Find the missing angles for angle 1 and angle 2 measurements round to the nearest 10th of a degree 

Significant figures and include the appropriate units is [tex]r = 1.166 \times 10^{(-10)}[/tex]

Count up all of the bonds. Determine how many bond groups there are between individual atoms. By the total number of bonding groups in the molecule, divide the number of bonds between atoms. X-Ray crystallography is the only reliable method of determining molecule size. This gives you the crystal structure, including the positions of every atom, and you consequently know the size of the molecule. Any substance that can be crystallised can be used in this procedure, even huge molecules like protein and DNA.

spacing between lines [tex]=4.236*10^{10} s^{(-1)}[/tex]

atomic mass of Li = 7.0160 amu

atomic mass of cl = 34.9688

Bond length of molecule

B = h*c*B

[tex]6.626*10^{(-34)} J*S*3*10^{(10)} cm/s*2.118*10^{(10)} 1/cm[/tex]

[tex]B=42.06 \times 10^{(-24)}J[/tex]

Now according to relation

[tex]B=\frac{h^2}{8\pi^2 I}[/tex]

where I is moment of inertia

[tex]I=\frac{h^2}{8\pi^2 B}[/tex]

[tex]=(6.62*10^{(-34)})^2(JS)^2/8*(3.14)^2*(42.06*10^{(-24)})\\\\= 13.20*10^{(-47)}[/tex]

Calculate,

[tex]K=\frac{7.0160*34.968}{7.0160+34.9688} /\frac{10^{(-3)}kg/mol}{6.022*10^{(23)} mol^{(-1)}}[/tex]

[tex]= 0.970*10^{(-26)}kg[/tex]

[tex]I = \mu r^2 \\\\I=\sqrt{\frac{I}{\mu} }[/tex]

[tex]I=\sqrt{\frac{13.20\times 10^{-47 kg\ mx^2}}{0.970\times 10^{-26}kg} }[/tex]

[tex]r=1.166\times 10^{(-10)}[/tex]

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(a) P-value for z₀=1.88 is 0.0614

(b) P-value for z₀=−1.92 is 0.0548

(c) P-value for  z₀=0.43 is 0.6672

Assuming a two-tailed test with a significance level of α=0.05, we can calculate the P-value for each test statistic using the standard normal distribution

(a) z₀=1.88

P-value = P(Z > 1.88) + P(Z < -1.88)

= 2 × (1 - P(Z < 1.88))

= 2 × (1 - 0.9693)

= 0.0614

(b) z₀=−1.92

P-value = P(Z < -1.92) + P(Z > 1.92)

= 2 × (1 - P(Z < 1.92))

= 2 × (1 - 0.9726)

Do the arithmetic operation

= 0.0548

(c) z₀=0.43

P-value = P(Z > 0.43) + P(Z < -0.43)

= 2 × (1 - P(Z < 0.43))

= 2 × (1 - 0.6664)

= 0.6672

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To reduce bias in an estimator, (B) use random sampling and (C) increase the number of items included in the sample. Random sampling ensures that each member of the population has an equal chance of being selected, while increasing the sample size reduces sampling error and increases the representativeness of the sample.

To reduce bias in an estimator, it is important to use random sampling rather than nonrandom sampling. Random sampling ensures that every item in the population has an equal chance of being included in the sample, which helps to eliminate any potential bias. Additionally, increasing the number of items included in the sample can also help to reduce bias by providing a more representative sample. However, decreasing the number of items included in the sample can actually increase bias as it may not accurately represent the population. Therefore, it is important to use random sampling and include a sufficient number of items in the sample to reduce bias in an estimator.

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To maximize a^2 + b^2, we can use the fact that the sum of two nonnegative real numbers a and b whose sum is 23 is constant. This means that as one number increases, the other must decrease in order to keep the sum at 23. Therefore, to maximize the sum of their squares, a and b must be equal.

