Answers
Answer:
If you begin with the graph for f(x) and then substituted x+3 for x, the effect on the graph will be to move the whole graph 3 units to the left.
Given that (-9,-1) is on the graph of f(x), and that we are to move the entire graph 3 units to the left, then the coordinate -9 becomes -9-3, or -12: (-12,-1).
Step-by-step explanation:
Related Questions
A feeder at the zoo in shape of a cone has a radius of 3 inches. It holds about 113.04 cubic inches of food. Approximate its height to the nearest inch. Use 3.14 to approximate the value of pie.
Answers
Answer:
12 inches
Step-by-step explanation:
Which of the equations represents the line that contains the point (-3,11) and is parallel to a line that has a slope of 8/3? Select all that apply.
A. y=8/3x+3
B. y=8/3x+19
C. 3x+8y=11
D.8x-3y=11
E. y+11=8/3(x-3)
F. y+11=8/3(x+3)
Answers
The correct answer is:y = (8/3)x + 29/3
The equation of the line that passes through the point (-3, 11) and is parallel to the line with a slope of 8/3.To find the slope of the line that we need to draw, we can use the fact that parallel lines have the same slope. So, slope of the line = 8/3.Now, we have the slope and a point on the line, so we can use the point-slope form to find the equation of the line.The point-slope form is:y - y₁ = m(x - x₁)where m is the slope of the line and (x₁, y₁) is the given point.Substituting the values, we get:y - 11 = (8/3)(x - (-3))Simplifying the equation:y - 11 = (8/3)x + 8y - 44/3 = (8/3)x + 15/3y = (8/3)x + 29/3So, the equation of the line is:y = (8/3)x + 29/3The equation that represents the line that contains the point (-3, 11) and is parallel to a line that has a slope of 8/3 is:y = (8/3)x + 29/3.Selecting the options that apply:y=8/3x+19 (Does not apply because the y-intercept is incorrect.)3x+8y=11 (Does not apply because the slope is not 8/3.)8x-3y=11 (Does not apply because the slope is not 8/3.)y+11=8/3(x-3) (Does not apply because the slope is negative.)y+11=8/3(x+3) (Does not apply because the slope is not 8/3.)Hence, the correct answer is:y = (8/3)x + 29/3.
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Person A wishes to set up a public key for an RSA cryptosystem. They choose for their prime numbers p = 41 and q = 47. For their encryption key, they choose e = 3. To convert their numbers to letters, they use A = 00, B = 01,... 1. What does Person A publish as their public key? 2. Person B wishes to send the message JUNE to person A using two-letter blocks and Person A's public key. What will the plaintext be when JUNE is converted to numbers? 3. What is the encrypted message that Person B will send to Person A? Your answer should be two blocks of four digits each. 4. Person A now needs to decrypt the message by finding their decryption key. What is (n)? 5. Find the decryption key by find a solution to: 3d mod (n) = 1. What is the decryption key? 6. Confirm your answer to the previous part works by computing cd mod n for each block of the encrypted message, and showing it matches the answer to part (b).
Answers
1) Person A publishes their public key as (3, 1927).
2) Converting JUNE to numbers, J = 09, U = 20, N = 13, E = 04
3) The encrypted message is the pair of blocks: (729, 1121).
4) Person A now needs to decrypt the message by finding their decryption key. The n is 1927.
5) The decryption key is 642
To set up an RSA cryptosystem, Person A needs to perform several steps. Let's go through each step to find the answers to the questions:
1. Finding the public key:
Person A has chosen prime numbers p = 41 and q = 47.
Compute n = p * q: n = 41 * 47 = 1927
The public key consists of the pair (e, n), where e = 3.
Therefore, Person A publishes their public key as (3, 1927).
2. Converting the message "JUNE" to numbers:
Using the given conversion scheme A = 00, B = 01, ..., Z = 25:
J = 09
U = 20
N = 13
E = 04
3. Encrypting the message using Person A's public key:
To encrypt each two-letter block, we need to calculate c = [tex]m^{e}[/tex] mod n, where m is the plaintext number and e is the encryption key.
