Guys please help me ill give brainily points

When an apple is cut open and left out on a table in your kitchen it turns brown over
time when oxygen reacts with the apple. Describe what happens to oxygen atoms in
order to make O2 instead of 0 +2 i

Answers

Answer 1

Answer:

Alright, We all know fruits contains enzyme, so there is a reaction name enzymic browning! Actually what happens when we cut the apple and keep it open the organic enzyme molecules starts reacting with oxygen of surroundings and oxidises it!


Related Questions

Draw the predominant product(s) of the following reactions including stereochemistry when it is appropriate. CH3-CEC-CH3 + 2HBr . Consider EZ stereochemistry of alkenes. • Do not show stereochemistry in other cases. • If no reaction occurs, draw the organic starting material. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate multiple products using the sign from the drop- down menu. ChemDoodle

Answers

The product of the reaction between [tex]CH_{3}[/tex]-CH=[tex]CH_{2}[/tex] and HBr is 2-bromo-3-methylbutane.

The reaction proceeds through the addition of a proton from HBr to the double bond, followed by the addition of a bromide ion.

The addition of the proton is stereospecific, and the bromide ion will add to the carbon atom that is least substituted by hydrogen. In this case, the carbon atom that is least substituted by hydrogen is the carbon atom that is attached to two hydrogen atoms.

Therefore, the bromide ion will add to the carbon atom that is attached to the double bond and the methyl group. The product of the reaction is 2-bromo-3-methylbutane.

here is the predominant product of the reaction of [tex]CH_{3}CHCH=CH-CH_{3}[/tex] with HBr:

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The complete question is:

Draw the predominant product(s) of the following reactions including stereochemistry when appropriate. CH CH CH -CEC-H HBr Consider EIZ stercochemistry of alkenes. Do not show stereochemistry in other cases If no reaction occurs_ raw the organic starting material. Draw one stnicture per sketcher Add additional sketchers using the drop down menu in the bottom right corner Separate multiple products using the sign from the drop-down menu: ChemDoodle Submit Answver Retry Entire Group more cirovp attempts remaining

what is the maximum amount of strong acid that can be added to a buffer made by the mixing of 0.35 mol sodium hydrogen carbonate with 0.50 mol sodium carbonate?

Answers

The balanced equation is: NaHCO₃ + HCl → NaCl + H2₃.

We can see that for every mole of NaHCO₃, one mole of HCl is required to convert it to H2CO₃. Therefore, the maximum amount of strong acid that can be added to the buffer is 0.35 mol HCl.

A buffer is a solution that resists pH change upon the addition of small amounts of acid or base. It is a solution of a weak acid and its corresponding conjugate base or a weak base and its corresponding conjugate acid. A buffer system consists of a weak acid or a weak base, and its conjugate base or conjugate acid.

When an acid or base is added to the buffer solution, the equilibrium is shifted either to the left or right, thereby minimizing the change in pH. Therefore, to determine the maximum amount of strong acid that can be added to a buffer made by the mixing of 0.35 mol sodium hydrogen carbonate with 0.50 mol sodium carbonate, we first need to identify the components of the buffer.

Sodium hydrogen carbonate (NaHCO₃) is a weak acid and sodium carbonate (Na2CO₃) is its conjugate base. The maximum amount of strong acid that can be added to the buffer is the amount that will convert all of the buffer components to their conjugate acid.

In this case, we need to convert all of the NaHCO₃ to H2CO₃.

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How long does it take for the earth to rotate

A. 24hrs
B. 1 yr
C. 2 weeks
D. 5 months​

Answers

Answer:

24 hrs it takes for the earth to rotate

Suppose you have 1000 lb of waste copper (II) oxide sitting in the basement of your factory. Do you see a problem with sending it to a landfill?

Answers

Answer:

Yes.

Explanation:

Yes, we have a problem with sending it to a landfill of copper oxide because it has harmful effect on the health of humans as well as more weight of the copper oxide. Copper oxide usually found in powder form which can easily be inhaled that causes death of the cell due to toxic effect on the mitochondria and lysosomes of the cell. It makes problem of health in carrying the copper oxide from the basement of the factory to the landfill region due to its power form so we can say that it can do problems  to human health while carrying from one place to another.

Which of the following elements has 2 electrons in the 4s sublevel?

