Help please I will mark you the brainly!

St. John’s

_________

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Answer:

  4/3 m/s

Explanation:

Assuming momentum is conserved, the sum of products of mass and speed before the collision is the same as after:

  (2000 kg)(4 m/s) +(4000 kg)(0 m/s) = (2000 +4000 kg)(Vt)

  Vt = (8000 kg·m/s)/(6000 kg) = 4/3 m/s

The speed of the combined objects after the collision is 4/3 m/s.

Answer:

Explanation:

The speed of the wave given only it's frequency and wavelength can be found by using the formula

[tex]c = f \times \lambda[/tex]

where

c is the velocity of the wave in m/s

[tex] \lambda[/tex] is the wavelength in m

f is the frequency in Hz

From the question

c = 2700 × 6 = 16,200

We have the final answer as

Hope this helps you

The final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.

EQUATION OF MOTION:

The final velocity of a moving object can be calculated by using one of the equations of motion as follows:

V = u + at

Where;

According to this question,

v = 0 + 4.3(5)

v = 21.5m/s.

Therefore, the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.

Learn more about equation of motion at: https://brainly.com/question/8898885?referrer=searchResults

Answer: The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg.

Explanation:

Answer:

The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg. which to calculate using this website is too large. To give idea of size, the Sun is 99.86% the mass of the solar system.

Explanation:

1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua ([tex]v[/tex]), en metros por segundo:

[tex]v = \sqrt{\frac{K}{\rho} }[/tex] (1)

Donde:

Si sabemos que [tex]\rho = 1\times 10^{3}\,\frac{kg}{m^{3}}[/tex] y [tex]K = 2,16\times 10^{9}\,\frac{N}{m^{2}}[/tex], entonces la velocidad de las ondas sonoras es:

[tex]v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }[/tex]

[tex]v\approx 1469,694\,\frac{m}{s}[/tex]

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.

2) Luego, determinamos la longitud de onda ([tex]\lambda[/tex]), en metros, mediante la siguiente fórmula:

[tex]\lambda = \frac{v}{f}[/tex] (2)

Donde [tex]f[/tex] es la frecuencia de las ondas sonoras, en hertz.

Si sabemos que [tex]v\approx 1469,694\,\frac{m}{s}[/tex] y [tex]f = 1000\,hz[/tex], entonces la longitud de onda de las ondas sonoras es:

[tex]\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}[/tex]

[tex]\lambda = 1,470\,m[/tex]

La longitud de onda de las ondas sonoras es 1,470 metros.

Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: https://brainly.com/question/1070238

Answer:

I think it would be 0.1496 but I'm not really sure sorry

Answer:

You should try your best to answer the question.

The main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.

The mechanical advantage of the ramp is calculated as follows;

[tex]M.A = \frac{L}{h}[/tex]

As the length of the ramp increases, people will be move up to a greater distance up the staircase.

Thus, the main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.

Learn more about mechanical advantages of ramps here: https://brainly.com/question/200179

Explanation:

c. if the vector is oriented at 0° from the X -axis.

Answer:

A network has 5 basic components viz. clients, servers, channels, interface devices and operating systems.

Answer:

This air being forced out causing the air pressure inside to be much lower than that on the outside. As higher air pressure always pushes, it keeps the two plungers together.

Hope that helps. x

[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2[/tex]

[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2[/tex]

[tex]\\ \sf\Rrightarrow K.E=20J[/tex]

[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2[/tex]

[tex]\\ \sf\Rrightarrow K.E=40J[/tex]

[tex]\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} [/tex]

[tex]\qquad[/tex]______________________________

Then –

[tex]\qquad[/tex] [tex]\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}[/tex]

[tex]\qquad[/tex] [tex] \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]

[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]

[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }[/tex]

[tex]\qquad[/tex][tex] \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }[/tex]

[tex]\qquad[/tex][tex] \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }[/tex]

[tex]\qquad[/tex] [tex]\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }[/tex]

[tex]\qquad[/tex] [tex] \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }[/tex]

Therefore, the vertical component of velocity of projectile at this height will be–

☀️[tex]\qquad[/tex][tex] \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }[/tex]

Answer:

A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2

The amount of work done by the car engine if it is 100% efficient is 366.67 Joules.

