Calculate the mass of compound (molar mass = 256 g [tex] mol {}^{-1} [/tex] ) to be dissolved in 75g of benzene to lower its freezing point by 0.48K
( [tex]K _{f} = 5.12 \: K \: \: kg \: mol { }^{ - 1} [/tex] )


thankyou.​

Answers

Answer 1

The mass of the compound is calculated by freezing point depression formula which is ΔTf=Kf×W₂×1000/M₂×W₁ which is equal to 3125 g.

What is a compound?

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.

Freezing point depression is calculated by the formula, ΔTf=Kf×W₂×1000/M₂×W₁ .Therefore,W₁=5.12×75×1000/0.48×256=3125 g.

Thus, mass of compound is 3125 g.

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Related Questions

Pls help with question a and b.

Answers

a) 1 - Trigonal planar 2 - Trigonal planar

b) 1- Linear  2 - Tetrahedral  3 - Tetrahedral

c) 1 - Trigonal planar 2 - Tetrahedral

What are the shapes?

We have to know that the shapes at the various carbon atoms and other atoms would depend on the number of the electron pairs and the hybridization of the atom.

We must have to note that the shape of the atom can be found on the basis of the valence shell electron pair repulsion theory which deals with the arrangement of that electrons around the outermost shell of the central atom.

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determine the mass of IF5 in a 15.88 L sample at 378 K and 0.935 atm

Answers

The mass of [tex]IF_5[/tex] that would be in a 15.88 L sample at 378 K and 0.935 will be 106.51 grams.

Ideal gas problem

The problem can be solved by first using the ideal gas equation to know the number of moles of the gas that is present.

PV = nRT

P = 0.935, V = 15.88 L, T = 378 K, R = 0.082

Making n the subject of the formula:

n = PV/RT

  = (0.935x15.88)/(0.082x378)

   = 0.48 moles of the gas

Recall that, mass = mole x molar mass

The molar mass of [tex]IF_5[/tex] is 221.89 g/mol

Mass of 0.48 moles [tex]IF_5[/tex] = 0.48 x 221.89

                                       = 106.51 grams

In other words, the mass of [tex]IF_5[/tex] that would be in a 15.88 L sample at 378 K and 0.935 is 106.51 grams.

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Use the data in the table below to calculate the heat of vaporization (AHvap) in kJ/mol of pinene.
Vapor Pressure
(torr)
760
515
340
218
135


Temperature
(K)
429
415
401
387
373
kJ/mol
Use the value of AHyap determined in Part 1 to calculate the vapor pressure of pinene (in torr) at room temperature (23°C)
760
torr

Answers

Answer:

41 kJ/mol4 torr

Explanation:

Given pinene has a (temperature, vapor pressure) relation (K, torr) = {(373, 135), (429, 760)}, you want the heat of vaporization in kJ/mol and the vapor pressure at room temperature (23 °C).

Clausius–Clapeyron Equation

The Clausius–Clapeyron equation can be used to find the heat of vaporization:

  [tex]\ln{P}=-\dfrac{\Delta H_{\text{vap}}}{R}\left(\dfrac{1}{T}\right)+C[/tex]

Solving for ∆H, we find ...

  [tex]\Delta H_{\text{vap}}=-\dfrac{R\cdot\ln{\dfrac{P_1}{P_2}}}{\dfrac{1}{T_1}-\dfrac{1}{T_2}}\\\\\\\Delta H_{\text{vap}}=-\dfrac{8.314\cdot\ln{\dfrac{760}{135}}}{\dfrac{1}{429}-\dfrac{1}{373}}\approx 41052.8[/tex]

The heat of vaporization of pinene is about 41 kJ/mol.

Vapor pressure

Rearranging the above equation to give P1, we have ...

  [tex]\ln{\dfrac{P_1}{P_2}}=-\dfrac{\Delta H_\text{vap}}{R}\left(\dfrac{1}{T_1}-\dfrac{1}{T_2}\right) \\\\\\P_1=P_2\cdot e^{-\frac{\Delta H_\text{vap}}{R}\left(T_1^{-1}-T_2^{-1})}[/tex]

Using the same P2 and T2 as above, we find the vapor pressure at room temperature (296.15 K) to be ...

  P1 ≈ 4.349 . . . . . torr

The vapor pressure of pinene at room temperature is about 4 torr.

Please help me fill in the blanks

Answers

Sublevels are indicated by letters s, p, d, and f.

How do write Electronic configuration?

