Find the velocity and rate of flow of water through a rectangular channel of 6m wide and 3m deep when it's running full. The channel is having a bed slope of 1 in 2000. Take Chezy's coefficient, C=55
Answers
Answer:
V = 1.5062 m/s
Explanation:
look to the photos
Related Questions
A lamp and a coffee maker are connected in parallel to the same 120-V source. Together, they use a total of 140 W of power. The resistance of the coffee maker is 300 Ohm. Find the resistance of the lamp.
Answers
Answer:
Resistance of the lamp (r) = 156.52 ohm (Approx.)
Explanation:
Given:
Total power p = 140 W
Resistance of the coffee maker = 300 Ohm
Voltage v = 120 V
Find:
Resistance of the lamp (r)
Computation:
We know that
p = v² / R
SO,
Total power p = [Voltage²/Resistance of the lamp (r)] + [Voltage²/Resistance of the coffee maker]
140 = [120² / r] + [120²/300]
140 = 120²[1/r + 1/300]
140 = 14,400 [1/r + 1/300]
Resistance of the lamp (r) = 156.52 ohm (Approx.)
Air is compressed by a 40-kW compressor from P1 to P2. The air temperature is maintained constant at 25°C during this process as a result of heat transfer to the surrounding medium at 20°C. Determine the rate of entropy change of the air. State the assumptions made in solving this problem
Answers
Answer:
the rate of entropy change of the air is -0.1342 kW/K
the assumptions made in solving this problem
- Air is an ideal gas.
- the process is isothermal ( internally reversible process ). the change in internal energy is 0.
- It is a steady flow process
- Potential and Kinetic energy changes are negligible.
Explanation:
Given the data in the question;
From the first law of thermodynamics;
dQ = dU + dW ------ let this be equation 1
where dQ is the heat transfer, dU is internal energy and dW is the work done.
from the question, the process is isothermal ( internally reversible process )
Thus, the change in internal energy is 0
dU = 0
given that; Air is compressed by a 40-kW compressor from P1 to P2
since it is compressed, dW = -40 kW
we substitute into equation 1
dQ = 0 + ( -40 kW )
dQ = -40 kW
Now, change in entropy of air is;
ΔS[tex]_{air[/tex] = dQ / T
given that T = 25 °C = ( 25 + 273.15 ) K = 298.15 K
so we substitute
ΔS[tex]_{air[/tex] = -40 kW / 298.15 K
ΔS[tex]_{air[/tex] = -0.13416 ≈ -0.1342 kW/K
Therefore, the rate of entropy change of the air is -0.1342 kW/K
the assumptions made in solving this problem
- Air is an ideal gas.
- the process is isothermal ( internally reversible process ). the change in internal energy is 0.
- It is a steady flow process
- Potential and Kinetic energy changes are negligible.
Peter B. is admitted to a local hospital emergency room (ER) suffering from an anxiety attack. He tells the ER physician that he is anxious about a job promotion for which he is being considered. Peter’s secretary is worried about him and asks her father, Dr. K., who is on the medical staff at the hospital, to go to the ER and see how Peter is doing. Dr. K., who is often in the ER, knows all the staff and they willingly give him Peter’s chart when he asks for it. Dr. K. calls his daughter to tell her that Peter is being treated for anxiety with an anti-depressant drug and will probably be discharged. She relays this encouraging message to Peter’s boss. Peter does not receive the promotion.
a. Will it be an easy matter for Peter to prove that the ER staff caused Peter to lose his promotion? Explain your answer.
b. What precautions can be taken to avoid giving confidential information to medical personnel who have no need to see it?
c. In your opinion, should a diagnosis of anxiety be a concern for an employer? Why or why not?
Answers
a.No it will be not an easy matter for Peter to prove that the Er staff caused peter to lose his promotion
Here's why?
1)The boss may think he might not able to stretch himself in emergency situations
2)He can think he can't handle normal pressure
b.What precautions can be taken to avoid giving confidential information to medical personnel who have no need to see it?
