Answer:
mass, weight, strength of gravity increases, weight decreases
Explanation:
got it on edge
Answer:
An object’s
✔ mass
will remain constant throughout the universe, but its
✔ weight
can change from planet to planet.
If you increase the mass of a planet, what happens to its gravity?
✔ strength of gravity increases
If the gravity on a planet decreases, what happens to the weight of an object on that planet?
✔ weight decreases
Explanation:
right on edge 22
An iron wire has a length of 1.50 m and a cross sectional area of 0.290 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and a potential difference of 0.700 V is maintained across its length, determine the current in the wire (in A).
Answer:
1.35 A
Explanation:
Applying,
V = IR
I = V/R..................... Equation 1
I = Current, V = Voltage, R = Resistance.
But,
R = Lρ/A............... Equation 2
Where L = Length of the wire, ρ = resistivity, A = Cross-sectional area of the wire.
Sustitute equation 2 into equation 1
V = AV/Lρ............... Equation 3
From the question,
Given: V = 0.7 V, A = 0.290 mm² = 2.9×10⁻⁷ m², L = 1.5 m, ρ = 10×10⁻⁸ Ω.m
Substitute these values into equation 3
I = (0.7× 2.9×10⁻⁷)/(1.5× 10×10⁻⁸ )
I = (2.03×10⁻⁷)/(15×10⁻⁸)
I = 1.35 A
5. A 6.0-kilogram mass is moving with a speed of 2.0 m/s. What is the kinetic energy of the mass?
Answer:
K.E. = ½ × mv²
= ½ × 6 × (2)²
= ½ × 6 × 4
= 3 × 4
= 12 J
A 70- kg bicycle rides his 9.8- kg bicycle with a speed of 16 m/ s. What is the magnitude of the braking force of the bicycle come to rest in 4.0 m?
Answer:
F = -319.2 N
Explanation:
Given that,
The mass of a bicyclist, m = 70 kg
Mass of the bicycle = 9.8 kg
The speed of a bicycle, v = 16 m/s
We need to find the magnitude of the braking force of the bicycle come to rest in 4.0 m.
The braking force is given by :
[tex]F=ma\\\\=\dfrac{m(v-u)}{t}\\\\=\dfrac{(70+9.8)(0-16)}{4}\\\\=-319.2\ N[/tex]
So, the required force is 319.2 N.
0)
A-B-C-D-E
Describe the mass of the reactants and products given the balanced chemical reaction
A)
The mass of the products is 2/3 that of the reactants.
B)
The mass of the reactants equals the mass of the products.
C)
The mass of the reactants is less than the mass of the products.
D)
The mass of the reactants is greater than the mass of the products.
Answer:
D)
The mass of the reactants is greater than the mass of the products.
Which statement best explains why objects are pulled toward Earth’s center?
Answer:
Earth has a much greater mass than objects on its surface
Rich says that light is the same thing as electromagnetic radiation. Do you agree or
disagree with Rich? Explain your response.
Answer:
Yes, I agree with rich
Explanation:
Yes I agree with rich.
Thus is because;
The electromagnetic process is what will determine how electromagnetic radiation will be emitted. Now, the mode of travel of electromagnetic energy is in the form of waves and then the wavelength of these waves is what will enable us know the form of energy. This includes light, x-rays, gamma rays e.t.c. This means that light and the others are just parts of the spectrum emitted and are called photons.
Thus, light can be said to be electromagnetic radiation.
I can agree with Rich that light is the same as electromagnetic radiation since the two terms can conveniently be used interchangeably.
Light has become a generic term that is used to describe all electromagnetic waves. All the waves in the electromagnetic spectrum have different frequencies and wavelengths but they are travel at the same speed which has been designated as "speed of light".
Therefore, i can agree with Rich that light is the same as electromagnetic radiation since the two terms can conveniently be used interchangeably.
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What makes a 10 year old girl perfect?
Answer:
kindness
Explanation:
(a) A simple pendulum oscillates back and forth on a space vehicle. An astronaut on the space vehicle measures the period of the pendulum to be 22.58 seconds (it is a big pendulum). A passing observer in another space ship measures the period to be 31.87 seconds. Determine the relative velocity between the two observers. Show all calculation steps.
