Heya!
[tex] \underline{ \underline{ \bf{Question}}}: [/tex] In the given figure , ABC is a triangle in which AB = AC. Also a circle passing through B and C intersects the sides AB and AC at the points D and E respectively. Prove that AD = AE.
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![Heya![tex] \underline{ \underline{ \bf{Question}}}: [/tex] In The Given Figure , ABC Is A Triangle In](https://brainimage.s3.us-east-005.backblazeb2.com/contents/attachments/rjguas5JIfual9EiyY3TE6Rbi4XGF9AY.jpeg)
Answers
Answer:
See Below.
Step-by-step explanation:
We are given that ABC is a triangle in which AB = AC.
A circle passing through B and C also intersects the sides AB and AC at points D and E respectively.
And we want to prove that AD = AE.
By the secant-secant theorem (shown below), we know that:
[tex]AD(AB)=AE(AC)[/tex]
We are given that AB = AC. So, by substitution:
[tex]AD(AB)=AE(AB)[/tex]
And by dividing both sides by AB (AB ≠ 0), we acquire:
[tex]AD=AE[/tex]
Q.E.D.
![Heya![tex] \underline{ \underline{ \bf{Question}}}: [/tex] In The Given Figure , ABC Is A Triangle In](https://brainimage.s3.us-east-005.backblazeb2.com/answers/attachments/jKJDE7Zt4cU6mgd98TsXnlSSMdCLAnP1.jpeg)
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The area of the circle is 452.39 mm².
What is the area of a circle ?The formula for the area of a circle
A = πr²
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A = π(12 mm)² = 144 π mm²
For an appropriate value of π, the area is
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For 3.14 as the value of π, the area
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