Electron configurations have a standard notation that tells you the principle energy levels and sublevels that electrons occupy. here is Sulphur:

The atomic number of Sulphur is 16.

the electronic configuration of Sulphur is 1s2 2s2 2p6 3s2 3p4.

The 4s sublevel has lower energy than the 3d sublevel,

so, it fills next.

Which four different electron configurations are there?

One orbital can house a maximum of two electrons, and there are four different types of orbitals (s, p, d, and f). More electrons can be held in the p, d, and f orbitals since they contain various sublevels. According to its location on the periodic table, each element's electron configuration is distinct.

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Use the ideal gas law to find the volume that 4.30 mol of oxygen gas occupies at 99.7 kPa and 35.0 °C.
help please

Answers

According to the ideal gas law, 4.30 molecule of o2 occupies 0.11 m³ at 99.7 kPa with 35.0 °C.

What is a straightforward definition of ideal gas law?

The relationship between a gas's pressure P, volumes V, and t in the range between low pressures and extremely high temperatures, when the gas's water moves virtually independently of one another, is known as the ideal gas, also known as the perfect gas law.

PV = nRTp = pressure in PaV

= volume in m³n = number of molesR

= molar gas constant (8.31 JK⁻¹mol⁻¹)T

= temperature in Kpressure ⇒ 99.7 × 10³ Pa

temperature ⇒ 35.0 + 273 = 308

KpV = nRT

= 99.7×10³×V= 4.30×8.31×308V

=(4.30×8.31×308)/(99.7×10³3 )V

= 0.11 m­³

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Which statement about the elements in Group 0 is correct?
Tick () one box.
A. All elements in the group are very reactive.
B. All elements in the group form negative ions.
C. The boiling points increase down the group.
D. The relative atomic masses (Ar) decrease down the group.

Answers

The boiling points increase down the group.Thus, option C is the answer.

Group 0, also known as the noble gases, is a group of chemical elements in the periodic table. These elements are all characterized by having a full valence shell of electrons, which gives them little tendency to gain or lose electrons and makes them generally unreactive. As a result, the elements in Group 0 are not very reactive and do not form many compounds.

The boiling points of the elements in Group 0 generally increase as you go down the group. This trend is due to the increasing atomic radius of the elements as you go down the group. The larger the atomic radius, the more space there is between the atoms in a substance, and the more energy is required to overcome the attractive forces between the atoms. This results in a higher boiling point.

In contrast, the relative atomic masses (Ar) of the elements in Group 0 generally decrease as you go down the group. This is because the atomic radius increases as you go down the group, but the number of protons in the nucleus (and therefore the atomic mass) does not change significantly. As a result, the relative atomic mass decreases as the atomic radius increases.

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URGENT PLEASE HELP

1) The following balanced chemical equations are for based on the combustions of various fuels. Calculate the heats of combustion for each reaction

a. C2H5OH(l) + 3O2(g) à 2CO2(g) + 3H2O(g)






b. 2C4H10(g) + 13O2(g) à 8CO2(g) + 10H2O(g)











c. C3H8(g) + 5O2(g) à 3CO2(g) + 4H2O(g)











2) Express the heats of combustion from the above reactions as energy changes per mole of fuel combusted. State the reason why energy changes are often expressed per mole of reactant.





3) An Electric Generator burns gasoline to produce electricity. The balanced equation is below:


2C8H18(l) + 25O2(g) à 16CO2(g) + 18H2O(g)


a. Calculate the energy change for the burning of gasoline.











b. If the generator produces 2000kJ of electrical energy for every mole of gasoline combusted calculate the efficiency of the generator.

Answers

Answer:

Explanation:

1) The following balanced chemical equations are for based on the combustions of various fuels. Calculate the heats of combustion for each reaction a. C₂H₂OH + ...

46 g of glycerin were dissolved in 100 g of water. What is the freezing point of this solution?


Additional information:
М(С3Н5(ОН)3) = 92 g/mol;
Тf(Н2О) = 273.15 К;
Кf = 1.86 kg⋅К/mol.

Answers

Based on the formula to determine the freezing point depression of the solvent, the freezing point of the solution is 263.85 K.

What is the freezing point of a substance?

The freezing point of a substance is the temperature at which the liquid changes to solid without any further decrease in temperature occurring during the process.

The addition of solute substances in liquids usually lowers the freezing point of the liquid solvent.

The formula to determine the freezing point depression of solvent is given below:

ΔT = i * Kf * m

where'

ΔT is the change in freezing point,i is the van't Hoff factor,Kf is the freezing point depression constant, andm is the molality of the solution.