For the first block "JU":
For J (m = 09): c1 = 09³ mod 1927 = 729
For U (m = 20): c2 = 20³ mod 1927 = 16000 mod 1927 = 1121
The encrypted message is the pair of blocks: (729, 1121).
4. Finding the decryption key:
To decrypt the message, Person A needs to find the decryption key d, where 3d mod n = 1.
Since n = 1927, we need to solve the equation 3d mod 1927 = 1 for d.
We can use the Extended Euclidean Algorithm to find the modular inverse of 3 modulo 1927.
Using the Extended Euclidean Algorithm, we get:
1927 = 3 * 642 + 1
1 = 1927 - 3 * 642
Therefore, the decryption key is d = 642.
5. Computing the decryption key:
We found that d = 642 in the previous step.
6. Confirming the decryption works:
To confirm that the decryption works, we need to compute [tex]c^{d}[/tex] mod n for each block of the encrypted message and check if it matches the corresponding plaintext number.
For the first block (c1 = 729):
Compute [tex]c_{1} ^{d}[/tex] mod n: 729⁶⁴² mod 1927 = 09 (which matches the first plaintext number "J").
For the second block (c2 = 1121):
Compute [tex]c_{2} ^{d}[/tex] mod n: 1121⁶⁴² mod 1927 = 20 (which matches the second plaintext number "U").
Therefore, the decryption process works correctly, and the decrypted message is "JUNE," which matches the original plaintext.
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please help!!!!! simplify
Answers
Answer:
Pretty sure it's B
Step-by-step explanation:
17. Find the missing angle(s).
132
f
9
Answers
Answer:
34
Step-by-step explanation:
Answer:
angle f is 132..........
Write a real world problem that can be represented by 10x-40=100
Answers
Answer:
10x - 40 = 100, x = 14
Step-by-step explanation:
At a flower shop, there are 10 bouquets with the same amount of flowers in each of them. In total, 40 flowers were purchased. Now, there are 100 flowers left in the shop. How many flowers are in a bouquet?
This situation can be represented by
10x
(the number represents the bouquets, while the variable x represents the amount of flowers in a bouquet)- 40
(this represents the flowers that were purchased)= 100
(this represents the flowers remaining)The list below shows the different taco shells, fillings, and toppings sold at Rico's Taco Bar.
Taco Shells
Fillings
Toppings
Soft
Chicken
Cheese
Hard
Beef
Lettuce
Bean
Sour Cream
Onions
Salsa
How many different types of tacos can Rico make using one taco shell, one filling, and one topping?
Answers
Answer:
30 different types of tacos can Rico make.
Step-by-step explanation:
Given - The list below shows the different taco shells, fillings, and toppings sold at Rico's Taco Bar.
Taco Shells Fillings Toppings
Soft Chicken Cheese
Hard Beef Lettuce
Bean Sour Cream
Onions
Salsa
To find - How many different types of tacos can Rico make using one taco shell, one filling, and one topping?
Proof -
Given that,
There are 2 different types of Taco shells, 3 different type of fillings and 5 different types of toppings.
So, by the fundamental principal of counting,
Total types of tacos Rico made = 2 × 3 ×5 = 30
Find the Mean of the following set of data. (Round to the
nearest hundredths place.)
1, 1, 3, 0, 7, 2,0,3, 1, 6, 8, 1
PLEASE HELP ASAP I WILL MARK BRAINLIST
Answers
Answer:
2.75 all ready rounded
Step-by-step explanation:
for the mean all you have to do is add up all the numbers, then divide by how many numbers there are. when u add them all up it is 33, then u divide by 12, and get 2.75
The button on Madelyn's jacket has a radius of 4 millimeters. What is the button's circumference?
Use 3.14 for .
Answers
Answer:
The circumference would be 25.12 mm
Step-by-step explanation:
[tex]c = 2\pi r[/tex]
[tex]c = 6.28 \times 4[/tex]
[tex]c = 25.12[/tex]
S2 are nonzero subspaces, with Si contained inside S2, and suppose that dim(S2) = 4 .(1) What are the possible dimensions of S1? (2) If S1 ≠S2, then what are the possible dimensions of S1 ?
