Hayley is considering two gym membership plans. The plans are detailed here. Plan One: $40 for a monthly pass plus $4 for each gym visit Plan Two: $12 for each gym visit. Which equation expresses the situation in the form of y=mx+b where x is the number of gym visits per year and y is the total cost per month for Plan One?

y=40x+4


y=4x+40


y=12x


y=3x+50

please help

Answer:

D: {-2, 0, 2}

R: {-1, 1, 3

[tex]\mathfrak{ x ^ { 2 } + b x - 4 = 0} [/tex]

[tex]\mathfrak{bx-4=-x^{2} } [/tex]

[tex]\mathfrak{bx=-x^{2}+4 } [/tex]

[tex]\mathfrak{xb=4-x^{2} } [/tex]

[tex]\mathfrak{\frac{xb}{x}=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{ b=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{b=-x+\frac{4}{x} } [/tex]

AnSwEr

[tex]\boxed{\mathfrak{b=-x+\frac{4}{x},x\neq 0 } }[/tex]

 ღ ꪑ꠸᥅ꫀꪊ

Answer:

55.56%

Step-by-step explanation:

55/99=.5555555...

.55555...*100=55.555...%

55.56%

Answer:

true

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]x - 0.20x \: = 1480[/tex]

[tex]0.8x = 1480[/tex]

[tex]x = 1480 \div 0.8[/tex]

I'm not sure if this is correct, but I got this

Last year’s computer models are discounted 20%. If a computer is on sale for $1,480, what is the original price of the computer rounded to the nearest dollar?

20% = 0.2

1,480 x 0.2 = 296

1,480 + 296 = 1,776

Answer: 1,776

Again, I don't know if this is correct, so don't be 100% sure with my response.

Answer: The blue dot's value on the number line is 1.

Step-by-step explanation: Each two-skip interval from -7 to -3 is a skip of 4. Therefore, -3 skipped two times is -3 + 4, which equals 1, therefore the blue dot's value on the number line is 1.

Answer:

the perimeter of the figure is 27.4 mi

Step-by-step explanation:

rectangle perimeter = 6+6+6 = 18

half circle perimeter = 1/2 2πr = 3.14 × 3 = 9.42

the perimeter of the figure is 18+9.42 = 27.42 --> 27.4 mi

Answer:

292.6

Step-by-step explanation:

Answer:

-5.

Step-by-step explanation:

5 + -5 = 0, so i's -5.

Jake's Argument is correct, adding zero (0) to an addend does not change a sum.

Addend is number which is added to another number.

For example:

y + 5 = 8

where;

Adding zero (0) to an addend does not change a sum. An example is present below;

5 + 3 = 8

add zero (0) to 3 and check if the final result will change;

5 + (3 + 0) = 5 + 3 = 8

Thus, Jake's Argument is correct, adding zero (0) to an addend does not change a sum.

Learn more about addend number here: https://brainly.com/question/654494

Answer:

I feel like something is wrong with the equation but the answer is a = 3

Step-by-step explanation:

a + 3a - 3 = 6 + 3 = 9

--> 4a = 12 --> a = 3

Answer:

one solution

Step-by-step explanation:

Since both are y-isolated equation, we can write as:

[tex]\displaystyle \large{6x-2=4x-2}[/tex]

Solve for x, first move 4x to subtract with 6x and -2 to add with -2

[tex]\displaystyle \large{6x-4x=-2+2}\\\displaystyle \large{2x=0}\\\displaystyle \large{x=0}[/tex]

Then substitute x = 0 in any of these equations which we receive y = -2.

And the solution is (0,-2) which only has one solution.

Answer:

Hey mate....

Step-by-step explanation:

This is ur answer....

an attribute of a shape or relation; exact reflection of form on opposite sides of a dividing line or plane.

Hope it helps!

Brainliest pls!

Follow me! :)

Answer:

The definition of correspondence is the act of conforming or agreeing with someone or something else. An example of correspondence is when a person acts in the same way she appears to think.

In simple terms, it means communication, generally looking at two things and identifying stuff about them

Hope that helps. x

So basically what you have to do is first identify all of the sides or angles that equal eachother then you can see if you did a side side and side in a row etc, like 44 would be SAS because the vertical angles would be inbetween the two sides. 46 would be SSS because after you make the line in the middle for reflexive property you can see that there are three sides in a row. If this didnt help i recommend looking on Khan Academy

Answer: store b because you can get more ground beat.

