=0.62\ \text{kg/m}^3[/tex]

Coefficient of lift is given by

[tex]CL=\dfrac{2L}{\rho v^2A}\\\Rightarrow \rho=\dfrac{2L}{CL v^2A}[/tex]

So

[tex]\rho\propto \dfrac{1}{v^2}[/tex]

[tex]\dfrac{\rho_1}{\rho_2}=\dfrac{v_2^2}{v_1^2}\\\Rightarrow v_2=\sqrt{\dfrac{\rho_1}{\rho_2}}\times v_1\\\Rightarrow v_2=\sqrt{\dfrac{1.23}{0.62}}\times 45\\\Rightarrow v_2=63.38\ \text{mph}[/tex]

The velocity at the required altitude should be [tex]63.38\ \text{mph}[/tex] to maintain the same lift.

A copper plate is free to swing between the poles of a large electromagnet. When the field is turned up the plate Group of answer choices will swing faster. will not be affected at all. will brake and quickly come to rest. will swing with a larger amplitude, because it is pushed by the magnet. will become a permanent magnet.

Answers

Answer:

C: will brake and quickly come to rest.

Explanation:

Correct answer is option C because for the swinging motion of the copper plates between the magnetic field which is set up as a result of it being between the two magnetic poles, there will be a continuous change of magnetic field flux that will be linked with the swinging pendulum.

As a result of this continuous change of magnetic field flux, it makes eddy currents to be set up in the copper plate which according to the Lenz's laws of electromagnetic induction tries to oppose the motion of the swinging pendulum and finally will make it come to rest.

A dentist uses a concave mirror to examine a tooth that is 1.00
cm in front of the mirror. The image of the tooth forms 10.0 cm
behind the mirror. What is the mirror's radius of curvature?

Answers

Answer:

-2.2cm

Explanation:

A dentist uses a concave mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the tooth forms 10.0 cm behind the mirror. What is the mirror's radius of curvature 0.909 m.

To determine the mirror's radius of curvature, we can use the mirror formula:

1/f = 1/v - 1/u

Where:

f is the focal length of the mirror

v is the image distance (distance of the image from the mirror)

u is the object distance (distance of the object from the mirror)

In this case, the object distance (u) is 1.00 cm and the image distance (v) is -10.0 cm (since the image is formed behind the mirror, the distance is negative).

1/f = 1/(-10.0) - 1/(1.00)

Simplifying the equation:

1/f = -0.1 - 1

1/f = -1.1

Now, we can find the reciprocal of both sides of the equation:

f/1 = -1/1.1

f ≈ -0.909 m

The negative sign indicates that the mirror is concave.

Therefore, the mirror's radius of curvature is approximately 0.909 m.

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no links or i will report. What is the potential energy of stretched spring, if the spring constant is 40 N/m and the elongation is 5 cm?

Answers

Answer: 0.05 J

Explanation:

List all variables before solving:

K = 40 N/m

x = 5 cm (convert to 0.05 m)

Use the equation for potential energy (PE):

PE = [tex]\frac{1}{2}[/tex] k[tex]x^{2}[/tex]

Plug in the given variables and solve:

PE = ( [tex]\frac{1}{2}[/tex] ) (40 N/m) (0.05 m)^2

The answer is 0.05 J

Somebody, please help me with these by April 6 I'm about to fail my class

1. Describe specific heat capacity and its use in calorimetry.
2. Define latent heat and how it is different than specific heat capacity.
3. Describe how a phase diagram changes when changing from a solid to a liquid.
4. Describe how work is done is related to a change in the volume of a fluid.
—Continue on the next page—
5. What is the relationship of change in internal energy, work, and heat? Explain the significance in terms of energy.
6. As succinctly as possible, explain why it is impossible to have an engine that is 100% efficient.
7. Describe the application of Archimedes principle in everyday terms.
Practice
8. 50 grams of a substance increases its temperature by 10 degrees when 100 J of heat is added. What is the specific heat capacity of the substance?
9. Ten kilograms of a substance has a latent heat of 1000 J/kg. How much energy does it take to change the phase of this substance?
—Continue on the next page—

10. The work done by a piston is measured to be 1000 J. If the pressure is a constant 1000 Pa, what is the change in volume of the piston?
11. Is the process described in #10 isovolumetric? Explain.
12. Is it possible for a substance to change the temperature in an isovolumetric and adiabatic process? Explain.
13. A substance is heated with 1000 J and does 700 J of work on the atmosphere. What is the change in the internal energy of the substance?
14. An engine causes a car to move 10 meters with a force of 100 N. The engine produces 10,000 J of energy. What is the efficiency of this engine?
—Continue on the next page—

15. If a ball of radius 0.1 m is suspended in water, density = 997 kg/m^3, what is the volume of water displaced and the buoyant force?
16. A 10 kg ball of volume = 0.005 m3 is set on a lake. Describe what will happen to the ball.
Application
A group of physics students heats a vial of water, which has a balloon at the top that traps the water vapor and air.
17. Describe how much the internal energy is changed if the students are adding heat to the water via a Bunsen burner. No need to calculate anything.
18. If 50 grams of water start to boil, then how much heat must be added to completely boil off the water? The latent heat of vaporization is 2,260,000 J/kg
—Continue on the next page—

19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
20. Assuming the atmospheric pressure to be constant at 101,325 Pa, by what amount does the volume of the balloon change?

Answers

Answer:

im sorry i would help but thats too much

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