Answers
Answer:
The x-coordinates for which the gradient of the curve is 5 is at x = -1/2 and x = 1/2.
Step-by-step explanation:
We have the function:
[tex]\displaystyle y=\frac{x^2 -1}{x}[/tex]
And we want to find the x-coordinates for which the gradient (or slope) at the point is 5.
The gradients of a curve at a point is given by its derivative. Find the derivative:
[tex]\displaystyle \frac{dy}{dx}=\frac{d}{dx}\left[\frac{x^2-1}{x}\right][/tex]
Use the quotient rule:
[tex]\displaystyle \frac{dy}{dx}=\frac{(x^2-1)'(x)-(x^2-1)(x)'}{(x)^2}[/tex]
Simplify:
[tex]\displaystyle \frac{dy}{dx}=\frac{(2x)(x)-(x^2-1)(1)}{x^2}[/tex]
Simplify:
[tex]\displaystyle \frac{dy}{dx}=\frac{x^2+1}{x^2}[/tex]
Since the gradient is 5, substitute 5 for dy/dx and solve for x:
[tex]\displaystyle 5=\frac{x^2+1}{x^2}[/tex]Multiply both sides by x² (x ≠ 0):
[tex]5x^2=x^2+1[/tex]
Subtract x² from boths sides:
[tex]4x^2=1[/tex]
Solve for x:
[tex]\displaystyle x=\pm\sqrt{\frac{1}{4}}=\frac{1}{2}\text{ or } -\frac{1}{2}[/tex]
So, the x-coordinates for which the gradient of the curve is 5 is at x = -1/2 and x = 1/2.
Related Questions
Suppose you have entered 115-mile biathlon that consists of a run and a bicycle race. During your run, your average velocity is 9 miles per hour, and during your bicycle race, your average velocity is 22 miles per hour. You finish the race in 7 hours. What is the distance of the run? What is the distance of the bicycle race?
Answers
Answer:
The distance of the run was 27 miles and the distance of the bicycle race was 88 miles.
Step-by-step explanation:
Since I have entered 115-mile biathlon that consists of a run and a bicycle race, and during my run, my average velocity is 9 miles per hour, and during my bicycle race, my average velocity is 22 miles per hour , and I finish the race in 7 hours, to determine what is the distance of the run and what is the distance of the bicycle race, the following calculations must be performed:
7 x 22 + 0 x 9 = 154
5 x 22 + 2 x 9 = 128
4 x 22 + 3 x 9 = 115
Therefore, the distance of the run was 27 miles and the distance of the bicycle race was 88 miles.
Find x round to the nearest degree?
Answers
i don't think this is complete question there isn't value for x
Help please, it’s for average rate of change.
Answers
Answer in fraction form = -3/2
Answer in decimal form = -1.5
=========================================
Work Shown:
[tex]m = \frac{g(b)-g(a)}{b-a}\\\\m = \frac{g(1)-g(-3)}{1-(-3)}\\\\m = \frac{0-6}{1-(-3)}\\\\m = \frac{0-6}{1+3}\\\\m = \frac{-6}{4}\\\\m = -\frac{3}{2}\\\\m = -1.5\\\\[/tex]
Effectively, we're finding the slope through the points (-3, 6) and (1, 0)
The g(b)-g(a) represents how y changes when going from x = a to x = b.
why is the solution to the following equation? x+(-21)=8
Answers
Answer:
x = 29
Step-by-step explanation:
[tex]x+(-21)=8[/tex]
[tex]29+(-21)=8[/tex]
[tex]29-21=8[/tex]
[tex]x=29[/tex]
Find the circumference of the circle.
Answers
Based on the family the graph below belongs to, which equation could represent the graph?
Answers
where is the graph????
Step-by-step explanation:
Segment EG is an angle bisector of angle FGH. Noah wrote a proof to show that triangle HEG is congruent to triangle FEG. Noah's proof is not correct. Which line of Noah's proof is incorrect, and why1. Side EG is congruent to side EG because they're the same segment.
2. Angle EGH is congruent to angle EGF because segment EG is an angle bisector of angle FGH.
3. Angle HEG is congruent to angle FEG because segment EG is an angle bisector of angle FGH.
4. By the Angle-Side-Angle Triangle Congruence Theorem, triangle HEG is congruent to triangle FEG.
Line 2 is incorrect; there is not enough information given to state this.
Line 2 is incorrect; there is not enough information given to state this.
Line 2 is incorrect; even though segment EG is a bisector, angles EGH and FGH are not necessarily congruent.
