Faber Kozlowski had 6 times as much money as Theriault Luigi. After Faber Kozlowski spent 1/3 of his money and Theriault Luigi spent 4/5 of his money, they had a total of $1155 left.

(a) How much money did Faber Kozlowski and Theriault Luigi have altogether at first?

(b) Theriault Luigi spent 3/4 of his remaining money on a hoodie. What fraction of his original amount of money did he spend on the hoodie?

Answers

Answer 1

Answer:

Step-by-step explanation:

Let's use variables to represent the amount of money each person had at first.

Let x be the amount of money that Theriault Luigi had.

Then, according to the problem, Faber Kozlowski had 6 times as much money as Theriault Luigi, which means Faber Kozlowski had 6x dollars.

After Faber Kozlowski spent 1/3 of his money, he had 2/3 of his money left, which is (2/3)(6x) = 4x dollars.

After Theriault Luigi spent 4/5 of his money, he had 1/5 of his money left, which is (1/5)x dollars.

Together, they had a total of $1155 left, which means:

4x + (1/5)x = 1155

Multiplying both sides by 5 to eliminate the fraction gives:

20x + x = 5775

Combining like terms gives:

21x = 5775

Dividing both sides by 21 gives:

x = 275

Therefore, Theriault Luigi had $275 at first, and Faber Kozlowski had 6 times as much, which is $1650 at first.

So, the answer to (a) is $275 + $1650 = $1925.

For (b), Theriault Luigi spent 3/4 of his remaining money on a hoodie, which means he spent (3/4)(1/5)x = 3/20 of his original amount of money on the hoodie.

Therefore, Theriault Luigi spent 3/20 of his original amount of money on the hoodie.

Answer 2

Answer:

(a) $1925

(b) 15%

Step-by-step explanation:

(a)

Let f = original amount of money Faber had.

Let t = original amount of money Theriault had.

"Faber Kozlowski had 6 times as much money as Theriault Luigi. "

f = 6t

"After Faber Kozlowski spent 1/3 of his money"

He has now: 2/3 f

"and Theriault Luigi spent 4/5 of his money"

He has now: 1/5 t

"they had a total of $1155 left"

2/3 f + 1/5 t = 1155

f = 6t

2/3 f + 1/5 t = 1155

2/3 (6t) + 1/5 t = 1155

4.2t = 115

t = 1155/4.2

t = 275

f = 6t = 6(275) = 1650

f + t = 275 + 1650 = 1925

Part (a) answer: $1925

(b)

Original amount: t = 275

He first spent 4/5 of the original amount, so he had 1/5 left.

275/5 = 55

He spent 3/4 of $55 on the hoodie.

3/4 × $55 = $41.25

$41.25/$275 × 100% = 15%

Part (b) answer: 15%


Related Questions


Calculate the area of the composite figure shown

Answers

The total area of the given figure is 525 cm² respectively.

What is the area?

The area is the entire amount of space occupied by a flat (2-D) surface or an object's shape.

The area of a plane figure is the area that its perimeter encloses.

The quantity of unit squares that cover a closed figure's surface is its area.

So, first, we will divide the figure into 2 parts which will be the triangle and the rectangle, and then add their area to get the total area as follows:

Triangle:

1/2 * b * h

1/2 * 15 * 20

15 * 10

150 cm²

Rectangle:

l*b

15*25

375 cm²

The total area of the figure: 375 + 150 = 525 cm²

Therefore, the total area of the given figure is 525 cm² respectively.

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Emilio took a random sample of n=12 giant Pacific octopi and tracked them to calculate their mean lifespan. Their lifespans were roughly symmetric, with a mean of x= 4 years and a standard deviation of sx=0.5 years. He wants to use this data to construct a t interval for the mean lifespan of this type of octopus with 90% confidence.

What critical value t* should Emilio use?

Answers

Emilio can find that the critical value t* for a 90% confidence level and 11 degrees of freedom is approximately 1.796.

Define standard deviation?