The molality of the given solution = moles of solute/kg of solvent

moles of solute = 46/92

mass of solvent = 100 g or 0.1 kg

Molality of solution = (46/92) / 0.1

Molality of solution = 5

for glycerine, i = 1

ΔT = ΔT = 1 * 1.86 * 5

ΔT = 9.3

The freezing point of the solution = 273.15 - 9.3

The freezing point of the solution = 263.85 K

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Please help me fill in the blanks

Answers

Electrons first occupy the position in lowest possible energy.

orbital diagrams:-

The higher the energy level, the Third energy the electrons in that level have. On the orbital diagram, fill in the boxes to label the representations of an orbital and a sublevel.   2   electrons can occupy a single orbital, and these electrons have Opposite spin. Within a sublevel, all the orbitals fill with one electron, each of which has the Positive spin before a second electron fills any of the orbitals.

what is Orbital?

Each energy position is made up of areas known as an orbital. An orbital is an area of probability in which electrons can be set up. Each energy position, except for the first, has further than one orbital. Each orbital has a specific shape.

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Neera and Tom dissolved different masses of salt in 500 cm³ of water.
They measured the temperature at which each salt solution boiled.
salt
solution
(They wrote down the variables that might affect the investigation.
temperature of the
mass of salt
laboratory
dissolved in water
boiling point of
salt solution
thermometer
volume of water
starting temperature
of the water
type of salt used

Answers

The variables that might affect the investigation while dissolving different masses of salt are temperature and mass of the salt.

In the provided investigation, what are the independent and dependent variables?

A variable that changed during the inquiry is regarded as an independent variable and is called "mass of salt dissolved in water." While the investigation's dependent variable, "boiling point of salt solution," is a variable that was monitored.

What are variables in a laboratory?

There are numerous things that can be changed to see how they affect other things. Variables are the changeable quantities. Any element, character trait, or condition that can exist in a variety of forms or concentrations is a variable. Independent, dependent, and controlled variables are the three types of variables that often make up an experiment.

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Neera and Tom dissolved different masses of salt in 500 cm3 of water.

They measured the temperature at which each salt solution boiled.

(a) They wrote down the variables that might affect the investigation.

temperature of the laboratorymass of salt dissolved in waterstarting temperature of the waterboiling point of salt solutionvolume of watertype of salt used

(i) What is the independent variable (the variable they changed) in

their investigation?

(ii) What is the dependent variable (the variable they measured) in

their investigation?

(iii) Which variable above would affect the experiment the least?

What effect does light have on the growth of plants?

Select all that apply.
Light does not have any effect on a plant’s growth.
Light makes a plant’s stem grow shorter.
Light makes a plant’s leaves turn brown.
Light will make a plant’s leaves grow bigger.

Answers

Answer:

The answer is the last one only.

Explanation:

Light/sun gives energy and growth which makes the plants leaves/plant grow bigger.

Explanation:

Without the sun, plants wouldn't get the food that's needed to grow, reproduce and survive. plants need sunlight, water and carbon dioxide to live.

use the kinetic particle model to describe the motion and separation of the particles in solid carbon dioxide and carbon dioxide gas

Answers

In solid carbon dioxide (dry ice), the particles are held together by strong covalent bonds, so they do not move around much.

What is the carbon dioxide?

Carbon dioxide (CO2) is an odorless, colorless gas created through natural processes such as respiration, combustion and the breakdown of organic materials. As a greenhouse gas, it is a major component of the Earth’s atmosphere and plays a critical role in regulating the global climate. Carbon dioxide is made up of one carbon atom and two oxygen atoms, and is produced when fossil fuels such as coal and oil are burned. Plants and trees also use carbon dioxide as part of their photosynthesis process. Carbon dioxide is essential for life on Earth, however, too much of it can have a negative impact on our planet. As human activity has increased over the past century, so too has our production of CO2, resulting in higher concentrations of this gas in the atmosphere and contributing to global warming.

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What is the name of the ionic compound formed from lithium and bromine?

Why is the answer lithium bromide? What is the indicator that this is the correct name, rather than lithium bromate? Is this because a compound would need to contain 3 different atoms and oxygen to have the name lithium bromate? Is that why NaNO3 is Sodium Nitrate?

Answers

Answer:

The answer is lithium bromide because it is the combination of a metal (lithium) and a nonmetal (bromine). The indicator that this is the correct name, rather than lithium bromate, is that the compound is composed of only two elements and does not contain oxygen. Yes, this is why NaNO3 is Sodium Nitrate; it is composed of three different elements (sodium, nitrogen, and oxygen).

