find two consecutive odd integers such as that 6 times the lesser integer is 7 more than 5 times the greater integer​

Answers

Answer 1

Answer:

The first consecutive integer is 17 while the second is 19

Step-by-step explanation:

Let us say that the first odd integer is x

At this point, the second odd integer will be x+2.

This is because to obtain the next consecutive odd integer, 2 will have to be added to the original number.

From the question, we can set up an equation as shown below:

[tex]6x= 7+5(x+2)[/tex]

from this, we can simply evaluate and find out the value of x

[tex]6x=7 +5x +10\\x=17[/tex]

therefore, the first consecutive integer is 17 while the second is 19


Related Questions

what is 12.3 -(-9.6) =12.3 + 9.6 simplified?

Answers

Answer:

Step-by-step explanation:

12.3 + 9.6 = 21.9

The expression 12.3 - (-9.6) is equivalent to 21.9.

Given is an expression 12.3 -(-9.6) = 12.3 + 9.6, we need to simplify it,

To simplify the expression 12.3 - (-9.6), we can rewrite it as 12.3 + 9.6.

When subtracting a negative number, it is equivalent to adding the positive value of that number.

So, -(-9.6) becomes +9.6.

Therefore, 12.3 - (-9.6) simplifies to 12.3 + 9.6.

Adding 12.3 and 9.6 gives us 21.9.

So, 12.3 - (-9.6) = 21.9.

Learn more about expression click;

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salesperson receives 16.7% commission. If her total sales for the month are $4900, what is her commission?

Answers

Answer:

$818,3

Step-by-step explanation:

16.7% in decimal is 0.167

= 0.167 x $4900

= $818,3

please help me out with this ​

Answers

Answer:

up is equal to 5/ 6

left side is equal to 3/4

Step-by-step explanation:

1/6 + 1/6+ 1/6+ 1/6+ 1/6= 5/6

1/4 + 1/4 + 1/4= 3/4

Evaluate the integral by interpreting it in terms of areas. integral -3 to 0(1+(9-x^2)^1/2)dx

Answers

Answer:

[tex]\int\limits^0_{-3}(1+\sqrt{9-x^{2}})\, dx=3+\frac{9\pi}{4}=10.068[/tex]

Step-by-step explanation:

We need to evaluate the following integral by interpreting it in terms of areas :

[tex]\int\limits^0_{-3}(1+\sqrt{9-x^{2}})\, dx[/tex]

The first step is to separate the integral into two easier integrals

[tex]\int\limits^0_{-3}(1+\sqrt{9-x^{2}})\, dx=\int\limits^0_{-3} 1 \, dx+\int\limits^0_{-3}\sqrt{9-x^{2}}\, dx[/tex]    (Integral of the sum)

Now we can calculate each integral by studying the area below each function.

For the first integral the function is [tex]f(x)=1[/tex]

(I will attach a file with the functions)

The area below this function is the area of a rectangle with sides 1 and 3 ⇒

[tex]\int\limits^0_{-3}1 \, dx=3[/tex]

For the second integral the function is

[tex]f(x)=y=\sqrt{9-x^{2}}[/tex]

If we study this function :

[tex]y=\sqrt{9-x^{2}}[/tex]

[tex]y^{2}=9-x^{2}[/tex] (I)

[tex]x^{2}+y^{2}=9[/tex]

Which is the equation of a circle centered at (0,0) with radius equal to 3

From the equation (I)

[tex]y^{2}=9-x^{2}[/tex]

[tex]|y|=\sqrt{9-x^{2} }[/tex]

The two possible solutions are :

[tex]y=\sqrt{9-x^{2}}[/tex] (II) and [tex]y=-\sqrt{9-x^{2}}[/tex]

We will use (II) to solve the integral (which is the upper part of the circle)

The area of a circle with radius equal to 3 is

[tex]\pi.3^{2}[/tex]

In the integral we only need a quarter of circle ⇒ We divide the total area by 4 ⇒ [tex]\frac{\pi.3^{2}}{4}[/tex] ⇒ [tex]\frac{9\pi }{4}[/tex]

Finally the integral is equal to

[tex]\int\limits^0_{-3}(1+\sqrt{9-x^{2}})\, dx=3+\frac{9\pi}{4}=10.068[/tex]

which of the following verifies that triangle YXZ is similar to triangle QPR?

Answers

Answer:

AA postulate

Step-by-step explanation:

Because both the angle are identical?

what five parts make up a data table

Answers

Answer:

Step-by-step explanation:

Check boxes.

