An electric frying pan was on sale for 20 percent off. The sale price was $36. What was the original price?

Answers

Answer 1

Answer: $45

Step-by-step explanation:

Let the original price be x.

Since there was a discount of 20%, it means the person bought the frying pan at (100% - 20%) = 80% of the original price. This can then be formed into an equation as:

80% × x = $36

0.8 × x = $36

0.8x = $36

x = $36/0.8

x = $45

The original price was $45


Related Questions

Eugenia gasto 10 euros en el quiosco, compro 5 bocaditos, un paquete de galletas que costaba 1 euro y pagó 4 euros que debia ¿cuanto cuesta cada bocadito?

Answers

Answer:

the each snack cost is 1

Step-by-step explanation:

Let us assume the each snack cost be x

So according to the question

The following equation would be applied

5x + 1 + 4 = 10

5x + 5 = 10

5x = 5

x = 1

hence, the each snack cost is 1

So the same would be considered and relevant too

Which of the following statements best describes the value of the expression 6x + 7 when x = 5?

Answers

Answer:

? is there a option?

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

6x+7

6(5)+7

37

PLSSS HELP IF YOU KNOW THISS:))

Answers

The answer is 428 there you go

Im not sure how to do this can someone please help me only answer if you know

Answers

Answer:

57%

Step-by-step explanation:

FORMULA:LESS/TOTAL × 100%

=52/92 × 100%

=56.52 %

ROUND OFF TO NEAREST WHOLE NUMBER

56.52%=57%

(because the 5 after the (.) is near 1)

pls help i’ll give brainliest

Answers

Answer:

1/5x12 and 12/5

Step-by-step explanation:

both are dividing by five or equal to 2.4 which is the same as 1/5 of 12

Answer Of means to multiply so two correct answer would be B,D  

Step-by-step explanation: hope this helps :)

Solve for v.
6v-7+2(5v+1) = -2(v + 4)

Answers

Answer:

v = -1/6

Step-by-step explanation:

Combine all like terms, getting 18v = -3. Then, divide both sides by 18 to get -3/18, or v = -1/6

Hopefully this helps- let me know if you have any questions!

Veterinarians often use nonsteroidal anti-inflammatory drugs (NSAIDs) to treat lameness in horses. A group of veterinary researchers wanted to find out how widespread the price is in the United States. They obtained a list of all veterinarians treating large animals, including horses. They send questionnaires to all the veterinarians on the list. Such a survey is called a cemus. The response rate was 40%. What is the population of interest? a all veterinarians Oball veterinarians treating large animals e all veterinarians in the United States treating large animals, including horses d. All of the answer options are correct.

Answers

The population of interest in this case is (d) All of the answer options are correct. It includes all veterinarians, all veterinarians treating large animals, and all veterinarians in the United States treating large animals, including horses.

The population of interest in this study is defined as all veterinarians in the United States who treat large animals, including horses. This population includes all individuals who fit this criteria, regardless of their location or any other specific characteristics.

The researchers wanted to gather information about the prevalence of using nonsteroidal anti-inflammatory drugs (NSAIDs) for treating lameness in horses among veterinarians in the United States. To do this, they obtained a list of all veterinarians who treat large animals, including horses, and sent questionnaires to each of them.

The response rate refers to the percentage of veterinarians who completed and returned the questionnaires out of the total number of questionnaires sent. In this case, the response rate was 40%, meaning that 40% of the veterinarians who received the questionnaires responded to them.

By surveying a representative sample of veterinarians, the researchers can gather information and make inferences about the larger population of veterinarians in the United States who treat large animals, including horses. The data collected from the survey can provide insights into the widespread use of NSAIDs for treating lameness in horses and contribute to the overall understanding of veterinary practices in this context.