Explanation:

How many oxygen atoms are in 1.00 kg of carbon dioxide?

Answers

Answer: I believe its two

Explanation:

1. what are the methods of vegetative propagation
2.give examples of organisms exihibiting each type
3.tubers-definitio example potatoes

science subject

Answers

Natural vegetative propagation uses bulbils, aerial shoots, roots, underground stems, and subaerial stems. Utilizing unique vegetative components, artificial vegetative propagation is accomplished.

What is vegetative propagation, and how does it work?

The production and growth of a new plant through asexual means or from a plant fragment is known as vegetative propagation. There is no gamete production or fertilization throughout the process of propagation.

What are some instances of vegetative tuber propagation?

In this procedure, tubers—modified roots—grow into new plants. In some plant species, adventitious buds even grow on the roots. If the correct circumstances are present, these buds develop into new plants or sprouts. Sweet potato and dahlia are two examples.

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For this assignment, you will make a scale model—a “core sample”—showing the layers of the Earth: crust, lithosphere, asthenosphere, mantle, outer core, and inner core.

Answers

To make a scale model of the Earth's layers, you will need the following
-A large, clear plastic container
-A ruler
-A variety of different colored modeling clay
-A sharp knife
-A marker

Instructions:
1. Measure the height of the plastic container and mark it with the marker.
2. Cut the modeling clay into thin slices with the knife.
3. Begin layering the clay slices in the container, starting with the crust at the bottom.
4. Layer the lithosphere, asthenosphere, mantle, outer core, and inner core in order.
5. Use the ruler to measure the thickness of each layer and mark it with the marker.
6. Once all the layers are in place, your scale model of the Earth's layers is complete!

Hope that helps !?
To make a scale model of the Earth's layers, you will need the following materials:

Cardboard or foam board
Scissors
Glue
Markers or paint
Ruler
First, decide on a scale for your model. For example, you could use a scale of 1 inch = 1000 miles. This means that for every 1 inch on your model, it represents 1000 miles in the actual Earth.

Next, use your ruler to measure and cut out strips of cardboard or foam board to represent the layers of the Earth. The crust is the outermost layer and is relatively thin, while the inner core is the innermost layer and is the thickest. Use your markers or paint to label each layer and add any additional details or information you would like to include on your model.

Finally, glue the layers together in the correct order, starting with the crust at the top and ending with the inner core at the bottom. Your scale model of the Earth's layers is now complete!

What is the ratio between the numbers 30 and 90

Answers

the answer is 1:3 ……
30:90
1:3

you can divide it

Bauxite ore contains aluminum oxide, which is decomposed using electricity to
produce aluminum metal and oxygen. What mass of aluminum metal can be
produced from 125 g of aluminum oxide?

Answers

Answer:

66.48 g.

Explanation:

Bauxite ore contains aluminium oxide which is decomposed using electricity to produce aluminium metal and oxygen gas

For this discussion, you get to explore one specific element and share the historical context and modern day application of that element with the class. Your initial post should address the following questions about the element you chose:

1. How did the element you chose get its name and who discovered it?
2. What are the properties this element possesses that places it where it is in the periodic table?
3. Write a sufficient summary of the element in common language that could be understood by the general public.
4. Describe the implications for society, benefits, drawbacks, practicality, and reactivity of the element.
5. What are some applications and hazards of this element and how is it commonly encountered?
6. Discuss your personal thoughts regarding the element.
7. Questions to your classmates that invite discussion and further the dialogue.
8. An embedded picture that is relevant to the discussion.
9. Give a citation of an external peer reviewed resource that you would like to

Answers

My exploration in one specific element as well as the sharing of the historical context and modern day application will be focused in the element Carbon. The essay is written below

What is carbon historical context?

Carbon was discovered by the ancient Egyptians, and it gets its name from the Latin word "carbo," which means "charcoal."

Carbon is a nonmetal that is located in Group 14 of the periodic table. It has a unique ability to form a wide variety of chemical compounds, which is one of the reasons it is so important in modern chemistry. Carbon has four valence electrons, which allows it to form stable chemical bonds with other elements.

Carbon is a chemical element that is found in all living things. It is a key component of proteins, DNA, and other essential biomolecules. Carbon can exist in several different forms, including graphite, diamond, and various forms of carbon-based compounds called organic molecules.