Answers
The possible dimensions of S1, can range from 0 to 4, and if S1 ≠ S2, then the possible dimensions of S1 can range from 1 to 4, where the dimension of S1 is equal to the dimension of S2 plus 1 up to a maximum dimension of 4.
(1) The possible dimensions of S1, when S2 is a nonzero subspace contained inside it and dim(S2) = 4, can be any integer value from 0 to 4.
(2) If S1 ≠ S2, then the possible dimensions of S1 can range from 1 to 4. Since S1 ≠ S2, it means that S1 must have at least one additional vector that is not present in S2. Therefore, the dimension of S1 can be equal to the dimension of S2 plus 1 (dim(S2) + 1), up to the maximum possible dimension of 4.
To elaborate further, when S1 ≠ S2, it implies that there exists a vector in S1 that is not in S2. This additional vector increases the dimension of S1 by one. Hence, the possible dimensions of S1 can be 1, 2, 3, or 4, as long as it is greater than or equal to the dimension of S2 plus 1. However, it is important to note that the specific dimension of S1 depends on the specific vectors and subspaces involved in the given context.
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PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Answers
Step-by-step explanation:
A. Right
B. Acute
C. Right
D. Obtuse
JK and LM are perpendicular diameters of a circle. They are each 12 inches long. What is the approximate length of chord LK?
Answers
ANSWER:
I think the approximate length og chord Lk is around 8.5 inches long
Enter the fraction using tenths and the decimal by the model.
Answers
Answer:
The fraction would be 5/10 or 1/2 and the decimal would be 0.5
Step-by-step explanation:
5 are shaded in out of 10 so that shaded part would be 5 out of 10 or 5/10. Same goes for the decimal, 5 are shaded which means that is 5 tenths or 0.5.
I hope this helps!
The following data gives an approximation to the integral M = S'f(x) dx = = 2.0282. Assume M = N, (h) + kyhº + k_h4 + ..., N, (h) = 2.2341, N, then N2(h) = 1.95956 0.95957 This option This option 2.23405 2.01333 This option O This option Romberg integration for approximating "', (x) dx gives R21 = 2 and R22 = 2.55 then R41 = 5.16 0.35 This option This option 4.53 2.15 O This option This option When approximating Sof(x)dx using Romberg integration, R4,4 gives an approximation of order: h10 h8 h4 h6
Answers
The value of N₂(h) for the given approximation is 1.95956. Richardson extrapolation allows us to estimate the integral with higher accuracy by combining two approximations with different step sizes. So, the correct answer is option a.
To approximate the integral [tex]M=\int\limits^1_0 {f(x)} \, dx[/tex] using the given data, we can use Richardson extrapolation.
Let N₁(h) be the approximation with step size h, and N₁(h/2) be the approximation with step size h/2.
We can express the error in terms of a power series as M = N₁(h) + k₂h² + k₄h⁴ + ...
Using Richardson extrapolation, we can eliminate the term with the highest power of h by taking a weighted sum of the two approximations:
[tex]N_2(h) = \frac{4N_1(\frac{h}{2}-N_1(h) )}{3}[/tex]
Substituting the given values N₁(h) = 2.2341 and N₁(h/2) = 2.0282:
[tex]N_2(h)=\frac{4(2.0282) - 2.2341}{3}[/tex]
N₂(h) = 1.95956
Therefore, the value of N₂(h) is approximately 1.95956. The correct answer is option a. 1.95956.
The question should be:
The following data gives an approximation to the integral[tex]M=\int\limits^1_0 {f(x)} \, dx[/tex] N₁(h) = 2.2341, N₁(h/2) = 2.0282. Assume M = N₁(h) + k₂h² + k₄h⁴ + ..., then N₂(h) = ?
a. 1.95956
b. 0.95957
c. 2.23405
d. 2.01333
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In a study of the fertility of married women, conducted by Martin O'Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of married women between the ages of 25 and 29 were randomly selected and without children, and each was asked if she planned to have a child at some point. A group of women married less than two years and another of women married five years were selected. Suppose that 240 of 290 women married less than two years plan to have a child someday, compared to 292 of 400 women married five years. We can conclude that the proportion of women married less than two years who plan to have a child children is significantly greater than the proportion of women married for five years who also plan to have children? Use a p-value.
Answers
The appropriate null hypothesis for this study is that there is no significant difference in the proportion of women married less than two years who plan to have children someday and the proportion of women married five years who plan to have children someday.
The alternative hypothesis states that there is a significant difference in the proportion of women married less than two years who plan to have children someday and the proportion of women married five years who plan to have children someday.
The hypothesis can be expressed in terms of population proportions as follows:H0: p1 = p2 (there is no significant difference in the proportion of women married less than two years who plan to have children someday and the proportion of women married five years who plan to have children someday)p1 - proportion of women married less than two years who plan to have children someday.
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Write the inequality that is represented by the number line below use x as your variable
Answers
Answer:
-4 < x < 2
Step-by-step explanation:
-4 is where the first point begins.-4
since the point is "open", aka not shaded, it should be "<"-4 <
we now have to insert the given variable, x-4 < x
the second, ending point, is also "open"-4 < x <
the ending point lands on 2-4 < x < 2
hopefully this answers your question. but a little fyi, this is simply the way i learned it, so it may/may not be what you exactly need :)
Sam has 3 water bottles. Together,Sam and Dave have at most 12 bottles of water
Answers
Answer:
Dave has 9 water bottles
Step-by-step explanation:
All 12 water bottles minus Sam's 3 water bottles equals Dave's 9 water bottles.
12 - 3 = 9
Solve the following initial value problem. y2 – 8y + 12, y(0) = 3 dx
Answers
The solution of the initial value problem is y= 3e2x - c2e2x +c2e6x.
Given y2 – 8y + 12, y(0) = 3
y2 – 8y + 12 = 0
The above equation is a quadratic equation, let us factorize it.
(y - 6)(y - 2) = 0y = 6 or y = 2
Therefore, the general solution of the differential equation isy = c1e2x + c2e6x............(1)
Now, let us apply the initial condition y(0) = 3 in the above general solution to find the value of c1 and c2.
y(0) = c1e2(0) + c2e6(0)3 = c1 + c2
On solving, we getc1 + c2 = 3c1 = 3 - c2
Substitute the value of c1 in equation (1)
y = (3 - c2)e2x + c2e6x = 3e2x - c2e2x + c2e6x...........(2)
The above equation is the required solution of the given initial value problem.
Therefore, the solution of the given initial value problem is
y = 3e2x - c2e2x + c2e6x.
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HELLLLPPP PLSSSSBXVXBCBCCBCX
Answers
Answer: -5,-1
Remember this: The number on the x axis ALWAYS goes first in the coordinates.
An archer la bete bathe buye 59% of the time Who shoots Barrows, what is the probability that she gets exactly 4 bulfs eyes? Assume each shot is independent of the others Round to three decimal places
A. 0.133
B. 0.003
C 0.240
D 0.121
Answers
The probability that the archer gets exactly 4 bullseyes is 0.133.
How do we calculate?The probability of an event is described as a number that indicates how likely the event is to occur and is expressed as a number in the range from 0 and 1.
P(X = k) = C(n, k) * [tex]P^k[/tex] * [tex](1 - p)^(^n^ - ^k^)[/tex]
C(n, k) = binomial coefficient
p= probability of success in a single trial
n = number of trials
The archer hits the bullseye 59% of the time,
p = 0.59
k = 4.
n = 8)
P(X = 4) = C(8, 4) *[tex]0.59^4[/tex] *[tex](1 - 0.59)^(^8^ -^ 4^)[/tex]
P(X = 4) = 0.133
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Simplify each Equation
Answers
Answer:
a.37
b. 82
c.101
d.8
e.6
f.3
Step-by-step explanation:
hope this helps
Area = 79.2 ft2
9 ft
4.2 ft
h
Answers
3(-2p-1)=-6p -3
Need help for this equation immediately have to turn it in tomorrow it’s pre algebra
Answers
(
−
2
−
1
)
=
−
6
−
3
3
(
−
2
p
−
1
)
=
−
6
p
−
3
3(−2p−1)=−6p−3
−
6
−
3
=
−
6
−
3
the answer is 0
Pls hurry!! It’s a quick question
Answers
Answer:
3/2
Step-by-step explanation:
State the name of the property illustrated. (2+1) + (6 +5) = (V6 +5) +(2+1)
Answers
The property illustrated in (2 + 1) + (6 + 5) = (6 +5) +(2 + 1) is the commutative property of addition
How to determine the name of the propertyFrom the question, we have the following parameters that can be used in our computation:
(2 + 1) + (6 + 5) = (6 +5) +(2 + 1)
In the above expression, we can see that
The terms of the expression are swapped
This can be illustrated as
if a + b = b + a
The name of the property is the commutative property of addition
Hence, the name of the property illustrated in (2 + 1) + (6 + 5) = (6 +5) +(2 + 1) is the commutative property of addition
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Peter is calculating the interest earned on a deposit of $275 in an account
that earns 8% simple interest for 12 years. How much interest will he
earn?
$2.915
$264
5539
52.640
The correct answer is $264 !
Get ya some points igs and ur welcome fam
Answers
please help me...please from the bottom of my heart
Answers
Answer:
I think No c
if wrong correct me pls
have a nice day
#Captainpower
Consider the following function. f(x) = 9x - 1
Find the difference quotient f(x)-f(a)/x-a for the function
Answers
The difference quotient for the function f(x) = 9x - 1 is (9x - 1 - (9a - 1))/(x - a).
The difference quotient is a measure of the average rate of change of a function over an interval. In this case, we are given the function f(x) = 9x - 1. The difference quotient formula is (f(x) - f(a))/(x - a), where f(x) is the value of the function at x, f(a) is the value of the function at a, and (x - a) represents the change in the input variable.
To calculate the difference quotient for the given function, we substitute the function values into the formula. So, we have (9x - 1 - (9a - 1))/(x - a). Simplifying this expression, we get (9x - 9a)/(x - a). This is the difference quotient for the function f(x) = 9x - 1.
The difference quotient represents the average rate of change of the function over the interval [a, x]. It measures how the function's output values change as the input values change from a to x. By evaluating this expression for different values of x and a, we can determine the average rate of change of the function over specific intervals.
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What is the diameter of a sphere with a volume of 332\text{ cm}^3,332 cm 3 , to the nearest tenth of a centimeter?
Answers
Answer:
The diameter is 8.6cm
Step-by-step explanation:
Given
Shape: Sphere
[tex]Volume = 332cm^3[/tex]
Required
Determine the diameter of the sphere
First, calculate the radius using:
[tex]Volume = \frac{4}{3} \pi r^3[/tex]
Substitute: [tex]Volume = 332cm^3[/tex]
[tex]332= \frac{4}{3} \pi r^3\\[/tex]
Solve for r
[tex]r^3 = \frac{332 * 3}{4 * \pi}[/tex]
[tex]r^3 = \frac{996}{4 * \pi}[/tex]
[tex]r^3 = \frac{249}{\pi}[/tex]
[tex]r^3 = \frac{249}{3.142}[/tex]
[tex]r^3 = 79.25[/tex]
Take cube roots
[tex]r = \sqrt[3]{79.25}[/tex]
[tex]r = 4.3[/tex]
Diameter (D) is calculated as:
[tex]D = 2r[/tex]
[tex]D = 2 * 4.3[/tex]
If a volume of an object varies directly with its height and if the volume is 24 while the height is 3 what is k
Answers
Answer:
8
Step-by-step explanation:
the formula for direct variation =
Y ∝ kX
such that
Y = kX
from the question we have here
Y = Volume = 24
x = height = 3
when we put this in the formula above in bold
24 ∝ 3k
24 = 3k
from here we have to find the value of k. to do this, we divide through by 3
24/3 = 3k/3
8 = k
therefore the value of k is 8