The two Health and safety risk at the scene are:
1. To deal with Chemicals.
2. To deal with Electricity.
What are Healthy and safety risk?The healthy and safety risk at the scene or office is described as safety hazards that has to be taken when employers are working in office in some mechanical or electrical workshops.
Employers need to e follow some healthy and safety risk while working in office like:
1. Chemicals : When employees have to handle harmful or dangerous chemicals as part of their work. To safety safe the must wear protective clothing.
2. Electrics - Electrical safety is an important issue in workplace , especially where there is a risk that heavy-duty equipment might cause electric shock.
These are some safety hazards employees must follow.
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In a typically constructed research study, the experimental group is selected:
A. after selecting the control group.
B. systematically.
C. through random selection.
D. from a separate pool than is the control group.
Answer:
D. from a separate pool than is the control group.
Explanation:
in the picture the person answers is backwards but...
hope this helps have a nice day
Consider a 4.80 kilogram feather (from a Big Bird) on Mars. Gravity on the surface of Mars is only about 38.0% of Earth's gravity.
What would the feather weigh on Earth?
If the feather dropped on you from a height, would it be better to be on Mars or the Earth?
What does the same feather weigh on Mars?
This feather weighs heavier on earth than on Mars hence it is better that the feather falls on you in Mars than on earth.
What is weight?The term weight refers to the effect of the gravitational pull on an object. The acceleration due to gravity on earth is about 9.8m/s^2. The weight of this feather on earth is about 4.80 Kg * 9.8m/s^2 = 47 N
On the planet Mars, the weight is;
4.80 Kg * (0.38 * 9.8m/s^2) = 18 N
This feather weighs heavier on earth than on Mars hence it is better that the feather falls on you in Mars than on earth.
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the given vector A=0.3i+0.4j+Bk is a unit vector the value of B is?
Explanation:
We know that,
Magnitude of a unit vector is 1.
and, magnitude of a vector in the form [tex] \sf a \hat{i}+b \hat{j} + c \hat{k} [/tex]
is [tex] \sf \sqrt{a^2+b^2+c^2 } [/tex]
The given vector is,
[tex]\sf \vec{A}= 0.3 \hat{i} + 0.4 \hat{j} + B \hat{k}[/tex]
Magnitude of the given vector is,
[tex]\sf | \vec{A}|= \sqrt{(0.3)^2+(0.4)^2+B^2} =1[/tex]
[tex]\sf \sqrt{0.09+0.16+B^2}=1[/tex]
[tex]\sf 0.25+B^2=1[/tex]
[tex]\sf B^2=1-0.25=0.75[/tex]
[tex]\sf B = \sqrt{0.75} ≈ 0.87[/tex]
A child jumps from a moving sled with a speed of 2.2 m/s and in the direction opposite the sled's motion. The sled continues to move in the forward direction, but with a new speed of 5.5 m/s. If the child has a mass of 38 kg and the sled has a mass 68 kg, what is the initial velocity of the sled?
Answer:
p=mv , m1*v1 = m2*v2 , 2.2*38 = 68*v2 -> v2=1.23 , vf=vi+v2 -> vi=vf-v2 -> vi=5.5-1.23=4.27
my apologies if it's wrong
let the child jump, do ur work~~~
hope helpz~
The driver of a car moving at 96.0 km/h receives a text message on his cellphone. If
it takes him 6.7 seconds to read and respond to the message. How many meters
does he drive during this time?
Answer:
179 m
Explanation:
Given:
v₀ = 96.0 km/h × (1000 m/km) × (1 h / 3600 s) = 26.67 m/s
a = 0 m/s²
t = 6.7 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (26.67 m/s) (6.7 s) + ½ (0 m/s²) (6.7 s)²
Δx = 179 m
A bunny hopping along the road can travel at an average of 0.6 m/s. Calculate far the bunny can travel in 11 seconds.
Answer:
6.6 m
Explanation:
.6 m/s * 11 s = 6.6 m ( see how the 's' cancels out and you are left with 'm' as the answer ?)
A girl pushes herself up a steep ramp in her
wheelchair. She gains a vertical distance of
25.8 m when she reaches the top of the ramp.
She turns around and coasts back down the ramp
If the combined mass of the girl and her wheelchair
is 64.6 kg, what would be her coasting speed at the
bottom of the ramp?!Show all your work.