Sorting (on columns)

Icons that communicate alerts.

Pagination.

Headers Row.

please help me with this problem​

Answers

Answer:

A) sin 70 = x/10

Step-by-step explanation:

From the angle 70 degrees, 10 is the hypotenuse and x is the opposite and if we go by SOH-CAH-TOA I have an O and a H so its sin.

so we know it's sin so we need to figure out the equation. since we have a hypotenuse as a factor it is on top. and the other number is on the bottom.

so,

A) sin 70 = x/10

Write an equation in slope-intercept form (y = mx + b).

Perpendicular to 7x - 2y = 16 passing through (-7, 5).

Answers

Answer:

y = 2/7x + 7

Step-by-step explanation:

We start off by putting the original equation into slope-intercept form. Subtract 7x from both sides, then divide both sides by -2. Your new equation should be y = -7/2x - 8. It's important to know that when two lines are perpendicular, their slopes (m) are opposite reciprocals of each other.  So -7/2 becomes 2/7. The first part of your final equation is y = 2/7x + b.

Next, we need to find the y intercept (b). You need to plug the x and y values from the given coordinate point (-7,5) into your final equation. You should end up with: 5 = 2/7(-7) + b. Then, solve for b.

5 = -14/7 + b

5 = -2 + b

7 = b

Finally, plug the b value into your final equation and you will have your answer.

please help Spotting Axis Intercepts

Answers

Answer:

Coordinate A ins not intercepting any axis.

Step-by-step explanation:

For a coordinate to intercept an axis, it will be in the form [tex](a, b)\ such\ that:\ a=0, b \in \mathbb{R},\ or:a\in \mathbb{R}, b=0.[/tex]

Since in (3, 6), none of the components are 0, it is not intercepting any axes.

Which answer describes the type of numbers that are dense? whole numbers and integers whole numbers but not integers rational numbers and irrational numbers rational numbers but not irrational numbers

Answers

Answer:

rational numbers and irrational numbers

Step-by-step explanation:

ILL GIVE YOU BRAINLIST !!!

Evaluate the expression given the replacement values.

Answers

Answer:

24

Step-by-step explanation:

[tex]a^{2}[/tex]= 49 because any number squared is positive.

Since b=2,

2(-4)= -8.

Then this is 49-8-17, which equals 24.

Answer:

24

Step-by-step explanation:

A bakery wants to determine the best placement for day-old goods. What type of data collection source do you think the bakery should use? Choose the correct answer below. A. The bakery should conduct an experiment. B. The bakery should collect information from operational or transactional systems. C. The bakery should conduct an observational study. D. The bakery should obtain information that was distributed by an organization or individual. E. The bakery should conduct a survey

Answers

Answer: C. The bakery should conduct an observational study

Step-by-step explanation:

From the question, we are informed that a bakery wants to determine the best placement for day-old goods. The type of data collection source that the bakery should use is an observational study.

An observational study is a form of study whereby the individuals who are to be observed are being studied by the researcher and certain conclusions are derived about them. When the bakery conductd an observational study, the behavior of the customers regarding goods placement can be observed.

Solve for b: 15 - 2b = -9
pleasee help:(

Answers

Answer:

b = 12

Step-by-step explanation:

15 - 2b = -9

Minus 15 to both sides

-2b = -24

Divide both sides by -2

b = 12

Please help 4+(-10)-(-9)

Answers

Answer:

-15

Step-by-step explanation:

-10+-9=-19+4=-15

The answer is 3 if you need me to tell you how (text back)

drag each statement to show it true,based on the graph.

Answers

Answer:

1). Cinnamon costs $7 per one pound

2). Price per pound of the cinnamon equals $[tex]\frac{5.25}{0.75}[/tex].

Step-by-step explanation:

x-values on the graph define the weight of cinnamon and y-values define the price.

Slope of the line drawn from the origin (0, 0) and (0.75, 5.25) will determine the per lb price of the cinnamon.

Slope of a line passing through two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] will be,

Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

If the points on the given line re (0,0) and (0.75, 5.25),

Slope = [tex]\frac{5.25-0}{0.75-0}[/tex]

          = 7

Therefore, two options are the correct options.

1). Cinnamon costs $7 per one pound

2). Price per pound of the cinnamon equals $[tex]\frac{5.25}{0.75}[/tex].

