Can someone please help me with this I'm not great with math.

The width of a rectangle is unknown. The length of the rectangle is two more units than its width.

Write a simplified algebraic expression for the area of the rectangle in terms of width (w).

Write your answer in descending order with no spaces. Use w as your variable and use ^ infront of exponents

Answer:

10.5 inches, 14 inches, 7 inches

Step-by-step explanation:

Let's say x is the multiplier of the ratio value and the actual length of the sides:

1/4 * x = side 1

1/3 * x = side 2

1/6 * x = side 3

Since the perimeter is the sum of all sides, the perimeter is equal to:

31.5 = 1/4 * x + 1/3 * x + 1/6 * x  ==> 31.5 inches is the perimeter

(31.5 = x/4 + x/3 + x/6)*12  ==> multiply the equation by 12 since 12 is the

                                           LCM (Least Common Multiple) of 4, 3, and 6

12 * 31.5 = 12 * x/4 + 12 * x/3 + 12 * x/6  ==> multiply each term by 12

378 = 12x/4 + 12x/3 + 12x/6 ==> simplify

378 = 3x + 4x + 2x

378 = 9x

x = 378/9 ==> divide both sides by 9

x = 42

Now find each side length [Refer to the first three equations] :

Side length 1: 1/4 * 42 = 42/4 = 10.5 inches

Side length 2: 1/3 * 42 = 42/3 = 14 inches

Side length 3: 1/6 * 42 = 42/6 = 7 inches

Answer: 10.5 inches, 14 inches, 7 inches

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The value of StartFraction P (t) Over A EndFraction for this problem will be 20

Take the value of x that they provide you and plug it into the problem for these kinds of difficulties.

The fraction's numerator is the highest number. It stands in for the entire thing that must be divided.

A fraction's denominator is the value at the bottom. It shows how many equally sized pieces are divided up in the object.

adding 3 to the formula:

6/(3) + 2(3)^2 —> use PEMDAS. Apply the 32 exponents first, followed by left-to-right multiplication and division, and finally addition.

6/x + 2x^2,

when x = 3

=20

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The question the incomplete the full question:

What is the value of StartFraction 6 Over x EndFraction + 2x2, when x = 3?

Answer:

The second part is 0.8 and B. About 1,845 years.

Step-by-step explanation:

:)

With 8 percent increase each year the Sutton family's condo's worth in 8 years will be $216000.

An exponential function is a mathematical function in the form f(x) = ax, where {x} is a variable and {a} is a constant which is called the base.

Given is that Condos in Georgetown go up in value by 10% each year. Sutton family's condo's current worth is $120,000.

We can write the function to calculate the worth after {T} years as follows.

A{T, R} = A{I} {1 + RT}

A{T, R} = {120000} {1 + (10/100) x 8}

A{T, R} = {120000} {1 + 0.1 x 8}

A{T, R} = {120000} {1 + 0.8}

A{T, R} = {120000 x 1.8}

A{T, R} = 216000

Therefore, the Sutton family's condo's worth in 8 years will be $216000.

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Answer: not enough to answer

Answer:

she has rode 16 miles this week

Step-by-step explanation:

3 miles on monday 3 times that many on tuesday plus 4 miles one wensaday add them all up

3 times 3 is 9 plus 3 is 12 plus 4 is 16 there fore 16 miles in totale

sorry for my speling erros

She rode a total distance of 16 miles this week.

An expression in mathematics is a combination of terms both constant and variable. For example, we can write the expressions as -

2x + 3y + 5

2z + y

x + 3y

The distance rode by Lexi per day is mentioned below -

Monday - Lexi rode 3 miles on a bike.

Tuesday - Lexi rode 3 times more than she did Monday.

Wednesday - Lexi rode an additional 4 miles.

We can write the expression to find the total distance in miles covered by Lexi as -

d = d{M} + d{T} + d{W}

d = 3 + (3 + 3) + 4

d = 3 + 6 + 4

d = 13 miles

Therefore, she rode a total distance of 16 miles this week.

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After 10 years the balance of the account will be $13000.

A simple interest is one that does not compound anyway. In this system, a creditor only pay interest on the initial amount and the rate of interest is not changed during the time period.

given, initial deposit money = initial principal amount = $8000

initial money is denoted by P

interest rate (annually), r = 6%

generally, simple interest is annual.

expected amount after t years = final amount = $13000

final amount is denoted by A.

t is the time in years.

According to the formula for simple interest, A = P (1 + rt)

                                                           $13000 = $8000(1 + 6/100×t)

                                                        $13000/ $8000 = (1 + 0.06t)

                                                         (1 + 0.06t) = 1.625

                                                        0.06t = 0.625

                                                        t = 10.417 years or t = 10 years

Therefore, after 10 years the balance of the account will be $13000.

