[H] = 1.00 x 10^-7 M

a. Acidic
b. Basic
c. Neutral

Answers

Answer 1
the answer would be A

Related Questions

In this experiment, you will need to prepare 250.0 mL of 0.100 M KCl(aq) solution. Determine the mass in grams of potassium chloride required to prepare this solution. Type your numerical answer (no units) in the box below. Even though the number of significant figures is limited to three by the inputs, please report your answer to four significant figures.

Answers

Answer: The mass in grams of potassium chloride required to prepare this solution is 1.862 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

moles of [tex]KCl[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{74.5g/mol}[/tex]

Now put all the given values in the formula of molality, we get

[tex]0.100=\frac{x\times 1000}{74.5g/mol\times 250.0ml}[/tex]

[tex]x=1.862g[/tex]

Therefore, the mass in grams of potassium chloride required to prepare this solution is 1.862 grams

intermolecular forces between particles are​

Answers

Explanation:

Intermolecular forces hold multiple molecules together and determine many of a substance's properties. All of the attractive forces between neutral atoms and molecules are known as van der Waals forces, although they are usually referred to more informally as intermolecular attraction.

Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules, or ions ). These forces are weak compared to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.

In a nuclear equation:??

Answers

All of the answers are true.

What determines how atoms will bond?​

Answers

Answer:

Explanation:

The number of electrons in the outermost shell of a particular atom determines its reactivity, or tendency to form chemical bonds with other atoms.

Question 4 (10 points)
If a sollition has a pOH of 5.2 the [OH-] of the solution is
оа
6x 10-6 M
Ob
6.3 x 10-6 M
Oc
1.58 x 10-5M
Od
2x10-5M

Answers

Answer:

     

Explanation:

       

. Explain why some desert animals excrete uric acid rather than ammonia.
(2 marks)​

Answers

Answer:

AFAIK

Explanation:

uric acid is much less toxic than ammonia, hence bigger concentrations of it are tolerated in the body. This means you can excrete it while excreting very little water - beneficial wherever water's not abundant.

There's a tradeoff though, uric acid requires more energy to synthesize than ammonia, so pretty much all fish, say, excrete ammonia rather than uric acid - it's no problem to dilute ammonia since there's no water shortage.

Bolt can run at a top speed of 28 mph.​

Answers

Actually in more accuracy, he can run in 27.33 mph. Same thing though

What are the components of DNA?

A. ribose sugar, cytosine, guanine, adenine, thymine, and phosphate group

B. ribose sugar, cytosine, guanine, adenine, uracil, and phosphate group

C. deoxyribose sugar, cytosine, guanine, adenine, thymine, and phosphate group

D. deoxyribose sugar, cytosine, guanine, adenine, uracil, and phosphate group

Answers

Answer:

C

Explanation:

A-T G-C

Answer:

C

Explanation:

EDGE 2022

For a chemical reaction, the activation energy for the forward reaction is +181 kJ and the activation energy for the backward reaction is +62 kJ. What is the overall energy change for the forward reaction?

Answers

Given :

For a chemical reaction, the activation energy for the forward reaction is +181 kJ and the activation energy for the backward reaction is +62 kJ.

To Find :

The overall energy change for the forward reaction.

Solution :

The overall energy change for the forward reaction is :

[tex]\Delta E_f = E_f - E_b\\\\\Delta E_f = 181 - 62 \ Kj\\\\\Delta E_f = 119 \ Kj[/tex]

Therefore, the overall energy change for the forward reaction is 119 Kj.

convert 113 Fahrenheit to celcius do full process​

Answers

[tex]\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}[/tex]

45° Celsius

Formula (113°F − 32) × 5/9 = 45°C

ThanksHope it helps

Which of the following involves a change in chemical properties

Answers

Answer: A chemical change occurs when the substance's composition is changed. When bonds are broken and new ones are formed a chemical change occurs.

what is the ph of a 8.4x10^-6 M H+ solution?

Answers

pH=-log[H+]
pH=-log8.4x10^-6

which molecule is butene

Answers

Answer:

Option C is the answer

Butene, also called Butylene, 4 isomeric compound belonging to the series of olefinic hydrocarbons. The chemical formula is C4H8, option c is correct.

What are the 4 isomers of butene?

Butene, also called Butylene, four isomeric Combinations belong to the series of olefinic hydrocarbons. The chemical formula is C4H8.

The isomeric forms are 1-butene, cis-2-butene, trans-2-butene, and isobutylene.

Thus, option "C" is correct. the chemical formula is C4H8.

To learn more about Butene click here:

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4.3 x 10^2 - 7.0 x 10^2 in scientific notation

Answers

-2.7 × 10^2 is the result of the equation.

How many liters of phosphine are produced when 34 L of hydrogen reacts with an excess of phosphorus under STP?

Answers

Answer:

22.67 L of PH₃

Explanation:

The balanced equation is:

[tex]P_4 (s) + 6H_2(g) \to 4PH_3(g)[/tex]

From the equation:

[tex]34 L \times \dfrac{1 \ mol \ of H_2 }{22.4 \ L \ H_2} \times \dfrac{4 \ mol \ of \ PH_3}{6 \ mol \ H_2} \times \dfrac{22.4 \ L \ PH_3}{1 \ mol \ PH_3}[/tex]

= 22.67 L of PH₃

How/what do I answer this?--> "heat of the chemical reactions"
like this is the question :/

Answers

Answer:

The heat of reaction is the energy that is released or absorbed when chemicals are transformed in a chemical reaction. It describes the change of the energy content when reactants are converted into products.

Explanation:

Yeah, that would confuse me a bit but then you read it and then you will get that answer above! Have a great rest of your day!

How many moles of nitrogen are required to produce 13.5 g of NH 3?

Answers

Answer:

number of moles of (N) = 0.794 moles

Explanation:

From the given information:

no of moles of nitrogen (N) = (unknown)???

mass of nitrogen = 13.5 g

molar mass of NH3 = 14 +( 1 × 3) = 17 g/mol

To calculate the no of moles of N, we have:

number of moles of (N) = mass of N/molar mass

number of moles of (N) = 13.5 g/17 g/mol

number of moles of (N) = 0.794 moles

Write the balanced half-reaction that occurs at the anode in a lead-acid (storage) battery during discharge. Phases are optional. anode half-reaction: Write the balanced half-reaction that occurs at the cathode in a lead-acid (storage) battery during discharge. Phases are optional. cathode half-reaction: Write the balanced overall cell reaction that occurs in the lead-acid (storage) battery during discharge. Phases are optional. overall cell reaction:

Answers

Answer: Anode: [tex]Pb+SO_4^{2-}\rightarrow PbSO_4+2e^-[/tex]

Cathode: [tex]PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O[/tex]

Overall cell reaction : [tex]Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O[/tex]

Explanation:

Lead storage battery is a secondary cell used in automobiles and invertors. The anode is made up of lead and undergoes oxidation during discharging and cathode is made up of lead oxide and acts as cathode during discharging. The electrolyte used is dilute .

Lead storage battery acts as electrochemical cell while discharging.

Discharging reaction for  Anode:

Discharging reaction for  Cathode: [tex]PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O[/tex]

Overall cell reaction : [tex]Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O[/tex]

A lead storage battery is an energy storage device. At the anode lead and sulfate ion reacts to produce Lead(II) sulfate and release two electrons.

What are anode and cathode?

In secondary cells or the recharge-discharge cells during recharge, the positive electrode is the anode, while during discharge cathode is the positive electrode.

The anode (lead) of the cell undergoes an oxidation reaction during the discharge, whereas the lead oxide or the cathode undergoes reduction.

The discharging reaction at the anode of the cell is given as,

[tex]\rm Pb + SO_{4}^{2-} \rightarrow PbSO_{4} + 2e^{-}[/tex]

The discharging reaction at the cathode of the cell is given as,

[tex]\rm PbO_{2} + 4H^{+} + SO_{4}^{2-} + 2 e^{-} \rightarrow PbSO_{4} + 2H_{2}O[/tex]

The overall cell reaction is given as,

[tex]\rm Pb + 2SO_{4}^{2-} + PbO_{2} + 4H^{+} \rightarrow 2PbSO_{4} + 2H_{2}O[/tex]

Therefore, the gain and loss of electrons are represented at the cathode and the anode of the cell.

Learn more about discharge battery here:

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how many moles of Li2SO4 molecules are in 12.71g?

Answers

Answer:

₰₮₤₳V₤

Explanation:

First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.

For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.

Jonathan raised 60 goats, then entered into a series of business transactions. He traded all the goats for sheep at an exchange rate of 5 goats for 7 sheep. Next, he exchanged all the sheep for hogs at a rate of 4 sheep for 2 hogs. How many hogs did he get?

Answers

Answer:

just awser

eeww

Explanation:

I am not 100% sure but I think 42 is the answer.

If you have a solution that is 15 percent by mass of KCl in benzene, what is the new boiling point?

Answers

Answer:

https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186

Explanation: Thats your answer

When water is boiling in a pot, heat energy is being transferred throughout the water by which type of heat transfer?
O Convection
O Conduction
O Radiation

Answers

Answer:

it would be Convection.

What type of compound is a salt

Answers

Answer: Salt is an ionic compound.

Explanation:

A compound formed by transfer of electrons from one atom to another is called an ionic compound.

For example, chemical formula of salt is NaCl (also called table salt).

Salt is formed when sodium (atomic no. 11) donates its one valence electron to chlorine (atomic no. 17). As a result, sodium ion and chlorine ion chemically combine together and form the compound NaCl.

Thus, we can conclude that salt is an ionic compound.

ibigay ang kahulugan nito ayun sa paliliwanag
konduktor piloto drayber makinista​

Answers

Answer:

konduktor

- ang konduktor ay maaaring isang konduktor nga koryente, train o isang taong namumuno sa isang orkestra o isang grupo ng mga mang-aawit.

piloto

-isang tao na tagalipad ng ereplano

drayber

- isang tao na nagmamaniho ng sasakyan

makinista

-ay isang tao na nagpapakilos o nagpapagana ng makina

please give me brainliest.

Colligative properties of solutions include all of the following except: a. an increase in the osmotic pressure of a solution upon the addition of more solute b. elevation of the boiling point of a solution upon addition of a solute to a solvent c. an increase of reaction rate with increase in temperature d. depression of the freezing pont of a solution upon addition of a solute to a solvent e. depression of vapor pressure upon addition of a solute to a solvent

Answers

Answer:

Option C, an increase of reaction rate with increase in temperature

Explanation:

Colligative properties are as follows

a) Decrease of  vapor pressure

b) Increase of boiling point

c) Reduction of freezing point

d) Increase of osmotic pressure

There is no impact on reaction rate and hence it is not a colligative property.

Thus, option c is the right choice

An increase of reaction rate with increase in temperature isn't an example

of colligative properties of solutions

Colligative properties of solutions depend on the ratio of the number of

solutes to that of the solvent(concentration) and not on the nature of the

substances involved.

Examples of colligative properties include vapor pressure lowering, boiling

point elevation, freezing point depression, and osmotic pressure. Increase of

reaction rate with increase in temperature is therefore not an example of

colligative properties of solutions.

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What molecule represents this structure

A)NH4
B)NH3
C)NH4+
D)NH3+

Answers

Explanation:

As I think Option C is correct i.e. NH4+.

In an effort to maintain homeostasis, the organ systems of the human body work to keep the body's internal water level constant. Which of the following statements describe how the human body responds when its internal water level drops too low?

A. The skeletal system produces more circulating blood cells that insecure the body’s water intake

B. The excretory system signals the kidneys to retain more water and produce more concentrated urine to decrease water loss.

C. The nervous system signals the muscles to constrict , holding more water in the digestive track and decreasing water loss .

D.The excretory system signals the kidneys to release more water into the bladder to increase water loss .

Answers

B. The excretory system signals the kidneys to retain more water and produce more concentrated urine to decrease water loss

How many grams of water can be heated from 15.0 oC to 55oC using 4250.0 J.

Answers

Answer:

25.42 grams

Explanation:

The specific heat of water is 4.18 J/g •°C, so that means that it takes 4.18 joules of energy to raise one gram of water 1 °C.

Change in temp = 55 - 15 = 40°C

So we can calculate how much energy it would take to raise the temp of one gram of water by one degree using the following

(4.18 J/g•°C) * (40°C) * (1 gram) = 167.2 J

So if it takes 167.2 J of energy to raise on gram of water 40°C, we now we can calculate the amount of grams of water that can heated with 4250 J of energy

(4250 J) ÷ (167.2 J) = 25.42 grams of water can be heated from 15°C to 55°C

Calculate the maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V. Al(s) |Al3+(aq) || H+(aq) | O2(g) |Pt. Note that O2 is reduced to H2O.​

Answers

Answer:

W = 615.91 kJ

Explanation:

We need to use the following expression:

W = ΔG° * mol   (1)

But in order to determine the ΔG° we need the following expression:

ΔG° = -n * F * E°   (2)

Where F is a constant and is 96,500 J/V mol

n is the number of transferred electrons in the reaction. As we are passing from Al to Al³⁺ we can say that the number of electrons are 3.