Given the following data:

To determine the amount of work done by the car engine if it is 100% efficient:

Mathematically, the work done by an object with respect to power and time is given by the formula:

[tex]Work\;done = \frac{Power}{time}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = \frac{22000}{60}[/tex]

Work done = 366.67 Joules.

Read more: https://brainly.com/question/13818347

Answer: 2

Explanation: Because if you add 1  to 8 you get 9 then subtract 9 by 7 then and your answer is

The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A

From the question,

We are to calculate, the amount of current flowing in the wire.

From the formula,

[tex]I =\frac{nQ}{t}[/tex]

Where I is the current

n is the number of charge

Q is the quantity of charge

t is the time

From the given information

n = 8

Q = e = 1.69 × 10⁻¹⁹ C

t = 8 msecs = 8 × 10⁻³ sec

Putting the parameters into the formula, we get

[tex]I = \frac{8 \times 1.69 \times 10^{-19} }{8\times 10^{-3} }[/tex]

[tex]I = 1.69 \times 10^{-16} \ A[/tex]

Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A

Learn more here: https://brainly.com/question/22135459

Answer:

Jake’s horse will only need to exert enough force to make the carriage accelerate. Even though the carriage will pull on the horse as well, that force is not enough to make the horse accelerate in the direction of the carriage because it is only strong enough to make the carriage accelerate, not the horse.

Explanation:

Additional info: the horse has more mass than the carriage does so it would require a stronger force to make the horse accelerate.

Answer: Jake’s horse will only need to exert enough force to make the carriage accelerate .Since the horse has a greater mass than the carriage, it requires a stronger force to make the horse accelerate.

Explanation: Sorry it took so long lol

Answer:

try 2.4136 as an answer/ good luck

Answer:

The inductive time  constant is just T = L / R

T = 10E-3 henry/ 10 ohm = 10E-2 sec = .1 sec  

(.01 / 10 = .1)

Answer:

0.9m/s^2 (yours is 0.87, so choose that)

Explanation:

formula for centripetal acceleration:

v^2/r

to find v, we know that f=1/90s, and r=180m.

v=(2pir)/T

v=(2pi(180))/90

v=12.6m/s

now plug into a=v^2/r

a=(12.6)^2/180

a=0.9m/s^2

Answer:

Point A

Explanation:

Point C is way to close to where the force would need to be.

Point B is close but not as close, the reasonable answer would be point A.

Marianne’s father should place the small rock: he should place the rock (fulcrum) close to the boulder (at Point A).

The simplest devices, like levers, are employed to complete tasks quickly. Leverage is the ability to increase an input force to produce a stronger output force. We are known that there are different kinds of levers depending on the force, weight, and fulcrum point. Each tool that is used to complete a task falls into one of these categories.

One of the six simple devices that Renaissance scientists identified. Leverage is the ability to increase an input force to produce a stronger output force.  The mechanical advantage of the lever is determined by the ratio of output force to input force.

Learn more about lever here:

https://brainly.com/question/18128414

#SPJ2

Answer:

Explanation:

The sun is much closer than the other stars

When traveling with average speed 40 km/h, the car would cover a distance of 80 km in time t such that

40 km/h = (80 km) / t   ⇒   t = 2 h

so the total travel time is 2 h + 3 h = 5 h.

Average speed is defined as the total distance traveled divided by the time it took to cover that distance. So if the overall average speed was 30 km/h, then

30 km/h = (80 km + x) / (5 h)   ⇒   x = 70 km

where x is the distance traveled in the last 3 h of the trip.

Then the total displacement of the car is 80 km + 70 km = 150 km.