Answers

Answer:

B. Ca

Explanation:

Let's look at the electron configurations of all four elements (I am going to write it in noble gas configuration to make it simpler):

Mg electron configuration: [Ne]3s2

Ca electron configuration: [Ar]4s2

Ar electron configuration: [Ar]

K electron configuration: [Ar] 4s1

We notice that Ca has two electrons in the 4s sublevel, which satisfies what the question is asking for.

The answer is thus B. Ca.

how many bonding electrons and lone pair electrons (nonbonding electrons) are there in the lewis structure of HCN?

Answers

In the Lewis structure of HCN (hydrogen cyanide), we can determine the number of bonding electrons and lone pair electrons by considering the valence electrons of each atom involved.

Hydrogen (H) is in Group 1 of the periodic table and has one valence electron. Carbon (C) is in Group 14 and has four valence electrons, and nitrogen (N) is in Group 15 with five valence electrons. Cyanide (CN) is a polyatomic ion, and since we have one carbon and one nitrogen, we have a total of nine valence electrons (four from carbon and five from nitrogen). In the Lewis structure, we first connect the atoms using a single bond between carbon and nitrogen, and carbon forms a single bond with hydrogen. This accounts for two of the nine valence electrons. To complete the octets around each atom, we distribute the remaining seven valence electrons as lone pairs around the nitrogen and carbon atoms. The lone pairs do not participate in bonding and are considered nonbonding or lone pair electrons. Therefore, in the Lewis structure of HCN, there are two bonding electrons and seven lone pair electrons (nonbonding electrons). The bonding electrons are involved in forming the bonds between the atoms, while the lone pair electrons are localized on the nitrogen and carbon atoms, fulfilling their octets.

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Sven perform this reaction with 15.0 grams of sodium sulfate and an excess of iron (III) phosphate to make iron (III) sulfate and sodium phosphate. In the actual experiment, 10.0 grams of sodium phosphate are experimentally made, what is the percent yield?


2FePO4+3Na2SO4-->Fe2(SO4)3+2Na3PO4

Answers

Answer:

85.5%

Explanation:

To get the experimental value, you need to convert 15.0 grams of Na2SO4 to grams of Na3PO4. You do this with stoichiometry.

Convert grams of Na2SO4 to moles with molar mass. Then convert to moles of Na3PO4 with the mole-to-mole ratio according to the balanced chemical equation. Then convert moles of Na3PO4 to grams with the molar mass.

15.0 g Na2SO4 x (1 mol/142.04 g) x (2 Na3PO4/3Na2SO4) x (163.94 g/1 mol) = 11.7 g Na3PO4

Percent Yield = (actual value/experimental value) x 100

Actual Value = 10.0 g

Experimental Value = 11.7 g

10.0g/11.7 g = 85.5%

what is a phase diagram? what is a phase diagram? a phase diagram is simply a map of the phase of a substance as a function of volume (on the y-axis) and number molecules (on the x-axis). a phase diagram is simply a map of the phase of a substance as a function of pressure (on the y-axis) and number molecules (on the x-axis). a phase diagram is simply a map of the phase of a substance as a function of pressure (on the y-axis) and temperature (on the x-axis). a phase diagram is simply a map of the phase of a substance as a function of volume (on the y-axis) and pressure (on the x-axis).

Answers

A phase diagram is a graphical representation or map that shows the different phases (solid, liquid, and gas) of a substance as a function of pressure and temperature. It provides valuable information about the conditions under which a substance exists in each phase or undergoes phase transitions.

In a phase diagram, pressure is typically represented on the y-axis, and temperature is represented on the x-axis. The diagram is divided into regions corresponding to different phases, and boundaries or lines separating these regions represent phase transitions.

The phase diagram allows us to determine the conditions at which a substance can exist as a solid, liquid, or gas, and it provides insights into the effects of temperature and pressure on the phase behavior of the substance.

It helps in understanding processes such as melting, boiling, and sublimation and provides a useful tool in various fields including chemistry, physics, and materials science.

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URGENT LOOK AT PICTURE
look at the thing and choose all that matches ​

Answers

Answer:

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

E

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BRAINLIEST PLEASE

(GIVING BRAINLIEST) Which of the following is a good source of carbohydrates?
pears
meat
eggs
fish

Answers

Answer:

I would choose pear fruits are a good source of carbohydrates hopefully its right sorry if its not

Answer: Fruit

Fruits have a lot of carbohydrates in them :) Hope this helped!

