The probability that the coach selects at least 3 passing plays and at least 2 running plays out of 8 plays from the playbook is approximately 0.4914 or 49.14%. This means there is a 49.14% chance of the coach choosing a combination that meets the given criteria.
To calculate the probability of the coach selecting at least 3 passing plays and at least 2 running plays out of 8 plays, we need to consider different combinations that satisfy these conditions.
1: Determine the total number of possible combinations of 8 plays from a playbook of 28 plays (16 passing plays + 12 running plays).
Total Combinations = C(28, 8) = 28! / (8! * (28-8)!) = 3,395,685
2: Calculate the number of combinations that have at least 3 passing plays and at least 2 running plays.
First, we calculate the number of combinations with exactly 3 passing plays and 2 running plays:
Number of Combinations with 3 passing and 2 running = C(16, 3) * C(12, 2) = (16! / (3! * (16-3)!) * (12! / (2! * (12-2)!) = 560 * 66 = 36,960
Next, we calculate the number of combinations with exactly 4 passing plays and 2 running plays:
Number of Combinations with 4 passing and 2 running = C(16, 4) * C(12, 2) = (16! / (4! * (16-4)!) * (12! / (2! * (12-2)!) = 1,820 * 66 = 120,120
Finally, we calculate the number of combinations with 5 passing plays and at least 2 running plays:
Number of Combinations with 5 passing and 2 or more running = C(16, 5) * (C(12, 2) + C(12, 3) + C(12, 4) + C(12, 5) + C(12, 6) + C(12, 7) + C(12, 8)) = (16! / (5! * (16-5)!) * (C(12, 2) + C(12, 3) + C(12, 4) + C(12, 5) + C(12, 6) + C(12, 7) + C(12, 8)) = 4368 * (66 + 220 + 495 + 792 + 924 + 792 + 495) = 4368 * 3786 = 16,530,048
Total Number of Combinations with at least 3 passing and 2 running plays = Number of Combinations with 3 passing and 2 running + Number of Combinations with 4 passing and 2 running + Number of Combinations with 5 passing and 2 or more running = 36,960 + 120,120 + 16,530,048 = 16,687,128
3: Calculate the probability.
Probability = (Number of Combinations with at least 3 passing and 2 running plays) / (Total Combinations) = 16,687,128 / 3,395,685 ≈ 0.4914
Therefore, the probability that the coach selects at least 3 passing plays and at least 2 running plays out of 8 plays is approximately 0.4914 or 49.14%.
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okay hi everyone can someone help me with my math reveiw im in 7th grade and i really need help with this and my mom is yelling at me because im failing
factor this trinomial in standard form 2n^2 + 7n + 5
Answer:
Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored. Equation at the end of step 2 : 2n2 - 7n - 5 = 0. Step 3 : Parabola ...
Step-by-step explanation:
Wendy’s family lost the power at their house when there was a bad storm. The power was out for 3 days! Wendy’s neighbors lost power for 68 hours. Whose power was out for a greater amount of time?
Can someone help me on this one please?
What is the answer to this question?
Answer:
C is the answer also can I have brian list
Step-by-step explanation:
help me please :)
thank you :P
Answer: Should be 7
Step-by-step explanation:
14/2 is 7
Given the solid Ethat lies between the cone z2 = x2 + y2 and the sphere x2 + y2 + (z + 2)2 = 2 a) Set up the triple integrals that represents the volume of the solid E in the rectangular coordinate system b)Set up the triple integrals that represents the volume of the solid E in the cylindrical coordinate system c) Evaluate the volume of the solid E
a) The volume of the solid E in rectangular coordinate system is given by: [tex]$$\iiint_{E}[/tex] dx dy dz = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$[/tex]
b) The volume of the solid E in cylindrical coordinate system is given by: [tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$[/tex]
c) The volume of the solid E is 11π/3.
a) The solid E that lies between the cone z² = x² + y² and the sphere x² + y² + (z + 2)² = 2.
Volume of solid E in rectangular coordinate systemLet the limits of x, y, z be X, Y, Z respectively.
