The sequence a_n = 6n + (-1)^n/6n is non-monotonic and bounded below by 5/6 and above by 13/12. So, the correct answer is A).
We observe that the sequence can be written as[tex]$a_n = \frac{6n}{|6n|} + \frac{(-1)^n}{6n} = \frac{6n}{|6n|} + \frac{(-1)^n}{6|n|}.$[/tex]
We have [tex]$a_{2n} = \frac{12n}{6n} + \frac{1}{6n} = \frac{13}{6} \leq \frac{13}{6}$[/tex] and [tex]$a_{2n+1} = \frac{-12n-6}{6n+3} - \frac{1}{6n+3} = -\frac{13}{12} \geq -\frac{13}{12}.$[/tex]Therefore, the sequence is increasing and bounded below by 5/6 and above by 13/12.
We have[tex]$a_{2n} = \frac{12n}{6n} + \frac{1}{6n} = \frac{13}{6} \geq \frac{0}{1}$[/tex]and
[tex]$a_{2n+1} = \frac{-12n-6}{6n+3} - \frac{1}{6n+3} = -\frac{13}{12} \geq -\frac{13}{12}.$[/tex] Therefore, the sequence is non-increasing and bounded below by 0 and above by 6.
From above part, we see that the sequence is not monotonic.
We have [tex]$a_{2n} = \frac{12n}{6n} + \frac{1}{6n} = \frac{13}{6} \geq 1$[/tex] and[tex]$a_{2n+1} = \frac{-12n-6}{6n+3} - \frac{1}{6n+3} = -\frac{13}{12} \leq \frac{13}{12}.$[/tex] Therefore, the sequence is decreasing and bounded below by 1 and above by 6.
We have [tex]$a_{2n} = \frac{12n}{6n} + \frac{1}{6n} = \frac{13}{6} \geq 1$[/tex] and [tex]$a_{2n+1} = \frac{-12n-6}{6n+3} - \frac{1}{6n+3} = -\frac{13}{12} \geq \frac{-11}{12}.$[/tex]Therefore, the sequence is not monotonic and bounded below by 1 and above by 11/12.
Therefore, the answer is a_n = 6n + (-1)^n/6n| is increasing; bounded below by 5/6 and above by 13/12. So, the correct option is A).
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5.6t for t=0.7
(evaluate the expression)
Answer:
3.92
Step-by-step explanation:
To evaluate the expression 5.6t when t=0.7, we just substitute 0.7 for t and multiply:
5.6(0.7) = 3.92
Therefore, 5.6t when t is 0.7 equals 3.92. Good Luck!
Evaluate the integral. (use c for the constant of integration. remember to use absolute values where appropriate.) ∫ x^3 / x-1 dx
___
the final answer is:
[tex]\int \frac{ x^3} { x-1} dx = \frac{1}{3} x^3 + \frac{1}{2} x^2 + x + ln|x-1| + c[/tex] (where c is the constant of integration)
To evaluate the integral ∫ [tex]x^3 / x-1[/tex]dx, we can use long division or partial fraction decomposition to simplify the integrand.
Using long division, we get:
[tex]\frac{x^3}{ (x-1)} = x^2 + x + 1 + \frac{1}{ x-1}[/tex]
So, we can rewrite the integral as:
[tex]\int (x^2 + x + 1 + \frac{1}{(x-1)} dx[/tex]
Integrating each term separately, we get:
[tex]\int x^2 dx + \int x dx + \int dx + \int (1/(x-1)) dx\\= (1/3) x^3 + (1/2) x^2 + x + ln|x-1| + c[/tex]
Thus, the final answer is:
[tex]\int \frac{ x^3} { x-1} dx = \frac{1}{3} x^3 + \frac{1}{2} x^2 + x + ln|x-1| + c[/tex] (where c is the constant of integration)
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find the terms through degree 4 of the maclaurin series. ()=2 (express numbers in exact form. use symbolic notation and fractions where needed.)
We need to calculate the first four derivatives of f(x) at x=0, and use the general formula for the Maclaurin series: f(x) = f(0) + f'(0)x + (f''(0)/2!)x² + (f'''(0)/3!)x³ + (f''''(0)/4!)x⁴ + ...
To find the Maclaurin series through degree 4 of a function f(x), we can use the formula:
f(x) = f(0) + f'(0)x + (f''(0)/2!)x^2 + (f'''(0)/3!)x^3 + (f''''(0)/4!)x^4 + ...
Here, we are given that f(x) = 2, which means that f'(x) = f''(x) = f'''(x) = f''''(x) = 0 for all values of x. Therefore, the Maclaurin series for f(x) through degree 4 is:
f(x) = 2 + 0x + (0/2!)x^2 + (0/3!)x^3 + (0/4!)x^4
= 2
In other words, the Maclaurin series for f(x) is simply the constant function 2, since all of the higher-order derivatives of f(x) are zero.
