describe the transformation of g(x)=(-1/2x) as it relates to the graph of f(x)=x

Answer:

[tex]x=4\frac{1}{8}[/tex]

Step-by-step explanation:

Step 1: Multiply (2x+5) by [tex]-\frac{3}{4}[/tex].

[tex]-\frac{3}{4}(2x+5)=-\frac{3}{4}*2x-\frac{3}{4}*5=-\frac{3}{2}x-\frac{15}{4}[/tex]

The equation becomes [tex]2\frac{1}{2}x-\frac{3}{2}x-\frac{15}{4}=\frac{3}{8}[/tex]

Step 2: Combine all terms that have a variable.

[tex]2\frac{1}{2}x-\frac{3}{2}x=\frac{5}{2}x-\frac{3}{2}x=\frac{2}{2}x=x[/tex]

The equation becomes [tex]x-\frac{15}{4}=\frac{3}{8}[/tex]

Step 3: Add [tex]\frac{15}{4}[/tex] to both sides of the equation.

[tex]x-\frac{15}{4}+\frac{15}{4}=\frac{3}{8}+\frac{15}{4}[/tex]

[tex]x=\frac{3}{8}+\frac{15}{4}=\frac{3}{8}+\frac{30}{8}=\frac{33}{8}=4\frac{1}{8}[/tex]

[tex]x=4\frac{1}{8}[/tex]

Answer:

It took 16 days

Step-by-step explanation:

400/25=16

13.5 teeth in five years

Answer:

x > -2

Step-by-step explanation:

3x>-6

Divide each side by 3

3x/3 > -6/3

x > -2

[tex] \frac{10}{ \sqrt{7} - \sqrt{2} } \\ = \frac{10}{ \sqrt{7} - \sqrt{2} } \times \frac{ \sqrt{7} + \sqrt{2} }{ \sqrt{7} + \sqrt{2} } \\ = \frac{10( \sqrt{7} + \sqrt{2}) }{( \sqrt{7} - \sqrt{2} )( \sqrt{7} + \sqrt{2} )} \\ = \frac{10 \sqrt{7} + 10 \sqrt{2} }{( { \sqrt{7} )}^{2} - ( \sqrt{2} ) ^{2} } \\ = \frac{10( \sqrt{7} + \sqrt{2} )}{7 - 2} \\ = \frac{10( \sqrt{7} + \sqrt{2} ) }{5} \\ = 2( \sqrt{7} + \sqrt{2} ) \\ = 2 \sqrt{7} + 2 \sqrt{2} [/tex]

[tex]\frac{10}{\sqrt{7} } -\sqrt{2} =\frac{10\sqrt{7} -7\sqrt{2} }{7}[/tex]

( Decimal: [tex]2.36543...[/tex])

Steps:

1: Convert element to fraction.

[tex]\sqrt{2} =\frac{\sqrt{2}\sqrt{7} }{\sqrt{7} }[/tex]

[tex]=\frac{10}{\sqrt{7} } -\frac{\sqrt{2} \sqrt{7} }{\sqrt{7} }[/tex]

2: Since denominator are equal, combine the fractions.

[tex]\frac{a}{c}[/tex] ± [tex]\frac{b}{c} =\frac{a+b}{c}[/tex]

[tex]=\frac{10-\sqrt{2} \sqrt{7} }{\sqrt{7} }[/tex]

-----------------------

[tex]\sqrt{2} \sqrt{7} =\sqrt{14}[/tex]

[tex]=\frac{10-\sqrt{14} }{\sqrt{7} }[/tex]

Rationalize [tex]\frac{10-\sqrt{14} }{\sqrt{7} }[/tex] : [tex]\frac{10\sqrt{7} -7\sqrt{2} }{7}[/tex]

[tex]=\frac{10\sqrt{7}-7\sqrt{2} }7}[/tex]

Answer:

[tex]\frac{1}{3} *\frac{1}{2} =\frac{1}{6}[/tex]

Step-by-step explanation:

So the first two balls are black, so the way to change the path is to take two out of six black balls over two out of ten balls, which is 1/3.

If the last one is red then the probability is that if you take one of the four red balls and you take one of the eight balls, you get 1/2.

So the total probability is 1/3 times 1/2 is 1/6.

Answer:

that 8/3

Step-by-step explanation:

thats because it goes too 2 2/3

9514 1404 393

Answer:

  A. 50 ft square

  B. 12√2 ft square

Step-by-step explanation:

These problems are basically the same, so have the same solution. The rectangle with maximum area for a given perimeter will have the same shape as the one with minimum perimeter for a given area.