The limits of X:
From the equation, z² = x² + y²
Z² = X² + Y²
X² = Z² - Y²
Let Z = 0, then X² = - Y² which is impossible. Therefore, Y can take any value such that Y < Z.
The limits of Y:
From the equation, z² = x² + y²
Z² = X² + Y²
Y² = Z² - X²
Let Z = 0, then Y² = - X² which is impossible. Therefore, X can take any value such that X < Z.
Limits of Z:
From the equation x² + y² + (z + 2)² = 2z² + 4z + 8 = 2(Z + 1)² + 6
The limits of z are Z < 2 and Z > - 2.
Volume in rectangular coordinate system:
[tex]$$\iiint_{E}[/tex] dx dy dz = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$[/tex]
b) Volume of solid E in cylindrical coordinate system
Let the limits of ρ, θ, z be R, Θ, Z respectively.
The limits of R:
From the equation, z² = ρ² cos²θ + ρ² sin²θ
Z² = ρ²
Rho² = Z²/ cos²θ + sin²θ
Rho = Z/ cosθ
Let Z = 0, then Rho = 0. Therefore, R can take any value such that 0 ≤ R < 2.
Limits of Θ:
From the equation, z² = ρ² cos²θ + ρ² sin²θ
Z² = ρ² sin²θ
Theta² = tan⁻²(Z²/ ρ²)
Let Z = 0, then Θ = 0. Therefore, Θ can take any value such that 0 ≤ Θ ≤ π/2.
Limits of Z:
From the equation x² + y² + (z + 2)² = 2z² + 4z + 8 = 2(Z + 1)² + 6
The limits of Z are -2 ≤ Z < 2.
Volume in cylindrical coordinate system:
[tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$[/tex]
c) Evaluation of the volume of solid E:
Using rectangular coordinate system, the volume of solid E is
[tex]$$\iiint_{E} dx dy dz[/tex] = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$$$[/tex]
[tex]=\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} [x]_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dy dz$$$$=\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} 2\sqrt{z^2 - y^2} dy dz$$$$=\int_{-2}^{2} \left[-\frac{1}{2}(z^2 - y^2)^{3/2}\right]_{y=0}^{y=\sqrt{z^2}} dz$$$$=\int_{-2}^{2} \frac{1}{2}z^3 dz = 0$$[/tex]
Therefore, the volume of solid E using rectangular coordinate system is 0.
Using cylindrical coordinate system, the volume of solid E is
[tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$$$=\int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \left[\frac{\rho^2}{2}\right]_{0}^{\sqrt{4 - z^2}} d\theta dz$$$$=\int_{0}^{2} \int_{0}^{\frac{\pi}{2}} 2 - \frac{z^2}{2} d\theta dz$$$$=\int_{0}^{2} \left[2\theta - \frac{\theta z^2}{2}\right]_{\theta = 0}^{\theta = \frac{\pi}{2}} dz$$$$=\int_{0}^{2} \pi - \frac{\pi z^2}{4} dz = \frac{11\pi}{3}$$[/tex]
Therefore, the volume of solid E using cylindrical coordinate system is 11π/3.
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5 - y"+ 2y' = 2x+5-e-2x {undetermined coefficients)
The solution to the differential equation 5y'' - 2y' = 2x + 5 - e^(-2x) using the method of undetermined coefficients is given by y = C1 + C2e^(2x) - (5/2)x + B, where C1, C2, and B are constants determined by the initial or boundary conditions.
To solve the differential equation 5y'' - 2y' = 2x + 5 - e^(-2x) using the method of undetermined coefficients, we assume a particular solution of the form:
y_p = Ax + B + Ce^(-2x)
where A, B, and C are undetermined coefficients to be determined.
Taking the derivatives:
y_p' = A - 2Ce^(-2x)
y_p'' = 4Ce^(-2x)
Substituting these derivatives into the original differential equation, we have:
5(4Ce^(-2x)) - 2(A - 2Ce^(-2x)) = 2x + 5 - e^(-2x)
Simplifying the equation:
20Ce^(-2x) - 2A + 4Ce^(-2x) = 2x + 5 - e^(-2x)
(24C)e^(-2x) - 2A = 2x + 5 - e^(-2x)
For the equation to hold for all x, the coefficients on both sides of the equation must be equal.