So, if a = b, then 2a = 23, or a = b = 11.5. Therefore, the two nonnegative real numbers a and b whose sum is 23 and maximize a^2 + b^2 are 11.5 and 11.5.

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The probabilities to be calculated are as follows:

a. P(T > t 0.2(df))

b. P(T(df))

c. P(-t 0.1(df)(df))

d. P(T < -t 0.21(df))

a. To calculate P(T > t 0.2(df)), we need to find the probability that a Student's t-distribution with an unknown degrees of freedom (df) exceeds the value of t 0.2. Since the degrees of freedom are unknown, we cannot determine the exact value of this probability without knowing the specific distribution being referred to.

b. To calculate P(T(df)), we need to find the probability that a Student's t-distribution with an unknown degrees of freedom (df) falls within the range of values from negative infinity to positive infinity. Since this range covers the entire distribution, the probability is equal to 1.

c. To calculate P(-t 0.1(df)(df)), we need to find the probability that a Student's t-distribution with an unknown degrees of freedom (df) is less than or equal to the negative value of t 0.1. Again, since the degrees of freedom are unknown, we cannot determine the exact value of this probability without knowing the specific distribution being referred to.

d. To calculate P(T < -t 0.21(df)), we need to find the probability that a Student's t-distribution with an unknown degrees of freedom (df) is less than the value of -t 0.21. As mentioned before, without knowing the degrees of freedom, we cannot determine the exact value of this probability.

Therefore, the probabilities cannot be calculated without knowing the specific degrees of freedom and the distribution being referred to..

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Answer:

d = 3

Step-by-step explanation:

Only table 2 is a function since it is a one to one mapping

A function is a one-to-one mapping of an equation.

Since we have four expressions to determine if they are functions, we notice that

So, only table 2 is a function

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Answer:

b. The outlier in the data set is the shoe priced at $78.95.

c. The outlier affects the mean by pulling it upward since it is much larger than the other prices. The median is not as affected since it is the middle value in the ordered data set, but it is still slightly shifted to the right. The mode is not affected since none of the prices are repeated.

d. Without the outlier, the median is the best measure of center because it is not as affected by extreme values as the mean, and the data set is not symmetric enough to have a clear mode. With the outlier, the median is still a good measure of center, but the mean is not as reliable due to the impact of the outlier.

The signal x[n] is:  x[n] = 19 cos((pi/5)n - pi/2).

The numerical values for A, B, and C are:

A = [tex]sqrt(2 * a0^2 - a5^2)[/tex]

B = [tex]2 * pi / N[/tex]

C = [tex]arctan((a5 / sqrt(2 * a0^2 - a5^2)) / tan(5 * pi / N))[/tex]

The given information about the signal x[n] can be used to find the constants A, B, and C in the representation of x[n] as:

x[n] = A cos(Bn + C)

where A, B, and C are constants. We have:

x[n] is a real and even signal with period N=10

The Fourier coefficient a0 is 11

The Fourier coefficient a5 is 5

The energy of x[n] is 50

The numerical values for A, B, and C can be found as follows:

A = [tex]sqrt(2 * a0^2 - a5^2) = sqrt(2 * 11^2 - 5^2)[/tex] = 19

B = [tex]2 * pi / N[/tex] = pi / 5

C = [tex]-arctan(a5 / sqrt(2 * a0^2 - a5^2)) = -arctan(5 / sqrt(2 * 11^2 - 5^2)) = -pi/2[/tex]

Therefore, the signal x[n] can be represented as:

x[n] = 19 cos((pi/5)n - pi/2)

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The acceleration of the particle at S = 40 m is approximately 2[tex]m/s^2[/tex]

To determine the acceleration of the particle when S = 40 m, we need to use the information given in the graph. The graph shows the velocity of the particle as a function of its displacement, S. Recall that acceleration is the rate of change of velocity with respect to time.

We can estimate the acceleration at S = 40 m by finding the slope of the tangent line to the velocity curve at that point.

