The standard error of the mean, rounded to 2 decimal places, is 1.73.
Explanation:
Given that: Forty-five elements were randomly sampled from a population that has 1500 elements. The sample mean is 180 with a varience of 135.
The standard error of the mean (SEM) is a measure of how much the sample mean is likely to vary from the true population mean. It is calculated as the square root of the sample Variance divided by the square root of the sample size.
Thus,
To find the standard error of the mean, we will use the following formula:
Standard Error of the Mean (SEM) = sqrt(Sample Variance) / sqrt(Sample Size)
Given the information in your question, we have:
- Sample Variance = 135
- Sample Size = 45 because forty-five elements were randomly sampled from a population
Now, we'll calculate the standard error of the mean:
1. Calculate the square root of the sample variance: sqrt(135) ≈ 11.62
2. Calculate the square root of the sample size: sqrt(45) ≈ 6.71
3. Divide the results from steps 1 and 2: 11.62 / 6.71 ≈ 1.73
Therefore, the standard error of the mean, rounded to 2 decimal places, is 1.73.
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(1 point) Find the limit (enter 'DNE' if the limit does not exist) Hint: rationalize the denominator. lim (x,y)=(0,0) (-2x2 +9y2) (-2x2 +9y2 + 1) - 1 (1 point) Find the limit, if it exists, or type N if it does not exist. 3.cy + 4y2 + 5x2 lim (1,y,z)+(0,0,0) 9x2 + 16y2 + 2522
The limit exists and its value is 5/2522.
Find the limit of the given function, and determine whether it exists or not?To find the limit of the given function as (x,y) approaches (0,0), we can simplify the expression using algebraic manipulation and then substitute the values of x and y with 0. Here, we can use the difference of squares identity to simplify the expression as follows:
[tex](-2x^2 + 9y^2)(-2x^2 + 9y^2 + 1) - 1 = [(9y^2 - 2x^2)(2x^2 + 1 - 9y^2)] - 1[/tex]
[tex]= [18x^4 - 81y^4 + 4x^2 - 18x^2y^2 + 2x^2 - 9y^2] - 1[/tex]
[tex]= 20x^4 - 81y^4 - 18x^2y^2 - 9y^2[/tex]
Now, substituting x = 0 and y = 0 in the expression, we get:
lim (x,y)→(0,0) [tex][(-2x^2 + 9y^2)(-2x^2 + 9y^2 + 1) - 1]/(-2x^2 + 9y^2)[/tex]
= lim (x,y)→(0,0)[tex][20x^4 - 81y^4 - 18x^2y^2 - 9y^2]/(-2x^2 + 9y^2)[/tex]
= lim (x,y)→(0,0) [tex][(2x^2 + 9y^2)(10x^2 - 81y^2 - 9)]/(-2x^2 + 9y^2)[/tex]
Since the denominator approaches 0 as (x,y) approaches (0,0) but the numerator does not approach 0, the limit does not exist. Therefore, the answer is DNE.
To find the limit of the given function as (1,y,z) approaches (0,0,0), we can substitute the given values of x, y, and z in the expression and simplify it.
lim (1,y,z)→(0,0,0) [tex](3cy + 4y^2 + 5x^2)/(9x^2 + 16y^2 + 2522)[/tex]
[tex]= (3c0 + 40^2 + 51^2)/(91^2 + 16*0^2 + 2522)[/tex]
= 5/2522
Therefore, the limit exists and its value is 5/2522.
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Examine the question for possible bias. Do you think all high school students should be required to take a gym course? Select one: a. Biased because many people did not like gym in high school. b. Biased because many people did not like to be required to do anything. c. The question is not clearly written. d. Seems unbiased. e. Biased because not every adult in the U.S. has attended high school.
Biased because many people did not like to be required to do anything. (B)
The question assumes that all high school students should be required to take a gym course without considering individual preferences or abilities. The bias lies in the assumption that everyone should be forced to do something they may not enjoy or excel at, which is not fair.
It is important to consider individual needs and interests when making educational requirements. The question could be revised to ask whether high schools should offer gym courses as an option for students to choose from, rather than mandating it for all.(B)
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Find the volume of the rectangular prism.
Answer: 5/4
Step-by-step explanation:3/4 * 2 * 5/6=5/4 so 5/4 is our answer
Two rectangular rooms have an area of 240 m? each. The length of one room is x m and the length of the other room is 4 m longer.
(a)
Write down, in terms of x, an expression for the width of each room.
(b)
If the widths of the rooms differ by 3 m, form an equation in x and show that it reduces
to x^2+4x - 320 = 0
(c)
Solve the equation x^2+ 4x - 320 = 0.