To construct a t interval for the mean lifespan with 90% confidence, Emilio needs to use a t-distribution with n-1 degrees of freedom. The confidence interval for the population is given by:

confidence interval = x ± t × (s·x/√n)

Where x is the sample mean, s·x is the sample standard deviation, n is the sample size, and t is the critical value of the t-distribution.

Since the sample size is n=12, the degrees of freedom for the t-distribution will be (n-1) = 11. To find the critical value t* for a 90% confidence level and 11 degrees of freedom, Emilio can use a t-distribution table or a statistical software.

Using a t-distribution table or calculator, Emilio can find that the critical value t* for a 90% confidence level and 11 degrees of freedom is approximately 1.796.

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Please answer quickly!!! I'll give BRAINLIEST!!!!! I attached the picture.

Answers

Answer: No.

Step-by-step explanation:

The graph doesn't represent a linear, exponential, or quadratic function.

An example of a linear function is a straight line.

An example of a quadratic function is like a smile.

An example of an exponential function is a curved line.

So hence, this doesn't represent a function.

Reply below if you have any questions of concerns.

You're welcome!

- Nerdworm

Calculus derivatives. Find f(x).

Answers

The solution equates to f(x) = 6x + 8.

How to explain the function

Reiterating the same statement without reiteration, it is observed that f'(x) equals ƒ""(x), ultimately resulting in a value of 6. Subsequently, we can derive a complete expression for f(x) where C represents an integration constant.

It should be noted that to find this constant, since f(-1) = 2, plugging in x as -1 and f(x) as 2 into the above equation results in:

2 = 6(-1) + C

C = 8

As such, we can confirm that the entire expression of f(x) is simply 6 times x added to 8. Validating this answer, when assessing f(0) or f(1) , either result should match the given values from our initial problem which they do. Hence, the solution equates to:

f(x) = 6x + 8.

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Find the x-intercept and y-intercept of this equation.

y = 4x + 7

Question 10 options:

x-intercept (4,0), y-intercept (0,7)


x-intercept (-7,0), y-intercept (0,-4)


x-intercept (7/4, 0), y-intercept (0,-4/7)


x-intercept (-7/4, 0), y-intercept (0,7)

Answers

The intercepts of the equation are: D. D. x-intercept (-7/4, 0), y-intercept (0,7).

What is the X-intercept and Y-intercept of a Linear Equation?

The x-intercept of an equation is simply the value of x when the corresponding value of y equals zero. Also, this is where the line of the equation cuts across the x-axis on a graph.

The y-intercept of an equation, on the other hand, is the value of y when the corresponding value of x equals zero. It is the point where the line of the equation cuts across the y-axis on a graph.

Thus, given the equation y = 4x + 7, the y-intercept is:

y = 4(0) + 7

y = 7

The x-intercept is:

0 = 4x + 7

-4x = 7

x = 7/-4

x = -7/4

The correct option is: D. x-intercept (-7/4, 0), y-intercept (0,7).

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In a different plan for area codes, the first digit could be any number from 1 through 7, the second digit was either 3, 4, 5, 6, and the third digit could be any number except 6, 7, or 8. With this plan, how many different area codes are possible?

Answers

Answer:

196

Step-by-step explanation:

There are 7 choices for the first spot.

4 choices for the second spot. And 7 choices for the third spot, which cannot be 6,7,8--so it can be 0,1,2,3,4,5 or 9 (7choices)

7 × 4 × 7 is 196

There are 196 possibilities for the three digit area code with this plan.

If a scatter plot has a pattern that is best fit by y=x2, we say that it has a property that displays a linear or a nonlinear pattern?​

Answers

The scatter plot that has a pattern that is best fit by y = x^2 has a property that displays a nonlinear pattern

Describing the property of the scatter plot

From the question, we have the following parameters that can be used in our computation:

Equation of the best fit of the scatter plot: y = x^2

As a general rule

Any equation that has a degree other than 1 is a non linear equation

This means that the property it displays is a nonlinear pattern

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Ms. Shaddai writes 3q = 51 and \{15, 16, 17\} on the board. Tell if each value in the set is a solution of the equation. Show your work.

Answers

Only 17 is a solution of the equation 3q = 51 among the values in the set {15, 16, 17}.

