Determine the speed, wavelength, and frequency of light from a helium-neon laser as it travels through flourite. The wavelength of the light from the laser is 632.8 nm in air and the index of refraction of flourite is 1.434.

Answers

Answer 1

Answer and Explanation:

The computation is shown below:

As we know that

Frequency = Speed ÷ wavelength

= (3 × 10^8 )÷ (632.8 × 10^-9)

= 4.74 × 10^14 Hz

Speed in flourite is

= Vaccum speed ÷ refraction index

= 3 × 10^8 ÷ 1.434

= 2.092 × 10^8 m/s

wavelength is

= Speed in flourite ÷ frequency

= (3 × 10^8 × 632.8 × 10^-9) ÷ (1.434 × 3 × 10^8)

= 441.28nm


Related Questions

helpp please
ASAP...​

Answers

Answer:

I believe it to be option A

Explanation:

A 2 kg block is sitting motionless on a ramp at 24° with the horizontal. What is the force of friction on the block that resists its motion?

Answers

Answer:

7.97 N

Explanation:

[tex]f = m g sin(\alpha) = 2 * 9.8 * sin(24) = 7.97 N[/tex]

A water balloon is dropped off the top of a building and bursts when it hits
the ground 6 seconds later. What is the height of the building?

Answers

Answer:

The building is 176.4 meters high.

Explanation:

We use the formula for kinematics of an accelerated object (in this case acceleration of gravity):

Distance travelled = 1/2 g  t^2

Distance travelled = 1/2 9.8  (6)^2 = 176.4 meters

A car with a mass of 2,000 kg travels at 20 m/s. Which one has the greatest impulse?

Answers

Answer:2000kg

Explanation:

Convert it

If a small motor does 520 J of work to move a toy car 260 m, what force does the engine exert on the car?

Answers

Answer:

2 N

Explanation:

The force engine exert on the car can be found by using the formula

[tex]f = \frac{w}{d} \\ [/tex]

w is the workdone

d is the distance

From the question we have

[tex]f = \frac{520}{260} = 2 \\ [/tex]

We have the final answer as

2 N

Hope this helps you

A dynamite blast blows a heavy rock straight up from the ground with a launch velocity of 160ft/sec. a) Write the height function.

Answers

Answer:

y = 160t - 16t²

Explanation:

Using y = ut -1/2gt² where y = height of heavy rock above the ground, u = initial launch velocity of rock = 160 ft/s, g = acceleration due to gravity = 32 ft/s² and t = time.

So, substituting the values of the variables into y, we have

y = (160 ft/s)t -1/2 × 32 ft/s² × t²

y = (160 ft/s)t - (16 ft/s²)t²

y = 160t - 16t²

So, the height function is y = 160t - 16t²

Imagine you were lifting very heavy jugs to the top of a house. You can either use the stairs on the left or push them up the inclined plane on the right. Which option is easier

Answers

Answer:

Use the stairs

Explanation:

This is easier because if you go on the stairs you can rest if you get tired but if you go on the inclined plane then the weight of the jugs will make you slower than you already are and you may end up going back down instead of up where you wanna go.

What is the current in a 160V circuit if the resistance is 200?

Answers

V=120 v=IR
R=2ø
I = ? I= v/r
I= 120r/ 10
Answer 12Amps

A force can change an object's direction and cause friction
True or False

Answers

Answer:

This is very true

Explanation:

The force from impact can easily change it to expanse in a different direction.