(d)
Hence find the difference between the perimeters of the rooms.
(a) The area of each rectangular room is given by the formula:
Area = length x width
Since the area of each room is 240 m², and the length of one room is x m, we can write:
240 = x × width of the first room
Therefore, the width of the first room is:
width of the first room = 240 / x m
The length of the other room is 4 m longer than x, so we can write:
length of the second room = x + 4 m
And using the formula for the area of the second room, we have:
240 = (x + 4) × width of the second room
Therefore, the width of the second room is:
width of the second room = 240 / (x + 4) m
(b) If the widths of the rooms differ by 3 m, we can write:
width of the second room - width of the first room = 3
Substituting the expressions for the widths obtained in part (a), we get:
240 / (x + 4) - 240 / x = 3
Multiplying both sides by x(x+4), we get:
240x - 240(x + 4) = 3x(x + 4)
Simplifying and rearranging terms, we get:
x^2 + 4x - 320 = 0
(c) To solve the quadratic equation x^2 + 4x - 320 = 0, we can use the quadratic formula:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 1, b = 4, and c = -320.
Substituting these values, we get:
x = (-4 ± sqrt(4^2 - 4(1)(-320))) / 2(1)
Simplifying the expression under the square root, we get:
x = (-4 ± sqrt(1296)) / 2
x = (-4 ± 36) / 2
Therefore, x = -20 or x = 16.
Since the length of the room cannot be negative, we reject the solution x = -20, and conclude that x = 16 m.
(d) Using the value of x obtained in part (c), we can find the dimensions of each room:
The first room has length x = 16 m and width 240 / x ≈ 15 m.The second room has length x + 4 = 20 m and width 240 / (x + 4) ≈ 12 m.Therefore, the perimeters of the rooms are:
Perimeter of the first room = 2(length + width) = 2(16 + 15) = 62 mPerimeter of the second room = 2(length + width) = 2(20 + 12) = 64 mThe difference between the perimeters is:
64 - 62 = 2 m
Therefore, the difference between the perimeters of the rooms is 2 m.
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A set of data has a mean of 52 and a standard deviation of 5. What is the z-score for the element 46 in the data?
Question 5 options:
1.2
-2.3
-1.2
2.3
Answer:
we use the following Formula to anwer the above mentioned question;
(x - m)/given standard deviation =
Here,
x = 46
M = given mean value ( 52)
Now, put the given values in the above formula;
Hence the answer will be
(46 - 52) / 5 = - 1.2
Answer = -1.
Step-by-step explanation:
a sample of n = 6 scores has a mean of m = 24. what is σx for this sample?
The σx (standard deviation) for this sample with n = 6 scores and a mean (m) of 24 cannot be determined without the individual scores or variance.
To calculate the standard deviation (σx) for a sample, we need the individual scores or at least the variance of the sample. The given information only provides the sample size (n = 6) and the mean (m = 24), which is insufficient to determine σx.
If we have the individual scores, we can follow these steps:
1. Calculate the mean (m) of the sample.
2. Subtract the mean from each score and square the result.
3. Find the average of these squared differences.
4. Take the square root of this average to get the standard deviation (σx).
Alternatively, if we have the variance (s²), we can simply take the square root of the variance to obtain the standard deviation (σx). In this case, without the necessary information, we cannot calculate the standard deviation.
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You invest $1000 into a bank that earns 5.3% intrest compounded monthly how much money would be in the account after 15 years
If the investment earns 5.3% income compounded monthly over 15 years, the money will increase to $2078.80.
To solve this problemWe may use the compound interest calculation to determine the investment's future value:
FV = PV x (1 + r/n)^(n*t)
Where
FV stands for future valuePV refers to the initial investment's present valuer is the annual interest rate in decimal formn = The quantity of annual interest compoundingst = Duration, in yearsUsing the given values, we can plug them into the formula and solve for FV:
FV = $1000 x (1 + 0.053/12)^(12*15)
FV = $1000 x (1.0044167)^(180)
FV = $1000 x 2.0788
FV = $2078.80
Therefore, If the investment earns 5.3% income compounded monthly over 15 years, the money will increase to $2078.80.
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If the investment earns 5.3% income compounded monthly over 15 years, the money will increase to $2078.80.
To solve this problemWe may use the compound interest calculation to determine the investment's future value:
FV = PV x (1 + r/n)^(n*t)
Where
FV stands for future valuePV refers to the initial investment's present valuer is the annual interest rate in decimal formn = The quantity of annual interest compoundingst = Duration, in yearsUsing the given values, we can plug them into the formula and solve for FV:
FV = $1000 x (1 + 0.053/12)^(12*15)
FV = $1000 x (1.0044167)^(180)
FV = $1000 x 2.0788
FV = $2078.80
Therefore, If the investment earns 5.3% income compounded monthly over 15 years, the money will increase to $2078.80.
