The anode reaction in the Fe₂+|Fe₃+ half-cell is: Fe₂+ (aq) + Fe₃+ (aq) -> Fe₃+ (aq) + Fe₂+ (aq) The cathode reaction in the Br-|Br₂ half-cell is:
Br₂ (aq) + 2e- -> 2Br- (aq)
The net cell reaction is Fe₂+ (aq) + Br₂ (aq) -> Fe₃+ (aq) + 2Br- (aq)
In the external circuit, electrons migrate from the Fe₂+|Fe₃+ electrode to the Br-|Br₂ electrode.
In the salt bridge, anions migrate from the Br-|Br₂ compartment to the Fe₂+|Fe₃+ compartment.
The anode reaction is: Pb (s) -> Pb₂+ (aq) + 2e-
The cathode reaction is: I₂ (s) + 2e- -> 2I- (aq)
In the external circuit, electrons migrate from the Pb|Pb₂+ electrode to the I-|I₂ electrode.
In the salt bridge, anions migrate from the I-|I₂ compartment to the Pb|Pb₂+ compartment.
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what is the difference between corrosion and rusting
Answer:
Corrosion is the process of deterioration of materials as a result of chemical, electrochemical or other reactions. Rusting is a part of corrosion and is a chemical process which results in the formation of red or orange coating on the surface of metals. ... Rust or rusting can affect only iron and its alloys.
Explanation:
Which species functions as the oxidizing agent in the following reduction-oxidation reaction? ZnO(s) + C(s) → Zn(s) + CO(g) A) ZnO(s) B) C(s) C) CO(g) D) Zn(s)
In the following reduction-oxidation reaction; ZnO(s) + C(s) → Zn(s) + CO(g), the species which functions as the oxidizing agent is option (B) C(s).
In the reaction ZnO(s) + C(s) → Zn(s) + CO(g), C(s) gains oxygen and goes from being a carbon atom to a carbon dioxide molecule which contains two oxygen atoms. Therefore, C(s) has been oxidized. Carbon is being oxidized in the above reaction because it has gained oxygen.
The term oxidation refers to the loss of electrons by an atom or molecule. Oxidation is a type of chemical reaction in which a substance loses electrons to another substance. The oxidation process usually occurs with a substance's interaction with oxygen.
Therefore, the correct answer is option B) C(s).
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The atmosphere is primarily made of what gas?
Carbon Dioxide
Nitrogen
Oxygen
Argon
Answer:
nitrogen
Explanation:
(this is science not chemistry)
I'm pretty sure ita A. acceleration
Answer:
it's a friction force
Sven perform this reaction with 15.0 grams of sodium sulfate and an excess of iron (III) phosphate to make iron (III) sulfate and sodium phosphate. In the actual experiment, 10.0 grams of sodium phosphate are experimentally made, what is the percent yield?
2FePO4+3Na2SO4-->Fe2(SO4)3+2Na3PO4
Answer:
85.5%
Explanation:
To get the experimental value, you need to convert 15.0 grams of Na2SO4 to grams of Na3PO4. You do this with stoichiometry.
Convert grams of Na2SO4 to moles with molar mass. Then convert to moles of Na3PO4 with the mole-to-mole ratio according to the balanced chemical equation. Then convert moles of Na3PO4 to grams with the molar mass.
15.0 g Na2SO4 x (1 mol/142.04 g) x (2 Na3PO4/3Na2SO4) x (163.94 g/1 mol) = 11.7 g Na3PO4
Percent Yield = (actual value/experimental value) x 100
Actual Value = 10.0 g
Experimental Value = 11.7 g
10.0g/11.7 g = 85.5%
what is the maximum amount of strong acid that can be added to a buffer made by the mixing of 0.35 mol sodium hydrogen carbonate with 0.50 mol sodium carbonate?
The balanced equation is: NaHCO₃ + HCl → NaCl + H2₃.
We can see that for every mole of NaHCO₃, one mole of HCl is required to convert it to H2CO₃. Therefore, the maximum amount of strong acid that can be added to the buffer is 0.35 mol HCl.
A buffer is a solution that resists pH change upon the addition of small amounts of acid or base. It is a solution of a weak acid and its corresponding conjugate base or a weak base and its corresponding conjugate acid. A buffer system consists of a weak acid or a weak base, and its conjugate base or conjugate acid.
When an acid or base is added to the buffer solution, the equilibrium is shifted either to the left or right, thereby minimizing the change in pH. Therefore, to determine the maximum amount of strong acid that can be added to a buffer made by the mixing of 0.35 mol sodium hydrogen carbonate with 0.50 mol sodium carbonate, we first need to identify the components of the buffer.
Sodium hydrogen carbonate (NaHCO₃) is a weak acid and sodium carbonate (Na2CO₃) is its conjugate base. The maximum amount of strong acid that can be added to the buffer is the amount that will convert all of the buffer components to their conjugate acid.
In this case, we need to convert all of the NaHCO₃ to H2CO₃.
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Compare the two reaction coordinate diagrams below and select the answer that correctly describes their relationship. In each case, the single intermediate is the ES complex. The contribution of binding energy is given by 5 in (a) and by 7 in (b) O The activation energy for the uncatalyzed reaction is given by 5+6 in (a) and by 7+4 in (b) O The ES complex is given by 2 in (a) and 4 in (b). O(a) describes a transition-state complementarity model, whereas (b) describes a strict "lock and key" model. O The activation energy for the catalyzed reaction is 5 in (a) and is 7 in (b).
The correct answer is O(a) describes a transition-state complementarity model, whereas (b) describes a strict "lock and key" model.
The two reaction coordinate diagrams given represent two different models that describe the catalysis of enzyme-catalyzed reactions. Both models have a single intermediate which is the ES complex. In each case, the contribution of binding energy is given, which is 5 in (a) and by 7 in (b). The ES complex is given by 2 in (a) and 4 in (b). The activation energy for the uncatalyzed reaction is given by 5+6 in (a) and by 7+4 in (b). The models presented in the diagrams are the transition-state complementarity model (a) and the strict "lock and key" model
(b). The two models are different from each other. They differ based on the mechanism by which the enzyme catalyzes the reaction. The lock-and-key model assumes that the active site of the enzyme is rigid and complementary to the substrate that fits into it. The substrate is said to "fit" into the active site of the enzyme as a lock fits into a key. In the transition-state complementarity model, the enzyme's active site has flexibility, which allows it to interact with the substrate in such a way that it stabilizes the transition state, reducing the energy required to reach it. The activation energy for the catalyzed reaction is 5 in (a) and is 7 in (b).
Hence, the correct answer is O(a) describes a transition-state complementarity model, whereas (b) describes a strict "lock and key" model.
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how many bonding electrons and lone pair electrons (nonbonding electrons) are there in the lewis structure of HCN?
In the Lewis structure of HCN (hydrogen cyanide), we can determine the number of bonding electrons and lone pair electrons by considering the valence electrons of each atom involved.
Hydrogen (H) is in Group 1 of the periodic table and has one valence electron. Carbon (C) is in Group 14 and has four valence electrons, and nitrogen (N) is in Group 15 with five valence electrons. Cyanide (CN) is a polyatomic ion, and since we have one carbon and one nitrogen, we have a total of nine valence electrons (four from carbon and five from nitrogen). In the Lewis structure, we first connect the atoms using a single bond between carbon and nitrogen, and carbon forms a single bond with hydrogen. This accounts for two of the nine valence electrons. To complete the octets around each atom, we distribute the remaining seven valence electrons as lone pairs around the nitrogen and carbon atoms. The lone pairs do not participate in bonding and are considered nonbonding or lone pair electrons. Therefore, in the Lewis structure of HCN, there are two bonding electrons and seven lone pair electrons (nonbonding electrons). The bonding electrons are involved in forming the bonds between the atoms, while the lone pair electrons are localized on the nitrogen and carbon atoms, fulfilling their octets.
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Which species will have the highestconcentration in a 0.25 M aq sol of boric acid?Ka1 = 7.3 x 10-10Ka2 = 1.8 x 10-13Ka3 = 1.6 x 10-14A. H3BO3B. H2BO3-C. HBO32-D. BO33-E. H+
In a 0.25 M aqueous solution of boric acid, the species with the highest concentration would be H_{3}BO_ 3}^{-} option B.
Boric acid (H_{3}BO_{3}) is a weak acid that can undergo multiple ionization steps. The given equilibrium constants (Ka) provide information about the ionization reactions. The first ionization reaction of boric acid is as follows:
[tex]H_{3}BO_{3}[/tex] ⇌ H^{+}+ H_{3}BO_ 3}^{-}
Ka1 = 7.3 x 10^-10
The second ionization reaction is:
[tex]H_{3}BO_ 3}^{-}[/tex] ⇌H^{+} + H_{3}BO_ 3}^{-2}
Ka2 = 1.8 x 10^-13
The third ionization reaction is:
H_{3}BO_ 3}^{-2} ⇌ H+ + [tex]BO_{3} ^{-3}[/tex]
Ka3 = 1.6 x [tex]10^{-14}[/tex]
To determine the species with the highest , we need to compare the equilibrium constants. The larger the Ka value, the more the reaction favors the dissociation of the species.
Based on the given Ka values, the second ionization reaction (H2BO3- ⇌ [tex]H^{+}[/tex] + H_{3}BO_ 3}^{-2}) has the highest Ka value (1.8 x 10^-13). This indicates that the concentration of H_{3}BO_ 3}^{-} in the solution would be higher compared to the other species. Therefore, option B, H_{3}BO_ 3}^{-}, would have the highest concentration in a 0.25 M aqueous solution of boric acid.
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Suppose you have 1000 lb of waste copper (II) oxide sitting in the basement of your factory. Do you see a problem with sending it to a landfill?
Answer:
Yes.
Explanation:
Yes, we have a problem with sending it to a landfill of copper oxide because it has harmful effect on the health of humans as well as more weight of the copper oxide. Copper oxide usually found in powder form which can easily be inhaled that causes death of the cell due to toxic effect on the mitochondria and lysosomes of the cell. It makes problem of health in carrying the copper oxide from the basement of the factory to the landfill region due to its power form so we can say that it can do problems to human health while carrying from one place to another.
9. What happens to the cell outside of the nucleus when the virus has been copied so many times? a. The cell fights back b. The cell gets help from its neighbor cells C. The cell gets help from white blood cells d. The cell is destroyed
Answer: it think the answer is c.) The cell gets help from white blood cells or b.) The cell gets help from its neighbor cells.
Explanation:
Draw the predominant product(s) of the following reactions including stereochemistry when it is appropriate. CH3-CEC-CH3 + 2HBr . Consider EZ stereochemistry of alkenes. • Do not show stereochemistry in other cases. • If no reaction occurs, draw the organic starting material. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate multiple products using the sign from the drop- down menu. ChemDoodle
The product of the reaction between [tex]CH_{3}[/tex]-CH=[tex]CH_{2}[/tex] and HBr is 2-bromo-3-methylbutane.
The reaction proceeds through the addition of a proton from HBr to the double bond, followed by the addition of a bromide ion.
The addition of the proton is stereospecific, and the bromide ion will add to the carbon atom that is least substituted by hydrogen. In this case, the carbon atom that is least substituted by hydrogen is the carbon atom that is attached to two hydrogen atoms.
Therefore, the bromide ion will add to the carbon atom that is attached to the double bond and the methyl group. The product of the reaction is 2-bromo-3-methylbutane.
here is the predominant product of the reaction of [tex]CH_{3}CHCH=CH-CH_{3}[/tex] with HBr:
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The complete question is:
Draw the predominant product(s) of the following reactions including stereochemistry when appropriate. CH CH CH -CEC-H HBr Consider EIZ stercochemistry of alkenes. Do not show stereochemistry in other cases If no reaction occurs_ raw the organic starting material. Draw one stnicture per sketcher Add additional sketchers using the drop down menu in the bottom right corner Separate multiple products using the sign from the drop-down menu: ChemDoodle Submit Answver Retry Entire Group more cirovp attempts remaining
a 30.0- ml volume of 0.50 m ch3cooh ( ka=1.8×10−5 ) was titrated with 0.50 m naoh . calculate the ph after addition of 30.0 ml of naoh at 25 ∘c . express the ph numerically.
The pH after the addition of 30.0 mL of NaOH at 25 °C is 8.82.
To calculate the pH after the addition of NaOH, we need to determine the moles of CH3COOH and NaOH that react, and then use the stoichiometry to find the resulting concentration of CH3COOH and OH-.
Given:
Volume of CH3COOH = 30.0 mL = 0.0300 L
Concentration of CH3COOH = 0.50 M
Ka for CH3COOH = 1.8×10^(-5)
Volume of NaOH = 30.0 mL = 0.0300 L
Concentration of NaOH = 0.50 M
First, we calculate the moles of CH3COOH:
moles of CH3COOH = concentration × volume
moles of CH3COOH = 0.50 M × 0.0300 L
moles of CH3COOH = 0.015 mol
Since CH3COOH and NaOH react in a 1:1 ratio, the moles of NaOH are also 0.015 mol.
Next, we calculate the moles of OH- produced:
moles of OH- = moles of NaOH
moles of OH- = 0.015 mol
Now, we calculate the concentration of OH-:
concentration of OH- = moles of OH- / total volume
concentration of OH- = 0.015 mol / (0.0300 L + 0.0300 L)
concentration of OH- = 0.250 M
Using the equilibrium expression for the dissociation of water, we can calculate the concentration of H+ (or H3O+):
[H+][OH-] = Kw
[H+] = Kw / [OH-]
[H+] = 1.0 × 10^(-14) / 0.250 M
[H+] = 4.0 × 10^(-14) M
Finally, we calculate the pH:
pH = -log[H+]
pH = -log(4.0 × 10^(-14))
pH = 8.82
The pH after the addition of 30.0 mL of NaOH at 25 °C is 8.82.
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how many grams is 3.49 moles NaCl
Answer:
m = 204.16 grams
Explanation:
Given that,
No. of moles, n = 3.49
Molar mass of NaCl, M = 58.5 g/mol
We need to find the mass of 3.49 moles NaCl. We know that,
[tex]n=\dfrac{m}{M}\\\\m=n\times M\\\\m=3.49 \times 58.5\\\\m=204.16\ g[/tex]
So, there are 204.16 grams in 3.49 moles NaCl.
What two emissions scenarios most closely represent the current trend in CO2 emissions?
The two emissions scenarios that most closely represent the current trend in CO2 emissions are the Representative Concentration Pathway (RCP) 4.5 and RCP 6.0 scenarios. RCP 4.5 assumes moderate emission reduction efforts, while RCP 6.0 represents a higher emission trajectory, reflecting the current trend where emissions reductions are not keeping pace with necessary targets.
The Representative Concentration Pathways (RCPs) are scenarios used to assess the potential impacts of greenhouse gas emissions on the climate system. RCP 4.5 assumes a moderate emission reduction pathway, with emissions peaking around 2040 and declining gradually. On the other hand, RCP 6.0 represents a higher emission trajectory, with emissions peaking later and declining more slowly compared to RCP 4.5. This scenario aligns with the current trend of rising CO2 emissions, indicating that global efforts to reduce emissions have not been sufficient. The current trend is closer to RCP 6.0, highlighting the challenges of achieving widespread emission reductions in various sectors of the global economy.
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URGENT LOOK AT PICTURE
look at the thing and choose all that matches
Answer:
E
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BRAINLIEST PLEASE
what is a phase diagram? what is a phase diagram? a phase diagram is simply a map of the phase of a substance as a function of volume (on the y-axis) and number molecules (on the x-axis). a phase diagram is simply a map of the phase of a substance as a function of pressure (on the y-axis) and number molecules (on the x-axis). a phase diagram is simply a map of the phase of a substance as a function of pressure (on the y-axis) and temperature (on the x-axis). a phase diagram is simply a map of the phase of a substance as a function of volume (on the y-axis) and pressure (on the x-axis).
