Answer:
I think u are traeling at speed of light and not ur friend
Explanation:
Who's Madame Marie curie?
Explanation:
In 1911, Marie was awarded a second Nobel Prize in Chemistry for her discovery of the elements polonium and radium. In honor of the 100-year anniversary of her Nobel award, 2011 was declared the "International Year of Chemistry."
Which statement best describes the Sun Earth-Moon system?
Answer:
A
Explanation:
A. The Moon orbits the Earth, and the Earth-Moon system orbits the Sun
B. The Earth and Moon both orbit the Sun separately
C. The Sun orbits the Earth-Moon system
D. The Moon revolves around Earth but not the Sun
As shown in the diagram below, a 1 kg rock tied to a rope is
swung by a boy. This rock has a constant speed of 5 m/s,
and the length of the rope is 1 m. The rock's angular
momentum is
Answer:
Explanation:
Angular momentum has a formula of L = mvr. Fillingin:
L = (1.0)(5.0)(1.0)
L = 5.0 kg*m/s
5. Alex worked out for 4 hours and lost 3 lbs. during that time. What is the range of water that he should drink in ounces after his workout?
9 ounces bc if he does then he wont be so like ugh I'm out of wonder land yeah 9 ounces deffo
Determine the small gravitational force F which the copper sphere exerts on the steel sphere. Both spheres are homogeneous, and the value of r is 50 mm. Express your result as a vector.
Solution :
We know that the volume of sphere is given by :
[tex]$V=\frac{4}{3}\pi r ^3$[/tex]
Given r = 50 mm
The density of copper is :
[tex]$\rho_c = 8910 \ kg/m^3$[/tex]
The density of steel is :
[tex]$\rho_s = 7830\ kg/m^3$[/tex]
Therefore, mass of copper is :
[tex]$m_c= V . \rho$[/tex]
[tex]$m_c= \frac{4}{3} \pi (0.05)^3 \times 8910$[/tex]
= 4.665 kg
= 4665 g
Similarly, mass of steel is :
[tex]$m_s= V . \rho$[/tex]
[tex]$m_s= \frac{4}{3} \pi (0.025)^3 \times 7830$[/tex]
= 0.512 kg
= 512 g
Now the distance between the centers of the particles is by Pythagoras theorem,
[tex]$l^2=(4r)^2+(2r)^2$[/tex]
l = 4.472 x r
= 4.472 x 50
= 224 mm
= 0.224 m
From the law of gravitation,
We know, [tex]G = 6673 \times 10^{-11} \ m^3 / kg-s^2[/tex]
∴ [tex]$F=G\times \frac{m_c \times m_s}{l^2}$[/tex]
[tex]$F=6.673 \times 10^{-11}\times \frac{4.665 \times 0.512}{(0.224)^2}$[/tex]
[tex]$F = 3.176 \times 10^{-9} \ N$[/tex]
Now,
[tex]$\alpha = \tan^{-1} \left( \frac{2r}{4r}\right)$[/tex]
= [tex]$26.56^\circ$[/tex]
Therefore, we can write it in the vector form as
[tex]$\text{F}=F(-i . \cos \alpha - j. \sin \alpha)$[/tex]
[tex]$\text{F}=3.176 \times 10^{-9}(-i . \cos 26.56 - j. \sin 26.56)$[/tex]
[tex]$\text{F}=(-2.840\ i- 1.420 \ j) \times 10^{-9} \ N$[/tex]
Cart A with a mass equal to 24 kg is moving to the right at 3.2 m/s. It collides with Cart B that
has a mass of 32 kg and is moving to the left with a velocity of 12.8 m/s. After the collision,
Cart A has a velocity of 2.9 meters per second to the left. What is the speed of the Cart B after
the collision?