I hope this helped you very much :)

which is not an insulator?
A wood
B plastic foam
C aluminum foil
D fiberglass

Answers

Answer:the answer is C aluminum foil

Explanation:

The intensity at a distance of 6 m from a source that is radiating equally in all directions is 6.0\times 10^{-10} W/m^2. What is the power emitted by the source

Answers

Answer:

P = 271 nW

Explanation:

If the source is radiating equally in all directions, it can be treated as a point source, so all points located at the same distance of the source, have the same intensity I, which is related to the power by the following expression:

       [tex]I = \frac{P}{A} =\frac{P}{4*\pi *r^{2} } (1)[/tex]

Solving for P, we get:

       [tex]P = I*4*\pi *r^{2} = 6.0e-10 W/m2 * 4 * \pi *(6m)^{2} =271 nW (2)[/tex]

1. Calculate the momentum of a 1.0 kg object moving with a velocity of +20 m/s.

2. What is the velocity of an object that has a momentum of -30 kg m/s and a mass of 3.0 kg?

3. Two objects have equal momentum but one has four times the mass of the other. What is the relationship between
their velocities?

4. Which answer below shows the correct units for momentum?
A. kg m/s
B. kg m/s?
C. kg m/s
D. kg s/m
5. Two bowling balls each have a mass of 4.0 kg
The red Bar is moving east 2.0 m/s. The blue ball is moving west at 1.0 m/s. Calculate the total momentum of the system.

Answers

Answer:

1)1*20=20

2)-30/3=- -10

3)velocity of the object 1=v1=4*V2

4) kg m/ s

5) momentum of the system= 12 kg m/ s

horizontal range = 200m, maximum height= 25m find the angle of projection.

Answers

Answer:

θ = 26.6°

Explanation:

Formula for maximum height is;

h = u²sin²θ/2g

We are told maximum height is 25 m, thus;

u²sin²θ/2g = 25 - - - - (eq 1)

Formula for horizontal range is;

R = u²sin2θ/g

In Mathematics, sin2θ = 2sinθcosθ

So; R = 2u²sinθcosθ/g

R = 2u²sinθcosθ/g

We are given Horizontal range = 200 m.

Thus;

2u²sinθcosθ/g = 200 - - - - (eq 2)

Divide eq 1 by eq 2 to get;

200/25 = 4cosθ/sinθ

8 = 4cosθ/sinθ

4/8 = sinθ/cosθ

0.5 = tan θ

θ = tan^(-1) 0.5

θ = 26.6°

A metallic ring of mass 1 kg has moment of inertia 1 kg m² when rotating about one of its diameters. It is molten and
remoulded into a thin uniform disc of the same radius. How much will its moment of inertia be, when rotated about its own
axis.​

Answers

Answer:

The moment of inertia of disc about own axis is 1 kg-m².

Explanation:

Given that,

Mass of ring m= 1 kg

Moment of inertia of ring at diameter [tex](I_{r})_{d}=1\ kg\ m^{2}[/tex]

The radius of metallic ring and uniform disc both are equal.

So, [tex]R_{r}=R_{d}[/tex]

We need to calculate the value of radius of ring and disc

Using theorem of perpendicular axes

[tex](I_{r})_{c}=2\times (I_{r})_{d}[/tex]

Put the value into the formula

[tex](I_{r})_{c}=2\times1[/tex]

[tex](I_{r})_{c}=2\ kg\ m^2[/tex]

Put the value of moment of inertia

[tex]MR_{r}^2=2[/tex]

[tex]R_{r}^2=\dfrac{2}{M}[/tex]

Put the value of M

[tex]R_{r}^2=\dfrac{2}{1}[/tex]

So, [tex]R_{r}^2=R_{d}^2=2\ m[/tex]

We need to calculate the moment of inertia of disc about own axis

Using formula of moment of inertia

[tex]I_{d}=\dfrac{1}{2}MR_{d}^2[/tex]

Put the value into the formula

[tex]I_{d}=\dfrac{1}{2}\times1\times2[/tex]

[tex]I_{d}=1\ kg\ m^2[/tex]

Hence, The moment of inertia of disc about own axis is 1 kg-m².

Which describes velocity?

Answers

Answer:

Velocity is the rate at which the position changes. The average velocity is the displacement or position change per time ratio.

Explanation:

Answer:

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).

Other units: mph, ft/s

In SI base units: m/s

Explanation:

i dont know if this helps.