1)Peter should not let the medical personnel about his personal life
2)He might have not said extra information about his job promotion
3)Will it be easy matter for Peter to prove that the ER staff caused Peter to lose his promotion? Explain your answer
No, it will not be easy, Peter has to prove in one or in another situation that he can face the difficulties and be able to handle anxiety attacks in the future.
Hence above answers are suitable for the given situation
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Estimate the theoretical fracture strength of a brittle material if it is known that fracture occurs by the propagation of an elliptically shaped surface crack of length 0.25 mm (0.01 in) and tip radius of curvature of 1.2 x 10-3 mm (4.7 x 10-5 in.) when a stress of 1200 MPa (174,000 psi) is applied.
Answers
Answer:
the theoretical fracture strength of the brittle material is 5.02 × 10⁶ psi
Explanation:
Given the data in the question;
Length of surface crack α = 0.25 mm
tip radius ρ[tex]_t[/tex] = 1.2 × 10⁻³ mm
applied stress σ₀ = 1200 MPa
the theoretical fracture strength of a brittle material = ?
To determine the the theoretical fracture strength or maximum stress at crack tip, we use the following formula;
σ[tex]_m[/tex] = 2σ₀[tex]([/tex] α / ρ[tex]_t[/tex] [tex])^{\frac{1}{2}[/tex]
where α is the Length of surface crack,
ρ[tex]_t[/tex] is the tip radius,
and σ₀ is the applied stress.
so we substitute
σ[tex]_m[/tex] = (2 × 1200 MPa)[tex]([/tex] 0.25 mm / ( 1.2 × 10⁻³ mm ) [tex])^{\frac{1}{2}[/tex]
σ[tex]_m[/tex] = 2400 MPa × [tex]([/tex] 208.3333 [tex])^{\frac{1}{2}[/tex]
σ[tex]_m[/tex] = 2400 MPa × 14.43375
σ[tex]_m[/tex] = 34641 MPa
σ[tex]_m[/tex] = ( 34641 × 145 )psi
σ[tex]_m[/tex] = 5.02 × 10⁶ psi
Therefore, the theoretical fracture strength of the brittle material is 5.02 × 10⁶ psi
As an engineer which types of ethical issues or problem you can face in industrial environment.
Answers
Explanation:
Answer ⬇️
Social and ethical issues in engineering, ethical principles of engineering, professional code of ethics, some specific social problems in engineering practice: privacy and data protection, corruption, user orientation, digital divide, human rights, access to basic services.
➡️dhruv73143(⌐■-■)
True or false all workers who do class 1 asbestos work must be part of a medical surveillance program
Answers
Answer:
Yes
Explanation:
Answer:
true
Explanation:
hehehe
An article gave a scatter plot along with the least squares line of x = rainfall volume (m3) and y = runoff volume (m3) for a particular location. The accompanying values were read from the plot.
c) Calculate a point estimate of the true average runoff volume when rainfall volume is 51. (Round your answer to four decimal places.)
(d) Calculate a point estimate of the standard deviation . (Round your answer to two decimal places.)
(e) What proportion of the observed variation in runoff volume can be attributed to the simple linear regression relationship between runoff and rainfall? (Round your answer to four decimal places.)
x 6 12 14 16 23 30 40 52 55 67 72 81 96 112 127
y 4 10 13 14 15 25 27 48 38 46 53 72 82 99 100
Answers
Answer:
y = 0.834X - 1.58015
Slope = 0.8340 ; Intercept = - 1.5802
y = 40.9539
19.93
0.9765
Explanation:
X: Rainfall volume
6
12
14
16
23
30
40
52
55
67
72
81
96
112
127
Y : Runoff
4
10
13
14
15
25
27
48
38
46
53
72
82
99
100
The scatterplot shows a reasonable linear trend between the Rainfall volume and run off.
The estimated regression equation obtained using a linear regression calculator is :
y = 0.834X - 1.58015
y = Runoff ; x = Rainfall volume
Slope = 0.8340 ; Intercept = - 1.5802
Point estimate for Runoff, when, x = 51
y = 0.834X - 1.58015
y = 0.834(51) - 1.58015
y = 40.95385
y = 40.9539
d.)