Answer:
22.5m/s, this is assuming conservation of energy and that the girl starts coasting from rest
Explanation:
conservation of energy: mgh = 1/2 m*v^2
h = 25.8m, m = 64.6kg, g=9.81m/s^2
plug in and solve for v
v = sqrt(2gh) = sqrt(2*9.81*25.8) = 22.5m/s
The coasting speed of the girl at the bottom of the ramp would be approximately 22.4 m/s.
To find the coasting speed at the bottom of the ramp, we can apply the conservation of energy principle. At the top of the ramp, the initial potential energy is converted into kinetic energy at the bottom of the ramp.
Calculate the potential energy at the top of the ramp:
Potential energy (PE) = mass (m) * acceleration due to gravity (g) * height (h)
PE = 64.6 kg * 9.8 m/s² * 25.8 m = 16114.284 J
At the bottom of the ramp, all the potential energy will be converted into kinetic energy:
Kinetic energy (KE) = 0.5 * mass (m) * velocity²
16114.284 J = 0.5 * 64.6 kg * velocity²
Solve for velocity:
velocity² = 2 * (16114.284 J) / 64.6 kg
velocity² = 500 m²/s²
velocity = √(500 m²/s²) ≈ 22.4 m/s
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The constant 40-N force is applied to the 36-kg stepped cylinder as shown. The centroidal radius of gyration of the cylinder is k = 200 mm, and it rolls on the incline without slipping. If the cylinder is at rest when the force is first ap- plied, determine its angular velocity weight seconds later.
The angular velocity of the stepped cylinder is determined as 2.35 rad/s.
Centripetal acceleration of the cylinder
The centripetal acceleration of the cylinder is calculated as follows;
F = ma
a = F/m
a = 40/ 36
a = 1.11 m/s²
Velocity of the cylindera = v²/r
v² = ar
v² = 1.11 x 0.2
v² = 0.222
v = 0.47 m/s
Angular velocity of the cylinderv = ωr
ω = v/r
ω = 0.47/0.2
ω = 2.35 rad/s
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1. What are the two factors affecting friction
A lamp with a resistance of 60 Ohms is plugged into a 110-Volt household circuit. How much current flows through the lamp?
The current flowing through the lamp is 1.833A
What is current?The current is the stream of charges which flow inside the conductors when connected across the end of voltage.
From the Ohm's law, V =IR
Here, R is the proportionality constant called resistance of the resistor
A lamp with a resistance of 60 Ohms is plugged into a 110-Volt household circuit.
I = V/R
Put the values, we get
I = 110/60
I = 1.833A
Thus, the current flowing through the lamp is 1.833A
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A 208.4 N force is pulling a 197 kg object across a horizontal surface.
The 208.4 N force acts at 32 degrees above the horizontal.
The coefficient of kinetic friction between the object and the surface is 0.455,
and the object is moved 161.5 m.
What work is done by the pulling force?
.
What work is done by kinetic friction?
.
Work done
FscosØ208.4(161.5)cos3233656.6cos3228542.4JWork done by kinetic friction:-
[tex]\mu_kN[/tex][tex]\sf \mu_Kmg[/tex]0.455(197)(9.8)878.423NAnswer:
The Work done is 28542.4J.
The work done by the kinetic friction is 878.423N
Given:
FscosØ
We put the values together.
208.4(161.5)cos32
33656.6cos32
28542.4J
Work done by kinetic friction:-
Given the formula, we put the values.
0.455(197)(9.8)
878.423N
Fig.3 shows three 10 g particles that have been glued to a rod of length L = 6 cm and negligible mass. The assembly can rotate around a perpendicular axis through point O at the left end. a) How much work is required to change the rotational rate from 40 to 60 rad/s?
b) If the outermost particle is removed, by what percentage does the rotational inertia of the assembly around the rotation axis decrease?
(a) The amount of work required to change the rotational rate is 0.0112 J.
(b) The decrease in the rotational inertia when the outermost particle is removed is 64.29%.
