Answer:
You have to answer this in your opinion!
Anyways, A time I took a big risk was when I decided to talk to strangers online. It was risky because the stranger was harrasing me and doing bad stuff to me online. I learned about online safety and I learned to be careful who I talk to online! :)
Explanation:
As you travel downhill, your vehicle needs less power to reach the bottom and your stopping _________ increases.
Answer: Distance
Explanation:
When driving, it is important for one to always use safety belt and obey traffic rules.
During a collision, it is vital to always adhere to safety belts and also use occupant protection systems in order to help reduce the impact that an be felt during a collision. As you travel downhill, your vehicle needs less power to reach the bottom and your stopping distance increase.
I need help with the questions when it says what is the topic and rest
If y is inversely proportional to x and y = 4 and x=10, find y when x = 20
Answer:
Y=8
Explanation:
Y=4
X=10
if x is 20 it means it is doubled frm the previous therefore it means even y has to be doubled
first. now
x=10. x=20
y=4. y=8
help me please I will thank you
Answer:
DNA= 2 strands, sugar is deoxyribose, and the Nitrogen Bases are adenine, uracil, cytosine, and thymine.
RNA= 1 strands, sugar is ribose, and the Nitrogen Nases are adenine, uracil, cytosine, and guanine.
Hope this helps :)
Explanation:
11 A car is driven on a long journey along a flat, horizontal road. The car stops several times on the
journey and its engine becomes hot.
Which type of energy does not change during the journey?
A the chemical energy in the fuel tank
the gravitational energy of the car
c the internal (thermal) energy of the engine
B
D the kinetic energy of the car
Answer:
A
Explanation:
Because the gravity is the one pulling the car to the ground so it doesnot change
The same same thing happens to the chemical energy in the engine it doesnot change as it is the one that makes the car to move from one place to another
Option B is correct that is the gravitational energy of the car does not change.
(A) The chemical energy in the fuel tank gets converted into thermal energy heating up the engine and mechanical energy which helps moving the car.
(B) Gravitational energy is due to the force of gravitation between the car and the earth and depends on their respective masses which does not change as the car moves.
(C) The internal energy is proportional to thermal energy. the thermal energy of the engine increases which means its internal energy also increases.
(D) The kinetic energy of the car changes as it moves and stops.
Learn more about gravitational energy:
https://brainly.com/question/19768887?referrer=searchResults
A light, flexible rope is wrapped several times around a hollow cylinder with a weight of 40 N and a radius of 0.25m that rotates without friction about a fixed horizontal axis. The cylinder is attached to the axle by spokes of a negligible moment of inertia. The cylinder is initially at rest. The free end of the rope is pulled with a constant force P for a distance of 5 m, at which point the end of the rope is moving 6 m/s. If the rope does not slip on the cylinder, what is the value of P
Answer:
The value is [tex]P = 14.7 \ N[/tex]
Explanation:
From the question we are told that
The weight of the hollow cylinder is [tex]W = 40 \ N[/tex]
The radius of the hollow cylinder is [tex]r = 0.25 \ m[/tex]
The distance which it is pulled is [tex]d = 5 \ m[/tex]
The velocity of the end of the rope is [tex]v = 6 \ m/s[/tex]
Gnerally the mass of the hollow cylinder is
[tex]m = \frac{W}{g }[/tex]
=> [tex]m = \frac{ 40 }{ 9.8 }[/tex]
=> [tex]m = 4.081 \ kg[/tex]
Generally angular displacement for the distance covered is mathematically represented as
[tex]\theta = 2 \pi * \frac{ d } {2\pi r }[/tex]
=> [tex]\theta = 2 \pi * \frac{ 5 } {2\pi r }[/tex]
=> [tex]\theta = \frac{ 5 } { 0.25}[/tex]
=> [tex]\theta =20[/tex]
Generally the torque experienced by the hollow cylinder is mathematically represented as
[tex]P * r = I * \alpha[/tex]
Here I is the moment of inertia
=> [tex]P * r = m r^2 * \alpha[/tex]
=> [tex]\alpha = \frac{P }{ mr }[/tex]
Generally from kinematic equation
[tex]w_f ^2 = w_i ^2 + 2\alpha \theta[/tex]
=> [tex]w_f ^2 = w_i ^2 + 2\alpha \theta[/tex]
Generally the final angular velocity is mathematically
[tex]w_f = \frac{v}{r}[/tex]
=> [tex]w_f = \frac{ 6 }{ 0.25 }[/tex]
=> [tex]w_f = 24 \ m/s[/tex]
Generally the initial angular velocity is Zero given that the hollow cylinder was at rest before rolling
[tex]24^2 = 0^2 + 2* \frac{P}{4.081 *0.25 } * 20[/tex]
=> [tex]24^2 = 0^2 + 2* \frac{P}{mr} * 20[/tex]
=> [tex]P = 14.7 \ N[/tex]
Please help me
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Answer:CCCCCCCCCCCCCCCCC
Explanation:CCCCCCCCCCCCC
Answer:
d
Explanation:
because it is talking of the solid rock in the core of the earth
Imagine that you fill a balloon at sea level (1.0 atm) with 18 L of air. You are taking the balloon to Denver, Colorado, for a birthday party. Colorado is the “Mile High State,” and Denver has an air pressure of 0.85 atm. When you get to the party, what will the volume of the balloon be?
