During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the hanging masses and other forces present is 0.91 J. At the initial time of observation the cart moves with speed 0.61 m/s. Determine the speed at the second point of observation. The mass of the cart is 0.80 Kg.

Answers

Answer 1

Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

KE₀ + W = KE₁

½mv₀² + W = ½mv₁²

½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²

v₁ = 1.626991...

v₁ = 1.6 m/s

Answer 2

The speed of the cart at the second point of observation is equal to 1.62 m/s.

What is the work done?

Work can be demonstrated as the energy utilized when a force is exerted to make an object move through a particular displacement. Work done by this force is calculated from the product of the magnitude of the exerted force (F) and the distance (d) covered by the body

W= F.d

Where 'F' is the exerted force and 'd' is the displacement and W is work done.

Work and energy have a direct relationship with each other. Work done by an object can be expressed as a change in kinetic energy:

[tex]W =\frac{1}{2}mv_2^2- \frac{1}{2}mv_1^2[/tex]

Where m is the mass of the object, v₂ is the final velocity (m/s), and v₁ is the initial velocity (m/s).

Given, the work done by the cart, W = 0.91 J

The mass of the cart, m = 0.80 Kg

The speed of the cart at the first point, v₁ = 0.61 m/s

[tex]0.91 =\frac{1}{2}\times 0.80 \times v_2^2- \frac{1}{2}0.80 \times (0.61)^2[/tex]

0.40 v₂² = 1.06

v₂² = 2.65

v₂ = 1.62 m/s

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Related Questions

what is the acceleration of a 10 kg mass pushed by a 5N force?

Answers

Answer:

0.5

Explanation:

F = ma

5 = 10 a

a = 5/10

a = 0.5

Condyloid joints are, logically enough, created by joints at condyle bone markings.
True or False

Answers

Answer: False

Explanation:

It's received in elliptical cavities.

False. The statement is not entirely accurate. Condyloid joints are a type of synovial joint that allow movement in two planes, similar to an ellipsoid joint.

These joints are characterized by an oval-shaped projection of one bone fitting into an elliptical cavity of another bone. The term "condyle" does refer to a rounded projection or bump on a bone, but not all condyle bone markings create condyloid joints.

Condyloid joints are found in various parts of the body, such as the wrist (between the radius and carpal bones) and the knuckles (between the metacarpal bones and phalanges). They allow for movements such as flexion, extension, abduction, adduction, and circumduction.

It's important to note that the formation of a condyloid joint involves not only the presence of condyle bone markings but also the specific structural arrangement of the bones and the presence of articular cartilage, joint capsule, and synovial fluid. Therefore, while the term "condyle" is related to these joints, it does not accurately capture the complexity of their formation and function.

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9. The acceleration (a)-time (t) graph of a particle moving in a straight line is as shown in figure. At time t = 0, the velocity of particle is 10 m/s. What is the velocity at t = 8 s?
(1) 2 m/s
(2) 4 m/s
(3) 10 m/s
(4) 12 m/s​

Answers

Answer:Acceleration - time graph for a particle moving in a straight line is as shown in figure. Change in velocity of the particle from t = 0 to t = 6s is:-.

1 answer

·

Top answer:

Change in velocity = (sum of area of graph) = ( 12 × 4 × 4 ) + ( 12 × ( + 2) ( - 1) ) - 4 = 8 - 4 = 4 x

Explanation:

What diameter telescope is needed to resolve the separation between an Earth-like planet and its star at 550 nm if the linear separation between them is 1 AU and the star system is 3 pc from Earth

Answers

The Rayleigh criterion allows finding the result for the diameter of the telescope that allows solving the separation of the star and the planet is:

The diameter of the telescope is D = 0.415 m

The Rayleigh criterion is used to find the separation of two points, it is based on the fact that the diffraction maximuum pattern of the first object coincides with the first minimum of the second object.

By entering in the diffraction ratio for slits you will find.

           sin θ  = [tex]\frac{\lambda}{a}[/tex]  

In general in diffraction experiments the angles are very small,

           [tex]tan \theta = \frac{y}{x} = \frac{sin \theta}{cos \theta} \\sin \theta = \frac{y}{x}[/tex]

 

For the case of circular apertures, when solving in polar coordinates, a constant appears.

 

        [tex]\frac{y}{x} = 1.22 \frac{\lambda}{D}[/tex]

       [tex]D = 1.22 \frac{\lambda \ x}{y}[/tex]

Where λ is the wavelength of light and D is the diameter of the aperture.

They indicate that the separation between the star and the planet is 1 AU and the distance from the system to the Earth is 3 parce.

Let's reduce the parce to astronomical units

       x = 3 pc (  [tex]\frac{206264 AU}{1 pc}[/tex] )

       x = 6.18 10⁵ AU

Let's calculate

          D = [tex]D = 1.22 \ \frac{550 \ 10^{-9 } \ 6.18 \ 10^5 }{1}[/tex]  

          D = 0.415  m

In conclusion, using the Rayleigh criterion we can find the result for the diameter of the telescope that allows solving the separation of the star and the planet is:

 The diameter of the telescope is D = 0.415 m

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In an earlier chapter you calculated the stiffness of the interatomic "spring" (chemical bond) between atoms in a block of lead to be 5 N/m. Since in our model each atom is connected to two springs, each half the length of the interatomic bond, the effective "interatomic spring stiffness" for an oscillator is 4*5 N/m = 20 N/m. The mass of one mole of lead is 207 grams (0.207 kilograms).
What is the energy, in joules, of one quantum of energy for an atomic oscillator in a block of lead?

Answers

Answer:

8.01e-22

Explanation:

The energy of one quantum of energy for an atomic oscillator in a block of lead is 0.102 J.

Extension produced by one mole of lead

The extension produced by one mole of lead atom is calculated by applying Hooke's law;

F = kx

mg = kx

x = mg/k

x = (0.207 x 9.8) / (20)

x = 0.101 m

Energy stored in the lead block

The Energy of one quantum of energy for an atomic oscillator in a block of lead is calculated as follows;

E = ¹/₂kx²

E = ¹/₂ (20)(0.101)²

E = 0.102 J

Thus, the energy of one quantum of energy for an atomic oscillator in a block of lead is 0.102 J.

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Pls help, I really need it and plz show steps I will give brainliest..

Answers

Answer:

21.31 meters

Explanation:

Since we're working with gravitational potential energy (GPE):

GPE (Joules) = mass (kg) * gravity (m/s^2) * height (meters)

1. Figure out what we have:

GPE = mass * gravity * height

We're looking for height, and we have the other three, so we're set to move on.

2. Isolate the unknown variable (height):

(GPE) / (mass * gravity) = height

3. Plug in your numbers:

(3.78 * 10^7 J) / ((1.81 * 10^5 kg) * (9.8 m/s^2)) = 21.31 meters

Question 3 of 20 :
Select the best answer for the question.
3. Which of the following accurately describes the behavior of water when subjected to
temperature change?
A. The volume of water will decrease if heated from 6°C to 7°C.
B. The volume of water will increase if cooled from 3°C to 2°C.
O C. A mass of water will contract if cooled from 1°C to 0°C.
D. A mass of water will expand if heated from 0°C to 2°C.

Answers

As water cools the volume expands.

Answer: B. The volume of water will increase if cooled from 3°C to 2°C.

I was in Anchorage Alaska during the Summer Solstice. The sun rose around 3am and set around 1 am the next day-- almost 24 hours of sunlight. If the tilt of the Earth was changed to be 10 degrees, how would the length of daylight in Alaska change at the Summer Solstice

Answers

Answer:

Daylight hours would be shorter.

Explanation:

If there were no tilt of the axis at all, every place on the planet except the north and south poles would have 12 hours of daylight and 12 hours of night every day of the year.

At a 10° tilt, the arctic circle and antarctic circles would be a little less than half the distance from the poles as they are today.

please help asap 100 POINTS and BRAINLIEST to best answer.

Answers

D. :)

lmk if im right or wrong

Answer:

D. 5ºC

Explanation:

Not B, because 1k= -457.87 fahrenheit. That means it is also not C. Since the icicles are melting, then that means it is not A either.

5ºC=about 41ºF

When an alpha particle is emitted from an unstable nucleus, what happens to the atomic number of the nucleus

Answers

Answer:

The answer to your question is the number decreases by 4.

Explanation:

I hope this helps and have a great day!

please answer fast in hindi ​

Answers

Answer:

1. Dheere Dheere (slowly slowly)

2. Har (every)

3. Kal (tomorrow)

4. Mat (don't)

5. Andar (inside)

sorry I wasn't able to write in hindi

10. What is Newton's 3rd Law?
O A. For every action there is an equal and opposite reaction.
B. Acceleration depends on two variables, the mass of the object and the amount of
force.
C. An object at rest will stay at rest, an object in motion will stay in motion, unless an
unbalanced force acts upon it.
D. The amount of matter in an object.
7. What is Newton's 2nd Law? *

Answers

Answer:

A. For every action there is an equal and opposite reaction.

Newton’s 3rd law is A. For every action there is an equal and opposite reaction.

Newton’s 2nd law is B. Acceleration depends on two variables, the mass of the object and the amount of force. (Acceleration = force/mass)

Question below...........................

Answers

[tex]\boxed{\sf PE=mgh}[/tex]

[tex]\boxed{\sf KE=\dfrac{1}{2}mv^2}[/tex]

[tex]\boxed{\sf ME=KE+PE}[/tex]

#1

[tex]\\ \sf\longmapsto PE=60(0)(10)=0J[/tex]

[tex]\\ \sf\longmapsto KE=\dfrac{1}{2}(60)(8)^2=30(64)=1920J[/tex]

[tex]\\ \sf\longmapsto ME=1920+0=1920J[/tex]

#2

[tex]\\ \sf\longmapsto PE=60(10)(1)=600J[/tex]

[tex]\\ \sf\longmapsto KE=600J[/tex]

[tex]\\ \sf\longmapsto ME=1200J[/tex]

Now

[tex]\\ \sf\longmapsto \dfrac{1}{2}mv^2=600\implies 30v^2=600\implies v^2=20\implies v=4.2m/s[/tex]

A less than youthful 82.6 kg physics professor decides to run the 26.2 mile (42.195 km) Los Angeles Marathon. During his months of training, he realizes that one important component in running a successful marathon is carbo-loading, the consumption of a sufficient quantity of carbohydrates prior to the race that the body can store as glycogen to burn during the race. The typical energy requirement for runners is 1 kcal/km per kilogram of body weight, and each mole of oxygen intake allows for the release of 120 kcal of energy by oxidizing (burning) glycogen.
(a) If the professor finishes the marathon in 4:45:00 h, what is the professor's oxygen intake rate, in liters per minute, during the race if he metabolizes all of the carbo-loaded glycogen during the race and the ambient temperature is 21.5°C? 2.28 Read the problem statement again carefully. Is the air at standard temperature and pressure during the marathon? How would this affect the volume of 1 mol of oxygen? L/min
(b) The human body has an efficiency of 25.0%. Only 25.0% of the energy released from oxidizing glycogen is used as macroscopic mechanical energy, and the remaining 75.0% is used for body processes such as pumping blood and respiration, and then leaves the body through the skin via radiation, evaporative cooling, and other processes. What is the average mechanical power (in W) generated by the professor during the run? 197.561 What is the total energy required by the professor during the run? How efficient is the human body, and how long did the race last? W
(c) What is the change in entropy (in J/K) of the professor's body if his core temperature has risen to 38.3°C during the run and his skin temperature is at 36.0°C during the marathon? J/K
(d) What is the change of the entropy (in J/K) of the air surrounding the professor during the race if the ambient temperature remains constant at 21.5°C? J/K

Answers

Mem me e m even have. Jags. Shah. Shiv side esicjm is n meh dish so do indbbd

PLEASE HELP ME GET THIS RIGHT

Answers

Explanation:

I'm not sure, but I would go for the more than A since its orbital speed is at its fastest and the sweep occurs in about the same period of days.

Christianity's aim is to produce​

Answers

Answer:

Christianity is an Abrahamic, monotheistic religion based on the life and teachings of Jesus, Christians believe that God created the Earth and everything that lives on it.

Explanation:

Or something related like this but the point is christianity was based in the belief of god and spread it by their words and the methods they had.

What is the possible resultant of a 2-unit vector and 4-unit vector?

Answers

Answer:

Explanation:

resultant could have magnitude 4 - 2 ≤ V ≤ 4 + 2 or 2 ≤ V ≤ 6

If θ is the angle of the 4 unit vector, the resultant could have angle φ in the range of

φ = θ ± arcsin (2/4)

θ - 30° ≤ φ ≤ θ + 30°

The possible resultant of a 2-unit vector and 4-unit vector is 6 and 2.

What is a Unit vector?The quantity which has both the magnitude and direction is known as vector.The Examples for Vector quantity is Acceleration, velocity, force and displacement, etc.,.The quantity which has only the magnitude but has no direction, (examples include speed, time and distance) can be known as scalar.

If the magnitude of vector is 1, then it can be the Unit vector.

In the Unit vector, x axis will have the vector of i, y axis will have the vector j, z axis will have the vector k.

When two vectors are in same direction then we add up to get their resultant and in this case resultant would be maximum

R = A + B

R = 4 + 2

R = 6

If vectors are in opposite direction then they provide minimum resultant and in this case we subtract them

R = A - B

R = 4 - 2

R = 2

Thus, the possible resultant are 6 and 2.

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in vacuum , the shorter the wavelength of an electromagnetic wave is , the:
A. lower its frequency
B. higher its energy
C. longer its period
D. slower its speed

Answers

Answer:

Higher its Energy

Explanation:

13. Which of the following lines (of latitude or longitude) would be represented by 0° Latitude?
14. Which of the following lines (of latitude or longitude) would be represented by 90° North
Latitude?
15. Which of the following lines (of latitude or longitude) would be represented by 90° South
Latitude?
16. Which of the following lines (of latitude or longitude) would be represented by 0° Longitude?

a. south pole b. equator c. prime meridian d. north pole

Answers

Answer:

14. Which of the following lines (of latitude or longitude) would be represented by 90° North  Latitude?

ANSWER: D. North Pole

15. Which of the following lines (of latitude or longitude) would be represented by 90° South  Latitude?

ANSWER: A. South Pole

16. Which of the following lines (of latitude or longitude) would be represented by 0° Longitude?

ANSWER: C. Prime Meridian

Answer:

A

Explanation:

i mark u brainliest answer please answer me​

Answers

Answer:

bathing and wear clean clothes 2 pollute 3throwing waste in land air water pollution

a wave travels at a constant speed. how does the wavelength change if the frequency is reduced by a factor of 3? assume the speed of the wave remains unchanged.
A. the wavelength decreases by a factor of 3
B. the wavelength does not change
C. the wavelength increases by a factor of 3
D. the wavelength increases by a factor of 9

Answers

Answer:

b

Explanation:

when the wavelength increase it doesnt affect the frequency of a wave.

Answer: The wavelength increases by a factor of 3

Explanation:

Calculate the amount of work done (in joules) to raise the 0.2kg mass 0.5 m

Answers

Answer:

1

Explanation:

A=mgh=0.2*10*0.5=1 J

PLEASE HELP BRAINLIEST TO THE RIGHT ANSWER!!!!!
A 7.8 kg object is suspended by a string from the ceiling of an elevator. The acceleration of gravity is 9.8 m/s^2.

A. Determine the tension in the string if it is accelerating upward at a rate of 1.5 m/s^2. Answer in units of N.

B. Determine the tension in the string if it is accelerating downward at a rate of
1.5 m/s^2

Answers

Gravitational pull downward on the object:  7.8 x 9.8 = 76.44N

A. 7.8 x 1.5 = 11.7N upward force

Tension = 76.44 + 11.7 =  88.14 N

Answer: 88.14 N

B. 76.44 - 11.7 = 64.74N

Answer: 64.74 N

Answer:

88.14 N

64.74 N

Explanation:

‏Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day? a) 1.25 O b) 1.5 c) 1 O d) 2
I think the answer is a but I'm not sure I'm really a little confused I want to check with this app please can someone heelp me

Answers

Answer:

c

Explanation:

It really depends on what the stuff is. This should not be a math or physics question.

Having said that, I answer it by rounding it to 1.       1.04 is closest two one.

That is not entirely a satisfactory answer. Most people who take medications have pill splitters. They easily cut a pill in half. They can do this only if a the medicine's directions, or a pharmacist, or a doctor tells you can do this. Cutting it into quarters should never be done.

So a is really incorrect medically.

1.5 is too far away

C is probably the intended answer; it would annoy me no end if it was anything but c. If this was just a rounding question, it rounds to c. There is no medication that requires an intake of 1.04. No one could get that kind of accuracy.

2 is really too far away.

HELP ME PLEASE I DONT GET THIS

Answers

the answer will be B.
The Answer is B oooo

Example 4.16
An object of mass 3 kg rests on a plane. The coefficient of static friction and that of kinein
friction are given by Hs = 0.3 and pk = 0.2.
The plane is inclined at angle o to the horizontal.
(i) Find the maximum value of 0 for which the object remains at rest on the plane.
(ii) Find the acceleration of the object if it started sliding from rest down the plane at
angle Omax to the horizontal.
(ii) How long does it take the object to move, from rest, a distance of Imetre under the
conditions of (ii).

Answers

Answer:

Explanation:

(i) μs = F/N = mgsinθ/mgcosθ = tanθ

  tanθ = 0.3

  θ = 16.7°

(ii) a = F/m

    a = (mgsinθ - (μk)mgcosθ) / m

    a = g(sinθ - (μk)cosθ)

    a = 9.8(sin16.7 - (0.2)cos16.7)

    a = 0.94 m/s²

(iii) s = ½at²

     t = √(2s/a)

     t = √(2(1)/0.94)

     t = 1.5 s

7. A 1.0 kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0 m/s. Assuming all the energy is retained by the hammer head, how much will its temperature increase

Answers

The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

mass of the metal hammer, m = 1.0 kgspeed of the hammer, v = 5.0 m/sspecific heat capacity of iron, 450 J/kg⁰C

The increase in temperature of the metal hammer is calculated as follows;

[tex]Q = K.E\\\\mc \Delta T = \frac{1}{2} mv^2\\\\\Delta T = \frac{v^2}{2 c}[/tex]

where;

c is the specific heat capacity of the metal hammer

Assuming the metal hammer is iron, c = 450 J/kg⁰C

[tex]\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C[/tex]

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

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What is the neutron number for 75 32Ge?

Answers

Answer:

If the mass of geranium is 75 and the atomic number is 32 then it must have

N = 75 -32 = 43 neutrons

Is carbon a source or a sink of energy? Why?

Answers

Carbon is the source of energy

Carbon-Based Fuels Dominate Global Energy Use

Crude oil, coal, and natural gas supply about 85% of the energy used in the world. Fossil fuels are valuable as sources of energy because they contain hydrocarbons and other carbon-based materials.

what are people words in english

Answers

Answer: Plenty

Explanation:

some words are Hi, Banana, Dude and many more

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