Line 2 is incorrect; even though segment , EG, is a bisector, angles , EGH, and , FGH , are not necessarily congruent.
Line 3 is incorrect; we don't know anything about the lengths of HG, FG, HE, and EF, so this line is not valid based on the given information.
Line 3 is incorrect; we don't know anything about the lengths of , HG, , , FG, , , HE, , and , EF, , so this line is not valid based on the given information.
Line 4 is incorrect; Angle-Side-Angle is not a valid congruence theorem.
Line 4 is incorrect; Angle-Side-Angle is not a valid congruence theorem.
Answers
Answer:
Line 3 is incorrect; we don't know anything about the lengths of HG, FG, HE, and EF, so this line is not valid based on the given information.
Step-by-step explanation:
In the Noah's poof of the construction, segment EG would divide angle FGH into two equal parts, which makes line 2 to be valid. i.e <EGH ≅ <EGF. And it can also be observed that line 4 is a valid theorem in proving the congruent nature of triangles.
But line 3 is not valid because of the condition of the statement. Furthermore, segments FG, EG, HG, HE and FE may not be congruent. Thus, the condition of the statement in line 3 is incorrect.
Write the equation of the trigonometric graph.
Answers
Answer(s):
[tex]\displaystyle y = 3sin\: (1\frac{1}{2}x + \frac{\pi}{2}) - 2 \\ y = 3cos\: 1\frac{1}{2}x - 2[/tex]
Explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{3}} \hookrightarrow \frac{-\frac{\pi}{2}}{1\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}\pi} \hookrightarrow \frac{2}{1\frac{1}{2}}\pi \\ Amplitude \hookrightarrow 3[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}\pi} \hookrightarrow \frac{2}{1\frac{1}{2}}\pi \\ Amplitude \hookrightarrow 3[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\: 1\frac{1}{2}x - 2,[/tex] in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{pi}{3}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACK [tex]\displaystyle \frac{\pi}{3}\:unit,[/tex] which means the C-term will be negative, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{3}} = \frac{-\frac{\pi}{2}}{1\frac{1}{2}}.[/tex] So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\: (1\frac{1}{2}x + \frac{\pi}{2}) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [0, 1],[/tex] from there to [tex]\displaystyle [1\frac{1}{3}\pi, 1],[/tex] they are obviously [tex]\displaystyle 1\frac{1}{3}\pi\:unit[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 1\frac{1}{3}\pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts horisontally, the midline will ALWAYS follow.
I am delighted to assist you at any time.
Only answer if you're very good at math.Please I keep on posting this but nobody is helping me.
What is the 4th term of the expansion of (1 - 2x)^n if the binomial coefficients are taken from the row of Pascal's triangle shown below?
1 6 15 20 15 6 1
A: 240x^4
B: 160x^3
C: -160x^3
D: -20x^3
Answers
The fourth term of the given expansion is [tex]-280x^{3}[/tex].
What is binomial expansion?
The binomial expansion is used to expand and write the terms which are equals to the natural number exponent of the sum or differences of two terms.
The general term of the binomial expansion is given by[tex]T_{r+1} =nC_{r} x^{n-r} y^{r}[/tex]
According to the given question
We have,
A binomial expression, [tex](1-2x)^{n}[/tex]
and, the binomial coefficients are taken from the row of Pascal's triangle 1 6 15 20 15 6 1
⇒ n = 7
Therefore,
The fourth term of the expansion of [tex](1-2x)^{n}[/tex] is given by
[tex]T_{3+1} = 7C_{3} 1^{7-3} (-2x)^{3}[/tex]
[tex]T_{4} =\frac{(7)(6)(5)(4)(3!)}{3!(4)(3)(2)} (1)(-2x)^{3}[/tex]
[tex]T{4} = -280x^{3}[/tex]
Hence, the fourth term of the given expansion [tex](1-2x)^{3}[/tex] is [tex]-280x^{3}[/tex].
Learn more about the binomial expansion here:
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below is a table showing the investment and the investment period of
Answers
Answer:
hey. pls complete your question.