One way to estimate the slope of the tangent line is to draw a line that is as close as possible to the curve at the point S = 40 m, and then find the slope of that line. We can use a ruler to draw a tangent line that intersects the curve at S = 40 m, as shown in the graph.

We then measure the displacement and velocity of two points on the tangent line, one on either side of S = 40 m. For example, we might choose the points S = 35 m and S = 45 m, and find their corresponding velocities, which are approximately v = 25 m/s and v = 45 m/s, respectively.

The slope of the tangent line is then given by the change in velocity over the change in displacement:

acceleration = (v2 - v1) / (S2 - S1)

Substituting the values we found, we get:

acceleration = (45 m/s - 25 m/s) / (45 m - 35 m) = 2[tex]m/s^2[/tex]

Therefore, the acceleration of the particle at S = 40 m is approximately 2[tex]m/s^2[/tex].

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The data is consistent with the Mendelian expected ratios at a significance level of alpha=0.10.

We must use the 9:3:3:1 ratio to calculate the expected numbers of each type of offspring in order to determine whether the observed data match the Mendelian expected ratios.

According to the 9:3:3:1 ratio, we would expect:

9/16 (56.25%) of the offspring to have white feathers and a small comb

3/16 (18.75%) of the offspring to have white feathers and a large comb

3/16 (18.75%) of the offspring to have dark feathers and a small comb

1/16 (6.25%) of the offspring to have dark feathers and a large comb

Using these expected proportions, we can calculate the expected number of offspring for each category:

Type Expected number Observed number (Expected - Observed)² / Expected

White feathers,  

small comb 106.875                   111                    0.197

White feathers,  

large comb 35.625                     37                         0.056

Dark feathers,  

small comb 35.625                   34                          0.018

Dark feathers,  

large comb 11.25                   8                         1.433

To calculate the chi-square statistic, we sum the last column:

chi-square = 0.197 + 0.056 + 0.018 + 1.433 = 1.704

For this test, the degrees of freedom are (4-1) = 3. The critical value from a chi-square distribution table is 6.251 with a significance level of alpha=0.10 and degrees of freedom of 3. We are unable to reject the null hypothesis that the observed data are in line with the Mendelian expected ratios because our calculated chi-square value (1.704) is lower than the critical value (6.251).

Therefore, based on the chi-square test, the data is consistent with the Mendelian expected ratios at a significance level of alpha=0.10.

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if we get the area of the 6x2.4 rectangle, and then subtract the area of the rectangle inside, the 2x4.4 one, what's leftover, is the part we didn't subtract, namely, the shaded part.

[tex]\stackrel{ \textit{containing rectangle} }{(6)(2.4)}~~ - ~~\stackrel{ \textit{inner rectangle} }{(2)(4.4)}\implies 14.4~~ - ~~8.8\implies \text{\LARGE 5.6}~cm^2[/tex]

In this case, the third column of matrix A is a linear combination of the first two columns, which makes the matrix singular and not invertible.

A matrix is a rectangular array of numbers or other mathematical objects, such as polynomials or functions, arranged in rows and columns.

Matrices are used to represent linear transformations, systems of linear equations, and other mathematical structures and operations.

To determine if a matrix is invertible or not, we need to calculate its determinant.

The given matrix is:

A = [1 2 0; 3 4 0; 5 6 0]

The determinant of  3x3 matrix is given by -

determinant(A) = a11(a22a33 - a23a32) - a12(a21a33 - a23a31) + a13(a21a32 - a22a31)

where aij is the element in i th row and j th column of the matrix.

By substituting the values from matrix A-

det(A) = 1(40 - 06) - 2(30 - 05) + 0(36 - 45)

det(A) = 0

Since the determinant of A is equal to zero, we can conclude that the matrix A is not invertible.

The matrix can be  invertible if and only if its determinant is nonzero. When the determinant is zero, the matrix is said to be singular, which means that its rows or columns are linearly dependent, and it cannot be inverted.

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The number line with plotted numbers 0, 1, 2, 3, 4, and 5 is present in above figure. The mixed number would be plotted where the arrow is pointing on the number line is equals to the [tex]2\frac{ 1}{4} [/tex].