We can find it generically. Let p represent the perimeter of a rectangular area with one side that measures x. The area will be ...

  A = x(p/2 -x) = -x^2 +(p/2)x

The area will be maximized when dA/dx = 0:

  dA/dx = -2x +p/2 = 0

  p/2 = 2x . . . . . add 2x

  x = p/4 . . . . . . divide by 2

The other dimension is ...

  p/2 -x = p/2 -p/4 = p/4

The dimensions of the maximum area for perimeter p are ...

  p/4 × p/4 . . . . . . . a square

__

$2400 worth of fence at $12 per foot is 2400/12 = 200 ft of fence. The largest possible area that can be enclosed will have dimensions of 200 ft/4 = 50 ft square:

  50 ft × 50 ft

__

The perimeter of the garden will be at its shortest when the shape of the garden is square.

  √(288 ft²) = 12√2 ft

The dimensions of the garden that will minimize the cost are ...

  12√2 ft × 12√2 ft

The maximum  number of pizzas that Mr. Braun can buy is 5.

The equation that can be used to represent the total amount spent on soda pop and pizzas is:

$75 = 5x($0.75) + x($9)

Where:

In order to determine the number of pizzas that can be bought, we have to solve for x

$75 = 3.75x + 9x

$75 = $12.75x

x = $75 / 12.75

x = 5.88

If 6 pizzas are bought, 30 drinks would be bought, the total cost would be:

6($9) + 30(0.75) = $76.50

If 5 pizzas are bought, 25 drinks would be bought, the total cost would be:

5($9) + 25(0.75) = $63.75

A similar question was answered here: https://brainly.com/question/13965560

Answer:

n = 5

Step-by-step explanation:

186 - 25 + n = 166

n + 186 - 25 = 166

n + 161 = 166

(n + 161) + (-161) = 166 + (-161)

n + 161 - 161 = 166 - 161

n = 5

Answer:

Happy birthday to you

Nobody like you

U look like a an animal go back to the zoo

Step-by-step explanation:

HINDI PO NAKATAWA

Answer:

226

Step-by-step explanation:

To find the percentage of a given value, firstly convert to a decimal by dividing by 100:

82 ÷ 100 = 0.82

Now, multiply this decimal by the number of tickets:

275 x 0.82 = 225.5

Because you can't sell half a ticket, round up.

This means the total of tickets they need to sell is 226.

Hope this helps!

Answer:

Step-by-step explanation:

Let v be her average speed from her parents house

Let t₁ be the time traveled to parents house

Let t₂ be the time traveled from parents house

t₁ + t₂ = 19

t₁ = 19 - t₂

as the distance does not change, we can equate two velocity•time statements

vt₂ = (v + 25)t₁

vt₂ = (v + 25)(19 - t₂)

vt₂ = 19v - vt₂ + 475 - 25t₂

2vt₂ = 19v + 475 - 25t₂

vt₂ = 570 and t₂ = 570/v

2(570) = 19v + 475 - 25(570/v)

1140 = 19v + 475 - 14,250/v

665 = 19v - 14,250/v

665v = 19v² - 14250

0 = 19v² - 665v - 14250

0 = v² - 35v - 750

quadratic formula

v = (35 ±√(35² - 4(1)(-750))) / 2

v = (35 ± 65) / 2

v = - 15 mph which we ignore as she did not spend hours driving backwards

or

v = 50 mph is average speed from parents house

v + 25 = 75 mph is average speed to parents house.

the trip to took 570/75 = 7.6 hrs

the trip from took 570/50 = 11.4 hrs.     total of 19 hrs.

Answer:

(c) part two is correct ans.

Step-by-step explanation:

mark me as a brainlist plz.

Answer:

Value of 5 is 500

From right to left ones, tens, hundreds, thousands, ten thousands, hundred thousands

5 is in the hundredth place

Answer:

0

Step-by-step explanation:

If you move like terms to one side you'll get

-7c + 7c = 3

0c =3

0 = 3

cannot be true, so there are zero solutions

Answer:

the magnitude of the vector is 11.40

Answer:

9

Step-by-step explanation:

It would be 9 because 7 +2 is 9 and 11 - 2 is 9.

Isn't way to hard.

Good luck on whatever you are doing.

9514 1404 393

Answer:

  9

Step-by-step explanation:

The midpoint between two values is their average. The average is half their sum.

  (7 +11)/2 = 18/2 = 9

The number 9 is halfway between 7 and 11.

_____

Check

The distance from 7 to 9 is 9-7 = 2. The distance from 9 to 11 is 11-9 = 2. The distances are the same, so 9 is halfway between 7 and 11.