Point estimate for standard deviation :
s = 5.145
σ = s * √n
σ = √15 * 5.145
= 19.93
e.)
r² = Coefficient of determination gives the proportion of explained variance in Runoff due to the regression line. From the model output, the r² value = 0.9765. Which means That about 97.65% Runoff is due to Rainfall volume.
Provide two programming examples in which multithreading provides better performance than a single-threaded solution. Provide one example where singlethreaded solution performs better than multi-threaded solution
Answers
Answer:
I dont kno
Explanation:
Im so sorry
Tech A says that some relays are equipped with a suppression diode in parallel with the winding. Tech B says that some relays are equipped with a resistor in parallel with the winding. Who is correct
Answers
Answer:
Both are correct.
Explanation:
Both the technician A and B are correct. Some relays are equipped with a suppression diode in parallel windings while some relays are equipped with resistors. This is due to different requirements of the electromagnetic objects. Some require resistors to stop the flow of current towards the magnet.
Consider the following example: The 28-day compressive strength should be 4,000 psi. The slump should be between 3 and 4 in. and the maximum aggregate size should not exceed 1 in. The coarse and fine aggregates in the storage bins are wet. The properties of the materials are as follows:________.
Cement : Type I, specific gravity = 3.15
Coarse Aggregate: Bulk specific gravity (SSD) = 2.70; absorption
capacity = 1.1%; dry-rodded unit weight = 105 lb./ft.3
surface moisture = 1%
Fine Aggregate: Bulk specific gravity (SSD) = 2.67; absorption
capacity = 1.3%; fineness modulus = 2.70;
surface moisture = 1.5%
Answers
A steel bar with a diameter of .875 inches and a length of 15.0 ft is axially loaded with a force of 21.6 kip. The modulus of elasticity of the steel is 29 *106 psi. Determine
Answers
Answer:
35.92 kpsi
Explanation:
Given data:
diameter of the steel bar d = 0.875 in
Area A = πd^2/4 = π(0.875)^2/4
length L = 15.0 ft
Load P = 21.6 kip
Modulus of elesticity E = 29×10^6 Psi
Assume we are asked to determine axial stress in the bar which is given as
[tex]\sigma = Load, P/ Area, A[/tex]
[tex]\sigma = 4P/\pi d^2[/tex]
substitute the value
[tex]\sigma = \frac{4\times 21.6}{\pi \times (0.875)^2} \\=35.92\ kpsi[/tex]
Analyze the rate of heat transfer through a wall of an industrial furnace which is constructed from 0.15-m-thick fireclay brick having a thermal conductivity of 1.7 W/m.K. Measurements made during steady state operation reveal temperatures of 1400 and 1150 K at the inner and outer surfaces, respectively. The wall dimension is 0.5 m by 1.2 m by side.
Answers
Answer:
1700 W
Explanation:
The heat transfer rate P = kA(T - T')/d where k = thermal conductivity of wall = 1.7 W/m-K, A = area of wall = 0.5 m × 1.2 m = 0.6 m², T = temperature of inner surface = 1400 K, T = temperature of outer surface = 1150 K and d = thickness of wall = 0.15 m
So, P = kA(T - T')/d
substituting the values of the variables into the equation, we have
P = 1.7 W/m-K × 0.6 m²(1400 K - 1150 K)/0.15 m
P = 1.7 W/m-K × 0.6 m² × 250 K/0.15 m
P = 255 Wm/0.15 m
P = 1700 W
So, the heat transfer rate through the wall is 1700 W
explain "columnar transposition" for the transposition ciphers using the following plaintext as an example:
abcd
efgh
ijkl
mnop
Answers
Answer:
wa 4tefaw gfawe f
Explanation:
so you do e Fse gaewr gware gfawe agfawe gwar g
Words and numbers can be
printed using many different
or type styles.
Answers
Appendix
Identify the transformation. Note: you can only submit this question once for marking. translation rotation shear projection none of the above
Answers
Answer:
The answer is "shear".
Explanation:
Every transformation could be shown by some kind of conventional matrix.
Its standard matrices of shape k here could be any real value enabling shear transformation to parallel to the y axis.