Finally to get the moles, we need the the atomic weight of aluminum which is 26.98 g/mol, so the moles:

moles = m/MM   (3)

Let's calculate the moles of aluminum:

moles = 50 / 26.98 = 1.85 moles of aluminum

Now let's calculate the gibbs energy using (2):

ΔG° = -3 * 96,500 * 1.15

ΔG° = -332,925 J or simply -332.925 kJ/mol

Finally, using (1) we can determine the work done:

W = 332.925 * 1.85

W = 615.91 kJ

Hope this helps

The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ

What is cell potential ?

The cell potential, Ecell, is the measure of the potential difference between two half cells in an electrochemical cell.

Expression for work done ;

W = ΔG° x mol   (1)

But, to determine the ΔG°

ΔG° = -n x F x E°   (2)

Where,

F is a constant and is 96,500 J/V moln is the number of transferred electrons in the reaction.

(As there is variation from Al to Al³⁺ the change in number of electrons are 3)

To get the moles,

moles = m/MM  (3)

moles = 50 / 26.98 = 1.85 moles of aluminum

Now,

ΔG° = -3 x 96,500 x 1.15

ΔG° = -332,925 J  

       = -332.925 kJ/mol

Now, using (1) we can determine the work done:

W = 332.925 x 1.85

W = 615.91 kJ

Hence, The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ

Learn more about work done here ;

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A gas has a volume of 6.00 liters at a temperature of 300 K and a pressure of 1.00 atm what is the volume of the gas in liters at a temperature of 600 K and a pressure of 3.00 atm

Answers

Answer:

V₂ = 4.00 L

Explanation:

Given that:

Volume (v1) = 6.00 L

Temperature (T1) = 300 K

Pressure (P1) = 1.00 atm

VOlume (V2) = unknown???

Temperature (T2) = 600 K

Pressure (P2) = 3.00 atm

Using combined gas law equation:

[tex]\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}[/tex]

[tex]\dfrac{1 \times 6}{300} = \dfrac{3 \times V_2}{600}[/tex]

[tex]\dfrac{1}{50} = \dfrac{1 \times V_2}{200}[/tex]

200 = 50V₂

V₂ = 200/50

V₂ = 4.00 L

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In the film, there are long sequences in which not all main characters appear at the same time. And there are big scenes where everybody shows up. Thinking about the making of the film, behind the scenes, we can hypothetically break down the entire cinematic project into the following aggregate activities (We assume away all the complexities in shooting the three installments at the same time and other production details): Plan, screenplay, finance, cast, film crew, location Construction of movie sets Shooting sequence 1 Shooting sequence 2 Shooting sequence 3 Big scene sequence Postproduction & finalization before releaseWe have the following hypothetical data on time in months and cost in millions of dollars:ID IP T ES EF LS LF SLK NT NC CT CC CCRA 6.0 6.0 13.0 6.0 13.0B A 4.0 4.0 9.0 3.0 12.0C B 4.0 4.0 12.0 4.0 12.0D B 5.0 11.0 5.0 14.0 4.0 16.0E B 6.0 0.0 6.0 16.0 4.0 19.0F C,D,E4.0 4.0 19.0 4.0 19.0G F 6.0 6.0 11.0 5.0 13.5Note: IP = Immediate Predecessor; T = NT = Normal Time; ES = Earliest Start; EF = Earliest Finish; LS = Latest Start; LF = Latest Finish; SLK = Slack Time; NT = Normal Time; NC = NormalCost; CT = Crash Time; CC = Crash Cost; & CCR = Crash Cost/Time Unit (Crash Cost Rate).Copy the table to your homework and complete the following parts:By looking at the chart in part (a), find all possible paths through the network with their corresponding path times. Based on these path times, determine the critical path.Based on part (a) By using the forward and backward passes together with the four time determination rules, fill your calculations for ES,EF, LS, LF, and SLK in the appropriate cells.(b) [2] Try to independently fill in the columns ES, EF, LS, LF, and SLK of the table. If you have difficulties, refer to part (a). Determine the activity with the most slack time.c) [2] Based on part (a), find the critical path by going through the activities with no slack time.Compare this result with the critical path found in part (b).d) Use appropriate data to compute crash costs per time unit and fill in the CCR column. Cross out any CCR cells where the corresponding activities cannot be crashed.(e) [2] Find the total normal cost of the film. Find the normal cost on the original critical path. Compute the cost proportion of the critical path in the film's budget. explain errors are not detected by a trial balance