Step-by-step explanation:

Step-by-step explanation:

Two t-shirts that are(31.80) plus a hat(6.20) cost £38.00.

which means that one t-shirt costs £15.90 :)

Answer:

4 burgers

Step-by-step explanation:

four burgers

If you're making the patties yourself (to save money or because you love making burgers), assume four burgers per pound of meat

Answer:

70% right, 30% wrong

Step-by-step explanation:

3 is 30% of 10

Answer:

1,2,4,5,8,10,20,40

Step-by-step explanation:

Have a nice day

Answer:

10.5

Step-by-step explanation:

A=a+b

2h=2+5

2·3=10.5

Answer:

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

[tex]AD^{2}=AC^{2}+CD^{2}[/tex]

25=9+[tex]CD^2[/tex]

[tex]CD^2[/tex]=25-9=16

[tex]CD=\sqrt{16} =4 units[/tex]

Now

Area of rectangle Δ ACD=[tex]\frac{1}{2} CD*AC=\frac{1}{2}*4*3=6\: square \:units[/tex]

similarly,

[tex]\frac{1}{2} AD*CE=6\: square \:units\\ 5*CE=6*2\\CE=\frac{12}{5}=2.4 units[/tex]

since AB=CE=2.4 units

Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

[tex]AC^{2}=AE^{2}+CE^{2}\\3^2=AE^2+2.4^2\\9-5.76=AE^2\\AE and BC=\sqrt{1.24} =1.11 units[/tex]

now

area of trapezoid=area ofΔACD+Area of ΔABC

=6+[tex]\frac{1}{2}AB*BC=6+\frac{1}{2}*2.4*1.11=6+1.33 =7.33\: square \:units[/tex]

Step-by-step explanation:

Answer:

n(E) = 6

Step-by-step explanation:

That's to say that there are 6 five-digit numbers with 7 in the first place and 8 in the last place, using the digits 2, 3, 4, 7 and 8. Therefore n(E) = 6.

Answer:

x=3, y=-6

Step-by-step explanation:

As you know there are many ways to solve this question! First is Subsitutuion, Second is Elimination, and Third is Graphing!

Let’s begin with our detailed answer:

As you know subsitution is solving for a variable and then it can be used as a variable substitution to figure out x and y.

So in our system of equations:

[tex]\left \ {3x+2y=-3}} \atop {9x+4y=3}} \right.[/tex]

I will just take one equation and solve for x but it actually dosent matter which variable you subsitutue and solve for.

[tex]\left \ {3x+2y=-3}} \atop {9x+4y=3}} \right.[/tex]

To eliminate this question we can divide the top part by -3:

[tex]\left \ {-9x-6y=9}} \atop {9x+4y=3}} \right.[/tex]

Let‘s sum these system of equation and we get: [tex]y=-6[/tex]

We can now insert y as -6 and solve for x:

[tex]3x-12=-3[/tex]

[tex]x=3[/tex]

So, [tex]x=3, y = -6[/tex]

Answer:

(3, - 6 )

Step-by-step explanation:

3x + 2y = - 3 → (1)

9x + 4y = 3 → (2)

Multiplying (1) by - 3 and adding to (2) will eliminate the x- term

- 9x - 6y = 9 → (3)

Add (2) and (3) term by term to eliminate x

0 - 2y = 12

- 2y = 12 ( divide both sides by - 2 )

y = - 6

Substitute y = - 6 into either of the 2 equations and solve for x

Substituting into (1)

3x + 2(- 6) = - 3

3x - 12 = - 3 ( add 12 to both sides )

3x = 9 ( divide both sides by 3 )

x = 3

solution is (3, - 6 )

Answer:

A. 511; 6

Step-by-step explanation:

The margin of error would be [tex]\pm\frac{517-505}{2}=\pm\frac{12}{2}=\pm 6[/tex]

The sample mean would be [tex]505+6=511[/tex] (or [tex]517-6=511[/tex])

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

[tex]\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}[/tex]

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

[tex]\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}[/tex]

c) The mean is given by the integral,

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy[/tex]

Integrate by parts, with

[tex]u = y \implies du = dy[/tex]

[tex]dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}[/tex]

Then

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)[/tex]

[tex]\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy[/tex]

[tex]\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}[/tex]