Directions: Name each polygon and tell if it is regular or irregular.

Answer: 30

Step-by-step explanation:

(Assuming the line is a tangent)

Answer:

difference quotient

Step-by-step explanation:

For the given linear system equations, the value for the variables are: x=-2, y=4, and z=-5 - Option C.

System of Linear Equations

System of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.

The question gives:

2x+y-5z=4 (1)

x+3y+z=5  (2)

3x-y-4z=-11 (3)

First, you should sum equations 1 and 2. The results will be:

3x+4y-4z=9 then you have a new equation (4).

3x-y-4z=-11 (3)

3x+4y-4z= 9(4)

Now, you should multiply equation (3) by -1, then you will have:

-3x+y+4z=+11 (3)

3x+4y-4z=9 (4)

After that, you should sum the previous equations: (3) and (4).

5y=20

y=4

For find z, you should multiply equation 2 by -2. After that, you should sum equations 1 and 2.

2x+y-5z=4 (1)

-2x-6y-2z=-10  (2)

Thus, you will have:

-5y-7z=-6, like y=4 you have

-5*4-7z=-6

-20-7z=-6

-7z=14

z=-2

If z=-2 and y=4 from equation 2, you can find x.

x+3y+z=5

x+3*4-2=5

x+12-2=5

x+10=5

x=5-10

x=-5

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Since 7y is common to both factors, therefore the GCF of the expression is 7y. The factored form will be 7y(3x + 2)

The greatest common factor is the value that will divide an expression without leaving a remainder.

Given the expression 21xy + 14y

Find the factors

21xy = 7 * 3 * x * y

14y = 7 * 2* y

From the factors above, it is clear that 7 and y are the greatest common factors.

Since 7y is common to both factors, therefore the GCF of the expression is 7y. The factored form will be 7y(3x + 2)

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Factor out

So

Now factor up

Option B

the scale says that each unit (cm/km/in/...) on the map is 150,000 times that unit so:

14cm on the map

= 150,000×14cm

= 2,100,000 cm

= 2100 km

(= 2.1 Mm)

Answer:

angleEAF=angleBAC (शिर्षभिमुख कोण भएर)

10x+90+5x=180 (सरल कोण भएर)

or, 15x+90=180

or, 15x=180-90

or, 15x=90

or, x=90÷15

or, x=4

Answer:

x=6

Step-by-step explanation:

90°+5x+10x=180°

90°+15x=180°

15x=180°-90°

15x=90°

x=90/15

=6

10×6=60

5×6=30

60°+30°=90°

90°+90°=180°

x=6 QED

If we need to turn this into a mathematical expression:

Answer: (x + y) - 9

Step-by-step explanation:

    9 less than the sum of x and y

    (the sum of x and y) - 9

    (x + y) - 9

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well, the total amount of technicians employed is 100% and that is "x" amount, now, we also know that 3% of of that is 10800, so

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x & 100\\ 10800& 3 \end{array} \implies \cfrac{x}{10800}~~=~~\cfrac{100}{3} \\\\\\ 3x=1080000\implies x=\cfrac{1080000}{3}\implies x=360000[/tex]

Answer:

5.5

Step-by-step explanation:

The longest string length is 12 3/4 (12.75)

The two shortest string lengths are 3 and 4 1/4 (4.25)

combine the length of the tow shortest string by adding them together,

3 + 4.25 = 7.25

to find how much longer the longest string you subtract the two numbers,

12.75 - 7.25 = 5.5

Answer:

14/29

Step-by-step explanation:

14/29 is the answer

Answer:

4500

Step-by-step explanation:

all of them were admitted.

Answer:

Step-by-step explanation:

You will need to know the   gram weight per mole from the periodic table for the element  ( or the molecule of elements) in question.

Answer:

5x2-2x+1 The highest exponent is the 2 so this is a 2nd degree trinomial.

Step-by-step explanation: Also pls answer by question

[tex]\\ \rm\Rrightarrow \dfrac{6}{x^2-3x}=\dfrac{12}{x}+\dfrac{1}{x-3}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{6}{x(x-3)}=\dfrac{12}{x}+\dfrac{1}{x-3}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{6}{x(x-3)}=\dfrac{12(x-3)+x}{x(x-3)}[/tex]

[tex]\\ \rm\Rrightarrow 6=12x-36+x[/tex]

[tex]\\ \rm\Rrightarrow 6=13x-36[/tex]

[tex]\\ \rm\Rrightarrow 13x=42[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{42}{13}[/tex]

Answer:

I have no clue, cant lie to you. God Bless you though.

Step-by-step explanation:

Answer: 10

Step-by-step explanation:

It appears that [tex]\overline{AC} \perp \overline{BC}[/tex], so to check if this is the case, we can use the slope formula.

[tex]m_{\overline{AC}}=\frac{3-1}{6-2}=\frac{1}{2}\\m_{\overline{BC}}=\frac{3-7}{6-4}=-2[/tex]

Since these slopes are negative reciprocals, we can see that this is the case. So, we can take [tex]\overline{AC}[/tex] as the base of the triangle and [tex]\overline{BC}[/tex] as the height of the triangle, and then use the formula [tex]A=\frac{1}{2}bh[/tex].