How to find out  if each value in the set is a solution of the equation?

To check if a value is a solution of the equation 3q = 51, we substitute the value for q and check if the equation is true.

Let's check each value in the set {15, 16, 17}:

For q = 15, 3q = 3(15) = 45, which is not equal to 51. Therefore, 15 is not a solution of the equation 3q = 51.

For q = 16, 3q = 3(16) = 48, which is not equal to 51. Therefore, 16 is not a solution of the equation 3q = 51.

For q = 17, 3q = 3(17) = 51, which is equal to 51. Therefore, 17 is a solution of the equation 3q = 51.

Therefore, only 17 is a solution of the equation 3q = 51 among the values in the set {15, 16, 17}.

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Juan catches 80% of the passes thrown to him in football. If the quarterback throws to him 15 times during a game, what is the probability he will catch atleast 10 of them?

Answers

the probability that Juan will catch at least 10 passes out of 15 is approximately 0.987.

The binomial distribution, which models the number of successful trials (catches) in a certain number of independent trials (passes thrown), can be used to solve this problem.

The likelihood of not catching a pass is 0.2, but the likelihood of catching one is 0.8. The likelihood of catching at least 10 passes out of 15 can be calculated as follows:

P(X >= 10) equals P(X = 10) plus P(X = 11). + ... + P(X = 15)

where X is how many of the 15 passes were intercepted.

The probability of catching precisely k passes out of n can be calculated using the binomial distribution formula:

P(X = k) = (n choose k) × p²k × (1 - p)²(n-k)

where (n choose k) is the binomial coefficient, which represents the number of ways to choose k items from a set of n distinct items.

Plugging in the values for n = 15, p = 0.8, and k = 10, 11, 12, 13, 14, and 15, we get:

P(X >= 10) = P(X = 10) + P(X = 11) + ... + P(X = 15)

= (15 choose 10) × 0.8²10 × 0.2²5 + (15 choose 11) × 0.8²11 × 0.2²4 + ... + (15 choose 15) × 0.8²15 × 0.2²0

≈ 0.987

Therefore, the probability that Juan will catch at least 10 passes out of 15 is approximately 0.987.

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A police car is located 40 feet to the side of a straight road.

A red car is driving along the road in the direction of the police car and is 140 feet up the road from the location of the police car. The police radar reads that the distance between the police car and the red car is decreasing at a rate of 85 feet per second. How fast is the red car actually traveling along the road?

The actual speed (along the road) of the red car is feet per second

Answers

The actual speed (along the road) of the red car is 8.37 feet per second

To solve this problem

Let's call the distance between the police car and the red car "x" at time t. Then, we know that:

x^2 = 40^2 + (140 - vt)^2

Where

v is the velocity of the red car (in feet per second) t is time

We are given that dx/dt (the rate at which x is decreasing) is -85 ft/s, so:

d/dt [x^2] = d/dt [40^2 + (140 - vt)^2]

2x(dx/dt) = 0 - 2v(140 - vt)

Substituting dx/dt = -85 and solving for v, we get:

2x(−85) = −2v(140−vt)

−170x = −280v + 2v^2t

v^2t = 140v - (85/2)x

Now, we can differentiate the equation x^2 = 40^2 + (140 - vt)^2 with respect to time to get:

2x(dx/dt) = 2(140 - vt)(-v)

Substituting dx/dt = -85 and solving for x, we get:

-170x = -2v(140 - vt)

x = (140v - vt^2)/85

Substituting this expression for x into the equation we derived earlier, we get:

v^2t = 140v - (85/2)((140v - vt^2)/85)

v^2t = 140v - 70(2v - t^2)

v^2t = 140v - 140v + 70t^2

v^2t = 70t^2

v = sqrt(70t^2)/t = sqrt(70) = 8.37 ft/s (rounded to two decimal places)

Therefore, the actual speed (along the road) of the red car is 8.37 feet per second

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resoudre l inequation (5x-4)(4x+3)<5(4x²-1)

Answers

Answer:

This shows the step by step process of rhetorical reduction of the question given

Elisa finished her math assignment in 1/2 hours. Then she completed her chemistry assignment in 1/5 hours. What was the tot amount of time Elsa spent doing these two assignments? Write your answer as a fraction in simplest form.