Answer:
21.18 L
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 1 atm
Initial volume (V₁) = 18 L
Final pressure (P₂) = 0.85 atm
Final Volume (V₂) =?
With the application of the Boyle's law equation, we can obtain the final volume (i.e the new volume) of the gas as follow:
P₁V₁ = P₂V₂
1 × 18 = 0.85 × V₂
18 = 0.85 × V₂
Divide both side by 0.85
V₂ = 18 / 0.85
V₂ = 21.18 L
Therefore, the new volume of the gas will be 21.18 L
A space probe recovered an 8.5-kg sample of rocks from the surface of Mars. The acceleration due to gravity on Mars is 3.7 meters per second squared. What is the weight of the sample of rocks on the surface of the earth?
Answer: 31N
Explanation:F = m x a
F = 8.5 x 3.7
F = 31.45
F = 31 (rounded)
F = 31 N
A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The defender catches the ball carrier in a completely inelastic collision. What was the kinetic energy of the ball carrier/defender system BEFORE the tackle?
Answer:
3,544.375Joules
Explanation:
Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;
Kinetic energy = 1/2mv²
m is the mass of the body
v is the velocity
For the ball carrier;
KE = 1/2(75)(6.5)²
KE = 3168.75/2
KE = 1584.375Joules
For the defender;
KE = 1/2(80)(7)²
KE = 3920/2
KE = 1960Joules
The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender
kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules
PLZ HELP MEEEEEEE,;-;
Answer:
thxs for the points
Explanation:
because just started
Select the reset button on the lab activity. Select the boy icon. Select the middle note located
in the bottom right of the lab activity. Select the GO button. What happened to the pitch of the
sound as the sound source moved past the observer? Record your observations.
Answer:
You need to include the website and stuff?
Explanation:
Hiaaa I need help pwease" concerning the planetary orbits why was Copernicus somewhat inaccurate?"
An explosion occurs at the end of a pier. The sound reaches the other end of the pier by traveling through three media: air, fresh water, and a slender metal handrail. The speeds of sound in air, water, and the handrail are 355, 1480, and 5490 m/s, respectively. The sound travels a distance of 117 m in each medium. (a) After the first sound arrives, how much later does the second sound arrive
Answer:
0.05773 sec
Explanation:
We know that
time = distance/speed = d/V
for air
t1 = 117/355 = 0.3295 sec
for fresh water
t_2 = 117/1480 = 0.07905 sec
for metal
t_3 = 117/5490 = 0.02131 sec
So as we can see sound will reach through metal hand rail 1st, then through fresh water and then through air
1st = metal hand rail
2nd = fresh water
3rd = air
time difference between 1st and 2nd sound = t_2 - t_3 = 0.07905 - 0.02131 = 0.05773 sec
A 75kg bicyclist (including the bicycle), initially at rest at the top of a hill, coasts down the hill, reaching a speed of 14.6m/s at the bottom of the hill. The distance and height of the hill are shown. Neglect any friction impeding the motion and the rotational energy of the wheels. List the energy types at the initial and final time and whether work and loss (due to non-conservative forces) occur as well as the corresponding amounts of energy.
The energy type at the initial time is potential energy and the energy at the final time or position is kinetic energy.
What is the law of conservation of energy?The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.
Based on the law of conservation of mechanical energy, the formula for the change in the kinetic energy and the potential energy of the bicyclist is given as;
K.Ei + P.Ei = K.Ef + P.Ef
where;
K.Ei is the initial kinetic energy of the bicyclistK.Ef is the final kinetic energy of the bicyclistP.Ei is the initial potential energy of the bicyclistP.Ef is the final potential energy of the bicyclistThe kinetic energy of the bicyclist increases with increase in the velocity of the bicyclist while the potential energy increases with increase in the height of the bicyclist.
At the initial position when the bicyclist is at rest, the kinetic energy is zero, so the only energy at the initial position is potential energy because the height is maximum.
