Mathematics College

Find the square
(8m + 7)^2

Find The Square(8m + 7)^2

Answers

Answer 1

Answer:

(8m + 7)^2 = 64m^2 + 112m + 49

(8m)^2 = 64m^2

2(8m)(7) = 112m

7^2 = 49

Answer 2
Expanding the expression (8m + 7)^2 using the square of a binomial formula, we get:

(8m + 7)^2 = (8m)^2 + 2(8m)(7) + 7^2
= 64m^2 + 112m + 49

Therefore, the answer is 64m^2 + 112m + 49.

Related Questions

ASAP Dr. Rollins is both an anthropologist and archeologist. While excavating some ruins in South America, he discovered a scale drawing of a replica of a Mayan pyramid.
-The scale for the drawing to the replica was 1 inch : 2 feet.
- The scale for the replica to the actual pyramid was 1 foot : 14 feet.

If the height of the pyramid on the drawing was 3 1/2 inches, what was the height of the actual pyramid?

A. 98 feet
B. 49 feet
C. 91 feet
D. 196 feet

Answers

The height of the actual pyramid is 98 feet.

How to determine the height of the actual pyramid?

To determine the height of the actual pyramid, we need to use both scales and convert the measurements.

First, let's convert the height of the drawing to the height of the replica,

1 inch : 2 feet (scale for drawing to replica)

[tex]3 \frac{1}{2} \: inches[/tex] = 7 feet (height of the replica)

Next, let's convert the height of the replica to the height of the actual pyramid:

1 foot : 14 feet (scale for replica to actual)

7 feet = 7 x 14 = 98 feet (height of the actual pyramid)

Therefore, the height of the actual pyramid is 98 feet, so the answer is A) 98 feet.

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Adjacent angles. View the photo ccd

Answers

Answer: ∠DEA

Step-by-step explanation:

Starting Angle: ∠FBG

Adjacent (SAME) Angle: ∠DEA

DEA Is the correct answer

The top and bottom margins of a poster are 6 cm and the side margins are each 8 cm. If the area of printed material on the poster is fixed at 380 square centimeters, find the dimensions of the poster with the smallest area.

Width =

Height =

Answers

Let's denote the width of the printed material on the poster as "x" cm and the height as "y" cm.

According to the given information, the top and bottom margins are each 6 cm, and the side margins are each 8 cm. This means that the actual width of the entire poster, including the margins, is "x + 2(8)" cm, and the actual height, including the margins, is "y + 2(6)" cm.

Given that the area of the printed material on the poster is fixed at 380 square centimeters, we can set up the following equation:

Actual Area of Poster = Area of Printed Material on Poster

(x + 2(8))(y + 2(6)) = 380

(x + 16)(y + 12) = 380

To find the dimensions of the poster with the smallest area, we need to minimize the product (x + 16)(y + 12).

Since the given area of the printed material on the poster is fixed at 380 square centimeters, the actual area of the entire poster, including the margins, will be minimized when (x + 16)(y + 12) is minimized.

To minimize the product (x + 16)(y + 12), we need to minimize both x + 16 and y + 12, as they are both positive quantities.

Since x and y represent the width and height of the printed material on the poster, respectively, the smallest possible values for x + 16 and y + 12 would be 0, which means x = -16 and y = -12. However, since width and height cannot be negative, we need to find the next best option.

The smallest possible values for x + 16 and y + 12 that are greater than or equal to 0 would be when x = 0 and y = 0. This means that the width of the printed material on the poster should be 0 cm and the height should be 0 cm, which would make the dimensions of the poster with the smallest area:

Width = 0 cm

Height = 0 cm

However, please note that this would mean there is no printed material on the poster, as the width and height are both 0. If you want to have a non-zero width and height for the printed material on the poster, you would need to adjust the given area of the printed material on the poster accordingly.

4) Construct the truth tables for the following
(a) pV r
​

Answers

The truth tables for the logic expression is

p   q   p v q

F   F      F

F   T     T

T   F     T

T  T     T

Constructing the truth tables for the logic expression

From the question, we have the following parameters that can be used in our computation:

p v r

The expression is pronounced p or r

The rule of the truth table is

The expression is true if any of p or q is trueThe expression is false if both p and q are false

Using the above as a guide, we have the following truth tables

p   q   p v q

F   F      F

F   T     T

T   F     T

T  T     T

The above represents the truth tables for the logic expression

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