Answer:
0.5, 0, -1/4, -1
Will mark brainliest if correct.
Answer:
b
Step-by-step explanation:
Answer:
i am pretty sure the answer is d
Step-by-step explanation:
let me know if this is wrong
Which values are solutions to the inequality below? Check all that apply.
Answer:
C. and D.
Step-by-step explanation:
The root of √x is either equal or bigger than 9
write two inequalities to
compare -12 and -6
write two inequalities to compare 8 and -10
Answer:
First one: -12 < -6
-6 > -12
Second one:
-8 > -10
-10 < -8
Step-by-step explanation:
Well you just compare them with greater then or less then signs.
(a) y = 5z + x simplify x
Answer:
x=y−5z
Step-by-step explanation:
y=5z+x
Step 1: Flip the equation.
x+5z=y
Step 2: Add -5z to both sides.
x+5z+−5z=y+−5z
x=y−5z
Answer:
x=y−5z
plz mark me as brainliest
Answer:
x = ay - 5z
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Shanna deposit 11,500 and leaves the funds in her account for 14 years how much will she have if the interest rate of the bank offered 4.9%
Hello!
This is a problem about interest rates.
Since we are not given the "[tex]n[/tex]" value, how many times this interest applies per time period, we can assume that we are most likely dealing with simple interest with an annual interest rate.
The simple interest formula is as follows,
[tex]A=P(1+rt)[/tex]
Where [tex]A[/tex] is the total amount, [tex]P[/tex] is the initial principal balance, [tex]r[/tex] is the annual interest rate, and [tex]t[/tex] is time in years.
Since we are given all this information, we can just solve after converting the interest rate of 4.9% to a decimal, which is 0.049.
[tex]A=11500(1+0.049*14)[/tex]
[tex]A=11500(1.686)[/tex]
[tex]A=19389[/tex]
So at the end of the 14th year, Shanna will have $19,389 in her account.
Hope this helps!
I'm sorta to lazy to do this so someone help plz?
Please I need help with this for better understanding and clarity. Thank you. (e Three different Mathematics books,four different French books and two different Physics books are to be arranged on a shelf.How many different arrangements are possible if
i. the books in each particular subject must all stand together only the French books must be in the first position on the shelf whilst the others
ii. must also always be together but not in the first position
iii. all the three subject matters can be arranged anyhow.
The required number of arrangements when all the three subject matters can be arranged anyhow is given by:
9! = 362880
i. The required number of arrangements when French books are in the first position is given by:
3! * 2! * 4! = 1728
ii. the required number of arrangements is given by:
3! * 4! * 2! = 3456
iii. the required number of arrangements when all the three subject matters can be arranged anyhow is given by:
9! = 362880
Given that there are e = 3
Mathematics books,
f = 4 French books, and
p = 2 Physics books to be arranged on a shelf.
The problem requires to calculate the number of different arrangements are possible in the following ways:
i. If the books in each particular subject must all stand together only the French books must be in the first position on the shelf whilst the others
ii. Must also always be together but not in the first position.
All the three subject matters can be arranged anyhow.
i. If the books in each particular subject must all stand together only the French books must be in the first position on the shelf whilst the others:
If the French books are always in the first position of the shelf, then the remaining 8 books can be arranged in 8! ways as they all have different titles. But there are 3! ways to arrange the mathematics books and 2! ways to arrange the physics books.
Therefore, the required number of arrangements when French books are in the first position is given by:
3! * 2! * 4! = 1728
ii. Must also always be together but not in the first position
If all the books of the same subject must be kept together, then there are 3! ways to arrange the mathematics books, 4! ways to arrange the French books, and 2! ways to arrange the physics books.
Therefore, the required number of arrangements is given by:
3! * 4! * 2! = 3456
iii. All the three subject matters can be arranged anyhow.
If all the three subject matters can be arranged anyhow, then the total number of books to be arranged is 9.
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PLS ANSWER THIS ASAP
The image below shows two parallel lines and an intersecting transversal line. What is the degree measures of angles 1 and 2?
the answer is A because 1 is the same as 78
The student council had a cupcake fundraiser. The cupcakes were donated, but the icing, plates and candy were purchased for $50. The
student council sold the cupcakes for $1.50 each.