A boat moves through the water of a river at 8 m/s relative to the water, regardless of the boat's direction. If the water in theriver is flowing at 1.9 m/s, how long does it take the boat to makea round trip consisting of a 260 m displacement downstream followedby a 260 m

Answers

Answer:

68.88 m/s

Explanation:

downstream speed = 8+1.9=9.9 m/s

upstream speed = 8-1.9= 6.1 m/s

Therefore, total time taken would be 260/9.9+260/6.1 = 26.26+42.62 =

68.88 m/s

3. Missy Diwater, the former platform diver for the Ringling Brother's Circus, had a kinetic energy of 12,000 ) just prior to hitting the bucket of water. If Missy's mass is 40 kg, then what is her speed?​

Answers

Answer:

v = 24.49[m/s]    

Explanation:

We must remember that kinetic energy can be calculated by means of a mathematical expression, which relates kinetic energy to mass and velocity

[tex]E_{kin}=\frac{1}{2}*m*v^{2} \\[/tex]

where:

Ekin = kinetic energy = 12000 [J]

m = mass = 40 [kg]

v = velocity [m/s]

[tex]12000=\frac{1}{2} *40*v^{2}\\24000=40*v^{2}\\600=v^{2}\\v=\sqrt{600}\\v=24.49[m/s][/tex]

A ball falls through the air at terminal velocity. Which of the following are forces that should be included in a free body
diagram? (select all that apply)

air resistance
force of motion
gravity
force of fall

Answers

Answer:

air resistance and gravity.

Explanation:

When the ball is falling down at terminal velocity, the velocity is constant.

This means that the net force acting on the ball will be zero (there is no acceleration)

In this situation, there are only two forces that can act on the ball.

The gravitational force, that pulls the ball down.

The air resistance which opposes to the movement of the ball and increases in magnitude as the velocity of the ball increases.

Then there is a point where the velocity of the ball is such that the air resistance is equal in magnitude to the acceleration, and then the net force becomes zero.

Then the two forces that need to be included in this diagram are the air resistance and gravity.

is this right? plzz anwser soon

Answers

Answer:

yes

Explanation:

Answer:

y e p  

Explanation:

A volleyball experiences 494 Ns of impulse over a time period of 7 seconds. What was the magnitude of the force that acted on the volleyball during this time period?

Answers

Answer:

70.6N

Explanation:

Given parameters:

Impulse  = 494Ns

Time  = 7s

Unknown:

Force applied = ?

Solution:

To solve this problem, we use the formula of impulse;

      Impulse = Force x time

Now insert the parameters and solve;

       494  = Force x 7

            Force  = [tex]\frac{494}{7}[/tex]  

          Force  = 70.6N

How must a tennis serve start

Answers

Answer/Explanation:

When serving the primary serve, remain behind the benchmark between the middle imprint and the correct sideline. The ball is hit corner to corner into the administration box on the opposite side of the net, on the contrary side of the middle imprint from which the worker is serving.

5) Choose the best revision of the following statement: "All the isotopes of a particular element decay radioactively by
emitting electrons."
A. All the isotopes of a particular element are stable and do not decay.
B. Some isotopes are stable and others are unstable. Unstable isotopes decay by emitting various subatomic
particles and radiation
C. Some isotopes are stable and others are unstable. Unstable isotopes decay by emitting protons or
electrons.
D. The statement is correct as it is currently written.

Answers

Answer:

B. some isotopes are stable and others are unstable. unstable isotopes decay by emitting various subatomic particles and radiation.

Explanation:

test gave me the answer so yeah :/ XD

A 15-kg wagon is pulled to the right across a surface by a tension
of 100 newtons at an angle of 30 degrees above the horizontal.
A frictional force of 20 newtons to the left acts simultaneously.
What is the acceleration of the wagon?

Answers

Answer:

4.44 m/s^2

Explanation:

A 15-kg wagon is pulled to the right across a surface by a tension of 100 newtons at an angle of 30 degrees above the horizontal. A frictional force of 20 newtons to the left acts simultaneously.The acceleration of the wagon 4.44 m/s².

What is acceleration?

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

Given in the question a 15 kg wagon is pulled to the right across a surface by a tension of 100 newtons at an angle of 30 degrees above the horizontal. A frictional force of 20 newtons to the left acts simultaneously, then the acceleration is  4.44 m/s².

The acceleration of the wagon 4.44 m/s².

To learn more about acceleration refer to the link:

brainly.com/question/12550364

#SPJ2

A 1000 kg car crashed into a barrier. The car changed speed from 30 m/s to 20 m/s in 0.2 seconds. What force did the barrier apply to stop the car?

Answers

Answer:

Force = -50000 Newton

Explanation:

Given the following data;

Initial velocity, u = 30 m/s

Final velocity, v = 20 m/s

Time = 0.2secs

Mass = 1000 kg

First of all, we have to solve for its acceleration.

Acceleration = (v - u)/t

Substituting into the equation, we have

Acceleration = 20 - 30)/0.2

Acceleration = -10/0.2

Acceleration = -50m/s²

To find the force;

Force = mass * acceleration

Force = 1000 * (-50)

Force = -50000 Newton. The value of the force is negative because it stopped the motion of the car.

Therefore, the barrier applied a force of -5,0000 Newtons to stop the car.

Answer: -50000

Explanation:

What is the potential energy of a 2500 g object suspended 5 m above the earth's surface?
kilograms. convert mass to kilograms to solve this problem.

Answers

Answer:

Explanation:

Potential energy, which is the energy a body assumes at a position, can be calculated using the formula:

P.E = m × g × h

Where;

m = mass (kg)

g = acceleration due to gravity (10m/s²)

h = height (m)

A construction laborer holds a 20 kg sheet of wallboard 3 m above the floor for 4 seconds. During these 4 seconds how much power was expended on the wallboard

Answers

Answer:

zero

Explanation:

no distance has moved while holding the sheet...so no distance means no workdone..no workdone means no power...

Two displacement vectors have magnitudes of 5.0 m and 7.0 m, respectively. If these two vectors are added together, the magnitude of the sum

Answers

Answer:

8.6m

Explanation:

Step one:

given data

we are given two displacement vectors of magnitudes 5 and 7m

Let us assume they are in the same direction and they are acting perpendicular to each other.

Step two:

The magnitude of the vector sum is the resultant vector

which is  found by

R^2=5^2+7^2

R^2= 25+49

R^2=74

R=√74

R=8.6m

A projectile is fired with a velocity of 8 m/s at an angle of 65º. What is the
vertical component of the velocity?
A. 6.5 m/s
B. 3.4 m/s
C. 10.2 m/s
D. 7.2 m/s

Answers

Answer:

i think its D

Explanation:

6. A yo-yo with a mass of 0.5 kg is tied to a radius of 2 m and is spinning at 3 m/s. What
is the centripetal force acting on the yo-yo?

Answers

Given that,

Mass of yo-yo, m = 0.5 kg

Radius of the path, r = 2 m

Speed of the object, v = 3 m/s

To find,

The centripetal force acting on the yo-yo.

Solution,

The formula for the centripetal force is given as follows :

[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{0.5\times (3)^2}{2}\\\\F=2.25\ N[/tex]

So, the magnitude of centripetal force acting on the y-yo is 2.25 N.

Help Help!!

Alcohol ___ the central nervous system and the peripheral nervous system.
A. sedates
B. stimulates
C. bypasses

Answers

Answer:

I think it is the answer A

Explanation:

Alcohol won't stimulate the central nervous system and the peripheral nervous system because the fact that the brain and the nervous system are affected can lead to many consequences: disorders of vision, hearing, motor coordination ...

Alcohol will therefore have a damaging effect, it will therefore sedate the nervous system.

Answer:A

Explanation:sedates

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