Using the distance formula,

[tex]AC=\sqrt{(6-2)^{2}+(3-1)^{2}}=\sqrt{16+4}=2\sqrt{5}\\BC=\sqrt{(4-6)^{2}+(7-3)^{2}}=\sqrt{4+16}=2\sqrt{5}[/tex]

So, the area is [tex]\frac{1}{2}(2\sqrt{5})(2\sqrt{5})=\boxed{10}[/tex]

So

Hence

Option A

Answer:

Option A

Step-by-step explanation:

y=4x+10

So

Put x ax 12°C

Hence

y=4(12)+10

y=48+10

y=58

[tex] \frac{1}{ \sqrt{1 - {(x - 1)}^{2} } } [/tex]

Answer:

E. 22

Step-by-step explanation:

Hello!

We know that b>6, and we are asked to find the possible values for 3b + 3.

Let's directly substitute 6 for b:

Now, because b is greater than 6, and not equal to 6, any value greater than 21 will work.

The correct option is E. 22.

Answer:

11.25

Step-by-step explanation:

6 3/4 + 4 1/2

Answer:

x = 10

Step-by-step explanation:

rewrite this equation with x on the left and numbers on the right

2x - 3x = 5 - 15

-x = -10

x=10

give brainliest, please!

hope this helps :)

The value of x is x = 10

To solve a first degree equation, first: we add or subtract like terms. Finally, we split the terms of both equalities.

- In this equation, we're going to subtract the like terms -- and on the other side of the equation, we're going to also subtract the real terms.

15 + 2x = 5 + 3x

2x - 3x = 5 - 10

-1x = -10

x = 10

So, the correct value is x = 10

Using the vertically opposite angles theorem and corresponding angles theorem, we have proven that alternate exterior angles are congruent

From the question, we are to prove that alternate exterior angles are congruent.

In the given diagram, examples of alternate exterior angles are

∠1 and ∠8

∠2 and ∠7

Now, we will prove that ∠1 = ∠8

In the diagram, we can observe that

∠1 = ∠4 (Vertically opposite angles theorem)

and

∠4 = ∠8 (Corresponding angles theorem)

Then,

By the substitution property of equality

∠1 = ∠8

Hence, alternate exterior angles are congruent

Here is the complete and correct question:

Consider parallel lines cut by a transversal. Parallel lines q and s are cut by transversal r. On line q where it intersects line r, 4 angles are created. Labeled clockwise, from uppercase left: angle 1, angle 2, angle 4, angle 3. On line s where it intersects line r, 4 angles are created. Labeled clockwise, from uppercase left: angle 5, angle 6, angle 8, angle 7.

Explain which theorems, definitions, or combinations of both can be used to prove that alternate exterior angles are congruent.

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Answer:

Step-by-step explanation:

Parallel lines q and q are cut by transversal r forming 4 angles at each intersection. At the intersection of lines r and q, clockwise from top left, the angles are: 1, 2, 4, 3. At the intersection of lines r and s, clockwise from top left, the angles are: 5, 6, 8, 7.

Use the diagram to complete the statements.

Angles 1 and 5 are

✔ congruent

because they are

✔ corresponding

angles.

Angles 4 and 6 are

✔ supplementary

because they are

✔ same-side interior

angles.

The equation of the line about which the quadrilateral is reflected will be y = x.

It is the image of the point which is located in the opposite direction of a given point.

The rule of the refection is given will be

Firstly, the rule for reflecting a point about the line y = x is;

While reflecting on the line y = x, we get the reflected points by swapping the coordinates.

First, draw the line on the graph. Then reflect each vertex of quadrilateral across the line to produce quadrilateral.

Vertex Preimage Coordinates                  Vertex Image Coordinates

          A (-3,-2)                                                           A' (-2,-3)

          B (-2,-1)                                                            B' (-1,-2)

          C (-1,-2)                                                            C' (-2,-1)

          D (-1,-4)                                                            D' (-4,-1)

The diagram is given below.

More about the reflection of the point link is given below.

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Answer:

D

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin45° = [tex]\frac{\sqrt{2} }{2}[/tex] , then

sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{x}{4}[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex] ( cross- multiply )

2x = 4[tex]\sqrt{2}[/tex] ( divide both sides by 2 )

x = 2[tex]\sqrt{2}[/tex]

Answer:

8

Step-by-step explanation:

I am good at math

Step-by-step explanation:

[tex] log_{5}(x + 9) = log_{5}(x + 5) + 1[/tex]

[tex] \frac{ log(x + 9) }{ log(5) } = \frac{ log(x + 5) }{ log(5) } + 1[/tex]

[tex] log(x + 9) = log(x + 5) + log(5) [/tex]

[tex] log(x + 9) = log(5x + 25) [/tex]

[tex]x + 9 = 5x + 25[/tex]

[tex]x = - 4[/tex]

If we plug it in, it is true