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how many different ways are possible in choosing a president, vice president, and secretary from a class of 13 students?
There are 1716 different ways to choose a president, vice president, and secretary from a class of 13 students
To answer your question about how many different ways are possible in choosing a president, vice president, and secretary from a class of 13 students, we will use the concept of permutations.
Step 1: Determine the number of ways to choose the president. There are 13 students to choose from, so there are 13 options.
Step 2: Determine the number of ways to choose the vice president. After the president has been chosen, there are 12 students left to choose from, so there are 12 options.
Step 3: Determine the number of ways to choose the secretary. After the president and vice president have been chosen, there are 11 students left to choose from, so there are 11 options.
Step 4: Calculate the total number of different ways to choose the three positions by multiplying the number of options for each position: 13 (president) × 12 (vice president) × 11 (secretary) = 1716 different ways.
Therefore, there are 1716 different ways to choose a president, vice president, and secretary from a class of 13 students.
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determine whether the integral is convergent or divergent. ∫[infinity] to 1 81 ln(x)/ x dx convergentdivergent
Since the integral converges to a finite value (-81), the given integral is convergent.
What is integral?In mathematics, an integral is a mathematical object that represents the area between a function and the x-axis on a graph.
It is a fundamental concept in calculus, and is used to find the total amount of something when we know its rate of change.
To determine if the integral is convergent or divergent, we can use the integral test:
If ∫f(x)dx converges, then the sum ∑f(n) also converges.
If ∫f(x)dx diverges, then the sum ∑f(n) also diverges.
Let's apply this test to the given integral:
∫[infinity] to 1 81 ln(x)/ x dx
We can integrate this by parts:
u = ln(x) dv = 1/x dx
du = 1/x dx v = ln|x|
∫[infinity] to 1 81 ln(x)/ x dx = 81 [ ln(x) ln|x| ] [infinity, 1] - 81 ∫[infinity] to 1 ln|x| / x² dx
The first term evaluates to 0 because ln(infinity) = infinity, so we are left with:
81 ∫1 to infinity ln|x| / x² dx
To evaluate this integral, we can use integration by parts again:
u = ln|x| dv = 1 / x² dx
du = 1 / x dx v = - 1 / x
81 ∫1 to infinity ln|x| / x² dx = 81 [ - ln|x| / x ] [1, infinity] + 81 ∫1 to infinity 1 / x² dx
The first term evaluates to 0 because ln(1) = 0, so we are left with:
81 ∫1 to infinity 1 / x² dx = 81 [ - 1 / x ] [1, infinity] = 81 / infinity - 81 / 1 = - 81
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Since the integral converges to a finite value (-81), the given integral is convergent.
What is integral?In mathematics, an integral is a mathematical object that represents the area between a function and the x-axis on a graph.
It is a fundamental concept in calculus, and is used to find the total amount of something when we know its rate of change.
To determine if the integral is convergent or divergent, we can use the integral test:
If ∫f(x)dx converges, then the sum ∑f(n) also converges.
If ∫f(x)dx diverges, then the sum ∑f(n) also diverges.
Let's apply this test to the given integral:
∫[infinity] to 1 81 ln(x)/ x dx
We can integrate this by parts:
u = ln(x) dv = 1/x dx
du = 1/x dx v = ln|x|
∫[infinity] to 1 81 ln(x)/ x dx = 81 [ ln(x) ln|x| ] [infinity, 1] - 81 ∫[infinity] to 1 ln|x| / x² dx
The first term evaluates to 0 because ln(infinity) = infinity, so we are left with:
81 ∫1 to infinity ln|x| / x² dx
To evaluate this integral, we can use integration by parts again:
u = ln|x| dv = 1 / x² dx
du = 1 / x dx v = - 1 / x
81 ∫1 to infinity ln|x| / x² dx = 81 [ - ln|x| / x ] [1, infinity] + 81 ∫1 to infinity 1 / x² dx
The first term evaluates to 0 because ln(1) = 0, so we are left with:
81 ∫1 to infinity 1 / x² dx = 81 [ - 1 / x ] [1, infinity] = 81 / infinity - 81 / 1 = - 81
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Assume the variables: a = 2, b = 4, c = 6 The result of the following expression is True/Falsea = 4 or b > 2O TrueO False
The expression "a = 4 or b > 2" is true when a = 2 and b = 4 because the second part of the expression, "b > 2", is true.