Algebra 1A, I need help

Answers

Answer:

for the first question at the top, x=10

Step-by-step explanation:

x+3+9x=8x+23

(subtract 8x from both sides)

x+3+x=23

(combine the x terms)

2x+3=23

(subtract 3 from both sides)

2x=20

(divide by 2 from each side)

x=10

Israel started to solve a radical equation in this way:

square root of x plus 6 − 4 = x
square root of x plus 6 − 4 + 4 = x + 4
square root of x plus 6 = x + 4
(square root of x plus 6)2 = (x + 4)2
x + 6 = x2 + 8x + 16
x + 6 − 6 = x2 + 8x + 16 − 6
x = x2 + 8x + 10
x − x = x2 + 8x + 10 − x
0 = x2 + 7x + 10
0 = (x + 2)(x + 5)

x + 2 = 0 x + 5 = 0
x + 2 − 2 = 0 − 2 x + 5 − 5 = 0 − 5
x = −2 x = −5

Solutions = −2, −5

What error did Israel make?

He subtracted 6 before subtracting x.
He added 4 before squaring both sides.
He factored x2 + 7x + 10 incorrectly.
He did not check for extraneous solutions.

Answers

Answer:

He did not check for extraneous solutions.

Step-by-step explanation:

He solved the equation correctly and obtained solutions -2 and -5, but there is one final step he did not do.

Every time you square both sides of an equation to solve it, you must check for extraneous solutions. If he did, he would have eliminated x = -5.

Answer: He did not check for extraneous solutions.

Thrice the product of two and "Y".

Answers

Answer:

6Y

Step-by-step explanation:

We need to solve the statement ' Thrice the product of two and "Y" '.

Thrice means 3 times and product means multiply. It means we have to multiply 3,2 and Y.

Let the result is R. It can be calculated as follows :

[tex]R=3\times 2\times Y[/tex]

We know that, 3×2 = 6

So,

[tex]R=6Y[/tex]

Hence, Thrice the product of two and "Y" is 6Y.

When three professors are seated in a restaurant, the hostess asks them: "Does everyone want coffee?" The first professor says: "I do not know." The second professor then says: "I do not know." Finally, the third professor says: "No, not everyone wants coffee."
The hostess comes back and gives coffee to the professors who want it. How did she figure out who wanted coffee?

Answers

the first two professors did not know if everyone wanted coffee because the third professor had to choose yes or no if he wanted coffee. the first two professors were waiting for the third to say something, and when he said no, they knew he did not want coffee. if one of the first two professors said no, the answer would be no.

Find an equation of the sphere with center (-3, 2 , 5) and radius 4. What is the intersection of this sphere with the yz-plane.

Answers

Answer:

The equation of the sphere with center (-3, 2 , 5) and radius 4 is [tex](x+3)^{2} +(y-2)^{2} + (z-5)^{2} = 16[/tex]

The intersection of the sphere with the yz- plane gave the equation [tex](y-2)^{2} + (z-5)^{2} = 7[/tex] which is a 2D- circle with center (0,2,5) and radius [tex]\sqrt{7}[/tex].

Step-by-step explanation:

The equation of a sphere of radius r, with center (a,b,c) is given by

[tex](x-a)^{2} +(y-b)^{2} + (z-c)^{2} = r^{2}[/tex]

where, [tex]x,[/tex] [tex]y,[/tex] and [tex]z[/tex] are the coordinates of the points on the surface of the sphere.

Hence, the equation of the sphere with center,  (-3, 2 , 5) and radius 4 becomes

[tex](x-a)^{2} +(y-b)^{2} + (z-c)^{2} = r^{2}[/tex]

[tex](x-(-3))^{2} +(y-(2))^{2} + (z-(5))^{2} = 4^{2}[/tex]

Then,

[tex](x+3)^{2} +(y-2)^{2} + (z-5)^{2} = 16[/tex]

This is the equation of the sphere with center (-3, 2 , 5) and radius 4,

Now, for the intersection of this sphere with the yz- plane,

The [tex]yz -[/tex]plane is where [tex]x = 0[/tex], then we set [tex]x = 0[/tex]

Them the equation [tex](x+3)^{2} +(y-2)^{2} + (z-5)^{2} = 16[/tex] becomes

[tex](0+3)^{2} +(y-2)^{2} + (z-5)^{2} = 16[/tex]

[tex](3)^{2} +(y-2)^{2} + (z-5)^{2} = 16\\9 +(y-2)^{2} + (z-5)^{2} = 16\\(y-2)^{2} + (z-5)^{2} = 16 - 9\\(y-2)^{2} + (z-5)^{2} = 7[/tex]

This equation is the equation of a 2D- circle with center (0,2,5) and radius [tex]\sqrt{7}[/tex]

This is the part of the sphere that intersects with the yz-plane.