A phase diagram is a graphical representation or map that shows the different phases (solid, liquid, and gas) of a substance as a function of pressure and temperature. It provides valuable information about the conditions under which a substance exists in each phase or undergoes phase transitions.
In a phase diagram, pressure is typically represented on the y-axis, and temperature is represented on the x-axis. The diagram is divided into regions corresponding to different phases, and boundaries or lines separating these regions represent phase transitions.
The phase diagram allows us to determine the conditions at which a substance can exist as a solid, liquid, or gas, and it provides insights into the effects of temperature and pressure on the phase behavior of the substance.
It helps in understanding processes such as melting, boiling, and sublimation and provides a useful tool in various fields including chemistry, physics, and materials science.
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: 1. a) Write an expression for the solubility product constant (Ksp) of manganese(II) hydroxide, Mn(OH)2. Mn(OH)2 = Mn + 2014ce) b) The concentration of hydroxide (OH) in a saturated solution of Mn(OH), is determined to be 7.5 x 10- M. What is the molar solubility (S) of manganese(II) hydroxide in water? c) Based on the molar solubility you calculated in (b), calculate the Kip of Mn(OH)2.
An expression for the solubility product constant (Ksp) of manganese(II) hydroxide is Ksp = [[tex]Mn^{2+}[/tex]][[tex]OH^-[/tex]]. b) Molar solubility (S) of Mn(OH)[tex]_2[/tex] in water is 2.3 x [tex]10^{-21}[/tex]. c) The Ksp value is 2.3 x [tex]10^{-21}[/tex].
a) The expression for the solubility product constant (Ksp) of manganese (II) hydroxide, Mn(OH)[tex]_2[/tex] is given below:
Ksp = [[tex]Mn^{2+}[/tex]][[tex]OH^-[/tex][tex]]^{2}[/tex]
Mn(OH)[tex]_2[/tex] ⇌ [tex]Mn^{2+}[/tex] + 2[tex]OH^-[/tex]
The equation shows that the stoichiometry of the reaction is one mole of Mn(OH)[tex]_2[/tex] dissociating to give one mole of [tex]Mn^{2+}[/tex] and two moles of [tex]OH^-[/tex].
b) Given the concentration of hydroxide ([tex]OH^-[/tex]) in a saturated solution of Mn(OH)[tex]_2[/tex], which is 7.5 x [tex]10^{-8}[/tex] M.
The molar solubility (S) of Mn(OH)[tex]_2[/tex] in water is determined by using the stoichiometry of the dissociation reaction and the equilibrium expression.
Using the stoichiometry of the dissociation reaction and the equilibrium expression;[[tex]Mn^{2+}[/tex]] = S[[tex]OH^-[/tex]] = 2S
Therefore, Ksp = [[tex]Mn^{2+}[/tex]][[tex]OH^-[/tex][tex]]^{2}[/tex]
= S × [tex](2S)^2[/tex]
= 4[tex]S^3[/tex]
= 4 (7.5 x[tex]10^{-8})^3[/tex]
= 2.3 x [tex]10^{-21}[/tex]
c) The Ksp value is 2.3 x [tex]10^{-21}[/tex] and the molar solubility (S) is 6.6 x [tex]10^{-8}[/tex] M which are calculated above.
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Which planet could support human life
Answer:
D
Explanation:
It states that D has oxygen, and is closer to the Sun.
Hope this helped, and please mark as Brianliest <3
Answer:
I am pretty sure it is B
Explanation:
The others would either burn u like a crispy chicken nugget or freeze you like a popsicle
Need help please!! To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. (Hint: be sure to work the problem with both PbS and O2).
The equation of the reaction is [tex]2PbS + 3O_{2} --- > 2Pb + 2SO_{3}[/tex] and the mass of lead produced is 2.28 g
What is the equation?The term equation is the means by which we could be able to represent what is going on in the reaction system on a piece of paper. Thus, when we write a reaction equation, it is a representation of the process that is going on in the system. By the use of the stoichiometry of the reaction we could obtain the parameters of the equation.
