GIVING EVERYTHING IF CORRECT. No fake answers, you will be reported.

Answer:

(4x²+36) feet²

Step-by-step explanation:

Area of the pool = L × W

Take width as x and Length as 4x

4x × x = (4x²)feet² {area of pool}

Area of walkway = L × W

6 × 6 = 36feet²

Total area = 4x² + 36 feet²

Answer:

120, 60

Step-by-step explanation:

half a century = 60 + 10 x 2 = ted.

she is 60.

Answer: B

Step-by-step explanation:

108 divide by 54 = 2

That equation means she paid 2 dollars per ticket, not 1 dollar for 2 tickets

(There is no 1 in the equation also)

Answer:

84sq. in

Step-by-step explanation:

Area of the rectangle  = length * width

Given

Length = 7in

Width = 12in

Area of the rectangle = 7in * 12in

Area of the rectangle = 84sq. in

Hence the area of the rectangle is 84sq. in

Answer:

y = 54

Step-by-step explanation:

Once again we are going to use the inscribed angle and intercepted arc relationship where the inscribed angle is equal to half of the measure of the intercepted arc.

Angle "y" is the inscribed angle and its intercepted arc has a measure of 108°

So y = one half of 108

[tex]\frac{108}{2} =54[/tex]

So we can conclude that y = 54

Answer:

56m

Step-by-step explanation:

5+7+5+11+7+16+5

= 56

Answer:

There was a increase of 1.7% over these three​ years

Step-by-step explanation:

Multipliers:

For a decrease of a%, we multiply by: [tex]\frac{100-a}{100}[/tex]

For a increase of a%, we multiply by: [tex]\frac{100+a}{100}[/tex]

What was the percentage​ increase/decrease of groundhogs over these three​ years?

Decrease of 12%(multiplication by 0.88).

Increase of 6%(multiplication by 1.06).

Increase of 9%(multiplication by 1.09).

After these three years:

0.88*1.06*1.09 = 1.017

1.017 - 1 = 0.017

0.017*100% = 1.7%

There was a increase of 1.7% over these three​ years

Answer:

C or D

Step-by-step explanation:

Answer: 1/8

Step-by-step explanation: hoped this helped:))

Answer:

i think its 1/3

Step-by-step explanation:

Answer:

75 FT

Step-by-step explanation:

Multiple 5 by 4 for each of the three squares, then multiply 5 by 3 for each triangle and divide it by 2. Add them all together and you get 75.

Answer:

75 Ft

Step-by-step explanation:

I told you im surewhwhwhhwhshsbsbwbsbsbsbs

Answer:

144cm

Step-by-step explanation:

Just search it up lol

Answer:

14 months until there equal

Answer:

14 months

Step-by-step explanation:

Answer:

314.96in

Step-by-step explanation:

Answer:

The mean is of 33.6

The margin of error is of 5.2.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

In this question:

Lower bound: 28.4

Upper bound: 38.8

Mean

(28.4+38.8)/2 = 33.6.

The mean is of 33.6

Margin of error:

(38.8 - 28.4)/2 = 5.2

The margin of error is of 5.2.

Answer:

Circumference of circle = 138.28 cm (Approx.)

Area of circle = 1,521.11 cm² (Approx.)

Step-by-step explanation:

Given:

Radius of circle = 22 cm

Find:

Circumference of circle

Area of circle

Computation:

Circumference of circle = 2πr

Circumference of circle = 2(22/7)(22)

Circumference of circle = 2(3.1428)(22)

Circumference of circle = 138.2832

Circumference of circle = 138.28 cm (Approx.)

Area of circle = πr²

Area of circle = (22/7)(22)²

Area of circle = (3.1428)(22)(22)

Area of circle = 1,521.1152

Area of circle = 1,521.11 cm² (Approx.)

Step-by-step explanation:

-2<-1<1, so f(-1)=-1-2=-3

Answer: Because the question uses the word “distinct” meaning obvious, and clear, I would select AB, AC, CB. (If it’s asking for all the possible line segments, I would select AB, AC, CB, BA, CA, BC).

Answer:

i think a.... sorry if im wrong

Step-by-step explanation:

Answer:

Step-by-step explanation:

Probably D,  he's measuring voltage across the wire.. and then across the light bulb,   there would be very little across the wire and a lot across the light bulb

Answer:

Answer is F. y = 6x

Step-by-step explanation:

Answer:

Courtney is travelling at 9mph

Christy is travelling at 18mph

Step-by-step explanation:

Courtney's speed = x

Christy's speed = y

Christy travels 9 mph faster than Courtney: x+9=y

Distance = speed * time

Courtney's distance after 7 hours = 7x

Christy's distance after 7 hours = 7y

After 7 hours, they're 189 miles apart:

7x+7y=189

x+y=27

x+y=27

x+x+9=27

2x=18

x=9

y=x+9

y=9+9

y=18

Answer:

D-B-A-C

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

an example

1x2=2

1 is a, 2 is b, see they equal the same 2 and 2.

Answer:

B. 0

Step-by-step explanation:

Any number multiplied by 0 equals zero.

Answer:

3(x^2 x Y)(4z x X)(2y x Z)

Step-by-step explanation:

Answer:

[tex]3(x^{3} * 2y^2*4z^2)[/tex]

Step-by-step explanation:

x^2(x) = x^3

2y(y) = 2y^2

4z(z) = 4z^3

Multiple it all by 3

Answer:

The correct answer is C. I tried B and got it wrong

Step-by-step explanation:

Answer:

The ratio of the drag coefficients [tex]\dfrac{F_m}{F_p}[/tex] is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, [tex]c_{m}[/tex] = The drag coefficient of the prototype, [tex]c_{p}[/tex]

The medium of the test for the model, [tex]\rho_m[/tex] = The medium of the test for the prototype, [tex]\rho_p[/tex]

The drag force is given as follows;

[tex]F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}[/tex]

We have;

[tex]L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m[/tex]

Therefore;

[tex]\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2[/tex]

[tex]\dfrac{L_p}{L_m} =\dfrac{17}{1}[/tex]

[tex]\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2[/tex]

[tex]\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2[/tex]

[tex]\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}[/tex]

[tex]\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2[/tex]

[tex]\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3[/tex]

[tex]\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3[/tex]= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients [tex]\dfrac{F_m}{F_p}[/tex] ≈ 0.0002.