De acuerdo con una encuesta se determino que en una region hay igual numero de personas lic en administracion comercio servicio de salud y servicio municipal ademas se encontro que 35% de los administrativos 25% de los comerciantes 20% de los servidores de salud y 15% de servicio municipal son mujeres cual es la probabilidad de que una mujer escogida al azar del grupo sea administradora

Answer:

La probabilidad de que una mujer sea administradora es de 0,35

Step-by-step explanation:

Sean A B, C y D los eventos de las mujeres administrativas, comerciantes, trabajadoras de salud y proveedoras de servicios municipales.

Sus probabilidades están dadas por

P (a) = 35% = 0,35

P (b) = 25% = 0,25

P (c) = 20% = 0,2

P (d) = 15% = 0,15

Como los eventos son independientes, la probabilidad conjunta sería

P (B∩C∩D) = P (D) * P (B) * P (C) = 0.25 * 0.2 * 0.15 = 0.0075

P (A / B∩C∩D) = P (A∩B∩C∩D) / P (B∩C∩D)

                        = 0,35 * 0,0075 / 0,0075 = 0,35

Por lo tanto, la probabilidad condicional de obtener la mujer administradora es la misma que la probabilidad individual de obtener la administradora, ya que los eventos son independientes.

La probabilidad de que una mujer sea administradora es de 0,35

English

Let A B, C and D be the events of the women administrative, merchants, health workers and municipal services providers.

Their probabilities are given by

P (a) = 35% = 0.35

P (b)= 25% = 0.25

P (c) =20% = 0.2

P (d) = 15 % = 0.15

As the events are independent then the joint probability would be

P (B∩C∩D)= P(D) * P(B)* P (C) = 0.25* 0.2*0.15= 0.0075

P(A/B∩C∩D) = P(A∩B∩C∩D)/P(B∩C∩D)

                        = 0.35*0.0075/ 0.0075= 0.35

Therefore the conditional probability of getting the administrator woman is the same as the individual probability of getting the woman administrator  as the events are independent.

Probability of woman administrator is 0.35

2 2 7 :(0.6x)= 4 21 :0.25

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