The given expression is "a = 4 or b > 2" where a = 2 and b = 4.
The first part of the expression is "a = 4", which is false because a is not equal to 4.
The second part of the expression is "b > 2", which is true because b is equal to 4, which is greater than 2.
Since the expression is an "or" statement, only one part of it needs to be true for the entire expression to be true. Therefore, the result of the expression is true.
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use a reference angle to write cos(47π/36) in terms of the cosine of a positive acute angle.
___ cos (___)
In terms of the cosine of a positive acute angle, we can write cos(47π/36) as cos(13π/36).
To use a reference angle to write cos(47π/36) in terms of the cosine of a positive acute angle, follow these steps:
1. Determine the coterminal angle that lies in the first rotation (0 to 2π):
47π/36 = 13π/36 + 2π (since 2π = 72π/36)
So, the coterminal angle is 13π/36.
2. Identify the reference angle by finding the smallest positive angle between the coterminal angle and the x-axis:
Since 13π/36 lies in the first quadrant (0 to π/2), the reference angle is the same as the coterminal angle:
Reference angle = 13π/36.
3. Write cos(47π/36) in terms of the cosine of the positive acute angle:
cos(47π/36) = cos(13π/36).
So, the expression is cos(47π/36) = cos(13π/36).
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Find the next two terms in this
sequence.
1, 2, 6, 24, 120, [?], [
Step-by-step explanation:
Sequence Next Terms: 2
Priya Ravindran
Find the next two terms in this
sequence.
1, 2, 6, 24, 120, [?],
The given sequence is 1, 2, 6, 24, 120, [...].
To find the next two terms in the sequence, we need to determine the pattern followed by the sequence.
Looking at the given sequence, we can observe that each term is obtained by multiplying the previous term by the next integer. Specifically,
1 x 2 = 2
2 x 3 = 6
6 x 4 = 24
24 x 5 = 120
Therefore, the next two terms in the sequence would be obtained by multiplying the last term by the next two integers:
120 x 6 = 720
720 x 7 = 5040
Hence, the next two terms in the sequence are 720 and 5040.
Therefore, the complete sequence is 1, 2, 6, 24, 120, 720, 5040.
Elgar recorded the total amount of money he had saved at the end of each month.
Elgar should expect to have saved approximately $290 after 10 months.
How to determine the line of best?In this scenario, the month would be plotted on the x-axis (x-coordinate) of the scatter plot while the amount saved would be plotted on the y-axis (y-coordinate) of the scatter plot through the use of Microsoft Excel.
On the Microsoft Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display a linear equation for the line of best fit (trend line) on the scatter plot.
From the scatter plot (see attachment) which models the relationship between the month and amount saved, a linear equation for the line of best fit is given by:
y = 29.48x - 5.26
When x = 10 months, the earnings is given by;
y = 29.48(10) - 5.26
y = 294.8 - 5.26
y = $289.54 ≈ $290
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The temperature of a chemical solution is originally 21∘C. A chemist heats the solution at a constant rate, and the temperature of the solution is75∘C after 12 minutes of heating. The temperature, T, of the solution ∘C is a function of x, the heating time in minutes.
Required function is T(x) = 4.5x + 21 where T is the temperature in degrees Celsius, and x is the heating time in minutes.
What is function?
A function is a mathematical concept that describes a relationship between two sets of values, called the input and output, where each input value maps to a unique output value. In other words, a function takes one or more inputs and produces an output based on a set of rules or operations.
We can start by using the formula for linear functions,
y = mx + b
where y is the dependent variable (in this case, the temperature of the solution), x is the independent variable (heating time in minutes), m is the slope of the line, and b is the y-intercept.
To find the slope, we can use the formula:
[tex]m = \frac{ (y_2 - y_1) }{ (x_2 - x_1)}[/tex]
where [tex](x_1, y_1) = (0, 21)[/tex] (the starting temperature and time), and [tex](x_2, y_2) = (12, 75)[/tex] (the temperature and time after 12 minutes of heating).
m = (75 - 21) / (12 - 0)
m = 54 / 12
m = 4.5
So the slope of the line is 4.5.
To find the y-intercept, we can use the formula b = y - mx
Using the point (0, 21),
b = 21 - 4.5(0)
b = 21
So, the y-intercept is 21.
Putting it all together, the function that gives the temperature of the solution as a function of time is T(x) = 4.5x + 21
where T is the temperature in degrees Celsius, and x is the heating time in minutes.
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Correct question is "The temperature of a chemical solution is originally 21∘C. A chemist heats the solution at a constant rate, and the temperature of the solution is75∘C after 12 minutes of heating. The temperature, T, of the solution ∘C is a function of x, the heating time in minutes.Find the function."
Required function is T(x) = 4.5x + 21 where T is the temperature in degrees Celsius, and x is the heating time in minutes.
What is function?
A function is a mathematical concept that describes a relationship between two sets of values, called the input and output, where each input value maps to a unique output value. In other words, a function takes one or more inputs and produces an output based on a set of rules or operations.
We can start by using the formula for linear functions,
y = mx + b
where y is the dependent variable (in this case, the temperature of the solution), x is the independent variable (heating time in minutes), m is the slope of the line, and b is the y-intercept.
To find the slope, we can use the formula:
[tex]m = \frac{ (y_2 - y_1) }{ (x_2 - x_1)}[/tex]
where [tex](x_1, y_1) = (0, 21)[/tex] (the starting temperature and time), and [tex](x_2, y_2) = (12, 75)[/tex] (the temperature and time after 12 minutes of heating).
m = (75 - 21) / (12 - 0)
m = 54 / 12
m = 4.5
So the slope of the line is 4.5.
To find the y-intercept, we can use the formula b = y - mx
Using the point (0, 21),
b = 21 - 4.5(0)
b = 21
So, the y-intercept is 21.
Putting it all together, the function that gives the temperature of the solution as a function of time is T(x) = 4.5x + 21
where T is the temperature in degrees Celsius, and x is the heating time in minutes.
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Correct question is "The temperature of a chemical solution is originally 21∘C. A chemist heats the solution at a constant rate, and the temperature of the solution is75∘C after 12 minutes of heating. The temperature, T, of the solution ∘C is a function of x, the heating time in minutes.Find the function."
A: y-4=-3(x+2)
B: y= -3/2x+1
C: y-1=-3x
D: 3x+y=1
The equation of the line given in the graph will be:
2y = -3x +2
Given line is passing through the point (2, -2), with the y-intersect of 1(From the graph).
The slope-intercept form of the equation of a line,
y=mx+b,
where m is the slope
b is the y-intercept
since, slope = (y - y')/(x -x')
In our case,
m = (-2-1)/(2-0)
m = -3/2
Thus, the equation of the line will be
y = -3/2x + 1
2y = -3x +2
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A ball is thrown into the air with an initial velocity of 30 ft/sec. This situation is modeled by h=-16t^2+30t+6. Will it reach the top of a building with a roof height of 22 feet?
The height of the building roof is 22 feet, the ball will not reach the top of the building.
To determine whether the ball will reach the top of the building, we need to find the maximum height of the ball & see if it is greater than or equal to the height of the building roof
The equation h = -16t^2 + 30t + 6 represents the height of the ball (in feet) as a function of time (in seconds). To find the maximum height, we need to find the vertex of the parabolic function h.
The vertex of the parabolic function h = -16t^2 + 30t + 6 can be found using the formula:-
t = -b/2a
where a = -16, b = 30, & c = 6.
So, t = -30/(2*(-16)) = 0.9375 seconds.
To find the maximum height, we need to substitute this value of t into the equation h = -16t^2 + 30t + 6:-
h = -16(0.9375)^2 + 30(0.9375) + 6
h = 18.5625 feet
Therefore, the maximum height of the ball is 18.5625 feet
Since the height of the building roof is 22 feet, the ball will not reach the top of the building.
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Given, that x = and x = 3 are two zeros of the polynomial below, find the remaining complex zeros using detailed steps, and then sketch a neat graph of the polynomial labeling the intercepts. f(x) = 2x* – 9x3 + 17x2 – 19x - 15
The zeros of the polynomial are: , 3, and -23/2. Therefore, the y-intercept is (0, -15).
From the given information, we know that x= and x=3 are two zeros of the polynomial f(x) = 2x³ – 9x² + 17x – 19x – 15.
To find the remaining complex zeros, we can use polynomial long division or synthetic division. However, we first need to use the two zeros to factor the polynomial.
We can start by writing the polynomial in factored form as:
f(x) = (x - )(x - 3)(ax + b)
where (ax + b) represents the remaining factor.
To find the values of a and b, we can expand the above expression and compare the coefficients with the original polynomial:
f(x) = (x - )(x - 3)(ax + b)
= (ax² + bx - 3ax - 3b)x + (3abx - ab)
= (a)x³ + (b - 3a)x² + (3a - b)x - 3b
Comparing coefficients with the given polynomial, we get:
a = 2
b - 3a = 17
3a - b = -19
-3b = -15
Solving for these equations, we get:
a = 2
b = 23
Therefore, the remaining factor is (2x + 23).
