El butano, C4H10, se quema en presencia de oxígeno gas, O2, y se produce dióxido de carbono, CO2, y agua. ¿Cuántos kg de CO2 se obtendrán al quemarse 12 kg de butano?

Answers

Answer 1

Answer:

don't know really and don't know at alll


Related Questions

Butane C4H10, is an easily liquedfied gaseous fuel. calculate the density of butane gas at 0.897 atm and 24°C. give the answer in grams per litre​

Answers

Answer:

Density = 2.137 gram per liter (Approx.)

Explanation:

Given:

Gaseous fuel Butane C4H10

Pressure = 0.897 atm

Temperature = 24°C = 24 + 273 = 297 k

Find:

Density of butane gas

Computation:

We know that molar mass of butane = 58.12 g/mol

Density = [molar mass x pressure] / Rt

Density = [58.12 x 0.897] / [0.0821 x 297]

Density = [52.13] / [24.3837]

Density = 2.137 gram per liter (Approx.)

What mass of HF is produced according to the given equation when 2.397 grams of each reactants are combined?

CaF2 + H2SO4 --> CaSO4 + 2HF​

Answers

+HF is the answer

Explanation:

molar absorptivity!
Us Aniline. CH, NH, when reacted with picric acid gives a derivative with a molar ab-
sorptivity of 13 cm E' lat 359 7. What would be the absorbance of a 1.00 x
10" solution or reacico aniline in a 1.00-cm cell? Al 25​

Answers

Answer:

baba

Explanation:

ndjshddjdjshshshsushs

What
is the major engine driving the planet's constant evolution and contains a geological record of much of the Earth's history

1. Mantle
2. Crust
3. Inner Core
4. Outer Core

Answers

Mantle I’m pretty sure
The mantle or inner core Is the answer


11. Beh, has no lone pairs of electrons. What's the structure of this molecule?
O A. Tetrahedral
O B. Octahedral
O C. Linear
D. Bent

Answers

Bent is the right answer did quiz
C) linear is the structure of this molecule

What volume of 0.686 M HCl would contain 0.037 moles of solute?

Answers

Given :

Molarity of HCl solution, M = 0.686 M.

Number of moles, n = 0.037 moles.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

[tex]M = \dfrac{Number \ of \ moles \ of \ solute}{Volume \ in \ liter}\\\\0.686 = \dfrac{0.037}{V}\\\\V = \dfrac{0.037}{0.686}\ L\\\\V = 0.053935 \ L \\\\V = 53.94 \ ml[/tex]

Hence, this is the required solution.

What are quarks?
A. Particles that bind gluons together within the nucleus
B. Radioactive material that is emitted from a nucleus
C. Subatomic particles that make up protons and neutrons.
D. Fundamental forces acting between two pieces of matter

Answers

Answer:

D. Fundamental forces acting between two pieces of matter

Answer:

D. Fundamental forces acting between two pieces of matter

which functional group does the molecule below contain

Answers

Answer:

All functional groups in organic chemistry

Functional groups include: hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.

Hope this helps Have a good day

can u pls help me i need the answer ASAP

Answers


The answer is c ( to disturbance heat

in any chemical reaction each type of atom is conserved​

Answers

Answer:

Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction. The law of conservation of mass states that the total mass of substances taking part in a chemical reaction is conserved during the reaction.

If the temperature decreases, then the pressure will​

Answers

then the temperature decreases.

A single ___ bond is made when two atoms share a pair of ____

Answers

Answer:

covalent

valence electrons

Explanation:

The attraction between two atoms that share a pair of valence electrons is known as a covalent bond. The nuclei of both atoms are drawn to the shared electrons. This results in a molecule with two or more atoms. Covalent bonds are formed solely between nonmetal atoms.

Between atoms of the same element or between atoms of different elements, covalent bonds can form. A new substance termed a covalent compound is formed when atoms of various elements create covalent bonds.

A sample of aluminum absorbed 9.86 J of heat and its temperature increased from 23.2 and 30.5 degrees * C . What is the mass of the aluminum? Th specific heat of aluminum is 0.902 J/g^ C . Round your answer to 2 significant figures. Do not include units in your answer. *

Answers

Explanation:

H=mc×∆©

9.86=m×0.902×(30.5-23.2)

m=1.5

Explanation:

The specific heat of a substance is the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius. The formula for calculating the heat absorbed or released by a substance is `q = mcΔT`, where `q` is the heat absorbed or released, `m` is the mass of the substance, `c` is the specific heat of the substance, and `ΔT` is the change in temperature.

In this case, we can use this formula to solve for the mass of the aluminum sample. We know that `q = 9.86 J`, `c = 0.902 J/g°C`, and `ΔT = 30.5°C - 23.2°C = 7.3°C`. Plugging these values into the formula, we get:

`9.86 J = m * 0.902 J/g°C * 7.3°C`

Solving for `m`, we find that the mass of the aluminum sample is approximately `1.5 g`, rounded to 2 significant figures.

PLEASE mark as Brainliest

How are the stratosphere and the mesosphere similar

Answers

Answer:

stay safe healthy and happy...

A yellow powder and a blue liquid are shaken together in a test tube to produce a clear green mixture that is all liquid.

Which of the following best describes the behavior of the above pair of substances?

Answers

Answer:

hkj

Explanation:

Plz help Will mark brainliest

Answers

Answer:

H

Explanation:

UMMM H2O .. im assuming the H missing

An electron in a hydrogen atom moves from level 1 to level 4. The electron then drops from level 4 to level 2. Which
statement describes the most likely result?
The energy absorbed in the first move equals the energy released in the second move.
The energy absorbed in the first move is greater than the energy released in the second move.
O The energy released in the first move equals the energy absorbed in the second move.
The energy released in the first move is greater than the energy absorbed in the second move.

Answers

Answer:

Your answer would be B because In the first move energy was absorbed, because when energy is gained an electron moves to a higher energy level in the second move energy will be released because that is how an atom moves to a lower energy level.  The jump from level 1 to 4 was bigger than the drop from 4 to 2, because in the first move it moved from more orbitals. thus describing the the energy in the first move had a far energy released in the second move.

Using the periodic table as a reference, which pair of elements are nonmetals?

A. oxygen and sulfur

B. cobalt and zinc

C. mercury and lead

D. sodium and iodine

Answers

Answer:

A). oxygen and sulphur

Non metals are on the right side of the periodic table they are generally in the gaesous form there are as many as 20 non metals in the periodic group ( including halogens and noble gas). non metal are electron withdrawning groups and they generally forms anion they are poor conductors of heat and electricity

Which waves are blocked by the atmosphere? A. gamma rays B. visible light C. radio waves D. infrared waves​

Answers

Answer: look at the explanation and try to work it

Explanation: in contrast, our atmosphere blocks most ultraviolet light (UV) and all X-rays and gamma-rays from reaching the surface of Earth. Because of this, astronomers can only study these kinds of light using detectors mounted on weather balloons, in rockets, or in Earth-orbiting satellites.

Concentrated aqueous perchloric acid is 70.5 wt% HClO4 and has a concentration of 11.7 M. Calculate the volume of concentrated perchloric acid that should be diluted to 1.90 L to form a 5.00 M HClO4 solution.

Answers

Answer:

0.812 L

Explanation:

As this is a dilution process problem, we can solve it by using the C₁V₁ = C₂V₂ formula, where in this case:

C₁ = 11.7 MV₁ = ?C₂ = 5.00 MV₂ = 1.90 L

We input the data:

11.7 M * V₁ = 5.00 M * 1.90 L

And solve for V₁:

V₁ = 0.812 L

This means that 0.812 L of concentrated perchloric acid should be diluted to a final volume of 1.90 L.

What transition energy corresponds to an absorption line at 460 nm?
A. 6.52 x 10-19 J
B. 4.32 x 10-19 J
C. 4.45 x 10-19 J

D. 2.31 x 10-19 J

Answers

The answer is b I think I hope it right

Answer:

B. 4.32 x 10-19 J is correct via a p e x

Explanation:

how many moles of potassium+hydroxide+would+react+with+one+mole+of+hydrocloric acid

Answers

Answer:

1 mole of potassium hydroxide, KOH

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

KOH + HCl —> KCl + H₂O

Considering the balanced equation above, we can see clearly that 1 mole of potassium hydroxide, KOH reacted with 1 mole of hydrochloric acid, HCl.

Therefore, we can conclude that at every given point, 1 mole of potassium hydroxide, KOH is required to react with 1 mole of hydrochloric acid, HCl.

why the environment in most communities continue to be dirty 2×8

Answers

Environments continue to be more dirty due to environmental factors and society around us.

Write a balanced chemical equation for the reaction. Na2CO3Na2CO3 and AgNO3AgNO3 Express your answer as a chemical equation. Identify all of the phases in your answer.

Answers

Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Explanation:

The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.

[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]

Here, number of atoms present on reactant side are as follows.

Na = 2[tex]CO_{3}[/tex] = 1Ag = 1[tex]NO_{3}[/tex] = 1

Number of atoms present on product side are as follows.

Na = 1[tex]CO_{3}[/tex] = 1Ag = 2[tex]NO_{3}[/tex] = 1

To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.

Hence, the equation can be rewritten as follows.

[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]

Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.

Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Answer:

2

Explanation:

According to one acid-base theory, water can act as a base because a water molecule can

1) donate an H+ ion
2) accept an H+ ion
3) donate an H- ion
4) accept an H- ion

Answers

Answer:

1) donate an H+ ion

Explanation:

option 1 is correct

Positive or negative , guys?

Answers

I think it’s positive

1. For the reaction 3A — C, the initial concentration of A was 0.2 M, and the reaction rate was
1.0 M/s. When [A] was doubled, the reaction rate increased to 4.0 M/s. Determine the rate
law for the reaction.

Answers

Answer:

[tex]r=25M^{-1}s^{-1}[A]^2[/tex]

Explanation:

Hello there!

In this case, according to the given information for this chemical reaction, it is possible for us to set up the following general rate law and the ratio of the initial and the final (doubled concentration) condition:

[tex]r=k[A]^n\\\\\frac{r_1}{r_2} =\frac{k[A]_1^n}{k[A]_2^n}[/tex]

Next, we plug in the given concentrations of A, 0.2M and 0.4 M, the rates, 1.0 M/s and 4.0 M/s and cancel out the rate constants as they are the same, in order to obtain the following:

[tex]\frac{1.0}{4.0} =\frac{0.2^n}{0.4^n}\\\\0.25=0.5^n\\\\n=\frac{ln(0.25)}{ln(0.5)} \\\\n=2[/tex]

Which means this reaction is second-order with respect to A. Finally, we calculate the rate constant by using n, [A] and r, to obtain:

[tex]k=\frac{r}{[A]^n} =\frac{1.0M/s}{(0.2M)^2}\\\\k=25M^{-1}s^{-1}[/tex]

Thus, the rate law turns out to be:

[tex]r=25M^{-1}s^{-1}[A]^2[/tex]

Regards!

why did researchers at the university of Antwerp study high speed videos of the black woodpecker​

Answers

here's your answer..

A chemist adds of a magnesium fluoride solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to significant digits.

Answers

The given question is incomplete, the complete question is:

A chemist adds 35.0mL of a 6.19 * 10^−4/mmol magnesium fluorideMgF2 solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to

3 significant digits.

Answer:

The correct answer is 1.35 microgram.

Explanation:

Based on the given information,

The volume of magnesium fluoride given is 35 ml, and the concentration of magnesium fluoride is 6.19 × 10⁻⁴ mmol/L.

Now the moles of MgF₂ can be determined by using the formula,

Moles = Concentration × Volume

Moles of MgF₂ = Concentration of MgF₂ × Volume of MgF₂

= 6.19 × 10⁻⁴ mmol/L × 35 ml × L/1000 ml

= 217 × 10⁻⁷ mmol

The molecular mass of magnesium fluoride is 62.3 gram per mole

Thus, the mass of MgF₂ is,

= 217 × 10⁻⁷ mmol × 62.3 g/mol

= 13500 × 10⁻⁷ mg

= 1.35 microgram

How much energy is released when 6.0 g of water is condensed from water
vapor?
A. 6.0 g x 1 mol/18.02 g x 4.186 kJ/mol
B. 6.0 g 1 mol/18.02 g 6.03 kJ/mol
O C. 6.0 g x 1 mol/18.02 g * (-285.83 kJ/mol)
O D. 6.0 g x 1 mol/18.02 g x 40.65 kJ/mol

Answers

Answer: 6.0g x 1 mol/18.02g x 40,65 kJ/mol which is D

Explanation: Just did

The water vapors change from vapor into water in condensation. The energy released by 6 gm of water is 6.0 g x 1 mol/18.02 g x 40.65 kJ/mol. Thus, option D is correct.

What is the heat of vapourization?

The heat of vapourization is the latent heat or enthalpy needed by the liquid to get converted into the vapor or the gaseous phase of the matter. It can be used to determine the energy released or absorbed by the substance.

The heat of vapourization of water is 40.65 kJ/mol, and its molar mass is 18.02 moles.

So, the energy released for the water when it is condensed into vapors will be,

6.0 g x 1 mol/18.02 g x 40.65 kJ/mol

Therefore, the heat of vapourization determines the amount of energy released.

Learn more about the heat of vapourization here:

https://brainly.com/question/14741853

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