Answer:
Explanation:
According to the Law of Momentum Conservation, what happens after the collision has to equal what happened before the collision because momentum cannot be created nor destroyed; it has to go somewhere else. Like energy eventually dissipates into heat. The equation for this is:
[tex][m_Av_A+m_Bv_B)]_b=[(m_Av_A+m_Bv_B)]_a[/tex] and filling in our info, calling right positive and left negative:
[(24(3.2) + 32(-12.8)] = [(24(-2.9) + 32(vB)] and
[(77 - 410)] = [(-7.0 × 10¹ + 32vB)] and
-330 = -7.0 × 10¹ + 32vB and
-260 = 32vB so
vB = -8.1 m/s Thus, cart B is moving to the left at a velocity of 8.1 m/s
(I used the rules for sig dig very intentionally and correctly; I'm not sure how strict your teacher is about them. I require my students to use the rules to perfection, as I did here.)
A ball is dropped from rest out of a high window in a tall building for 5 seconds. Assuming we ignore air resistance and assume upwards to be positive. A) What will be the final velocity of the ball B) What is the height of the building if it hits the ground after those 5 seconds.
Answer:
what is the upwards force?
Answer:
final velocity=-49m/s and height=122.5
Explanation:
u=0,t=5s,v=?
v=u+gt
v=0+(-9.8)5
v=-49m/s
h=ut+1/2gt*2
h=0(5)±1/2(-9.8)5*2
h=-122.5 or 122.5
but height=122.5 because height cannot be negative
How is the annostructure on the chocolate related to the nanostructure of the grating?
help me plss:(
Answer:
From butter in croissants to cocoa solids in chocolate, edible fats pack a flavor punch that delights like no other macronutrient we consume. Fats are the most energy dense macronutrients, providing more than twice as many kilocalories per gram as proteins or carbohydrates, which may be the reason we've developed a taste for them.
Explanation:
In a longitudinal wave, amplitude can be measured from the distance between high pressure areas of the wave called what?
Answer:
The high pressure areas in a longitudinal wave are called compressions.
Physicist ____ was found to have completely made up some of the data on which his astounding discoveries were made.
Answer:
Jan Hendrik Schön I believe
PLEASE HELP 40 POINTS
Liar, not even 40 points....
what are the four importance of apron?
Answer:
To prevent our clothes from dust, dirt, spills and debris during cooking, serving, cleaning or performing a creative task. Aprons protect your clothes and acts as a protective barrier.
When storm clouds produce lighting and thunder, what kind of energy is produced?
Answer:
Static Electricity
Explanation:
I think this is what your asking
An object of mass m slides down an incline with angle 0.
Which expression
shows the net force on the object along the surface of the incline?
A. mg cos(0) - FN
B. mg cos(0)
C. mg sin(0)
D. mg sin(0) - FN
Answer:
C. mg sin(θ)
Explanation:
The plane is incline and the only force acting in the object is the gravity, so you multiply mg per sin(θ) because sin(θ) gave you the part of the gravity acting in the horizontal direction parallel with the inclined surface
The expression shows the net force on the object along the surface of the incline is mg sin(θ). The correct option is C.
What is Net force?When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
An object of mass m slides down an incline with angle (θ).
The plane is incline and the only force acting in the object is the gravity, The weight or gravity acting in the horizontal direction parallel with the inclined surface is mg sin(θ).
Thus, the correct option is C.
Learn more about net force.
https://brainly.com/question/18031889
#SPJ2
Can somebody please answer this correctly I will give brainliest
what is a product made from no renewable resources
Answer:
a nail
Explanation:
Answer:
crude oil, natural gas, coal, and uranium. These are all resources that are processed into products that can be used commercially.
Explanation:
A 4kg and 5kg bodies moving on a frictionless horizontal surface at a velocity of ( -6i )m/s and ( +3 )m/s respectively. Collide a head on elastic collision. What is the velocity ( magnitude and direction) of the each body after collision?
Answer:
4 kg → +4 m/s
5 kg → -5 m/s
Explanation:
The law of conservation of momentum states that:
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'left side → velocities before collisionright side → velocities after collisionYou'll notice that we have two missing variables: v₁' & v₂'. Assuming this is a perfectly elastic collision, we can use the conservation of kinetic energy to set the initial and final velocities of the individual bodies equal to each other.
v₁ + v₁' = v₂ + v₂'Let's substitute all known variables into the first equation.