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help me pleaseeee thankss if u do
The linear function defined in the table is given as follows:
y = 0.5x + 9.
How to define a linear function?The slope-intercept representation of a linear function is given by the equation presented as follows:
y = mx + b
The coefficients of the function and their meaning are described as follows:
m is the slope of the function, representing the change in the output variable y when the input variable x is increased by one.b is the y-intercept of the function, which is the initial value of the function, i.e., the numeric value of the function when the input variable x assumes a value of 0. On a graph, it is the value of y when the graph of the function crosses the y-axis.From the table, we get that the slope and the intercept are obtained as follows:
m = 0.5, as when x increases by 3, y increases by 1.5.b = 9, as when x = 0, y = 9.Hence the function is:
y = 0.5x + 9.
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THIS IS -Using proportional relationships
Find the distance from the park to the house
similar triangles by AAA, thus
[tex]\cfrac{XT}{WY}=\cfrac{XZ}{ZY}\implies \cfrac{8}{4}=\cfrac{XZ}{5}\implies \cfrac{40}{4}=XZ\implies \stackrel{ meters }{10}=XZ[/tex]
Write the expressions. Then evaluate.
1. a. the product of 5 and a number x.
b. Evaluate when x = -1.
2. a. 18 decreased by a number z
b. Evaluate when z = 23.
3. a.The quotient of 16 and a number m
b. Evaluate when m=4
4. aThe product of 8 and twice a number n
b. Evaluate when n = 3
5.aThe sum of 3 times a number k and 4
b. Evaluate k= -2
The values of the expressions are: 5x, -5, 18 - z , -5, 16/m, 4, 36n, 3k +4 , 2,
What is a mathematical expression?Recall that a mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context. Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation and grouping to help determine order of operations and other aspects of logical syntax.
1a. the product of 5 and a number x.
= 5*x = 5x
b Evaluate when x = -1.
= 5*-1 = -5
2a 18 decreased by a number z
this implies 18 - z
b Evaluate when z = 23.
18-23 = -5
3a The quotient of 16 and a number m
= 16/m
b Evaluate when m=4
this means 16/4 = 4
4. aThe product of 8 and twice a number n
= 18*2(n)
= 36n
b. Evaluate when n = 3
= 36*3 = 108
5.aThe sum of 3 times a number k and 4
= 3(k) + 4
= 3k +4
b. Evaluate k= -2
= 3*-2 + 4
-6+4 = 2
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A straight line joins the points A (2, 1) and B (8, 10). The point C (6, y) lies on the line AB. Find the y-coordinate of C.
If a straight line joins the points A (2, 1) and B (8, 10) and the point C (6, y) lies on the line AB. Then the y-coordinate of C is 7.
What is line?A line is a geometric object in mathematics that extends infinity in both directions and is symbolised by a straight line that never ends.
Two points, referred to as endpoints, define it as being one-dimensional and lacking in both width and depth.
A line equation has the slope-intercept form y = mx + b, where m is the slope and b is the y-intercept.
A number of real-world situations, such as the motion of an object or the direction of a force, can be modelled and described using lines.
We can find the equation of line AB using the two given points A and B:
Slope of AB = (change in y) / (change in x) = (10 - 1) / (8 - 2) = 9/6 = 3/2
Using point-slope form with point A:
y - 1 = (3/2)(x - 2)
Simplifying, we get:
y - 1 = (3/2)x - 3
y = (3/2)x - 2
Now we substitute x = 6 to find the y-coordinate of C:
y = (3/2)(6) - 2
y = 7
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use the technique of example 2 in the text to evaluate the integral ∫1−1(|2x|+2) dx exactly. ∫1−1(|2x|+2) dx =
To evaluate the integral ∫1−1(|2x|+2) dx exactly using the technique of example 2 in the text, we first split the integral into two parts:
∫1−1(|2x|+2) dx = ∫1^0 (-2x + 2) dx + ∫0^-1 (2x + 2) dx
Next, we can simplify the absolute values:
∫1^0 (-2x + 2) dx + ∫0^-1 (2x + 2) dx = ∫1^0 (-2x + 2) dx + ∫0^-1 (-2x + 2) dx
Now we can integrate each part:
∫1^0 (-2x + 2) dx + ∫0^-1 (-2x + 2) dx = [-x^2 + 2x]1^0 + [-x^2 + 2x]0^-1
Simplifying further, we get:
[-1^2 + 2(1)] - [0^2 + 2(0)] + [0^2 + 2(0)] - [-(-1)^2 + 2(-1)]
= 1 + 1 + 1 = 3
Therefore, the exact value of the integral ∫1−1(|2x|+2) dx is 3.
