Which is the decimal expansion of 7/22?
0.318
0.318
0.318
0.318

Answer:

just do it on ur caslc im pretty sure it would work

Step-by-step explanation:

Answer:

-5

Step-by-step explanation:

or, f(x) = -x^2+10x+16

or, f(7) = (-7)^2+10*-7+16 (-7*-7=49)

=49-70+16

=65-70

=-5

Answer:

Answer A

Step-by-step explanation:Option B is saying that he went back 8 yards and was pushed even farther. Option C is saying he ran foward 17 yards and got pushed back 8. Option D is saying he got pushed foward 17 yards.

Option A is saying that he ran 8 yards and then lost 17 by getting pushed back.

Answer:

A

[tex]f(x + h) = 21x -x^2 -2xh+ 21h+h^2[/tex]

B

[tex]f(x-h)-f(x) = 21h+h^2 -2xh[/tex]

C

[tex]\frac{f(x-h)-f(x)}{h} = 21+h -2x[/tex]

Step-by-step explanation:

From the question we are told that

   The equation given is

                    [tex]f(x) = x (21 - x )[/tex]

Considering  A

      [tex]f(x + h) = (x + h) (21 - (x + h))[/tex]

      [tex]f(x + h) = (x + h) (21 - x - h)[/tex]

      [tex]f(x + h) = 21x -x^2 -2xh+ 21h+h^2[/tex]

Considering B

       [tex]f(x + h)-f(x) = 21x -x^2 -2xh+ 21h+h^2 -[ x(21 -x)][/tex]

        [tex]f(x + h)-f(x) = 21x -x^2 -2xh+ 21h+h^2 -21x + x^2[/tex]

       [tex]f(x-h)-f(x) = 21h+h^2 -2xh[/tex]

Considering C

       [tex]\frac{f(x-h)-f(x)}{h} = \frac{21h+h^2 -2xh}{h}[/tex]  

       [tex]\frac{f(x-h)-f(x)}{h} = \frac{h(21+h -2x)}{h}[/tex]

       [tex]\frac{f(x-h)-f(x)}{h} = 21+h -2x[/tex]

Answer:

7x + 13y [tex]\leq[/tex] $81

Step-by-step explanation:

The inequality that represents the situation given will be  7x + 13y ≤ 81.

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Answer:

36 9/16 ft^3

Step-by-step explanation:

volume = length * width * height

volume = 3 3/4 ft * 3 ft * 3 1/4 ft

Change all mixed numerals to fractions.

volume = 15/4 * 3/1 * 13/4 ft^3

volume = 585/16 ft^3

volume = 36 9/16 ft^3

Answer:

12 hours 50 minutes

Step-by-step explanation:

8:40 pm to 9:30 am

8:40 pm to 8:40 am = 12 hours

8:40 am to 9:30 am = 50 minutes

The interval between 8:40 pm and 9:30 am is 12 hours and 50 minutes

What is an Interval?

An interval is measured in terms of numbers. An interval includes all the numbers that come between two particular numbers. This range includes all the real numbers between those two numbers.

Given data ,

Let the interval be denoted as [ a , b ] , where a is the start point and b is the final point

Now ,

a = 8:40 pm

b = 9:30 am

The interval can be calculated by ( b - a )

8:40 pm → 8:40 am = 12 hours

8:40 am → 9:30 am = 50 minutes

Therefore , total interval = 12 hours and 50 minutes

Hence , The interval between 8:40 pm and 9:30 am is 12 hours and 50 minutes

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Answer:

56.077

Step-by-step explanation:

Answer:

56.077

Step-by-step explanation:

i did it in my caculator lol :)

Answer:

Step-by-step explanation:

(8 + 2)/(-2 - 1)= -10/3

Answer:

[tex]R(200) = 6200[/tex]

[tex]R(3000) = 93000[/tex]

Step-by-step explanation:

Given

[tex]R(x) = 31x[/tex]

Solving (a): R(200)

[tex]R(x) = 31x[/tex]

Substitute 200 for x

[tex]R(200) = 31 * 200[/tex]

[tex]R(200) = 6200[/tex]

This means that the revenue from 200 hats is 6200

Solving (b): Revenue from 3000 hats

[tex]R(x) = 31x[/tex]

Substitute 3000 for x

[tex]R(3000) = 31 * 3000[/tex]

[tex]R(3000) = 93000[/tex]

The above represents the functional notation and the revenue sale is 93000

Answer:

False because the vertical intercept is not always a snap point.

Step-by-step explanation:

In a line graph, the vertical intercept of a line will not always be a point snap. This is because snap points rest on nodes and are used to define boundary or shape of objects in a line graph. So in a case whereby the intercept of the line doesn't rest on a node that defines the boundary or shape of the object, then the vertical intercept may not be a snap point.