Find the circumference and area of a circle having a diameter of 7 1/2 ft. Use 3.14 for pi
Answers
Answer:
circumference= 32.56
area= 44.18
Step-by-step explanation:
for area: (A=pi×r^2) your diameter is 7.5 so you divide that by 2 to get your radius. and the radius is 3.75. then you are going to do 3.75^2 to get 14.1 then you are going to multiply 14.1 by pi to get 44.18
for circumference: (2×pi×r) you are going to take the same radius for the area and simply multiply that by pi (3.14) to get 11.78, then you are going to multiply 11.78×2 and that equals 23.56
can someone help me please?! I'll give brainlest for correct answer
Answers
1.) The answers:
A) BME
B) MER
C) Mm
D) xBy
E) Straight
F) REB
G) MEB and BER
H) xBy
use the diagram below to find all missing angles
Answers
Answer:
Step-by-step explanation:
Soooo, angle 1 is 157 degrees
That means:
Angle 2 is 23 degrees Supplementary Angles
Angle 3 is 157 degrees Vertical Angle to Angle 1
Angle 4 is 23 degrees Vertical angle to Angle 2
Answers:
angle 2 = 23 degreesangle 3 = 157 degreesangle 4 = 23 degrees=======================================================
Explanation:
Angles 1 and 2 are supplementary as they form a straight line. So the angles add to 180
(angle1)+(angle2) = 180
angle2 = 180-(angle1)
angle2 = 180-157
angle2 = 23 degrees
Angle 4 is congruent to this because angles 2 and 4 are vertical angles. Vertical angles are always congruent. Note how angles 1 and 4 are supplementary.
Since angles 1 and 3 are the other pair of vertical angles, this must mean angle 3 is 157 degrees.
Classify the triangle shown below.
ضع تصنيفا للمثلث الموضح أدناه.
11 cm
3 cm
13 cm
Answers
Answer:
Scuse me what the flip
Which expression is equivalent to x(97-12)?
– 12
Answers
Answer:
85x−12
Step-by-step explanation:
Dhani has 4 cards numbered 1 through 4. He removes 2 cards at random and adds their values.
What is the probability that the sum is less than or equal to 5?
7/12
2/3
3/5
3/4
Answers
Answer:
[tex]2/3[/tex]
Step-by-step explanation:
The total number of sums (not distinct) is [tex]4\cdot 3=12[/tex], because we're removing without replacement.
Count the sums that fit the stipulation (sum [tex]\leq[/tex] 5):
[tex]1,2,\\2,1\\1,3\\3,1\\1, 4\\4, 1\\2, 3, \\3,2[/tex]
There are 8 sums that work. Therefore, the desired answer is [tex]\frac{8}{12}=\boxed{\frac{2}{3}}[/tex]
CAN SOMEONE HELP ME WITH THIS?!
Answers
Answer:
a = 14
b = 24
c = 24.9
A = 33.2 degrees
B = 70 degrees
C = 76.8 degrees
Step-by-step explanation:
a/sin(A) = b/sin(B) = c/sin(C)
14/sin(A) = 24/sin(70)
sin(A)×24 = sin(70)×14
sin(A) = sin(70)× 14/24 = sin(70) × 7/12 = 0.548154029...
A = asin(0.548154029...) = 33.240464... degrees
the sum of all angles in a triangle is airways 180 degrees.
C = 180 - 70 - 33.240464... = 76.75954... degrees
24/sin(70) = c/sin(76.75954...)
c = 24×sin(76.75954...)/sin(70) = 24.86133969...
4x² – 16x + 9 at x = 5.
Use the remainder theorem to evaluate f(x)
Answers
Answer:
29
Step-by-step explanation:
plug in 5 where x is.
so
4(5)^2-16(5)+9=
which equals 29
SEE IMAGE BELOW:)
Adam bought three kinds of
bagels at the bagel store. He
bought twice as many onion bagels as plain
bagels. He bought four more sesame
bagels than he did plain bagels. Adam ate
one of the sixteen onion bagels he bought
as soon as he got home. How many bagels
does Adam have left?
Answers
9514 1404 393
Answer:
35
Step-by-step explanation:
The 16 onion bagels are twice as many as plain bagels, so there were 8 plain bagels.
There were 4 more sesame bagels than plain bagels, so there were 12 sesame bagels.
Adam has 8 plain, 12 sesame, and 15 onion bagels left, for a total of 35 bagels left.
You used (formula in screenshot) when calculating variance and standard deviation. An alternative formula for the standard deviation that is sometimes convenient for hand calculations is shown below. You can find the sample variance by dividing the sum of squares by n-1, and the sample standard deviation by finding the square root of the sample variance. Complete parts (a) and (b) below.