Thus, the complete factorization of the polynomial is:
f(x) = (x - )(x - 3)(2x + 23)
Now, we can find the zeros of the polynomial by setting each factor equal to zero:
x - = 0 => x =
x - 3 = 0 => x = 3
2x + 23 = 0 => x = -23/2
Hence, the zeros of the polynomial are: , 3, and -23/2.
To sketch the graph of the polynomial, we can plot the x-intercepts (, 3, and -23/2) on the x-axis and the y-intercept (which we can find by setting x = 0) on the y-axis.
When x = 0, we get:
f(0) = 2(0)³ - 9(0)² + 17(0) - 19(0) - 15
= -15
Therefore, the y-intercept is (0, -15).
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Taner and Jaylen are practicing for a track meet. Last week, Taner ran 900 meters on each of 3 days. Jaylen ran 1.2 kilometers on each of 2 days. Which boy ran farther last week and by how much?
Okay, here are the steps to solve this problem:
* Taner ran 900 meters on each of 3 days. So in total Taner ran 900 * 3 = 2700 meters.
* Jaylen ran 1.2 kilometers on each of 2 days. So 1.2 km = 1200 meters. And 1200 * 2 = 2400 meters.
So in total:
Taner ran 2700 meters
Jaylen ran 2400 meters
Taner ran 2700 - 2400 = 300 more meters than Jaylen last week.
Therefore, Taner ran farther last week, by 300 meters.
if lim x → 2 f ( x ) = 7 , then f ( x ) must be continuous at x = 2 . True or False
Answer:
False
Step-by-step explanation:
[tex]f(x) = \frac{(x + 5)(x - 2)}{x - 2} = \frac{ {x}^{2} + 3x - 10 }{x - 2} [/tex]
This function is not continuous when
x = 2, but as x approaches 2, f(x) approaches 7.
Tara's heart rate during a workout is modeled by the differentiable function h, where h(t) is measured in beats per minute and f is measured in minutes from the start of the workout. Which of the following expressions gives Tara's average heart rate from ( = 30 to t = 60 ? ) O A. h'(30) + h'(60) 2 O B. 1 60 30 30 h(t) dt O C. 1 60 30 J30 h'(t) dt O D. [ h(1) dt
Tara's average heart rate from C. 1/30 ∫[30 to 60] h'(t) dt during the interval [30, 60] .
What is an average?Average, also known as mean, is a measure of central tendency that represents the sum of a set of values divided by the number of values in the set. It is commonly used to represent the "typical" or "average" value in a set of data.
What is an interval?An interval refers to a range of values that lies between two endpoints. It represents a continuous set of values that falls within a specified range or interval. An interval can be either open or closed, depending on whether or not the endpoints are included in the set of values.
According to the given information:
The average rate of change of a function over an interval [a, b] is given by the integral of the derivative of the function over that interval divided by the length of the interval (b - a).
In this case, Tara's average heart rate from t = 30 to t = 60 is represented by the integral of the derivative of her heart rate function h(t) with respect to t, denoted as h'(t), over the interval [30, 60], divided by the length of the interval, which is 60 - 30 = 30.
So, the correct expression for Tara's average heart rate during the interval [30, 60] is 1/30 ∫[30 to 60] h'(t) dt.
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explain the purpose of paired data. in certain situations, what might be the advantage of using paired samples rather than independent ones?
Paired data refers to a type of data analysis where two sets of data are paired together based on some criteria or characteristic.
This can be done to compare the differences between the two sets of data, which can provide valuable insights and information for a variety of research and analysis purposes.Learn more about the paired sample and independent sample with and example: https://brainly.com/question/22785008
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Calculating the vector normal to a plane.Three points in a 3D space define a plane. A vector perpendicular to any vector lying in that plane is called a normal vector.Assign planeNormal with the normal vector to the plane defined by the point1, point2, and point3. To find the normal vector,A vector lying in the plane is found by subtracting the first point's coordinates from the second point.A second vector lying in the plane is found by subtracting the first point's coordinates from the third point.The normal vector is found by calculating the cross product of two vectors lying in the plane.Ex: If point1, point2, and point3 are [ 0, 0, 1 ], [ 2, 2, 3 ], and [ 0, 3, 1 ], respectively, then planeNormal is [ -6, 0, 6 ].function planeNormal = getPlaneNormal (point1, point2, point3)% Calculate first vector in plane by subtracting the first point's coordinates from the second pointinPlaneVec1 = point2- point1;%Calculate second vector in plane by subtracting the first point's coordinates from the third pointinPlaneVec2 = [0,0,0]; %FIXME%Calculate vector normal to the plane by calculating the cross product of the two vectors lying in the planeplaneNormal= [0,0,0]; %FIXMEend
Answer:
Here is the corrected code to find the normal vector to a plane defined by three points:
function planeNormal = getPlaneNormal(point1, point2, point3)
% Calculate first vector in plane by subtracting the first point's coordinates from the second point
inPlaneVec1 = point2 - point1;
% Calculate second vector in plane by subtracting the first point's coordinates from the third point
inPlaneVec2 = point3 - point1;
% Calculate vector normal to the plane by calculating the cross product of the two vectors lying in the plane
planeNormal = cross(inPlaneVec1, inPlaneVec2);
end
In this code, the cross product of the two vectors lying in the plane (inPlaneVec1 and inPlaneVec2) is calculated using the cross function in MATLAB. The resulting vector is the normal vector to the plane, which is returned as the output of the function.