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Can somebody help me please no links

Answers

Answer:

Lololololo9lolo9lkiujyhgdfbhjkifewkjuhgsdvcgfh

Step-by-step explanation:

Someone help what would my average be if I got 100% on my both of my tests? I just wanna know

Answers

Answer:

To figure out your average, you add them together then divide by2

Step-by-step explanation:

PLEASE HELP HARD FOR ME BUT EASY FOR OTHERS

Answers

The answer should be 72 degrees.
You add 31 and 39 first to get 70 degrees.
Then add 38 degrees because the angle in the lower corner is the same as one the would be placed to the right of the top two angles. 70 plus 38 equals 108 degrees.
Next you subtract 108 from 180 to get the answer for x. That gives you 73 degrees.

can some one please help. 4789658953 round to the nearest 10th
mean =
mean absolute deviation =

Answers

Answer:

i believe your answer is.

4,789,658,950

Step-by-step explanation:

y= 5x - 9; domain = { 1,3,7 }
what is the range values?

Answers

Answer:

Step-by-step explanation:

range = [-4,6,26]

Step-by-step explanation:

y = 5x - 9.....domain = [1,3,7]....the domain is ur x values, and I am assuming ur looking for the y values that go with the x ones

y = 5x - 9.....when ur domain (ur x) = 1

y = 5(1) - 9

y = 5 - 9

y = -4

y = 5x - 9...when ur domain (x) = 3

y = 5(3) - 9

y = 15 - 9

y = 6

y = 5x - 9...when ur domain(x) is 7

y = 5(7) - 9

y = 35 - 9

y = 26

so ur range (ur y valus) = [-4,6,26]

Find the area under the standard normal distribution curve between z=0 and z=0.25. Use The Standard Normal Distribution Table and enter the answer to 4 decimal places.
The area between the two z values is ______

Answers

The area under the standard normal distribution curve between z=0 and z=0.25 is 0.0987.

First cumulative probability = z = 0 and

Second cumulative probability = z = 0.25

The Standard Normal Distribution Table, often known as the Z-table, may be used to determine the area under the standard normal distribution curve between z=0 and z=0.25. The table shows the total likelihood (area) up to a specified z-value. The cumulative probability, which can be found by looking up the z-value of 0 in the table, is 0.5000. The cumulative probability is 0.5987 when we look up the z-value of 0.25.

Calculating the area -

Area = First cumulative probability - Second cumulative probability

= 0.5987 - 0.5000

= 0.0987

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Find the area of the shaded sector.

Answers

The answer would be 8 feet

Joe has been riding his bicycle at a speed of 12 mph and has gone 48 miles. How long has he been riding?

Answers

Answer:

Joe's been riding 4 hours because if you divide 48 by 12 it gives you 4 and it's by hours so it would be 4 hours. point blank period.

Step-by-step explanation:

Please help !!!!!!!!!

Answers

Answer:

5

Step-by-step explanation:

3x -12 = -36

-36 ÷ -3 = 12

-7 + 12 = 5

Answer:

The value of -7 + 3(-12) ÷ (-3) is 5

Step-by-step explanation:

First: -7 + -36 ÷ (-3)

Second: -7 + 12

Third: = 5

Therefore your value of this equation is 5.

your welcome.

Evaluate the integral by reversing the order of integration 7/2 cosx V1+cosx dc dụ.

Answers

The evaluated integral is (7/4) (π - (3√3)/6) (rounded to an appropriate decimal approximation based on the given values of π and √3).

To evaluate the integral ∫∫(7/2 cos(x)) dV, where the region of integration is given by V: 1 ≤ c ≤ 2 and 0 ≤ x ≤ cos⁻¹(2c-1), we can reverse the order of integration.

Step 1: Write the integral with reversed order of integration:

∫∫(7/2 cos(x)) dc dx

Step 2: Determine the limits of integration for the reversed order. The variable c now varies from 1 to 2, and x varies from 0 to cos⁻¹(2c-1). Therefore, the integral becomes:

∫[1,2] ∫[0,cos⁻¹(2c-1)] (7/2 cos(x)) dx dc

Step 3: Integrate with respect to x first. The integral with respect to x is straightforward:

∫[1,2] [sin(x)] [0,cos⁻¹(2c-1)] (7/2) dc

Step 4: Evaluate the inner integral:

∫[1,2] [sin(cos⁻¹(2c-1))] (7/2) dc

Step 5: Simplify the inner integral using the trigonometric identity sin(cos⁻¹(u)) = √(1 - u²):

∫[1,2] [√(1 - (2c-1)²)] (7/2) dc

Step 6: Integrate with respect to c:

(7/2) ∫[1,2] [√(1 - (2c-1)²)] dc

Step 7: Evaluate the integral:

Using the trigonometric substitution u = sin(t), du = cos(t) dt, and the limits change to t: π/6 ≤ t ≤ π/2.