In addition, at the final position, the velocity of the bicyclist is maximum and the height is zero, so the only energy at the final position is kinetic energy.
Learn more about conservation of energy here: https://brainly.com/question/166559
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Which of the following is the most sensible way to conserve natural resources?
O Don't use any products made from trees
O Stop using electricity entirely
Never ride in a car
O Bike or walk to school instead of taking a gasoline-powered car.
Answer:Bike or walk to school instead of taking a gasoline powered car.
Explanation: gasoline is not infinite. trees can be replanted and regrown. electricity can by generated and is not a natural recourse.
Consider the moment immediately before the puck is released. At that moment, the kinetic energy, the gravitational potential energy, and the elastic potential energy are, respectively, Select the best answer from the choices provided. a-zero, at a maximum, and at a maximumb-at a maximum, zero, and zeroc-zero, at a maximum, and zerod-at a maximum, at a maximum, and zeroe-zero, zero, and at a maximum
Answer:
zero, at a maximum, and zero
Explanation:
At the instant that the puck is released, its kinetic energy is zero because we define the kinetic energy of a body as the energy possessed by a body by virtue of its motion.
The gravitational potential energy at the point of release is maximum since gravitational potential energy is possessed by any object in the earth's gravitational field.
Elastic potential energy refers to energy stored in a body as a result of applying a force that deforms the elastic object. . Hence elastic potential energy is available in the puck only when it is deformed upon hitting the earth.
A ball is thrown straight upward with a velocity of 14 m/s. What is the maximum height
reached by the ball?
(1 Point)
10 m
20 m
14 m
32 m
Hello!
[tex]\large\boxed{d = 10 m}[/tex]
When the ball reaches its maximum height, the velocity equals 0. We can use the kinematic equation:
vf = vi + at, where:
vf = final velocity (0)
vi = initial velocity (14 m/s)
a = acceleration due to gravity, or 9.8 m/s (downwards)
t = time, which will be solved for.
Plug in the given values:
0 = 14 - 9.8(t)
-14 = -9.8(t)
t ≈ 1.429 sec
Solve for the distance traveled using the kinematic equation:
d = 1/2(vf + vi)t
Plug in the values:
d = 1/2(14 + 0)(1.429)
d = 1/2(14 · 1.429)
d ≈ 10 m
3. Jackie tells Mike she can't go swimming, she is allergic to the chlorine. This is an example of ______.
A. self-concept
B. self-talk
C. self-disclosure
D. self-perception
Answer:
self perception
Explanation:
i think its self perception because he tells to others
Incident ray X passes parallel to the principal axis of a concave lens. Incident ray Y passes parallel to the principal axis of a convex lens.
How do the rays behave differently after passing through each lens?
Ray X continues moving in the same direction, and ray Y refracts and passes through the focal point located behind the lens.
Both rays refract and move as though they passed through the focal point.
Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Both rays continue moving in the same direction.
Answer:
Explanation:
It would be option C. Ray x appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Answer:
c. Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Explanation:
A ball of mass 0.0887 kg is dropped from a height 1.76 m above the ground. The acceleration of gravity is 9.8 m/s 2 . Neglecting air resistance, determine the
Answer:
determine the.........
at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C
Answer:
The volume of the gas becomes three times the initial volume.
Explanation:
Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.
So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.
The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.
As the pressure is constant, so [tex]P_1=P_2[/tex].
Let V_1 and V_2 be the initial and final volume respectively.
Assuming that the given gas is ideal gas.
So, applying the ideal gas equation
PV=nRT
where n is the number of moles of the gas and R is the universal gas constant.
For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]
and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]
Dividing the equation (i) by (ii), we have
[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]
As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then
[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]
As the pressure is not changing, so [tex]P_1=P_2[/tex], then
[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]
[tex]V_2=3V_1[/tex]
So, the volume of the gas becomes three times the initial volume.
You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 35 m/s. The ball has __________________ energy. Calculate it.
Answer:
The ball has kinetic energy
the kinetic energy is 945 J
Explanation:
Answer:
The ball has 1286.25 J of energy
Explanation:
Kinetic Energy
Is the type of energy of an object due to its state of motion. It's proportional to the square of the speed.
The equation for the kinetic energy is:
[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]
Where:
m = mass of the object
v = speed at which the object moves
The kinetic energy is often expressed in Joules (J).