False

A vertical intercept is a point where a line crosses the vertical axis, or [tex]\boldsymbol{y-}[/tex]axis.

The vertical intercept of a line in a line graph is not always a snap point. Snap points are used to define the boundary or shape of objects in a line graph, rely on nodes. In the event when the line's intercept does not rest on a node that defines the object's boundary or shape, the vertical intercept may not be a snap point.

False, the vertical intercept of the line may not always be a snap point.

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Answer:

75%

Step-by-step explanation:

Total = 21 + 7

         = 28 cupcakes

Vanilla cupcakes = 21 / 28 x 100

                             = 0.75 x 100

                             = 75%

Answer:

75%

Step-by-step explanation:

21+7=28

21 divided by 28 is equal to 0.75. 0.75 x 100 = 75%

Please choose my answer as the brainliest. It gets me to the next level!

Answer:

1. [tex] \boxed{ \boxed{ \sf{mean = 10}}}[/tex]

2. [tex] \boxed{ \boxed{ \sf{median = 10.5}}}[/tex]

3. [tex] \boxed{ \boxed{ \sf{mode = 11}}}[/tex]

4. [tex] \boxed{ \boxed{ \sf{range = 16}}}[/tex]

Step-by-step explanation:

1. Given data : 2 , 3 , 5 , 7 , 8 , 10 , 11 , 11 , 13 , 15 , 17 , 18

Σx = 2 + 3 + 5 + 7 + 8 + 10 + 11 + 11 + 13 + 15 + 17 + 18 = 120

N ( total number of items ) = 12

Finding the mean

To find the mean, divide the sum of all the items by the number of items.

[tex] \boxed{ \sf{mean = \frac{Σx}{N} }}[/tex]

[tex] \dashrightarrow{ \sf{mean = \frac{120}{12} }}[/tex]

[tex] \dashrightarrow{ \sf{mean = 10}}[/tex]

Mean = 10

----------------------------------------------------------

2. Given data : 2 , 3 , 5 , 7 , 8 , 10 , 11 , 11 , 13 , 15 , 17 , 18

N ( total number of items ) = 12

Finding the position of median

[tex] \boxed{ \sf{median = { \frac{n + 1}{2} }^{th \: item}}} [/tex]

[tex] \dashrightarrow{ \sf{median = {( \frac{12 + 1}{2}) }^{th \: } item}}[/tex]

[tex] \dashrightarrow{ \sf{median = {( \frac{13}{2}) }^{th \: }item }}[/tex]

[tex] \dashrightarrow{ \sf{median = {6.5}^{th \: }}} [/tex] item

[tex] \sf{ {6.5}^{th} }[/tex] item is the average of 6 th and 7 th items.

[tex] \sf{∴ \: median = \frac{ {6}^{th}item + {7}^{th} item}{2}} [/tex]

[tex] \dashrightarrow{ \sf{median = \frac{10 + 11}{2} }}[/tex]

[tex] \dashrightarrow{ \sf{median = \frac{21}{2} }}[/tex]

[tex] \dashrightarrow{ \sf{median = 10.5}}[/tex]

Median = 10.5

-----------------------------------------------------------

3. The mode of a set of data is the value with the highest frequency.

Given data : 2, 3, 5, 7, 8, 10, 11, 11, 13, 15, 17, 18

Here, 11 has the highest frequency.

So, Mode = 11

----------------------------------------------------------

4. Highest number = 18

Lowest number = 2

[tex] \boxed{ \sf{range = highest \: number - lowest \: number}}[/tex]

[tex] \dashrightarrow{ \sf{range = 18 - 2}}[/tex]

[tex] \dashrightarrow{ \sf{range = 16}}[/tex]

Hope I helped!

Best regards! :D

Answer:

1.125

Step-by-step explanation:

Each piece weighs 1.125 ounces

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

We are given that small apple weighs 4.5 ounces.

if it is divided into 4 equal Pieces then

Therefore, Weight of apple = 4.5 ounces

Total pieces = 4

Now Weight of 1 piece = 4.5 ÷ 4

= 1.125

Hence the answer is 1.125 ounces

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Answer:

(a) (x - 3)² + (y + 4)² + (z - 5)² = 25

(b) (x - 3)² + (y + 4)² + (z - 5)² = 9

(c) (x - 3)² + (y + 4)² + (z - 5)² = 16

Step-by-step explanation:

The equation of a sphere is given by:

(x - x₀)² + (y - y₀)² + (z - z₀)² = r²            ---------------(i)

Where;

(x₀, y₀, z₀) is the center of the sphere

r is the radius of the sphere

Given:

Sphere centered at (3, -4, 5)

=> (x₀, y₀, z₀) = (3, -4, 5)

(a) To get the equation of the sphere when it touches the xy-plane, we do the following:

i.  Since the sphere touches the xy-plane, it means the z-component of its centre is 0.

Therefore, we have the sphere now centered at (3, -4, 0).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (3, -4, 0) as follows;

[tex]d = \sqrt{(3-3)^2+ (-4 - (-4))^2 + (0-5)^2}[/tex]

[tex]d = \sqrt{(3-3)^2+ (-4 + 4)^2 + (0-5)^2}[/tex]

[tex]d = \sqrt{(0)^2+ (0)^2 + (-5)^2}[/tex]

[tex]d = \sqrt{(25)}[/tex]

d = 5

This distance is the radius of the sphere at that point. i.e r = 5

Now substitute this value r = 5 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 5²  

(x - 3)² + (y + 4)² + (z - 5)² = 25  

Therefore, the equation of the sphere when it touches the xy plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 25  

(b) To get the equation of the sphere when it touches the yz-plane, we do the following:

i.  Since the sphere touches the yz-plane, it means the x-component of its centre is 0.

Therefore, we have the sphere now centered at (0, -4, 5).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (0, -4, 5) as follows;

[tex]d = \sqrt{(0-3)^2+ (-4 - (-4))^2 + (5-5)^2}[/tex]

[tex]d = \sqrt{(-3)^2+ (-4 + 4)^2 + (5-5)^2}[/tex]

[tex]d = \sqrt{(-3)^2 + (0)^2+ (0)^2}[/tex]

[tex]d = \sqrt{(9)}[/tex]

d = 3

This distance is the radius of the sphere at that point. i.e r = 3

Now substitute this value r = 3 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 3²  

(x - 3)² + (y + 4)² + (z - 5)² = 9  

Therefore, the equation of the sphere when it touches the yz plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 9  

(b) To get the equation of the sphere when it touches the xz-plane, we do the following:

i.  Since the sphere touches the xz-plane, it means the y-component of its centre is 0.

Therefore, we have the sphere now centered at (3, 0, 5).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (3, 0, 5) as follows;

[tex]d = \sqrt{(3-3)^2+ (0 - (-4))^2 + (5-5)^2}[/tex]

[tex]d = \sqrt{(3-3)^2+ (0+4)^2 + (5-5)^2}[/tex]

[tex]d = \sqrt{(0)^2 + (4)^2+ (0)^2}[/tex]

[tex]d = \sqrt{(16)}[/tex]

d = 4

This distance is the radius of the sphere at that point. i.e r = 4

Now substitute this value r = 4 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 4²  

(x - 3)² + (y + 4)² + (z - 5)² = 16  

Therefore, the equation of the sphere when it touches the xz plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 16

By using the general sphere equation and what we know about planes, we will get:

The general sphere of radius R centered in the point (a, b, c) is given by:

(x - a)^2 + (y - b)^2 + (z - c)^2 = R^2

If we want a sphere centered in (3, -4, 5) we will have:

(x - 3)^2 + (y + 4)^2 + (z - 5)^2 = R^2

a) We want the sphere to touch the xy-plane, (with z = 0) then the radius must be at least equal to the z-component of the point, so we have R = 5, then the equation is:

(x - 3)^2 + (y + 4)^2 + (z - 5)^2 = 5^2

b) This time is the yz-plane, so the radius must be equal to the x-component.

(x - 3)^2 + (y + 4)^2 + (z - 5)^2 = 3^2

c) Finally, the xz-plane, this time the radius must be equal to the y-component.

(x - 3)^2 + (y + 4)^2 + (z - 5)^2 = 4^2

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She will most likely finish graduation portraits.

I'm not to sure so try not to pick my answer.

Answer:

[tex]-\frac{15}{16}[/tex]

Step-by-step explanation:

[tex]\frac{1}{4} ^{2}[/tex]= [tex]\frac{1}{16}[/tex]

2*(pq)= 2([tex]\frac{1}{6}[/tex])= [tex]\frac{1}{3}[/tex]

-3[tex]q^{2}[/tex]= -3[tex](\frac{4}{9} )[/tex]= [tex]-\frac{4}{3}[/tex]

[tex]\frac{1}{16} +\frac{1}{3}-\frac{4}{3}[/tex]=

[tex]\frac{1}{16} -1[/tex]=

[tex]-\frac{15}{16}[/tex]

Answer:

Step-by-step explanation:

3

Answer:

Radius= 11

Circumference= 69.12

Area= 380.133

Step-by-step explanation:

Radius is half of the diameter.

Circumference is 2[tex]\pi[/tex]r.

Area is [tex]\pi r^2[/tex].

Answer:

See below.

Step-by-step explanation:

Rule:

[tex] a^m \times a^n = a^{m + n} [/tex]

Explanation:

When multiplying monomials with the same base, write the same base and add the exponents.

Answer:

A) [tex]\huge\boxed{3.9}[/tex]

B) [tex]\huge\boxed{5.42}[/tex]

C) [tex]\huge\boxed{125}[/tex]

Step-by-step explanation:

A) 3.892

To round off to nearest tenth, we'll see the digit in hundredths place. If it is greater than 5 or equal to 5, 1 will be added to the tenths place. If it's not, it will remain the same.

So, it will be like:

=> 3.9

B) 5.424

To round off to nearest hundredth, we'll see the digit in thousandths place. If it is greater than 5 or equal to 5, 1 will be added to the hundredths place. If it's not, it will remain the same.

So, it will be like:

=> 5.42

C) 124.62

To round off to nearest whole number, we'll see the digit in tenths place. If it is greater than 5 or equal to 5, 1 will be added to the ones place. If it's not, it will remain the same.

So, it will be like:

=> 125

Answer:Avocados:4

Broccoli:3

Carrots:2

Onions:1

Step-by-step explanation:I did the question it is correct.

Answer:

the area is 9in^3

Step-by-step explanation:

the formula for area of a triangle is 1/2bh, so it's 1/2 x 7.2 x 2.5

Answer:

a: 15 in

b:210 cm

c: 21 yds

Step-by-step explanation:

a: to find the area of a triangle multiply the base and the height, then divide the result by two.

b: to find the area of a trapezoid, multiply the median ( the point where the opposite corners cross) and the height.

c: to find the area of a parallelogram, multiply the lenght and the height.

Hope this helps!

Step-by-step explanation:

[tex] \\ 8 \times 5 = 40 \\ 40 = 4 \times 10 \\ \\ 8 \times 5 = 4 \times 10[/tex]

This question is incomplete, the complete question is;

Your boss asks you to design a Boolean circuit that verifies whether a given integer 0 < x < 16 is divisible by 5.

Every such number is represented in binary using four bits, say b₃b₂b₁b₀, and so your Boolean circuit will have four inputs. For instance, the number 13 is written in binary as 1101 and so to test its divisibility by 5 a user would feed the values b₀ = 1, b₁ = 0, b₂ = 1, and b₃ = 1 into the inputs of your circuit.

The Boolean circuit will have a single output, which should deliver the value 1 if the iput values represent a number that is divisible by 5 and 0 otherwise.

a) write down the truth table of the Boolean function F(b₀,b₁,b₂b₃) that implements this "divisible by 5" operation

b) construct a Boolean expression in disjunctive normal form that implements the Boolean function yo wrote down in a)

Answer:

Given that;

integer range = 0≤ x ≤ 16

within 4bits, we can represnt each number

(0,5,10,15)

a)  

Truth table for function that implements  divisible by 5

Integer    B3    B2    B1    B0     Y

0              0       0      0      0      1

1              0       0      0       1      0

2              0       0      1        0     0

3              0       0      1        1      0

4              0       1       0       0     0

5              0       1       0       1      1

6              0       1       1        0     0

7              0       1       1        1       0

8              1       0      0        0      0

9              1       0      0        1       0

10             1       0      1         0      1

11              1       0      1          1      0

12             1        1      0         0     0

13             1         1     0          1      0

14             1         1       1         0     0

15            1         1        1        1       1

b)

Boolean expression that implements the Boolean function from a)

from the truth table;

Boolean expression Y is;

Y = b⁻₃b⁻₂b⁻₁b⁻₀ / y₁   +   b⁻₃b₂b⁻₁b₀ / y₂   +   b₃b⁻₂b₁b⁻₀ / y₃   +   b₃b₂b₁b₀ / y₄

Answer:

  circuit is in the second attachment

Step-by-step explanation:

Attached is a truth table for the desired circuit, where b3–b0 are the input bits, MSB–LSB. We notice that the output is true whenever b3=b1 and b2=b0. This can be written in DNF as ...

  [tex]Y=b_3'b_2'b_1'b_0'+b_3b_2'b_1b_0'+b_3'b_2b_1'b_0+b_3b_2b_1b_0[/tex]

More compactly, it can be written in terms of the exclusive-nor function as ...

  [tex]y=(b_3\odot b_1)\wedge(b_2\odot b_0)[/tex]

A circuit diagram showing this circuit is the second attachment. (A–D are the input bits, in order MSB–LSB (or its reverse)).