Answers
Answer:
[tex]Varianve = 3.842[/tex]
[tex]SD = 1.960[/tex]
Step-by-step explanation:
Given
See attachment for data
First, calculate [tex]\sum x^2[/tex]
[tex]\sum x^2 = 18^2 + 17^2 +20^2 + 19^2 + 20^2 + 16^2 + 16^2 + 15^2 + 18^2+14^2 +19^2 + 19^2+18^2+17^2 + 16^2+20^2+16^2+18^2+14^2+20^2[/tex]
[tex]\sum x^2 = 6198[/tex]
Calculate [tex]\sum x[/tex]
[tex]\sum x = 18 + 17 +20 + 19 + 20 + 16 + 16 + 15 + 18+14 +19 + 19+18+17 + 16+20+16+18+14+20[/tex]
[tex]\sum x = 350[/tex]
So, we have:
[tex]SS_x = \sum x^2 -\frac{(\sum x)^2}{n}[/tex]
[tex]SS_x = 6198 -\frac{350^2}{20}[/tex]
[tex]SS_x = 6198 -\frac{122500}{20}[/tex]
[tex]SS_x = 6198 -6125[/tex]
[tex]SS_x = 73[/tex]
Solving (a): The variance
[tex]Varianve = \frac{SS_x}{n-1}[/tex]
[tex]Varianve = \frac{73}{20-1}[/tex]
[tex]Varianve = \frac{73}{19}[/tex]
[tex]Varianve = 3.842[/tex]
Solving (b): The standard deviation
[tex]SD = \sqrt{Variance}[/tex]
[tex]SD = \sqrt{3.842}[/tex]
[tex]SD = 1.960[/tex]
Help please, solve and explain
Answers
Answer:
Step-by-step explanation:
17.
18.
f(x)=6x^2+7x-4
(a)
f(3)=6(3)^2+7(3)-4
=54+21-4
=71
(b)
f(m)=6m^2+7m-4
(c)
f(x+1)=6(x+1)²+7(x+1)-4
=6(x²+2x+1)+7x+7-4
=12x²+12x+6+7x+7-4
=12x²+19x+9
19.
(fg)(x)=f(g(x)=f(2x²+3)=2x²+3+5=2x²+8
20.
(a)
f(x)=x²+3x+4
domain:all real values
(b)
domain:all real values≥-2
(c)f(x)=log(x+7)
Domain:x≥-7
21.
x²+6x+y²-7=0
(x²+6x+6/2)²)-(6/2)²+y²=7
(x+3)²+y²=7+9
(x+3)²+y²=4²
center=(-3,0)
radius=4
22.
(x-3)²+(y-5)²=3²
or
x²-6x+9+y²-10y+25=9
x²+y²-6x-10y+25=0
Graph is for 17th question.
Which system of inequalities does the graph represent?
Answers
Answer:system of linear equalities in one variable .
Step-by-step explanation:
Ack, sorry im gonna need a way to delete this lol.
Thanks to the people who tried.
ima need someone to delete this.
Answers
The pie chart is best because pie charts are a good way to portray percentage based data. B. The Pareto chart is best because it allows you to see which sources account for most of the electricity. C. The pie chart is best because pie charts should always be used when comparing percentages. D. The Pareto chart is best because the bars make it easy to visually compare the different percentages. E. Neither type of chart is a good way to portray the data.
Answers
Answer:
The pie chart is best because pie charts are a good way to portray percentage based data.
Step-by-step explanation:
Pie charts are used for graphical representation of data. The data can be shown in percentages or numbers. It is easy for the user to understand the data in the pie chart because it clearly represents the data in circular graphical form.
400 is 100 times as much as
Answers
Multiply the following using the vertical multiplication method: 3x^2-5x+1
x x^2+2x+4
Answers
9514 1404 393
Answer:
3x^4 +x^3 +3x^2 -18x +4
Step-by-step explanation:
The multiplication is done the same way as "long multiplication" with numbers. Each partial product is placed in the column corresponding to its "place value" (the degree of the variable). The only difference from numerical multiplication is that the sums of the partial products have no carry into any column with a different "place value".
Which system of equations can be used to find the roots of the equation 4x2 = x3.
ly=-4x²
ly=x²+2x
(y = x² - 4x² + 2x
»
O
ly=0
0
o y
Jy = 4x²
Lva-x-2x
ly=44²
ly=x²+2x
o
Answers
Answer:
The second answer
Y=X³-4X²+2X
Y=0
The system of equations can be used to find the roots of the given equation is y = 4x², y = x³+2x
What is an equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
For example, 3x – 5 = 16 is an equation.