[tex]\left[\begin{array}{cc}1&0\\k&1\\\end{array}\right][/tex]
This coefficient matrix A is the standard matrix during transformation. With the use of a the transformation could be entered into T(x)=Ax
And standard transfer function is standard.
[tex]\left[\begin{array}{cc}1&0\\6&1\\\end{array}\right][/tex]
The matrix in the form of the shear matrix.
What is code in Arduino to turn led on and off
Answers
here's your answer..
7
Which wire can carry a higher current?
ered
tof
Select one:
A. AWG 6
B. AWG 18
C. AWG 12
D. AWG 24
Answers
Answer:
the wire that can carry much current is AWG 24
AWG 24 is the wire can carry a higher current. The diameter of the wire increases with decreasing gauge. The electrical resistance to the signals decreases with increasing wire diameter. Hence, option D is correct.
What is meant by high current?Any current above 10 mA has the potential to deliver an unpleasant to severe shock, while 200 mA and above is considered lethal. Despite the fact that currents above 200 mA might cause serious burns and unconsciousness, they usually do not cause death if the sufferer receives timely medical attention.
Higher voltage and lower current are frequently more effective combinations. The amount of current that a wire is rated to handle is frequently indicated by its capacity rating. People can use the same cable to drive a load twice as large by doubling the voltage and maintaining the same current.
Thus, option D is correct.
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Example 12: Write an algorithm and draw a flowchart to calculate
the factorial of a number(N). Verify your result by a trace table by
assuming N = 5.
Hint: The factorial of N is the product of numbers from 1 to N)
Answers
Answer:
An algotherum is a finite set of sequential instructions to accomplish a task where instructions are written in a simple English language
Para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al vacío. En el evaporador se elimina el agua necesaria para que el jugo salga con una concentración del 60% de peso de sólidos. Si se introducen al proceso 1000 kg/h de jugo diluido, calcule la cantidad de agua evaporada y de jugo concentrado saliente.
Answers
Answer:
Se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.
Explanation:
Dado que para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al vacío, y en el evaporador se elimina el agua necesaria para que el jugo salga con una concentración del 60% de peso de sólidos, si se introducen al proceso 1000 kg/h de jugo diluido, para calcular la cantidad de agua evaporada y de jugo concentrado saliente se debe realizar el siguiente cálculo;
1000 x 0.07 = 70
60 = 70
100 = X
100 x 70 / 60 = X
7000 / 60 = X
116.66 = X
Por lo tanto, se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.
A main cable in a large bridge is designed for a tensile force of 2,600,000 lb. The cable consists of 1470 parallel wires, each 0.16 in. in diameter. The wires are cold-drawn steel with an average ultimate strength of 230,000 psi. What factor of safety was used in the design of the cable
Answers
Answer:
the factor of safety was used in the design of the cable is 2.6146
Explanation:
Given the data in the question;
Load on the main capable [tex]P_{initial[/tex] = 2600000 lb
number of parallel wires n = 1470
Diameter d = 0.16 in
average ultimate strength [tex]S_{ultimate[/tex] = 230000 psi
First we calculate the Load acting on each cable;
[tex]P_{initial[/tex] = P × n
P = [tex]P_{initial[/tex] / n
we substitute
P = 2600000 lb / 1470
P = 1768.70748 lb
Next we determine the working stress acting in a member;
[tex]S_{working[/tex] = P/A
{ Area A = [tex]\frac{\pi }{4}[/tex]d² }
[tex]S_{working[/tex] = P / [tex]\frac{\pi }{4}[/tex]d²
we substitute
[tex]S_{working[/tex] = 1768.70748 / [tex]\frac{\pi }{4}[/tex](0.16)²
[tex]S_{working[/tex] = 1768.70748 / 0.02010619298
[tex]S_{working[/tex] = 87968.29 psi
Now we calculate the factor of safety F.S
F.S = [tex]S_{ultimate[/tex] / [tex]S_{working[/tex]
we substitute
F.S = 230000 psi / 87968.29 psi
F.S = 2.6145785 ≈ 2.6146
Therefore, the factor of safety was used in the design of the cable is 2.6146
A Si pin photodiode has an active light-receiving area of diameter 0.4 mm. When radiation of wavelength 700 nm (red light and intensity 0.1 mW cm^-2 is incident it generates a photocurrent of 56.6 nA. What is the responsivity (A W^-1) and quantum efficiency (QE) of the photodiode at 700 nm?
