Which relationships have the same constant of proportionality between y and x as the following table?
y
4
32
7
56
8 64
Choose 3 answers:

Answer:

4

Step-by-step explanation:

f(-3) = 2 * (-3) + 10

Answer:

0.3 recurring so 0.33333333333333333333333333333333333333

and....

__________________________________________________________

How to Overcome Insecurity

Step 1

The first step of Voice Therapy involves vocalizing your self-critical thoughts in the second person.You can also write down these thoughts.

Step 2

In the second step, you can start to think and talk about the insights and reactions you have to exposing these mean thoughts.

Step 3

People often struggle with the third step of this process, because it involves standing up to long-held beliefs and insecurities about oneself. You will answer back to your voice attacks, expressing your real point of view.

Step 4

In step five of Voice Therapy, you start to make a connection between how the voice attacks are influencing your present-day behaviors.

Step 5

The final step involves making a plan to change these behaviors. If insecurity is keeping you from asking someone on a date or going after a promotion, it’s time to do the actions anyway. If you’re indulging in self-hating thoughts that encourage you to engage in self-destructive behaviors, it’s time to interrupt these behaviors and unleash the real you.

Hope it help and if it did please give brainliest

Stay safe and healthy

Thank You

Answer:

88.75%

Step-by-step explanation:

add all the terms given = 355

there are 4 terms.in this set.

355 ÷ 4 = 88.75

Answer:

x=-1±[65]

________

8

Step-by-step explanation:

solve the equation for xby finding a,b, and come of the quadratic then applying the quadratic formula

Answer:

  7.38×10^3

Step-by-step explanation:

The usual rules of exponents apply.

  (20.5×10^7)(3.6×10^-5) = (2.05)(3.6)(10^(8-5)) = 7.38×10^3

_____

Additional comment

You can have your scientific or graphing calculator or your spreadsheet compute this product for you and display the result in scientific notation. You can enter the numbers in scientific notation or in standard form in any calculator or spreadsheet. (For a spreadsheet, the first number would be entered 20.5e7 or 2.05e8.)

The applicable rule of exponents is ...

  (10^a)(10^b) = 10^(a+b)

Just as the place values increase by factors of 10 going to the left of the decimal point, so they decrease by factors of 10 to the right. The number 3 in 0.000036 is in the 5th place to the right of the decimal point, so has a place value of 10^-5.

Answer:

the number 0 Originally called finding the vertical asymptote.

she drove for 4  hours

Answer:

the person above me is wrong its not an option for me ;-;

Step-by-step explanation:

Answer:

start at 5 on the number line and move 8 to the left.

Step-by-step explanation:

Answer:

Here is your answer hope I helped! <3

Step-by-step explanation:

t=k/3-p/3

Answer:

Step-by-step explanation:

If you're supposed to plot that, it would be a line from (0, 10) to (5, 0)

slope would be -2 mi/hr

Answer:

[tex]\boxed{\tt \frac{40}{9}} \ \sf or \ \boxed{\tt 4 \frac{4}{9}}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to solve for the sum of 2 fractions.}[/tex]

[tex]\large\underline{\textsf{What are Fractions?}}[/tex]

[tex]\textsf{Fractions are representations of rational numbers that can be represented as part}[/tex]

[tex]\textsf{of a whole number.}[/tex]

[tex]\underline{\textsf{What are the parts of a fraction?}}[/tex]

[tex]\textsf{Fractions have 2 parts, they're called the Numerator and the Denominator.}[/tex]

[tex]\frac{\sf Numerator}{\sf Denominator}[/tex]

[tex]\textsf{The Numerator represents the amount of equal parts a certain rational number}[/tex]

[tex]\textsf{has compared to the Denominator. The Denominator represents the total amount}[/tex]

[tex]\textsf{of parts that make a fraction equal to 1. If the Numerator is the same as the}[/tex]

[tex]\textsf{Denominator, then the fraction is just 1. If the Numerator is greater than 1, then}[/tex]

[tex]\textsf{this kind of fraction is considered an Improper Fraction, and improper fractions}[/tex]

[tex]\textsf{are fractions that are improper due to the Numerator being greater than the}[/tex]

[tex]\textsf{Denominator, which means these fractions shouldn't be represented as fractions,}[/tex]

[tex]\textsf{but there's nothing wrong with representing it as a fraction.}[/tex]

[tex]\textsf{Since we know what majority of fractions are, we may begin adding these fractions}[/tex]

[tex]\textsf{which are improper.}[/tex]

[tex]\large\underline{\textsf{How are we able to Add Fractions?}}[/tex]

[tex]\textsf{Adding Fractions is simply adding the Numerators together since the Denominator}[/tex]

[tex]\textsf{can't be changed, if so then the equation won't be equal.}[/tex]

[tex]\textsf{*Remember that when adding fractions we must have common denominators.}[/tex]

[tex]\textsf{This means that we should find the LCM (Least Common Multiple) of the}[/tex]

[tex]\textsf{Denominators.}[/tex]

[tex]\underline{\textsf{For our problem;}}[/tex]

[tex]\textsf{Since we already have Common Denominators, we are able to simply add the}[/tex]

[tex]\textsf{Numerators.}[/tex]

[tex]\large\underline{\textsf{Solving;}}[/tex]

[tex]\textsf{Add the Numerators together.}[/tex]

[tex]\tt \frac{\boxed{\tt 23}}{9} + \frac{\boxed{\tt 17}}{9} =\boxed{\tt \frac{40}9}[/tex]

[tex]\tt \frac{40}{9} \ \textsf{can be our final answer. However, since our sum is an Improper Fraction, it's}[/tex]

[tex]\textsf{greater than 1. Since 40 can divide into 9 about 4 times, our whole number will}[/tex]

[tex]\textsf{be 4, and the remainder will be our fraction.}[/tex]

[tex]\underline{\textsf{Explained in numerical;}}[/tex]

[tex]\tt \frac{40}{9} = \frac{9}{9} + \frac{9}{9} + \frac{9}{9} + \frac{9}{9} + \frac{4}{9} = \boxed{\tt 4 \frac{4}{9}}[/tex]

[tex]*\tt \frac{36}{9} = \frac{4}{1}[/tex]

[tex]\textsf{These are called Whole Number Fractions.}[/tex]

[tex]\large\underline{\textsf{Hence;}}[/tex]

[tex]\tt \frac{23}{9} + \frac{17}{9} = \boxed{\tt \frac{40}{9}} \ \sf or \ \boxed{\tt 4 \frac{4}{9}}[/tex]

[tex]\large\underline{\textsf{Learn more about Fractions;}}[/tex]

https://brainly.com/question/26180542

[tex]\textsf{This answer will give you a great review of how to turn word-form problems into}[/tex]

[tex]\textsf{fractions, and how to simpify those fractions.}[/tex]

Answer:

5.164×10^-5

Step-by-step explanation:

[tex]5.164 \times {10}^{ - 5} [/tex]

Answer:

260

Step-by-step explanation:

A=bh

A=13 x 20

A=260

Answer: yes they are

Step-by-step explanation:

Answer:

Can you put the screen more closer to the values

Step-by-step explanation:

Or you could type  in the values so i can see.

Answer:

Edges = 18

Step-by-step explanation:

We know that

v - e + f = 2

Where,

v = vertices

e = edge

f = faces

So,

12 - e + 8 = 2

20 - e = 2

20 - 2 = e

18 = e

Answer:

18 edges

Step-by-step explanation:

As said in the answer before it is 18. The equation used to find the answer is the Euler's Formula : F+V=E+2. Where F is faces, V is vertices, and E is edges. If given the F and V then all you have to do is add them together and subtract 2. Toodles ;)

PS: ACELLUS SUCKS

Answer:

Merry Christmas to u, ik i can't help but I would just like to say merry Christmas to u too

Answer:

45°, 75°, 61°, 44°, 22°, 86°

Step-by-step explanation:

They have to be angles less than 90°.

Answer:

  (c)  75°, 61°, 44°

  (d)  22°, 86°, 72

Step-by-step explanation:

The largest angle must be less than 90°, and the sum of angles must be 180°. These conditions are met by the lists of angles shown above.

Answer:

-32>x

Step-by-step explanation:

-16>x÷2

-16×2>x

-32>x

The point-slope equation of the line as described by the points is; y + 5 = -4(x - 2).

The equation of the line given in the task content in the point-slope form can be determined as follows;

Slope = (-5-3)/(2-0) = -8/2 = -4.

Hence, it follows that point-slope form of the equation of the line is; Choice A; A. y + 5 = -4(x - 2).

Read more on point-slope equation;

https://brainly.com/question/24907633

#SPJ1

Answer:

answer is 25

Step-by-step explanation:

EKJ = 90, same as JHF, and EJK is 65 (because EJF =115 and 180-115=65

65+90=155

180-155=25

Answer:

72/5

Step-by-step explanation:

18/5 x4 = t/4 x4

(18x4)/5 = t

t = 72/5

Answer:

Option B is correct.

add 4 times the second equation to 3 times the first equation

Step-by-step explanation:

Answer:

B) add 4 times the second equation to 3 times the first equation

Step-by-step explanation:

So you have these two equations:

2x - 4y = 6

-3x + 3y = 12

In order "to solve this system of equations by elimination" we want to make BOTH of the equations have a term (in this case the y term) and have the same coefficient (that's the number right next to the y) If they are the exactly same number, even the same sign in front, then we would subtract the equations. If they have the same coefficient but different signs, then we would add the equations. This will eliminate the y term completely. So in order to make them have the same coefficient. We'll multiply the first equation by 3 and the second equation by 4

3(2x - 4y = 6)

4(-3x + 3y = 12) multiplying all the way across the equation (distributing)

We'll get

6x -12y = 18

-12x + 12y = 48 Then you are actually adding from the top, down and get one equation from adding the two existing ones together.

-6x = 66 And then you are able to solve it by dividing both sides by -6 to get

x = -11

You can then use either equation and x = -11 to find y. Your solution is the x, y pair. You can check it by putting the x and y into both equations and finding it makes a true statement in both.

Answer:  -0.65 approximately

Work Shown:

[tex]\log_{9}(0.24) = \frac{\log(0.24)}{\log(9)}\\\\\log_{9}(0.24) = \frac{\log(0.03*8)}{\log(3^2)}\\\\\log_{9}(0.24) = \frac{\log(3*10^{-2}*2^3)}{\log(3^2)}\\\\\log_{9}(0.24) = \frac{\log(3)+\log(10^{-2})+\log(2^3)}{\log(3^2)}\\\\\log_{9}(0.24) = \frac{\log(3)-2\log(10)+3\log(2)}{2\log(3)}\\\\\log_{9}(0.24) \approx \frac{0.477-2*1+3*0.301}{2*0.477}\\\\\log_{9}(0.24) \approx \frac{-0.62}{0.954}\\\\\log_{9}(0.24) \approx -0.649895\\\\\log_{9}(0.24) \approx -0.65\\\\[/tex]

Step-by-step explanation:

in the first object:

force = mass × acceleration = 2 × 14 = 28 N

in the second object :

force = mass × acceleration

28=mass×4

then the mass = 28/4 = 7 kg

Answer:

[tex]a_{87}=1119[/tex]

Step-by-step explanation:

Arithmetic sequence:

[tex]a_n=a_1+(n-1)d[/tex]

where d is the common difference between terms and n is the index of any given term.

Find the difference between the terms in the given sequence here:

[tex]14-1=13\\27-14=13[/tex]

Each term has a common difference of 13. Using that, you can write the equation for this sequence:

[tex]a_n=1+(n-1)13[/tex]

Finally, you can use this equation to find the 87th term by plugging in 87 for n:

[tex]a_{87}=1+(87-1)13\\a_{87}=1+(86)13\\a_{87}=1+1118\\a_{87}=1119[/tex]

Answer:

width is 4

height is 20

Step-by-step explanation:

Area=½ width × height

let the width be x

height will be 6x - 4

40 = ½ × x × (6x - 4)

40 = 2/2 × 3x² - 2x

40 = 3x² - 2x

3x² - 2x - 40 = 0

3x² -12x + 10x - 40 = 0

3x(x-4) + 10(x-4) = 0

(3x + 10)(x - 4) = 0

x = -10/3 or 4

dimension cannot be negative

x is 4

6x-4= 6(4) - 4

24 - 4

20

Step-by-step explanation:

For finding k we'll have to plug in the x-value of the coordinate (3,k) into the equation, and solve for the y:

5(3) - 2y = 7

15 - 2y = 7

2y = 8

y = 4 => k =4

2) I assume the gradient is the slope of the line. If so, just isolate the y in the original equation and see what's the coefficient of the x:

-2y = -5x + 7

y = (5/2)x + 7/2 => the gradient is 5/2

3) the condition of perpendicularity is expressed by the following relation:

a * a' = -1

Where a is the slope of the first line and a' of the second line. We need to find a' that will be:

-1/a = -1/(5/2) = -2/5

The perpendicular line will be:

y = (-2/5)x + b

We need to find  b, and we know that this line passes through A (1,-1):

-1 = (-2/5)*1 + b

b = -1+(2/5) = -3/5

The equation will be:

y = (-2/5)x - 3/5.

4) I don't know what that symbol means (pV2).