(7/4) ∫[π/6, π/2] [√(1 - sin²(t))] cos(t) dt

Step 8: Simplify the integrand:

(7/4) ∫[π/6, π/2] [cos²(t)] dt

Step 9: Apply the double-angle formula for cosine:

(7/4) ∫[π/6, π/2] [(1 + cos(2t))/2] dt

Step 10: Split the integral into two separate integrals:

(7/4) [∫[π/6, π/2] (1/2) dt + ∫[π/6, π/2] (cos(2t)/2) dt]

Step 11: Integrate each term separately:

(7/4) [(t/2) + (sin(2t)/4)] evaluated from π/6 to π/2

Step 12: Substitute the limits and simplify:

(7/4) [((π/2)/2 + (sin(2(π/2))/4) - ((π/6)/2) - (sin(2(π/6))/4)]

Step 13: Simplify further:

(7/4) [(π/4 + 0 - π/12 - (1/4)(√3/2))]

Step 14: Simplify and calculate the final value:

(7/4) [(π/4 - π/12 - (√3/8))]

= (7/4) [(3π - π - 3√3)/12]

= (7/4) [(2π - 3√3)/12]

= (7/4) (π - (3√3)/6)

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The curb weight of a new car is 3,347 pounds. How much does the car weigh?

Answers

Answer: 3,347 pounds

Step-by-step explanation:

Curb weight is simply the weight of a car with no passengers, cargo, or anyting other than the standard base model options.

Basically it's the weight of a base model car sitting on the dealership lot.  Curb weight would be different if ANYTHING is added to the base model car such as a passenger, any cargo, or any upgrades aftermarket or otherwise.

Answer:

Not sure if this the correct type of way your looking but its between 1 and 2 tons which is 1000

Step-by-step explanation:

I think...

how many yards are in 1 foot?

correct=brainliest

Answers

Answer:

0.333333

Step-by-step explanation:

0.333 yards are in one foot

Suppose X is an exponential random variable, show that E(X²) = 2/λ²

Answers

The exponential distribution is a continuous probability distribution that is widely used in probability theory and statistics. In probability theory, an exponential random variable is a continuous random variable that represents the waiting time between events in a Poisson process.

Suppose X is an exponential random variable. We have to show that E(X²) = 2/λ². We can show this by using the definition of expectation that is, E(X) = ∫[0,∞] xf(x) dx

where f(x) is the probability density function of X.

Similarly, E(X²) = ∫[0,∞] x²f(x) dx

We know that the probability density function of an exponential distribution with parameter λ is given by f(x) = λe^(-λx)So, E(X²) = ∫[0,∞] x²λe^(-λx) dx

Using integration by parts, we have ∫[0,∞] x²λe^(-λx) dx= [-x²e^(-λx)/λ] + [2xe^(-λx)/λ²] + [(-2/λ³)e^(-λx)]∞ 0= (2/λ²)

E(X²) = 2/λ².

The exponential distribution is a continuous probability distribution that is widely used in probability theory and statistics. In probability theory, an exponential random variable is a continuous random variable that represents the waiting time between events in a Poisson process.

Suppose X is an exponential random variable. We have to show that E(X²) = 2/λ². We can show this by using the definition of expectation that is, E(X) = ∫[0,∞] xf(x) dx

where f(x) is the probability density function of X.

Similarly, E(X²) = ∫[0,∞] x²f(x) dx

We know that the probability density function of an exponential distribution with parameter λ is given by f(x) = λe^(-λx)So, E(X²) = ∫[0,∞] x²λe^(-λx) dx

Using integration by parts, we have ∫[0,∞] x²λe^(-λx) dx= [-x²e^(-λx)/λ] + [2xe^(-λx)/λ²] + [(-2/λ³)e^(-λx)]∞ 0= (2/λ²)Therefore, the main answer to this question is E(X²) = 2/λ².