The balanced reaction equation is; [tex]2PbS + 3O_{2} --- > 2Pb + 2SO_{3}[/tex].
Number of moles of lead (II) sulfide = 2.54 grams/239 g/mol = 0.011 moles
Number of moles of oxygen = 1.88 g/32 g/mol = 0.059 moles
If 2 moles of lead (II) sulfide reacts with 3 moles of oxygen
0.011 moles of lead (II) sulfide reacts with 0.011 moles * 3 moles /2 moles
= 0.0017 moles
Hence lead (II) sulfide is the limiting reactant.
If 2 moles of lead (II) sulfide produces 2 moles of lead
Mass of the Lead produced = 0.011 moles * 207 g/mol = 2.28 g
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Question Identify the element with the ground state electron configuration [Xe]4f14
5d6
6s2 .
Answer Ir
Ta
Os
Ru
Au
The element with the ground state electron configuration [Xe]4f¹⁴5d⁶6s² is actually Ir, which represents iridium. Option A is correct.
The electron configuration is a representation of how electrons are distributed among the energy levels, subshells, and orbitals within an atom. It follows a specific notation that describes the arrangement of electrons.
The electron configuration indicates that the electrons are arranged in the following manner;
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d⁶
The [Xe] notation represents the electron configuration of the noble gas xenon (Xe), which includes all the electrons up to the 5p level. After the noble gas core, we have 4f¹⁴ 5d⁶, which corresponds to the electron configuration of iridium (Ir).
Hence, A is the correct option.
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--The given question is incomplete, the complete question is
"Identify the element with the ground state electron configuration [Xe]4f¹⁴5d⁶6s². Options; A) Ir B) Ta C) Os D) Ru E) Au."--
identify the limiting reactant when 7.28 grams of magnesium oxide reacts with 4.50 grams of aluminum to make magnesium and aluminum oxide? i need a typed answer a link wont work
Answer:
the limiting reactant is aluminum
Explanation:
A researcher uses an electrochemical cell to interrogate the redox activity between a solution of copper and a solution of an unknown metal. The free energy change under standard conditions is determined to be -293.4 kJ/mol a. What is a reasonable guess for the unknown metal. Justity. b. Write the reduction and oxidation half reactions
a. Metals such as zinc (Zn) or aluminum (Al) could be reasonable guesses as they have higher standard reduction potentials than copper. b. Reduction half-reaction is Cu₂+(aq) + 2e⁻ → Cu(s), Oxidation half-reaction is Unknown metal (M)(s) → M₂+(aq) + 2e⁻.
a. To make a reasonable guess for the unknown metal in the electrochemical cell, we can consider the standard reduction potentials (E°) of different metals. The standard reduction potential is a measure of the tendency of a metal to undergo reduction (gain electrons) compared to a standard hydrogen electrode (SHE).
Since the free energy change under standard conditions is negative (-293.4 kJ/mol), it indicates a spontaneous redox reaction, where the copper solution undergoes reduction and the unknown metal solution undergoes oxidation.
A reasonable guess for the unknown metal would be a metal with a higher standard reduction potential than copper (Cu). This is because for the overall reaction to be spontaneous, the unknown metal should have a greater tendency to undergo oxidation (lose electrons) compared to copper. Based on this, metals such as zinc (Zn) or aluminum (Al) could be reasonable guesses as they have higher standard reduction potentials than copper.
b. The reduction and oxidation half-reactions can be written as follows
Reduction half-reaction
Cu₂+(aq) + 2e- → Cu(s)
Oxidation half-reaction
Unknown metal (M)(s) → M₂+(aq) + 2e⁻
In the reduction half-reaction, copper ions (Cu₂⁺) in solution are reduced and gain two electrons to form solid copper (Cu).
In the oxidation half-reaction, the unknown metal (M) in solid form is oxidized, losing two electrons to form metal ions (M₂⁺) in solution.