(4)(-6) + (5)(3) = (4)v₁' + (5)v₂' -24 + 15 = 4v₁' + 5v₂' -9 = 4v₁' + 5v₂'Let's substitute the known variables into the second equation.
(-6) + v₁' = (3) + v₂' -9 = -v₁' + v₂' 9 = v₁' - v₂'Now we have a system of equations where we can solve for v₁ and v₂.
-9 = 4v₁' + 5v₂' 9 = v₁' - v₂'Use the elimination method and multiply the bottom equation by -4.
-9 = 4v₁' + 5v₂' -36 = -4v₁' + 4v₂'Add the equations together.
-45 = 9v₂'-5 = v₂'The final velocity of the second body (5 kg) is -5 m/s. Substitute this value into one of the equations in the system to find v₁.
9 = v₁' - v₂'9 = v₁' - (-5) 9 = v₁' + 5 4 = v₁'The final velocity of the first body (4 kg) is 4 m/s.
We can verify our answer by making sure that the law of conservation of momentum is followed.
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂' (4)(-6) + (5)(3) = (4)(4) + (5)(-5)-24 + 15 = 16 - 25 -9 = -9The combined momentum of the bodies before the collision is equal to the combined momentum of the bodies after the collision. [✓]
On what factors does critical velocity depend on
Explanation:
The critical velocity is that velocity of liquid flow, up to which its flow is streamlined (laminar)& above which its flow becomes turbulent. It's denoted by Vc & it depends upon: Coefficient of viscosity of liquid (η) Density of liquid. Radius of the tube.
4. A girl is sitting on a tire swing that is attached with a rope that is 2.1 m in length. Her dad pushes her with a speed of 3.0 m/s. If the centripetal force is 88 N, what is the mass of the girl?
pls help will mark brainliest, pls
Answer:
The answer is true. This is correct.
If you stood on Mars and lifted a 15kg pack,you would be pulling with a force greater than...
Answer: See answers below.
Explanation: In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
Venus
Moon
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
Venus
Moon
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
A solid cylinder has a mass of 5 kg and radius of 2 m and is fixed so that it is able to rotate freely around its center without friction. A 0.02 kg bullet is moving from right to left with an angular momentum of 9 kgm2s just before it strikes the cylinder near its bottom and gets stuck at the outer radius. What is the angular velocity (magnitude and direction) of the cylinder bullet system after the impact
Answer:
0.893 rad/s in the clockwise direction
Explanation:
From the law of conservation of angular momentum,
angular momentum before impact = angular momentum after impact
L₁ = L₂
L₁ = angular momentum of bullet = + 9 kgm²/s (it is positive since the bullet tends to rotate in a clockwise direction from left to right)
L₂ = angular momentum of cylinder and angular momentum of bullet after collision.
L₂ = (I₁ + I₂)ω where I₁ = rotational inertia of cylinder = 1/2MR² where M = mass of cylinder = 5 kg and R = radius of cylinder = 2 m, I₂ = rotational inertia of bullet about axis of cylinder after collision = mR² where m = mass of bullet = 0.02 kg and R = radius of cylinder = 2m and ω = angular velocity of system after collision
So,
L₁ = L₂
L₁ = (I₁ + I₂)ω
ω = L₁/(I₁ + I₂)
ω = L₁/(1/2MR² + mR²)
ω = L₁/(1/2M + m)R²
substituting the values of the variables into the equation, we have
ω = L₁/(1/2M + m)R²
ω = + 9 kgm²/s/(1/2 × 5 kg + 0.02 kg)(2 m)²
ω = + 9 kgm²/s/(2.5 kg + 0.02 kg)(4 m²)
ω = + 9 kgm²/s/(2.52 kg)(4 m²)
ω = +9 kgm²/s/10.08 kgm²
ω = + 0.893 rad/s
The angular velocity of the cylinder bullet system is 0.893 rad/s in the clockwise direction-since it is positive.
Electrical current is the flow of ____________
A) helium
B) protons
C) atoms
D) electrons
How much voltage is required to make 0.56 A flow through a 72-ohm resistance? [V = I x R]
A)48 V
B)36 V
C)40 V
D)52 V
WILL GIVE BRAINLIEST!!!