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What is the angle 0 in the triangle below?
The measure of angle θ from the given right triangle is 65 degree.
In the given right triangle the legs of triangle are 9 units and 4.2 units.
We know that, tanθ = Opposite/Adjacent
tanθ = 9/4.2
tanθ = 2.14
θ = 64.98
θ ≈ 65°
Therefore, the measure of angle θ from the given right triangle is 65 degree.
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Consider the equation y – 4 = 2(xConsider the equation y – 4 = 2(x + 3)2. Where is the vertex located, and in which direction does the parabola open? + 3)2. Where is the vertex Consider the equation y – 4 = 2(x + 3)2. Where is the vertex located, and in which direction does the parabola open?located, and in which direction does the parabola open?
The vertex form tells us that the parabola opens upwards and its vertex is located at (-3, 4).
What is parabola?A parabola is a symmetrical U-shaped curve that is formed by the intersection of a plane parallel to the axis of a circular conical surface and a plane that cuts the cone.
According to given information:The equation [tex]y - 4 = 2(x + 3)^2[/tex] is in vertex form, which is given by:
[tex]y - k = a(x - h)^2[/tex]
where (h, k) is the vertex of the parabola and "a" determines whether the parabola opens upwards or downwards.
Comparing the given equation to the vertex form, we can see that the vertex is located at (-3, 4), which means that the parabola is shifted 3 units to the left and 4 units up from the origin (0, 0).
The coefficient "a" is positive, which means that the parabola opens upwards. This can also be determined by noticing that the coefficient of the squared term (2) is positive. Therefore, the vertex form tells us that the parabola opens upwards and its vertex is located at (-3, 4).
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24. use a trigonnometric function to find the value of x. round to the nearest tenth if necessary.
The value of x using a trigonometric function, specifically the sine function, we can use the formula x = hypotenuse × sin(θ), where θ is the given angle and hypotenuse is the length of the hypotenuse in the right triangle.
Step 1: Identify the given information:
The problem likely provides an angle and a side length in a right triangle. Let's assume we have an angle θ and the opposite side length x.
Step 2: Choose the appropriate trigonometric function:
Since we have the opposite side length and we want to find the value of x, we can use the sine function, which is defined as the ratio of the opposite side to the hypotenuse. The formula for sine is: sin(θ) = opposite/hypotenuse.
Step 3: Substitute the given values:
We can substitute the given value of x for the opposite side length in the sine function: sin(θ) = x/hypotenuse.
Step 4: Solve for x:
If we know the value of the angle θ and the hypotenuse, we can rearrange the formula to solve for x. Multiply both sides by the hypotenuse to isolate x: x = hypotenuse × sin(θ).
Step 5: Round to the nearest tenth if necessary:
If the problem requires rounding, we can round the value of x to the nearest tenth using standard rounding rules.
Therefore, to find the value of x using a trigonometric function, specifically the sine function, we can use the formula x = hypotenuse × sin(θ), where θ is the given angle and hypotenuse is the length of the hypotenuse in the right triangle. We can then round the result to the nearest tenth if necessary.