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(GIVING BRAINLIEST) Which of the following is a good source of carbohydrates?
pears
meat
eggs
fish
Answer:
I would choose pear fruits are a good source of carbohydrates hopefully its right sorry if its not
Answer: Fruit
Fruits have a lot of carbohydrates in them :) Hope this helped!
What do glycine, leucine, and lysine all have in common?
They are the building blocks of proteins.
They have an important role in the heart.
They have a role in the functioning of the stomach.
They store equal amounts of energy in their bonds.
Answer:
a, they are the building blocks of proteins.
Explanation:
hope this helps!
~mina
Answer:
A. They are the building blocks of proteins.
(Photo for proof at the bottom.)
Explanation:
Glycine, leucine, and lysine are all amino acids. There are 20 different kinds of amino acids, including the 3 mentioned here. Different amino acids bond together to form different structures, depending on how many there are. Generally, 50 or more amino acids bonded together makes a protein. But there are some exceptions. Amino acids (including glycine, leucine, and lysine) are the building blocks of proteins.
Here's a photo of Edge incase you're doubtful.
Please click the heart if this helped.
You are required to make 1 L of 70% isopropyl alcohol for surface disinfection, You have a stock solution of 99% isopropyl alcohol and sterile water. Calculate the amounts of isopropyl 99% alcohol and sterile water you need to use to make the 70% isopropyl solution using the alligation method.
A. 700 mL of isopropyl 99% and 300 mL of water
B. 750 mL of isopropyl 99% and 250 mL of water
C. 707.1 mL of isopropyl 99% and 292.9 mL of water
D. 708.1 mL of isopropyl 99% and 291.9 mL of water
E. 706.1 mL of isopropyl 99% and 299 9 mL of water
The amounts of isopropyl 99% alcohol and sterile water you need to use to make the 70% isopropyl solution using the alligation method are 707.1 mL of isopropyl 99% and 292.9 mL of water. The correct answer is option C.
Alligation method is a type of mathematical process used to calculate the quantities of two or more components of a mixture to obtain a mixture with a specific concentration or quality. This method uses the concept of averaging and the weighted average to get the desired results.
The allegation formula for isopropyl alcohol solution: Required % strength —— Higher % strength | DifferenceLower % strength | Difference70% ——- 99% | 29%70-29=41% | 29%
So, the required ratio of the alcohol to be mixed with water should be 41:29. Thus, the volumes of the 99% alcohol and water needed are (41/70) L and (29/70) L, respectively. Let's substitute the values and calculate:
41/70 × 1L = 0.586 L of 99% isopropyl alcohol
29/70 × 1L = 0.414 L of sterile water
Now we have the volumes of the 99% isopropyl alcohol and sterile water required. By adding these, the total volume of the solution is 1L, as given in the question. Therefore, the answer is 707.1 mL of 99% isopropyl alcohol and 292.9 mL of sterile water (707.1 mL + 292.9 mL = 1000 mL = 1 L).
Hence, option C) 707.1 mL of isopropyl 99% and 292.9 mL of water is the correct answer.
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The colision of two plates causes the fomation of _____
mountain
How long does it take for the earth to rotate
A. 24hrs
B. 1 yr
C. 2 weeks
D. 5 months
Answer:
24 hrs it takes for the earth to rotate
Which of the following elements has 2 electrons in the 4s sublevel?
Answer:
B. Ca
Explanation:
Let's look at the electron configurations of all four elements (I am going to write it in noble gas configuration to make it simpler):
Mg electron configuration: [Ne]3s2
Ca electron configuration: [Ar]4s2
Ar electron configuration: [Ar]
K electron configuration: [Ar] 4s1
We notice that Ca has two electrons in the 4s sublevel, which satisfies what the question is asking for.
The answer is thus B. Ca.
A buoy bobs up and down in the ocean. The waves have a wavelength of
2.5 m, and they pass the buoy at a speed of 4.0 m/s. What is the frequency
of the waves?
A. 1.6 Hz
B. 10 Hz
C. 6.5 Hz
D. 1.5 Hz
Answer:
c
Explanation: