Answer:
a) v₁ = - ½ v₂, K₁ / K ₂ = ½,)
Explanation:
A) Let's use the conservation of the moment, for this we define the system formed by the spring and the two cars, so the force during the separation is internal, therefore the moment is conserved
initial instant. Before releasing the carts
p₀ = 0
final instant. After jumping the cars
p_f = M v₁ + m v₂₂
how the moment was preserved
p₀ = p_f
0 = M v₁ + m v₂
v₁ = - m / M v₂
indicate that M = 2m
v₁ = - ½ v₂
the kinetic energy of each car is
K₁ = ½ M v₁²
K₁ = ½ 2m (v₂/ 2) ²
K₁ = m ₂v₂² / 4
K₂ = ½ m v₂²
the relationship between the kinetic energies is
K₁ / K₂ = ½
B) If the much greater than the mass of car 1 is mass of car 2
v = - m / M v₂
In this case, the speed of car 1 is very small, so the car 1 practitioner does not backtrack and car 2 leaves with a lot of speed.
The energy is still conserved, where almost all the energy has it is car 2
Please help me do this problem
Answer:
i) acceleration from B to D is 0, because the velocity is constant (stays the same)
ii) whatever units of distathat might be, we can calculate the number:
for 4 time-steps (2 to 6) the velocity is 6 per time step, that makes 24 distance units in these 4 time steps. it's the same the area underneath the graph.
there is also the vertical line from 0 to 2. we can calculate that distance like the area of a triangle with 2*6 / 2 = 6
the total distance from 0 to D is therefore 30
Wire B has twice the length and twice the radius of wire A. both wires are made from the same material. if wire A has a resistance R, what is the resistance of wire B?
Answer:
Hello There!!
Explanation:
1/2R because wire B has twice the radius,it has four times the cross-sectional area of wire A.
hope this helps,have a great day!!
~Pinky~
Molten iron has a density of 7.0 g/cm. In its solid state, iron has a density of
8.0 g/cm?
Calculate the volume of 10 kg of molten iron.
Volume =
Can someone help me :)
Answer:
undergone a chemical change
Explanation:
Answer:
undergone a chemical change
Which of earths spheres are involved in the water cycle
Answer:
All of the major spheres of the Earth are involved in the water cycle. The four spheres are the atmosphere, hydrosphere, lithosphere, and biosphere....
Explanation:
pa follow thanks ☺️
Which of earths spheres are involved in the water cycle ?
Hydrosphere, atmosphere, lithosphere, and biosphere are all sphere involved in the water cycle.What is Hydrosphere ?
Hydrosphere is a discontinuous layer of water at or near Earth’s surface. It includes all liquid and frozen surface waters, groundwater held in soil and rock, and atmospheric water vapour.What is atmosphere?
Atmosphere refers to the gases surrounding a star or planetary body held in place by gravity. ... The composition of the Earth's atmosphere is about 78 percent nitrogen, 21 percent oxygen, 0.9 percent argon, with water vapor, carbon dioxide, and other gases.What is lithosphere?
A lithosphere is the rigid, outermost shell of a terrestrial-type planet or natural satellite. On Earth, it is composed of the crust and the portion of the upper mantle that behaves elastically on time scales of thousands of years or greater.What is Biosphere?
The biosphere, also known as the ecosphere, is the worldwide sum of all ecosystems. It can also be termed the zone of life on Earth. The biosphere is virtually a closed system with regards to matter, with minimal inputs and outputs.#CarryOnLearning
#BrainliestBunch
-BrainliestUser
A trip is taken that passes through the following points in order
Point A Om
Point B 15.0 m
Point C -30.0 m
Point D 20.0 m
Point E -10.0 m
Point F 5.0 m
What is the displacement from Point B to Point E?
A) 5.0 m right
B) 85 m right
C) 25.0 m left
D) 85 m left
Answer:
The displacement from point B to point E is 25.0 m left
What is a sound wave?
What's scientific notation
1 kg of rice is weighed by
Answer:
beam balance
Explanation:
A beam balance compares the sample mass with a standard reference mass
When do we say that work is done?
Answer:
Work is said to be done when a force applied to an object moves that object. We can calculate work by multiplying the force by the movement of the object.
Answer:
Work is done by a force on an object if (i) a force acts on the object and (ii) the object is displaced from its original position
A ball at rest has a mass of 2.5 kg. Determine the force required to accelerate the ball to 2.5 m/s?
Answer:
6.25 N
Explanation:
F = ma
F = 2.5 × 2.5
F = 6.25 Newtons
1. Do you think that hand signals are important in officiating games? why?
Yeah, hand signals are important in officiating games. The hand signals are given by the referee who first signals the fault and then indicates which team has won the point. A point is indicated by one finger at the side of the court to indicate the winner of the rally.
How much pressure is created by a circular piston that is 0.24 meter in diameter
with a Force of 200.0 N? N/m2 ... (round answer to nearest ones place -no decimal)
Answer:
4000 N/m²
Explanation:
Area = πr²
Area = π x 0.12² (diameter/2)
Area = 0.05 m²
Pressure = force/area
Pressure = 200/0.05
Pressure = 4000 N/m²
Hope this helps!
What nuclear reaction is shown in the equation below
Answer:
nuclear fission
Explanation:
nuclear fission
Answer: Nuclear fission
Explanation:
What are the units for impulse?
m/s
Kg
Ns
Newtons
Answer:
Kg.m/s is the unit for impulse
Explanation:
If i were wrong please correct me.
Cuatro contenedores idénticos tienen la misma cantidad de gas helio a la misma temperatura inicial. Los recipientes también cuentan con un émbolo móvil que no permite que el helio escape. Cada muestra de gas sigue un proceso distinto como se describe a continuación: Muestra 1: 500 J de calor salen del gas y este realiza 300 J de trabajo. Muestra 2: 500 J de calor entran al gas y este realiza 300 J de trabajo. Muestra 3: 500 J de calor salen del gas y se hace un trabajo de 300 J sobre él. Muestra 4: 500 J de calor entran al gas y se hace un trabajo de 300 J sobre él.
Answer:
1) ΔE = -800 J, 2) ΔE = 200 J, 3) ΔE = -200 J, 4) ΔE = 800 J
Explanation:
For this exercise let's use the first law of thermodynamics
ΔE = Q + W
Where we will apply this expression to several cases
1) output Q = 500 J and does work of W = 300 J.
The two processes involve an energy output
ΔE = - 500 - 300
ΔE = -800 J
Therefore, the internal energy of the gas decreases by this amount,
2) enter Q = 500J and do work of W = 300 J
Positive heat is added and does negative work
ΔE = 500 - 300
ΔE = 200 J
3) they leave Q = 500 J and do (work on the gas) W = 300J
negative heat and positive work come out
ΔE = -500 + 300
ΔE = -200 J
4) heat enters Q = 500 J, work on gas W = 300 J
both positive
ΔE = 500 + 300
ΔE = 800 J
Tom is throwing an baseball at an aluminum can,
present an argument about the likely kinetic energy of the ball before and after.
describe the evidence that would support the argument.
present an argument about the likely kinetic energy of the can before and after.
describe the evidence that would support the argument.
Answer:
The question relates to the conservation of energy principle, the conservation of the linear momentum, and Newton's Laws of motion
Part A
1) Tom throwing a baseball at a can
The initial velocity of the baseball = v₂
The initial kinetic energy of the baseball, K.E.₂ = (1/2)·m₂·v₂²
∴ The final kinetic energy of the baseball, K.E.₂' = (1/2)·m₂·v₂'² < (1/2)·m₂·v₂²
Therefore, the energy of the ball before the collision is lesser than the energy of the ball after the collision
2) The evidence that would likely support the claim is that the baseball's height above the ground reduces rapidly immediately after the collision which is due to the reduced velocity, and therefore, the reduced (kinetic) energy
The final velocity of the baseball v₂' < v₂
Part B
1) The argument
The initial velocity of the can = v₁ = 0 (The can is initially at rest)
The initial kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² = 0
The final velocity of the can v₁' > v₁ = 0
∴ The final kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² > 0
Given that the velocity of the can increases from zero to a positive value after collision with the baseball, the kinetic energy of the can is increased from zero before the collision to a positive value after the collision
2) An evidence in support of the argument is the motion of the can which was initially at rest which is an indication of increase in energy podded by the can
Explanation:
In Einstein’s analysis, a photon striking the surface of a conductor is absorbed by an electron. Which statement describes the set of energy transfers that could occur?
A. the electron receives either all or none of the photon's energy
B. The electron may receive any fraction of the photon's energy, including all or none of it
C. The electron may receive only certain quantized amounts of the photon's energy, including all or none of it
Answer:
the correct answer is A
Explanation:
In an Einstein-type analysis, the photon is absorbed, it loses all its energy, therefore the electron must receive all or none of the energy of the incident photon. In a type of inelastic shock.
Let's analyze the different answers
A) true. In photon it is completely absorbed or passes without interaction
B) False. The photon must change energy, but in this case there is no absorption of the photon
C) False. In the insistent analyzes, the quantization of the electron in discrete states is not mentioned.
Therefore the correct answer is A
An object of mass 3kg was released from 40m above the ground. Using the conservation of energy, determine the velocity of the object right before hitting the ground.
Answer:
v=28m/s
Explanation:
Conservation of Energy
Ei=Ef
mgh= 1/2mv^2
9.8*40*2= v^2
784= v^2
v= 28m/s
The volume of a gas is halved during an adiabatic compression that increases the pressure by a factor of 2.5. By what factor does the temperature increase?
Answer: 1.24
Explanation:
Given
Volume becomes half and pressure increases by a factor of 2.5
In adiabatic process [tex]PV^{\gamma}=\text{constant}\ \text{or}\ TV^{\gamma}=\text{constant}[/tex]
Finding out [tex]\gamma[/tex] first
[tex]\Rightarrow PV^{\gamma}=2.5P(0.5V)^{\gamma}\\\\\Rightarrow \left(\dfrac{V}{0.5V}\right)^{\gamma}=2.5\\\\\Rightarrow 2^{\gamma}=2.5\\\\\text{Taking log both side}\\\\\Rightarrow \gamma=\dfrac{\ln (2.5)}{\ln (2)}\\\\\Rightarrow \gamma=1.32[/tex]
Applying same principle for Temperature
[tex]\Rightarrow TV^{1.32-1}=T'(0.5V)^{1.32-1}\\\\\Rightarrow T'=(2)^{0.32}T\\\\\Rightarrow T'=1.24T[/tex]
Thus, the temperature increases by a factor of [tex]1.24[/tex]
The factor by which the temperature increases is; 1.24
How to find increase in temperature in an adiabatic process?
In thermodynamics, an adiabatic process is one that happens when there is zero heat transfer between the system and its environment. Thereafter, the internal energy change becomes the total work done by the system. The formula associated with this process for an ideal gas is;
[tex]PV^{\gamma }[/tex] = Constant
We are told that there is an increase in pressure by a factor of 2.5 and that the volume is halved. Thus, we will have;
[tex]PV^{\gamma} = 2.5P(0.5V)^{\gamma}[/tex]
This will be simplified to;
[tex](\frac{1}{0.5})^{\gamma} = 2.5[/tex]
⇒ [tex]\gamma = \frac{In2.5}{In 2}[/tex]
γ = 1.32
Now, If the volume expands in an adiabatic process, then the volume temperature relation is expressed as:
[tex]T_{1}V_{1}^{\gamma - 1 } = T_{2}V_{2}^{\gamma - 1 }[/tex]
[tex]T_{1}V_{1}^{1.32 - 1 } = T_{2}(0.5V_{1})^{1.32 - 1 }[/tex]
Simplifying this gives;
T₁ = 1.24T₂
Read more about Adiabatic Process at; https://brainly.com/question/3962272
Mrs. Botts applies brakes on a car help it to decelerate at the rate of -0.80m/s2. What distance is required to stop the car when it is moving 17 m/s.
Answer:
Explanation:
vf=0
vi = 17
a = -0.8
Δx = ?
vf^2 = vi^2 + 2 a Δx
Δx = (vf^2 - vi^2) / 2a
Δx = (0-17^2) / 2 (-0.8)
Δx = 180.625 m
Using dimensional analysis prove that work = force x displacement
please answer to correct answer i will give 50 points
Answer:
Work = M1 L2 T^-2
Force =M1 L1 T^-2
displacement = L1
Work = F.ds
Work = M1 L1 T^-2 L1
work = M1 L2 T^-2
Liana draws a diagram to show the direction of the electric force acting on a charged particle in a uniform electric field.
Which change would make the diagram correct?
A. Changing the charge to negative
B. Making the field lines point down
C. Changing the force to point right
D. Removing the force arrow
Answer:
changing the force to point right is the correct answer :)
The direction of the force acting on the field should be changed to point towards the right.
What is an electric field?An electric field is referred to as the region where the influence of charge is felt. Thus, the force acts in the direction of the electric field when the field is uniform.
Having said that, it follows that the direction of the force acting on the field should be changed to point towards the right.
Learn more about electric field:https://brainly.com/question/15800304
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You might have noticed that a feather falls slowly toward the ground, while a ball falls rapidly. Which statement correctly explains the motion of these objects?
1. The ball does not experience fluid friction as it falls.
2. Gravity is the only force acting on the feather and the ball.
3.The acceleration of the ball and feather are the same.
4. The feather experiences more fluid friction than the ball.
Answer:
4. the feather experiences more fluid friction than the ball
hhhhhhhhhhhhhhhheeeeeeeeeeeeeeeeeeeeellllllllllllllllllllllllllllllllllpppppppppppp
Answer:
I'm pretty sure the answer is broken
Explanation:
¿Cuál es la presión que soporta un buzo sumergido a 10 metros de profundidad en el mar? Datos: Densidad del agua de mar = 1025 kg/m^3 Presión atmosférica 101325 Pa Y por que
Answer:
The pressure at the depth is 201775 Pa.
Explanation:
Depth, h = 10 m
density, d = 1025 kg/m3
atmospheric pressure, Po = 101325 Pa
The total pressure at the depth is
P = Po + h d g
P = 101325 + 10 x 1025 x 9.8
P = 101325 + 100450
P = 201775 Pa
can someone please help me with this question... thank u ❤️
Answer:
Which of the following... : constant velocity horizontal motion
A ball is thrown at certain... : 0 m/s
A crate of mass 2 kg is being pulled to the right across a rough horizontal surface by constant force F. The force F is applied at an angle of 20° to the horizontal, as shown in the diagram. how can l draw a labelled free body showing all force
Explanation:
Finding the (maximum) respective prime powers would yield the answer. Also we need not ... Is perfectly divisible by 720^n? ... So we can say that for any positive value of n it not
divisible.
A light ray strikes a reflective plane surface at an angle of 65º with the surface.
Answer the following questions (show your work)
1) Determine the angle of incidence.
2)Determine the angle made by the incident and reflected rays.
Answer:
65degrees
130degrees
Explanation:
In reflection, the angle of incidence(i) is the same as the angle of reflection (r)
Given that
Angle of reflection is 65degrees
Hence
i=r = 65degrees
Angle that angle made by the incident and reflected rays = i+r = 65+65
Angle that angle made by the incident and reflected rays = i+r = 130degrees
A rock from the top of a hill is falling from rest.
Object name?
Starting energy form?
Conversion?
Final energy form?
Non usable form of energy?
Object name:- Rock
Starting energy:- Kinetic energy
Conversion:- Potential to kinetic energy
Final energy form:- Potential energy
Non usable form if energy:- Nil [ As it has potential & kinetic both]