Given is an equation, 4x² = x³+2x, we need to identify the system of equations can be used to find the roots of this,
An equality can be transformed in a system of equations by making each side equal to a new variable. In this case the variable y was made equal to each side.
See that may find the solution of such system by graphing both functions in a same coordinate system, where the intersection of the functions would show the solution of the system.
The attached image. In such graph, the red curve is the function y = x² and the blue function is y = x³ + 2x.
The intersection point is (0,0) meaning that the solution is x = 0, y = 0.
Hence, the system of equations can be used to find the roots of the given equation is y = 4x², y = x³+2x
Learn more about equations, click;
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Find the value of unknown figure plz tell i will mark as brainliest
Answers
Answer:
1. [tex]2^{3}[/tex] x [tex]3^{6}[/tex]
ii. 18
b. -12
2. nth = a + (n - 1)d
ii. k = 103
3. [tex]x^{o}[/tex] = [tex]27^{o}[/tex]
4. Volume = 25.025 [tex]m^{3}[/tex]
Step-by-step explanation:
1. Prime factors of 5832 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3
= [tex]2^{3}[/tex] x [tex]3^{6}[/tex]
ii. [tex]\sqrt[3]{5832}[/tex] = 18
b. 2[tex]a^{2}[/tex] - 3[tex]b^{2}[/tex] + 3abc
a = 3, b = 2, c = -1
Thus,
2[tex](3)^{2}[/tex] - 3[tex](2)^{2}[/tex] + 3(3 x 2 x -1)
= 18 - 12 - 18
= -12
2. The required formula is;
nth = a + (n - 1)d
where: a is the first term, n is the number of terms in the sequence and d is the common difference.
b. kth term = 304, then
304 = -2 + (k - 1) 3
= -2 + 3k -3
= 3k - 5
3k = 304 + 5
3k = 309
k = [tex]\frac{309}{3}[/tex]
= 103
k = 103
3. Comparing <DAB and < EBC;
<DAB ≅ <EBC = [tex]x^{o}[/tex]
<BEC = [tex]90^{o}[/tex] (right angle property)
<C = [tex]63^{o}[/tex]
Thus,
<B + <C + <E = [tex]180^{o}[/tex] (sum of angles in a triangle)
[tex]x^{o}[/tex] + [tex]63^{o}[/tex] + [tex]90^{o}[/tex] = [tex]180^{o}[/tex]
[tex]x^{o}[/tex] + 153 = [tex]180^{o}[/tex]
[tex]x^{o}[/tex] = 180 - 153
= 27
[tex]x^{o}[/tex] = [tex]27^{o}[/tex]
4. Volume of a cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h
where r is the radius and h is the height of the cylinder.
Diameter = 3.5 m, h = 2.6 m
r = [tex]\frac{3.5}{2}[/tex]
r = [tex]\frac{7}{4}[/tex] m
So that,
Volume = [tex]\frac{22}{7}[/tex] x [tex](\frac{7}{4}) ^{2}[/tex] x 2.6
= [tex]\frac{22}{7}[/tex] x [tex]\frac{49}{16}[/tex] x [tex]\frac{13}{5}[/tex]
= 25[tex]\frac{1}{40}[/tex]
Volume = 25.025 [tex]m^{3}[/tex]
Is this correct? I just started learning negative numbers.
Answers
Answer:
It's on the negative side, so make sure you put -2.25. But yes, it's right.
The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –y minus 3 equals negative StartFraction 2 Over 3 EndFraction left-parenthesis x plus 8 right-parenthesis.x + 6. What is the point-slope form of the equation for this line?
y – 3 = –StartFraction 8 Over 5 EndFraction x plus StartFraction 2 Over 3 EndFraction equals StartFraction one-half EndFraction minus StartFraction 1 Over 5 EndFraction x.(x + 8)
y + 3 = –y plus 3 equals negative StartFraction 2 Over 3 EndFraction left-parenthesis x minus 8 right-parenthesis.(x – 8)
y + 8 = –y plus 8 equals negative StartFraction 2 Over 3 EndFraction left-parenthesis x minus 3 right-parenthesis.(x – 3)
y – 8 = –y minus 8 equals negative StartFraction 2 Over 3 EndFraction left-parenthesis x plus 3 right-parenthesis.(x + 3)
Answers
y – 8 = –y minus 8 equals negative StartFraction 2 Over 3 EndFraction left-parenthesis x plus 3 right-parenthesis.(x + 3)
Step-by-step explanation: