Answer:
Bill earns $220.00 in 22 weeks.
Step-by-step explanation:
If he is paid 20 dollars every 2 weeks for a car wash, we need to find out how many he gets for 22 weeks.
20 dollars = 2 weeks, to find 22, multiply both of the values by 11 to get to 22.
11(2 weeks = 20 dollars)
22 weeks = 220.
The amount of money earned in 22 weeks is $220.
Option D is the correct answer.
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
The amount for each car wash = $20
Number of car wash in two weeks = 1
Now,
Number of car washes in 22 weeks.
= 22 / 2
= 11
Now,
The amount earned in 11 car washes.
= 11 x 20
= $220
Thus,
Amount earned in 22 weeks is $220.
Learn more about expressions here:
https://brainly.com/question/3118662
#SPJ2
jada uses a pitcher to fill a pot of water. the pitcher holds 8/10 liter of water. it takes 12 full pitchers of water to fill the pot. what is the total amount of water that the pot holds?
Answer:
The pot can hold 9 6/10 liters of water
Step-by-step explanation:
Since you know that the pitcher can hold 8/10 liters of water and that Jada has to fill the pitcher 12 times to fill the pot you would first convert the 8/10 liters that the pitcher can hold to a decimal so that would become 0.8 liters of water and then you would multiply the 0.8 by 12 to get 9.6 liters of water and then you can convert that back to a fraction which would be 9 6/10 liters of water. So the pot can hold 9 6/10 liters of water
How many solutions are there to the system
{y = 1/3x + 5
{x + 3y = 6
Answer:
there are 3 solutions which can be done by substitution method, elimination method,graphical method, 9f you need solution than contact me 8n comments I can show solutions
PLEASE HELP PLEASE (dont do links)
Answer:
B
-2(0)²+24(0)-54
= -54
Answer:
I think its C
Step-by-step explanation:
y intercepts (0,-54)
You need a 70% alcohol solution. On hand, you have a 40 mL of a 35% alcohol mixture. You also have 75% alcohol mixture. How much of the 75% mixture will you need to add to obtain the desired solution?
Answer:
250 ml of the 75% mixture are needed to obtain the desired solution.
Step-by-step explanation:
Since I need a 70% alcohol solution, and on hand, I have a 40 mL of a 35% alcohol mixture, and I also have 75% alcohol mixture, to determine how much of the 75% mixture will you need to add to obtain the desired solution, the following calculation must be performed:
100 x 0.75 + 0 x 0.35 = 75
90 x 0.75 + 10 x 0.35 = 71
89 x 0.75 + 11 x 0.35 = 70.6
87.5 x 0.75 + 12.5 x 0.35 = 70
12.5 = 40
87.5 = X
87.5 x 40 / 12.5 = X
3,500 / 12.5 = X
280 = X
Therefore, 250 ml of the 75% mixture are needed to obtain the desired solution.
What is the answer to this
Answer:
5 f
Re-order terms so that constants are on the left
. 5
5 f
solution
5 f
Please help I'll mark you as brainiest
The answer is going to be B
10% of $200,000 = $20,000
WILLL MARK BRAINLIEST IF GOTTEN RIGHT
Sorry for the changing answers, did the question too fast and misinterperted the diagram. The answer below is the correct one.
Answer:
mUC=70°
Step-by-step explanation:
The angle (87) formed by two chords (US and TS) is half the sum of the intercepted arcs(104 and mUC):
87=(1/2)(104+mUC)
174=104+mUC
mUC=70°
What’s the slope???? Please help meee!
Answer:
The slope is 0.
Step-by-step explanation:
Suppose we have two points in a data set, the slope is given by the change in the output divided by the change in the input.
In this question:
Two points: (0,-20) and (1,-20)
Change in the output: -20 - (-20) = -20 + 20 = 0
Change in the input: 1 - 0 = 1
Slope: 0/1 = 0
The slope is 0.
Tori's Burgers cooks its burgers either well done or medium. Last night the restaurant served
25 burgers in all, 5 of which were well done. What percentage of the burgers were well done?
Write your answer using a percent sign (%).
I need help please tell the right answer
Answer: 47.6 is your answer hope this helped
plz make brainly
Step-by-step explanation:
Answer:
36 - 4
Step-by-step explanation:
(6x - 2)(6x + 2)
= (6x)(6x) + (6x)(-2) + (2)(6x) + (-2)(2)
= 36 - 12x + 12x - 4
= 36 - 4Step-by-step explanation:
What are the values of the coefficients and constant term of 0 = 4 - 7x2 + x in standard form?
a =
b =
C=
Answer:
a = -7
b = 1
c = 4
Step-by-step explanation:
0 = 4 - 7x²+ x
-7x²+x+4 = 0
But
ax²+bx + c = 0
a = -7
b = 1
c = 4
Answer:
-7, 1, 4
Step-by-step explanation:
For which value of k does Limit as x approaches kf(x) = 4?
0
2
6
8
Answer:
2
Step-by-step explanation:
on Edge
Answer: 2
Step-by-step explanation:
have a great day!
Ms. Clark is building a patio that is 4 yards long and 3 yards wide. She has enough bricks to cover an area of 14 square yards. Does Ms. Clark have enough bricks to build the patio? Explain.
Answer:
DONT CLICK THE LINK!!!! IT IS A BOT. THEY WILL. HACK.
Step-by-step explanation:
Given, we know that she has 14 bricks.
We also know that the patio is 4 yards long and 3 yards wide. If we multiply those two numbers together we get 12.
So, if we do the math 14-12=2 bricks left over.
Therefore, she will have enough bricks to build the patio.
Condense the logarithm
q log b + 3 log k
Answer:
a
Step-by-step explanation:
Answer:
[tex]log(\frac{a^{2} }{b^{3} } )[/tex]
Step-by-step explanation:
[tex]q[/tex] [tex]log[/tex] [tex]a -3log[/tex] [tex]b[/tex]
[tex]=log[/tex] [tex]a^{2} -log[/tex] [tex]b^{2}[/tex]
[tex]now[log[/tex][tex]a/b=log[/tex] [tex]a-log[/tex] [tex]b[/tex][tex]][/tex]
[tex]= log(a^{2} /b^{3)}[/tex]
[tex]--------[/tex]
hope it helps...
have a great day!!!
does the graph of this equation widen or narrow from the parent function? g(x)=3/4(x-5)^2+12
9514 1404 393
Answer:
widen
Step-by-step explanation:
The vertical scale factor is 3/4, so the vertical extent is shortened at a given x-value distance from the axis of symmetry. That will give the appearance of making the parabola (slightly) wider.
Answer:
Widen is the answer.Step-by-step explanation:
#CarryOnLearningapp 19.study
Tools
Tools
Probability
Jacob performed an experiment with a weighted die, numbered 1 to 6. He rolled the die 125 times and recorded the results.
Complete the table below.
0.232
37
24
0.176
18
0.048
0.104
22
Result of Roll
Frequency
Experimental
Probability
1
2
13
3
0.144
4
29
5
0.296
6
Reset
Submit
Answer:
[tex]1 \to 22 \to 0.176[/tex]
[tex]2 \to 13 \to 0.104[/tex]
[tex]3 \to 18 \to 0.144[/tex]
[tex]4 \to 29 \to 0.232[/tex]
[tex]5 \to 37 \to 0.296[/tex]
[tex]6 \to 6 \to 0.048[/tex]
Step-by-step explanation:
Given
[tex]n = 125[/tex]
See attachment for proper table
Required
Complete the table
Experimental probability is calculated as:
[tex]Pr = \frac{Frequency}{n}[/tex]
We use the above formula when the frequency is known.
For result of roll 2, 4 and 6
The frequencies are 13, 29 and 6, respectively
So, we have:
[tex]Pr(2) = \frac{13}{125} = 0.104[/tex]
[tex]Pr(4) = \frac{29}{125} = 0.232[/tex]
[tex]Pr(6) = \frac{6}{125} = 0.048[/tex]
When the frequency is to be calculated, we use:
[tex]Pr = \frac{Frequency}{n}[/tex]
[tex]Frequency = n * Pr[/tex]
For result of roll 3 and 5
The probabilities are 0.144 and 0.296, respectively
So, we have:
[tex]Frequency(3) = 125 * 0.144 = 18[/tex]
[tex]Frequency(5) = 125 * 0.296 = 37[/tex]
For roll of 1 where the frequency and the probability are not known, we use:
[tex]Total \ Frequency = 125[/tex]
So:
Frequency(1) added to others must equal 125
This gives:
[tex]Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125[/tex]
[tex]Frequency(1) + 103 = 125[/tex]
Collect like terms
[tex]Frequency(1) =- 103 + 125[/tex]
[tex]Frequency(1) =22[/tex]
The probability is then calculated as:
[tex]Pr(1) = \frac{22}{125}[/tex]
[tex]Pr(1) = 0.176[/tex]
So, the complete table is:
[tex]1 \to 22 \to 0.176[/tex]
[tex]2 \to 13 \to 0.104[/tex]
[tex]3 \to 18 \to 0.144[/tex]
[tex]4 \to 29 \to 0.232[/tex]
[tex]5 \to 37 \to 0.296[/tex]
[tex]6 \to 6 \to 0.048[/tex]
The number of hours per week that the TV is turned on is determined for each family in a sample.
The mean of the data is 37 hours.
The median is 33.2 hours.
Twenty four of the families in the sample watched TV for less than 22 hrs per week.
The 16th percentile is 22hrs.
150 families participated in the study.
The first percentile is greater than or equal to 22 hours: True or False?
Answer:
False, the first percentile is less than 22 hours.
Step-by-step explanation:
xth percentile:
If a measure is said to be in the xth percentile, it means that x% of the measures are smaller than it, and (100-x)% are larger.
Twenty four of the families in the sample watched TV for less than 22 hrs per week. In the sample, there are 150 families.
This means that 22 is the:
24*100%/150 = 16th percentile.
The first percentile is greater than or equal to 22 hours: True or False?
The first percentile is less than the 16th percentile, which is 22. This means that this is false, the first percentile is less than 22 hours.
The cost of a spa treatment is $42 and there is sales tax of 6%. What is the total cost of the spa treatment?
Answer:
$52.92 has been spent in total for spa treatment and this amount includes a sales tax of $2.52 and a tip of $8.40.
Step-by-step explanation:
Cost of the spa treatment = $42
Percentage of sales tax = 6%
Percentage of tips = 20%
Normally the tips amount is calculated before adding sales tax.
Then
Amount of tips given = (20/100) * 42
= (1/5) * 42
= 8.40 dollars
Amount of sales tax taken = (6/100) * 42
= 252/100
= 2.52 dollars
Then
The total amount spent for spa treatment = (42 + 8.40 + 2.52) dollars
= 52.92 dollars
which equation is equivalent to xy (3x + 2y) = 4
Answer:
the value x is 0 and the value of y is 2
What is the answer to this problem?
Answer:
Surface area = 24in
Step-by-step explanation:
I think its 6in x 4in
so like since the green cylinder is 6in i think you multiply it with the purple (sorry if I’m wrong)
Farmer Bob can get 10 gallons of milk from 4 cows. How many gallons of milk can he get from 14 cows?
Answer:
40 gallons of milk
Step-by-step explanation:
trust me that's the answer
The farmer will get 35 gallons of milk from 14 cows.
Process:
1) find the unit rate. do this by taking the independent value and divide it by the dependent value
10/4=2.5
2) Take this number and multiply it by the next dependent value
2.5 x 14 = 35
what is the measure of angle a enter your answer as a decimal in the box round only your final answer to the nearest hundredth
ANSWER.
The measure of angle A is 53.13°.
STEP BY STEP
Given,
ABC is a triangle,
In which m∠CBA = 90°, AB = 3 cm, BC = 4 cm and CA = 5 cm,
By the law of sine,
( By cross multiplication )
By substituting the values,
( sin 90° = 1 )
Hence, the measure of angle A is 53.13°.
What is the slope of the line graphed below? (-1,3) (-2,-1)
Answer:
the slope of (-1,3) (-2,-1) is 4
The waiting time W for accessing one record from a computer database is a random variable uniformly distributed between 0 and 28 milliseconds. The read time R for moving the information from the disk to the main memory is 7 milliseconds. The random variable X milliseconds is the total access time (waiting time + read time) to get one block of information from the disk. Before performing a certain task, the computer must access 6 different blocks of information from the disk. (Access times for different blocks are independent of one another.). Compute the followings:
a. E[X]
b. Vae[X]
c. E[A]
Solution :
Let
Waiting time for accessing one record = W
Read time for moving the information = R
Total time for accessing to get one block of information = X
So, the random variable X is defined as :
X = W + R
= W + 7
a). Calculating E(X)
E(X) = E(W+7)
= E(W) + 7
[tex]$=\int_{0}^{28}\frac{1}{28-0}w dw +7$[/tex]
[tex]$=\frac{1}{28}\int_{0}^{28}w dw +7$[/tex]
[tex]$=\frac{1}{28}\left[\frac{w^2}{2}\right]_0^{28}+7$[/tex]
[tex]$=\frac{1}{56}\left[28^2\right]+7$[/tex]
[tex]$=\frac{28}{2}+7$[/tex]
= 14 + 7
= 21
b). Calculating Var(X)
V(X) = V(W+7)
= V(W)+0
= V(W)
= [tex]$E(W^2)-[E(W)]^2$[/tex]
[tex]$=\int_0^{28}\frac{1}{28}w^2 dw-[14]^2$[/tex]
[tex]$=\frac{1}{28}\left[\frac{w^3}{3}\right]_0^{28}-196$[/tex]
[tex]$=\frac{1}{28\times 3}\times 28^3-196$[/tex]
[tex]$=\frac{28\times 28}{3}-196$[/tex]
= 65.33
c). Considering A is the random variable that can be defined as follows:
A = 6(W+7)
=6W + 42
So calculating E(A)
E(A) = E(6W + 42)
= E(6W) +42
= 6E(W) + 42
= 6(14) + 42
= 84 + 42
= 126
In triangle ABC, m∠A=(2x+2)∘, m∠C=54∘, and the exterior angle at B is (4x)∘.
Triangle A B C. Angle A is 2 X plus 2 degrees, angle C is 54 degrees, & the exterior angle at B is 4 X degrees.
© 2020 StrongMind. Created using GeoGebra.
What is the measure of angle A?
58∘
112∘
28∘
68∘
Answer:
112 ^0
Step-by-step explanation:
cant explains it very well
At the beginning of the school year, Jamie had $500 in her savings account. She wants to have at least $200 left in the account at the end of the school year. Each week, she withdraws $30 for spending money. To determine how many weeks she can spend $30, Jamie wrote and solved this inequality.
500 − 30x ≥ 200
−500 −500
−30x ≥ −300
x ≥ 10
Review Jamie’s work. What was her error?
Her error was that she misplaced the numbers
-30x ≥ -300
its supose
to be -30x ≥ 200
Answer:
Jamie should have reversed the inequality when using the division property of inequality.
Step-by-step explanation:
which equation represents a line that passes through (5,4) with a slope of 2/5
Answer:
y = 2/5x +2
Step-by-step explanation:
y - 4 = 2/5(x -5)
y-4 = 2/5x -2
y = 2/5x +2
A tree farm has 70 rows of trees. The first row has 25 trees, the second
row has 30 trees, the third row has 35 trees, and so on. Let n be the
number of the row.
Write a function f(n) to represent the number of total trees in the nth
row. (gmm) pls help
Step-by-step explanation:
The function is:
[tex]f(n) = 25 + 5 \times (n - 1) \\ n \geqslant 1[/tex]
What is the perimeter of triangle ABC?
12 units
13 units
14 units
18 units
\
Step-by-step explanation:
Here
A(-2,6)B(1,2)C(-2,-2)Now,
[tex]\\ \tt\hookrightarrow AB=\sqrt{(-2-1)^2+(6-2)^2}[/tex]
[tex]\\ \tt\hookrightarrow AB=\sqrt{(-3)^2+(4)^2}[/tex]
[tex]\\ \tt\hookrightarrow AB=\sqrt{9+16}[/tex]
[tex]\\ \tt\hookrightarrow AB=\sqrt{25}=5units[/tex]
And,
[tex]\\ \tt\hookrightarrow BC=\sqrt{1+2)^2+(2+2)^2}[/tex]
[tex]\\ \tt\hookrightarrow BC=\sqrt{(3)^2+(4)^2}[/tex]
[tex]\\ \tt\hookrightarrow BC=\sqrt{9+16}[/tex]
[tex]\\ \tt\hookrightarrow BC=\sqrt{25}=5units[/tex]
And
[tex]\\ \tt\hookrightarrow AC=\sqrt{(-2+2)^2+(6+2)^2}[/tex]
[tex]\\ \tt\hookrightarrow AC=\sqrt{(0)^2+(8)^2}[/tex]
[tex]\\ \tt\hookrightarrow AC=\sqrt{8^2}=\sqrt{64}=8units[/tex]
Now
[tex]\\ \tt\hookrightarrow perimeter=5+5+8=18units[/tex]
You have been given the task of designing a study concerning the lifetimes of five different types of electric motor. The initial question to be addressed is whether there are differences in mean lifetime among the five types. There are 20 motors, four of each type, available for testing. A maximum of five motors can be tested in a day. The ambient temperature differs from day to day, and this can affect motor lifetime.
a. Describe how you would choose the five motors to test each day. Would you use a completely randomized design? Would you use any randomization at all?
b. If X;j represents the measured lifetime of a motor of type i tested on day j, express the test statistic for testing the null hypothesis of equal lifetimes in terms of the Xir
Answer:
a-As the only factor of interest is type of electric motor, thus instead of using 1-factor randomization, a randomized block design is used where at maximum one motor of each type is tested every day.
b- The test statistic is given as
[tex]F_{I-1,(I-1)(J-1)}=\dfrac{12\left(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}\right) }{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}[/tex]
Step-by-step explanation:
a-
This is done such that the days are considered as blocks and the randomization is only occuring within the block. The order of testing is random. However the condition is implemented such that one motor of each type is tested each day.
b-
The F-Value is given as
[tex]F-Value=\dfrac{MSA}{MSAB}[/tex]
Here MSA is given as
[tex]MSA=\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}[/tex]
Here
I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex]Similarly MSAB is given as
[tex]MSAB=\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}[/tex]
Here
I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{.j}[/tex] is the column-wise mean which is given as [tex]\bar{X}_{.j}=\dfrac{1}{I}\Sigma^I_{i=1}X_{ij}[/tex][tex]X_{ij}[/tex] is the any motor j of type iBy putting these values and simplifying, equation becomes:
[tex]F-Value=\dfrac{MSA}{MSAB}\\\\F-Value=\dfrac{\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}}{\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}}\\\\F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{5-1}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(5-1)(4-1)}}\\\\[/tex]
This is further simplified as
[tex]F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{4}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\[/tex]
The numerator can be written as
[tex]F-Value=\dfrac{\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{12(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..})}{{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}}\\[/tex]