Answer:

m/4

Step-by-step explanation:

Using the normal approximation to the binomial, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

The mean and the standard deviation are given by:

[tex]\mu = np = 300(0.85) = 255[/tex]

[tex]\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185[/tex]

The probability that we will have enough seats for everyone who shows up is the probability of at most 270 people showing up, which, using continuity correction, is [tex]P(X \leq 270 + 0.5) = P(X \leq 270.5)[/tex], which is the p-value of Z when X = 270.5.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{270.5 - 255}{6.185}[/tex]

[tex]Z = 2.51[/tex]

[tex]Z = 2.51[/tex] has a p-value of 0.994.

0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

A similar problem is given at https://brainly.com/question/24261244

Answer:

5 miles

Step-by-step explanation:

divide the 9 by 45 to get 6 subtract the 1 to get 4

Step-by-step explanation:

Given Question

Complete the following tables and plot the points on the graph paper yo represents the equations given below :-

[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = x + 1 & \sf & \sf & \sf \\ \\ \sf (x,y)& \sf & \sf & \sf \\ \end{array}} \\ \end{gathered} \\ [/tex]

and

[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = - 3x & \sf & \sf & \sf \\ \\ \sf (x,y)& \sf & \sf & \sf \\ \end{array}} \\ \end{gathered} \\ [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that,

[tex]\rm \longmapsto\:y = x + 1[/tex]

On substituting x = 1, we get

[tex]\rm \longmapsto\:y = 1 + 1[/tex]

[tex]\rm \longmapsto\:y = 2[/tex]

On substituting x = 2, we get

[tex]\rm \longmapsto\:y = 2 + 1[/tex]

[tex]\rm \longmapsto\:y = 3[/tex]

On substituting x = 3, we get

[tex]\rm \longmapsto\:y = 3 + 1[/tex]

[tex]\rm \longmapsto\:y = 4[/tex]

Hence,

[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = x + 1 & \sf 2 & \sf 3 & \sf 4\\ \\ \sf (x,y)& \sf (1,2) & \sf (2,3) & \sf (3,4)\\ \end{array}} \\ \end{gathered}[/tex]

Now, draw a graph using the points (1 , 2), (2 , 3) & (3 , 4)

---------------------------------------------

Given equation is

[tex]\rm \longmapsto\:y = - 3x[/tex]

On substituting x = 1, we get

[tex]\rm \longmapsto\:y = - 3 \times 1[/tex]

[tex]\rm \longmapsto\:y = - 3[/tex]

On substituting x = 2, we get

[tex]\rm \longmapsto\:y = - 3 \times 2[/tex]

[tex]\rm \longmapsto\:y = - 6[/tex]

On substituting x = 3, we get

[tex]\rm \longmapsto\:y = - 3 \times 3[/tex]

[tex]\rm \longmapsto\:y = - 9[/tex]

Hence,

[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = - 3x & \sf - 3 & \sf - 6 & \sf - 9\\ \\ \sf (x,y)& \sf (1, - 3) & \sf (2, - 6) & \sf (3, - 9)\\ \end{array}} \\ \end{gathered}[/tex]

Now, draw a graph using the points (1 , - 3), (2 , - 6) & (3 , - 9)

Answer:

2 Hola cómo estás mi amigo

Answer:

sale price SP= cost + sales tax

SP= 60 + 7% of 60

SP= 60+4.2

SP= $64.2

Answer: Calculate the sphere volume, the volume of a spherical cap or of a hemisphere thanks to this sphere volume calculator.

Answer: If the quadratic equation has real, rational solutions, the quickest way to solve it is often to factorise into the form (px + q)(mx + n), where m, n, p and q are integers. This is especially true where the coefficient of x2 is 1.

Example 1 - Solve x2+7x+12=0

Step-by-step explanation:

that's the only one I remember

Answer:

factoring, using the square roots, completing the square and the quadratic formula.

Step-by-step explanation:

Answer:

Step-by-step explanation:

x^2 + 18x + 81 = 0

x^2 + 9x + 9x + 81 = 0

x(x+9) + 9(x+9) = 0

(x + 9)(x + 9) = 0

(x + 9) = 0

x + 9 = 0

x = 0 - 9

Answer:

4

Step-by-step explanation:

( 5x - 6 ) and ( 3x + 2 ) are alternate interior angles.

Alternate interior angles are equal,

So,

5x - 6 = 3x + 2

5x - 3x = 2 + 6

2x = 8

x = 8 / 2

x = 4