Given m n, find the value of x and
y.

Answer:

Greatest common factor of 280 and 168 is 56

-NULL

Brainliest will be appreciated thank you!

Answer:

[tex]2 {y}^{7} x - 5 {y}^{5} {x}^{2} - 4{y}^{8} {x}^{3}[/tex]

Answer:

make a chart and it will be easy for you

Answer:

The value of the expression is - 9.

Evaluating the expression before simplifying is preferred because you only have to substitute once instead of substituting three times.

Step-by-step explanation:

x = 2

- 8x + 5 - 2x - 4 + 5x

= - 8x - 2x + 5x + 5 - 4

= - 10x + 5x + 1

= - 5x + 1

= - 5 ( 2 ) + 1

= - 10 + 1

= - 9

Answer:

-4

Step-by-step explanation:

The form of a liner equation is y=mx+b.  b is 0 in this example.  So we are left with y=-4x

-4 is the m, the slope.  It is also called the unit rate of change.  It tells us how much y changes for each 1x unit.  

y     x

0    0

-4    1   One unit changes y by -4 :  The unit rate of change.

-8    2

please mark this answer as brainlist

The value of given expression is 27.

An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.

The given expression is 6²-(8-4)²+7.

Here, 6²-(8-4)²+7

= 6²-(4)²+7

= 36-16+7

= 20+7

= 27

Therefore, the value of given expression is 27.

To learn more about an expression visit;

https://brainly.com/question/28170201.

#SPJ2

Answer:

5hg vb

Step-by-step explanation:

,hgbn

Answer:

−120314x − 11

Step-by-step explanation:

Answer:

this is a trick question 176 fps is equal to 120 mph

so 120=120

Explanation: the correct answer is C.

Answer:

This polynomial is either a function like f(x), or it's just =0 and it's solved by a quadratic equation.

Step-by-step explanation:

Let's say it's equal to 0, we can easily divide the whole expression with 3, as obviously 3,24,48 have the same divisor(3), then we are left with:

x²-8x+16=0, then we apply the quadratic equation, and we got only 1 solution and that's x=4

If it is a function f(x), than it will have roots(root of a quadratic function is the x-coordinate where y=0, basically when the parabola intersects the x-axis(y=0), as we'll get that the only root is x=4

Step-by-step explanation:

z°=180°-25°

z°= 155°

z°=x°=155° (vertically opposite angle).

w°=25°(alternate angle).

y°=z°=155°(alternate angle).

hope this helps you.

Answer:

Step-by-step explanation:

As AB and CD are parallel lines cut by a transversal, we have:

So the measures are:

Answer:

cos(30) = (sqrt(3)/2) * cos(0)    

Step-by-step explanation:

cos(0) = 1

cos(30) = sqrt(3)/2

Thus, we can write that:

cos(30) = (sqrt(3)/2) * cos(0)

Here we need to Prove that ,

[tex]\bf\implies \sqrt[ab]{ \frac{ {x}^{a} }{ {x}^{b} } } . \sqrt[bc]{ \frac{ {x}^{b} }{ {x}^{c} } } . \sqrt[ca]{ \frac{ {x}^{c} }{ {x}^{a} } } = 1.[/tex]

Lets start with LHS , which is ,

[tex]\bf\implies LHS = \sqrt[ab]{ \dfrac{ {x}^{a} }{ {x}^{b} } } . \sqrt[bc]{ \dfrac{ {x}^{b} }{ {x}^{c} } } . \sqrt[ca]{ \dfrac{ {x}^{c} }{ {x}^{a} } } [/tex]

We know that ,

[tex]\bf\implies \sqrt[n]{k^m }= k^{\frac{m}{n}}[/tex]

• So that ,

[tex]\bf\implies \sqrt[ab]{x^{a-b}} . \sqrt[bc]{x^{b-c}} .\sqrt[ac]{x^{c-a}} \\\\\bf\implies x^{\frac{a-b}{ab}} . x ^{\frac{b-c}{bc}} .x^{\frac{c-a}{ca}} \\\\\bf\implies x^{\frac{ ac - bc + ab - ac + bc - ba }{abc } }\\\\\bf\implies x^{\frac{0}{abc}} \\\\\bf\implies x^0 \\\\\bf\implies 1 = RHS [/tex]

Hence ,

[tex]\implies \boxed{\bf \red{ LHS = RHS }} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

Consider LHS:

[tex]\sf= \sqrt[\sf ab]{\dfrac{\sf x^{a}}{\sf x^{b}}}\cdot \sqrt[\sf bc]{\dfrac{\sf x^{b}}{\sf x^{c}}}\cdot \sqrt[\sf ac]{\dfrac{\sf x^{c}}{\sf x^{a}}}[/tex]

As we know that:

[tex]\sf\red\leadsto\dfrac{x^{a}}{x^{b}}=x^{a-b}[/tex]

We get:

[tex]\sf= \sqrt[\sf ab]{\sf x^{a-b}}\cdot \sqrt[\sf bc]{\sf x^{b-c}}\cdot \sqrt[\sf ac]{\sf x^{c-a}}[/tex]

We can also write it as:

[tex]\sf= x^{\dfrac{a-b}{ab}}\cdot x^{\dfrac{b-c}{bc}}\cdot x^{\dfrac{c-a}{ac}}[/tex]

We know that:

[tex]\sf \red\leadsto x^{a}\cdot x^{b}=x^{a+b}[/tex]

We get:

[tex]\sf= x^{\bigg(\dfrac{a-b}{ab}+\dfrac{b-c}{bc}+\dfrac{c-a}{ac}\bigg)}[/tex]

[tex]\sf= x^{\bigg(\dfrac{c(a-b)+a(b-c)+b(c-a)}{abc}\bigg)}[/tex]

[tex]\sf= x^{\bigg(\dfrac{ac-bc+ab-ac+bc-ab}{abc}\bigg)}[/tex]

[tex]\sf= x^{\bigg(\dfrac{0}{abc}\bigg)}[/tex]

[tex]\sf= x^{0}[/tex]

[tex]\sf=1[/tex]

[tex]\textsf{= RHS}\\[/tex]

Answer:

1  143 /5000

Step-by-step explanation:

Answer:

15t+9r=2

Step-by-step explanation:

the terms which are the variables are not the same on any part of the equation

Answer: y = 3x + 3

Step-by-step explanation:

We know the linear function as following:

y = mx + b

m is the slope of the equation. b represents the y-intercept.

To find m, we divide the rate of change of y by the rate of change of x. We know that the rate of change y is +3 because we add three each time in order to find the next value. The rate of change of x is +1 because we add one each time to find the next value. So m would be:

m = 3/1

m = 3

Our linear equation is now as following:

y = 3x + b

In order to find b, we should first substitute a coordinate in the equation above.

y = 3x + b

6 = 3(1) + b

Then, we multiply 3 with 1

6 = 3 + b

Finally, we substract 3 on both sides. Now we've got our b value.

b = 3

Now our equation should look like this.

y = 3x + 3

To verify if the equation, we should substitute another coordinate, and verify if each side of the equation is equal.

y = 3x + 3

15 = 3(4) + 3

15 = 12 + 3

15 = 15

So we now know that the equation is indeed correct.

Answer:

Step-by-step explanation:

As per given table we have ordered pairs:

Find the slope and y- intercept to work out the equation.

The slope:

The y -intercept:

The equation is:

The graph is attached

Answer:

72 is the correct answer

Answer:

I believe 72 is the correct answer

Step-by-step explanation:

Step-by-step explanation:

Based on the given conditions,

[tex] formulate: 1.6\% \times 40000 \times 12 \div 12

[tex] formulate: 1.6\% \times 40000 \times 12 \div 12Reduce the fraction: \dfrac{2 \times 40000}{125}

[tex] formulate: 1.6\% \times 40000 \times 12 \div 12Reduce the fraction: \dfrac{2 \times 40000}{125}[/tex]

[tex]Reduce the fraction: 2 \times320

[tex]Reduce the fraction: 2 \times320Calculate the product orquotient: 640[tex]

Answer 640

Answer:

[tex]\sf\longmapsto \: 640[/tex]

Step-by-step explanation:

Based on given cases:

[tex] \sf \: Formulate: 1.6\% \times 40000 \times 12 \div 12[/tex]

Reduce the fraction:

[tex] \sf \longmapsto \: \dfrac{2 \times 40000}{125}[/tex]

[tex] \sf \longmapsto \: 320 \times 2[/tex]

Calculate the product/quotient:

[tex] \sf\longmapsto \: 640[/tex]

Answer:

40%

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

pls maerk as brainliest

Answer:

33.176

Step-by-step explanation:

951 4 1404 393

Answer:

  w = 17

Step-by-step explanation:

Altitude SU of isosceles triangle RST bisects base RT. This means ...

  UR = UT

  5w = w+68

  4w = 68 . . . . . subtract w

  w = 17 . . . . . . divide by 4

Answer:

- 1/4

Step-by-step explanation:

[tex]\frac{1-\sqrt{x} }{x^{2}-1 } = \frac{(1-\sqrt{x})*(1+\sqrt{x} ) }{(x+1)(x-1)(1+\sqrt{x} )} \\= \frac{1-x}{-(1-x)(x+1)(1+\sqrt{x} )} \\= - \frac{1}{(x+1)(1+\sqrt{x} )} \\ \lim_{->1} - \frac{1}{(x+1)(1+\sqrt{x} )} \\ = -\frac{1}{(1+1)(1+\sqrt{1}) } = - 1/4[/tex]

Answer:

408, 250, and 4055 hope this helps

Answer:

B

Step-by-step explanation:

Might be C, but I hope it helps

Answer:

Here are the answers for the whole QC for CA students.

1. C

2. A

3. no

4. c

5. A

Step-by-step explanation: