Find the compound interest on an investment of $8,000 at 6% compounded semiannually for 3 months.
a) $9,552.80
b) $1,552.80
c) $1,500.00
d) $9,500.00
e) None of these

Answer:

Solution;

given equation : 3.67 = c - 2.13

On solving equation, we get

c = 3.67 +2.13

c = 5.8

Hence, Janae solution is incorrect. So I disagree.

Answer: No because the answer is c =5.8 or 5.80

Step-by-step explanation:

Add 2.13 to both sides. 3.67 + 2.13 = 5.80

Answer:

x=8.6

Step-by-step explanation:

x=8.6

Answer:56

Step-by-step explanation: -8x-7=56

Answer: -15

Step-by-step explanation: it will just give you a higher negative number it is literally the opposite from positive equations if u have to negative numbers u add them if there is a negative AND a positive then you substract them :)

9514 1404 393

Answer:

  (a) -6±√5

Step-by-step explanation:

  (z +6)^2 = 5 . . . . . given

  z +6 = ±√5 . . . . .  take the square root

  z = -6 ±√5 . . . . . . subtract 6

Answer:

[tex]12.7[/tex]

Step-by-step explanation:

[tex]180 - 167.3 = 12.7 \\ < angle \: on\: a \: stright \: line \: is \: 180[/tex]

Answer:

6/13

Step-by-step explanation:

Solution :

The null and the alternate hypothesis can be stated as :

Null hypothesis

[tex]$H_0:\mu_1 \geq \mu_2$[/tex]

Alternate hypothesis

[tex]$H_a:\mu_1 \leq \mu_2$[/tex]

We known;

[tex]$\overline x_1=\frac{\sum_{i=1}^n X_i}{n_1}$[/tex]

   [tex]$=\frac{43+....+75}{7}$[/tex]

   = 62.286

[tex]$\overline x_2=\frac{\sum_{i=1}^n X_i}{n_2}$[/tex]

   [tex]$=\frac{66+....+81}{16}$[/tex]

   = 72.125

[tex]$s_1^2=\frac{\sum_{i=1}^n(X_i- \overline X_1)^2}{n_1-1}$[/tex]

    [tex]$=\frac{(43-65.5)^2+....+(75-65.5)^2}{7-1}$[/tex]

   = 116.571

[tex]$s_2^2=\frac{\sum_{i=1}^n(X_i- \overline X_2)^2}{n_2-1}$[/tex]

    [tex]$=\frac{(66-72.13)^2+....+(81-72.13)^2}{16-1}$[/tex]

   = 23.45

Therefore, calculating the test statics :

[tex]$t=\frac{\overline x_1 - \overline x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}}$[/tex]

[tex]$t=\frac{62.29-72.125}{\sqrt{\frac{116.571}{7}+\frac{23.45}{16}}}$[/tex]

[tex]$t=\frac{-9.839}{4.2566}$[/tex]

 = -2.312

Now calculating the P-value for the test as follows :

P=T.DIST(t, df)

[tex]$df=\frac{\left(\frac{s_1^2}{n_1}+\frac{s^2_2}{n_2}\right)^2}{\frac{1}{n_1-1}\left(\frac{s^2_X}{n_1}\right)^2+\frac{1}{n_2-1}\left(\frac{s^2_Y}{n_2}\right)^2}$[/tex]

[tex]$df=\frac{\left(\frac{116.571}{7}+\frac{23.45}{16}\right)^2}{\frac{1}{7-1}\left(\frac{116.571}{7}\right)^2+\frac{1}{16-1}\left(\frac{23.45}{16}\right)^2}$[/tex]

    [tex]$=\frac{328.2868}{46.36395}$[/tex]

   [tex]$\approx 7$[/tex]

P=T.DIST(t, df)

 =T.DIST(-2.31, 7)

 = 0.0270

Thus, the [tex]$\text{P-value}$[/tex] of the test is P = 0.0270 is [tex]$\text{less}$[/tex] than the level of significance [tex]$\alpha= 0.05$[/tex]. Hence the researcher can reject the null hypothesis.

Conclusion: The mean launch temperature for the flights with O ring damages less than that for the flights with no O rings.

Answer:

C

Step-by-step explanation:

None of the others have the correct data like C

Answer:

m∠RPQ = 8°

Step-by-step explanation:

m∠QRS = 4x - 15

m∠RPQ = x + 1

m∠PQR = x - 2

m∠QRS is exterior angle and m∠RPQ and m∠PQr are opposite interior angles to m∠QRS

m∠QRS = m∠RPQ + m∠PQR      {Exterior angle property of triangle}

4x - 15 = x +1 + x - 2

4x - 15 = x + x + 1-2          {Combine like terms}

4x - 15 = 2x - 1        {Subtract 2x from both sides}

4x - 2x - 15 = - 1

2x - 15 = - 1                  {Add 15 to both sides}

2x = -1 + 15

2x = 14          {Divide both sides by 2}

x = 14/2

x = 7

m∠RPQ = x + 1 = 7 + 1 = 8°

Answer: x+1 =(7)+1=8

Step-by-step explanation:

Answer:

"less than high school" and" high school graduate".

Answer:

The table below is comparing level of education achieved to the rate of unemployment and the median weekly earnings in 2008.  Based on the information provided, the unemployment rate decreases the most when moving between which two consecutive educational levels?

a.

“Less than high school” and “High School Graduate”  <<<<<<<CORRECT

b.

“High school graduate” and “Some college, no degree”

c.

“Associate degree” and “Bachelor’s degree”

d.

“Professional degree” and “Doctoral degree”

Step-by-step explanation:

Edge2021

Answer:

D

Step-by-step explanation:

Lets use the the chart. The (5,9) if the 5 was doubled that it would equal to 10. Now you subract 1 from it making it 9.

Answer:

13u√2u

Step-by-step explanation:

Remark

Removing factors from under the square root sign means factoring the numbers into prime factors. If there are an even number of equal prime factors, take one out and throw one away for all the primes that are the same. An odd number of factors always leaves 1 under the root sign.

For example

u^3 = u * u * u

One of the u's will be left behind. Of the two others, one will be discarded and one will be taken outside the root sign.

√u^3 = √(u * u * u) = u√u

Question Breakdown

Answer

48u√2u - 56√2u + 21u√2u

13u√2u

Answer:

2.14 divided by 5 x 2 is the ansewer

Step-by-step explanation:

Answer:

lesser x = -2, greater x = 2/3

Step-by-step explanation:

(2x+4)= 0 ---> bring 4 to the other side

2x=-4 ----> divide by 2 on both sides

x= -4/2 = -2 ----> simplify

(3x-2)= 0 ----> bring the 2 to the other side

3x=2 ----> divide by three on both sides

x=2/3

hope this helps!

30%....................................

Answer:  At Kennedy Middle School, the probability that a student takes Technology and Spanish is 0.087. The probability that a student takes Technology is 0.68

Step-by-step explanation: u divide

Answer:

We reject H₀  the actual percentage of type A donations differs from 40%

Step-by-step explanation:

Sample information:

sample size   n = 146

Type A   x₁  =  81   and   p₁  = 81 / 146     p₁  =  0,5547

then  q₁   =  1 - p₁    q₁  =  1  -  0,5547    q₁  =  0,4453

We choose as significance level  α  = 5%  α = 0,05   α /2  = 0,025

from z-table we find   z (c) = 1,96

National % of the population  ( μ  = 40 %  μ = 0,4 )

Test hypothesis

Null hypothesis                           H₀           p₁  =  μ

Alternative Hypothesis              Hₐ           p₁   ≠ μ

The Alternative hypothesis indicates that the test is a two-tail test

z(s) =  ( p₁  -   μ )/ √ p₁*q₁ / n

z(s) =  ( 0,5547  -  0,40 )/ √ 0,5547*0,4453 / 146

z(s) =  0,1547 / 0,041

z(s) = 3,77

Comparing  z(s)  and z(c)

z(s) > z(c)  

z(s) is in the rejection region. We reject H₀. Sample does not give evidence to support that the actual percentage of type A donations is equal to the national population

Answer:

I have no idea what sohcahtoa is but:

tan 50.1° = x/5

1.196 = x/5

multiply both sides of the equation by 5:

x = 5.98

Answer:

C) 28

Step-by-step explanation:

RSTV = WXYZ

WX = x

[tex]\frac{RS}{VR} =\frac{WX}{ZW} \\\\\frac{7}{3} =\frac{x}{12} \\\\3x=84\\x=28[/tex]

Answer:

60

Step-by-step explanation:

The computation of the third quartile is given below:

The third quartile Q3 is

= 3(n + 1)÷ 4

= 3 (24 + 1) ÷ 4

= 75 ÷ 4

= 18.75th term

Now the 18.75th term is

= 18th term + 0.75 term

= 57 +  (19 term - 18term)

= 57 +  0.75 (61 - 57)

= 57 + 0.75 (4)

= 60

Answer: Look at the picture

Step-by-step explanation: Hope this help :D

Answer:

It should be 50%

Step-by-step explanation:

It should be 50% because there are 12 yellow balls, so it should be 50%.

Hope it helps you

Answer:

There monthly income is 300$

Answer:

Joseph has 90 coins after 3 months

Step-by-step explanation:

Joseph: 25x + 15

Molly: 25x + 25

x = 3

Joseph: 25(3) + 15  =  90

Answer:

-5+5i

Step-by-step explanation:

Answer:

D on edge

Step-by-step explanation:

-5+5i

• ||v|| = 42, which is to say

||v||² = 〈v, v 〉

…  = 〈a u₁ + b u₂ + c u₃, a u₁ + b u₂ + c u₃〉

… = a ² 〈u₁, u₁〉 + b ² 〈u₂, u₂〉 + c ² 〈u₃, u₃〉 + 2(ab 〈u₁, u₂〉 + ac 〈u₁, u₃〉 + bc 〈u₂, u₃〉)

… = a ² ||u₁||² + b ² ||u₂||² + c ² ||u₃||²

[since each vector in the basis for V is orthogonal to any other vector in the basis, and 〈x, x〉 = ||x||² for any vector x ]

42² = a ² + b ² + c ²

[since each vector in the basis has unit length]

42 = √(a ² + b ² + c ²)

• v is orthogonal to u₃, so 〈v, u₃〉 = 0. Expanding v gives the relation

〈v, u₃〉 = 〈a u₁ + b u₂ + c u₃, u₃〉

… = a 〈u₁, u₃〉 + b 〈u₂, u₃〉 + c 〈u₃, u₃〉

… = c ||u₃||²

… = c

which gives c = 0, and so

42 = √(a ² + b ²)

• Lastly, 〈v, u₂〉 = -42, which means

〈v, u₂〉 = 〈a u₁ + b u₂ + c u₃, u₂〉

… = a 〈u₁, u₂〉 + b 〈u₂, u₂〉 + c 〈u₃, u₂〉

… = b ||u₂||²

… = b

so that b = -42. Then

42 = √(a ² + (-42)²)   →   a = 0

So we have a = 0, b = -42, and c = 0.

The required values are, [tex]a=0,b=-42 ,c=0[/tex]

Given,

[tex]v=au_1+bu_2+cu_3[/tex]

[tex]\left\| V\right\|=42[/tex]

Computation:

Since, [tex]v[/tex] is orthogonal to [tex]u_3[/tex] then we have,

[tex]\left<v,u_3 \right> =0\\\left< v,u_2\right> =-42[/tex]

Then,

[tex]\left\| V\right\|^2=\left<v,v \right>\\=\left<au_1+bu_2+cu_3,au_1+bu_2+cu_3 \right>\\=a_2\left\|u_1 \right\|^2+b_2\left\|u_2 \right\|^2+c_2\left\|u_3 \right\|^2\\=a^2+b^2+c^2\\=a^2+b^2+c^2=42^2[/tex]

As we know,

[tex]a=\left<v_1u_1 \right>\\b=\left< v_1u_2\right>= -42\\c=\left<v_1u_3 \right> =0[/tex]

[tex]a_2+b_2+c_2=42\\a=0[/tex]

Learn More:https://brainly.com/question/13152748

Answer:

The Answer will be (0.75)