What do glycine, leucine, and lysine all have in common?
They are the building blocks of proteins.
They have an important role in the heart.
They have a role in the functioning of the stomach.
They store equal amounts of energy in their bonds.

Answers

Answer:

a, they are the building blocks of proteins.

Explanation:

hope this helps!

~mina

Answer:

A. They are the building blocks of proteins.

(Photo for proof at the bottom.)

Explanation:

Glycine, leucine, and lysine are all amino acids. There are 20 different kinds of amino acids, including the 3 mentioned here. Different amino acids bond together to form different structures, depending on how many there are. Generally, 50 or more amino acids bonded together makes a protein. But there are some exceptions. Amino acids (including glycine, leucine, and lysine) are the building blocks of proteins.

Here's a photo of Edge incase you're doubtful.

Please click the heart if this helped.

: 1. a) Write an expression for the solubility product constant (Ksp) of manganese(II) hydroxide, Mn(OH)2. Mn(OH)2 = Mn + 2014ce) b) The concentration of hydroxide (OH) in a saturated solution of Mn(OH), is determined to be 7.5 x 10- M. What is the molar solubility (S) of manganese(II) hydroxide in water? c) Based on the molar solubility you calculated in (b), calculate the Kip of Mn(OH)2.

Answers

An expression for the solubility product constant (Ksp) of manganese(II) hydroxide is Ksp = [[tex]Mn^{2+}[/tex]][[tex]OH^-[/tex]]. b) Molar solubility (S) of Mn(OH)[tex]_2[/tex] in water is  2.3 x [tex]10^{-21}[/tex]. c) The Ksp value is 2.3 x  [tex]10^{-21}[/tex].

a) The expression for the solubility product constant (Ksp) of manganese (II) hydroxide, Mn(OH)[tex]_2[/tex] is given below:

Ksp = [[tex]Mn^{2+}[/tex]][[tex]OH^-[/tex][tex]]^{2}[/tex]

Mn(OH)[tex]_2[/tex] ⇌ [tex]Mn^{2+}[/tex] + 2[tex]OH^-[/tex]

The equation shows that the stoichiometry of the reaction is one mole of Mn(OH)[tex]_2[/tex] dissociating to give one mole of [tex]Mn^{2+}[/tex] and two moles of [tex]OH^-[/tex].

b) Given the concentration of hydroxide ([tex]OH^-[/tex]) in a saturated solution of Mn(OH)[tex]_2[/tex], which is 7.5 x [tex]10^{-8}[/tex] M.

The molar solubility (S) of Mn(OH)[tex]_2[/tex] in water is determined by using the stoichiometry of the dissociation reaction and the equilibrium expression.

Using the stoichiometry of the dissociation reaction and the equilibrium expression;[[tex]Mn^{2+}[/tex]] = S[[tex]OH^-[/tex]] = 2S

Therefore, Ksp = [[tex]Mn^{2+}[/tex]][[tex]OH^-[/tex][tex]]^{2}[/tex]

= S × [tex](2S)^2[/tex]

= 4[tex]S^3[/tex]

= 4 (7.5 x[tex]10^{-8})^3[/tex]

= 2.3 x [tex]10^{-21}[/tex]

c) The Ksp value is 2.3 x  [tex]10^{-21}[/tex] and the molar solubility (S) is 6.6 x [tex]10^{-8}[/tex] M which are calculated above.

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A researcher uses an electrochemical cell to interrogate the redox activity between a solution of copper and a solution of an unknown metal. The free energy change under standard conditions is determined to be -293.4 kJ/mol a. What is a reasonable guess for the unknown metal. Justity. b. Write the reduction and oxidation half reactions

Answers

a. Metals such as zinc (Zn) or aluminum (Al) could be reasonable guesses as they have higher standard reduction potentials than copper. b. Reduction half-reaction is Cu₂+(aq) + 2e⁻ → Cu(s), Oxidation half-reaction is Unknown metal (M)(s) → M₂+(aq) + 2e⁻.

a. To make a reasonable guess for the unknown metal in the electrochemical cell, we can consider the standard reduction potentials (E°) of different metals. The standard reduction potential is a measure of the tendency of a metal to undergo reduction (gain electrons) compared to a standard hydrogen electrode (SHE).

Since the free energy change under standard conditions is negative (-293.4 kJ/mol), it indicates a spontaneous redox reaction, where the copper solution undergoes reduction and the unknown metal solution undergoes oxidation.

