An object is released from rest near a planet’s surface. A graph of the acceleration as a function of time for the object is shown for the 4 s after the object is released. The positive direction is considered to be upward. What is the displacement of the object after 2 s?

Answers

Answer 1

Answer:

the body has descended a height (4a)

Explanation:

This exercise should use the acceleration given in the graph, but unfortunately the graph is not loaded, but we can build it, using the law of universal gravitation and the fact that you indicate that the movement is near the surface of the planet

           F = m a

f

orce is gravitational force

           G M m / r² = m a

           a = G M / r²

where G is the universal constant of gravitation, M the mass planet and r the distance from the center of the planet of radius R to the body, if we measure the height of the body from the surface of the planet (y), we can write

           r = R + y

for which

           a = G M/R²     (1+ y/R)⁻²

if we use y«R we can expand the function in series

           a = (G M /R²)   (1 -2 y/R - 2 (-2-1) /2!   y² / R² +…)

as the height is small we can neglect the quadratic term and in many cases even the linear term, for this exercise we will remain only constant therefore the acceleration is constant

           a = G M / R²

from this moment we can use the relations of motion with constant acceleration for the exercise

a) they ask us for the position for t = 2s

            y = y₀ + v₀ t - a t²

as the body is released v₀ = 0

            y-y₀ = - a t²

            y-y₀ = - a 2²

             y-y₀ = - a 4

therefore  

therefore the body has descended a height (4a) where a is the acceleration of the planet's gravity


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Explanation:

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Answers

Answer:

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Explanation:

For this exercise we use the definition of average velocity

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Answers

Answer:

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Answers

Answer:

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Answer:

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Answers

Answer:

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Answer:

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Answer:

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Answer:

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Answer:

Hey there!

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Answer:

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Answers

Answer:

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Explanation:

Given;

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Answer:

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A race car starts from rest and speeds up uniformly to the right until it reaches a maximum velocity of 60m/s^2



What is the acceleration of the race car?

Answers

Question:

A race car starts from rest and speed up uniformly to the right until it reaches a maximum velocity of 60m/s in 15 secs

Answer:

4m/s²

Explanation:

The acceleration of a body in uniform motion can be found by using one of the equations of motion as follows;

v = u + at         ------------------(i)

Where;

v = final velocity of the body

u = initial velocity of the body

a = acceleration of the body

t = time taken for the motion

From the question, the body is the race car and has the following:

v = 60m/s²

u = 0 [since the car starts from rest]

t = 15 secs.

Now, substitute these values into equation(i) as follows;

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[tex]\frac{60}{15}[/tex] = [tex]\frac{15a}{15}[/tex]

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Therefore, the acceleration of the race car is 4m/s²

help pls!!

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Answers

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Answer :

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Given : d = 10km and t = 40min

To Find : Vav

_________________________________

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[tex]:\implies\:\boxed{\bf{\orange{V_{av}\:15\:kmph}}}[/tex]

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nngh have

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True
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this is a true and false question correct or did you accidentally put two truths ??

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Answers

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed {\sf{8.33 \: m \:/s \: }}}}} [/tex]

Explanation:

Distance travelled = 200 metre

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[tex] \boxed{ \sf{velocity = \frac{distance \: travelled \: }{time \: taken}}} [/tex]

[tex] \dashrightarrow{ \sf{velocity = \frac{200 \: m}{24 \: s} }}[/tex]

[tex] \dashrightarrow{ \sf{velocity = 8.33 \: m/s}}[/tex]

Hope I helped!

Best regards!

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Answers

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Explanation:

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Explanation:

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Answers

Answer:

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Explanation:

Which statement describes an advantage of models? And Developing is an advantage of a model.

Developing scientific methods.

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The scientific method has five basic steps, plus one feedback step:

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Know more about models here

https://brainly.com/question/19426210

#SPJ2

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Answers

Answer:

7.43 m/s

Explanation:

Time taken for car to stop = 7.0 s

distance traveled before coming to rest = 26 m

Final speed of the car = 0 m/s (since it stops)

initial speed of the car = ?

To get the final speed, we use the equation

s = [tex]\frac{1}{2}t(u + v)[/tex]

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It's important to match your exercise shoes with the type of exercise in which you will be participating.

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Answer:

True is the correct answer

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