Carbon has many important implications for society. It is used as a fuel to produce energy, and it is also a key ingredient in the production of steel and other metals. Carbon is also an essential component of many plastics and other synthetic materials. However, carbon can also have negative impacts on the environment, as the burning of fossil fuels releases carbon dioxide into the atmosphere, contributing to climate change.

Carbon has many practical applications, including its use as a fuel, a structural material, and a chemical feedstock. However, carbon can also be hazardous in certain situations. For example, inhaling carbon monoxide can be deadly, and carbon dust can be explosive. Carbon is commonly encountered in many different forms, including coal, oil, and natural gas.

Personally, I think that carbon is a very interesting element with a wide range of important applications. It is fascinating to consider the role that carbon plays in the biology of living organisms, as well as its practical uses in industry and technology.

Some questions for my classmates might include: What are some other interesting properties of carbon that you have learned about? Can you think of any examples of how carbon is used in your everyday life? Do you think that the benefits of carbon outweigh the potential drawbacks?

One peer-reviewed resource that I found informative is "The Many Forms of Carbon," an article published in the journal Chemical & Engineering News. (Citation: "The Many Forms of Carbon." Chemical & Engineering News, vol. 95, no. 39, 2017, pp. 38-54.)

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Conduct research to identify two naturally occurring radioactive elements and two synthetic radioactive elements.

Answers

Natural radioactive elements are those that spontaneously radiate in nature and have an atomic number between 82 and 92. In dirt, air, water, rocks, plants, food, uranium—a radioactive element—can be discovered.

What makes certain substances radioactive?

When an element's atoms contain excess neutrons or protons, the extra energy produced in the nucleus causes the atom to lose its equilibrium or become unstable. if and how radioactive particles can become stable. Radiation is produced by radioactive atoms' unstable nuclei.

What radiation is the most dangerous?

Compared to beta and gamma particles, alpha particles represent the most dangerous internal threat. The most hazardous methods of exposure to radioactive elements that release alpha and beta radiation are ingestion, inhalation, absorption, and injection. Gamma radiation is the outside hazard that causes the most damage.

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an oxygen atom, the number of nucleons is 16. What is its atomic mass?​

Answers

Answer:

oxygen-16 is a stable isotope of oxygen, having 8 neutrons and 8 protons in its nucleus. It has a mass of 15. u

The information provided below was obtained from the label of the commercial stock
bottle of concentrated tetraoxosulphate (VI) acid. Calculate the volume of the acid that
is needed to prepare 8dm3
of 0.5moldm-3
solution of the compound from the stock.
Specific gravity of H2SO4 = 1.84gcm-3
% purity of acid =97%
Molar mass = 98gmol-1

Answers

The volume of acid required to prepare 8dm3 of 0.5moldm-3 solution of the compound is 203 cm3.

What is volume?

Volume is the amount of space that an object or substance occupies. It is typically measured in cubic units, such as metres cubed (m³). Volume is an important concept in mathematics, physics, and engineering. Volume plays an important role in everyday life; for example, the volume of water in a swimming pool can be measured to determine how much water needs to be added or subtracted. Volume is also used to measure the amount of a substance, such as oil or gas. The volume of a container can also be used to measure the amount of material contained within it. Volume can also be used to measure the capacity of a container, such as a bucket or a tank. In addition, volume can be used to calculate the mass of an object by measuring its density.

The mass of acid required to prepare 8dm3 of 0.5moldm-3 solution of the compound is:
M = 8 x 0.5 x 98 = 392 g
The volume of acid required to prepare 8dm3 of 0.5moldm-3 solution of the compound is:
V = 392 / (1.84 x 0.97) = 203 cm3
Therefore, the volume of acid required to prepare 8dm3 of 0.5moldm-3 solution of the compound is 203 cm3.

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How many short columns are on the periodic table?

Answers

Answer:

They are 4 short column on the periodic table

What is the molecular weight of H2O

Answers

Answer:

18.015

Explanation:

Using the periodic table of the elements to find atomic weights, we find that hydrogen has an atomic weight of 1, and oxygen's is 16. In order to calculate the molecular weight of one water molecule, we add the contributions from each atom; that is, 2(1) + 1(16) = 18 grams/mole.