Matching the coefficients:
24C = 0 -> C = 0
-2A = 5 -> A = -5/2
Therefore, the particular solution is:
y_p = (-5/2)x + B
To find the value of B, we substitute the particular solution back into the original differential equation:
5(-5/2) - 2(0) = 2x + 5 - e^(-2x)
-25/2 = 2x + 5 - e^(-2x)
Solving for x and e^(-2x) in terms of B:
2x = -25/2 - 5 + e^(-2x)
2x = -35/2 + e^(-2x)
As the left side is a linear function of x and the right side is a constant plus an exponential function, there is no value of x that satisfies this equation for all x. Hence, the equation is inconsistent, and there is no particular solution in the form y_p = Ax + B.
Therefore, the solution to the given differential equation using the method of undetermined coefficients is the complementary function (homogeneous solution) plus the particular solution, which is:
y = y_c + y_p = C1 + C2e^(2x) + (-5/2)x + B
where C1 and C2 are constants determined by the initial or boundary conditions, and B is an arbitrary constant.
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You may need to use the appropriate appendix table to answer this question.
Automobile repair costs continue to rise with the average cost now at $367 per repakt Assume that the cost for an automobile repair is normally distributed with a standard deviation of $88. Answer the following questions about the cost of automobile repairs
(a) What is the probability that the cost will be more than $480 (Round your answer to four decimal places.________
(b) What is the probability that the cost will be less than $240 (Roxind your answer to four decimal places.)________
(c) What is the probability that the cast will be between $240 and $480 (Round your answer to four decimal places.)________
(d) of the cost for your car repair is in the lower 5% of automoble repair charges, what is your matmum possible cast in dollars? (Round your answer to the nearest cent)
$________
The maximum possible cost in dollars is $226.76 (approx).
Standard deviation = $88
Let X be the cost of the automobile repair, then X ~ N(367, 88^2) (normal distribution)
Now, we need to find the following probabilities:
(a) P(X > 480)(b) P(X < 240)(c) P(240 < X < 480)(d)
Find X such that P(X < X1) = 0.05, where X1 is the lower 5% point of X(a) P(X > 480)
We need to find P(X > 480)P(X > 480) = P(Z > (480 - 367)/88) [Standardizing the random variable X]P(X > 480) = P(Z > 1.2955)
Using the standard normal table, the value of P(Z > 1.2955) = 0.0983 (approx)
Hence, the required probability is 0.0983 (approx)(b) P(X < 240)
We need to find P(X < 240)P(X < 240) = P(Z < (240 - 367)/88) [Standardizing the random variable X]P(X < 240) = P(Z < -1.4432)
Using the standard normal table, the value of P(Z < -1.4432) = 0.0749 (approx)
Hence, the required probability is 0.0749 (approx)(c) P(240 < X < 480)
We need to find P(240 < X < 480)P(240 < X < 480) = P(Z < (480 - 367)/88) - P(Z < (240 - 367)/88) [Standardizing the random variable X]P(240 < X < 480) = P(Z < 1.2955) - P(Z < -1.4432)
Using the standard normal table, the value of P(Z < 1.2955) = 0.9017 (approx)and the value of P(Z < -1.4432) = 0.0749 (approx)
Hence, the required probability is 0.9017 - 0.0749 = 0.8268 (approx)(d)
Find the maximum possible cost in dollars, if the cost for your car repair is in the lower 5% of automobile repair charges.
This is nothing but finding the lower 5% point of X.We need to find X1 such that P(X < X1) = 0.05.P(X < X1) = P(Z < (X1 - 367)/88) [Standardizing the random variable X]0.05 = P(Z < (X1 - 367)/88)
Using the standard normal table, the value of Z such that P(Z < Z0) = 0.05 is -1.645 (approx)
Hence, we get,-1.645 = (X1 - 367)/88
Solving for X1, we get: X1 = 88*(-1.645) + 367 = $226.76 (approx)
Therefore, the maximum possible cost in dollars is $226.76 (approx).