Moment of inertia of the rod
The moment of inertia of the rod from the axis of rotation is calculated as follows;
I = md² + m(2d)² + m(3d)²
where;
m is mass = 10 g = 0.01 kgd = 3 equal division of the lengthd = 6/3 = 2 cm = 0.02 m
I = md²(1 + 2² + 3²)
I = 14md²
I = 14(0.01)(0.02)²
I = 5.6 x 10⁻⁵ kg/m³
Work done to change the rotational rateK.E = ¹/₂Iω²
K.E = ¹/₂(5.6 x 10⁻⁵)(60 - 40)²
K.E = ¹/₂(5.6 x 10⁻⁵)(20)²
K.E = 0.0112 J
Percentage decrease of rotational inertia when the outermost particle is removedI₂ = md² + m(2d)²
I₂ = 5md²
ΔI = 14md² - 5md²
ΔI = 9md²
η = (ΔI/I) x 100%
η = (9md²/14md²) x 100%
η = 64.29 %
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answer please help me
Answer:
It is showing the wavelength.
Explanation: Hope it helps you:)))
have a good day
If 12 photovoltaic cells at 0.5 V each produce a total of 6 V of potential energy and carry a 1 A current to your phone, what are the power output of these cells and the resistance inside your phone? P = VI and R = V/I (Show calculations and units)
The power output of the cells is 6 watts and the resistance inside the phone is 6 Ohms.
What is power output?Power Output can be defined as the average rate of electric energy delivery in a circuit.
The S.I unit of power is Watts (W)
Resistance can be defined as the opposition to the flow of electric current caused by a substance.
The S.I unit of resistance is Ohm, denoted with the symbol (Ω)
How to calculate the power output and resistanceUsing the formula given;
Power output, P = VI
where V = voltage = 0.5 × 12 V = 6V
I = current = 1 A
Power output = 6 × 1 = 6 Watts
Resistance = V ÷ I = 6 ÷ 1 = 6 Ohms
Therefore, the power output of the cells is 6 watts and the resistance inside the phone is 6 Ohms.
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A boy whirls a ball on a string 1.0 m long in a horizontal circle at 50 rpm. If the mass of the ball is 0.22 kg
What is the tension in the string?
Hi there! :)
We can begin by doing a summation of forces on the ball. In the horizontal direction, we have the force of tension:
[tex]F_{Net} = T[/tex]
The tension force results in a centripetal force experienced by the ball. The equation of centripetal force is equivalent to:
[tex]F_C = m\omega^2 r[/tex]
[tex]F_C[/tex] = Centripetal force (N)
m = mass of ball (0.22 kg)
ω = angular speed of ball(? rad/sec, must convert rpm to rad/sec)
r = radius/length of string (1.0 m)
We must begin by converting rpm to rad/sec:
[tex]\frac{50 rev}{min} * \frac{2\pi rad}{1 rev}* \frac{1 min}{60 sec} = 5.236 \frac{rad}{s}[/tex]
Now, we can set tension equal to the centripetal force and solve. [tex]T = F_{Net} = F_C\\\\T = m\omega^2 r\\\\T = (0.22)(5.236^2)(1) = \boxed{6.031 N}[/tex]
Why would you expect a person with impairment of the organs of equilibrium to become more unsteady when the eyes are closed?
Answer:
A person with impairment of organs of equilibrium would compensate for their lack of sensory information by their eyes therefore if their eyes are closed they aren't able to sense their location in space accurately (Proprioception)
Explanation:
Which two questions can be used to identify criteria for how successful the design of ineffective high altitude drone is?
A. Will it become more popular than the last drone design?
B. Does it improve efficiency by 35%?
C. Can it reach an altitude of 8000 m?
D. Will it cost more than the last drone design?
E. Does it also work at low altitudes?
Option A and D are the right answer for the successful design of ineffective high altitude drone.
What are the two questions?''Will it become more popular than the last drone design?'' and ''Will it cost more than the last drone design?'' are the two questions that can be used to identify criteria for the successful design of ineffective high altitude drone because popularity and cost are the two factors which plays greater role in the success of a design.
So we can conclude that option A and D are the right answer for the successful design of ineffective high altitude drone.
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?How much work is done by 5 kg water as it is evaporated at 10 bar pressure
Answer:
The (latent) heat of vaporization (∆Hvap) also known as the enthalpy of vaporization or evaporation, is the amount of energy (enthalpy) that must be added to a liquid substance, to transform a given quantity of the substance into a gas.
The enthalpy of vaporization is a function of the pressure at which that transformation takes place. The heat of vaporization diminishes with increasing temperature and it vanishes completely at a certain point called the critical temperature (Critical temperature for water: 373.946 °C or 705.103 °F, Critical pressure: 220.6 bar = 22.06 MPa = 3200 psi ).
How do light waves differ from sound waves?
Answer:
Light waves are electromagnetic waves while sound waves are mechanical waves. :)
Electromagnets show the interaction of
a. electric current and electric
charges
b. electric charges and magnetic
dipoles
c. magnetic fields and iron filings
d. magnetic fields and electric
currents
Answer:
B
Explanation:
Electric charges and magnetic dipoles
Calculate the amount of energy needed to boil away 1.6 L of water that initially has a temperature of 55 °C.
The amount of energy needed to boil away the water at the initial temperature is 301,248 J.
Energy required to boil the water
The amount of energy needed to boil the water at the given is calculated as follows;
Q = mcΔθ
where;
m is mass of waterdensity of water = 1000 g/L
mass = density x volume
mass of water = 1000 g/L x 1.6 L = 1,600 g
Q = 1600 g x 4.184 J/g⁰C x (100⁰C - 55 ⁰C)
Q = 301,248 J
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One of the possible criteria of Schizophrenia is hallucinations.
Select one:
O True
O False
a steam engine work on its vicinity 285 k heat is released with the help of 225 c energy absorbed to the system what is the efficiency of steam engine explain the use of the rest of the energy physic problem
The efficiency of the steam engine is 78.9% because the rest of the work input is used to overcome friction.
What is efficiency of machines?Efficiency of a machine expresses the useful work done by a a machine as a percentage.
Efficiency of a machine = work output/work input × 100 %%The efficiency of machines are always less than 100% percent due to energy losses due to friction and heat.
For the steam engine:
Work output = 225 J
Work input = 285 J
Efficiency = 225/285 × 100% = 78.9 %
Therefore, the efficiency of the steam engine is 78.9% because the rest of the work input is used to overcome friction.
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How is gravity involved in the formation of stars?
what is dipersion of light
Answer:
The separation of visible light into its different colors is known as dispersion. It was mentioned in the Light and Color unit that each color is characteristic of a distinct wave frequency; and different frequencies of light waves will bend varying amounts upon passage through a prism
Explanation:
Part B
Keep track of how many hours you use the appliance in one day, and record the value below. You might want to track the
time in minutes and convert it to hours using this formula:
time in minutes = time in hours.
60
BIU X¹ X₂ 10pt
A
≡ ≡ 四
The number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
Average daily power consumptionThe average daily power consumption is the amount of electric energy consumed by an individual on a daily rate.
The average daily power consumption of individuals in USA is 12,100 W-hr.
Converting watts to kilowattsE = 12,100 Whr/1000
E = 12.1 kWh
Thus, the number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
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Ampère placed two 1.50-m wires parallel to each other so that they were 4.80 cm apart.
He delivered a current of 6.50 A to the wires. Both wires experienced an external
magnetic field of 2.71 X 10^−5 T. Determine the force on one of the wires.
The force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.
Force on the wire
The force between the two parallel wire is calculated as follows;
F = μI²L/2πr
where;
I is the current in the two wiresL is length of the wiresr is the distance between the wiresF = (4π x 10⁻⁷ x 6.5² x 1.5)/(2π x 0.048)
F = 2.64 x 10⁻⁴ N
Force per unit length of the wireF/L = 2.64 x 10⁻⁴ N / 1.5
F/L = 1.76 x 10⁻⁴ N/m
Thus, the force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.
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Tearing of paper is said to be a change that cannot be reversed. What about paper recycling? Explain.
BEST ANSWER WILL BE MARKED
Answer:
Recycling of paper cannot be reversed thus making it an irreversible change
Explanation:
When we recycle paper an entirely new product can be made which cannot be changed back to paper
Three sticks are arranged to form a right triangle. If the lengths of the three sticks are 0.47 m, 0.62 m and 0.78 m, what are the three angles of the triangle?
An ocean liner leaves New York City and travels 18.0o north of east for 155 km. How far east and how far north has it gone? In other words, what are the magnitudes of the components of the ship’s displacement vector in the north and the east direction, respectively?