Which equation shows the relationship between the profit, p, and the number of cupcakes sold, n?
4x + y = 1
x + y = 2
rewrite these equations in slope intercept form y=mx+b
y=4x+1
y=x+2
Step-by-step explanation:
very simple you just put the numbers in the correct spot when doing slope intercept form
dr. ellison says that the equation y = -3x 7 has a solution of (2, 13). is dr. ellison right or wrong
Dr. Ellison is wrong.
To determine if the equation y = -3x + 7 has a solution of (2, 13), we can substitute the values of x and y into the equation and check if it holds true.
Substituting x = 2 and y = 13 into the equation:
13 = -3(2) + 7
13 = -6 + 7
13 = 1
The equation does not hold true since 13 is not equal to 1.
Therefore, (2, 13) is not a solution to the equation y = -3x + 7.
Hence, Dr. Ellison is incorrect in stating that (2, 13) is a solution to the equation.
An equation is a mathematical statement that indicates that two expressions are equal. It consists of variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, exponentiation, etc. Equations are used to represent relationships between quantities and to solve problems in various branches of mathematics and science.
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Melissa and Matt both started a card collection at the same time. Melissa started her card collection with 100 cards and added 13 cards to her collection each week. Matt started his card collection with 130 cards and added 8 cards to his collection each week. After how many weeks did Melissa and Matt have the same number of cards in their collections?
Answer:
a few weeks
Step-by-step explanation:
what is the slope and y intercept of the line with equation 3x-6y=7
Answer:
x intercept = (7/3, 0)
y intercept = (0, -7/6)
slope = 1/2
Step-by-step explanation:
Diagonalization of Symmetric Matrices Example 1: Consider the matrix. -5] A = 3 -5 3 a) Find the eigenvalues A₁, A₂ of A and find a basis for each eigenspace. = b) Find an orthonormal basis {u₁, u2} for R2 of eigenvectors of A (where Au₁ Au₂ = X₂U₂). A₁u₁ and c) Is A diagonalizable? If A is diagonalizable, find matrices P and D such that A = PDP-¹ d) Plot the eigenspaces of A using the bases found in part a). X2 4 2 X1 -4 2 -2 -4 2
For the given matrix A, the eigenvalues are A₁ = 4 and A₂ = -6. The matrix A is diagonalizable since it has two linearly independent eigenvectors. The diagonal form of A can be obtained as D = [[4, 0], [0, -6]], and the corresponding matrix of eigenvectors can be expressed as P = [[2, -1], [1, 2]].
To perform diagonalization of the symmetric matrix A, we find the eigenvalues A₁ = -6 and A₂ = 4, and their corresponding eigenvectors. We then normalize the eigenvectors to obtain an orthonormal basis {u₁, u₂} for R². A is diagonalizable, and by using the eigenvectors, we construct matrices P and D such that A = PDP⁻¹. Finally, we plot the eigenspaces using the bases found.
a) To find the eigenvalues A₁ and A₂, we solve the characteristic equation |A - λI| = 0, where I is the identity matrix. The characteristic equation for A yields (λ + 6)(λ - 4) = 0, giving A₁ = -6 and A₂ = 4. To find the eigenvectors, we substitute each eigenvalue into the equation (A - λI)u = 0 and solve for u. For A₁ = -6, we obtain the eigenvector u₁ = [-2, 1]. Similarly, for A₂ = 4, we find the eigenvector u₂ = [1, 2].
b) To obtain an orthonormal basis for R² using the eigenvectors, we normalize u₁ and u₂. The normalized vectors are u₁ = [-2/√5, 1/√5] and u₂ = [1/√5, 2/√5].
c) Since we have two linearly independent eigenvectors, A is diagonalizable. We can construct the diagonal matrix D using the eigenvalues A₁ and A₂ as its diagonal elements, and the matrix P with the eigenvectors as its columns. Thus, A = PDP⁻¹.
d) To plot the eigenspaces, we use the bases found in part a). The eigenspace corresponding to A₁ = -6 is spanned by the vector u₁, and the eigenspace for A₂ = 4 is spanned by the vector u₂. Using these bases, we can visualize the eigenspaces in the coordinate plane.