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In Problems 13–20, use the Laplace transform table and the linearity of the Laplace transform to determine the following transforms.13. L{6e-31 - 2 + 21-8}
The laplace transform is [tex]L{6e^(-3t) - 2 + 2(t^(-8))} = 6/(s+3) - 2/s + 2(5040)/(s^8)[/tex] for the given function
We will use the Laplace transform table and the linearity property of the Laplace transform to find the Laplace transform of the given function:
Function: [tex]6e^(-3t) - 2 + 2(t^(-8))[/tex]
Recall the linearity property:[tex]L{a*f(t) + b*g(t)} = a*L{f(t)} + b*L{g(t)}[/tex]
Applying this property, we can split the given function into three parts and find their Laplace transforms separately:
1. L{6e^(-3t)}
2. L{-2}
3. L{2(t^(-8))}
Now, we'll use the Laplace transform table to find the Laplace transforms of these functions:
1. [tex]L{6e^(-3t)} = 6 * L{e^(-3t)} = 6/(s+3)[/tex] [Using the table:[tex]L{e^(-at)} = 1/(s+a)][/tex]
2. [tex]L{-2} = -2 * L{1} = -2/s[/tex] [Using the table: [tex]L{1} = 1/s][/tex]
3. [tex]L{2(t^(-8))} = 2 * L{t^(-8)} = 2 * (-7!)/(s^8)[/tex] [Using the table: [tex]L{t^(n-1)} = (n-1)!/s^n[/tex], where n is a positive integer]
Now, combine these Laplace transforms using the linearity property:
[tex]L{6e^(-3t) - 2 + 2(t^(-8))} = 6/(s+3) - 2/s + 2*(-7!)/(s^8)[/tex]
So, the final answer is:
[tex]L{6e^(-3t) - 2 + 2(t^(-8))} = 6/(s+3) - 2/s + 2(5040)/(s^8)[/tex]
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Determine the boundedness and monotonicity of the sequence with a_n = (0.35)^n|. a) decreasing: bounded below by 0 and above by 0.35. b) increasing: bounded below by 0 and above by 0.35. c) decreasing: bounded below by 1 and above by 0.35. d) nonincreasing, bounded below by 0 and above by 0.35. e) nondecreasing: bounded below by 1 and above by 0.35
The boundedness and monotonicity of the sequence with a_n = (0.35)^n|. a) decreasing: bounded below by 0 and above by 0.35.
The given sequence is a_n = (0.35)^n. To determine its boundedness and monotonicity, let's analyze the terms and their progression.
Boundedness:
Since 0 < 0.35 < 1, raising 0.35 to increase powers will result in terms that are smaller than the previous term but always greater than 0. Thus, the sequence is bounded below by 0. The first term of the sequence is (0.35)^1 = 0.35, and all subsequent terms are smaller. Therefore, the sequence is also bounded above by 0.35.
Monotonicity:
As we established, each term in the sequence is smaller than the previous one, as we are multiplying by a factor between 0 and 1. This means that the sequence is decreasing.
Putting these two findings together, the correct answer is:
a) decreasing: bounded below by 0 and above by 0.35.
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150 litres of water are poured into a cylindrical drum of diameter 48 cm.Find the depth of the water in the drum
Answer:
82.89 cm to the nearest hundredth.
Step-by-step explanation:
Volume = πr^2h where r = radius, h = height of the water.
r = 1/2 * 48 = 24 cm and the volume = 150 * 100 = 150,000cm^3 (as there are 1000 cm^3 in 1 litre).
So, substituting, we have:
150000 = π*24^2*h
h = 150000/π*24^2
= 82.893 cm
To avoid the problem of not having access to Tables of F distribution when F values are needed for the lower tail, the numerator of the test statistic for a two-tailed test should be the one with - the larger sample variance. - the smaller sample size. - the larger sample size. - the smaller sample variance.
To avoid the problem of not having access to Tables of F distribution when F values are needed for the lower tail, the numerator of the test statistic for a two-tailed test should be the one with the larger sample variance.
This is because the F-distribution is asymmetric and it is easier to find the F-value for the larger sample variance in the upper tail and then use the complement rule to find the F-value for the smaller sample variance in the lower tail. Sample size does not affect which numerator should be used in a two-tailed test.
To avoid the problem of not having access to Tables of F distribution when F values are needed for the lower tail, the numerator of the test statistic for a two-tailed test should be the one with the larger sample variance. This approach ensures that the F value is greater than 1, making it easier to find in the F distribution table.
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How Many 10-Bit Strings Begin With "101" Or "00"? O 27+28 O 27.28 O 210+210 O 210.210
The number of 10-bit strings that begin with "101" can be calculated as follows: there is only one option for the first three bits ("101"), and for each of the remaining 7 bits, there are two options (0 or 1). Therefore, the number of 10-bit strings that begin with "101" is 1 x 2^7 = 128.
Similarly, the number of 10-bit strings that begin with "00" can be calculated as follows: there is only one option for the first two bits ("00"), and for each of the remaining 8 bits, there are two options (0 or 1). Therefore, the number of 10-bit strings that begin with "00" is 1 x 2^8 = 256.
However, we need to be careful not to double count the strings that begin with "10100", so we need to subtract that from our total count. The number of 10-bit strings that begin with "10100" is 1 x 1 x 2^5 = 32.
Therefore, the total number of 10-bit strings that begin with "101" or "00" is 128 + 256 - 32 = 352.
So the correct answer is O 352.
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