A reasonable guess for the unknown metal would be a metal with a higher standard reduction potential than copper (Cu). This is because for the overall reaction to be spontaneous, the unknown metal should have a greater tendency to undergo oxidation (lose electrons) compared to copper. Based on this, metals such as zinc (Zn) or aluminum (Al) could be reasonable guesses as they have higher standard reduction potentials than copper.

b. The reduction and oxidation half-reactions can be written as follows

Reduction half-reaction

Cu₂+(aq) + 2e- → Cu(s)

Oxidation half-reaction

Unknown metal (M)(s) → M₂+(aq) + 2e⁻

In the reduction half-reaction, copper ions (Cu₂⁺) in solution are reduced and gain two electrons to form solid copper (Cu).

In the oxidation half-reaction, the unknown metal (M) in solid form is oxidized, losing two electrons to form metal ions (M₂⁺) in solution.

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Question Identify the element with the ground state electron configuration [Xe]4f14
5d6
6s2 .
Answer Ir
Ta
Os
Ru
Au

Answers

The element with the ground state electron configuration [Xe]4f¹⁴5d⁶6s² is actually Ir, which represents iridium. Option A is correct.

The electron configuration is a representation of how electrons are distributed among the energy levels, subshells, and orbitals within an atom. It follows a specific notation that describes the arrangement of electrons.

The electron configuration indicates that the electrons are arranged in the following manner;

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d⁶

The [Xe] notation represents the electron configuration of the noble gas xenon (Xe), which includes all the electrons up to the 5p level. After the noble gas core, we have 4f¹⁴ 5d⁶, which corresponds to the electron configuration of iridium (Ir).

Hence, A is the correct option.

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--The given question is incomplete, the complete question is

"Identify the element with the ground state electron configuration [Xe]4f¹⁴5d⁶6s². Options; A) Ir B) Ta C) Os D) Ru E) Au."--

Heat is the measure of the average kinetic energy of particles; temperature is the measure of the transfer of thermal energy .
true or false

Answers

I think the answer is true, no?

what is the difference between corrosion and rusting​

Answers

Answer:

Corrosion is the process of deterioration of materials as a result of chemical, electrochemical or other reactions. Rusting is a part of corrosion and is a chemical process which results in the formation of red or orange coating on the surface of metals. ... Rust or rusting can affect only iron and its alloys.

Explanation:

(this is science not chemistry)

Answers

I'm pretty sure ita A. acceleration

Answer:

it's a friction force

how many grams is 3.49 moles NaCl​

Answers

Answer:

m = 204.16 grams

Explanation:

Given that,

No. of moles, n = 3.49

Molar mass of NaCl, M = 58.5 g/mol

We need to find the mass of 3.49 moles NaCl​. We know that,

[tex]n=\dfrac{m}{M}\\\\m=n\times M\\\\m=3.49 \times 58.5\\\\m=204.16\ g[/tex]

So, there are 204.16 grams in 3.49 moles NaCl​.

You are required to make 1 L of 70% isopropyl alcohol for surface disinfection, You have a stock solution of 99% isopropyl alcohol and sterile water. Calculate the amounts of isopropyl 99% alcohol and sterile water you need to use to make the 70% isopropyl solution using the alligation method.

A. 700 mL of isopropyl 99% and 300 mL of water

B. 750 mL of isopropyl 99% and 250 mL of water

C. 707.1 mL of isopropyl 99% and 292.9 mL of water

D. 708.1 mL of isopropyl 99% and 291.9 mL of water

E. 706.1 mL of isopropyl 99% and 299 9 mL of water

Answers

The amounts of isopropyl 99% alcohol and sterile water you need to use to make the 70% isopropyl solution using the alligation method are 707.1 mL of isopropyl 99% and 292.9 mL of water. The correct answer is option C.

Alligation method is a type of mathematical process used to calculate the quantities of two or more components of a mixture to obtain a mixture with a specific concentration or quality. This method uses the concept of averaging and the weighted average to get the desired results.