The volleyball of a mass m=2.1 Kg is served at v=35 m/s, calculating its kinetic energy:
[tex]\displaystyle K=\frac{1}{2}\cdot 2.1\cdot 35^2[/tex]
[tex]\displaystyle K=\frac{1}{2}\cdot2.1\cdot 1225[/tex]
K = 1286.25 Joule
The ball has 1286.25 J of energy
A spacecraft is travelling in space with no resultant force and no resultant moment acting on it
Answer:
is that a question or a statement lol
Explanation:
what is a good college i can attend if i have Low B's and high C's as grades
Answer:
search easy colleges to get into ig
Explanation:
Which of the following is an example of light energy being changed to chemical energy?
Group of answer choices
A flashlight with rechargeable batteries
A solar panel that charges a battery
Food that is eaten to provide mechanical energy
Answer:
A solar panel
Explanation:
URGENTE : Un cuerpo de 8m³ flota en el agua. Si el volumen sumergido es de 5m³. Determina el modulo de la fuerza de empuje (en kn) que presenta
Answer:
La magnitud del empuje hacia arriba o fuerza hacia arriba que actúa sobre el cuerpo es 48,853 kN
Explanation:
Los parámetros dados son;
El volumen del cuerpo = 8 m.³
El volumen del cuerpo sumergido = 5 m³
Por el principio de Arquímedes, que establece que el empuje hacia arriba, [tex]F_b[/tex], actuar sobre un cuerpo en un fluido es igual al peso del fluido desplazado por el cuerpo
Matemáticamente, tenemos;
[tex]F_b[/tex] = ρ × g × V
Dónde;
ρ = La densidad del fluido = La densidad del agua = 997 kg / m³
g = La aceleración debida a la gravedad = 9,8 m / s²
V = El volumen del fluido desplazado = El volumen del cuerpo sumergido = 5 m.³
∴ [tex]F_b[/tex] = 997 kg / m³ × 9,8 m / s² × 5 m³ = 48,853 N = 48,853 kN (hacia arriba)
La magnitud del empuje hacia arriba o la fuerza hacia arriba que actúa sobre el cuerpo = 48,853 kN.
Which way can heat never flow?
Answer:
Cold to hot.
Explanation:
Heat can never flow from cold to hot, heat transfers itself from hot to cold.
plzzzzzzzzz help me will mark u brainest
Answer:
B
Explanation:
acceleration = change in speed / change in time
for 1, speed increases over time, so positive acceleration
for 3, speed decreases over time, so negative acceleration (or deceleration)
Un automóvil se mueve a velocidad constante v = 60 [km/h]. Si el tiempo de reacción del conductor al ver la luz roja de una intersección es de 0.5 [s], y ´este desacelera a razón de 40 [m/s2 ] ¿Qué distancia recorre el automóvil desde el instante en que el conductor nota la se˜nal hasta detenerse por completo? Entiéndase por tiempo de reacción, el intervalo de tiempo transcurrido entre el instante en que se percibe la señal y el instante en que se lleva a cabo la acción (instante en que el conductor activa el sistema de frenado).
Answer:
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
Explanation:
De acuerdo con el enunciado, el conductor nota la luz roja, empieza a decelerar 0.5 segundos después y decelera hasta detenerse. La distancia total recorrida por el automóvil desde el instante en que el conductor nota la luz roja ([tex]\Delta s_{T}[/tex]), medida en metros:
[tex]\Delta s_{T} = \Delta s_{1}+\Delta s_{2}[/tex] (1)
Donde:
[tex]\Delta s_{1}[/tex] - Distancia recorrida a velocidad constante, medida en metros.
[tex]\Delta s_{2}[/tex] - Distancia recorrida hasta alcanzar el reposo, medida en metros.
Si suponemos que la segunda etapa describe un movimiento uniformemente acelerado, entonces la distancia recorrida total que representada por la siguiente fórmula:
[tex]\Delta s_{T} = v_{o}\cdot \Delta t_{o} + \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial del automóvil, medida en metros por segundo.
[tex]v_{f}[/tex] - Velocidad final del automóvil, medida en metros por segundo.
[tex]\Delta t_{o}[/tex] - Tiempo de reacción del conductor, medido en segundo.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
Si conocemos que [tex]v_{o} = 16.667\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex], [tex]\Delta t_{o} = 0.5\,s[/tex] y [tex]a = -40\,\frac{m}{s^{2}}[/tex], entonces la distancia recorrida total es:
[tex]\Delta s_{T} = \left(16.667\,\frac{m}{s} \right)\cdot (0.5\,s)+\frac{\left(0\,\frac{m}{s} \right)^{2}-\left(16.667\,\frac{m}{s}\right)^{2}}{2\cdot \left(-40\,\frac{m}{s^{2}} \right)}[/tex]
[tex]\Delta s_{T} = 11.806\,m[/tex]
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.