Solution :
A) Electric current is the flow of electrons .
B) We know, by ohm's law :
V = I × R
Putting given values in above equation, we get :
V = 0.56 × 72 V
V = 40.32 V
Hence, this is the required solution.
Lake is home to a large number of trout. Identify what is most likely to happen if a chemical is dumped into the lake. It is a science question
Answer:
The correct option is C) III. That is, the trout will suffer from disease.
Explanation:
Note: This question is not complete as the options are not included. The complete question with the options is therefore provided before answering the question as follows:
A lake is home to a large number of trout. Identify what is most likely to happen if a chemical is dumped into the lake.
I. The trout will not be affected by the pollution.
II. The number of trout will increase.
III. The trout will suffer from disease.
A) I
B) I and II
C) III
D) II and III
The explanation of the answer is now provided as follows:
Natural selection is the process that took place in the lake. Only those trouts that were fit to survive, or those that have alleles that allow them adapt to new conditions, live and multiply in the presence of an external environmental effect like pollution. In such a circumstance, the fittest organisms would have survived, and the population's allelic frequency would have grown through time. Due to pollution, creatures harboring the other alleles died, causing the total frequency of alleles to alter.
Therefore, the correct option is C) III. That is, the trout will suffer from disease.
show the relation between degree Celsius and degree fahrenheit??
I hope you understand....
Light travels through space at a speed of 3.0 x 108 m/s. A space probe is
traveling toward Earth at 2.5 * 108 m/s when one of its spotlights is turned
on. What speed would an observer on Earth measure for the light from the
spotlight?
O A. 2.5 * 108 m/s
O B. 3.0 x 108 m/s
O c. 5.5 x 108 m/s
O D. 0.5 x 108 m/s
Explanation:
The answer is (B). The speed of light is the same for all observers regardless of their motion relative to the light source.
The speed would an observer on Earth measures for the light from the spotlight will be 3×10⁸ m/sec.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.
The given data in the problem is;
The speed of light is, [tex]\rm C =3 \times 10^8\ m/sec[/tex]
All frames of reference have the same speed of light in a vacuum. Therefore the speed would an observer on Earth measures for the light from the spotlight will be 3×10⁸ m/sec.
Hence option B is correct.
To learn more about the speed refer to the link;
https://brainly.com/question/7359669
One twin sets off on a long space voyage traveling at 0.9 c, while the other stays on Earth. When she returns 60 years later, the traveling sister has hardly aged at all, while her twin has aged 60 years. Which aspect of relativity is demonstrated in this situation
Answer:
This is the twin paradox.
Which of the following changes occurs during nuclear fission?
A. Energy is absorbed from the surroundings.
B. Atomic nuclei combine to form a larger nucleus.
C. Energy is converted into mass.
D.
The parent nucleus splits into lighter daughter elements.
Reset
Answer:
The parent nucleus splits into lighter daughter elements
Explanation:
Nuclear fission involves the splitting of nucleus of a lighter element with smaller particles
Choices:
A. Most kinetic energy and least potential energy
B. Most potential energy and least kinetic energy
C. Potential energy is equal to kinetic energy
D. Potential energy is increasing
E. Potential energy is decreasing
F. Kinetic energy is increasing
G. Kinetic energy is decreasing
Directions: Write one letter from the choices above in each of the spaces.
1. When the minion hits the ball at position one, what choices best describe the energy present. (choose 3)
___________, ___________, _____________
2. Position 2 (choose 2) ____________, ___________
3. Position 3 (choose 3) _____________, ____________, ______________
4. Position 4 (choose 2) ______________, _____________
5. Position 5 (choose 2) ______________, _____________
6. Positions 6 (right when the ball is about to touch the ground ___________, ____________, _____________
Answer:
I think there's a pdf for the questions you need
WorksheetKineticVsPotentialEnergy.pdf
Explanation:
(answer it or get reported) Please answer it w the steps
Answer;
The mass value for the above kinetic energy equation is 400.0000 kg. This is equal to:
■ 400,000.0000 g.
■ 14,109.6000 ounces.
■ 881.8480 pounds.