The allegation formula for isopropyl alcohol solution: Required % strength —— Higher % strength | DifferenceLower % strength | Difference70% ——- 99% | 29%70-29=41% | 29%

So, the required ratio of the alcohol to be mixed with water should be 41:29. Thus, the volumes of the 99% alcohol and water needed are (41/70) L and (29/70) L, respectively. Let's substitute the values and calculate:

41/70 × 1L = 0.586 L of 99% isopropyl alcohol

29/70 × 1L = 0.414 L of sterile water

Now we have the volumes of the 99% isopropyl alcohol and sterile water required. By adding these, the total volume of the solution is 1L, as given in the question. Therefore, the answer is 707.1 mL of 99% isopropyl alcohol and 292.9 mL of sterile water (707.1 mL + 292.9 mL = 1000 mL = 1 L).

Hence, option C) 707.1 mL of isopropyl 99% and 292.9 mL of water is the correct answer.

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Which species will have the highestconcentration in a 0.25 M aq sol of boric acid?Ka1 = 7.3 x 10-10Ka2 = 1.8 x 10-13Ka3 = 1.6 x 10-14A. H3BO3B. H2BO3-C. HBO32-D. BO33-E. H+

Answers

In a 0.25 M aqueous solution of boric acid, the species with the highest concentration would be H_{3}BO_ 3}^{-} option B.

Boric acid (H_{3}BO_{3}) is a weak acid that can undergo multiple ionization steps. The given equilibrium constants (Ka) provide information about the ionization reactions. The first ionization reaction of boric acid is as follows:

[tex]H_{3}BO_{3}[/tex] ⇌ H^{+}+ H_{3}BO_ 3}^{-}

Ka1 = 7.3 x 10^-10

The second ionization reaction is:

[tex]H_{3}BO_ 3}^{-}[/tex] ⇌H^{+} + H_{3}BO_ 3}^{-2}

Ka2 = 1.8 x 10^-13

The third ionization reaction is:

H_{3}BO_ 3}^{-2} ⇌ H+ + [tex]BO_{3} ^{-3}[/tex]

Ka3 = 1.6 x [tex]10^{-14}[/tex]

To determine the species with the highest , we need to compare the equilibrium constants. The larger the Ka value, the more the reaction favors the dissociation of the species.

Based on the given Ka values, the second ionization reaction (H2BO3- ⇌ [tex]H^{+}[/tex] + H_{3}BO_ 3}^{-2}) has the highest Ka value (1.8 x 10^-13). This indicates that the concentration of H_{3}BO_ 3}^{-} in the solution would be higher compared to the other species. Therefore, option B, H_{3}BO_ 3}^{-}, would have the highest concentration in a 0.25 M aqueous solution of boric acid.

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a 30.0- ml volume of 0.50 m ch3cooh ( ka=1.8×10−5 ) was titrated with 0.50 m naoh . calculate the ph after addition of 30.0 ml of naoh at 25 ∘c . express the ph numerically.

Answers

The pH after the addition of 30.0 mL of NaOH at 25 °C is 8.82.

To calculate the pH after the addition of NaOH, we need to determine the moles of CH3COOH and NaOH that react, and then use the stoichiometry to find the resulting concentration of CH3COOH and OH-.

Given:

Volume of CH3COOH = 30.0 mL = 0.0300 L

Concentration of CH3COOH = 0.50 M

Ka for CH3COOH = 1.8×10^(-5)

Volume of NaOH = 30.0 mL = 0.0300 L

Concentration of NaOH = 0.50 M

First, we calculate the moles of CH3COOH:

moles of CH3COOH = concentration × volume

moles of CH3COOH = 0.50 M × 0.0300 L

moles of CH3COOH = 0.015 mol

Since CH3COOH and NaOH react in a 1:1 ratio, the moles of NaOH are also 0.015 mol.

Next, we calculate the moles of OH- produced:

moles of OH- = moles of NaOH

moles of OH- = 0.015 mol

Now, we calculate the concentration of OH-:

concentration of OH- = moles of OH- / total volume

concentration of OH- = 0.015 mol / (0.0300 L + 0.0300 L)

concentration of OH- = 0.250 M

Using the equilibrium expression for the dissociation of water, we can calculate the concentration of H+ (or H3O+):

[H+][OH-] = Kw

[H+] = Kw / [OH-]

[H+] = 1.0 × 10^(-14) / 0.250 M

[H+] = 4.0 × 10^(-14) M

Finally, we calculate the pH:

pH = -log[H+]

pH = -log(4.0 × 10^(-14))

pH = 8.82

The pH after the addition of 30.0 mL of NaOH at 25 °C is 8.82.

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The colision of two plates causes the fomation of _____
mountain

Answers

The collision of two plates causes the formation of fold mountains.