Answers
Answer:
Explanation:
here is your answer:
The responsivity will be 0.45 A / W. Then the quantum efficiency will be 80%.
How to calculate responsivity and quantum efficiency?A Si pin photodiode has an active light-receiving area of a diameter of 0.4 mm.
When radiation of wavelength 700 nm (red light and intensity 0.1 mW cm^-2 is incident it generates a photocurrent of 56.6 nA.
Diameter (d) = 0.4 mm = 0.04 cm
Then the area will be
Area (A) = π / 4 x d²
Area (A) = π / 4 x 0.04²
Area (A) = 1.26 x 10⁻³ square cm
Then the incident power will be
P₀ = intensity of light x area
P₀ = 1.26 x 10⁻³ x 0.1 x 10⁻³
P₀ = 0.126 x 10⁻⁶ μW
Then the responsivity will be
R = photocurrent / power
R = 56.6 x 10⁻⁹ / 0.126 x 10⁻⁶
R = 0.4492
R ≅ 0.45 A / W
Then the quantum efficiency will be
η = Rhc / qλ
h = plank constant
c = speed of light
q = charge of an electron
Then we have
η = 0.45 x 6.62 x 10⁻³⁴ x 3 x 10⁸ / 1.6 x 10⁻¹⁹ x 700 x 10⁻⁹
η = 0.7979
η = 0.8
η = 80%
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A rapid sand filter has a loading rate of 8.00 m/h, surface dimensions of , an effective filtration rate of 7.70 m/h, and a production efficiency of 96 percent. A complete filter cycle duration is 52 h and the filter is rinsed for 20 minutes at the start of each cycle
Required:
a. What flow rate (m3/s) does the filter handle during production?
b. What volume of water is needed for backwashing plus rinsing the filter in each filter cycle?
Answers
Answer: hello there is a Missing information below is the missing information
surface dimensions of 10m * 8m
answer :
a) 640 m^3/hr
b) 1334.66 m^3
Explanation:
a) Determine the flow rate ( m^3/s ) of the filter handle
Va = Q /A[tex]_{f}[/tex]
where ; Va = filtration rate ( 8.00 m/h ) , Q = flow rate of filter handle , A[tex]_{f}[/tex] = surface area ( 10 m * 8 m )
Q = 8 * ( 10m * 8m ) = 640 m^3 / hr
b) Determine the volume of water needed for backwashing plus rinsing the filter in each filter cycle
Лf = 0.96 ( production efficiency )
Vb + Vr = 0.04 Vf
∴ Vf = ( Vb + Vr ) / 0.04 ------ ( 1 )
next step ; determine the volume of filtered water making use of effective filtration rate
Ref = ( Vf - Vb - Vr ) / A[tex]_{f}[/tex]T[tex]_{c}[/tex]
therefore : Vb + Vr = Vf - ( 80 * 52 * 7.7 ) ---- ( 2 )
Input equation 1 into 2
Vb + Vr = ( ( Vb + Vr ) / 0.04 ) - 32032 ---- ( 3 )
Resolve equation 3
hence the Volume of water needed for Backwashing and rinsing the filter in each filter cycle
= 1334.66 m^3
What is the Code requirement for receptacles connected to circuits of different voltages and installed in one building
Answers
Answer:
National Electrical Code
Explanation:
The National Electrical Code (NEC) is the foundational code that establishes the minimum requirements for electrical installation work. The NEC protects individuals and properties from being discriminated against dangers associated with the use of electricity. For electrical installation work, local and state electrical standards and codes should be consulted in addition to the NEC.
Section 406.4 of the NEC refers to On the same premises, receptacles linked to circuits with distinct voltages frequencies, or kinds of current (AC or DE) must be designed in such a way that the attachment plugs utilized on these circuits cannot be interchanged.
