Heat Transfer 12 Directions: Drag the arrows to the correct locations on the image. directions in which heat flows. The diagram below shows three solid objects. Two of the objects are hot and one is cold. If heat is transferred between these objects via conduction, use the arrows to indicate the direction.

That's the question and please someone help me I can't figure this out because of how much I've been absent throughout this lesson
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The statement that best illustrates the application of the principles of behaviorism is -

"A parent is using "time out" as a consequence for bad behavior".

The theory that human and animal behaviour can be explained in terms of conditioning, without appeal to thoughts or feelings, and that some mental conditions are best treated by altering behaviour patterns.

Given are the applications of the principles of behaviorism.

The statement that best illustrates the application of the principles of behaviorism is -

"A parent is using "time out" as a consequence for bad behavior".

Therefore, the statement that best illustrates the application of the principles of behaviorism is -

"A parent is using "time out" as a consequence for bad behavior".

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The magnetic field strength of the solenoid of radius 2 m is 2.0096 T.

Magnetic field is the region or space around which magnetic force is felt or experienced.

To calculate the magnetic field strength inside a solenoid, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the magnetic field strength is 2.0096 T.

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Answer:

To find the distance the vehicle traveled, you will need to find the average speed of the vehicle over the 4.60 seconds and multiply that by the time traveled.

The average speed of the vehicle can be found by adding the initial speed and the final speed, and then dividing by 2: (15.0 + 28.0) / 2 = 21.5 km/h.

The distance traveled can be found by multiplying the average speed by the time traveled: 21.5 km/h * 4.60 s = 98.7 km.

So, the vehicle will have traveled 98.7 km.

Explanation:

The reaction is in A in vertical direction is W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ).

In terms of psychology, "stress" and "strain" are sometimes used interchangeably in popular culture, as in the expressions "I'm feeling stressed" or "I'm under a lot of pressure."

In engineering, these phrases have specific, technical meanings. If a hook in the steel wire is attached,

If you hang the wire from the ceiling while placing a weight on the lower end, it will sag. By dividing the length change by the starting length, the strain in the wire may be computed.

Thus, as per the given scenario, W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ) will be the equation.

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(a) The kinetic energy of the ball just before it hits the ground is 78.4 J.

(b) The kinetic energy of the ball at a height of 1.2 m is 31.36 J.

The kinetic energy of the ball just before it hits the ground is calculated as follows;

K.E ( bottom) = P.E (top)

P.E (top) = mgh

where;

P.E (top) = 4 x 9.8 x 2

P.E (top) = 78.4 J

The change in the potential energy of the ball during its motion is calculated as follows;

ΔU = P.Ef - P.E i

where;

ΔU = 0 J - 78.4 J

ΔU = -78.4 J

The kinetic energy of the ball at a height of 1.2 m is the change in the potential energy of the ball and it is calculated as follows;

K.E = -ΔU

K.E = -mg (hf - hi)

K.E = (4 x 9.8)(2m - 1.2 m)

K.E = 31.36 J

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In the figure below, the maximum speed of a 2.0 g particle that oscillates between x = 2.0 mm and x = 8.0 mm is 63 m/s.

Periodic or oscillatory motion is defined as a motion that repeats itself. Due to a restoring force or torque, an object in such motion oscillates around an equilibrium position.

Energy is conserved in oscillation.

So, the maximum loss in Potential Energy = Maximum gain in Kinetic energy

5 J - 1 J = Maximum gain in Kinetic energy

Maximum gain in Kinetic energy = 4 J

[tex]0.5 \times m \times vmax^2 = 4\\0.5 \times 2.0 \times 10^-3\; Kg \times vmax^2 = 4 J\\vmax^2 = 4 \times 10^3 m^2/s^2\\vmax = 63.2 m/s[/tex]

Therefore, the maximum speed of a 2.0 g particle that oscillates between x = 2.0 mm and x = 8.0 mm is 63 m/s.

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Answer:

Choice A. gamma rays

Explanation:

If an object is working against gravity, that means gravity must have the opposite sign of the object (this is why we see objects slow down at their peak height and return to us if we throw them in the air!). If the object is working with gravity, though, they must both be moving in the same direction, therefore gravitational acceleration would be the same sign as the velocity (positive or negative depending on how you define your axes).

Therefore, your answer should be C. Different sign + or - on the acceleration.

I hope this helps!

The atmospheric pressure on earth is 1 atm. This pressure is equivalent to the mercuric pressure of 760 mmHg. The atmospheric pressure on the surface of Venus is 9200 kpa which is equivalent to 69017 mmHg.

Pressure is the force acting per unit area. In the atmosphere, the gaseous particles and dust exerts a pressure in the atmosphere. The atmospheric pressure depends on the temperature.

There are various units for pressure. Normally the atmospheric pressure is expressed in atm unit. The mmHg pressure is based on the raise in mercuric level with respect to increase in pressure.

1 mmHg = 0.0013133 atm

hence, 760 mmHg = 1 atm

On the surface of Venus, the pressure is 9200 kilopascal.

1 mmHg = 0.133 KPa

then 9200 KPa = 9200/0.133 = 69017 mmHg pressure.

Therefore, height of mercuric column will be 69017 mm in Venus surface.

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To solve this we must be knowing each and every concept related to  net current. Therefore, the circuit's overall net current is 0.1 A, flowing clockwise.

The term "net current" refers to the total currents after taking current direction into account. If a node sends 1 mA inside and 5 mA out, the total current equals 4 mA out.

The sum of all entering currents must match the sum of all exiting currents, according to KCL. According to Ohm's Law, the current flowing is equivalent to the combined voltage dividing by the entire resistance. In contrast to a series circuit, where the total current is the same across all of the components, the total current inside a parallel connection is really only equal to the particular current in that part of the circuit.

Net current

i = V / Ri

 = (9 - 6) / (10 + 20)i

 = 0.1 A

in clockwise way

Therefore, the circuit's overall net current is 0.1 A, flowing clockwise.

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Ans-The density of states function describes the number of states that are available in a system and is essential for determining the carrier concentrations and energy distributions of carriers within a semiconductor.

Answer:

density equal to mass upon volume

simple definition

Answer:

70.56 J

Explanation:

The increase in potential energy of the ball can be calculated using the formula:

PE = mgh

where:

PE is the increase in potential energy

m is the mass of the ball (6 kg)

g is the acceleration of gravity (9.8 m/s²)

h is the height the ball is lifted (1.2 m)

Substituting in the values, we get:

PE = (6 kg)(9.8 m/s²)(1.2 m)

This simplifies to:

PE = 70.56 J

So the increase in the ball's potential energy is 70.56 J.

Answer:

70.56 J

Explanation:

Gravitational Potential Energy= mass×gravitational pull× height

= 6×9.8×1.2= 70.56 J

Answer:

-0.0069 rad/s

Explanation:

The change in angular velocity of the rod can be determined by using the conservation of angular momentum equation: Lf = Li.

The initial angular momentum of the rod is Li = Iwo and the final angular momentum of the rod is Lf = Iwf.

Plugging in the given values, we get:

(1.05 x 10^-3 kg•m^2)(0.606 rad/s) + (5 x 10^-3 kg)(0.609 m)^2(wf) = (1.05 x 10^-3 kg•m^2)(wo).

Solving for wf, we get wf = -0.0069 rad/s.

Therefore, the change in angular velocity of the rod is -0.0069 rad/s.

The third force must be 3.0 newtons due north in order for equilibrium to exist in the system.

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The total work done by this force is 28.9-1457.86 N m.

Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.

The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.

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The potential energy of a rock of mass 500 g, held at a height of 2 m above ground is 9.8J.

The formula for the gravitational potential energy of an object is:

PE = mgh

where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2 on the Earth's surface), and h is the height of the object above the reference point.

So, in this case, we can plug in the given values to find the potential energy of the rock:

PE = (500 g) x (9.8 m/s^2) x (2 m)

The weight of the rock is m*g = 500 g * 9.8 m/s^2 = 4.9 N

Therefore,

PE = 4.9 N x 2 m = 9.8 J

Therefore, the potential energy of a rock of mass 500 g, held at a height of 2 m above ground is 9.8J.

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The initial horizontal velocity of the football if a player kicks a football from ground level with a velocity of 27/ms at an angle of 30 degrees above the horizontal is 23.662 m/s.

To find the initial horizontal velocity (Vx) of the football, you can use the horizontal component of the velocity vector. The horizontal component of velocity is found by multiplying the velocity by the cosine of the angle of launch.

[tex]V_{x}[/tex] = V × cos(angle)

where V is the initial velocity, the angle is the angle of launch (in this case, 30 degrees), and cos is the cosine function.

So, in this case, the initial horizontal velocity of the football would be:

[tex]V_{x}[/tex] = 27 m/s × cos(30)

[tex]V_{x}[/tex] = 27 m/s × 0.866

[tex]V_{x}[/tex] = 23.662 m/s

So the initial horizontal velocity of the football, which moves in the x-direction, is approximately 23.662 m/s.

This means the football will move 23.662 m/s in x direction initially and if no air resistance acts upon the football, it will move at the same velocity in x direction throughout the motion.

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Precipitation amount, storm frequency, and severity, storm duration, kind of precipitation, wind during storm, and wind during evaporation are the main precipitation and storm elements that influence interruption loss (Kenneth, 1996).

All procedures that stop rainfall from instantly reaching the soil are referred to as interceptions. The two main ways that vegetation intercepts water are by catching it on leaf surfaces throughout the canopy and by depositing litter on the ground.

Precipitation that is intercepted by leaves, plant branches, and the forest floor prevents it from reaching the soil and instead stays on the surface.

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Answer:

CM of a system ( 0.5l , 0.25l )

Explanation:

x = (m1.x1 +m2.x2 +m3.x3) / ( m1 + m2 +m3)

x = ( m x 0 + m x 0 + 2m x l ) / ( m+m+2m)

x = 2m x l / 4m

x = 0.5 l

y = (m1 x y1 +m2 x y2 +m3 x y3) / ( m1 + m2 +m3)

y = (m x 0) + m x l + 2m x 0 ) / ( m + m + 2m )

y = m x l / 4m

y = 0.25 l

It is a “new moon” (the Moon is totally dark in the sky). The gravitational force between the Earth and the Moon is:

Generally, The gravitational force between two objects is given by the equation:

force = G * (mass1 * mass2) / distance^2

Where G is the gravitational constant (6.67 x 10^-11 N*(m/kg)^2), mass1 and mass2 are the masses of the two objects, and distance is the distance between the two objects.

The mass of the Earth is 5.972 x 10^24 kg, the mass of the Moon is 7.347 x 10^22 kg, and the mass of the Sun is 1.989 x 10^30 kg. The average distance between the Earth and the Moon is 384,400 km, and the average distance between the Earth and the Sun is 149.6 million km.

The gravitational force between the Earth and the Moon is:

force = (G * (mass of Earth) * (mass of Moon)) / (distance between Earth and Moon)^2 force

= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (7.347 x 10^22 kg) / (384400 x 10^3 m)^2 force

= 2.9 x 10^20 N

The gravitational force between the Earth and the Sun is:

force = (G * (mass of Earth) * (mass of Sun)) / (distance between Earth and Sun)^2 force

= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (149.6 x 10^9 m)^2 force

= 3.5 x 10^22 N

To find the net gravitational force on the Earth from the Sun and Moon combined, we add the two forces we found above.

Net force = 2.9 x 10^20 N + 3.5 x 10^22 N

= 3.5 x 10^22 N

When it is a Full Moon the distance is the same 384,400 km

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Answer:

F = G M m / R^2 = m a

G M / R^2 = a

M = a R^2 / G

M = 1.56 N/kg * 6.35 m^2 / 6.67E10-11 N-m^2 / kg^2

M = 1.56 * 6.35 / 6.67E-11 kg

M = 1.49 * 10^11 kg

Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].

Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.

We are given that:

Number of point charges = 3

Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so

E4 = E1 + E2 + E3

E4 = kQ/a² + kQ/√(2a²) + kQ/a²

E4 = kQ [1/a² + 1/√(2a²) + 1/a²]

Thus the electric field at the fourth corner is  E4 = kQ [2/a² + 1/a√2].

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The full load primary current of a 230/115V, 2kVA transformer can be calculated using the formula:

I_primary = (2kVA * 1000 VA/kVA) / (230V)

I_primary = 8.7V

The full load secondary current of the transformer can be calculated using the formula:

I_secondary = (2kVA * 1000 VA/kVA) / (115V)

I_secondary = 17.4V

Therefore, the full-load primary current of the transformer is approximately 8.7V, and the full-load secondary current is approximately 17.4V. It is important to note that these values are based on the assumption that the transformer is operating at its full load capacity. If the transformer is operating at a lower load, the primary and secondary currents will be correspondingly lower.

The things that I will need to survive the layer of the earth called the mesosphere would be thick clothings.

The five(5) layers of the earth include the following such as:

The Mesosphere is one of the layers of the earth that is found directly above the stratosphere and then below the thermosphere.

The characteristics of the mesosphere is that the temperature rises due to reduced absorption of solar radiation and increased cooling by CO2 radiative emissions.

Therefore, for an individual to survive and live effectively at the Mesosphere layer of the earth, such needs thick clothings.

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Time required to film something in HD to collect 1 PB of data is all day for about 3.5 years.

A petabyte, or 2 to the 50th power of a byte, is a unit of measurement for memory or data storage. One exabyte is equal to about 1,024 petabytes (PB), or 1,024 terabytes (TB).

Although traditional network-attached storage (NAS) can handle petabytes of data and is expandable, it might be resource-intensive to traverse the system's ordered storage index.

A common laptop or desktop computer has 16 GB of random access memory for storage (RAM).

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The radius of the hydrogen-atom Bohr orbit shown in the figure is 5.3 nm.

The path that hypothetical electrons take around the nucleus is known as Bohr's orbit.

These orbits are described by Bohr in his hypothesis of the structure of an atom as energy levels or shells where electrons move in a fixed circle around the nucleus.

These orbits resemble solar system orbits, with the exception that they are attracted by electrical forces rather than gravity. The term "ground state" refers to the amount of energy that an electron typically occupies.

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Expansion of universe is not a hypothetical one but the universe is expanding in the sense increase distance over the space and dark matter.

The increase in distance over time between any two particular gravitationally unbound regions of the observable universe is known as the universe's expansion. 

As a result, the size of space itself expands intrinsically. It is not necessary for space to exist outside of the cosmos or for it to extend into anything.

The metric changes in scale rather than space or the things in space moving in the conventional sense. Objects move farther apart from one another at ever-increasing speeds as the spatial component of the universe's spacetime metric scales up.

Any viewer in the cosmos would see that all of space appears to be expanding, except for the galaxies receding with a speed proportional to the distance from the observer.

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The nodal voltage is V and the currents are as defined in the diagram.

At the upper node, Kirchhoff's current law equation is  I1+I5=I2+I3

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