Which planet could support human life

Answers

Answer:

D

Explanation:

It states that D has oxygen, and is closer to the Sun.

Hope this helped, and please mark as Brianliest <3

Answer:

I am pretty sure it is B

Explanation:

The others would either burn u like a crispy chicken nugget or freeze you like a popsicle

What two emissions scenarios most closely represent the current trend in CO2 emissions?

Answers

The two emissions scenarios that most closely represent the current trend in CO2 emissions are the Representative Concentration Pathway (RCP) 4.5 and RCP 6.0 scenarios. RCP 4.5 assumes moderate emission reduction efforts, while RCP 6.0 represents a higher emission trajectory, reflecting the current trend where emissions reductions are not keeping pace with necessary targets.

The Representative Concentration Pathways (RCPs) are scenarios used to assess the potential impacts of greenhouse gas emissions on the climate system. RCP 4.5 assumes a moderate emission reduction pathway, with emissions peaking around 2040 and declining gradually. On the other hand, RCP 6.0 represents a higher emission trajectory, with emissions peaking later and declining more slowly compared to RCP 4.5. This scenario aligns with the current trend of rising CO2 emissions, indicating that global efforts to reduce emissions have not been sufficient. The current trend is closer to RCP 6.0, highlighting the challenges of achieving widespread emission reductions in various sectors of the global economy.

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A buoy bobs up and down in the ocean. The waves have a wavelength of
2.5 m, and they pass the buoy at a speed of 4.0 m/s. What is the frequency
of the waves?

A. 1.6 Hz
B. 10 Hz
C. 6.5 Hz
D. 1.5 Hz

Answers

Answer:

c

Explanation:

The atmosphere is primarily made of what gas?
Carbon Dioxide
Nitrogen
Oxygen
Argon​

Answers

Answer:

nitrogen

Explanation:

identify the limiting reactant when 7.28 grams of magnesium oxide reacts with 4.50 grams of aluminum to make magnesium and aluminum oxide? i need a typed answer a link wont work ​

Answers

Answer:

the limiting reactant is aluminum

Explanation:

Which species functions as the oxidizing agent in the following reduction-oxidation reaction? ZnO(s) + C(s) → Zn(s) + CO(g) A) ZnO(s) B) C(s) C) CO(g) D) Zn(s)

Answers

In the following reduction-oxidation reaction; ZnO(s) + C(s) → Zn(s) + CO(g), the species which functions as the oxidizing agent is option (B) C(s).

In the reaction ZnO(s) + C(s) → Zn(s) + CO(g), C(s) gains oxygen and goes from being a carbon atom to a carbon dioxide molecule which contains two oxygen atoms. Therefore, C(s) has been oxidized. Carbon is being oxidized in the above reaction because it has gained oxygen.

The term oxidation refers to the loss of electrons by an atom or molecule. Oxidation is a type of chemical reaction in which a substance loses electrons to another substance. The oxidation process usually occurs with a substance's interaction with oxygen.

Therefore, the correct answer is option B) C(s).

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Compare the two reaction coordinate diagrams below and select the answer that correctly describes their relationship. In each case, the single intermediate is the ES complex. The contribution of binding energy is given by 5 in (a) and by 7 in (b) O The activation energy for the uncatalyzed reaction is given by 5+6 in (a) and by 7+4 in (b) O The ES complex is given by 2 in (a) and 4 in (b). O(a) describes a transition-state complementarity model, whereas (b) describes a strict "lock and key" model. O The activation energy for the catalyzed reaction is 5 in (a) and is 7 in (b).

Answers

The correct answer is O(a) describes a transition-state complementarity model, whereas (b) describes a strict "lock and key" model.

The two reaction coordinate diagrams given represent two different models that describe the catalysis of enzyme-catalyzed reactions. Both models have a single intermediate which is the ES complex. In each case, the contribution of binding energy is given, which is 5 in (a) and by 7 in (b). The ES complex is given by 2 in (a) and 4 in (b). The activation energy for the uncatalyzed reaction is given by 5+6 in (a) and by 7+4 in (b). The models presented in the diagrams are the transition-state complementarity model (a) and the strict "lock and key" model

(b). The two models are different from each other. They differ based on the mechanism by which the enzyme catalyzes the reaction. The lock-and-key model assumes that the active site of the enzyme is rigid and complementary to the substrate that fits into it. The substrate is said to "fit" into the active site of the enzyme as a lock fits into a key. In the transition-state complementarity model, the enzyme's active site has flexibility, which allows it to interact with the substrate in such a way that it stabilizes the transition state, reducing the energy required to reach it. The activation energy for the catalyzed reaction is 5 in (a) and is 7 in (b).

