What is the interquartile range (IQR) of the data?

Answer:

A) 2 inches

Step-by-step explanation:

Answer:

Hi,

These are corresponding angles. Corresponding angles are congruent. So the equation would be 100=x+106. Do you think you can solve that? If you can't let me know and I will do it for you?

Step-by-step explanation:

Answer:

Cecily's claim is true for all values of b.

Step-by-step explanation:

Cecily's claim is true for all values of b.

If she graphs y = mx, and then y = mx + b, and then y = mx + c, and so on, she will find that her graphs are all straight lines that are parallel to each other (as they will all have the same slope, m).

Answer:

Subtraction property of equality

Step-by-step explanation:

In the equation, 5 is subtracted from both the sides

Answer:

two times

Step-by-step explanation:

ΔM:  let 'h' = height; let '4b' = base

ΔN:  let 'h/2' = height; let 'b' = base

Area (ΔM) = 2bh

Area (ΔN) = bh

Answer:

16.

Step-by-step explanation:

n - 7 = 9

Add 7 to both sides

n = 9 + 7 = 16.

Answer:

16

Step-by-step explanation:

Given

n - 7 = 9 ( add 7 to both sides )

n = 16

Answer: 237,500 total decrease

Step-by-step explanation:

Answer:

13.62 m

Step-by-step explanation:

We are to determine the value of the adjacent side given the value of the hypotenuse

we would use cos to determine this value

cos 63 = adjacent / hypotenuse

0.45399 = x / 30

x = 30 x 0.45399 = 13.62

Answer:

C. - 4x^2 + 5x - 4

Step-by-step explanation:

just expand the equation and you'll get C

Answer:

O C.   [tex]-4x^2+5x-28[/tex]

Step-by-step explanation:

[tex]3x^2+5x[/tex] -7(x^2+4)      Distribute

[tex]3x^{2} +5x[/tex] -7x^2-28       Multiply - 7 by 4

3x^2 [tex]+5x[/tex] -7x^2 [tex]-28[/tex]   Combine Like Terms

-4x^2 [tex]+5x-28[/tex]           Final Answer

Answer:

o really sis/bro hsgsmhsndjd

Answer:

[tex]\frac{8}{10}[/tex]

Step-by-step explanation:

[tex]\frac{1}{2} +\frac{3}{10}[/tex]

[tex]\frac{5}{10} +\frac{3}{10} =\frac{8}{10}[/tex]

Hope this is helpful

Given:

The logarithmic equation is:

[tex]\log_618=x[/tex]

To find:

The exponential equation of this logarithmic equation.

Solution:

According to the properties of logarithm:

[tex]\log_bm=x\Leftrightarrow m=b^x[/tex]

We have,

[tex]\log_618=x[/tex]

Here, [tex]b=6, m=18[/tex]. Using the above property of logarithm, we get

[tex]18=6^x[/tex]

Therefore, the required exponential equation is [tex]18=6^x[/tex].

Answer:

the awnser is acctully 6^x =18

Step-by-step explanation:

Answer:

(3x+2)^2+1

Step-by-step explanation:

(f°g)(x) =g(f(x)) =g(3x+2)=(3x+2)^2 +1

Answer:

3(x+1) + 2

Step-by-step explanation:

Step-by-step explanation:

it might be the last one

may it helped u

(1, 2) because that's where the lines intersect!

Answer: (1, 2)

Step-by-step explanation:

The solution of the systems of equations graphed can be found where the two linear lines intersect. In this graph, the lines intersect at 1 in the x-axis (the line with arrows that runs from left to right" and at 2 in the y-axis (the line with arrows that runs north to south).

Answer:

Step-by-step explanation:

They are similar because they have two respective congruent angles

Answer:

(1) 102.55 in

(2)  316.69 in²

Step-by-step explanation:

Applying (1)

a² = b²+c².............. Equation 1

Given: a = 25 in, b = 20 in,

25² = 20²+b²

b² = 25²-20²

b² = 225

b = √225

b = 15 in

b = diameter of the semicircle

The lenght of the semicircle = πd/2 = 3.14×15/2 = 23.55 in

Therefore,

P = 37+25+17+23.55 = 102.55 in

(2) Applying,

A = Area of the tripezium- area of the semi circle

A = [h(a+b)/2]-πh²/8.............. Equation 2

Given; h = 15 in, a = 17 in, b = 37 in

A = (15(17+37)/2)-(3.14×15²/8)

A = 405-88.31

A = 316.69 in²

Answer:

Vertical Angles

x = 21

Step-by-step explanation:

Vertical Angles

4x + 3 = 87

4x = 84

x = 21

Answer:

Step-by-step explanation:

for the right side :

its a triangular prism and the volume is 4 x 8 x 10 = 320.

the SA is 10x4 divided by 2 x 2which is just 40.

8x5x2= 80 and

10x10= 100,  so

the SA of the right figure is 220 in^2

[tex]{ \bf{ \underbrace{Given :}}}[/tex]

Radius of the circle = 1 unit.

[tex]{ \bf{ \underbrace{To\:find:}}}[/tex]

The area of the circle.

[tex]{ \bf{ \underbrace{Solution :}}}[/tex]

[tex]\sf\orange{The\:area\:of\:the\:circle\:is\:3.14\:units².}[/tex] ✅

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

We know that,

[tex]\sf\purple{Area\:of\:a\:circle \:=\:πr² }[/tex]

[tex]=\:3.14 \times 1 \times 1 \: \: {units}^{2} \\ \\ = 3.14 \: \: {units}^{2} [/tex]

Therefore, the area of the circle is 3.14 units².

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]

Answer:

13.25 years

Step-by-step explanation:

Take the number of booklets and divide by the number of booklets per year

159/12

13.25 years

Answer:

J >= 1 or j is greater than or equal to 1

Step-by-step explanation:

Write equation:

2(j-4)>= -6

1. Distribute:

2j - 8 >= -6

2. Add 8 on both sides:

2j -8 +8 >= -6 + 8

2j >= 2

3. Divide 2 on both sides:

2j/2 >= 2/2

j >= 1

There ya go! Hope this helps, have a good night or day! ;)

BD = 2x-4

But it's also BE - CE + CD

BE is 3x-1

CE is 2x-3

CD is 2

so

BD = 3x-1 -(2x-3) +2

simplified

BD = 1x +4

since BD = BD (obviously), we can also say that the righthand sides of the two equation must be equal

2x -4 = 1x +4

let's solve for x and that put it into either of the 2 equations.

2x -4 = 1x +4

subtract 1x on both sides

x -4 = 4

add 4 on both sides

x = 8

substitute x for its value in 2x -4 = 1x +4

(this way we double check BD in two expressions at once. the equation should come out true, meaning same value for BD in each expression. both sides should be equal).

2*8 -4 = 1*8 +4

12 = 12

seems true

BD is safely 12

Answer:

The answer is D (6).

hope this helps!

Answer:

The common ratio is 2.

Step-by-step explanation:

3 : 6 : 12

1 : 2 : 4

Step-by-step explanation:

1) [tex](-4)^2{\cdot}(-4)[/tex]

We know that, [tex]a^x{\cdot}a^y=a^{x+y}[/tex]

[tex](-4)^2{\cdot}(-4)=(-4)^{2+1}\\\\=(-4)^3\\\\=64[/tex]

2) [tex](-2)^5{\cdot} (-2)^3[/tex]

Again using above property,

[tex](-2)^5{\cdot} (-2)^3=(-2)^8\\\\=256[/tex]

3) [tex]5^{-3}[/tex]

We know that,

[tex]a^{-x}=\dfrac{1}{a^x}[/tex]

So,

[tex]5^{-3}=\dfrac{1}{5^3}\\\\=\dfrac{1}{125}[/tex]

4) [tex]2.5^2=2.5\times 2.5\\\\=6.25[/tex]

Hence, this is the required solution.