A cylinder is internally pressurized to a pressure of 100 MPa. This causes tangential and axial stresses in the outer surface of 400 and 200 MPa, respectively. Make a Mohr circle representation of the stresses in the outer surface. What maximum normal and shear stresses are experienced by the outer surface?
Answers
Answer:
[tex]\mu_{max}=200Mpa[/tex]
Explanation:
From the question we are told that:
Internally pressurized [tex]P_i=100MPa[/tex]
Tangential Stress [tex]P_t=400mpa[/tex]
Axial stress [tex]P_a=200mpa[/tex]
Generally the equation for maximum normal and shear stresses are experienced by the outer surface is mathematically given by
[tex]\mu_{max}=|\frac{P_t-P_a}{2}|,|\frac{P_t}{2}|,|\frac{P_t}{2}|[/tex]
Therefore
[tex]\mu_{max}=|\frac{400-200}{2}|,|\frac{400}{2}|,|\frac{200}{2}|[/tex]
[tex]\mu_{max}=200Mpa[/tex]
Unit of rate of heat transfer
Answers
Answer:
The units on the rate of heat transfer are Joule/second, also known as a Watt.
Explanation:
Heat flow is calculated using the rock thermal conductivity multiplied by the temperature gradient. The standard units are mW/m2 = milli Watts per meter squared. Thus, think of a flat plane 1 meter by 1 meter and how much energy is transferred through that plane is the amount of heat flow.
hope it helps .
stay safe healthy and happy..The rate of heat transfer is measured in Joules per second, also known as Watts.
What is heat transfer?Heat transfer is a thermal engineering discipline that deals with the generation, use, conversion, and exchange of thermal energy between physical systems.
Heat transfer mechanisms include thermal conduction, thermal convection, thermal radiation, and energy transfer via phase changes.
The rate of heat transfer through a unit thickness of material per unit area per unit temperature difference is defined as thermal conductivity. Thermal conductivity varies with temperature and is measured experimentally.
Heat is typically transferred in a combination of these three types and occurs at random. Heat transfer rate is measured in Joules per second, also known as Watts.
Thus, Joules per second or watts is the unit of rate of heat transfer.
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(8 pts.) Air in an Otto cycle engine is compressed to a temperature and pressure of 450 °C and 2.5 MPa. After the power stroke, the conditions are 600 °C and 0.45 MPa. Find the peak cycle temperature (°C), heat addition (kJ/kg), and efficiency
Answers
Answer:
a) [tex]Tb=1845.05K[/tex]
b) [tex]Q=1000.25KJ[/tex]
c) [tex]\mu=0.59[/tex]
Explanation:
From the question we are told that:
Temperature x [tex]Tx=450c=>723K[/tex]
Pressure x [tex]Px=2.5MPa[/tex]
Temperature y [tex]Ty=600c=>873K[/tex]
Pressure y [tex]Py=0.45MPa[/tex]
Let
Air atmospheric temperature be [tex]25c[/tex]
Therefore
Temperature [tex]Ta=25+273=298k[/tex]
Generally the equation for Otto cycle is mathematically given by
[tex]\frac{Tb}{Tx}=\frac{Ty}{Ta}[/tex]
[tex]Tb=\frac{873*723}{298}[/tex]
[tex]Tb=2118.05[/tex]
Therefore the peak cycle temperature (°C)
[tex]Tb=2118.05k[/tex]
[tex]Tb=2118.05-273[/tex]
[tex]Tb=1845.05K[/tex]
Generally the equation for Heat addition is mathematically given by
[tex]Q=Cv(Tb-Tx)[/tex]
[tex]Q=Cv(2118.05-723)[/tex]
[tex]Q=1000.25KJ[/tex]
Generally the equation for Thermal efficiency is mathematically given by
[tex]\mu=1-\frac{Ta}{Tx}[/tex]
[tex]\mu=1-\frac{298}{723}[/tex]
[tex]\mu=0.59[/tex]
Consider a single crystal of silver oriented such that tensile stress is applied along a (0 0 1) direction. If slip occurs on a (1 1 1) plane and in a (1 0 1) direction and is initiated at an applied tensile stress of 1.1 MPa (160 psi), compute the critical resolved shear stress.
Answers
Answer:
i don't know
Explanation:
sorry
tech a says that a slightly lean mixture offers good fuel economy and low exhaust emissions. Tech b says that a mixture that is too rich fouls spark plugs and causes incomplete burning. Who is correct
Answers
Explanation:
Exhaust emissions are gases that are expelled from vehicle engines and they include carbon monoxide, unburned fuel, nitrogen oxides and particulate matter such as mercury. These emissions can cause air pollution and green house effects which leads to climate changes. Low exhaust emissions can be achieved through the use of lean mixtures which has high air- fuel ratio and less emission. Therefore, Tech A is correct.
Rich mixtures are mixtures that are of low air- fuel ratios and it's burning in a diesel engine increases particulate matter emission, fouls spark plugs, causes incomplete burning. Therefore Tech B is equally correct. Hope this helps, thanks.
A 2400-lb rear-wheel drive tractor carrying 900 lb of gravel starts from rest and accelerates forward at 3ft/s2. Determine the reaction at each of the two (a) rear wheels A, (b) front wheels B.
Answers
Answer:
Explanation:
The missing diagram attached to the question is shown in the attached file below:
The very first thing we need to do in other to solve this question is to determine the mass of both the tractor and the mass of the gravel
For tractor, the mass is:
[tex]m_1 = \dfrac{2400 \ lb }{32.2 \ ft/s^2}[/tex]
[tex]m_1 = 74.53 \ lb.s^2/ft[/tex]
For gravel, the mass is:
[tex]m_2 = \dfrac{900 \ lb}{32.2 \ft/s^2}[/tex]
[tex]m_2 = 27.95 \ lb.s^2/ft[/tex]
From the diagram, let's consider the force along the horizontal components and vertical components;
So,
[tex]\sum F_x = ma_x \\ \\ 2F = (m_1+m_2) a \\ \\ F = \dfrac{1}{2}(74.53 4 + 27.950)lb.s^2/ft(2 \ ft/s^2) \\ \\ F = 102.484 \ lb[/tex]
[tex]\sum F_y = 0 \\ \\ 2N_A+2N_B - 2400 -900 = 0 \\ \\ N_A +N_B = 1650 \ lb[/tex]
Consider the algebraic sum of moments in the plane of A, with counter-clockwise moments being positive.
[tex]\sum M_A = I_o \alpha + \sum ma (d) \\ \\ = -2400 (20) + 2N_B (60) -900(110) = 0 - (74.534)(2)(20) - (27.950)(2)(40)[/tex]
[tex]=-48000 + 2N_B (60) -99000 = -2981.36-2236 \\ \\ = + 2N_B (60) = -2981.36-2236+48000+99000 \\ \\ = + 2N_B (60) = 141782.64 \\ \\ N_B = \dfrac{141782.64}{120} \\ \\ N_B = 1181.522 \ lb[/tex]
Replacing the value of 1181.522 lb for [tex]N_B[/tex] in equation (1)
[tex]N_A[/tex] + 1181.522 lb = 1650 lb
[tex]N_A[/tex] = (1650 - 1181.522)lb
[tex]N_A[/tex] = 468.478 lb
The net reaction on each of the rear wheels now is:)
[tex]F_R = \sqrt{N_A^2 +F^2}[/tex]
[tex]F_R = \sqrt{(468.478)^2 + (102.484)^2}[/tex]
[tex]\mathbf{F_R =479.6 \ lb}[/tex]
Now, we can determine the angle at the end of the rear wheels at which the resultant reaction force is being made in line with the horizontal
[tex]\theta = tan ^{-1}( \dfrac{468.478 }{102.484})[/tex]
[tex]\theta = 77.7^0[/tex]
Finally, the net reaction on each of the front wheels is:
[tex]F_B = N_B[/tex]
[tex]F_B =[/tex] 1182 lb
Fill in the truth table for output A.
A = (x+y)(x'+z')(x'+z')
Answers
Answer:
1+1×1 multiplay then you get the answer