To evaluate the integral ∫₁₋₁ (|2x|+2) dx, we first need to split the integral into two parts due to the absolute value function.
For x >= 0, |2x| = 2x, and for x < 0, |2x| = -2x.
Now, we split the integral into two parts:
∫₁₋₁ (|2x|+2) dx = ∫₀₋₁ (-2x+2) dx + ∫₁₀ (2x+2) dx.
Now, we evaluate each integral separately:
∫₀₋₁ (-2x+2) dx = [-x²+2x]₀₋₁ = (1-2)-(0) = -1.
∫₁₀ (2x+2) dx = [x²+2x]₁₀ = (1+2)-(0) = 3.
Finally, we add the two results together:
∫₁₋₁ (|2x|+2) dx = -1 + 3 = 2.
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The point x = 0 is a regular singular point of the given differential equation. xy" + 2y' - xy = 0 Show that the indicial roots r of the singularity differ by an integer. (List the indicial roots below as a comma-separated list.) | x Use the method of Frobenius to obtain at least one series solution about x = 0. Use (23) in Section 6.3 e-SP(x) dx y2(x) = y(x) of dx (23) where necessary and a CAS, if instructed, to find a second solution. Form the general solution on (0,0). O y=x[c, sinh x + C2 cosh hx] O y = [( sin x + C2 cos x] O y = [9 sinhx + C cosh x] O y=x[cz 5x] O y=x?[c, sinhx + ] sin x + C2 cos
The given differential equation xy" + 2y' - xy = 0 has a regular singular point at x=0, and the indicial roots of the singularity differ by an integer.
To show that the indicial roots of the singularity differ by an integer, we need to use the Frobenius method to obtain a series solution about x=0. The differential equation can be written as:
x^2y" + 2xy' - x^2y = 0
Assuming a series solution of the form y(x) = ∑n=0∞ anxn+r, we can substitute this into the differential equation and simplify the terms to obtain a recurrence relation for the coefficients an:
n(n+r)an + (n+2)(r+1)an+1 = 0
To ensure that the series solution converges, we require that the coefficient an does not become zero for all values of n, except for a finite number of cases. This condition leads to the indicial equation:
r(r-1) + 2r = 0
which gives the two indicial roots:
r1 = 0, r2 = -2
Since the difference between the two roots is an integer (2), we have shown that the indicial roots of the singularity differ by an integer.
Using r1 = 0 as the dominant root, the series solution for y(x) can be written as:
y1(x) = c0 + c1x - (c1/4)x^2 + (c1/36)x^3 - (c1/576)x^4 + ...
Using the formula (23) in Section 6.3, we can find a second linearly independent solution y2(x) in terms of y1(x) as:
y2(x) = y1(x) ∫ (e^-∫P(x)dx / y1^2(x))dx
where P(x) = 2/x - x. After simplification, we get:
y2(x) = c2x^2 + c3x^3 + (2c1/9)x^4 + ...
Therefore, the general solution of the given differential equation on (0,0) can be written as:
y(x) = c1x - (c1/4)x^2 + (c1/36)x^3 - (c1/576)x^4 + c2x^2 + c3x^3 + (2c1/9)x^4 + ...
or, simplifying further:
y(x) = x[c1 + c2x + c3x^2] + c1x[1 - (1/4)x + (1/36)x^2 - (1/576)x^3] + ...
where c1, c2, and c3 are constants determined by the initial/boundary conditions.
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A solid cone with a diameter of 10 centimeters and a height of 8 centimeters
The volume of a solid cone with a diameter of 10 centimeters and a height of 8 centimeters is equal to 209.47 cubic centimeters.
How to calculate the volume of a cone?In Mathematics and Geometry, the volume of a cone can be determined by using this formula:
V = 1/3 × πr²h
Where:
V represent the volume of a cone.h represents the height.r represents the radius.Note: Radius = diameter/2 = 10/2 = 5 cm.
By substituting the given parameters into the formula for the volume of a cone, we have the following;
Volume of cone, V = 1/3 × 3.142 × 5² × 8
Volume of cone, V = 1/3 × 3.142 × 25 × 8
Volume of cone, V = 209.47 cubic centimeters.
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Complete Question:
A solid cone with a diameter of 10 centimeters and a height of 8 centimeters. Find the the volume of this cone.
let xx and yy have joint density function
p(x,y)={23(x+2y)0for 0≤x≤1,0≤y≤1,otherwise.p(x,y)={23(x+2y)for 0≤x≤1,0≤y≤1,0otherwise.
Find the probability that
(a) x>1/7x>1/7:
probability =
(b) x<17+yx<17+y:
probability =
(a) The probability that x > 1/7 is 4/7
(b) The probability that x < 1 + 7y is 1/9.