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e. 15 = 1.5t t=? Solve please

Answers

Answer:

E Z

10

Step-by-step explanation:

15 = 1.5t

so t = 15/1.5

      = 10

Answer: t = 10

1. Switch sides

- 1.5t = 15

2. Multiply both sides by 10

- 15t = 150

3. Divide both sides by 15

4. Simplify

t = 10

when comparing the f(x) = x2 2x and g(x) = log(2x 1), on which interval are both functions negative? (–[infinity], –2) (–2, 0) (–1, 1) (–[infinity], [infinity])

Answers

To find out on which interval are both functions f(x) = x^2 + 2x and g(x) = log (2x + 1) negative, we need to analyze the intervals of negative values of both functions.

We can plot their graphs to have a better understanding:

Graphs of f(x) = x² + 2x and g(x) = log(2x + 1)

Now, we need to observe the intervals where both functions lie below the x-axis: The function f(x) = x^2 + 2x is below the x-axis on the interval (-∞, -2).

The function g(x) = log(2x + 1) is below the x-axis on the interval (-1/2, 0).

Therefore, the interval on which both functions are negative is (-2, 0).Thus, the correct option is (–2, 0).

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The lenght of an arc in a circle with radius 8 inches is 3.2π. determine the measure of the arc​

Answers

Answer:

72

Step-by-step explanation:

32pi×360/2pi(8)=72

central angle= arc length 360/2pi×r

The measure of the arc is 72 degree

What is mean by Circle?

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

The measure of the arc, we use the formula:

⇒ Arc length = (angle measure / 360°) x 2πr

where r is the radius of the circle.

Now, We know that;

The radius is 8 inches, and that the arc length is 3.2π inches.

So, we can plug in those values and solve for the angle measure:

3.2π = (angle measure / 360°) x 2π(8)

3.2π = (angle measure / 360°) x 16π

Divide both sides by 16π:

0.2 = angle measure / 360°

Multiply both sides by 360°:

Angle measure = 72°

Thus, The measure of the arc is 72 degree

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Use the function f=d+1 to find the value of f when d=5.

Answers

Answer:

f = 6

Step-by-step explanation:

Plug in what you know then solve:

f = d + 1

f = 5 + 1

f = 6

PLEASE HELP THIS IS MATHHHHH

Answers

what inequality??????

Solve X
[tex] {16}^{ \frac{1}{5} } \times {2}^{x} = {8}^{ \frac{3}{4} } [/tex]
I got X= 9/10
am I right?​

Answers

16^1/5 = 2^4/5 .. & .. 8^3/4 = 2^9/4

____________

2^4/5 × 2^x = 2^9/4

2^16/20 × 2^x = 2^45/20

2^[ ( 16/20 ) + x ] = 2^45/20

16/20 + x = 45/20

x = 45/20 - 16/20

x = 29/20

In a study of spat dating es were asked them in the same time to What other out of the popu 23,50710090 What is the concerto? D-lichte places need was the other the contacto OA TN repostane posting tone OR Weather to the memo and on dem O. We second have the end மொயமால மாமா mg 140 Newt 0 View an example Get more help Help me solve this C M a o 0 10 1 In a study of speed dating male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractivo 10 = extremely attractive) Construct a confidence interval using a 95% confidence level What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,9, 6, 6, 8, 8, 7, 10,5,9 What is the confidence interval for the population mean? [<<(Round to one decimal place as needed) west point(s) possible in a study of speed dating, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractive 10 = extremely attractive) Construct a confidence interval using a 95% confidence level What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,9,6,6,8,8.7. 10,5,9 PO What is the confidence interval for the population mean? <-- (Round to one decimal place as needed) What does the confidence interval tell about the population of all adult fernales? Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. ative Area from the LEF 02 O A. The results tell nothing about the population of all adult females, because participants in speed dating are not a representative sample of the population of all adult females 5000 5178 03 5120 5517 5990 5871

Answers

Confidence interval are 5.9 < μ < 8.5 for the population mean.