Answers

1/2+1/5 = 5/10+2/10= 7/10

You have to make the denominator the same so you multiply the numerator and denominator.

1/2•5= 5/10
1/5•2=2/10

Betty has 30 mls of cough medicine with breakfast.
She drinks half of her 4 ounce orange juice, and 25% of her 8 oz cup of coffee. How many mls total
did she consume?

Answers

Betty consumed a total of 148.294 milliliters of liquid with her breakfast.

To solve this problem

We can change the volumes of the coffee and orange juice to milliliters so that all of the measurements are in the same unit:

4 ounces =  4 * 29.5735, = 118.294 ml.

8 ounces = 8 x 29.5735, = 236.588 ml.

Half of Betty's 4-ounce glass of orange juice, or:

1/2 * 118.294 mls = 59.147 mls

She consumed 25% of her 8-ounce coffee, which is :

0.25 * 236.588 mls = 59.147 mls.

So, in total, Betty consumed:

30 mls of cough medicine + 59.147 mls of orange juice + 59.147 mls of coffee = 148.294 mls

Therefore, Betty consumed a total of 148.294 milliliters of liquid with her breakfast.

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what is the difference between the square of the sum and the square of a difference?​

Answers

Answer:

The product of the sum and difference of the same two terms is always the difference of two squares; it is the first term squared minus the second term squared.

Step-by-step explanation:

Thus, this resulting binomial is called a difference of squares.

Answer:

Step-by-step explanation:

Square of the sum

square means you are multiplying something twice and looks like:  

ex.       [tex]x*x=x^{2}[/tex]

sum is the addition of numbers

so square of the sum looks like:

(a+b)²

Square of the difference

difference means subtraction of numbers

so square of the difference looks like:

(b-a)²

Answer:

The product of the sum and difference of the same two terms is always the difference of two squares; it is the first term squared minus the second term squared.

Step-by-step explanation:

Thus, this resulting binomial is called a difference of squares.

Answer:

Step-by-step explanation:

Square of the sum

square means you are multiplying something twice and looks like:  

ex.       [tex]x*x=x^{2}[/tex]

sum is the addition of numbers

so square of the sum looks like:

(a+b)²

Square of the difference

difference means subtraction of numbers

so square of the difference looks like:

(b-a)²

Question
Each answer choice below represents a relation by a set of ordered pairs. In which of the answer choices is the relation a function?

Select all correct answers.
Select all that apply:

{(2,−5),(−2,0),(−3,6),(2,−4)}
{(−1,5),(−4,8),(−4,14),(2,6)}
{(1,3),(−2,−1),(4,3),(8,1)}
{(−2,−5),(7,1),(7,−3),(4,−1)}
{(8,8),(4,1),(1,6),(−5,6)}

Answers

Answer:

(c)  {(1,3),(−2,−1),(4,3),(8,1)}(e)  {(8,8),(4,1),(1,6),(−5,6)}

Step-by-step explanation:

You want the lists of ordered pairs that represent a functional relation.

Function

A function maps an input value to exactly one output value. A set of ordered pairs will represent a function if no input (x-value) is repeated.

We only need to look at the first values of the ordered pairs.

  (a) 2 is repeated

  (b) -4 is repeated

  (c) a function

  (d) 7 is repeated

  (e) a function

Answer:

(c)  {(1,3),(−2,−1),(4,3),(8,1)}(e)  {(8,8),(4,1),(1,6),(−5,6)}

Step-by-step explanation:

You want the lists of ordered pairs that represent a functional relation.

Function

A function maps an input value to exactly one output value. A set of ordered pairs will represent a function if no input (x-value) is repeated.

We only need to look at the first values of the ordered pairs.

  (a) 2 is repeated

  (b) -4 is repeated

  (c) a function

  (d) 7 is repeated

  (e) a function

Hannah is working in England for 3 months on a project for her company. One weekend Hannah decides to go to France with her car on the ferry, then explore the French countryside. In England, speed limit signs are posted in miles per hour (mph) and Hannah's rental car only shows the speed in miles per hour. In France, speed limit signs are posted in kilometers per hour (kph). Hannah looks up the conversion and learns that 1 kph = 0.62 mph.

On the road that Hannah is currently on, the posted speed limit is 130 kilometers per hour. What is the maximum whole-number speed, in miles per hour, that Hannah can drive without exceeding the speed limit?

A. 82 mph
B. 79 mph
C. 209 mph
D. 80 mph

Answers

Answer:

To convert kilometers per hour to miles per hour, we need to multiply by 0.62. Therefore, to find the maximum speed that Hannah can drive without exceeding the speed limit of 130 kilometers per hour, we can multiply 130 by 0.62:

130 km/h * 0.62 = 80.6 mph

Since Hannah needs to stay within the speed limit, the maximum whole-number speed she can drive is 80 mph, which is option D.

Step-by-step explanation:

A bag has 30 cards it in. There are 10 red cards, 10 blue cards, and 10 yellow cards. What is the probability that you reach in without looking and pick a red card?

Answers

The probability of picking a red card can be calculated by dividing the number of red cards by the total number of cards in the bag:

P(red card) = number of red cards / total number of cards

P(red card) = 10 / 30

P(red card) = 1/3 or approximately 0.333

So the probability of picking a red card is 1/3 or 0.333.

Need help with this problem

Answers

The sales tax on 250 dollars purchase is: $3865

How to find the equation model?

We are told that sales tax is directly proportional to retail price. Thus:

S ∝ p

Any item that sells for 158 dollars has a sales tax of 10.22 dollars. Thus:

158 = 10.22k

where k is constant of proportionality

Thus:

k = 158/10.22

k = 15.46

Thus, the equation is:

S = 15.46p

Sales tax on 250 dollars purchase is:

S = 15.46 * 250

S = $3865

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Construct a 95% confidence interval of the mean pulse rate for adult males ___bpm

Answers

The 95% confidence interval of the mean pulse rate for adult females is 68.2 bpm < μ < 76.4 bpm

For a 95% confidence interval, the Z-score is 1.96. Plugging in the values we have for the sample mean, sample standard deviation, and sample size, we get:

Confidence interval = 75.8 ± (1.96 × (3.7 / √50))

Simplifying the expression, we get:

Confidence interval = 71.5 bpm < μ < 80.2 bpm

This means that we can be 95% confident that the true population mean pulse rate for adult females falls within this range.

Now let's construct a confidence interval for adult males. We are given that the sample mean pulse rate for adult males is 72.3 bpm, and the sample standard deviation is 4.0 bpm. Using the same formula and Z-score as before, we can calculate the confidence interval as follows:

Confidence interval = 72.3 ± (1.96 × (4.0 / √50))

Simplifying the expression, we get:

Confidence interval = 68.2 bpm < μ < 76.4 bpm

This means that we can be 95% confident that the true population mean pulse rate for adult males falls within this range.

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A triangle with an area of 40 in.² has a height that is four less than six times the base. Find the base and height of the triangle.

Answers

Let's call the base of the triangle "b" and the height "h". We know that the area of the triangle is 40 in², so:

Area = 1/2 * base * height

Plugging in the given values, we get:

40 = 1/2 * b * h

Simplifying, we get:

80 = b * h

We also know that the height is four less than six times the base, so:

h = 6b - 4

Now, we can substitute this expression for "h" into the equation we just derived for the area:

80 = b * (6b - 4)

Expanding the brackets, we get:

80 = 6b² - 4b

Rearranging, we get:

6b² - 4b - 80 = 0

Dividing both sides by 2, we get:

3b² - 2b - 40 = 0

This is a quadratic equation, which we can solve using the quadratic formula:

b = (-(-2) ± sqrt((-2)^2 - 4(3)(-40))) / 2(3)

b = (2 ± sqrt(304)) / 6

The positive solution is:

b = (2 + sqrt(304)) / 6

b ≈ 3.54

Now, we can use the equation we derived earlier to find the height:

80 = b * h

h = 80 / b

h = 80 / 3.54

h ≈ 22.6

Therefore, the base of the triangle is approximately 3.54 inches and the height is approximately 22.6 inches.

Answer: 9.32 inches.

Step-by-step explanation:

The perimeter of a rectangle is 21.2 m, and its area is 23.68 m².
Find its length and width.
length: m
width: m

Answers

Perimeter of a rectangle =2(l+w)=21.2m
Area of a rectangle =l*w=23.6m2
21.2=2l+2b————-(eq 1)
23.6=lw—————(eq 2)
l=23.6/w———————(eq 3)
Substitute eq 3 into eq 1
21.2=2(23.6/w)+2w
21.2=47.2/b +2w
Add the right hand side
21.7=(47.2+2w^2)/w
Cross multiply
21.7w=47.2+2w^2


3 A system of two linear equations is graphed on a coordinate plane. If the system of
equations has infinitely many solutions, which statement must be true?
a. On the graph, there are no points (x, y) that satisfy both equations.
b. On the graph, there is exactly one point (x, y) that satisfies both equations.
c. On the graph, any point (x, y) that satisfies one of the equations cannot satisfy the
other equation.
d.
On the graph, any point (x, y) that satisfies one of the equations must also satisfy
the other equation.

Answers

Answer:

d. On the graph, any point (x, y) that satisfies one of the equations must also satisfy the other equation.

----------------------

If the system of linear equations has infinitely many solutions, it means the two lines overlap.

In other words, each point of one of the lines also belongs to the second line.

Choices a, b, c  give us one or no solutions and therefore not the answer.

Choice d is reflecting the infinitely many solutions and hence is the correct one.

what is the value of the expression shown below
2 3/5 - 1 3/5
^ ^
TWO THREE-FIFTHS MINUS ONE THREE-FIFTHS

THE NUMBERS ARE MIXED FRACTIONS

Answers

Answer:

1

Step-by-step explanation:

1.  One way to do this is converting both into improper fractions.  To do this, multiply the whole number by the denominator and add that to the numerator.

2 3/5 --> 2*5 is 10 --> 10+3 is 13.  --> 13/5

2.  This leaves us with 13/5 - 8/5

3.  Subtract the numerators

13/5 - 8/5 = 5/5

4.  Simplify.  If the numerator is the same number as the denominator, it's a whole number.

5/5 = 1

To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B.


The mean braking distance for Make A is 42 feet. Assume the population standard deviation is 4.6 feet.

The mean braking distance for Make B is 45 feet. Assume the population standard deviation is 4.3 feet.


At α = 0.10, can the engineer support the claim that the mean braking distances are different for the two makes of automobiles?

Assume the samples are random and independent, and the populations are normally distributed.


​(a) Identify the claim and state H_0 and H_a

(The mean braking distance is different for the two makes of automobiles.)


What are H_0 and ​H_a?


(b) Find the critical​ value(s) and identify the rejection​ region(s).


​(c) Find the standardized test statistic z for μ_1 - μ_2

z = _____


(d) Decide whether to reject or fail to reject the null hypothesis.


​(e) Interpret the decision in the context of the original claim.

Answers

Upper Critical Value; 1.645

p-Value; 0.0814

Reject the null hypothesis

How to solve

a).

claim: A. The mean breaking distance is different for the two makes of automobiles

H0 and Ha.: E

[tex]\ H_0: \mu_1 = \mu_2 \ \ \ H_a: \mu_1 \neq \mu_2[/tex]

b).

critical values are (-1.645, 1.645)

Rejection region: E. z < -1.645 , z >1.645

c)

test statistic z= -1.743

d).

C. Reject H0. The stat statistic falls in the rejection region.

e).

At the 10% significance level, there is sufficient evidence to support the claim that means breaking distance of make A is different from mean breaking distance of making B.

m 2

M1

7t

Z Test for Differences in Two Means

Data

Hypothesized Difference

0

Level of Significance

0.1

Population 1 Sample

Sample Size

35

Sample Mean

42

Population Standard Deviation

4.9

Population 2 Sample

Sample Size

35

Sample Mean

44

Population Standard Deviation

4.7

Intermediate Calculations

Difference in Sample Means

-2

Standard Error of the Difference in Means

1.1477

Z Test Statistic

-1.7427

Two-Tail Test

Lower Critical Value

-1.645

Upper Critical Value

1.645

p-Value

0.0814

Reject the null hypothesis

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The circumference of the hub cap of a tire is 83.90 centimeters. Find the area of this hub cap. Use 3.14 for x. Use pencil and paper. If the circumference
were smaller, explain how this would change the area of the hub cap.
The area of this hub cap is about 560 square centimeters.
(Round the final answer to the nearest whole number as needed. Round all intermediate values to the nearest thousandth as needed.)

Answers

It can be seen that if the circumference were smaller, the area would decrease, as it is proportional to the square of the radius.

How to solve

Given the circumference (C) of the hub cap as 83.90 cm, we can find the radius (r) using the formula C = 2 * π * r,

where π = 3.14.

Thus, r ≈ 13.363 cm.

To find the area (A), use the formula A = π * r^2, yielding A ≈ 560.509 cm². Rounded, the area is about 561 cm².

Therefore, it can be seen that if the circumference were smaller, the area would decrease, as it is proportional to the square of the radius.

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A scatter plot is shown on a coordinate plane. The x-axis is numbered 0 to 15 and the y-axis is numbered from 2 to 26 in increments of 2. Points shown are located at (7, 2), (9, 1), (11, 3), (7, 6), (5, 8), (8.5, 8), (3, 12), (6, 13), and (4, 16). A line of best fit goes through points (5, 12) and (9, 4) and is extended to show it approaching the points (0, 22) and (11, 0).
Which equation represents the line of best fit?

Answers

The equation represents the line of best fit is y = -2x + 22.

What is an equation?

A mathematical statement that represents a relationship between two or more quantities is typically expressed using symbols, numbers, and mathematical operations. Equations are used to express mathematical relationships, make predictions, and solve problems. An equation typically consists of an expression on each side of an equal sign (=), indicating that the values on both sides are equivalent.

According to the given information:

To determine the equation of the line of best fit in the scatter plot, we can use the slope-intercept form of a linear equation, which is given by:

y = mx + b

where m is the slope and b is the y-intercept.

Given that the line of best fit goes through points (5, 12) and (9, 4), we can calculate the slope (m) using the formula:

m = [tex]\frac{(y_{2}-y_{1})}{(x_{2}-x_{1} ) }[/tex]

Plugging in the values from the given points, we get:

m = [tex]\frac{(4-12)}{(9-5)}[/tex]

m = -8 / 4

m = -2

So, the slope of the line of best fit is -2.

Next, we can substitute the slope and one of the given points (5, 12) into the slope-intercept form to solve for the y-intercept (b):

12 = -2(5) + b

12 = -10 + b

b = 12 + 10

b = 22

So, the y-intercept of the line of best fit is 22.

Thus, the equation of the line of best fit is:

y = -2x + 22.

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An air traffic controller is tracking two planes. To start, Plane A is at altitude of 2639 feet and Plane B is just taking off. Plane A is gaining altitude at 35.25 feet per second and Plane B is gaining altitude at 80.75 feet per second
How many seconds will pass before the planes are at the same altitude?
What will their altitude be when they're at the same altitude?

Answers

Answer:

Step-by-step explanation:

To find the number of seconds it will take for the planes to be at the same altitude, we need to set the altitude equations for both planes equal to each other and solve for time:

2639 + 35.25t = h    (altitude equation for Plane A)

0 + 80.75t = h       (altitude equation for Plane B)

where h is the altitude of both planes when they are at the same altitude, and t is the number of seconds that have passed.

Setting the two equations equal to each other and solving for t, we get:

2639 + 35.25t = 80.75t

45.5t = 2639

t = 58

Therefore, it will take 58 seconds for the planes to be at the same altitude.