A chemist has one solution that is 30.% acid and another solution that is 18% acid. How much of each solution should be used to get 300. L of a solution that is 21% acid?

a. 23 L of the 30.% solution and 277 L of the 18% solution
b. 75 L of the 30.% solution and 225 L of the 18% solution
c. 131 L of the 30.% solution and 169 L of the 18% solution
d. 138 L of the 30.% solution and 162 L of the 18% solution
e. 244 L of the 30.% solution and 56 L of the 18% solution

Answers

There is a golden rule of solubility, non polar solute dissolve in non polar solvent and polar solute dissolve in polar solvent. Therefore, the correct option is option B.

What is solution?

Solution is a homogeneous mixture of two or more than two substances. A solution is a homogeneous mixture of solute and solvent molecules. Solvent is a substance that is in large amount in solution. solute is the substance which is in small amount in a solution.

There are two types of mixture that is homogeneous and heterogeneous. Solution is a homogeneous solution. The nature of solvent tells about whether the solvent is in liquid, solid or gas form.

Let amount of 30% to mix, be X

Then amount of 18% to mix = 300 - X

0.3X + 0.18(300 - X) = 0.21(300)

0.3X+ 0.18(300) - 0.18X= 0.21(300)

0.3X - 0.18X =0 .21(300) -0 .18(300)

0.12X =0 .03(300)

X=75L

Therefore, the correct option is option B.

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what mechanism of formation of magma is represented by the experiment.justify your answer




need Kona Po please ​

Answers

Explanation:

This hot material rises to an area of lower pressure through the process of convection. Areas of lower pressure always have a lower melting point than areas of high pressure. This reduction in overlying pressure, or decompression, enables the mantle rock to melt and form magma.

Which one of the following pairs are the common languages of science?
A. English & Latin
B. Mathematics & Units
C. Standards & Measures
D. English & French

Answers

Answer:

a whole new world too be into

Explanation:

I think is't B. Mathematics & amp; units

What mass of 65% and 20% nitric acid must be mixed to produce 4.5 kg of 30% nitric acid?

Answers

The mass of 65% and 20% nitric acid that must be mixed to produce 4.5 kg of 30% nitric acid are 1.306 kg and 3.189 kg respectively.

What is the volume of 4.5 kg of 30% nitric acid?

The volume of 4.5 kg of 30% nitric acid is determined using the formula below:

Volume = mass/density

The density of 30% nitric acid is 1.18 g/mL

The mass of the  30% nitric acid is 4.5 kg or 4500 g

Hence, the volume will be:

The volume of 30% nitric acid = 4500 / 1.18

The volume of 30% nitric acid = 3813.56 mL

The volume of 65% and 20% nitric acid required is then determined.

Let the volume of the 65% and 20% nitric acid be x and y respectively;

x + y = 3813.56 ---(1)

amount of acid in 3813.56 ml solution = 30% * 3813.56

amount of acid in 3813.56 ml solution = 1144.07 mL

therefore;

60% * x + 20% * y = 1144.07 mL

0.6x + 0.2y = 1144.07 ----(2)

Solving for x and y in the two equations

From (1), x = 3813.56 - y

Substitute x = 3813.56 - y in (2)

0.6(3813.56 - y) + 0.2y = 1144.07

0.4y = 1144.07

y = 2860.18 mL
x = 3813.56 - 2860.18

x = 953.38 mL

The mass of the acids required is then determined as follows:

The density of 60% nitric acid is 1.37 g/mL

Mass of 60% nitric acid required = 953.38 mL * 1.37 g/mL

Mass of 60% nitric acid required = 1306 g or 1.306 kg

The density of 20% nitric acid is 1.115 g/mL

Mass of 20% nitric acid required = 2860.18 mL * 1.115 g/mL

Mass of 20% nitric acid required = 3189 g or 3.189 kg

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Osmosis.
10 % solution of sodium chloride is on the first side of the semipermeable membrane separating the vessel and 2 % solution of sodium chloride is on its other side. Describe the process taking place there.

Answers

Answer:

Osmosis is taking place in the vessel, where a 10% solution of sodium chloride is on one side of the semipermeable membrane and a 2% solution of sodium chloride is on the other side. Osmosis is a special case of diffusion, where water moves from an area of higher concentration to one of lower concentration. In this case, water will move from the 10% solution to the 2% solution, as it has a higher solute concentration. This process is known as osmoregulation and it involves maintaining salt and water balance across membranes within the body’s fluids. The key to remember about osmosis is that water flows from the solution with the lower solute concentration into the solution with higher solute concentration. As such, in this case, water will flow from the 2% solution to the 10% solution.

Explanation:

Which of the following statements is/are incorrect regarding dilution of concentrated sulphuric acid?

Answers

Answer:

Option d) 3 only is the right answer

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