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Step-by-step explanation:

(1). x-intercept: Put y = 0 in the equation y = 2x - 6 and solve for x. The x-intercept is 3.

y-intercept: Put x = 0 in the equation y = 2x - 6 and solve for y. The y-intercept is -6.

(2). x-intercept: Put y = 0 in the equation y = x - 7 and solve for x. The x-intercept is 7.

y-intercept: Put x = 0 in the equation y = x - 7 and solve for y. The y-intercept is -7

(3). x-intercept: Put y = 0 in the equation y = (3/2)x - 9 and solve for x. The x-intercept is -6.

y-intercept: Put x = 0 in the equation y = (3/2)x -9 and solve for y. The y-intercept is -9.

(4). x-intercept: Put y = 0 in the equation y = (-1/4)x + 1 and solve for x. The x-intercept is -4.

y-intercept: Put x = 0 in the equation y = (-1/4)x + 1 and solve for y. The y-intercept is 1.

(5). x-intercept: Put y = 0 in the equation -x + y = -5 and solve for x. The x-intercept is 5.

y-intercept: Put x = 0 in the equation -x + y = -5 and solve for y. The y-intercept is -5.

(6). x-intercept: Put y = 0 in the equation x + 2y = -14 and solve for x. The x-intercept is -14.

y-intercept: Put x = 0 in the equation x + 2y = -14 and solve for y. The y-intercept is -7.

(7). x-intercept: Put y = 0 in the equation 3x - y = -3 and solve for x. The x-intercept is -1.

y-intercept: Put x = 0 in the equation 3x - y = -3 and solve for y. The y-intercept is 3.

(8). x-intercept: Put y = 0 in the equation 5x + 3y = 15 and solve for x. The x-intercept is 3.

y-intercept: Put x = 0 in the equation 5x + 3y = 15 and solve for y. The y-intercept is 5.

We can express √832 as 4(2√13).

A definite integral of a function can be represented as the signed area of the region bounded by its graph.

Given is the root of 832 or √832.

Assume that {4n} is equal to {y}. So, we can write -

y = 4n

Squaring both sides, we get -

y² = (4n)² = (√832)²

y² = 16n² = 832

16n² = 832

n² = (832/16)

n² = 52

n = √52

n = 2√13

So, we can write (√832) as 4(2√13).

Therefore, we can express √832 as 4(2√13).

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Step-by-step explanation:

we need to use both equations for the volumes.

the only variables in them are r1 and r2.

when we say both results (volumes) are equal, that means we can create an equation with one formula on one side and the other formula on the other side.

and then we can easily transform the equation into "r1 = ..." or "r2 = ..."

and yes, your teacher made a mistake by hinting to solve for r1 in a. and b. it is r1 in a. and r2 in b.

a.

the goal here is an equation in the form

"r1 = ..."

that means r1 is a function of r2.

36×pi×r1² = 1/2 × 4/3 × pi × r2³ = 4/6 × pi × r2³ =

= 2/3 × pi × r2³

36 × r1² = 2/3 × r2³

r1² = (2/3 / 36) × r2³ = (1/(3×18)) × r2³ = 1/54 × r2³

r1 = sqrt(1/54 × r2³) = 1/3 × sqrt(1/6 × r2³)

b.

the goal here is

"r2 = ..."

again

36×pi×r1² = 2/3 × pi × r2³

36 × r1² = 2/3 × r2³

3×36 × r1² = 2 × r2³

3×18 × r1² = r2³

54 × r1² = r2³

[tex]r2 = \sqrt[3]{54 \times {r1}^{2} } = 3 \times \sqrt[3]{2 \times {r1}^{2} } [/tex]

c.

r2 is doubled.

so, we have to go back to our equation of a.

r1 = sqrt(1/54 × r2³).

when r2 is doubled, we get

r1 = sqrt(1/54 × (2×r2)³) = sqrt(1/54 × 8 × r2³) =

= sqrt(8) × sqrt(1/54 × r2³)

so, when r2 doubles, r1 has to grow by the factor of sqrt(8) to keep the equality intact.

The triangle LJK is congruent to the triangle RTS.

What do congruent triangles mean?

Triangles that are congruent share the same matching side lengths and angle measurements. The conditions for triangle congruence are: SSS, SAS (Side, Side, Side) (Side-Angle-Side)

According to the given image of triangles,

We can observe that:

∠L=∠R, ∠T=∠J, ∠S=∠K.

We can also observe that TS=JK, LK=RS, RT=LJ.

Therefore according to SSS congruency ΔLJK ≅ ΔRTS.

According to SAS congruency ΔLJK ≅ ΔRTS.

According to ASA congruency ΔLJK ≅ ΔRTS.

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Answer: 11, 23, 166

Step-by-step explanation:

Hiya! From the drawings, I'm assuming all of the triangles are right-angled triangles. If they aren't though, tell me and I'll tell you how to solve them.

Anyways, assuming they are right angled-triangles, you can use Pythagoras' Theorem (aka a² + b² = c²)

c is the hypotenuse or the side opposite the right angle.

a and b are just the other two sides (doesn't really matter which is which)

Question 7:

c² = a² + b²

12² = a² + 5²

144 = a² + 25

144 - 25 = a²

119 = a²

a = 10.908712114635714411502154487373

(To the nearest whole number: 11)

Question 8:

c² = a² + b²

24² = 7² + b²

576 = 49 + b²

576 - 49 = b²

527 = b²

b = 22.956480566497992703585747092065

(To the nearest whole number: 23)

Question 9:

c² = a² + b²

c² = 90² + 140²

c² = 8,100 + 19,600

c² = 27,700

c = 166.43316977093238068928214785346

(To the nearest whole number: 166)

Hoped this helped! Tell me if there's something you don't understand. :)

The solution to the system of equations is x = 4 and y = 2.

We would use the elimination method to solve the system of equations:

Let's eliminate the variable y by adding equations 1 and 2:

4x + 8y = 24

2x + y = 19

.

.

.,

6x + 9y = 43

Now we can eliminate the variable x by subtracting equation 3 from the above equation:

6x + 9y = 43

3x + y = 15

.

.

.

3x + 8y = 28

We now have an equation with one variable: 3x + 8y = 28. We can solve for x by dividing both sides by 3:

x = (28 - 8y) / 3

Now we can substitute this expression for x into one of the original equations and solve for y. Let's use equation 4:

4x + 2y = 12

Substituting x = (28 - 8y) / 3:

4((28 - 8y) / 3) + 2y = 12

If we simplify:

Finally, we can use this value of y to find x by plugging it into the expression we found earlier:

x = (28 - 8(2)) / 3

x = (28 - 16) / 3

x = 12 / 3

x = 4.

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A linear equation in two variables has only 1 solution.

Now, According to the question:

Let's know:

The linear equations in one variable is an equation which is expressed in the form of ax+b = 0, where a and b are two integers, and x is a variable and has only one solution. For example, 2x+3=8 is a linear equation having a single variable in it. Therefore, this equation has only one solution, which is x = 5/2. Whereas if we speak about linear equation in two variables, it has two solutions.

An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0.

A linear equation in two variables has only 1 solution.

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I think it's answer this .

Answer:

the answer is (3,4) and (2,3)

Step-by-step explanation:

that's my answer

Using the calculator there are various methods according to the calculator we used and the approach we follow, Basic answer is to select N and generate random number.

Random sampling is a method of selecting a sample from a population in such a way that each member of the population has an equal probability of being selected. This ensures that the sample is representative of the population, and reduces bias in the sampling process. In simple random sampling, a random sample is drawn from a larger population by using random number generators, tables of random numbers, or other methods that ensure that each member of the population has an equal chance of being selected.

A sample is a portion or a subset of a population that is selected for the purpose of studying characteristics of the population. The sample is used to make inferences or conclusions about the population from which it was drawn. The sample is usually smaller in size than the population, and it is selected through a process called sampling. The process of sampling is used to select a sample that is representative of the population, meaning that the sample has similar characteristics as the population.

Define the population size (N) and the sample size (n) that you want to obtain.

Use the calculator's random number generator to generate a random number between 1 and N. This will be the first element of your sample.

Repeat step 2 to generate the remaining elements of the sample, making sure that each element is different from the previous ones.

Record the elements of the sample, which are the random numbers that have been generated.

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In order to find the negation of an expression we simply put the not operator in front of them . Therefore, the negation of ∃ is that â is not ^ to f.

The term negation means opposite , that is the negation of a statement is the opposite of the given mathematical statement. If we will take the example of P , let P be a statement, then the negation of P will be represented by ~P.

There are two  symbols which are  used to represent the negation of a statement which are “~” or “¬”. Therefore, ~P is known as the negation of P.

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Answer:

y = 3/2x - 3

Step-by-step explanation:

first find slope (m):

m = (-3/2 -(-15/2)) / (1 - (-3)) = (12/2) / 4 = 6/4 = 3/2

plug the point (1, -3/2) into the point-slope form (y-y1) = m(x-x1):

y - (-3/2) = 3/2(x-1)

y + 3/2 = 3/2x -3/2

now put it in slope-intercept form y = mx + b:

y = 3/2x -6/2

y = 3/2x - 3

Answer:10

Step-by-step explanation: Because negative 40 equals -50 + x equals 10

Answer:

4/8
3/8 + 1/8 = 4/8

Answer: A pendulum of length 1m and period 2.01s is placed at the top of Mount Everest having an altitude of 8849m. Calculate the value of 'g' at that point.

The period of this pendulum can be solved using the formula shown in the picture below. T is the period in seconds; L is the length in meters and g is the acceleration due to gravity which is equal to 9.81 m/s²near the equator.

T = 2 × π × (square root of 1.00 m / 9.81 m/s²)

T = 2 * 3.1416 * (square root of 0.101936799)

T = 6.2832 * 0.319275428

T = 2.00 seconds

The period of this pendulum correct to 3 significant figures is 2.00 seconds.

The frequency of this pendulum is solved by the formula f = 1/T

f = 1/2.00 seconds

f = 0.500 hertz

Answer: 9.76 m/s^2

Step-by-step explanation:

Answer:

y = -1/5x - 3.6

Step-by-step explanation:

(2, -4) and (-3, -3)

m = -3+4/ -3-2

m = 1/-5

m = -1/5

y = -1/5x + b

-4 = -1/5(2) + b

-4 = -0.4 + b

b = -3.6

y = -1/5x - 3.6

Answer:

x = 5/3, y = 2/3

Step-by-step explanation:

x + 1/3 = 2 equ 2

The company is likely to sell 3,120 copies of rock music per week.

If the company estimates sales of 6,000 copies a week at its online store, it is likely that 78/150 x 6,000 = 3,120 copies will be from the rock genre.

To find this, we first need to calculate the proportion of visitors that preferred rock music by dividing the number of visitors who preferred rock (78) by the total number of visitors surveyed (150). This gives us 78/150 = 0.52.

Next, we multiply this proportion by the estimated number of weekly sales at the online store (6,000) to find the number of sales that are likely to be from the rock genre. 0.52 x 6,000 = 3,120.

So, the company is likely to sell 3,120 copies of rock music per week.

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Answer: t = 0

Step-by-step explanation:

Expand 8950×0.7²: 4385.5t

8950(0.7) ²t

8950×0.49t = 4385.5t

N(t) = 4385.5t

N(t) - 4385.5t=0

Factor N(t) - 4385.5t: t (N - 4385.5)

t (N - 4385.5) =0

t=0

Answer:

62 candies can fit into each box

Step-by-step explanation:

We know

A small box can hold 94.24 g of candy

Each candy has a mass of 1.52 g

How many candies can fit into each box?​

To find it we take

94.24 divided 1.52 = 62 candies

So, 62 candies can fit into each box

The combined cost of 0.7 pound of strawberries and 1.4 pounds of apples is $8.778.

The Latin word "poundus," which means "weight," is whence its name originates.

Any of the many weight and mass units. especially: a measurement that is commonly used by English-speaking peoples and equals 16 ounces (about 0.454 kilograms) see measurement. the United Kingdom's fundamental monetary unit. known also as the pound sterling.

Given that A pound of strawberries costs $3.28

and a pound of apples costs $4.63

So the combined cost of 0.7 pound of strawberries and 1.4 pounds of apples is

cost = $3.28(0.7) + $1.4(4.63)

cost = $2.296 + $6.482

cost = $8.778

Therefore, the answer is $8.778.

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The area of the figure given is 49 square feet's.

       ∫dA = ∫∫F(x, y) dx dy

       A =  ∫∫F(x, y) dx dy

Given is a figure as shown in the image attached.

We can write the area of the figure as -

A = A{T} + A{R}

A = (4 x 10) + (1/2 x 6 x 3)

A = 40 + 9

A = 49 square feet's

Therefore, the area of the figure given is 49 square feet's.

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x2 - 3x - 5 = 0 has a unique solution of type -11, which is what the equation entails.

The "discriminant" is the value that aids in identifying the many types of solutions when using the quadratic formula to solve a problem. It is a unique function of a co-efficient in a mathematical equation (a quadratic equation), and the value it yields provides details about the roots of the equation. Calculating the discriminant involves square rooting the "b" term and subtracting four times the "a" term from the "c" term. Alongside "D," there is a (delta) that represents discrimination. A quadratic equation with two distinct real number solutions is said to have a positive discriminant. A quadratic equation with a discriminant of zero has repeated real number solutions. Both of the solutions are not real numbers, as indicated by a negative discriminant.

given

x2 - 3x - 5 = 0

D=b2−4ac

D= −32−4×1×5

D=92−20

D= −11

x2 - 3x - 5 = 0 has a unique solution of type -11, which is what the equation entails.

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When the state of an object is changed from one to another it is known as translation in mathematics and they are of three types.

The three types of translation in math are

When the object moves either from left to right or from right to left it is known as vertical translation.

The movement in up or downward direction of the graph is known as  horizontal translation.

The domain of the function remains same in both the cases.

A translation in which the size of the object decreases or is compressed is known as the compression translation.

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