To find their altitude at that time, we can substitute t = 58 into either of the altitude equations and solve for h:

2639 + 35.25t = h

2639 + 35.25(58) = h

h = 4818.5

Therefore, when the planes are at the same altitude, their altitude will be approximately 4818.5 feet.

the angle of elevation from the horizontal to the sun is 38°. How long of a shadow would a 32 foot tree make at this time?

Answers

The length of the shadow would be approximately 41.7 feet if the angle of elevation from the horizontal to the sun is 38° at this time.

If the angle of elevation from the horizontal to the sun is 38°, then the tangent of that angle is equal to the opposite side (the height of the tree) divided by the adjacent side (the length of the shadow).

Therefore, we can set up the equation using trigonometric function tangent as,
tan(38°) = height of tree / length of shadow

Solving for the length of the shadow, we get:
length of shadow = height of tree / tan(38°)

Plugging in the given height of the tree (32 feet) and using a calculator to find the tangent of 38°, we get:
length of shadow = 32 / tan(38°) = 41.7 feet (rounded to one decimal place)

Therefore, the length of the shadow would be approximately 41.7 feet at this time.

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Tyrone factored the polynomial completely. What is the value of B?

12x4+30x3+4x2+10x

Ax(Bx2+1)(2x+5)

2
3
5
6

Answers

Answer:

the value of B is 3

Step-by-step explanation:

We can start by factoring out the greatest common factor of the polynomial, which is 2x:

2x(6x3 + 15x2 + 2x + 5)

Now, we can factor the expression inside the parentheses by grouping:

2x[(6x3 + 2x) + (15x2 + 5)]

2x[2x(3x + 1) + 5(3x + 1)]

2x(2x + 5)(3x + 1)

Comparing this expression to the given expression:

Ax(Bx2+1)(2x+5)

We see that A = 2, B = 3, and the factor (2x + 5) is the same in both expressions. Therefore, the value of B is 3.

Suppose a company wanted to find out whether a new highlighter lasted less than their original highlighters lasted.

Answers

The value of t= -1.946; p = 0.029; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last less than 14 hours.

To test the hypothesis that the highlighters last less than 14 hours, we will use a one-sample t-test. The null hypothesis for this test is that the mean continuous writing time for the highlighters is equal to or greater than 14 hours. The alternative hypothesis is that the mean continuous writing time for the highlighters is less than 14 hours.

In this problem, we are given that x = 13.6 hours and s = 1.3 hours. The sample size is n = 40. Substituting these values into the formula for the test statistic, we get:

t = (13.6 - 14) / (1.3 / √(40)) = -1.946

The p-value for the test can be found using a t-distribution table or a statistical software program. The p-value is the probability of observing a t-value as extreme as the one we calculated, assuming the null hypothesis is true. In this problem, the p-value is 0.029.

To make a decision about the null hypothesis, we compare the p-value to the significance level, which is typically set at 0.05. If the p-value is less than the significance level, we reject the null hypothesis. If the p-value is greater than the significance level, we fail to reject the null hypothesis.

In this problem, the p-value is less than 0.05, so we reject the null hypothesis. This means there is strong evidence to suggest that the highlighters last less than 14 hours. We can conclude that the manufacturer's claim that their highlighters can write continuously for 14 hours is not supported by the sample data.

Hence the correct option is (c).

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Complete Question:

Solve the problem. Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours. The researcher tested 40 highlighters and recorded the number of continuous hours each highlighter wrote before drying up. Test the hypothesis that the highlighters wrote for less than 14 continuous hours. Following are the summary statistics:

x =13.6 hours,

s =1.3 hours

Report the test statistic, p-value, your decision regarding the null hypothesis, and your conclusion about the original claim. Round all values to the nearest thousandth.

a)  z = 1.946; p = 0.029; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last less than 14 hours.

b) t = -1.946; p = 0.029; Fail to reject the null hypothesis; there is not strong evidence to suggest that the highlighters last less than 14 hours. o

c)  t= -1.946; p = 0.029; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last less than 14 hours.

d) z = 1.946; p = 0.974; Fail to reject the null hypothesis; there is not “strong evidence to suggest that the highlighters last less than 14 hours.

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