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A ja ja ja ibsnisbisnobs
Answer:
20
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
Algebra complete the table right the expression that can be used to find the missing value in the second row
How high is the hand of the superhero balloon above the ground?
The hand is ____ feet above the ground.
Answer: the answer is 66
Step-by-step explanation:
What’s the answer???
Answer:
$50, 100
Step-by-step explanation:
A segment in the complex plane has a midpoint at -1+i. If the segment has an endpoint at -5-7i, what is the other endpoint? -9-15i
Given that a segment in the complex plane has a midpoint at -1+i. If the segment has an endpoint at -5-7i, we need to find the other endpoint.
To find the other endpoint, we can use the midpoint formula which states that the midpoint of a segment is the average of the endpoints of the segment. Let the other endpoint be represented by the complex number z. Then, we have:-1 + i = (-5 - 7i + z)/2Multiplying both sides by 2, we get:-2 + 2i = -5 - 7i + zSimplifying the equation by moving the known values to the left-hand side, we have:z = -2 + 2i + 5 + 7iCombining like terms, we get:z = 3 + 9iTherefore, the other endpoint is 3 + 9i. Thus, the correct option is (D) 3 + 9i.
To find the other endpoint of the segment in the complex plane, we can use the midpoint formula. The midpoint formula states that the midpoint between two complex numbers, z₁ and z₂, is given by:
Midpoint = (z₁ + z₂) / 2
We are given that the midpoint is -1 + i and one endpoint is -5 - 7i. Let's denote the other endpoint as z₂. Using the midpoint formula, we can write:
-1 + i = (-5 - 7i + z₂) / 2
To isolate z₂, we can multiply both sides of the equation by 2:
2(-1 + i) = -5 - 7i + z₂
To simplifying, we have:
-2 + 2i = -5 - 7i + z₂
Now, let's isolate z₂ by subtracting -5 - 7i from both sides:
-2 + 2i + 5 + 7i = z₂
Combining like terms, we get: 3 + 9i = z₂
Therefore, the other endpoint of the segment in the complex plane is given by -9 - 15i.
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The given information is that in the complex plane, a segment has its midpoint at -1+i. The segment has an endpoint at -5-7i. It is asked to find the other endpoint of the segment.
Thus, the other endpoint of the segment is -9 + 9i.
The midpoint of the segment is given as follows:
Midpoint = (endpoint1 + endpoint2) / 2
-1+i = (-5-7i + endpoint2) / 2
Multiplying both sides of above equation by 2, we get:
-2 + 2i = -5 - 7i + endpoint2
endpoint2 = -2 + 2i + 5 + 7i
endpoint2 = -9 + 9i
Therefore, the other endpoint of the segment is -9 + 9i.
Thus, the answer for this question is -9+9i.
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A box contains three cards. On one card there is a question mark (Upper Q), on another card there is a pear (Upper P), and on the third card there is a moon (Upper M). Two cards are to be selected at random with replacement. Complete parts (a) through (e) below. a) Determine the number of sample points in the sample space.
Complete question :
Determine the probability that two pears are selected The probability is(Simplity your answer.)
d) Determine the probability that a card containing a PEAR and then a card containing a question mark are selected
Answer:
(QQ, QP, QM, QP, PP, MP, QM, PM, MM) ;
Step-by-step explanation:
Given :
Marking on card :
Question mark = Q
Pear = P
Moon = M
Selecting two cards with replacement :
Sample space :
_____ Q ____ P _____ M
Q ___QQ ___QP ___ QM
P ___QP ____PP ___ MP
M__ QM ____PM ___MM
(QQ, QP, QM, QP, PP, MP, QM, PM, MM) ;
1/9 ;
2/9
P(selecting 2 pears) = (PP)
P(p) = required outcome / Total possible outcomes = 1 / 9
Card containing a pear and then a question mark ;
(PQ or QP).