How to find the probability that x > 1/7?(a) To find the probability that x > 1/7, we need to integrate the joint density function over the region where x > 1/7 and y is between 0 and 1:
[tex]P(x > 1/7) = \int \int _{x > 1/7} p(x,y) dx dy[/tex]
[tex]= \int_{1/7}^1 \int _0^1 2/3 (x + 2y) dx dy (since p(x,y) = 2/3 (x + 2y)[/tex]for 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, and 0 otherwise)
[tex]= (2/3) \int_{1/7}^1 (\int_0^1 x dx + 2 \int_0^1 y dx) dy[/tex]
[tex]= (2/3) \int_{1/7}^1 (1/2 + 2/2) dy[/tex]
[tex]= (2/3) \int _{1/7}^1 3/2 dy[/tex]
= (2/3) (1 - 1/14)
= 12/21
= 4/7
Therefore, the probability that x > 1/7 is 4/7.
How to find the probability that x < 1 + 7y?(b) To find the probability that x < 1 + 7y, we need to integrate the joint density function over the region where x is between 0 and 1 + 7y and y is between 0 and 1:
[tex]P(x < 1 + 7y) = \int \int_{x < 1+7y} p(x,y) dx dy[/tex]
=[tex]\int_0^1 \int_0^{(x-1)/7} 2/3 (x + 2y) dy dx[/tex](since p(x,y) = 2/3 (x + 2y) for 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, and 0 otherwise)
= [tex](2/3) \int_0^1 (\int_{7y+1}^1 x dy + 2 \int_0^y y dy) dx[/tex]
= [tex](2/3) \int_0^1 [(1/2 - 7/2y^2) - (7y/2 + 1/2)] dx[/tex]
= [tex](2/3) \int_0^1 (-6y^2/2 - 6y/2 + 1/2) dy[/tex]
=[tex](2/3) \int_0^1 (-3y^2 - 3y + 1/2) dy[/tex]
= (2/3) (-1/3 - 1/2 + 1/2)
= -2/9 + 1/3
= 1/9
Therefore, the probability that x < 1 + 7y is 1/9.
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1. In a group of people, 20 like milk, 30 like tea, 22 like coffee, 12 like coffee only, 6 like milk and coffee only, 2 like tea and coffee only and 8 like milk and tea only. Show these information in a Venn-diagram and find:
a)How many like at least one drink?
b) How many like exactly one drink?
The following Venn diagram represents the supplied information:
Milk
/ \
/ \
/ \
Coffee Tea
/ \ / \
/ \ / \
/ \ / \
M & C C T M & T
(6) (12) (2) (8)
a) To find how many people like at least one drink, we need to add up the number of people in each region of the Venn-diagram:
Milk: 20
Tea: 30
Coffee: 22
Milk and Coffee only: 6
Coffee and Tea only: 2
Milk and Tea only: 8
Milk, Coffee, and Tea: 12
Adding these up, we get:
20 + 30 + 22 + 6 + 2 + 8 + 12 = 100
So 100 people like at least one drink.
b) To find how many people like exactly one drink, we need to add up the number of people in the regions that are not shared by any other drink:
Milk only: (20 - 6 - 8) = 6
Tea only: (30 - 2 - 8) = 20
Coffee only: (22 - 12 - 2) = 8
Adding these up, we get:
6 + 20 + 8 = 34
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An equilateral triangle has length of each side 12 cm. Calculate the area of the triangle. Calculate its area.
Answer:
72
Step-by-step explanation:
12x12 is 144
and 144/2 is 72
Answer:
72
Step-by-step explanation:
12 X 12 = 144
Then you divide the answer to 2 and you get 72
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evaluate the given limit. (a) limx→0 sin 3x 4x
Applying L'Hopital's rule, we get: limx→0 sin 3x / 4x = limx→0 3cos 3x / 4 = 3/4 Therefore, the limit of sin 3x / 4x as x approaches 0 is 3/4.
(a) lim(x→0) (sin(3x) / (4x))
To evaluate this limit, we can use L'Hôpital's Rule, which states that if the limit of the ratio of the derivatives of two functions exists, then the limit of the original functions also exists and is equal to the limit of the ratio of their derivatives.
Step 1: Take the derivative of the numerator and denominator with respect to x:
- Derivative of sin(3x) with respect to x: 3cos(3x)
- Derivative of 4x with respect to x: 4
Step 2: Rewrite the limit using the derivatives:
lim(x→0) (3cos(3x) / 4)
Step 3: Evaluate the limit by plugging in x = 0:
(3cos(3*0) / 4) = (3cos(0) / 4) = (3*1) / 4 = 3/4
So, the given limit is 3/4.
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For every household in a particular county, the water use in thousands of gallons over the course of a year was recorded. The mean water use for the households in the county was found to be 162 and the standard deviation was 140.a) based on the information given above, could the distribution of household water use for that county be approximately normal? Explain.b) A random sample of 50 households will be selected, and the mean water use will be calculated for the households in the sample. Is the sampling distribution of the sample mean for random samples of size 50 approximately normal? Explain.