Hence, the correct answer is O(a) describes a transition-state complementarity model, whereas (b) describes a strict "lock and key" model.

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9. What happens to the cell outside of the nucleus when the virus has been copied so many times? a. The cell fights back b. The cell gets help from its neighbor cells C. The cell gets help from white blood cells d. The cell is destroyed​

Answers

Answer: it think the answer is c.) The cell gets help from white blood cells or b.) The cell gets help from its neighbor cells.

Explanation:

Other Questions
Benchmark Metrics Inc. (BMI), an all-equity financed firm, reported EPS of $5.97 in 2008. Despite the economic downturn, BMI is confident regarding its current investment opportunities. But due to the financial crisis, BMI does not wish to fund these investments externally. The Board has therefore decided to suspend its stock repurchase plan and cut its dividend to $0.83 per share (vs. almost $2 per share in 2007), and retain these funds instead. The firm has just paid the 2008 dividend, and BMI plans to keep its dividend at $0.83 per share in 2009 as well. In subsequent years, it expects its growth opportunities to slow, and it will still be able to fund its growth internally with a target 40% dividend payout ratio, and reinitiating its stock repurchase plan for a total payout rate of 62%. (All dividends and repurchases occur at the end of each year.) Suppose BMI's existing operations will continue to generate the current level of earnings per share in the future. Assume further that the return on new investment is 15%, and that reinvestments will account for all future earnings growth (if any). Finally, assume BMI's equity cost of capital is 10%. a. Estimate BMI's EPS in 2009 and 2010 (before any share repurchases). b. What is the value of a share of BMI at the start of 2009 (end of 2008)? Hint: Make sure to round all intermediate calculations to at least four decimal places. a. Estimate BMI's EPS in 2009 and 2010 (before any share repurchases). (Round to the nearest cent.) BMI's EPS in 2009 is $ ____(Round to the nearest cent.) BMI's EPS in 2010 is $ ____(Round to the nearest cent.) b. What is the value of a share of BMI at the start of 2009 (end of 2008)? The value of a share of BMI at the start of 2009 is $____(Round to the nearest cent.) D las palabras definidas. OJO! Incluya el artculo definido (el, la, los, las) en las respuestas. Inmanaging its international operations, should Hisense usecentralized or decentralized decision-making? what is the molarity of 48.6 g of magnesium (mg) ions in 2 l h2o? The age distribution of the Canadian population and the age distribution of a random sample of 455 residents in the Indian community of a village are shown below.Age (years)Percent of Canadian PopulationObserved Numberin the VillageUnder 57.2%475 to 1413.6%7815 to 6467.1%28265 and older12.1%48Use a 5% level of significance to test the claim that the age distribution of the general Canadian population fits the age distribution of the residents of Red Lake Village.(a) What is the level of significance?State the null and alternate hypotheses.H0: The distributions are the same.H1: The distributions are different.H0: The distributions are different.H1: The distributions are the same.H0: The distributions are different.H1: The distributions are different.H0: The distributions are the same.H1: The distributions are the same.(b) Find the value of the chi-square statistic for the sample. (Round your answer to three decimal places.)Are all the expected frequencies greater than 5?Yes NoWhat sampling distribution will you use?chi-squarebinomialuniformnormalStudent's tWhat are the degrees of freedom?(c) Estimate the P-value of the sample test statistic.P-value > 0.100 0.050 < P-value < 0.1000.025 < P-value < 0.0500.010 < P-value < 0.0250.005 < P-value < 0.010P-value < 0.005(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories?Since the P-value > , we fail to reject the null hypothesis.Since the P-value > , we reject the null hypothesis.Since the P-value , we reject the null hypothesis.Since the P-value , we fail to reject the null hypothesis.