Find an equation of the plane.
The plane through the point (1, -1, - 1 ) and parallel to the plane 5x - y - z = 6

Answers

Answer: equation of the plane is 5x - y - z - 7 = 0  

same as ( 5x - y - z = 7 )

Step-by-step explanation:

Given data;

5x - y - z = 6

therefore vector of plane is n° = ( 5, -1, -1)

so equation will be

n°(x-x₀, y-y₀, z-z₀) = 0

( 5, -1, -1) (x-x₀, y-y₀, z-z₀) = 0

5(x- (1)) -1(y - (-1)) -1(z - (-1)) = 0

5x - 5 - y - 1 - z - 1 = 0

5x - y - z - 7 = 0

Therefore equation of the plane is 5x - y - z - 7 = 0  

same as ( 5x - y - z = 7 )

Please hurry! Which expression is equivalent to 2 (5) Superscript 4? 2 times 5 times 4, 2 times 5 times 5 times 5 times 5, 2 times 4 times 4 times 4 times 4 times 4 ,10 times 10 times 10 times 10

Answers

Answer:

10 x 10 x 10 x 10.

Step-by-step explanation:

2(5)^4

10^4

Expanded form; 10*10*10*10.

Answer:

10 x 10 x 10 x 10

Step-by-step explanation:

the question can been seen in the picture

Answers

Answer:

(2)

Step-by-step explanation:

Help please if u can

Answers

Answer:

Negative infinity

Step-by-step explanation:

The line points down infinitely in the graph.

-4.5 x (-2)???????????????????????

Answers

Answer:

9

Step-by-step explanation:

-4.5 x (-2) is equal to 9

The product of -4 and d

Answers

Answer:

-4d

Step-by-step explanation:

The answer is -4d, hope this helped

Veronica has been wanting to learn to ice skate for years!
When the Glacier Zone Ice Rink opened, Veronica bought 12
ice-skating lessons during their grand-opening sale. Veronica
paid $305.40 in all. How much did each lesson cost?

Answers

Answer:

25.45 per lesson

Step-by-step explanation:

divide $305.40 by 12

A tortoise and a hare are competing in a 2000-meter race. The arrogant hare decides to let the tortoise have a 510-meter head start. When the start gun is fired the hare begins running at a constant speed of 8 meters per second and the tortoise begins crawling at a constant speed of 6 meters per second. -Let t represent the number of seconds that have elapsed since the start gun was fired. 1) Write an expression in terms of t that represents the hare's distance from the starting line (in meters) 2) Write an expression in terms of t that represents the tortoise's distance from the starting line (in meters) 3) Write an expression in terms of t that represents the number of meters the tortoise is ahead of the hare.

Answers

Answer:

1. 8t

2. 510 + 6t

3. 510 - 2t

Step-by-step explanation:

1. Since the hare moves at a speed of 8 metres per second, the distance it moves from the starting line is d = speed × time = 8t

2. Since the rabbit moves at a speed of 6 metres per second, and gets a head start of 510 metres, the distance it moves from the starting line is d = 510 m + speed × time = 510 + 6t

3. The distance the tortoise is ahead of the hare is thus, distance moved by rabbit - distance moved by hare in time, t.

d' = 510 + 6t - 8t

= 510 - 2t  

Find an equation of a plane through the point (3, 0, 2) which is orthogonal to the linex=?2+3t,y=2+4t,z=?1?3tin which the coefficient of x is 3.

Answers

Answer: 3x + 4y - 3z - 3 = 0

Step-by-step explanation:

with the given point (3, 0, 2), the plane is orthogonal to this line so it

has directional ratios (3, 4, -3)

therefore the given equation can be written as;

(x+2)/3 = (y-2)/4 = (z+1)/-3

so equation of the plane passing through point x1, y1 and z1 in the one point form is given as;

a(x-x1) + b(y - y1) + c(z -z1) = 0

abc represent the direction ratio

so we substitute

3(x-3) + 4(y-0) + (-3(z-2)) = 0

3x - 9 + 4y - 0 - 3z + 6 = 0

3x + 4y - 3z - 3 = 0

therefore the equation of the plane through the point is  3x + 4y - 3z - 3 = 0

Match the vocabulary to the correct operation

Answers

Product=Multiplication
Sum= Addition
Difference=Subtraction
Quotient=Division
Quantity=Parenthesis

Answer:

Step-by-step explanation:

Product—Multiplication

Sum— Addition

Difference—Subtraction

Quotient—Division

Quantity— Parenthesis

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