A fraction, often called a fraction, is a combination of a number (integer) and a fraction (part of a whole number). So it has two parts. [tex]4 \frac{1}{7} [/tex] is an example of a mixed number. A number line is a horizontal line in which numbers are evenly distributed. It is used to pictorial representation of numbers. We have numbers for plotting on number line and conditions for plotting are

Now, the plotted number line is present in above figure. See the figure carefully. From the figure the mixed number that would plotted on red mark is [tex]2 \frac{1}{4} [/tex].

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Answer:

In a 30°-60°-90° right triangle, the length of the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is √3 times the length of the shorter leg.

2) DE = 2 × 5 = 10, DF = 5√3

3) MO = 3√3, LM = 3√3√3 = 9

4) LK = 2√6/√3 = 2√2, JK = 2 × 2√2 = 4√2

The probability of the horse not winning the race is 0.875 or 7/8, given that the odds against the horse winning the race were set at 7 to 1.

When the odds against a horse winning a race are set at 7 to 1, it means that for every 7 times the horse loses, it will win once. In other words, the probability of the horse winning is 1/8 or 0.125.

To find the probability of the horse not winning the race, we can subtract the probability of winning from 1. So, the probability of the horse not winning is:

1 - 0.125 = 0.875 or 7/8

This means that there is a 7/8 chance that the horse will lose the race. It is important to note that the odds and probabilities are two different ways of expressing the same information. The odds are a ratio of the probability of winning to the probability of losing, while the probability is simply the chance of an event occurring.

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Answer: The probability of Sandra choosing a blue marble is 2/9, the probability of choosing a yellow marble is 5/9, and the probability of choosing a white marble is 2/9.

Step-by-step explanation:

There are a total of 2 + 5 + 2 = 9 marbles in the bag.

The probability of Sandra choosing a blue marble is 2/9 because there are 2 blue marbles out of 9 total marbles.

The probability of Sandra choosing a yellow marble is 5/9 because there are 5 yellow marbles out of 9 total marbles.

The probability of Sandra choosing a white marble is 2/9 because there are 2 white marbles out of 9 total marbles.

The sum of these probabilities is equal to 1, as Sandra must choose one marble and it must be one of the available options:

2/9 + 5/9 + 2/9 = 9/9 = 1

95% confidence interval for the population mean is 170.2 to 189.8, option d is correct.

We are given the following information:

- Sample size (n) = 225
- Standard deviation (σ) = 75
- Sample mean (x) = 180
- Confidence level = 95%

We need to calculate the 95% confidence interval for the population mean (μ). To do this, we will use the formula:

Confidence interval = x ± (z × σ/√n)

First, we need to find the z-score that corresponds to a 95% confidence level. For a 95% confidence interval, the z-score is 1.96 (you can find this value in a standard z-score table).

Now, we can plug in the values we have:

Confidence interval = 180 ± (1.96 × 75/√225)

Calculate the standard error (σ/√n):

Standard error = 75/√225 = 5

Now, calculate the margin of error (z * standard error):

Margin of error = 1.96 × 5 = 9.8

Finally, calculate the confidence interval:

Confidence interval = 180 ± 9.8 = (170.2, 189.8)

So, the 95% confidence interval for the population mean is 170.2 to 189.8, which corresponds to option d.

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Answer: b. $52.00

Step-by-step explanation:

The probability P(a < Y < b) where Y = -ln(1-X), a = 6.86, and b = 4.22, with X being uniformly distributed between 0 and 1, is 0. This is because the given interval is invalid (a > b).

To explain, we first find the Cumulative Distribution Function (CDF) of Y. Since X is uniformly distributed, its probability density function (PDF) is f_X(x) = 1 for 0 ≤ x ≤ 1. Using the change of variables technique, we differentiate y = -ln(1-x) with respect to x, obtaining dy/dx = 1/(1-x). Thus, the PDF of Y is f_Y(y) = f_X(x) * |dx/dy| = 1 * (1-x) for y = -ln(1-x).

Now, we find the CDF of Y, F_Y(y) = P(Y ≤ y) = ∫f_Y(y)dy, and integrate with the limits from -∞ to y. Finally, to find the probability P(a < Y < b), we compute F_Y(b) - F_Y(a). However, since a > b, the interval is invalid and the probability is 0.

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The given sequence an=(2n 1)2(5n−1)2 converges or diverges with the same behavior as the sequence (4/25)^n. The option that suits the answer is option c.diverges. With the limit (4/25)

To determine if the sequence converges or diverges, we can use the limit definition of convergence.

First, we can simplify the expression inside the parentheses:

(2n + 1)^2 / (5n - 1)^2 = (4n^2 + 4n + 1) / (25n^2 - 10n + 1)

Then, we can use the fact that for two sequences {a_n} and {b_n}, if a_n / b_n converges to a non-zero constant, then {a_n} and {b_n} have the same convergence behavior.

So, let's take the limit of this new expression:

lim (n → ∞) [(4n^2 + 4n + 1) / (25n^2 - 10n + 1)]

We can use the highest degree terms in the numerator and denominator to simplify:

lim (n → ∞) [(4n^2 / 25n^2)]

This simplifies to:

lim (n → ∞) (4/25)

Since this limit is a non-zero constant, we can conclude that the sequence {an} converges or diverges with the same behavior as the sequence (4/25)^n.

Thus, the answer is (c) diverges.

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Answer:

approximately 1,392 grams

Step-by-step explanation:

The decay of a radioactive substance can be modeled using the formula:

N(t) = N0 * (1/2)^(t / T)

where:

N(t) is the amount of the substance remaining after time t,

N0 is the initial amount of the substance,

t is the time for which we want to calculate the remaining amount,

T is the half-life of the substance.

Given that you have 44,544 grams of europium and its half-life is 9 years, we can use the formula to calculate the amount remaining after 45 years.

Plugging in the values:

N0 = 44,544 grams

t = 45 years

T = 9 years

N(45) = 44,544 * (1/2)^(45/9)

Now we can calculate N(45):

N(45) = 44,544 * (1/2)^(5)

Using the exponent rule for fractional exponents:

(1/2)^5 = 1/32

N(45) = 44,544 * 1/32

N(45) = 1,392 grams (rounded to the nearest gram)

So, after 45 years, approximately 1,392 grams of europium will be left.

Step-by-step explanation:

They will pay $ 360    PLUS 20% of 360        (20% is .20 in decimal)

$   360 ( 1 + .20)  

 $  360 ( 1.20) = $ 432

The derivative of the function f(x) is f'(x) = (2x - 3)³[20x⁴ + 44x³ + 56x² + 40x + 8(x² + x + 1)⁵].

The derivative of the function f(x) = (2x − 3)4(x²+ x +1)5 is obtained by using the product rule and chain rule of differentiation. The product rule states that the derivative of the product of two functions is equal to the first function times the derivative of the second function plus the second function times the derivative of the first function.

The chain rule states that the derivative of a function composed with another function is equal to the derivative of the outer function times the derivative of the inner function. Applying these rules, the derivative of f(x) is given by:

f'(x) = 4(2x - 3)³(x² + x + 1)⁵ + (2x - 3)⁴(5x⁴ + 10x³ + 10x²)

This can be simplified by factoring out (2x - 3)^3 from both terms:

f'(x) = 4(2x - 3)³(x² + x + 1)⁵ + (2x - 3)³(5x⁴ + 10x³ + 10x²)²

= (2x - 3)³[4(x² + x + 1)⁵ + 2(5x⁴ + 10x³ + 10x²)]

= (2x - 3)³[20x⁴ + 44x³ + 56x² + 40x + 8(x² + x + 1)⁵]

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Note that the volume of the smaller cone is Vs = 900cm³

We must use the formula for the volume of a cone in this prompt.

V = (1/3) x   π x r ² x h

Let's assume that the radius of the bigger cone is R, and the radius of the smaller   cone is r.

Since the cones are similar, we knw that the ratio of the heights is the same as the ratio of  the radii

8 / 4 = R / r

Simplifying this equation, we can state

2 = R / r

This is also

R = 2r

So substituting into the expression for the bigger cone we say

Vb = (1/3) x π x (2r)² x 8

(1/3) x π x (2r)² x 8= 3600
8.37758040957 x (2r)² = 3600

2r² = 3600/8.37758040957

2r² = 429.718346348

r² = 214.859173174

r = 14.6580753571

So we can now enter tis into the expression for the smaller volume:

Vs = (1/3) x pi x 14.6580753571² x4

Vs = (1/3) x 3.14159265359 x 214.85917317442229252041 x4

Vs = 900cm³

So we are correct to state that the volume of the smaller cone is 900cm³

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To construct the exponential function that contains the points (0,-2) and (3,-128), we can use the general form of an exponential function:

y = a * b^x

where y is the function value, x is the input value, b is the base of the exponential function, and a is a constant representing the y-intercept. To find the specific exponential function that contains the two given points, we need to solve for a and b using the given coordinates.

First, we can use the point (0,-2) to find the value of a:

-2 = a * b^0
-2 = a * 1
a = -2

Next, we can use the point (3,-128) to find the value of b:

-128 = -2 * b^3
64 = b^3
b = 4

Now that we know the values of a and b, we can write the exponential function:

y = -2 * 4^x

Therefore, the exponential function that contains the points (0,-2) and (3,-128) is y = -2 * 4^x.

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Not possible since the value of sin(a) must lie between -1 and 1. Therefore, there is no solution for this problem.

We know that:

csc(a) = 3/2

Since csc(a) = 1/sin(a), we can find sin(a) as:

1/sin(a) = 3/2

Cross-multiplying, we get:

2sin(a) = 3

Dividing by 2, we get:

sin(a) = 3/2

This is not possible since the value of sin(a) must lie between -1 and 1. Therefore, there is no solution for this problem.

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For the quadratic function,

(a) Standard form: f(x) = (x + 1)^2 - 7

(b) Its graph will be a parabola opening upward

(c) Minimum value: f(x) = -7

(a) To express the quadratic function f(x) = x^2 + 2x - 6 in standard form, we complete the square.

f(x) = (x^2 + 2x) - 6
To complete the square, take half of the linear coefficient (2) and square it: (2/2)^2 = 1.

Now, add and subtract this value inside the parentheses:
f(x) = (x^2 + 2x + 1 - 1) - 6
f(x) = (x + 1)^2 - 7

So, the standard form is f(x) = (x + 1)^2 - 7.

(b) Since the leading coefficient (1) is positive, the graph of this quadratic function opens upward. The vertex is at the point (-1, -7), which is the minimum point. To sketch the graph, plot the vertex and draw a parabola opening upward.

(c) The minimum value of the function is the y-coordinate of the vertex: f(x) = -7.

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The maximum speed occurs when the angle of elevation of the plane is 90 degrees (i.e., a vertical drop)

(a) The speed of the ball bearing after t seconds is given by the derivative of s(t) with respect to t:

s'(t) = 9.8 (sin theta) t

(b)

t (seconds) theta = 30 degrees theta = 45 degrees theta = 60 degrees

0 0 0 0

1 4.9 6.8 8.8

2 9.8 13.7 17.6

3 14.7 20.5 26.4

4 19.6 27.4 35.2

5 24.5 34.2 44.0

To find the value of theta that produces the maximum speed at a particular time, we need to find the derivative of s'(t) with respect to theta:

s''(t) = 9.8 t cos(theta)

Setting s''(t) to zero, we find that cos(theta) = 0, which means theta = 90 degrees. Therefore, the maximum speed occurs when the angle of elevation of the plane is 90 degrees (i.e., a vertical drop).

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