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ALGEBRAICALLY solve the following system of equations:
y= 22 - 4x + 6 and y=x + 2
Rewrite the expression in the form 3^n
Answer:
n=2
Step-by-step explanation:
[tex]\frac{3.3.3.3.3.3}{3.3.3.3} = 3^{n}[/tex]
[tex]3^{2}[/tex]= [tex]3^{n}[/tex]
n=2
Answer:
[tex]3^1[/tex]
Step-by-step explanation:
[tex]\frac{3*3*3*3*3}{3*3*3*3} =3^1[/tex]
Can anyone help me with this? Please and thank you!
Answer:
x=-6, y=-7
Step-by-step explanation:
Answer:
x = -6, y = -7
Step-by-step explanation:
One way to solve for x and y is using the substitution method
(1) 3x + 4y = -46
(2) 6x + y = -43
Solve for y in equation (2)
6x + y =-43, so y = -43 - 6x
Substitute y = -43 -6x into equation (1)
3x + 4(-43 -6x) = -46
3x -172 -24x = -46
-21x -172 = -46
-21x = 126
x = -6
Find y by substituting x = -6 into equation (2)
6(-6) + y = -43
-36 + y = -43
y = -7
Two samples of sizes 25 and 35 are independently drawn from two normal populations has standard deviation of 0.9 and 0.8 respectively. Determine the variance sampling distribution for difference of two means.
A. 0.25
B. 0.51
C. 0.30
D. 0.051
Regardless of the shape of the population, the sampling distribution of the mean approaches a normal distribution as sample size increases
A. False
B. True
The variance of the sampling distribution for the difference of the two means is 0.0147142857.
The correct option is D. 0.051.
The variance of the sampling distribution for the difference of two means of sample populations can be calculated using the formula given below:
[tex]\Large\frac{{{\sigma }_{1}}^{2}}{n_{1}}+\frac{{{\sigma }_{2}}^{2}}{n_{2}}[/tex]
Where,[tex]{{\sigma }_{1}}$ and ${{\sigma }_{2}}[/tex] are the standard deviations of the two populations respectively, and [tex]{{n}_{1}} and ${{n}_{2}}[/tex] are the sample sizes of the first and second populations respectively.
Substituting the given values, we get
[tex]\Large\frac{0.9^2}{25}+\frac{0.8^2}{35}=0.009+0.0057142857[/tex]
=0.0147142857
Therefore, the variance of the sampling distribution for the difference of the two means is 0.0147142857.
Sampling distribution approaches normal distribution:
True. Regardless of the shape of the population, the sampling distribution of the mean approaches a normal distribution as the sample size increases.
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HELP PLEASE! MARKING BRAINLIEST
WHT IS THE CIRCUMFERENCE OF THE CIRCLE SHOWN IN THE PICTURE? (Also show the process or tell me what the radius or diameter of the circle is)
Answer:
109.9 cm
Step-by-step explanation:
Circumference = (pi)(diameter)
They tell you diameter = 35
c = (3.14)(35)
c = 109.9 cm
Please lmk if you have questions.
Answer:
circumference : 109.96 cm
Step-by-step explanation:
The radius of a circle is half its diameter. The radius of a circle with a diameter of 35cm is 17.5cm.
The circumference of a circle is found by 2πr . So that would be 2π 17.5
which would be equal to 109.96cm (2 sig. fig.).
The area of a circle is found by πr2 . So that's π⋅17.5 which is equal to 962.11cm (2 sig.fig.).
During an experiment in which you are investigating the acceleration changes due to force changes, what value must stay constant during these trials?
a. Force
b. Velocity
c. Acceleration
d. Mass
During an experiment of acceleration changes, the value that must stay constant during these trials is d. Mass
Inertia, a basic characteristic of all matter, may be measured quantitatively using mass. When a force is applied, an item effectively provides resistance to changes in velocity or position. The change brought about by an applied force is less the more mass an item has. According to Newton's second law of motion an object's acceleration is inversely proportional to its mass and directly proportional to the net force that has been applied to it. It may be expressed mathematically as F = ma.
The goal of this experiment is to see how variations in force impact acceleration. It is crucial to maintain the mass constant throughout the trials in order to isolate the impact of force on acceleration. Any observable variations in acceleration may be entirely attributable to variations in the applied force by maintaining the mass constant.
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Sam just purchased a new car. After his employee discount and the sale that the dealership applied to the original
price, Sam paid $13,734.60. If Sam's employee discount was applied to the original price after the dealer discount,
then determine the original price of the vehicle given that the employee discount was 8% and the dealership
discount was 25%. Round your answer to the nearest cent.
a $20,375.21
c. $19,250.13
b. $18,350.33
d. $19,905.22
Answer:
D 19,905
Step-by-step explanation:
19,905.22×25%=4976.31
19905.22-4976.31=14,928.91
14928.91×8%=1194.31
14928.91-1194.31=13734.6
help me please, i’m confused. thanks!
Answer:
Step-by-step explanation:
Delano downloaded 9 songs on Saturday and 5 songs on Sunday. How many total songs did he download on Saturday and Sunday?
Answer:
the answer is 14 I pinkie promise!
The total number of cookies, y, contained in x packages can be represented by the equation y=24x. Which of the following graphs best represents this situation?
Answer: B)
Step-by-step explanation:
By checking which graph is satisfied, we choose points that the function has pass through.
First, we know that y = mx + b, where m is the slope, how the line change; and b is the y-intercept. In this equation, the slope is 24 which the line is increased. So we can eliminate the choice D, the line in D decreased.
Then we find where the first point and second point this graph will be.
When x = 0, y = 24x = 24(0) = 0, (0,24)
When x = 1, y = 24x = 24(1) = 24, (1,24)
1 package can have 24 cookies, only B have 24 cookies in 1 package.
PLEASEEEE HELP ‼️‼️1️⃣
Answer:
8/7
Step-by-step explanation:
12*2=24.
7*3=21
24/21 is divisible by 3
=8/7
Best disc and answer will get BRAINLIEST
Answer:
A is the answer
Step-by-step explanation:
All you have to do is follow the order pair such as 2, 100 and see if that is a correct pair.
Hope that helps
Answer: A. (2, 100)
Step-by-step explanation:
What is the least common multiple of 3,4 and 6?
Answer:
12
Step-by-step explanation:
Write down multiples of each number:
3, 6, 9, 12 . . .
4, 8, 12 . . .
6, 12 . . .
The first one they all have is the LCM.
Answer:
12
Step-by-step explanation:
Think of it this way. Simplifying 3, 4 and 6 into their simplest factors:
[tex]3=3[/tex]
[tex]4=2*2[/tex]
[tex]6=3*2[/tex]
6 is a multiple of both 3 and 2, which are both represented by the factors of 3 and 4. Thus, as it is doubled in these, it is not necessary to find the lowest common multiple of the numbers.
Now the LCM can be multiplied with the factors of the remaining numbers:
LCM[tex]=3*2*2[/tex]
Notice the first two numbers equal 6, the second and third equal 4, and the first only equals 3. This means the three numbers are represented in the LCM.
[tex]3*2*2=24[/tex]
And that is the LCM, so we are done. QED
Alan and Beth share $1190 in the ratio Alan : Beth = 5:2.
Work out how much Alan receives.
options:
$850
$1666
$34
$119
The share of money Alan receives is $850. Therefore, option C is correct answer.
Given that, the total amount is $1190 and the ratio Alan: Beth = 5:2.
We need to find the how much money Alan gets.
What is the ratio?The quantitative relation between two amounts shows the number of times one value contains or is contained within the other.
Now, 5+2=7
Money Alan receives=5/7×1190
=$850
The share of money Alan receives is $850. Therefore, option C is correct answer.
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A new car is purchased for 20300 dollars. The value of the car depreciates at 8.75% per year. What will the value of the car be, to the nearest cent, after 12 years?
My question is more on how do I know how to change the percentage, and what to change it to.
Answer:
Therefore, after 12 years the car will value $6,765.35.
Step-by-step explanation:
PLEASE HELP! EASY MATH!!
Rosie measures the heights and arm spans of the girls on her basketball team. She plots the data and makes a scatterplot comparing heights and arm spans, in inches. Rosie finds that the trend line that best fits her results has the equation y = x + 2. If a girl on her team is 69 inches tall, what should Rosie expect her arm span to be?
A) 69 = x + 2
x = 67 inches
B) y = 69 - 2 = 67 inches
C) y = 69 inches
D) y = 69 + 2 = 71 inches
Answer:
Your answer would be D. I know this is kind of late, but maybe other people that come up here could get some help
Step-by-step explanation:
1. What is ✓ 48 in simplified radical form?
Answer:
4[tex]\sqrt{3}[/tex]
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then
[tex]\sqrt{48}[/tex]
= [tex]\sqrt{16(3)}[/tex]
= [tex]\sqrt{16}[/tex] × [tex]\sqrt{3}[/tex]
= 4[tex]\sqrt{3}[/tex]
Compare lengths. Select >, <, or = ,
2 km _ 4,000 m
Answer:
2 km < 4,000 m
Step-by-step explanation:
2 km = 2,000 m
Therefore, 2,000 m is less than 4,000 m.
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 320 babies were born and 288 of them were girls. Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born. Based on the result, does the method appear to be effective?
Based on the sample data, we can construct a 99% confidence interval estimate for the percentage of girls born as approximately 85.1% to 94.9%.
To construct a confidence interval estimate for the percentage of girls born, we can use the formula for estimating a proportion.
First, we calculate the sample proportion, which is the number of successes (girls) divided by the total number of trials (babies born):
Sample proportion (p-hat) = Number of girls / Total number of babies born
= 288 / 320
= 0.9
Next, we can construct the confidence interval using the sample proportion. Since we want a 99% confidence interval, we need to find the critical value corresponding to that level of confidence. For a two-tailed test, the critical value is obtained from the standard normal distribution (Z-distribution).
Using a Z-table or calculator, the critical value for a 99% confidence level is approximately 2.576.
The margin of error (E) can be calculated as:
Margin of error (E) = Critical value * Standard error
The standard error (SE) for estimating a proportion is given by:
Standard error (SE) = [tex]\sqrt {(p-hat * (1 - p-hat)) / n}[/tex]
where p-hat is the sample proportion and n is the sample size.
Using these values, we can calculate the margin of error:
Standard error (SE) = [tex]\sqrt {(0.9 * (1 - 0.9)) / 320}[/tex]
≈ 0.019
Margin of error (E) = 2.576 * 0.019
≈ 0.049
Finally, we can construct the confidence interval:
Confidence interval = Sample proportion ± Margin of error
= 0.9 ± 0.049
≈ (0.851, 0.949)
Therefore, based on the sample data, we can construct a 99% confidence interval estimate for the percentage of girls born as approximately 85.1% to 94.9%.
Since the interval includes the value of 0.5 (50%), which represents an equal chance of having a girl or a boy, it suggests that the method used in the clinical trial does not significantly increase the probability of conceiving a girl.
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yo i need help please no links i just need the correct answer to pass this
if T= 101+102+103+...+199 find T
...............................................
A cylindrical test tube holds 6π cm of liquid when filled to the 6cm mark what is the diameter of the test tube to the nearest hundredth of a Centimeter
Answer:
2cm
Step-by-step explanation:
Given data
Capacity/volume of liquid held= 6π cm^3
Height= 6cm
Required
The diameter d of the tube
let us apply the expression for the volume of cylinder
V=πr^2h
6π=πr^2*6
6=r^2*6
r^2= 6/6
r^2=1
r= √1
r=1cm
Hence the diameter d = 2r= 2*1= 2cm