What is the measure of the
third angle of this triangle?

Answer:

Solve by multiplying a scale factor of 4 to each coordinate

Step-by-step explanation:

If the coordinate of J is dilated by a scale factor of 4, the resulting coordinate of the figure J' will be at (-48, 64)

Dilation is a transformation technique used to change the size and shape of an object on a xy-plane.

Given the following coordinate point of a figure JKLM:

J (− 12 , 16 ),

K ( − 4 , − 3 )

L ( − 2 , 16 )

M ( 1 , 0 )

If the coordinate of J is dilated by a scale factor of 4, the resulting coordinate of the figure J' will be at (-48, 64).

Learn more on dilation here: https://brainly.com/question/10253650

The lowest point of the cables above the bridge is 48 feet above the bridge.

The statement give us a parabola equation in standard form, the vertical distance of the lowest point above the bridge is determined by the y-coordinate of the vertex. Hence, the lowest point of the cables above the bridge is 48 feet above the bridge.

We kindly invite to check this question on parabolae: https://brainly.com/question/8495869

Answer:

B) Alternate Exterior Angles

Step-by-step explanation:

They are exterior (on the outside of the the lines) and they are alternate (opposite left and right).

Answer:

Alternate exterior angles

Step-by-step explanation:

Alternate exterior angles are outside angles that lies to the opposite side.

Answer:

m = − 1/2

Step-by-step explanation:

Use the formula to calculate the slope of the line passing through the points.

slope = (y₂ - y₁) / (x₂ - x₁)

Input the values into the formula.

Subtract the values in parentheses.

Simplify the fraction to get the slope.

Answer: y = -1/2x +2

Answer:

3rd option

Step-by-step explanation:

a point (0, y ) lies on the y- axis

a point (x, 0 ) lies on the x- axis

a point (x, y ) lies in I quadrant

a point (- x, y ) lies in II quadrant

a point (- x, - y ) lies in III quadrant

a point (x, - y ) lies in IV quadrant

Then

point (2, - 5 ) lies in IV quadrant

-----------------------------------------------------------------

We require 2 equations with the repeating digit 7 placed after the decimal point.

let x = 0.427777... ( multiply both sides by 100 and 1000 )

100x = 42.777..... (1)

1000x = 427.777.... (2)

Subtract (1) from (2), thus eliminating the repeating digits

900x = 385 ( divide both sides by 900 )

x = [tex]\frac{385}{900}[/tex] = [tex]\frac{77}{180}[/tex]

Answer:

13) E

14) B

15) D

16) F

17) A

18) C

Answer:

5.73

Step-by-step explanation:

The difference is 5.73.

Angle 8 and angle 5 are vertical angles

2090

Step-by-step explanation:

220 divided by 2 hours is 110 per hour

19 times 110 equals 2090

Answer:

log

2

(

y

)

=

5

→

2

5

=

y

⇒

y

=

32

Step-by-step explanation:

Answer:

Hi There,

Your answer is -926.318

Answer:

-90

Step-by-step explanation: I hope its the right answer. If not I'm sorry.... I'm just a kid...

Step-by-step explanation:

there seems to be something missing.

I assume the slope of the line is -2/3.

the slope of a line is always the factor of x in the equation.

the slope is the y/x ratio indicating how many units y changes, when x changes by a certain amount of units (e.g. when going from one point on the line to another).

the equation for the line looks like this then :

y = (-2/3)×x + b

to get b we use the provided point (-6, -5) and it's x and y values.

-5 = (-2/3)×-6 + b = 4 + b

b = -9

so, the full equation of the line is

y = (-2/3)×x - 9

Answer:

y=4 because 8x4=32

32-2 =30

30+60=90

Answer:

the value of y is 4, so 8(4)-2 are 30 , then 30 degrees are the angle

Answer:A manufacturing company makes two types of water skis, a trick ski and a slalom ski. The relevant manufacturing data are given in the table. (A) If the profit on a trick ski is $40$ and the profit on a slalom ski is $30,$ how many of each type of ski should be manufactured each day to realize a maximum profit? What is the maximum profit? (B) Discuss the effect on the production schedule and the maximum profit if the profit on a slalom ski decreases to $25$ and all other data remains the same. (C) Discuss the effect on the production schedule and the maximum profit if the profit on a slalom ski increases to $45$ and all other data remain the same.

Step-by-step explanation:

The optimal production plan for maximizing profit is to manufacture 48 slalom skis and 0 trick skis each day, resulting in a maximum profit of $2880.

Given data:

To solve this problem, we can use linear programming techniques to find the optimal number of trick skis and slalom skis that should be manufactured each day to maximize the profit.

x = number of trick skis

y = number of slalom skis

We need to maximize the profit function: P = 40x + 60y

Subject to the following constraints:

1x + 1y ≤ 336 (Fabricating department constraint)

1x + 1y ≤ 48 (Finishing department constraint)

x, y ≥ 0 (Non-negativity constraint)

We can graphically represent these constraints on a coordinate plane and find the feasible region, which is the region where all constraints are satisfied. Then, we can evaluate the profit function at the corner points of the feasible region to find the maximum profit.

After solving this system of linear inequalities, we find that the feasible region is a triangle with vertices at (0, 48), (0, 48), and (48, 48).

Evaluating the profit function at these vertices:

P(0, 48) = 40(0) + 60(48)

= $2880

P(0, 0) = 40(0) + 60(0)

= $0

P(48, 0) = 40(48) + 60(0)

= $1920

The maximum profit is $2880, which occurs when they produce 48 slalom skis and 0 trick skis.

Hence, the optimal production plan for maximizing profit is to manufacture 48 slalom skis and 0 trick skis each day, resulting in a maximum profit of $2880.

To learn more about linear programming, refer:

https://brainly.com/question/28579054

#SPJ3

Answer:

here's your answer

hope it helps

(look at attachment)

Answer:

6

Step-by-step explanation:

Following PEMDAS ( parentheses, exponents, multiplication, division, addition, subtraction)

| 7 - 9 | + ( 7 - 9 ) ^ 2

| 7 - 9 | + -2 ^ 2

| 7 - 9 | + ( -2 x -2 )

| 7 - 9 | + 4

| -2 | + 4

2 + 4

6

Answer:

No

Step-by-step explanation:

7 + 3 = 10, and in order for this to make a triangle two sides must be greater than one side

Answer:

No

Step-by-step explanation:

two sides, say a and b, with a greater than or equal to b, ,put limits on the length of the third side, c: a-b < c < a+b.

a-b < c < a+b.

7-3 < 10 < 7+3

4 < 10 < 10

False,

The slope is [tex]-\frac{3}{7}[/tex]

[tex]{ \qquad{ \sf \green{Answer \downarrow}}}[/tex]

Subtract 16  from both sides of the equation.

[tex]{ \qquad{\longmapsto \sf \red{2x + 16 - 16 = 8 - 16}}}[/tex]

Subtract the numbers

[tex]{ \qquad{\longmapsto \sf \red{2x = 8}}}[/tex]

Divide both sides of the equation by the same term.

[tex]{ \qquad{\longmapsto \sf \green{ \frac{2x}{2} = \frac{ 8}{2} }}}[/tex]

Cancel terms that are in both the numerator and denominator

[tex]{ \qquad{\longmapsto \sf{ \qquad\longrightarrow\quad\sf \dfrac{\cancel{2x}}{\cancel{2} } = }}}\qquad\quad\sf\dfrac{\cancel{ 8}}{\cancel{2}}[/tex]

[tex]{ \qquad{\longmapsto \sf{x = {\qquad{ \sf \pink{ 4}}}}}}[/tex]

[tex]{ \red{ \rule{9cm}{0.1cm}}}[/tex]

Answer:

SSS~

RQP

Step-by-step explanation:

36/15 = 2.4

48/20 = 2.4

72/30 = 2.4

Triangles are similar by SSS~.

triangle JKL is similar to triangle RQP

Answer:

Step-by-step explanation:

Slope of perpendicular line = [tex]\frac{-1}{m}[/tex]

       = -1 ÷ [tex]\frac{-5}{3}[/tex]

        [tex]= -1 *\dfrac{-3}{5}\\\\=\dfrac{3}{5}[/tex]

Answer:

x = [tex]\frac{5}{4} + \frac{ \sqrt{5} }{4}[/tex]

x = [tex]\frac{5}{4} - \frac{ \sqrt{5} }{4}[/tex]

Step-by-step explanation:

Quadratic equation:

[tex]x = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}[/tex]

The equation is:

[tex]4x^2 - 10x + 5 = 0\\[/tex]

So:

a = 4

b = -10

c = 5

Plug the variables into the quadratic equation:

[tex]x = \frac{-(-10) +- \sqrt{(-10)^2 - (4 * 4 * 5)} }{(2 * 4)}[/tex]

[tex]x = \frac{\sqrt{10 +- \sqrt{100 - 80} } }{8}[/tex]

[tex]x = \frac{10 + \sqrt{20} }{8}[/tex]

Divide both sides by 8:

10 ÷ 8 = [tex]\frac{5}{4}[/tex]

[tex]\sqrt{20}[/tex] ÷ 8 = [tex]\frac{\sqrt{5}}{4}[/tex]

[tex]\frac{5}{4}[/tex] +- [tex]\frac{\sqrt{5}}{4}[/tex]

This means that the solutions that satisfy the equation is:

x = [tex]\frac{5}{4} + \frac{ \sqrt{5} }{4}[/tex]

x = [tex]\frac{5}{4} - \frac{ \sqrt{5} }{4}[/tex]

Hope this helps!

The value of the stamp at the end of the third year is £976.31.

From the information, Sam buys a rare stamp for his stamp collection at an auction. he buys the stamp for 920£ the stamp increased in value by 7% in each of the first 2 years.

First year value:

= 920 + (2% × 920)

= 938.4

Second year value:

= 938.4 + (2% × 938.4)

= 957.168

Third year value:

= 957.168 + (2% × 957.168)

= £976.31

Learn more about percentages on:

brainly.com/question/24877689

#SPJ1

Complete question

sam buys a rare stamp for his stamp collection at an auction. he buys the stamp for 920£ the stamp increased in value by 7% in each of the first 2 years decreased in value by 4% in the third year. What is the cost by the end of. the third year?

Answer:

Counterclockwise rotation 90°

Step-by-step explanation:

first quadrant graph -> 2nd quadrant

Counterclockwise rotation 90° : (x,y) -> (-y , x)

Answer:

1/4 cup of milk

Step-by-step explanation:

= 1/2 ÷ 2

= 1/2 × 1/2

= 1/4

Answer:

z. sjshshdbd.d.difffjfjfjf

Answer:

42:30

Step-by-step explanation:

10 x 3 = 30

14 x 3 = 42