Given:

Let x = 6,9,3,9, 6, 6, 8, 8, 7, 10,5,9

N = 12, ∑x = 86 x = 86/12 = 7.16

[tex]s=\sqrt{\frac{(x-\bar x)^2}{N-1} } = \sqrt{\frac{(6-7.16)^2+.....+(9-7.16)}{12-1} }[/tex]

[tex]\sqrt{\frac{45.66}{11} } =2.03[/tex]

At 98% confidence interval.

[tex]z=1-\frac{95}{100} =0.05\\[/tex]

[tex]t=2.201[/tex]

Confidence interval.

[tex]\bar x \pm t\frac{s}{\sqrt{n} } = 7.16\pm 2.201(\frac{2.03}{\sqrt{12} } )[/tex]

[tex]5.9 < \mu < 8.5[/tex]

Therefore, 95% confidence interval are 5.9 < μ < 8.5

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g(x) = -3x-8g(x)=−3x−8g, left parenthesis, x, right parenthesis, equals, minus, 3, x, minus, 8
g\Big(g(g, left parenthesis
\Big)=10)=10

Answers

Answer:

try your best

Step-by-step explanation:

write a quadratic function with leading coefficient 1 that has roots ofp.

Answers

A quadratic function with leading coefficient 1 and roots of p can be expressed as f(x) = (x - p)(x - p), which simplifies to f(x) = x^2 - 2px + p^2.

To construct a quadratic function with leading coefficient 1 and roots of p, we utilize the relationship between the roots and the factors of a quadratic equation. Since p is a root, the factors of the quadratic function would be (x - p) and (x - p). By multiplying these factors together, we obtain the quadratic function f(x) = (x - p)(x - p). Simplifying further, we can expand the expression:

f(x) = (x - p)(x - p) = x^2 - px - px + p^2 = x^2 - 2px + p^2

Hence, the quadratic function with leading coefficient 1 and roots of p is given by f(x) = x^2 - 2px + p^2. This form allows for easy identification of the coefficients and reveals that the constant term of the quadratic is p^2.

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f(x) = 9x-7. If f(x)= -7, find x.​

Answers

Answer: the answer is 56

Step-by-step explanation: since the f(x) is -7 it would be 9 times -7 then minus 7 and get the answer.

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Inventory Prepaid expenses Total current assets FORTEN COMPANY Comparative Balance Sheets December 31 Equipment Accumulated depreciation-Equipment Total assets Liabilities and Equity $647,500 298,000 349,500 179, 150 (18.125) 152,225 42,450 $ 109,775 Current Year Prior Year $69,400 85,400 295,156 1,340 451,296 144,500 (43,125) $ 552,671 $ 86,500 63,625 264,800 2,155 417,080 121,000 (52,500) $ 485,580 Assets Cash FORTEN COMPANY Comparative Balance Sheets December 31 Accounts receivable Inventory Prepaid expenses Total current assets Equipment Accumulated depreciation-Equipment Total assets Liabilities and Equity Accounts payable. Long-term notes payable Total liabilities Current Year $ 69,400 85,400 295,156 1,340 451,296 144,500 (43,125) $ 552,671 d. Paid $51,325 cash to reduce the long-term notes payable. e. Issued 3,800 shares of common stock for $20 cash per share. f. Declared and paid cash dividends of $52,700. $ 66,141 72,400 138,541 Prior Year $ 86,500 63,625 264,800 2,155 182,250 57,000 174,880 $ 552,671 417,080 121,000 (52,500) $ 485,580 Equity Common stock, $5 par value Paid-in capital in excess of par, common stock Retained earnings Total liabilities and equity Additional Information on Current Year Transactions a. The loss on the cash sale of equipment was $18,125 (details in b). b. Sold equipment costing $85,875, with accumulated depreciation of $43,125, for $24,625 cash. c. Purchased equipment costing $109,375 by paying $56,000 cash and signing a long-term notes payable for the balance.. $ 134,175 70,350 204,525 163,250 0 117,805 $ 485,580 es Required: 1. Prepare a complete statement of cash flows using the indirect method for the current year. (Amounts to be deducted should be indicated with a minus sign.) 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