Brett draws the shape shown below.
He says the shape can be classified as a quadrilateral, parallelogram, rhombus, and square.
Is Brett correct? Explain.

Answer:

The one on the top left

Step-by-step explanation:

What makes a function, a function is that the x coordinate (x,y), cannot be repeated in the tables. The y coordinate can though.

A group of young men decided to raise Ksh.480000 to start a business. Before actual payment was made four members pulled out and each of the remaining had to pay an additional Ksh.20000. Write an expression in terms of P for.

(a) (i) Original contribution of each member.

(ii) Contribution after withdrawal of four members.

(b) Form an equation in P and hence determine the number of initial members.

(c) Three men Kamau, James and Hassan shared Shs.480000 such that Kamau: James is 3: 2 and James: Hassan is 4: 2. Find how much each got.

The big arc is 2.09 centimeters longer than the small arc.

For a circle of radius R, if we define an arc with an angle θ, the length of that arc will be:

L = (θ/360°)*2πR

Where π = 3.14

in this case, for both arcs, we have θ = 120°.

For the smaller arc, the radius is R = 5cm, so we get:

L = (120°/360°)*2*3.14*5cm = 10.47 cm

For the larger arc, the radius is R = 5cm, so we get:

L' =  (120°/360°)*2*3.14*6cm = 12.56 cm

Then we can see that:

L' - L = 12.56 cm -  10.47 cm = 2.09 cm

So the largest arc is 2.09 centimeters longer than the smaller arc.

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Answer:

True

Step-by-step explanation:

The coordinate of the point is (6,-2)

The given parameters are:

A = (1,8)

B = (7,-4)

The location of the point (i.e 5/6) means that the ratio is:

m :n = 5 : (6 - 5)

m : n = 5 : 1

The coordinate of the point is then calculated as:

[tex](x,y) = \frac{1}{m + n}* (mx_2 + nx_1,my_2 + ny_1)[/tex]

So, we have:

[tex](x,y) = \frac{1}{5 + 1}* (5 * 7 + 1 * 1 , 5 * -4 + 1 * 8)[/tex]

Evaluate

[tex](x,y) = \frac{1}{6}* (36 , -12)[/tex]

Evaluate the product

(x,y) = (6,-2)

Hence, the coordinate of the point is (6,-2)

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Answer:

7

Step-by-step explanation:

350÷50=7

................

Answer:

-2, 5, 12, 19, 26, 33, 40, 47, 54, 61, 68, 75, 82, 89, 96, 103

Answer:

x = 6.3

Step-by-step explanation:

since the quadrilaterals are similar then the ratios of corresponding sides are in proportion, that is

[tex]\frac{QR}{KL}[/tex] = [tex]\frac{RS}{LM}[/tex] ( substitute values )

[tex]\frac{x}{7}[/tex] = [tex]\frac{3.6}{4}[/tex] ( cross- multiply )

4x = 7 × 3.6 = 35.2 ( divide both sides by 4 )

x = 6.3

Answer:

2/8, 3/12 and 4/16

Step-by-step explaination:

All these fractions are equivalent to 1/4 as the numerator is a multiple of 1, the denominator is a multiple of 4, and the numerators are all a quarter of their respective denominators.

Answer:

rhombus

Step-by-step explanation:

If ABCD is a parallelogram, then AB and CD are opposite sides and should be equal

3x - 4 = x + 18

subtract x.

2x - 4 = 18

add 4.

2x = 22

divide by 2.

x = 11

Find the lengths of the sides.

AB= 3(11)-4 = 29

BC= 2(11)+7 = 29

CD = 11+18 = 29

If BC is 29, then DA must also be 29. So all four sides are the same, it is a rhombus.

The shape of experiment 1 is roughly bell shaped. This indicates that it is normally distributed. The shape of experiment 2 is asymmetrical. This indicates that it is not normally distributed.

A dot plot is a graph that is used to represent the frequency of a data set using dots. The dots represents the frequency of a number.  The results from experiment 1 is more spread out over the numbers compared to experiment 2 which is concentrated around the center.

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Answer:

A - x = 4

Step-by-step explanation:

According to The Midsegment Trapezoid Theorem the length of the midsegment is the sum of both bases divided by 2.

So to find the value of x:

x + 3 + 4x  7 = 15*2  add like terms

5x + 10 = 30 subtract 10 from both sides

5x = 20 divide both sides by 5

x = 4

Step-by-step explanation:

¿qué es eso?¿es esto importante? :)

Answer:

As ΔABC is an isosceles triangle:

⇒ BA = BC  
(the dashes on the line segments indicate they are of equal measure)

⇒ ∠BAC = ∠BCA = 55°

⇒ ∠BCA = ∠BAD = 55°

Angles on a straight line sum to 180°

⇒ ∠ADE + ∠EDC = 180°

⇒ 98° + ∠EDC = 180°

⇒ ∠EDC = 82°

As BE intersects AC, the vertically opposite angles are equal:

⇒ ∠BDC = ∠ADE = 98°

⇒ ∠ADB = ∠EDC = 82°

Interior angles in a triangle sum to 180°

⇒ ∠BAD + ∠ADB + ∠ABD = 180°

⇒ 55° + 82° + ∠ABD= 180°

⇒ ∠ABD = 180° - 55° - 82°

⇒ ∠ABD = 43°

Answer:

∠ABD = 43°

Step-by-step explanation:

Let's solve !

⇒ ∠BAC = ∠BCA = 55° (Angles opposing equal sides)

⇒ ∠BDA = 180° - 98° (Linear pair)

⇒ ∠BDA = 82°

⇒ ∠BAC + ∠BDA + ∠ABD = 180° (Angle Sum Property)

⇒ ∠ABD + 82° + 55° = 180°

⇒ ∠ABD + 137° = 180°

⇒ ∠ABD = 43°

Answer:

6 races

Step-by-step explanation:

If he won 40% of the races he competed in, and he raced 15 times, this means that he won roughly 4/10 races.

4/10= ?/15

cross multiply 4 and 15 = 60

60/10 = 6

He won 6 races

Give brainliest please!

hope this helps :)

The first option, “yes, the conditions for inference are met” is correct.

It is described as a collection of data with the same entity that is linked to a problem. The sample is a subset of the population, yet it is still a part of it.

Lets you're conducting an experiment on the honesty of a random sample of 50 persons. A total of 42 adults were assessed to be trustworthy.

It has to be determined whether the conditions of inference are satisfied.

A) The randomness of the sample.

The sample is given to be randomly selected. So, this condition is satisfied.

B) The number of success and failures must be at least 10.

The success rate is 0.80, and the sample size is 50. As a result, the following conditions must be met:

[tex]\rm n_p\geq 10 \ and \ n\left ( 1-p \right )\geq 10[/tex]

[tex]\rm 50\left ( 0.80 \right )=40 > 10[/tex]

[tex]\rm 50\left ( 1-0.80 \right )=10=10[/tex]

As a result, the sample size is sufficient, and the big numbers requirement is met.

C) 10% condition:

The sample size is modest, at 50 people, and hence represents less than 10% of the population.

As a result, the inference requirements are met.

Thus, the first option “yes, the conditions for inference are met” is correct.

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Answer:

The answer to this question is -11

The area of the triangle is 608 cm².

Area is the region bounded by a plane shape.

To calculate the area of the triangle, we use the formula below.

Formula:

Where:

From the question,

Given:

If

Substitute these values into equation 1

Hence, the area is 608 cm².

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1. 0.0563

2. 0.05

3. 0.008

4. 0.6

5. eight tenths

6. six tenths three hundredths

7. eight five thousandth

8. six hundredths

Answer:

the answer to the question above would be the option 3 (vertex)

Explanation:

1) sin(37º)=x/10.3————>trigonometric ratio (sine)

2)7²+10²=c²—————-> pythagorean theorem

3) using sine—————> sin(51º)=9/x

using tangent —————> tan(51º)=9/x and x = 7.3 (rounded)

4)using pythagorean theorem————> 6²+7²=c²

angle b is tanx=6/7 where x = 40.6 degrees, angle a is tanx=7/6 where x = 49.4

Answers:

1)x= 6.2

2)x= 12.2

3)x= 11.6 (rounded)

4)x= 9.2

credit to genan for question 3 and 4

ur welcome :)

correct me if im wrong

brainliest please?

Answer: 123.84

Step-by-step explanation: You can set pi as 3.14. Then, you get 123.836576. Round to the nearest hundredth to get 123.84.

[tex]\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\[/tex]

[tex]\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\[/tex]

[tex]\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625[/tex]

Answer:

[tex]16[/tex]

Step-by-step explanation:

[tex]~~~~~~x^2 -8x = 5 \\\\\implies x^2 -2\cdot 4 \cdot x+ 4^2 = 5+ 4^2~~~~~~~~~~~~;[\text{Add}~ 4^2 = 16 ~ \text{to both sides }]\\\\\implies (x-4)^2 = 21[/tex]

The simplification of the expression is 28. The mistake in your calculation occurred in step 3.

TO simplify expressions involving brackets, we use a common method called BODMAS (Brackets, Of, Division, Multiplication, Addition, and Subtraction).

This means that we will first solve the expression in brackets first, followed by division, multiplication, addition, and subtraction as the case may be.

Now, from the given information, we have:
= 22+6[(14-5)÷3(17-14)]

solving parameters in the bracket first, we have:
= 22 + 6[(9) ÷3(3)]

= 22 + 6[(9) ÷9]          

= 22 + 6[(9) ÷9]    

= 22 + 6[ 1]

= 22 + 6

= 28

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0.16 (with 6 repeating) = 1/6

3.16 = 3 1/6

Mixed Number = 3 1/6

Improper Fraction = 19/6

Hope this helps!

Answer:

3 4/25

Step-by-step explanation:

[tex]\frac{3.16}{1} \cdot \frac{100}{100} = \frac{316}{100}[/tex]

[tex]\frac{316 \div 4}{100 \div 4} = \frac{79}{25}[/tex]

[tex]= 3\frac{4}{25}[/tex]

A type I error takes place if a given null hypothesis is rejected but is said to be true in the population such as the forecast shows it is snowing outside but actually it is isn't.

A type II error is known to be a statistical term that tells the error that takes place when one fails not to accept a null hypothesis that is said to be really false. A type II error create a false negative.

Note that:

The power of the test shows that:

See full question below

Suppose you have the following null and alternative hypothesis:

H o: it is snowing.

H a: It is not snowing

(A) in the context of this problem, describe a Type-1 error

(B) Describe Type II error

(C)Describe power of the test

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Answer:

a) [tex](3x)^{15} + 15(3x)^{14}(\frac{2}{x}) + 105(3x)^{13}(\frac{2}{x})^2 + ... + 15(3x)(\frac{2}{x})^{14} + (\frac{2}{x})^{15}[/tex]

b) [tex](2x)^{20} + 20(2x)^{19}(-\frac{3}{x}) + 190(2x)^{18}(-\frac{3}{x})^2 + ... + 20(2x)(-\frac{3}{x})^{19} + (-\frac{3}{x})^{20}[/tex]

Step-by-step explanation:

The binomial expansion formula is:
[tex](a + b)^n = a^n + \binom{n}{1}a^{n-1} b + \binom{n}{2}a^{n-2}b^2 + ... + \binom{n}{r}a^{n-r}b^{r} + ... + b^n[/tex]
The (n r) in front of each term is the binomial coefficient. This can be calculated on a calculator using the nCr button (in this case, you'd put 15C1 for (n 1), 15C2 for (n 2), etc). This can be calculated without a calculator using this formula:
[tex]\binom{n}{r} = \frac{{n!}}{{r!\left( {n - r} \right)!}}[/tex]

In a), a = 3x, b = 2/x and n = 15.

You can plug these into the formula above to get:
[tex](3x)^{15} + 15(3x)^{14}(\frac{2}{x}) + 105(3x)^{13}(\frac{2}{x})^2 + ... + 15(3x)(\frac{2}{x})^{14} + (\frac{2}{x})^{15}[/tex]

Here's how to do this without the formula:

You could 'simplify' this by expanding the brackets, but this gives you massive numbers so it's probably best to leave it like this.

Applying this to b):

a = 2x, b = -3/x, n = 20

[tex](2x)^{20} + 20(2x)^{19}(-\frac{3}{x}) + 190(2x)^{18}(-\frac{3}{x})^2 + ... + 20(2x)(-\frac{3}{x})^{19} + (-\frac{3}{x})^{20}[/tex]