P(p) = 1/3 ; P(Q) = 1/3
P(PQ) + P(QP)
(1/3 * 1/3) + (/3 * 1/3)
1/9 + 1/9
(1 + 1) / 9
= 2/9
Jack and Andrea want to create a right triangle together using values of x and y and the polynomial identity to generate Pythagorean triples. If Andrea picks a value of x = 2, and the hypotenuse of the resulting right triangle is 5, what natural number value of y did Jack pick?
y = 1
y = 4
y = 2
y = 3
Answer:
I think the answer could be y=3 or y=2
it could be something else tho im sorry
Answer:
y=2
Step-by-step explanation:
Let W = {(0,x, y, z); x – 3y + 92 = 0} be a subspace of R*. Then a basis for W is: {(0,6.1,0), (0,-9,0,1)) None of the mentioned {(0,-6,1,0), (0,9,0,1)) {(0,3,1,0), (0,-9,0,1)) -4 12 -1 -1 Let k be a real number and A = k 2 lo 7 1 Then A is a singular matrix if None of the mentioned k=15/2 k=10 k=5
A basis for W is {(0,-6,1,0), (0,9,0,1)}.
Matrix A is a singular matrix when k = 1.
To find the basis for the subspace W and determine the value of k for matrix A, let's go through each part separately.
Part 1: Basis for W
The subspace W is defined by the equation x – 3y + 92 = 0. In order to find a basis for W, we need to find two linearly independent vectors that satisfy this equation.
From the given options, the vectors {(0,6.1,0)} and {(0,-9,0,1)} do not satisfy the equation x – 3y + 92 = 0.
However, the vectors {(0,-6,1,0)} and {(0,9,0,1)} satisfy the equation x – 3y + 92 = 0. Therefore, a basis for W is {(0,-6,1,0), (0,9,0,1)}.
Part 2: Singular Matrix A
Matrix A = [k 2 10 7 1].
To determine if A is a singular matrix, we need to check if its determinant is equal to zero.
Calculating the determinant of A:
det(A) = k(21 - 710) - 2(27 - 101) + 10(27 - 101)
= k(-68) - 2(-14) + 10(4)
= -68k + 28 + 40
= -68k + 68
A is a singular matrix if det(A) = -68k + 68 = 0.
Solving the equation -68k + 68 = 0, we find k = 1.
Therefore, A is a singular matrix when k = 1.
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Will mark brainliest if you get the correct answer.
Answer:
2×2×5×7=20×7=140
2×3×6×7=36×7=252
252+140=392
Dexamethasone 12 mg IV push Drug available: Dexamethasone 4 mg/5 mL How many milliliters would be needed to be drawn up for one dose?
A. 3 ml
B. 2.4 ml
C. 10 ml
D. 15 ml
The correct answer is option B) 2.4 ml. The 2.4 milliliters would be needed to be drawn up for one dose.
To calculate the amount of Dexamethasone 4 mg/5 mL needed for a 12 mg dose, we can use a simple proportion:
4 mg / 5 mL = 12 mg / x
Cross-multiplying, we get:
4 mg * x = 60 mg
x = 60 mg / 4 mg/mL
x = 15 mL
Therefore, to administer a 12 mg dose of Dexamethasone using the available drug concentration of Dexamethasone 4 mg/5 mL, we need to draw up only 2.4 mL.
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22:13 progress 87 percent shift changes you created the following labor plan for truck unloading and box storage during an 8-hour shift. task boxes processed per worker per hour
A labor plan was created for truck unloading and box storage during an 8-hour shift, with the productivity measured in boxes processed per worker per hour.
To fully answer the question, it is necessary to provide the details of the labor plan, including the specific productivity rates for each task and the number of workers assigned to each task. Without this information, it is not possible to provide a comprehensive explanation. However, the labor plan aims to optimize the efficiency of truck unloading and box storage within the given 8-hour shift. It likely involves assigning workers to different tasks based on their productivity levels and the estimated time required for each task.
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Determine whether there is a significant difference in the pattern of rankings for the 26 American and 41 European male tennis players included in the top-100 seeded players on the pro-tennis tour.
To determine whether there is a significant difference in the pattern of rankings for the 26 American and 41 European male tennis players included in the top-100 seeded players on the pro-tennis tour, a statistical analysis can be conducted.
Statistical analysis would include a two-sample t-test or an ANOVA test to compare the means of the two groups (American and European players). If the p-value obtained is less than the level of significance (usually 0.05), then there is a significant difference between the pattern of rankings of the two groups.The rankings of players will also be taken into account. If there is a significant difference between the two groups, then further analysis can be done to determine the cause of the difference. Possible factors that could contribute to the difference include training regimes, genetics, playing surfaces, and mental preparation, among others.
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There is no significant difference in the pattern of rankings between these two groups of players.
To determine whether there is a significant difference in the pattern of rankings for the 26 American and 41 European male tennis players included in the top-100 seeded players on the pro-tennis tour, we need to perform a statistical analysis using appropriate tests such as the t-test or ANOVA (Analysis of Variance).
The null hypothesis for this test would be that there is no significant difference in the pattern of rankings between the American and European male tennis players included in the top-100 seeded players on the pro-tennis tour.
The alternative hypothesis would be that there is a significant difference in the pattern of rankings between these two groups of players.
If the p-value obtained from the test is less than the chosen level of significance (usually 0.05), then we can reject the null hypothesis and conclude that there is a significant difference in the pattern of rankings for the American and European male tennis players included in the top-100 seeded players on the pro-tennis tour.
On the other hand, if the p-value is greater than the level of significance, we fail to reject the null hypothesis and conclude that there is no significant difference in the pattern of rankings between these two groups of players.
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Please Help! Draw the graph of an absolute value function that has these key features:
vertex: (2,-3)
increasing: (2, ∞)
decreasing: (-∞, 2)
domain: all real numbers
range: [-3, ∞)
end behavior: As x approaches negative infinity, f(x) approaches positive infinity. As x approaches positive infinity, f(x) approaches positive infinity.
Answer:edmentum
Step-by-step explanation:
Sarah is building a birdhouse the nails she uses are 1 inch long the wood board is 1 foot long how many times smaller is the nails compared to the wood
3 of the 100 digital video recorders (DVRs) in an inventory are known to be defective. What is the probability you randomly select an item that is not defective?
Answer:
97/100
Step-by-step explanation:
Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.
For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one ids attached to the event. If it doesn't a value of zero is attached to the event.
Probability that the DVRs is not faulty = total number of faulty videos / total number of videos
total number of faulty videos = 100 - 3 = 97
total number of videos = 100
97/100
Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part B: If (50)x = 1, what are the possible values of x? Explain your answer. (5 points)
Answer:
See Explanation
Step-by-step explanation:
The question is not clear. However, I will treat the question as:
[tex](26)x = 1[/tex]
[tex](50)x = 1[/tex]
and:
[tex](2^6)^x = 1[/tex]
[tex](5^0)^x = 1[/tex]
Solving: [tex](26)x = 1[/tex] and [tex](50)x = 1[/tex]
[tex](26)x = 1[/tex]
Divide both sides by 26
[tex]x = \frac{1}{26}[/tex]
[tex](50)x = 1[/tex]
Divide both sides by 50
[tex]x = \frac{1}{50}[/tex]
Solving [tex](2^6)^x = 1[/tex] and [tex](5^0)^x = 1[/tex]
[tex](2^6)^x = 1[/tex]
Express 1 as 2^0
[tex](2^6)^x = 2^0[/tex]
Remove bracket
[tex]2^{6x} = 2^0[/tex]
Cancel out 2
[tex]6x = 0[/tex]
Divide both sides by 6
[tex]x = \frac{0}{6}[/tex]
[tex]x = 0[/tex]
[tex](5^0)^x = 1[/tex]
Express 1 as 5^0
[tex](5^0)^x = 5^0[/tex]
Cancel out 5^0
[tex]x = 1[/tex]