(e) Interpret your conclusion in the context of the application.At the 5% level of significance, the evidence is insufficient to conclude that the village population does not fit the general Canadian population.At the 5% level of significance, the evidence is sufficient to conclude that the village population does not fit the general Canadian population. An object is placed 30 cm in front of a converging lens which has a focal length of 45 cm. Calculate the distance, magnification, character (real/virtual), and orientation (upright/inverted) of the image. Carefully draw a ray diagram to scale. (Make sure your object distance is three times the focal length.) . probabilities for two events, event a and event b, are given. p(a and b) = 0.14 p(b) = 0.4 what is the probability of event a given b? The Imperial War Museum says that "The Holocaust was the systematic murder of Europe's Jews by the Nazis and their collaborators during the Second World War. This programme of targeted mass murder was a central part of the Nazis broader plans to create a new world order based on their ideology. " As Mrs. Gruwells students read the "The Diary of Anne Frank", how did they apply what happened to Anne in the Holocaust to their own lives? You have recently been tasked to come up with a set of 8-year payment options to cater to a specific customer's requirement of flexible payment terms. More specifically, you are to determine how much the customer should be paying under each of 3 payment schemes below such that you would be indifferent to which one is chosen by the customer. For each one, draw the CFD and provide the values requested in the sub-bullet. Assume cash flows are compounded monthly at an interest rate of 1% per month. Payment scheme 1: Eight fixed equal annual payments to be paid every year on the anniversary of the contract. [7.5 points] o Annual payment amount Payment scheme 2: First pay 40% downpayment on the principal amount then pay any remaining balance and associated interests in fixed equal monthly payments starting in month 25 and ending in month 96. (This means that there are no monthly payments to be made from months 1 to 24 and the first of the 72 monthly payments is deferred to month 25.) [7.5 points] o Downpayment amount o Fixed monthly payment amount Payment scheme 3: Paid according to the schedule of payments in the table below. [10 points] o Value of X Margaret has a project with a $30,000 first cost that returns $5000 per year over its 14-year life.It has a salvage value of $3000 at the end of 14 years.If the MARR is 15 percent, what is the annual worth of this project? Click the icon to view the table of compound interest factors for discrete compounding periods when i=15% The annual worth of the project is$ (Round to the nearest cent as needed.) Let f(x) = *4*6=2 ) 12 What is the set of all values of R on which is concave down? (a) (- 0,-1) (1,2) (c)(-V3, 3) (b) (0,3) (d) (-1,1) On January 1, 2021, Berkshire paid $100,000 for 8,700 shares of Occidental Petroleum common stock. The ownership in Occidental Petroleum is 10%. Berkshire does not have significant influence over Occidental Petroleum. Occidental Petroleum reported net income of $58,000 for the year ended December 31, 2021. Occidental Petroleum paid dividends of $1 per share on December 31, 2021. The fair value of the Papa stock on that date was $62 per share. What amount will be reported in the balance sheet of Berkshire for the investment in Occidental at December 31, 2021? Multiple Choice O $539,400. O $494,400. O $479,400. O $464,400. What is the half-life of a material which starts with 10 gramsand after 2 days you are down to 2.5 grams?a) 5b) 2c) 1d) 1.5 B eBook H Problem Walk-Through Lloyd Inc. has sales of $400,000, a net income of $20,000, and the following balance sheet: Cash $ 42,880 Accounts payable 128,000 Notes payable to bank 339,200 Total cu Calculus Expectations: V4U.C.1: make connections, graphically and algebraically, between the key features of a function and its first and second derivatives, and use the connections in curve sketching V4U.C.2: solve problems, including optimization problems that require the use of the concepts and procedures associated with the derivative, including problems arising from real-world applications and involving the development of mathematical models 1. Graph the function y = x3 3x2 144x 140 = (x+1)(x+10)(x 14). Make sure to include the following list of items (and explanations /full solutions to how to find them!): a. Any x and y intercepts b. Any local max/min coordinates c. The interval where the function is increasing or decreasing d. Any points of inflection e. The intervals where the function is concave up or concave down f. A clear, labelled sketch! (there's a grid for you to use!) Summary of the data on two variables to be presented simultaneously is called a. simultaneous equations b. a histogram c Pivot table 18-2. OBJECTIVE: Describe the Chicago "standard form". What is meant by bilateral agreement? What was the Two Freedoms Agreement? The Five Freedoms Agreement? Explain why a firm may not necessarily want to reduce itsprice risks to zero byentering into hedging transactions. the equation x 2 8 x 5 = 0 can be transformed into the equation ( x p ) 2 = q , where p and q are real numbers. what are the values of p and q ? Show that each equation has no rational roots. x^3-3x+1=0