The probability of x' bar to be greater than 59 is equal to 0.1193.
What is Mean value?
Apart from mode and median, mean is the one of the measures of central tendency. When we do the average of given set of values, it is called mean. Here in this question we need to check if the data meets the criterion for a normal distribution. One of these criterion is that data should be symmetric & bell shaped and another one is that mean and median should be approximately equal. By adding the total values given in the datasheet and dividing the sum by total no of values we will get the value of mean.
Here, the mean is = 162 point, the standard deviation = 140 point and x is considered as a variable for household water use in the country
μ=162
σ=140
X:- household water use for country
i.e., approx. Normal
(b) n=50
n>30
i.e., approx. normal
(c) P(X'>59) = 1 - P(X'≤59)
= 1- P((X'-μ)/(σ/√n)≤59-57/(12/√50))
= 1- P(z ≤ 1.178)
= 1-0.8807
P(X'>59)= 0.1193
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A pn junction with ND = 3 * 1016 cm3 and NA = 2 * 1015 cm3 experiences a reverse bias voltage of 1.6 V.
(a) Determine the junction capacitance per unit area.
(b) By what factor should NA be increased to double the junction capacitance?
(a) The junction capacitance per unit area is approximately 1.75 x 10^-5 F/cm². (b) To double the junction capacitance, we need to increase the acceptor concentration by a factor of 4. In other words, we need to increase NA from 2 x 10^15 cm⁻³ to 8 x 10^15 cm⁻³.
(a) The junction capacitance per unit area can be calculated using the following formula:
C = sqrt((qε/NA)(ND/(NA+ND))×V)
Where:
q is the elementary charge (1.6 x 10^-19 C)ε is the permittivity of the semiconductor material (assumed to be 12.4 ε0 for silicon)NA and ND are the acceptor and donor concentrations, respectivelyV is the applied voltagePlugging in the values given in the question, we get:
C = sqrt((1.6 x 10^-19 C × 12.4 ε0 / (2 x 10^15 cm⁻³)) × (3 x 10^16 cm⁻³ / (2 x 10^15 cm⁻³ + 3 x 10^16 cm⁻³)) × 1.6 V)
C ≈ 1.75 x 10^-5 F/cm²
(b) To double the junction capacitance, we need to increase the acceptor concentration (NA) by a certain factor. We can use the following formula to calculate this factor:
F = (C2/C1)² × (NA1+ND)/(NA2+ND)
Where:
C1 is the initial capacitance per unit areaC2 is the desired capacitance per unit areaNA1 is the initial acceptor concentrationNA2 is the new acceptor concentration we need to calculateND is the donor concentration (assumed to be constant)Plugging in the values from part (a) as C1 and NA1, and using C2 = 2C1, we get:
2C1 = sqrt((qε/NA1)(ND/(NA1+ND))×V) × 2
Squaring both sides and simplifying, we get:
NA2 = NA1 × 4
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use the table of integrals to evaluate the integral. ∫2 31x^3 √4x2 − x4 dx 0
The value of the integral is (11/15)√3.
First, we can simplify the integrand using the trigonometric substitution:
Let x = 2sinθ
Then dx = 2cosθ dθ and 4x^2 - x^4 = 4(2sinθ)^2 - (2sinθ)^4 = 4(4sin^2θ - sin^4θ) = 4sin^2θ(4 - sin^2θ)
Substituting these expressions into the integral, we have:
∫2^3 1x^3 √4x2 − x4 dx
= ∫sin(θ=π/6)sin(θ=π/3) 8sin^3θ √(4sin^2θ)(4-sin^2θ) (2cosθ)dθ
= 16∫sin(θ=π/6)sin(θ=π/3) sin^3θ cos^2θ dθ
We can use the identity sin^3θ = (1-cos^2θ)sinθ to simplify the integral further:
16∫sin(θ=π/6)sin(θ=π/3) sinθ(1-cos^2θ)cos^2θ dθ
Now, we can make the substitution u = cosθ, du = -sinθ dθ, and use the table of integrals to evaluate the integral:
16 ∫u=-√3/2u=1/2 -u^2(1-u^2) du
= 16 [(-1/3)u^3 + (1/5)u^5]u=-√3/2u=1/2
= 16 [(-1/3)(-√3/2)^3 + (1/5)(-√3/2)^5 - (-1/3)(1/2)^3 + (1/5)(1/2)^5]
= 16 [(-√3/24) + (3√3/160) + (1/24) - (1/160)]
= 16 [(11√3/480)]
= (11/15)√3
Therefore, the value of the integral is (11/15)√3.