Answer:
0.706
Explanation:
Since the other astronaut measures a longer time, this is a time dilation problem. So, our equation for time dilation is given by
T = T₀/√(1 - β²) where T = period on passing space ship = 31.87 s, T₀ = period on other space vehicle = proper time = 22.58 s and β = relative velocity of between the two observers.
T = T₀/√(1 - β²)
√(1 - β²) = T₀/T
squaring both sides, we have
[√(1 - β²)]² = (T₀/T)²
1 - β² = (T₀/T)²
β² = 1 - (T₀/T)²
taking square root of both sides, we have
√β² = √[1 - (T₀/T)²]
β = √[1 - (T₀/T)²]
substituting the values of the variables into the equation, we have
β = √[1 - (22.58 s/31.87 s)²]
β = √[1 - (0.7085)²]
β = √[1 - 0.502]
β = √0.498
β = 0.706
Naming covalent compounds
P4S5
Answer:
what the heck is sakurfa
Explanation:
If F = force, which equation illustrates the Law of Conservation of Momentum?
A) F1 = F2
B) F1 = - F2
C) - F1 = -F 2
D) F1 + - F2 = F3
Answer:
b
Explanation:
f1=-f2 that could be thank u
A cold block of metal feels colder than a block of wood at the same temperature. Why? A hot block of metal feels hotter than a block of wood at the same temperature. Again, why? Is there any temperature at which the two blocks feel equally hot or cold? What temperature is this?
: In general, metals feel colder or hotter to the touch than other materials at the same temperature because they're good thermal conductors. This means they easily transfer heat to colder objects or absorb heat from warmer objects
It is because the metal conducted heat faster than it feels colder than the wood, which conducted heat slower. Even tho they are similar temperatures. The metal will feel colder than the wood because of the thermal conductivity of the metal, compared to the wood.
The shortest pipe in a particular organ is 1.23 m.
Determine the frequency (in Hz) of the ninth harmonic (at 0°C) if the pipe is closed at one end.
Hz
Answer:
The 9th harmonic is 1,010.67 Hz.
Explanation:
Given;
length of the pipe, L = 1.23 m
speed of sound at 0°C = 331.5 m/s
A pipe closed at one end is known as a closed pipe;
The wavelength of the sound for the first harmonic is calculated as;
L = Node ------ > Antinode
[tex]L = \frac{\lambda }{4} \\\\\lambda = 4L[/tex]
First harmonic: [tex]F_0 = \frac{V}{\lambda} = \frac{V}{4L}[/tex]
The wavelength of the sound for the first harmonic is calculated;
L = Node ----> Node + Node ------> Antinode
[tex]L = \frac{\lambda}{2} + \frac{\lambda}{4} = \frac{2\lambda+\lambda}{4} = \frac{3\lambda}{4} \\\\\lambda = \frac{4 L}{3}[/tex]
Second harmonic: [tex]F_1 = \frac{V}{\lambda} = \frac{3V}{4L}[/tex]
F₁ = 3F₀
The increment from F₀ to F₁ is 1 to 3; (odd number).
(1, 3, 5, 7, 9, 11, 13, 15, 17, 19..... n+2, where n is odd number)
The 9th harmonic = F₈
F₈ = 15F₀
[tex]F_8= 17(F_0) = 15 (\frac{V}{4L} )\\\\F_8 = 15(\frac{331.5}{4\times 1.23} )\\\\F_8 = 1,010.67 \ Hz[/tex]
Therefore, the 9th harmonic is 1,010.67 Hz.
The frequency of the 9th harmonic if the pipe is closed at one end is 605.48 Hz.
Based on the given information,
• The length (l) of the shortest pipe given is 1.23 m.
The speed of sound at 0 degree C is,
[tex]V = 331\sqrt{1+\frac{T}{273} } \\V = 331\sqrt{1+\frac{0}{273} } \\V = 331 m/s[/tex]
Now the condition is that the pipe is closed at one end. The formula to use in the given case is,
[tex]fn = \frac{nv}{4l} \\[/tex]
Here l is the length of the organ pipe.
Now the frequency of the 9th harmonic will be,
[tex]f9 = \frac{9v}{4l} \\\\f9 = \frac{9*331}{4*1.23} \\f9 = 605.48 Hz[/tex]
Thus, the frequency of the 9th harmonic if the pipe is closed at one end is 605.48 Hz.
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PLEASE HELP I AM SO STUMPED ABOUT THIS QUESTION PLEASE HELP
This is my alt account just grinding points
define projectile in your own .
Answer:
a body which was thrown in space ,moves under the influence of gravity only is defined as projectile.
Answer:
projectile is defined as a body thrown in space , moves under the influence of gravity .hope it is you
15 points!
a. Calculate the electric potential energy stored in a 1.4 x 10-7 F capacitor
that stores 3.40 x 10-6 C of charge at 24.0 V.
Answer:
[tex]4.12\times 10^{-5}\ J[/tex].
Explanation:
Given that,
Capacitance, [tex]C=1.4\times 10^{-7}\ F[/tex]
Charge stored in the capacitor, [tex]Q=3.4\times 10^{-6}\ C[/tex]
We need to find the electric potential energy stored in the capacitor. The formula for the electric potential energy stored in the capacitor is given by :
[tex]E=\dfrac{Q^2}{2C}[/tex]
Put all the values,
[tex]E=\dfrac{(3.4\times 10^{-6})^2}{2\times 1.4\times 10^{-7}}\\\\=4.12\times 10^{-5}\ J[/tex]
So, the required electric potential eenergy is equal to [tex]4.12\times 10^{-5}\ J[/tex].
Star X has an apparent magnitude of 1. Star Y has an apparent magnitude of 4. Both stars are in the same star cluster. Which star is more intrinsically luminous and by what factor
Answer:
Explanation:
From the given information:
Since both stars are in the same cluster, the magnitude and luminosity relationship can be calculated as:
[tex]m_1 - m_2 = -2.5 log _{10} (\dfrac{L_1}{L_2})[/tex]
Given that;
m_1 = 1 and
m_2 = 4
Therefore,
[tex]1 - 4 = -2.5 log _{10} ( \dfrac{L_1}{L_2})[/tex]
[tex]3 = -2.5 log _{10} ( \dfrac{L_1}{L_2})[/tex]
Making [tex]\dfrac{L_1}{L_2}[/tex] the subject of the formula:
[tex]\implies \dfrac{L_1}{L_2}= 10^{(\dfrac{3}{2.5})}[/tex]
=15.84
≅ 16
Hence, we can conclude that star X is more luminous by a factor of 16
Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweezers is 1000 W/m2, the same as the intensity of sunlight at the surface of the Earth. (a) What is the pressure on an atom if light from the tweezers is totally absorbed
Answer:
a= 4.4×10 m/s^2
Explanation:
pressure P = E/c
Where, E = 100 W/m^2 intensity of light
c= speed of light = 3×10^8 m/s
P = 1000/ 3×10^8
P = 3.33×10^(-6) Pa
Force F = P×A
P is the pressure and c= speed of lightF = 3.33×10^{-6}×6.65×10(-29)
= 2.22×10^{-6}
acceleration a = F/m = 2.22×10^{-6}/ 5.10×10^{-27}
a= 4.4×10 m/s^2
help fast lol- sience!!! giving brainliest answer too!
Answer:
I think it's C. Long root systems to reach water deep underground.
Answer:
C
stilt roots provide extra support
Why do we experience winter during the time the Earth is closest to the sun’s heat.
Answer:
Because the earth's axis is tilted. ... It is all about the tilt of the Earth's axis. Many people believe that the temperature changes because the Earth is closer to the sun in summer and farther from the sun in winter. In fact, the Earth is farthest from the sun in July and is closest to the sun in January
which of the following best defines spring constant ?
a. the amount of force needed to extend or compression og the spring.
b. the amount of force needed every 1 meter of stretch or compression of the spring.
c. the amount of energy needed to extend or compress a spring for every 1 kilogram of mass of the spring.
d. the amount of energy needed for every 1 meter of stretch or compression of the spring.
Answer:
A
Explanation:
A bullet with mass m = 5.21 g is moving horizontally with a speed v = 443 m/s when it strikes a block of hardened steel with mass M = 14.8 kg (initially at rest). The bullet bounces off the block in a perfectly elastic collision. (a) What is the speed (m/s) of the block immediately after the collision?
[tex]V_{f2} =0.29 \dfrac{m}{s}[/tex] :Speed of the block immediately after the collision.
What is the elastic collision?
From elastic collision theory.
Momentum of a body is given as
[tex]P=m\times v[/tex]
where
p:Linear momentum
m: mass
v:velocity
There are 3 cases of collisions : elastic, inelastic and plastic.
For elastic collision the change in momentum remains constant
[tex]P_{i} =P_{f}[/tex]
Nomenclature and data
m₁: ball mass= 5.21 g= 5.21*10⁻³kg
V₀₁: initial ball speed, =412 m/s
[tex]V_{f1}[/tex]: final ball speed
m₂: block mass = 14.8 kg
V₀₂: initial block speed, = 0
[tex]V_{f2}[/tex]: final block speed
We apply furmula
[tex]P_{i} =P_{f}[/tex]
m₁[tex]\times[/tex]V₀₁+m₂[tex]\times[/tex]V₀₂=m₁[tex]\times[/tex]Vf₁+m₂[tex]\times[/tex]Vf₂
5.21[tex]\times[/tex]10⁻³[tex]\times[/tex]412+14.8[tex]\times[/tex]0= 5.21[tex]\times[/tex]10⁻³[tex]\times[/tex]Vf₁+14.8[tex]\times[/tex]Vf₂
2.15= 5.21*10⁻³[tex]\times[/tex]Vf₁+14.8[tex]\times[/tex]Vf₂ Equation (1)
For perfectly elastic collision the coefficient of elastic restitution (e) is equal to 1, and e is defined like this:
[tex]e=\dfrac{v_{f2-V_{f1} } }{v_{01-V_{ 02} } }[/tex]
1*(V₀₁-V₀₂) =Vf₂-Vf₁ , V₀₂=0, V₀₁ =412 m/s
412=Vf₂-Vf₁
Vf₁=Vf₂-412 Equation (2)
We replace Equation (2) in Equation (1)
2.15= 5.21[tex]\times[/tex]10⁻³(Vf₂-412)+14.8[tex]\times[/tex]Vf₂
2.15= 5.21[tex]\times[/tex]10⁻³*Vf₂-2.15+14.8*Vf₂
4.3=14.805Vf₂
[tex]Vf_{2} =\dfrac{4.3}{14.805} =0.29 \dfrac{m}{s}[/tex]: (+) ,with equal direction of the movement of the ball before the collision.
Hence [tex]V_{f2} =0.29 \dfrac{m}{s}[/tex] Speed of the block immediately after the collision.
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is being a plat 2 in rainbow 6 siege a good rank?
Answer:
In a way it does, but overall, there are many factors that affect your rank. In general, and talking about the average Platinum II, they are pretty decent according to casual player standards.
Explanation:
Can the tangent line to a velocity vs. time graph ever be vertical? Explain.
Answer:
No. Because it would correspond to zero Instantaneous acceleration.
Explanation:
hope this helps
2..Read the following statements carefully and choose the correct option
Statement 1: Angle of incidence is equal to angle of reflection
Statement 2: Angle between incident ray and reflected ray is double that of the
Angle of incidence.
A) Statement (1) is correct while statement (2) is incorrect
B) Statement (2) is correct while statement (1) is incorrect
C) Both statements are correct
D) Both statements are incorrect
Answer:
statement 1 is correct
2 not sure
Explanation:
A turbo molecular pump has rapidly rotating blades which hit the molecules of gas in the coating chamber. This collision transfers some momentum to the particles. This process of momentum transfer is more efficient if the average linear velocity of a molecule is less than the linear velocity of the blade tip. Assuming that a particular pump has a linear blade tip velocity of 400 m/s, (a) calculate the ratio of the average room temperature (say, 27 0 C) molecular velocity to blade tip velocity for the gases such as hydrogen, nitrogen and xenon having molar masses of 2, 28 and 131 g/mol, respectively. (b) Is the turbo molecular pump better for pumping heavy element or light element?
Answer:
heavy molecules are pumped much more efficiently than light molecules. Most gases are heavy enough to be well pumped but it is difficult to pump hydrogen and helium efficiently.
a rocket sled decelerates from 400m/s to 0 in 5 seconds. Calculate the acceleratio
Answer:
80m/s2
Explanation:
a = v-u/ t
=>a = 0- 400/ 5
= -400/5
= -80m/s2
v- sign is negligible
An object accelerates at a=20m/s/s and reaches a final speed of v=5m/s. How is this possible? *
A)Trick question, it has to reach 20m/s at a minimum
B) It accelerated for 0.25s
C) Something slowed it down.
Answer:
B) It accelerated for 0.25s
Explanation:
Given the following data;
Acceleration = 20 m/s²
Final velocity, v = 5 m/s
Initial velocity, u = 0 m/s
To find the time, we would use the first equation of motion;
V = u + at
Substituting into the formula, we have;
5 = 0 + 20t
5 = 20t
Time, t = 5/20
Time, t = 0.25 seconds
Classify each change (which can be manipulated within the green box) according to its effect on the wavelength.
a. Decrease frequency
b. Decrease damping
c. Decrease amplitude
d. Increase frequency
e. Increase amplitude
f. Increase damping
g. Shortens wavelength
Answer:
Explanation:
The classification will be made into 3 categories, which are
Ones that shortens wavelengths
Ones that lengthens wavelengths
Ones that has no effect on wavelengths
Shortens wavelengths -> Increase frequency
Lengthens wavelengths -> Decrease frequency
No effect -> Increase amplitude, decrease amplitude, increase damping, decrease damping.
Below are the ingredients of photosynthesis. Organize them to show what is used and what is produced
during this process.
carbon dioxide
water
oxygen
glucose
sunlight
_____plus_____in the presence of_____result in_____plus_____
Answer:
carbon dioxide plus water in the presence of energy from light, results in glucose plus oxygen
The process is like carbon dioxide plus water in the presence of sunlight result in glucose plus oxygen.
What is photosynthesis?Photosynthesis is a process that plants and other organisms use to convert light energy into chemical energy that can then be released to fuel the organism's activities via cellular respiration.
Photosynthesis is important because it is the process by which plants convert carbon dioxide into oxygen using sunlight. Animals require oxygen to survive, and plants serve as nature's air filter, filtering out harmful carbon dioxide.
Photosynthesis is the conversion of light energy by phototrophs into chemical energy, which is then used to power cellular activities. Sugars, which are formed from water and carbon dioxide, are used to store chemical energy.
The process of photosynthesis includes:
[tex]6CO_2+6H_2O \frac{Sunlight}{chlorophyll} > C_6H_1_2O_6+6O_2[/tex]
Thus, this is the basic process of photosynthesis.
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A truck is traveling on a level road. The driver suddenly applies the brakes, causing the truck to decelerate by an amount g/2. This causes a box in the rear of the truck to slide forward. If the coefficient of sliding friction between the box and the truckbed is 2/5, find the acceleration of the box relative to the truck and relative to the road.
Answer:
Truck [tex]\dfrac{g}{10}[/tex]
Road [tex]-\dfrac{g}{10}[/tex]
Explanation:
[tex]a_1[/tex] = Acceleration of truck = [tex]-\dfrac{g}{2}[/tex]
[tex]\mu[/tex] = Coefficient of friction = [tex]\dfrac{2}{5}[/tex]
Frictional force is given by
[tex]f=-\mu mg\\\Rightarrow f=-\dfrac{2}{5}mg\\\Rightarrow ma_2=-\dfrac{2}{5}mg\\\Rightarrow a_2=-\dfrac{2}{5}g[/tex]
Net acceleration is given by
[tex]a=a_2-a_1\\\Rightarrow a=-\dfrac{2}{5}g+\dfrac{g}{2}\\\Rightarrow a=\dfrac{g}{10}[/tex]
The acceleration of the box relative to the truck is [tex]\dfrac{g}{10}[/tex] and [tex]-\dfrac{g}{10}[/tex] relative to the road.