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HELP ASAP ! With the problem
The correct result for solving the radical equation √(2x - 7) = 9 is derive to be 2x - 7 = 81, which makes the variable x = 44
What are radicals?In mathematics, the symbol √ is used to represent or show that a number is a radical. Radical equation is defined as any equation containing a radical (√) symbol.
The radical symbol for the equation √(2x - 7) = 9 can be removed squaring both sides as follows;
[√(2x - 7)]² = 9²
(2x - 7)^(2/2) = 9 × 9
2x - 7 = 81
the value of the variable x can easily then be derived as follows:
2x = 81 + 7 {collect like terms}
2x = 88
x = 88/2 {divide through by 2}
x = 44
Therefore, removing the radical symbol by squaring both sides of the equation will result to 2x - 7 = 81, and the variable x = 44
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Express the function as the sum of a power series by first using partial fractions. f(x) = 11/(x^2 - 7x - 18). f(x) = siqma^infinity_n=0 (_________)Find the interval of convergence. (Enter your answer using interval notation.)
The interval of convergence is (-18/5, 18/5).
To express f(x) as a power series, we first need to decompose it into partial fractions:
f(x) = 11/(x^2 - 7x - 18) = 11/[(x - 9)(x + 2)]
Using partial fractions, we can write:
11/[(x - 9)(x + 2)] = A/(x - 9) + B/(x + 2)
Multiplying both sides by the denominator (x - 9)(x + 2), we get:
11 = A(x + 2) + B(x - 9)
Setting x = 9, we get:
11 = A(9 + 2)
A = 1
Setting x = -2, we get:
11 = B(-2 - 9)
B = -1
Therefore, we have:
f(x) = 1/(x - 9) - 1/(x + 2)
Now, we can write the power series of each term using the formula for a geometric series:
1/(x - 9) = -1/18 (1 - x/9)^(-1) = -1/18 * sigma^n=0 to infinity (x/9)^n
1/(x + 2) = 1/11 (1 - x/(-2))^(-1) = 1/11 * sigma^n=0 to infinity (-x/2)^n
So, putting everything together, we get:
f(x) = 1/(x - 9) - 1/(x + 2) = -1/18 * sigma^n=0 to infinity (x/9)^n + 1/11 * sigma^n=0 to infinity (-x/2)^n
The interval of convergence can be found using the ratio test:
|a_n+1 / a_n| = |(-x/9)^(n+1) / (-x/9)^n| + |(-x/2)^(n+1) / (-x/2)^n|
= |x/9| + |x/2|
= (|x|/9) + (|x|/2)
For the series to converge, we need |a_n+1 / a_n| < 1. This happens when:
(|x|/9) + (|x|/2) < 1
Solving for |x|, we get:
|x| < 18/5
Therefore, the interval of convergence is (-18/5, 18/5).
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How is a simple random sample obtained?A. By recruiting every other person who meets the inclusion criteria admitted on three consecutive days
B. By advertising for persons to participate in the study
C. By selecting names from a list of all members of a population in a way that allows only chance to determine who is selected
D. By selecting persons from an assumed population who meet the inclusion criteria
A simple random sample obtained by
selecting names from a list of all members of a population in a way that allows only chance to determine who is selected. So, option(C) is correct choice.
In probability sampling, the probability of each member of the population being selected as a sample is greater than zero. In order to reach this result, the samples were obtained randomly. In simple random sampling (SRS), each sampling unit in the population has an equal chance of being included in the sample. Therefore, all possible models are equally selective. To select a simple example, you must type all the units in the inspector. When using random sampling, each base of the population has an equal probability of being selected (simple random sampling). This sample is said to be representative because the characteristics of the sample drawn are representative of the main population in all respects. Following are steps for follow by random sampling :
Define populationconstruct a list Define a sample Contacting Members of a SampleHence, for random sampling option(c) is answer.
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David madd 4/3 of quart of fruit juice. Each mug he had holdes 1/3 of a quart. How many mugs will David be able to fill?
4 mugs are required to fill if David made 4/3 of a quart of fruit juice. In each mug, he held 1/3 of a quart as per the fractions.
Fruit juice quart = 4/3
Holdes of quart = 1/3
This can be calculated by using the division of fractions. The number of mugs that can be filled will be calculated by using the fraction equation of division of quart of juice and holdes.
Mathematically,
number of mugs = 4/3 ÷ 1/3
number of mugs = 4/3 × 3/1
number of mugs = 4
Therefore we can conclude that David will able to fill in 4 mugs.
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A 9-pound bag of sugar is being split into containers that hold 34 of a pound. How many containers of sugar will the 9-pound bag fill
Answer:36
Step-by-step explanation: 3/4, but take away the denominator. now we have 3. what's a multiple of 3 and 9? 36.
now divide 36 by the denominator, that's 9. so that's the answer. (i think)
What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is
4x+y-2=0?
04x-y=13
4x+y=13
4x+y=-13
Answer:
4x + y = 13
Step-by-step explanation:
The original equation is: 4x + y - 2 = 0 --> y = -4x + 2
Equation 1: 4x - y = 13 --> y = 4x - 13. Since it does not have the same slope as the original equation, Equation 1 is not the answer.
Equation 2 turns into y = -4x + 13. -3 = -4(4) + 13 = -16 + 13 = -3. Since the equation passes through this point and has the same slope as the original equation, it fits the criteria for the problem.
How do I do this step by step
Step 1: Find the number of bronze members
40% of the gym's members are bronze members. Therefore, we need to find 40% of 4000. We can do this either by multiplying 4000 by 0.4 (40% as a decimal) or setting up a proportion. I will demonstrate the proportion method.
percent / 100 = part / whole
40 / 100 = x / 4000
---Cross multiply and solve algebraically.
100x = 160000
x = 1600 bronze members
Step 2: Find the number of silver members
Using the same methodology as last time, we can set up and solve a proportion to find the number of silver members.
percent / 100 = part / whole
25 / 100 = y / 4000
100y = 10000
y = 1000 silver members
Step 3: Find the number of gold members
Now that we know how many bronze and silver members the gym has, we can subtract those values from the total number of members to find the number of gold members.
4000 - bronze - silver = gold
4000 - 1600 - 1000 = gold
gold = 1400 members
Answer: 1400 gold members
ALTERNATIVE METHOD OF SOLVING
Alternatively, we could have used the given percents and only used one proportion. We know percents have to add up to 100. We are given 40% and 25%, which means the remaining percent is 35%. Therefore, 35% of the members are gold members. Just as we did for the silver and bronze members above, we can set up a proportion and solve algebraically.
percent / 100 = part / whole
35 / 100 = z / 4000
100z = 140000
z = 1400 gold members
Hope this helps!
0.5 miles = 2,640 feet
O A. True
OB. False
Answer:
true
Step-by-step explanation:
Yes, the statement "0.5 miles = 2,640 feet" is true.
One mile is equal to 5,280 feet, so half a mile (0.5 miles) is equal to 2,640 feet.
Or
1 mile = 5280
1/2 = 0.5 / 5280 = 5280 / 2 =2640
find the x-coordinates of the inflection points for the polynomial p(x) = x 5 /20 − 5x 4 /12 + 2022/ π .
The inflection points occur at x = 0 and x = 5.
How to find the x-coordinates of the inflection points?To find the x-coordinates of the inflection points for the polynomial p(x) = [tex]x^5/20 - 5x^4/12[/tex] + 2022/π, follow these steps:
1. Compute the second derivative of p(x):
First derivative: p'(x) =[tex](5x^4)/20 - (20x^3)/12[/tex]
Second derivative: p''(x) = [tex](20x^3)/20 - (60x^2)/12 = x^3 - 5x^2[/tex]
2. Set the second derivative equal to zero and solve for x:
[tex]x^3 - 5x^2 = 0[/tex]
[tex]x^2(x - 5) = 0[/tex]
3. Find the x-coordinates where the second derivative is zero:
x = 0 and x = 5
These x-coordinates are the inflection points for the polynomial p(x) = [tex]x^5/20 - 5x^4/12[/tex] + 2022/π. So, the inflection points occur at x = 0 and x = 5.
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For f(x) = x to the power of 2 and g(x) = (x-5) to the power of 2, in which direction and by how many units should f(x) be shifted to obtain g(x)?
To obtain g(x) the graph of f(x) should be shifted in the right direction by 5 units
We can see and compare the graphs of f(x) and g(x) to see this visually
Since f(x) = x to the power of 2, so the graph of f(x) will be a parabola which will have center at the origin and opens upwards
The graph of g(x) will also be a parabola but it will have center at x = 5
So, we just need to shift the graph of f(x) by 5 units in right direction to obtain g(x)
In the equation of f(x), we just have to replace x with (x- 5) and we will get
g(x) = (x-5)^2
So, this will be the equation of parabola that's identical to f(x)
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We can start by setting the two functions equal to each other and solving for x:
f(x) = g(x)
x^2 = (x-5)^2
Expanding the right-hand side:
x^2 = x^2 - 10x + 25
Simplifying:
10x = 25
x = 2.5
So, the two functions intersect at x = 2.5. To shift f(x) to obtain g(x), we need to move it 5 units to the right, since the vertex of g(x) is at x = 5, which is 5 units to the right of the vertex of f(x) at x = 0.
Therefore, to obtain g(x) from f(x), we need to replace x with x-5:
g(x) = f(x-5) = (x-5) ^2
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If a set of difference scores with df - 8 has a mean of Mp - 3.5 and a variance of s2 = 36, then the sample will produce a repeated-measures t statistic oft- +1.75 True False
The calculated t-value is 1.75. To determine whether this t-value is significant, we would need to compare it to the critical t-value for df = 8 and the desired level of significance. However, the question only asks whether the t-value is +1.75, which is true.
To determine if the statement is true or false, we will first calculate the t statistic for the given data using the formula for a repeated-measures t-test:
t = (M - μ) / (s / sqrt(n))
where M is the mean of the difference scores, μ is the population mean (in this case, 0 because we're testing for differences), s is the standard deviation (square root of the variance), and n is the number of difference scores (df + 1).
Given:
Mean of difference scores (M) = 3.5
Variance (s^2) = 36
Degrees of freedom (df) = 8
First, calculate the standard deviation (s) and the sample size (n):
s = sqrt(s^2) = sqrt(36) = 6
n = df + 1 = 8 + 1 = 9
Now, calculate the t statistic:
t = (3.5 - 0) / (6 / sqrt(9)) = 3.5 / (6 / 3) = 3.5 / 2 = 1.75
The calculated t statistic is indeed 1.75, which matches the provided value in the statement. Therefore, the statement is true.
True.
To calculate the t-statistic for a repeated-measures design, we use the formula:
t = (Mdiff - μdiff) / (sd_diff / √n)
where Mdiff is the mean of the difference scores, μdiff is the population mean of the difference scores (which we assume is 0), sd_diff is the standard deviation of the difference scores, and n is the sample size.
We are given that the mean of the difference scores (Mdiff) is 3.5 and the variance (s2) is 36. To find the standard deviation, we take the square root of the variance:
sd_diff = √s2 = √36 = 6
The sample size is not given, but we know that the degree of freedom (df) is 8. For a repeated-measures design, df = n - 1. Solving for n:
8 = n - 1
n = 9
Now we can plug in all the values into the t-formula:
t = (3.5 - 0) / (6 / √9) = 1.75
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suppose a 5 × 3 matrix has 3 pivot columns. is Col A = R^5 ? Is Nul A = R^2? Explain your results
A 5 × 3 matrix A has 3 pivot columns. Col A is a subspace of [tex]R^5[/tex] with dimension 3, and Nul A is not equal to [tex]R^2[/tex]; it has a dimension of 0.
Suppose a 5 × 3 matrix A has 3 pivot columns. A pivot column is a column in a matrix that has a leading 1 (pivot position) after performing row reduction. Having 3 pivot columns in matrix A means there are 3 linearly independent columns.
Now, let's consider the two parts of your question:
1. Is Col A = R^5?
Col A represents the column space of matrix A, which is the span of its linearly independent columns. Since A is a 5 × 3 matrix with 3 linearly independent columns, the dimension of Col A (the column space) is 3. Therefore, Col A is a subspace of [tex]R^5[/tex], but not equal to [tex]R^5[/tex].
2. Is Nul A = [tex]R^2[/tex]?
Nul A represents the null space of matrix A, which is the set of all solutions to the homogeneous system Ax = 0. The dimension of the null space called the nullity of A, is equal to the number of columns minus the number of pivot columns. In this case, nullity(A) = 3 (number of columns) - 3 (pivot columns) = 0. This means Nul A has a dimension of 0, not 2, and consists only of the zero vector. So, Nul A ≠ [tex]R^2[/tex].
To summarize, Col A is a subspace of [tex]R^5[/tex] with dimension 3, and Nul A is not equal to [tex]R^2[/tex]; it has a dimension of 0.
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find the first four terms of the infinite series expansion of the given function f(x)=(1 + 2x)^3/2
Answer: [DISCLAIMER]: All answers are rounded to the nearest hundredth of a decimal
f(1) = 5.20 ; f(2) = 14.70 ; f(3) = 27 ; f(4) = 41.57
Step-by-step explanation:
f(1) = (1 + [2×1])[tex]^{3/2}[/tex]
f(1) = (1 + 2)[tex]^{3/2}[/tex]
f(1) = (3)[tex]^{3/2}[/tex]
f(1) ≈ 5.20
f(2) = (2 + [2×2])[tex]^{3/2}[/tex]
f(2) = (2 + 4)[tex]^{3/2}[/tex]
f(2) = (6)[tex]^{3/2}[/tex]
f(2) ≈ 14.70
f(3) = (3 + [2×3])[tex]^{3/2}[/tex]
f(3) = (3 + 6)[tex]^{3/2}[/tex]
f(3) = (9)[tex]^{3/2}[/tex]
f(3) = 27
f(4) = (4 + [2×4])[tex]^{3/2}[/tex]
f(4) = (4 + 8)[tex]^{3/2}[/tex]
f(4) = (12)[tex]^{3/2}[/tex]
f(4) ≈ 41.57